New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'checkley77'
checkley77 answered: 12560 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569, >>Next
Graphs/205568: How do you graph (-2,5), (3,-1) 1 solutions
Answer 155196 by checkley77(12569) on 2009-08-05 19:02:16 (Show Source):
You can put this solution on YOUR website!Y=mX+b
m=slope=(y2-y1)/(x2-x1)=(-1-5)/(3+2)=-6/5
(-2,5), (3,-1)
5=-2*-6/5+b
5=12/5+b
b=5-12/5
b=(5*5-12)/5
b=(25-12)/5
b=13/5=2.6 is the y intercept.
y=-6x/5+2.6
 (graph 300x200 pixels, x from -6 to 6, y from -10 to 10, -6x/5 +2.6).
|
Travel_Word_Problems/205456: Two cars, A and B, having average speeds of 30 and 40 mph, respectively are 280 miles apart they start moving towards each other at 3pm, At what time will they meet? 1 solutions
Answer 155112 by checkley77(12569) on 2009-08-05 10:15:44 (Show Source):
|
Pythagorean-theorem/205474: Suppose you need to construct a right triangle in which the shorter side is eight feet less than the longest side and the third side is seven feet more than the shortest side. 1 solutions
Answer 155111 by checkley77(12569) on 2009-08-05 10:12:40 (Show Source):
You can put this solution on YOUR website!a^2+b^2=c^2
a=c-8
b=a+7 or b=(c-8)+7 or b=c-1
(c-8)^2+(c-1)^2=c^2
c^2-16c+64+c^2-2c+1=c^2
2c^2-c^2-18c+65=0
c^2-18c+65=0
(c-13)(c-5)=0
c-13=0
c=13 ans.
a=13-8
a=5 ans.
b=5+7
b=12 ans.
Proof:
5^2+12*2=13^2
25+141=169
169=169
|
Numbers_Word_Problems/205461: "if the larger of two numbers is subtracted from 6 times the smaller,the result is 20.if twice the larger number is added to 4 times the smaller,he resul is 56.find the numbers" 1 solutions
Answer 155104 by checkley77(12569) on 2009-08-05 09:54:34 (Show Source):
You can put this solution on YOUR website!Let x be the smaller number & y be the larger number.
6x-y=20 or y=6x-20
4x+2y=56
4x+2(6x-20)=56
4x+12x-40=56
16x=56+40
16x=96
x=96/16
x=6 ans.
y=6*6-20
y=36-20
y=16 ans.
Proof:
4*6+2*16=56
24+32=56
56=56
|
Miscellaneous_Word_Problems/205468: solve the equation by eliminating fractions
A) x/2+x/3=20
b) 3m/4+m/2= -5 1 solutions
Answer 155101 by checkley77(12569) on 2009-08-05 09:38:20 (Show Source):
You can put this solution on YOUR website!A) x/2+x/3=20
(3x+2x)/(2*3)=20
5x/6=20
5x=20*6
5x-120
x=120/5
x=24 ans.
Proof:
24/2+24/3=20
12+8=20
20=20
b) 3m/4+m/2=-5
(2*3m+4*m)/(4*2)=-5
(6m+4M)/8=-5
10M/8=-5
10M=-5*8
10M=-40
M=-40/10
M=-4 ANS.
PROOF:
3*-4/4+(-4/2)=-5
-12/4-2=-5
-3-2=-5
-5=-5
|
Angles/205473: If the measure of an angle is 30 less than twice the measure of its supplement, what is the measure of each angle? 1 solutions
Answer 155099 by checkley77(12569) on 2009-08-05 09:29:09 (Show Source):
You can put this solution on YOUR website!x+3x-30=180
4x=180+30
4x=210
x=210/4
x=52.5 ans. for the smaller angle.
3*52.5-30=157.50-30=127.7 ans for the larger angle.
Proof:
52.5+127.5=180
180=180
|
Miscellaneous_Word_Problems/205487: Find three consecutive odd numbers such that 1/7 of the first plus 1/3 of the second plus 1/5 of the third is 63. 1 solutions
Answer 155096 by checkley77(12569) on 2009-08-05 09:17:40 (Show Source):
You can put this solution on YOUR website!Let x, x+2, x+4 be the 3 odd numbers.
x/7+(x+2)/3+(x+4)/5=63
[(15x+35(x+2)+21(x+4)]/105=63
[15x+35x+70+21x+84]/105=63
[71x+154)/105=63
71x+154=63*105
71x+154=6,615
71x=6,615-154
71x=6,461
x=6,461/71
x=91 the first number
91+2=93 the second number
91+4=95 the third number
Proof:
91/7+93/3+95/5=63
13+31+19=63
63=63
|
Miscellaneous_Word_Problems/205486: Find three consecutive odd numbers such that 1/7 of the first plus 1/3 of the second plus 1/5 of the third is 63. 1 solutions
Answer 155095 by checkley77(12569) on 2009-08-05 09:16:23 (Show Source):
You can put this solution on YOUR website!Let x, x+2, x+4 be the 3 odd numbers.
x/7+(x+2)/3+(x+4)/5=63
[(15x+35(x+2)+21(x+4)]/105=63
[15x+35x+70+21x+84]/105=63
[71x+154)/105=63
71x+154=63*105
71x+154=6,615
71x=6,615-154
71x=6,461
x=6,461/71
x=91 the first number
91+2=93 the second number
91+4=95 the third number
Proof:
91/7+93/3+95/5=63
13+31+19=63
63=63
|
Problems-with-consecutive-odd-even-integers/205398: This question is from textbook algebra 1 an integrated approach
sara has $1.45 in nickles and dimes. There are 18 in all. how many of many of each are there? Use the 5-step method and a table in solving this problem. (hint this problem is very similar to the try it exercise on page 205. use the answer to that question to help you determine the variables and organize your table.) i really hope u guys can help me i got the table all set up and the first part of this problem figured out i just didnt know how to solve it! thank you for your time !!!!!!!!!!!!!!!!!!! 1 solutions
Answer 155030 by checkley77(12569) on 2009-08-04 15:54:02 (Show Source):
You can put this solution on YOUR website!N+D=18
N=18-D
.05N+.10D=1.45
.05(18-D)+.10D=1.45
.90-.05D+.10D=1.45
.05D=1.45-.90
.05D=.55
D=.55/.05
D=11 DIMES.
N+11=18
N=18-11
N=7 NICKLES.
PROOF:
.05*7+.10*11=1.45
.35+110=1.45
1.45=1.45
|
Rectangles/205186: The area of a rectangular piece of cardboard shown is 735 square inches. The cardboard is used to make an open box by cutting a 3-inch square from each corner and turning up the sides. If the box is to have a volume of 1305 cubic inches, find the dimensions of the cardboard that must be used. Any help you can give would be greatly appreciated, thanks!! 1 solutions
Answer 154939 by checkley77(12569) on 2009-08-03 15:35:01 (Show Source):
You can put this solution on YOUR website!xy=735
x=735/y
(x-2*3)(y-2*3)*3=1305
(735/y-6)(y-6)*3=1305
(735-6y-6*735/y+36)*3=1305
(735-6y-4410/y+36)*3=1305
2205-18y-13230/y+108=1305
-18y-13230/y=1305-2205-108
-18y-13230/y=-1008
(-18y*y-13230)/y=-1008
-18y^2-13230=-1008y
18y^2-1008y+13230=0
18(y^2-56y+735)=0
18(y-21)(y-35)=0
y-21=0
y=21 then x=35
y-35=0
y=35 then x=21
Proof:
21*35=735
735=735
(21-2*3)(35-2*3)*3=1305
(21-6)(35-6)*3=1305
15*29*3=1305
1305=1305
|
Linear_Equations_And_Systems_Word_Problems/205250: TJ plans to erect 132 feet of fencing around his rectangular garden, using his house as one side of the garden. Each width (x) is 3 feet longer than twice the length (y). Find the dimensions of the garden. 1 solutions
Answer 154937 by checkley77(12569) on 2009-08-03 15:09:21 (Show Source):
You can put this solution on YOUR website!x=2y+3
2x+(2y+3)=132
2(2y+3)+2y+3=132
4y+6+2y+3=132
6y+9=132
6y=132-9
6y=123
y=123/6
y=20.5 ans. for the length.
x=2*20.5+3
x=41+3
x=44 ans for the width.
Proof:
2*44+(2*20.5+3)=132
88+41+3=132
132=132
|
Geometry_Word_Problems/205194: Please help with me find an equation of line l and solve for y when Line l goes through (0,0) and is perpendicular to the line through (0,6) and (-5,0). I am stumped because I don't think there is a slope for the first line. Any help is greatly appreciated. 1 solutions
Answer 154918 by checkley77(12569) on 2009-08-03 10:51:52 (Show Source):
You can put this solution on YOUR website!(0,6)(-5,0)
The equation for this line is:
Y=mX+b
m=slope=(y2-y1)/(x2-x1)=(0-6)/(-5-0)=-6/-5=6/5 ans.
6=6/5*0+b
6=b ans. for the y intercept.
y=6x/5+6 is the equation for this line. (red line)
A perpendicular line will have a slope=-5/6 passing through (0,0).
0=-5/6*0+b
0=b ans. for the y intercept for this line.
y=-5x/6+0s the equation for thjis line. (green line)
 (graph 300x300 pixels, x from -6 to 6, y from -6 to 6, of TWO functions 6x/5 +6 and y = -5x/6).
|
|