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# Recent problems solved by 'checkley77'

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 Miscellaneous_Word_Problems/242687: One number is 5 less than twice another, their sum is 124. Find the numbers1 solutions Answer 177739 by checkley77(12569)   on 2009-11-25 17:10:24 (Show Source): You can put this solution on YOUR website!x=2y-5 x+y=124 2y-5+y=124 3y=124+5 3y=129 y=129/3 y=43 ans. for the smaller number. 124-43=81 ans. for the larger number. Proof: 43+81=124 124=124
 decimal-numbers/242688: hockey teams receive 1 point when they tie, and 2 points when they win. One season a team won with 64 points, they won 11 more games than they tied, how many wins and how many ties did they have? 1 solutions Answer 177735 by checkley77(12569)   on 2009-11-25 16:53:41 (Show Source): You can put this solution on YOUR website!w=t+11 2w+1t=64 2(t+11)+t=64 2t+22+t=64 3t=64-22 3t=42 t=42/3 t=14 number of games tied. w=14+11=25 games won. Proof: 2*25+14*1=64 50+14=64 64=64
 Linear-equations/242706: Determine the equation of the line described. Put answer in the slope-intercept form, if possible. Through (1,-8), perpendicular to -7-4y=25. 1 solutions Answer 177733 by checkley77(12569)   on 2009-11-25 16:42:12 (Show Source): You can put this solution on YOUR website!Through (1,-8), perpendicular to -7-4y=25. -7-4y=25 -4Y=25+7 -4Y=32 Y=32/-4 Y=-8 ANSWER FOR THE Y INTERCEPT. (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -8).
 Miscellaneous_Word_Problems/242708: Ticket sales. Tickets for a concert were sold to adults for \$3 and to students for \$2. If the total receipts were \$824 and twice as many adult tickets as student tickets were sold, then how many of each were sold? 1 solutions Answer 177730 by checkley77(12569)   on 2009-11-25 16:38:28 (Show Source): You can put this solution on YOUR website!A=2S 3A+2S=824 3*2S+2S=824 6S+2S=824 8S=824 S=824/8 S=103 STUDENT TICKETS WERE SOLD. 2*103=206 ADULT TICKETS WERE SOLD. PROOF: 3*206+2*103=824 618+206=824 824=824
 Linear-equations/242709: Find the x-intercept for the line represented by this equation.4x-3y=6x+y 1 solutions Answer 177727 by checkley77(12569)   on 2009-11-25 16:31:41 (Show Source): You can put this solution on YOUR website!4x-3y=6x+y -3y-y=6x-4x -4y=2x y=2x/-4 y=-x/2 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -x/2). X intercept=(0,0)
 Money_Word_Problems/242729: If I invest \$400 at 3% compound quarterly for 4 years how much money will I have? 1 solutions Answer 177726 by checkley77(12569)   on 2009-11-25 16:26:36 (Show Source): You can put this solution on YOUR website!400(1+.03/4)^4*4 400(1+.0075)^16 400(1.0075)^16 400*1.127=\$450.80 ans.
 Mixture_Word_Problems/242742: A goldsmith has two alloys that are different purities of gold. The first is three-fourths pure gold and the second is five twelfths pure gold. How many ounces of each should be melted and mixed in order to obtain a 6-oz mixture that is two-thirds pure gold?1 solutions Answer 177725 by checkley77(12569)   on 2009-11-25 16:21:25 (Show Source): You can put this solution on YOUR website!.75x+5/12(6-x)=2/3*6 .75x+5*6/12-5/12x=12/3 .75x+30/12-5x/12=4 .75x-5x/12+2.5=4 (.75x*12-5x)/12=4-2.5 (9x-5x)/12=1.5 4x=1.5*12 4x=18 x=18/4 x=4.5 oz. of 3/4 pure gold is used. 6-4.5=1.5 oz. of 5/12 pure gold is used. Proof: .75*4.5+5/12*1.5=2/3*6 3.375+.625=4 4=4
 Geometry_Word_Problems/242492: The length of a rectangle is 30cm less than three times the width. The perimeter of this rectangle is 180cm. What are the dimensions of this rectangle?1 solutions Answer 177552 by checkley77(12569)   on 2009-11-24 18:57:45 (Show Source): You can put this solution on YOUR website!L=3W-30 2L+2W=30 2(3W-30)+2W=30 6W-60+2W=30 8W=30+60 8W=90 W=90/8 W=11.25 CM. IS THE WIDTH. L=3*11.25-30=33.75-30=3.75 CM IS THE LENGTH. PROOF: 2*3.75+2*11.25=30 7.5+22.5=30 30=30
 Numeric_Fractions/242498: Simplify (2/x +3/y)/(3/x -2/y)1 solutions Answer 177549 by checkley77(12569)   on 2009-11-24 18:49:44 (Show Source): You can put this solution on YOUR website!(2/x +3/y)/(3/x -2/y) [(2Y+3X)/XY]/[(3Y-2X)/XY]CANCEL OUT THE XY TERMS. (2Y+3X)/(3Y-2X) ANS.
 Miscellaneous_Word_Problems/242338: Of 100 students surveyed, 80 were taking a math class and 75 were taking a science class. If 70 students were taking both math and science, how many were taking neither? 1 solutions Answer 177545 by checkley77(12569)   on 2009-11-24 18:42:43 (Show Source): You can put this solution on YOUR website!100-(80-70)-(75-70)=100-10-5=85 STUDENTS TAKE MATH OR SCIENCE OR BOTH. THUS 100-85=15 TAKE NEITHER.
 Word_Problems_With_Coins/242339: A wallet contains 10 coins, all nickels or dimes, totaling 80 cents. How many dimes are there? 1 solutions Answer 177544 by checkley77(12569)   on 2009-11-24 18:36:46 (Show Source): You can put this solution on YOUR website!N+D=10 OR N=10-D .05N+.10D=.80 .05(10-D)+.10D=.80 .5-.05D+.10D=.80 .05D=.80-.50 .05D=.30 D=.30/.05 D=6 DIMES. 10-6=4 NICKELS. PROOF: .05*4+.10*6=.80 .20+.60=.80 .80=.80
 Linear-systems/242351: For spring break some students flew to cancun. From mexico city, the airplane took 2 hrs to fly 600 mi against a head wind. The return trip with the wind took 1 2/3 hr. Find the speed of the plane in still air.1 solutions Answer 177541 by checkley77(12569)   on 2009-11-24 18:29:33 (Show Source): You can put this solution on YOUR website!600/2=300 MPH. AGAINST THE WIND. 600/(5/3)=600*3/5=1800/5=360 MPH WITH THE WIND. (360-300)/3=60/2=30 MPH IS THE WIND SPEED. 360-30=330 THE PLANE'S SPEED IN STILL AIR. 300+30=330 DITTO.
 Numbers_Word_Problems/242352: michael bought a jacket and a sweater. the jacket cost \$28 more than the sweater. the sum of the prices was \$146. how much did each item cost?1 solutions Answer 177540 by checkley77(12569)   on 2009-11-24 18:25:31 (Show Source): You can put this solution on YOUR website!J=S+28 J+S=146 (S+28)+S=146 2S=146-28 2S=118 S=118/2 S=\$59 WAS THE COST OF THE SWEATER. J=59+28=\$87 WAS THE COST OFTHE JACKET. PROOF: 59+87=146 146=146
 Equations/242363: 0.4x+2<0.8x-91 solutions Answer 177536 by checkley77(12569)   on 2009-11-24 18:21:05 (Show Source): You can put this solution on YOUR website!0.4x+2<0.8x-9 .4x-.8x<-9-2 -.4x<-11 x>-11/-.4 note: the < changes to a > when divided by a negative value. x>27.5 ans. Proof: Let x=28 .4*28+2<.8*28-9 11.2+2<22.4-9 11.2<13.4
 Polynomials-and-rational-expressions/242402: Can someone help me with these two. I have to factor and tell if the polynomials is prime or not. Thanks 1. x2 - 1.1x + 0.28 2. x4 + 3x2 + 2x3 + 6x 1 solutions Answer 177534 by checkley77(12569)   on 2009-11-24 18:15:16 (Show Source): You can put this solution on YOUR website!1. x2 - 1.1x + 0.28 (x-.7)(x-.4) ans. ------------------------ 2. x4 + 3x2 + 2x3 + 6x x^2(x^2+3)+2x(x^2+3) (x^2+2x)(x^2+3) ans. -----------------------
 Equations/242404: Factor completely. If the polynomial is prime, state this. thanks y^2 + 0.4y + 0.04 1 solutions Answer 177533 by checkley77(12569)   on 2009-11-24 18:11:35 (Show Source): You can put this solution on YOUR website!y^2 + 0.4y + 0.04 (y+.2)^2 ans.
 Linear_Equations_And_Systems_Word_Problems/242412: Andea's car averages 18.4 mi/gal in city driving and 25.8 mi/gal in highway driving. if she drove a total of 652.0 mi on 29 gal of gas, how many of the gallons were used for city driving? i think this a system of equations problem. i don't know how to set up the equations1 solutions Answer 177531 by checkley77(12569)   on 2009-11-24 18:07:51 (Show Source): You can put this solution on YOUR website!YOU DON'T NEED A SYSTEM OF EQUATIONS; THE FOLLOWING ONE WILL DO. 18.4X+25.8(29-X)=652 18.4X+748.2-25.8=652 -7.4X=652-748.2 -7.4X=-96.2 X=-96.2/-7.4 X=13 GAL CONSUMMED @ 18.4 MPH. CITY DRIVING. 29-13=16 GAL CONSUMMED @ 25.8 MPH. PROOF: 18.4*13+25.8*16=652 239.2+412.8=652 652=652
 Complex_Numbers/242415: 2vsquared-5v-25=01 solutions Answer 177525 by checkley77(12569)   on 2009-11-24 17:50:42 (Show Source): You can put this solution on YOUR website!2v^2-5v-25=0 (2v+5)(v-5)=0 2v+5=0 2v=-5 v=-5/2 v=-2.5 ans. v-5=0 v=5
 test/242443: A 3-ft by 6-ft picnic table is placed on an outdoor patio measuring x ft by x ft. Find a polynomial for the remaining open space on the patio (in square feet).1 solutions Answer 177521 by checkley77(12569)   on 2009-11-24 17:47:18 (Show Source): You can put this solution on YOUR website!3*6=18 ft^2 x^2-18 ft^2 is the remaining open space.
 expressions/240117: (-46)-30-(17)1 solutions Answer 177517 by checkley77(12569)   on 2009-11-24 17:44:02 (Show Source): You can put this solution on YOUR website!(-46)-30-(17)=-46-30-17=-93 ans.
 Quadratic_Equations/242420: What is the number of solutions for the quadratic function f(x) = 3x^2 + 5x + 101 solutions Answer 177516 by checkley77(12569)   on 2009-11-24 17:38:47 (Show Source): You can put this solution on YOUR website!f(x) = 3x^2 + 5x + 10 x=(-5+-sqrt[5^5-4*3*10])/2*3 x=(-5+-sqrt[25-120)/6 x=(-5+-sqrt-95)/6 x=(-5+-9.7468i)/6 x=-5/6+-1.6244i x=-.8333+-1.6244i ans.
 Rectangles/242485: What is the perimeter of a rectangle if the area is 36 m square?1 solutions Answer 177515 by checkley77(12569)   on 2009-11-24 17:28:51 (Show Source): You can put this solution on YOUR website!LW=36 THERE ARE MANY SOLUTIONS. A FEW FOLLOW: L*W/////2L+2W 6*6///2*6+2*6=12=12=24 ANS. 9*4///2*9+2*4=18+8=26 ANS. 12*3//2*12+2*3=24+6=30 ANS. 18*2//2*18+2*2=36+4=40 ANS. 36*1//2*36+2*1=72+2=74 ANS.
 Angles/242136: What is the measure of the only angle that is its own complement and the measure of the only angle that is its own supplement1 solutions Answer 177319 by checkley77(12569)   on 2009-11-23 20:00:54 (Show Source): You can put this solution on YOUR website!COMPLEMENT: 45+45=90 ANS. 45 DEGREES. SUPPLEMENT: 90+90=180 ANS. 90 DEGREES.
 expressions/242143: Find the median of the following set of numbers. 45, 21, 54, 22, 65, 61 How do I find the median. I just need to know how to find it1 solutions Answer 177318 by checkley77(12569)   on 2009-11-23 19:58:45 (Show Source): You can put this solution on YOUR website!45, 21, 54, 22, 65, 61 ARRANGE THE VALUES IN ORDER: 21,22,45,54,61,65 THE MEDIAN IS THE MIDDLE VALUES. BECAUSE THER IS NO SINGLE MIDDLE VALUE, AVERAGE THE 2 MIDDLE VALUES. (45+54)/2=99/2-49.5 ANS. FOR THE MEDIAN.
 Radicals/242155: (3 - 2 Square root of 12) squared1 solutions Answer 177315 by checkley77(12569)   on 2009-11-23 19:50:51 (Show Source): You can put this solution on YOUR website!(3 - 2 Square root of 12) squared 3-2SQRT12 3-2SQRT12 --------------- 9-6SQRT12-6SQRT12+4*12 9-12SQRT12+48 9+48-12SQRT(4*3) 57-12*2SQRT3 87-24SQRT3 ANS.
 Rectangles/242159: . The length of a rectangular room is 7 feet longer than its width. The area of the room is 60 feet. What are the dimensions of the room?1 solutions Answer 177312 by checkley77(12569)   on 2009-11-23 19:46:14 (Show Source): You can put this solution on YOUR website!L=W+7 LW=60 (W+7)W=60 W^2+7W-60=0 (W+12)(W-5)=0 W-5=0 W=5 ANS. L=5+7=12 ANS. PROOF: 5*12=60 60=60
 Square-cubic-other-roots/242163: x^2+6x+45=01 solutions Answer 177310 by checkley77(12569)   on 2009-11-23 19:42:51 (Show Source): You can put this solution on YOUR website!x^2+6x+45=0 x=(-6+-sqrt[6^2-4*1*45])/2*1 x=(-6+-sqrt[36-180])/2 x=(-6+-sqrt-144)/2 x=(-6+-12i)/2 x=(-6/2+-12i/2 x=-3+-6i
 Rational-functions/242167: I don't understand how to solve this problem. Any help wpuld be appreciated. 1 solutions Answer 177308 by checkley77(12569)   on 2009-11-23 19:37:59 (Show Source): You can put this solution on YOUR website! x^2(x+4)>=x+4 divide both sides by (x+4) x^2>=1 x>=+-1 ans.
 Linear-equations/242176: PERPINDICULAR TO 3X+4Y=12,THROUGH (7,1)1 solutions Answer 177306 by checkley77(12569)   on 2009-11-23 19:33:23 (Show Source): You can put this solution on YOUR website!PERPINDICULAR TO 3X+4Y=12,THROUGH (7,1) 3x+4y=12 4y=-3x+12 y=-3x/4+12 slope=-3/4. (red line) A perpendicular line has a slope=4/3 1=4/3*7+b 1=28/3+b b=1-28/3 b=3/3-28/3 b=-25/3 the Y intercept. Y=4X/3-25/3 ans. (green line) (graph 300x300 pixels, x from -10 to 15, y from -10 to 15, of TWO functions -3x/4 +12 and 4x/3 -25/3).
 Numbers_Word_Problems/242180: Denise bought 50 postage stamps for which she paid \$13.00. Some were 20-cent stamps and some were 40-cent stamps. How many of each did she buy?1 solutions Answer 177302 by checkley77(12569)   on 2009-11-23 19:14:45 (Show Source): You can put this solution on YOUR website!X+Y=50 OR X=50-Y .20X+.40Y=13 .20(50-Y)+.40Y=13 10-.20Y+.40Y=13 .20Y=13-10 .20Y=3 Y=3/.20 Y=15 40 CENT STAMPS WERE BOUGHT. 50-15=35 20 CENT STAMPS WERE BOUGHT. PROOF: .20*35+.40*15=13 7+6=13 13=13
 Numbers_Word_Problems/242183: One week a business sold 40 scarves. White ones cost \$4.95, and printed ones cost \$7.95. In all, total sales of scarves were \$282. How many of each kind were sold?1 solutions Answer 177296 by checkley77(12569)   on 2009-11-23 18:59:52 (Show Source): You can put this solution on YOUR website!P+W=40 OR P=40-W 4.95W+7.95(40-W)=282 4.95W+318-7.95W=282 -3W=282-318 -3W=-36 W=-36/3 W=12 WHITE SCARVES WERE SOLD. 40-12=28 PRINTED SCARVES WERE SOLD. PROOF: 4.95*12+7.95*28=282 59.4+222.6=182 282=282