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I NEED HELP WITH EVERYTHING ABOUT ALGEBRA.
I DON'T UNDERSTAND ANYTHING.
INEVER UNDERSTOOD ANYTHING.
HELP ME.
1) x^2-2x-7= sqrt (5)
2) 3/5 = sqrt (9)
3) 56x -18x+ x^2= 17
4) sqrt (9) = sqrt (35)
1 solutions
Answer 221488 by checkley77(12569) on 2010-05-29 18:50:18 (Show Source):
You can put this solution on YOUR website!ARE YOU SURE YOU HAVE COPIED THESE PROPLEMS CORRECTLY???
SOME OF THEM DON'T MAKE ANY SENSE (NUMBERS 2 & 4).
--------------------------------------------------------
1) x^2-2x-7= sqrt (5)
X^2-2X-7-2.236=0
X^2-2X-9.236=0 USING THE QUADRATIC EQUATION BELOW WE GET:
X=(2+-SQRT[-2^2-4*1*-9.236])/2*1
X=(2+-SQRT[4+36.944)/2
X=(2+-SQRT40.944)/2
X=(2+-6.399)/2
X=(2+6.399)/2
X=8.399/2
X=4.199 ANS.
X=(2-6.399)/2
X=-4.399/2
X=-2.199 ANS.
2) 3/5 = sqrt (9)
3/5=3
3=5*3
3=15 DOES NOT COMPUTE.
3) 56x -18x+ x^2= 17
38X+X^2-17=0
X^2+38X-17=0
X=(-38+-SQRT[38^2-4*1*-17])/2*1
X=(-38+-SQRT[1,444+68])/2
X=-38+-SQRT1,512)/2
X=(-38+-38.88)/2
X=(-38+38.88)/2
X=.88/2
X=.44 ANS.
X=(-38-38.88)/2
X=76.88/2
X=-38.44 ANS.
4) sqrt (9) = sqrt (35)
3=5.91 DOES NOT COMPUTE.
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Linear-equations/309598: If the vertical line of a triangle is 24m and the bottom horizontal line is 10m,
then what would the missing length be? Help please & thanks 1 solutions
Answer 221483 by checkley77(12569) on 2010-05-29 18:29:09 (Show Source):
You can put this solution on YOUR website!IF THE VERTICLE LINE IS ONE OF THE SIDES & IT'S A RIGHT TRIANGLE THEN:
10^2+24^2=C^2
100+576=C^2
C^2=676
C=SQRT676
C=26 m.
iF THE VERTICLE ANGLE IS THE MIDDLE HEIGHT OF THE TRIANGLE THEN:
5^2+24^2=C^2
25+576=C^2
C^2=601
C=SQRT601
C=24.5m.
ALL OTHER VERTICLE LINES WILL RESULT IN THE THIRD SIDE BEING BETWEEN
24.5M. & 26 m.
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Quadratic_Equations/309616: For the Equation 4X^2-100=0, did I do my work right? 4X^2-100=0
+100 +100
4X^2=100
/4 /4
X^2=25
My teacher said that if it was a prime number or if it had no perfect square you could leave it as it is is this true and is my answer right? Thank you
1 solutions
Answer 221477 by checkley77(12569) on 2010-05-29 18:14:18 (Show Source):
You can put this solution on YOUR website!4X^2-100=0
+100 +100
4X^2=100
/4 /4
X^2=25
YOUR ANSWER IS CORRECT SO FAR BUT:
NO YOU CAN'T QUIT NOW BECAUSE 25 IS A PERFECT SQUARE AND THE ANSWER IS:
X=SQRT25
X=5 ANS.
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test/309623: The length of a new rectangular field is 7 yards longer than triple the width. If the perimeter of the rectangular playing field is 470 yards what are its dimensions? 1 solutions
Answer 221475 by checkley77(12569) on 2010-05-29 18:06:08 (Show Source):
You can put this solution on YOUR website!L=3W+7
P=2L+2W
470=2(3W+7)+2W
470=6W+14+2W
470=8W+14
8X=470-14
8W=456
W=456/8
W=57 YDS. IS THE WIDTH.
L=3*57+7=178 YDS. FOR THE LENGTH.
PROOF:
470=2*178+2*57
470=356+114
470=470
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Triangles/309624:
In a isosceles triangle ABC, b is the vertex. the vertex angle measures 3 times the sum of the measures of the other 2 angles. what is the measure of angle b?
is it 36
is it 72
is it 108
is it 135
i need help soon as possible 1 solutions
Answer 221474 by checkley77(12569) on 2010-05-29 18:01:53 (Show Source):
You can put this solution on YOUR website!b=3*2a
b+a+a=180
3*2a+2a=180
6a+2a=180
8a=180
a=180/8
a=22.5 degrees for the other 2 angles.
b+2*22.5=180
b+45=180
b=180-45
b=135 degres for the apex angle.
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Linear-equations/309625: find the slope, if it exists, on the lines containing points (6,2) and (7,-5)
simplify your answer. type and integer or an fraction.type n if there is no slope 1 solutions
Answer 221473 by checkley77(12569) on 2010-05-29 17:53:04 (Show Source):
You can put this solution on YOUR website!(6,2) and (7,-5)
slope=(y2-y1)/(x2-x1)
slope=(-5-2)/(7-6)=-7/1=-7 ans. for the slope.
Y=mX+b
2=-7*6+b
2=-42+b
b=2+42
b=44 ans. for the Y intercept.
y=-7x+44
 (graph 300x200 pixels, x from -6 to 10, y from -10 to 50, -7x +44)
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Permutations/309629: a popular model of car is being offered in 4 body styles, 3 types of engins, and 5 metal flake paint schemes. how many cars are needed to display all possible option variations? 1 solutions
Answer 221472 by checkley77(12569) on 2010-05-29 17:48:00 (Show Source):
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Equations/309645: I need help finding the real solution to this equation.
3.67x2 + 4.35x - 2.13 = 0 1 solutions
Answer 221467 by checkley77(12569) on 2010-05-29 17:14:11 (Show Source):
You can put this solution on YOUR website!3.67x2 + 4.35x - 2.13 = 0
X=(-4.35+-SQRT[4.35^2-4*3.67*-2.13])/2*3.67
X=(-4.35+-SQRT[18.9225+31.2684])/7.34
X=(-4.35+-SQRT[50.1909)/7.34
X=(-4.35+-7.08455)/7.34
X=(-4.35+7.08455)/7.34
X=2.73455/7.34
X=.3726 ANS.
X=(-4.35-7.08455)/7.34
X=-11.43455/7.34
X=-1.5578 ANS.
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Geometry_Word_Problems/309646: The Golden Ratio.
The anceint greeks thought that the most pleasing shape for a rectangle was one for which the ratio fo the length to the width was approximately 8 to 5, the golden ratio. If the length of a rectangular painting is 2 ft longer thann it's width, then for what demensions would the length and width have the golden ratio? 1 solutions
Answer 221466 by checkley77(12569) on 2010-05-29 17:04:44 (Show Source):
You can put this solution on YOUR website!L/W=8/5
8/5=(X+2)/X
8X=5(X+2)
8X=5X+10
8X-5X=10
3X=10
X=10/3
X=3.33 ANS. FOR THE WIDTH.
PROOF:
8/5=(3.33+2)/3.33
8/5=5.33/3.33
8*3.33=5*5.33
26.64~26.65
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Equations/309658: I need to find the exact answer and simplify it using the rules for radicals.
Diagonal of a patio. Find the length of the diagonal of a
square patio with an area of 40 square meters.
Basic facts:
1. Area of a square = side2
2. Diagonal of a square = √2*side2
1 solutions
Answer 221460 by checkley77(12569) on 2010-05-29 16:40:07 (Show Source):
You can put this solution on YOUR website!x^2=40
x=sqrt40
x=6.325 ans. for the length of the sides.
s^2+s^2=d^2
2s^2=d^2
2*6.325^2=d^2
2*40=d^2
80=d^2
d=sqrt80
d=8.945 ans. for the diagonal of the square.
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Geometry_Word_Problems/309665: The perimeter of Triangle ABC is 306 inches. Find the lengths of the sides.
My problem is that I am not sure what formula to use.
AB=_____ in BC=_______in AC=______in 1 solutions
Answer 221456 by checkley77(12569) on 2010-05-29 16:13:05 (Show Source):
You can put this solution on YOUR website!Without any additional information there are an infinite number of solutions to this probnlem.
a+b+c=306
102+102+102=306 is one solution.
103+101+102=306 is another solution.
101+101+104=306 is a third solution.
104+104+98=306 is a fourth solution.
And there are many many more.
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Equations/309532: the permiter of a rectangle is 164m and the length is 7m more than twice the width, could you show me how to find the width and the length? 1 solutions
Answer 221386 by checkley77(12569) on 2010-05-28 20:28:06 (Show Source):
You can put this solution on YOUR website!P=2L+2W
L=2W+7
164=2(2W+7)+2W
164=4W+14+2W
6W=164-14
6W=150
W=150/6
W=25 ANS. FOR THE WIDTH.
L=2*25+7
L=50+7=57 ANS. FOR THE LENGTH.
PROOF:
164=2*57=2*25
164=114+50
164=164
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Equations/309533: three times as many units of plywood is sold as lumber, the profit on the lumber is $25 per unit and the profit on the plywood is $40 per unit could you show me how to find how many units of lumber and plywood would be produced and sold to make a profit of $14,790 1 solutions
Answer 221385 by checkley77(12569) on 2010-05-28 20:22:48 (Show Source):
You can put this solution on YOUR website!3X*40+X*25=14,790
120X+25X=14,790
145X=14,790
X=14,790/145
X=102 PIECES OF LUMBER WAS SOLD.
3*102=306 PIECES OF PLYWOOD WERE SOLD.
3*102*40+102*25=14,790
12,240+2,550=14,790
14,790=14,790
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Polynomials-and-rational-expressions/309163: company A rents copiers for a monthly charge of $250 plus 10 cents per copy. Company B rents copiers for a monthly charge of $500 plus 5 cents per copy. What is the number of copies above which company A's charges are the higher of the two? 1 solutions
Answer 221156 by checkley77(12569) on 2010-05-27 20:31:47 (Show Source):
You can put this solution on YOUR website!250+.10x>500+.05x
.10x-.05x>500-250
.05x>250
x>250/.05
x>5,000 copies is the same cost for Co.A & B.
More than 5,000 copies Co. a will be more expensive.
Proof:
Let copies be=5,001
250+.10*5,001>500+500+.05*5,001
250+500.1>500+25.005
750.01>750.005
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