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Points-lines-and-rays/312613: A school yard sandbox is in the shape of a rectangle. It has 54 feet of boards around the border that enclose the sand box. If the length of the sandbox is 3 feet less than twice the width, find the dimensions of the sand box. 1 solutions
Answer 223502 by checkley77(12569) on 2010-06-08 19:37:42 (Show Source):
You can put this solution on YOUR website!L=2W-3
P=2L+2W
54=2(2W-3)+2W
54=4W-6+2W
6W=54+6
6W=60
W=60/6
W=10 ANS. FOR THE WIDTH.
L=2*10-3
L=20-3
L=17 ANS. FOR THE LENGTH.
PROOF:
54=2*17+2*10
54=34+20
54=54
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Triangles/312611: What are the side measurements for a right triangle with the area of 90 sq. cm.
1 solutions
Answer 223501 by checkley77(12569) on 2010-06-08 19:33:33 (Show Source):
You can put this solution on YOUR website!MANY & VARIED.
A=BH/2
90=10*18/2
90=180/2
90=90
10^2+18^2=C^2
100+324=C^2
424=C^2
C=SQRT424
C=20.59 ANS. FOR THE HYPOTENUSE.
------------------------------
90=12*15/2
90=180/2
90=90
12^2+15^2=C^2
144+225=C^2
369=C^2
C=SQRT368
C=19.9 ANS FOR THE HYPOTENUSE.
-------------------------------
90=4*45/2
90=180/2
90=90
4^2+45^2=C^2
16+2,025=C^2
2,041=C^2
C=SQRT=2,041
C=45.18 ANS FOR THE HYPOTENUSE.
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ALSO:(2 & 90), (6 & 30), (8 & 22.5) OR ANY PRODUCT=180.
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test/312492: Jim has a total of 50 coins. Some are nickels and some are quarters. Altogether he has $4.10. How many quarters does he have? How many nickels? 1 solutions
Answer 223497 by checkley77(12569) on 2010-06-08 19:13:38 (Show Source):
You can put this solution on YOUR website!N+Q=50 OR N=50-Q
.05N+.25Q=4.10
.05(50-Q)+.25Q=4.10
2.50-.05Q+.25Q=4.10
.20Q=4.10-2.50
.20Q=1.60
Q=1.60/.20
Q=8 QUARTERS.
50-8=42 NICKELS.
PROOF:
.05*42+8*.25=4.10
2.10+2=4.10
4.10=4.10
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Polynomials-and-rational-expressions/312521: Suppose you are entered in a driving contest and you are to maintain an average speed of 60 mph for 2 miles. Your engine develops a miss and you can only maintain 30 mph for the first mile. The miss disappears after the first mile and the engine returns to normal. How fast must you drive the second mile to meet the overall average speed requirement? 1 solutions
Answer 223494 by checkley77(12569) on 2010-06-08 19:01:54 (Show Source):
You can put this solution on YOUR website!60*2=120 MILES IS THE DISTANCE.
D=RT
120=30*1+X*1
120=30+X
X=120-30
X=90 MPH IS THE SPEED FOR THE SECOND MILE.
120=[(30+90)/2]2
120=[120/2]2
120=60*2
120=120
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Geometry_Word_Problems/312563: The length of a rectangular solid is 7. The width of the solid is 2 more than the height. The volume of the solid is 105. Find the width and the height of the solid. 1 solutions
Answer 223489 by checkley77(12569) on 2010-06-08 18:52:39 (Show Source):
You can put this solution on YOUR website!W=H+2
V=LWH
105=7(H+2)H
105=7(H^2+2H)
105=7H^2+14H
7H^2+14H-105=0
7(H^2+2H-15)=0
7(H+5)(H-3)=0
H-3=0
H=3 ANS. FOR THE HEIGHT.
W=3+2=5 ANS FOR THE WIDTH.
PROOF:
105=7*5*3
105=105
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Linear-systems/312578: Solve this linear system. 2y=3x+2 (Give answer in ordered pair)
Solve this linear system. 3x-4y=8 (Give answer in ordered pair) 1 solutions
Answer 223475 by checkley77(12569) on 2010-06-08 18:13:34 (Show Source):
You can put this solution on YOUR website!2y=3x+2
y=3x/2+2/2
y=3x/2+1(red line)
(-2/3,1) ans
3x-4y=8
-4y=-3x+8
y=-3x/-4+8/-4
y=3x/4-2 (green line)
(8/3,-2) ans.
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions 3x/2 +1 and 3x/4 -2).
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Graphs/312500: Regrind, Inc. regrinds used typewriter platens. The cost per platen is $1.70. The fixed cost to run the grinding machine is $112 per day. If the company sells the reground platens for $3.70, how many must be reground daily to break even? 1 solutions
Answer 223465 by checkley77(12569) on 2010-06-08 17:39:34 (Show Source):
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Miscellaneous_Word_Problems/312502: The length of a rectangular field is 50 meters more than twice it's length. If the perimeter is 700 meters, find the dimensions of the field. 1 solutions
Answer 223463 by checkley77(12569) on 2010-06-08 17:35:19 (Show Source):
You can put this solution on YOUR website!L=2W+50
P=2L+2W
700=2(2W+50)+2W
700=4W+100+2W
700=6W+100
6W=700-100
6W=600
W=600/6
W=100 ANS. FOR THE WIDTH.
L=2*100+50=200+50=250 ANS. FOR THE LENGTH.
PROOF:
700=2*250+2*100
700=500+200
700=700
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Travel_Word_Problems/312517: If 2 automoblies start at the same place and the same route and the first averge is 40 miles and the 2nd is 55 miles, how many miles along the route is the 2nd auto at the end of 5 hours? 1 solutions
Answer 223462 by checkley77(12569) on 2010-06-08 17:22:17 (Show Source):
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Numbers_Word_Problems/312531: The sum of the squares of two consecutive positive numbers is 41. What is the smaller number? 1 solutions
Answer 223460 by checkley77(12569) on 2010-06-08 17:01:15 (Show Source):
You can put this solution on YOUR website!LET X & X+1 BE THE 2 NUMBERS.
41=X^2+(X+1)^2
41=X^2+X^2+2X+1
2X^2+2X+1-41=0
2X^2+2X-40=0
2(X^2+X+420)=0
2(X+5)(X-4)=0
X-4=0
X=4 ANS FOR THE SMALLER NUMBER.
PROOF:
41=4^2+(4+1)^2
41=16+5^2
41=16+25
41=41
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Rectangles/312537: If the perimeter of a rectangle is 60 inches. If the width of the rectangle is 12 inches, then what is the length of the rectangle? 1 solutions
Answer 223453 by checkley77(12569) on 2010-06-08 16:45:46 (Show Source):
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Human-and-algebraic-language/312551: The Candy Shack sells a particular candy in two different size packages. One size sells for $1.25 and the other sells for $1.75. If the store received $65.50 for 42 packages of candy, how many of each size were sold? 1 solutions
Answer 223450 by checkley77(12569) on 2010-06-08 16:33:27 (Show Source):
You can put this solution on YOUR website!1.75x+1.25(42-x)=65.50
1.75x+52.50-1.25x=65.50
.50x=65.50-52.50
.50x=13
x=13/.50
x=26 number of $1.75 sizes sold.
42-26=16 number of $1.25 sizes sold.
Proof:
1.75*26+1.25*16=65.50
45.50+20,00=65.50
68.50=65.50
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Miscellaneous_Word_Problems/312217: Mardi received an inheritance of $70,000. She invested part at 10% and deposited the remainder in tax-free bonds at 8%. Her total annual income from the investments was $6800. Find the amount invested at 10%. 1 solutions
Answer 223240 by checkley77(12569) on 2010-06-07 18:58:28 (Show Source):
You can put this solution on YOUR website!.10x+.08(70,000-x)=6,800
.10x+5,600-.08x=6,800
.02x=6,800-5,600
.02x=1,200
x=1,200/.02
x=$60,000 amount invested @ 10%.
Proof:
.10*60,000+.08(70,000-60,000)=6,800
6,000+.08*10,000=6,800
6,000+800=6,800
6,800=6,800
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