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Recent problems solved by 'checkley77'
checkley77 answered: 12560 problems
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After how long are the bicyclists 5 miles apart? 1 solutions
Answer 224451 by checkley77(12569) on 2010-06-13 18:39:06 (Show Source):
You can put this solution on YOUR website!D=RT
D=8T
D=10T-5
8T=10T-5
8T-10T=-5
-2T=-5
T=-5/-2
T=2/5
T=2.5 HOURS THEY WILL BE 5 MILES APART.
PROOF:
8*2.5=10*2.5-5
20=25-5
20=20
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Linear-equations/313939: Please help me solve this equation world problem
If a plane can travel 480 miles per hour with the wind and 440 miles per hour against the wind, find the speed of the plane in still air 1 solutions
Answer 224449 by checkley77(12569) on 2010-06-13 18:28:37 (Show Source):
You can put this solution on YOUR website!s+w=480
s-w=400 add,
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2s=880
s=880/2
s=440 mph. speed of the plane in still air.
(480-440)=40 mph. speed of the wind.
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Rectangles/313597: Three squares have sides of different integer lengths, a, b, and c. The total area of the three squares cannot be
(A) 14 (B) 29 (C) 50 (D) 88 (E) 101 1 solutions
Answer 224308 by checkley77(12569) on 2010-06-12 18:18:07 (Show Source):
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Graphs/313564: graph this problem a.) y = 2x – 1
b.) y = (–3/4)x + 5
c.) y = x2 – 4
y = –3x2 – 6x – 5
1 solutions
Answer 224302 by checkley77(12569) on 2010-06-12 17:17:47 (Show Source):
You can put this solution on YOUR website!a.) y = 2x – 1
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 2x -1).
b.) y = (–3/4)x + 5
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -3x/4 +5).
c.) y = x^2 – 4
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, x^2 -4).
d.) y = –3x^2 – 6x – 5
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -3x^2 -6x -5 )
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Travel_Word_Problems/313574: two sculptures are similar. The height of one sculpture is four times the height of the other sculpture. The smaller sculpture is 2.5 feet tall. How tall is the larger sculpture? 1 solutions
Answer 224301 by checkley77(12569) on 2010-06-12 17:09:33 (Show Source):
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Miscellaneous_Word_Problems/313593: A box containing 5 oranges weighs 1.678 kilograms. The same box with 10
oranges in it weighs 2.278 kilograms. How much does the empty box weigh?
(Assume all oranges weigh the same.)
(A) 0.300 kg (B) 0.539 kg (C) 0.600 kg (D) 1.078 kg (E) 1.356 kg
1 solutions
Answer 224300 by checkley77(12569) on 2010-06-12 17:05:31 (Show Source):
You can put this solution on YOUR website!10X+Y=2.278
5X+Y=1.678 SUBTRACT THIS EQUATION
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5X=.6
X=.6/5
X=.12 KG. WEIGHT OF AN ORANGE.
10*.12+Y=2.278
1.2+Y=2.278
Y=2.278-1.2
Y=1.078 KG. WEIGHT OF THE BOX.
ANSWER D).
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Numbers_Word_Problems/313600: The sum of all the digits used in writing the integers from 1 to 10 is 46. What is the sum of all the digits used to write the integers from 1 to 50?
(A) 230 (B) 240 (C) 270 (D) 284 (E) 330 1 solutions
Answer 224299 by checkley77(12569) on 2010-06-12 16:54:47 (Show Source):
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Rectangles/313613: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well.
The length of a rectagle is 2 cm. more than 3 times its width. If the area of the rectange is 95 cm^2, find the dimensions of the rectangle. 1 solutions
Answer 224298 by checkley77(12569) on 2010-06-12 16:43:13 (Show Source):
You can put this solution on YOUR website!L=3W+2
A=LW
95=(3W+2)W
95=3W^2+2W
3W^2+2W-95=0
W=(-2+-SQRT[2^2-4*3*-95])/2*3
W=(-2+-SQRT[4+1,140])/6
W=(-2+-SQRT1,144)/6
W=(-2+-33.823)/6
W=(-2+33.823)/6
W=31.823/6
W=5.304 ANS.
W=(-2-33.823)/6
W=-35.823/6
W=-5.967 ANS.
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Rectangles/313614: Solve the following application problem (show your equation and then your solution). Round answers to nearest thousandths and properly label your answer as well.
A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 15ft by 25ft. The total area, garden plus walkway, is to be 650ft^2. What must be the width of the walkway? 1 solutions
Answer 224294 by checkley77(12569) on 2010-06-12 16:30:37 (Show Source):
You can put this solution on YOUR website!(15+2X)(25+2X)=650
375+50X+30X+4X^2=650
4X^2+80X+375-650=0
4X^2+80X-275=0
X=(-80+-SQRT[80^2-4*4*-275])/2*4
X=(-80+-SQRT[6,400+4,400])/8
X=(-80+-SQRT10,800)/8
X=(-80+-103.923)/8
X=(-80+103.923)/8
X=23.923/8
X=2.99 ANS. FOR THE WIDTH OF THE WALKWAY.
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Problems-with-consecutive-odd-even-integers/313618: Ten consecutive integers are arranged in order from least to greatest. If the sum of the first five integers is 200, what is the sum of the last five integers ?
1 solutions
Answer 224290 by checkley77(12569) on 2010-06-12 16:17:18 (Show Source):
You can put this solution on YOUR website!X+X+1+X+2+X+3+X+4=200
5X+10=200
5X=200-10
5X=190
X=190/5
X=38 ANS. FOR THE FIRST INTEGER.
38+1=39 ANS. THE SECOND INTEGER.
38+2=40 ANS. FOR THE THIRD INTEGER.
38+3=41 ANS. FOR THE FOURTH INTEGER.
38+4=42 ANS. FOR THE FIFTH INTEGER.
43+44+45+46+47=225 ANS. FOR THE SUM OF THE NEXT FIVE INTEGERS.
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test/313619: Find an equation of variation in which y varies directly as x and y=12 when x=1/3. Then find the value of y when x=20. 1 solutions
Answer 224289 by checkley77(12569) on 2010-06-12 16:10:52 (Show Source):
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test/313621: The distance d traveled by a car varies directly as the time t. A car travels 60 km in 2/3 hr. How far will it travel in 6 hr? 1 solutions
Answer 224288 by checkley77(12569) on 2010-06-12 16:05:44 (Show Source):
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test/313628: Find an equation of the line containing the pair of points (-6,3) and (1,1). 1 solutions
Answer 224287 by checkley77(12569) on 2010-06-12 15:58:46 (Show Source):
You can put this solution on YOUR website!(-6,3) and (1,1)
Y=mX+b
m=slope=(y2-y1)/x2-x1)
m=(1-3)/(1+6)
m=-2/7 ans. for the slope.
1=-2/7*1+b
1=-2/7+b
b=1+2/7
b=7/7+2/7=9/7 ans. for the y intercept.
Y=-2X/7+9/7
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -2x/7 +9/7).
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Miscellaneous_Word_Problems/313635: Last month a factory produced 800 tv's. This month they producted 1,064 tv's. The increase in production from last month to this month is what percentage?
An electronic device that perviously sold $21 has been reduced to $17.43. The price reduction rounded to the nearest percent is what? 1 solutions
Answer 224285 by checkley77(12569) on 2010-06-12 15:48:25 (Show Source):
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Circles/313643: Find the area of a circle with radius 3 units. Give your answer in terms of and as a decimal rounded to the nearest tenth. Use 3.14 for the approximation of .
1 solutions
Answer 224281 by checkley77(12569) on 2010-06-12 15:38:20 (Show Source):
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Triangles/313653: 1)The base of a parallelogram is 10 inches.The height is 2 inches more than half the base.Find the are.
2)The height of a parallelogram is 4.5cm.The base is twice the height.What is the area?
3)The area of a parallelogram is 6 ft squared.The height is 5ft.How long is the base?
4)The are of a parallelogram is375 cm squared.The base is 25cm. Find the height.
1 solutions
Answer 224279 by checkley77(12569) on 2010-06-12 15:31:47 (Show Source):
You can put this solution on YOUR website!1) AREA=B*H
AREA=10*(10/2+2)
AREA=100/2+20
AREA=50+20=70 IN^2. ANS.
2) AREA=2*4.5*4.5
AREA=40.5 IN^2 ANS.
3) 6^2=B*5
36=5B
B=36/5
B=7.2 FT. ANS.
4) 375=25H
H=375/25
H=15 cm^2. ans.
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Equations/313678: the perimeter of a rectangle is 24 cm. the are of the same rectangle is 20 sq. cm. find the sides of the rectangle without using calculus. 1 solutions
Answer 224274 by checkley77(12569) on 2010-06-12 15:19:20 (Show Source):
You can put this solution on YOUR website!24=2L+2W
20=LW OR L=20/W
REPLACING L IN THE FIRST EQUATION BY (20/W) & SOLVE FOR W.
24=2(20/W)+2W
24=40/W+2W
24=(40+2W*W)/W
24=(40+2W^2)/W CROSS MULTIPLY.
24*W=40+2W^2
24W=40+2W^2
2W^2-24W+40=0
2(W^2-12W+20)=0
2(W-10)(W-2)=0
W-10=0
W=10 ANS.
L=20/10=2 ANS.
W-2=0
W=2 ANS.
L=20/2=10 ANS.
PROOF:
20=2*10
20=20
24=2*10+2*2
24=20+4
24=24
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