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checkley77 answered: 12560 problems
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Average/326175: four empty trucks are on a bridge that has a maximum capacity of 30,000 pounds. If the average (arithmetic mean) weight of three of the trucks is 7,800 pounds, what is the greatest possible safe weight of the fourth truck?
1 solutions

Answer 233466 by checkley77(12569) About Me  on 2010-07-27 16:37:20 (Show Source):
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3*7,800+x=30,000
23,400+x=30,000
x=30,000-23,400
x=6,600 pounds for the 4 th. truck.


Quadratic_Equations/325806: The flower garden has the shape of a right traingle. 51 ft. of a perennial border forms the hypotenuse of the traingle, and one leg is 21 ft. longer than the other leg. Find the lengths of the legs. What are the lengths of the legs in ft?
1 solutions

Answer 233269 by checkley77(12569) About Me  on 2010-07-26 20:48:05 (Show Source):
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X^2+(X+21)^2=51^2
X^2+X^2+42X+441=2,601
2X^2+42X+441-2,601=0
2X^2+42X-2,160=0
2(X^2+21X-1,080)=0
2(X-24)(X+45)=0
X-24=0
X=24 ANS.
X+45=0
X=-45 ANS.


Miscellaneous_Word_Problems/325809: Millie and Samantha began saving money at the same time. Millie plans to save $3 a month, and Samantha plans to save $5 a month. After how many months will Samantha have saved exactly $10 more than Millie?
1 solutions

Answer 233264 by checkley77(12569) About Me  on 2010-07-26 20:40:12 (Show Source):
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86-70=16
92-86=6
6:16=3:8
86*8+92*3=86*(8+3)
688+276=86*11
964=946


Problems-with-consecutive-odd-even-integers/325836: What is the difference between two integers is 38. one integer is three times as great as the other. find the intergers
1 solutions

Answer 233256 by checkley77(12569) About Me  on 2010-07-26 20:21:50 (Show Source):
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X-Y=38
X=3Y
3Y-Y=38
2Y=38
Y=38/2
Y=19 ANS
PROOF:
X=3*19=57
PROOF:
57-19=38
38=38 ANS.


Polynomials-and-rational-expressions/325842: 25x^2 + 10x + 1
1 solutions

Answer 233255 by checkley77(12569) About Me  on 2010-07-26 20:14:57 (Show Source):
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25x^2 + 10x + 1
(5x+1)^2 ans.


Polynomials-and-rational-expressions/325847: Solve using the principle of zero products
(5t − 8)(t − 1) = 0

1 solutions

Answer 233254 by checkley77(12569) About Me  on 2010-07-26 20:13:18 (Show Source):
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(5t − 8)(t − 1) = 0
5t-8=0
5t=8
t=8/5 ans.
t-1=0
t=1 ans.


Polynomials-and-rational-expressions/325855: Complete the factorization.
2x^2 = 2x( )

1 solutions

Answer 233251 by checkley77(12569) About Me  on 2010-07-26 20:10:50 (Show Source):
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2x^2 = 2x(x) ans.


Polynomials-and-rational-expressions/325860: Solve using the principle of zero products.
(y - 7)(4y + 12)(y + 13) = 0
1 solutions

Answer 233249 by checkley77(12569) About Me  on 2010-07-26 20:09:05 (Show Source):
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(y - 7)(4y + 12)(y + 13) = 0
y-7=0
y=7 ans.
4y+12=0
4y=-12
y=-12/4
y=-3 ans.
y+13=0
y=-13 ans.


Polynomials-and-rational-expressions/325861: Factor completely. Show all work necessary.
x^2 + 24x + 144

1 solutions

Answer 233246 by checkley77(12569) About Me  on 2010-07-26 20:06:41 (Show Source):
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x^2 + 24x + 144
(x+12)^2 ans.


Exponents/325857: Hi-
Can you help me with this problem please?
Evaluate
-4 x 5+((-1)^3-3)^2
1 solutions

Answer 233244 by checkley77(12569) About Me  on 2010-07-26 20:05:19 (Show Source):
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-4 x 5+((-1)^3-3)^2
-20+(-1-3)^2
-20+(-4)^2
-20+16=-4 ans.


Polynomials-and-rational-expressions/325358: Please solve by factoring and show how it is worked. I worked it and came up with the answer of 16. Thank you
a+7÷a-4+9-5a÷a-4
I worked it and came up with 16
a+7÷a-4+9-5a÷a-4 = a-5a+7+9÷a-4 = -4a+16÷a-4 = 16
1 solutions

Answer 233027 by checkley77(12569) About Me  on 2010-07-25 13:49:27 (Show Source):
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I worked it and came up with 16
a+7÷a-4+9-5a÷a-4
a-5a[+a)+7[-4]+9÷a-4 YOU LOST THE -4 & THE +a
-2a+16-4-4=-2a+8=-2(a-4) ans.


Average/325369: On a recent quiz 6 students received course averaging 92 . The remaining students in the class received scores averaging 89 .if the quiz grades for the entire class averaged 90 .how many students were in the class ?

1 solutions

Answer 233025 by checkley77(12569) About Me  on 2010-07-25 13:41:23 (Show Source):
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6*92+89X=90(6+X)
552+89X=540+90X
89X-90X=540-552
-X=-12
X=12 STUDENTS AVERAGED 90 ON THE TESTS.
PROOF:
6*92+89*12=90(6+12)
552+1,068=90*18
1,620=1,620


Miscellaneous_Word_Problems/325373: How many six-inch square tiles are needed to tile the floor in a room that is 12 feet by 15 feet?
1 solutions

Answer 233024 by checkley77(12569) About Me  on 2010-07-25 13:35:15 (Show Source):
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12*15=180 FT^2 IS THE AREA.
A 6 IN. SQUARE TILE=1/2*1/2=1/4 FT^2
180/(1/4)=180*4=720 TILES WILL BE NEEDED.


Circles/325377: A circle has a radius of 8 inches. Find the area of a sector of the circle if the sector has an arc that measures 45°.
1 solutions

Answer 233023 by checkley77(12569) About Me  on 2010-07-25 13:31:06 (Show Source):
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A=PIR^2
A=3.14*8^2
A=3.14*64
A=200.96 INCHES^2 ANS. FOR THE AREA OF THE CIRCLE.
BECAUSE AN ARC OF 45 DEGREES IS 45/360=.125 OF THE AREA.
THEN:
.125*200.96=25.12 INCHES^2


Numbers_Word_Problems/325378: four times a number, added to the sum of the number and five
1 solutions

Answer 233022 by checkley77(12569) About Me  on 2010-07-25 13:26:18 (Show Source):
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4X+(X+5) ans.


Linear_Algebra/325380: Ok...here goes...I am attempting to find the sum of the polynomials:
6x^3-2x^4+9 and -2x^4+3x+3
I think this is the way to complete the problem, if at all possible can someone confirm this and if i am wrong please assist me in understanding what I have done wrong...
My thoughts:
write equation
(6x^3-2x^4+9)+(-2x^4+3x+3)combine like terms
6x^3(-2x^4+(-2x^4)+3x+3+9
6x^3-4^4+3x+12
basically resulting in the answer being
-4^4+6x^3+3x+12
I would appreciate any feed back on this problem and thank you in advance for your time and help
1 solutions

Answer 233021 by checkley77(12569) About Me  on 2010-07-25 13:23:35 (Show Source):
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6x^3-2x^4+9 and -2x^4+3x+3
I think this is the way to complete the problem, if at all possible can someone confirm this and if i am wrong please assist me in understanding what I have done wrong...
My thoughts:
write equation
(6x^3-2x^4+9)+(-2x^4+3x+3)combine like terms
6x^3(-2x^4+(-2x^4)+3x+3+9
6x^3-4[X]4+3x+12 (you left out the X)
basically resulting in the answer being
-4[X]^4+6x^3+3x+12 (you did it again!)


Miscellaneous_Word_Problems/325386: Find the length for side a in the right triangle, if b=4 and c=5.
1 solutions

Answer 233020 by checkley77(12569) About Me  on 2010-07-25 13:18:06 (Show Source):
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a^2+b^2=c^2
a^2+4^2=5^2
a^2+16=25
a^2=25-16
a^2=9
a=sqrt9
a=3 ans. for side a.


Quadratic_Equations/325398: if the sides of a square are lenghtened by 8cm, the area becomes 225cm2.Find the lenght of a side of the original square
1 solutions

Answer 233019 by checkley77(12569) About Me  on 2010-07-25 13:15:03 (Show Source):
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(X+8)^2=225
X^2+16X+64-225=0
X^2+16X-161=0
(X=23)(X-7)=0
X-7=0
X=7 cm. was the original square sides.
Proof:
(7+8)^2=225
15^2=225
225=225


Human-and-algebraic-language/325400: Miriam is four years older than Ricardo. Ten yeras ago Miriam was 3 times as old as Ricardo was then.
A. How old are they now?
B. Determine whether your answer is correect by checking that it satisfies the conditions of the problem.
1 solutions

Answer 233018 by checkley77(12569) About Me  on 2010-07-25 13:10:10 (Show Source):
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R=X
M=X+4
(X+4)-10=3(X-10)
X+4-10=3X-30
X-6=3X-30
X-3X=-30+6
-2X=-24
X=-24/-2
X=12 AGE OF RICARDO NOW.
12=4=16 AGE OF MIRIAM NOW.
PROOF:
16-10=3(12-10)
6=3*2
6=6


Human-and-algebraic-language/325401: In a collge there are 13 times as many students as professors. If together the students and professors number 28,000. how many students are there in the college?
1 solutions

Answer 233016 by checkley77(12569) About Me  on 2010-07-25 13:04:06 (Show Source):
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X+13X=28,000
14X=28,000
X=28,000/14
X=2,000 NUMBER OF PROFESSORS.
13*2,000=26,000 NUMBER OF STUDENTS.
PROOF:
2,000+26,000=28,000
28,000=28,000


Problems-with-consecutive-odd-even-integers/325142: The product of two consecutive positive odd integers is one less than three times their sum. Find the integers.
can someone show me how to set this up im so confused
1 solutions

Answer 232933 by checkley77(12569) About Me  on 2010-07-24 18:42:11 (Show Source):
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X & X+2 ARE THE 2 CONSECUTIVE INTEGERS.
X(X+2)=3(X+X+2)-1
X^2+2X=3(2X+2)-1
X^2+2X=6X+6-1
X^2+2X-6X-5=0
X^2-4X-5=0
(X-5)(X+1)=0
X-5=0
X=5 ANS.
5+2=7 ANS.
X+1=0
X=-1 ANS.
-1+2=1 ANS.
PROOF:
5*7=3(5+7)-1
35=3*12-1
35=36-1
35=35


Expressions-with-variables/325146: Find the indicated outputs for f(x)= 3x(to the second power) - 4x
f(0)=
f(-1)=
f(2)=
1 solutions

Answer 232931 by checkley77(12569) About Me  on 2010-07-24 18:35:26 (Show Source):
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f(x)= 3x^2 - 4x
f(0)=3*0^2-4*0
F(0)=0+0=0 ANS.
f(-1)=3(-1)^2-4(-1)
F(-1)=3*1+4
F(-1)=3+4=7 ANS.
f(2)=3*2^2-4*2
F(2)=3*4-8=12-8=4 ANS.


Equations/325152: Write a general formula to describe the variation if v varies directly with t and v = 1.6 when t =.8
1 solutions

Answer 232930 by checkley77(12569) About Me  on 2010-07-24 18:30:34 (Show Source):
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V/T
1.6/.8=2 ANS.


Quadratic_Equations/325153: Roberto invested some money at 7%, and then invested $2000 more than twice this amount at 9%. His total annual income from the two investments was $2930. How much was invested at 9%?

1 solutions

Answer 232928 by checkley77(12569) About Me  on 2010-07-24 18:28:30 (Show Source):
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.09(2x+2,000)+.07x=2,930
.18x+180+.07x=2,930
.25x=2,930-180
.25x=2,750
x=2,750/.25
x=11,000 ans. for the amount invested @ 7%.
2*11,00+2,000
22,000+2,000=24,000 ans. for the amount invested @ 9%.
Proof:
.09*24,000+.07*11,000=2,930
2,160+770=2,930
2,930=2,930


Miscellaneous_Word_Problems/325173: the growth of a town's population is modeled by p=104e^0.03t how large will the population be when t=24
1 solutions

Answer 232921 by checkley77(12569) About Me  on 2010-07-24 18:09:22 (Show Source):
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p=104e^0.03t
p=104*2.7182^(.03*24)
p=104*2.7182^.72
p=104*1.71
p=178 ans.


Exponential-and-logarithmic-functions/325174: I need help solving this. I keep getting an answer with negative exponents.
9x^-12
_______
24x^-2
1 solutions

Answer 232918 by checkley77(12569) About Me  on 2010-07-24 18:00:21 (Show Source):
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9x^-12
_______
24x^-2
9/24=3/8
X^-12/X^-2
1/X^(12-2)
1/X^10
3/8X^10 ans.


Geometry_Word_Problems/325183: A swimming pool 100 metres long and 40 metres wide is 1 metre deep at the shallow end and 5 metre at the deep end. Find the volume (in cubic metres) of water contained in the pool.
1 solutions

Answer 232915 by checkley77(12569) About Me  on 2010-07-24 17:55:59 (Show Source):
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100*40(1+5)/2
4,000*6/2
4,000*3=12,000 CUBIC METERS OF WATER.


Triangles/325185: The Perimeter of a Triangle is 42 inches the second side is 1 inch more than twice the first side and the third side is 1 inch less than 3 times the first side. Find the lengths of the 3 sides of the triangle.
I need an inequality set up.
P=42
would my inequality be: x>1(2x + side 1) x>1(3x side 1)??

1 solutions

Answer 232913 by checkley77(12569) About Me  on 2010-07-24 17:53:21 (Show Source):
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S2=2*S1+1
S3=3*S1-1
P=S1+S2+S3
42=S1+2*S1+1+3*S1-1
42=6*S1
S1=42/6
S1=7 ANS. FOR S1.
S2=2*7+1=14+1=15 ANS FOR S2.
S3=3*7-1=21-1=20 ANS. FOR S3.
PROOF:
42=7+15+20
42=42


test/325195: I need help factoring perfect square trinomials such as
25x^2-120+144
49x^2+84+36
1 solutions

Answer 232910 by checkley77(12569) About Me  on 2010-07-24 17:46:43 (Show Source):
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25x^2-120+144
(5X-12)^2 ANS.
49x^2+84+36
(7X+6)^2 ANS.


Travel_Word_Problems/325215: the speed of train A is 14mph slower than the speed of train B. train A travels 200 miles in the same time it takes train B to travel 270 miles. find the speed of each train.
1 solutions

Answer 232908 by checkley77(12569) About Me  on 2010-07-24 17:43:26 (Show Source):
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D=RT
200=(R-14)T
T=200/(R-14)
270=RT
T=270/R
200/(R-14)=270/R
270(R-14)=200R
270R-3,780=200R
270R-200R=3,780
70R=3.780
R=3,780/70
R=54 ANS. FOR TRAIN B.
54-14=40 ANS. FOR TRAIN A.
PROOF:
200=40T
T=200/40
T=5 HOURS.
5=270/54
5=5


Miscellaneous_Word_Problems/325255: This is the word problem. Thanks!:
Jane and Tariq took a canoeing trip, traveling 6 mi upsteam against a 2 mi/h current. They then returned to the same point downstream. If their entire trip took 4 h, how fast can they paddle in still water? (Hint: If r is their rate, in mi/h, in still water, their rate upstream is r-2 and their rate dwonstream is r+2)
1 solutions

Answer 232903 by checkley77(12569) About Me  on 2010-07-24 17:31:12 (Show Source):
You can put this solution on YOUR website!
D=RT
T=D/R
4=6/(R+2)+6(R-2)
4=[6(R-2)+6(R+2)]/(R+2)(R-2)
4=(6R-12+6R+12)/(R^2-4)
4=12R/(R^2-4)
4(R^2-4)=12R
4R^2-16-12R=0
4R^2-12R-16=0
4(R^2-3R-4)=0
4(R-4)(R+1)=0
R-4=0
R=4 ANS FOR THE RATE OF THE CANOE IN STILL WATER.
PROOF:
4=6/(4+2)+6/(4-2)
4=6/6+6/2
4=1+3
4=4