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Inequalities/147729: The members of a drama club are selling tickets to their next production. If their goal is to raise at least $350 the number of tickets they must sell at $2.20 each in order to meet their goal can be expressed by the inequality 2.20x>350. Is 163 a solution of the inequality? 1 solutions
Answer 108110 by checkley77(12569) on 2008-07-09 17:16:47 (Show Source):
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Systems-of-equations/147408: An airplane flew for 3 hours with a tail wind of 40 km/hr. The Return flight against the same wind took 4 hours. Find The Speed of the airplane in still air. 1 solutions
Answer 107841 by checkley77(12569) on 2008-07-07 15:11:31 (Show Source):
You can put this solution on YOUR website!D=RT
SEEING AS THE DISTANCES ARE THE SAME WE HAVE:
(R+40)3=(R-40)4
3R+120=4R-160
3R-4R=-160-120
-R=-280
R=280 KM/HR THE PLANES SPEED IN STILL AIR.
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Mixture_Word_Problems/147450: If grade A coffee costs .95 cents a pound and grade b coffee costs .75 cents a pound, how many pounds of each grade is needed if the total cost is $50.50, and the amount of grade b that is needed is twice the amount needed for grad A plus 5 pounds? 1 solutions
Answer 107839 by checkley77(12569) on 2008-07-07 15:05:40 (Show Source):
You can put this solution on YOUR website!.95x+.75(2x+5)=50.50
.95x+1.5x+3.75=50.50
2.45x=50.50-3.75
2.45x=46.75
x=46.75/2.45
19.08 lbs. of $.95 coffee is used
2*19.08+5=43.16 lbs. of $.75 coffee is used
proof
.95*19.08+.75*43.16=50.50
18.13+32.37
50.50=50.50
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Linear-systems/147355: Hi, I dont know what Im doing wrong I need help please. Here is the question: One year ago you invested $4300 into three accounts that earn 3.25%, 4%, and 5.75% annual interest. The interest you earned after one year is $193. You remembered you invested three times as much in the 4% account than you did the 3.25% account. How much did you invest in each type of account? This is what i have so far, I dont think its right.
x + y + Z = 4300
325x + 400Y + 575z = 19300
Y=3x
x + (3x) + Z = 4300
4x + z = 4300
325x + 400 (3x) + z =19300
1525x +575z = 19300
(-575) 4x + z = 4300 (-575)
-2300x - 575z =-2472500
1525x + 575z = 19300
-775x = -2453200
x=3165.4 then when I do 3 times x to get y it doesnt fit with the total of 4300. I dont know please help me thank you.
1 solutions
Answer 107731 by checkley77(12569) on 2008-07-06 16:20:48 (Show Source):
You can put this solution on YOUR website!x+y+z=4300 (multiply by -.0575 & subtract. You neglected to change the % to decimals.)
.0325x+.04y+.0575z=193
-.0575x-.0575y-.0575z=-247.25
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-.0255x-.0175y=-54.25
y=3x
-.0255x-.0175*3x=-54.25
-.0255x-.0525x=-54.25
-.078x=-54.75
x=-54.25/-.078
x=695.52 amount invested @ 3.25%
3*695.52=2,086.54 amount invested @ 4%
695.52+2,086.54+y=4,300
y=4,300-695.52-2,086.54
y=1,517.94 amount invested @ 5.75%
proof:
.0325*695.52+.04*2,086.54+.0575*1,517.94=193
22.60+83.46+87.28=193
193~193
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Linear-equations/147306: can you please solve the equation:2x (3+4x)-4x(3-6x)is greater or less than10.
thank you 1 solutions
Answer 107681 by checkley77(12569) on 2008-07-06 07:36:33 (Show Source):
You can put this solution on YOUR website!2x(3+4x)-4x(3-6x)>=10
6x+8x^2-12x+24x^2-10>=0
32x^2-6x-10>=0
2(16x^2-3x-5)>=0
using the quadratic equation:  we get:
x=(3+-sqrt[-3^2-4*16*-5])/2*16
x=(3+-sqrt[9+320])/32
x=(3+-sqrt329)/32
x=(3+-18.14)/32
x=(3+18.14)/32
x=21.14/32
x=.66 answer.
x=(3-18.14)/32
x=-15.14/32
x=-.473 answer.
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Linear-equations/147307: can you please solve the equation:2x (3+4x)-4x(3-6x)is greater or less than10.
thank you 1 solutions
Answer 107680 by checkley77(12569) on 2008-07-06 07:35:15 (Show Source):
You can put this solution on YOUR website!2x(3+4x)-4x(3-6x)>=10
6x+8x^2-12x+24x^2-10>=0
32x^2-6x-10>=0
2(16x^2-3x-5)>=0
using the quadratic equation:  we get:
x=(3+-sqrt[-3^2-4*16*-5])/2*16
x=(3+-sqrt[9+320])/32
x=(3+-sqrt329)/32
x=(3+-18.14)/32
x=(3+18.14)/32
x=21.14/32
x=.66 answer.
x=(3-18.14)/32
x=-15.14/32
x=-.473 answer.
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Miscellaneous_Word_Problems/147222: trains a and b are traveling in the same direction on parallel tracks. train a is traveling at 80 miles per hour and train b is traveling at 90 per hour train a passes a station at 5:20 am. if train b passes the same station at 5:50 am, what time will train b catch up to train a? 1 solutions
Answer 107589 by checkley77(12569) on 2008-07-05 09:56:08 (Show Source):
You can put this solution on YOUR website!80T=90(T-.5)
80T=90T-45
80T-90T=45
-10T=-45
T=-45/-10
T=4.5 HOUR AFTER a LEAVES THE STATION THEY WILL MEET. OR @ 9:50.
PROOF
80*4.5=90(4.5-.5)
360=90*4
360=360
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Travel_Word_Problems/147094: Brian and Jake left their homes, which are 500 miles apart, and drove straight toward each other. It took 4 hours for the two to meet. If Jake's speed was 15 mph slower than Brian's speed, what was Brian's speed? 1 solutions
Answer 107431 by checkley77(12569) on 2008-07-02 15:19:18 (Show Source):
You can put this solution on YOUR website!4X+4(X-15)=500
4X+4X-60=500
8X=500+60
8X=560
X=560/8
X=70 MPH FOR THE BRIAN'S SPEED.
70-15=55 FOR JEFF'S SPEED
PROOF:
4*70+4*55=500
280+220=500
500=500
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Geometry_Word_Problems/147090: I need help on how to solve this word problem.
(((The area of triangle is 462m^2 if the altitude is 2m longer than half the base find the altitude and base of the triangle.))) 1 solutions
Answer 107430 by checkley77(12569) on 2008-07-02 15:13:37 (Show Source):
You can put this solution on YOUR website!AREA=B*H/2
462=B(B/2+2)/2
462=[B(B+4)/2]/2
462=(B^2+4B)/2*1/2
462=(B^2+4B)/4
4*462=B^2+4B
1,848=B^2+4B
B^2+4B-1,848=0
USING THE QUADRATIC EQUATION:
B=(-4+-SQRT4^2-4*1*-1848})/281
B=(-4+-SQRT[16+7,392])/2
B=(-4+-SQRT7,408)/2
B=(-4+-86.07)/2
B=(-4+86.07)/2
82.07/2
B=41.03 FOR THE LENGTH OF THE BASE
H=2+41.03/2=2+20.52=22.52 FOR THE HEIGHT
PROOF
462=41.03*22.52/2
462~462
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