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checkley75 answered: 3664 problems
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Geometry_Word_Problems/75524: This question is from textbook McDougal Littell Middle School Math Course 2 2004
Hi - Please help. My son has a problem on a worksheet that I cannot help him figure out. An 18 Ft ladder is leaning against a wall. If the base of the ladder is 9 Ft from the wall, how far up the wall will the ladder reach? Thank You!!
1 solutions

Answer 54168 by checkley75(3666) About Me  on 2007-03-22 20:55:14 (Show Source):
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USING THE PATHAGORIAN FORMULA A^2+B^2=C^2. WE GET:
9^2+X*2=18^2
81+X^2=324
X^2=324-81
X^2=243
X=15.588 FEET IS THE DISTANCE UP THE WALL THE LADDER REACHES.


Complex_Numbers/75526: what are all solutions of
x^2-10x+3=0
1 solutions

Answer 54167 by checkley75(3666) About Me  on 2007-03-22 20:50:30 (Show Source):
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X^2-10X+3=0
X=(10+-SQRT[-10^2-4*1*3])/2*1
X=(10+-SQRT[100-12])/2
X=(10+-SQRT88)/2
X=(10+-9.38)/2
X=(10+9.38)/2
X=19.38/2
X=9.69 ANSWER.
X=(10-9.38)/2
X=.62/2
X=.31 ANSWER.


Numbers_Word_Problems/75533: This question is from textbook Elementary algebra
This is from the Chapter 4 - test, and I have no notes or examples.
s=35 + 0.5s
just not sure what I do.
Thanks

1 solutions

Answer 54166 by checkley75(3666) About Me  on 2007-03-22 20:44:24 (Show Source):
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s=35+0.5s
s-0.5s=35
0.5s=35
s=35/0.5
s=70 answer.


Square-cubic-other-roots/75318: This question is from textbook Alegbra 2 An Incremental Development
Help to simplify :
5 times the square roo ot 16 times the square root o 2
1 solutions

Answer 54157 by checkley75(3666) About Me  on 2007-03-22 16:21:09 (Show Source):
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5*SQRT16*SQRT2
5*4*SQRT2
20*SQRT2
20*1.414=28.28 ANSWER.


Square-cubic-other-roots/75325: This question is from textbook Alegbra 2 An Incremental Development
Help to simplify :
4 times the square root of 8 times the square root of 2
1 solutions

Answer 54156 by checkley75(3666) About Me  on 2007-03-22 16:18:03 (Show Source):
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4SQRT8*SQRT2
4SQRT(4*2)SQRT2
4*2QRT2*SQRT2
4*2*2=16 ANSWER.


Polynomials-and-rational-expressions/75345: x+2y=4
3x-2y=4
1 solutions

Answer 54154 by checkley75(3666) About Me  on 2007-03-22 16:11:39 (Show Source):
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X+2Y=4, X=-2Y+4
3X-2Y=4 NOW SUBSTITUTE (-2Y+4) FOR X & SOLVE FOR Y:
3(-2Y+4)-2Y=4
-6Y+12-2Y=4
-8Y=4-12
-8Y=-8
Y=-8/-8
Y=1 ANSWER.
X=-2*1+4
X=-2+4
X=2 ANSWER.
PROOF
3*2-2*1=4
6-2=4
4=4


real-numbers/75468: Which of the following is/true?
A.The prime factors of 20 are 4 and 5.
B.The HCF of 12 and 20 is 2.
C.The LCM of 2,10 and 14 is 70.
1 solutions

Answer 54153 by checkley75(3666) About Me  on 2007-03-22 16:04:34 (Show Source):
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A. NOT TRUE. 1,2,4,5,10 &20 ARE ALL FACTORS OF 20.
B. NOT TRUE. 4 IS THE HCF OF 12 & 20 [4*3 & 4*5]
C. YES. 2,2*5,2*7 2*5*7=70


Geometry_Word_Problems/75470: Here is the question. I even know the answer. However, I do not know how to solve it.
"A woman walks home by traveling 20 meters north, 25 meters east, and then 5 more meters north. If she could walk home along a straight line, how many fewer meters would she need to walk? Round your answer to the nearest hundredth."
The answer is 14.64 meters.
1 solutions

Answer 54152 by checkley75(3666) About Me  on 2007-03-22 16:00:31 (Show Source):
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THE BEST WAY TO SOLVE THIS PROBLEM IS WITH A GRAPH USING X & Y COORDINATES.
START AT THE INTERSECTION (0,0), GO UP (NORTH) 25 UNITS, THEN GO 20 UNITES TO THE RIGHT (EAST) THEN ANOTHER 5 UP (NORTH).
YOU ARE NOW AT (25,25). NOW DRAW A LINE FROM HERE TO THE ORIGIN (0,0) AND YOU HAVE THE HYPOTENUSE OF A 25 BY 25 RIGHT TRIANGLE.
USING THE FORMULA A^2+B^2=C^2 WE HAVE
25^2+25^2=C^2
625+625=C^2
1250=C^2
C=35.36 METERS IS THE LENGTH OF THE WALK HOME.
50-35.36=14.64 METERS IS THE DIFFERENCE BETWEEN THE TWO WALKS.


Numbers_Word_Problems/75454: Suppose you have two numbers. The difference of the two numbers is 12. The product of the two numbers is 17. Multiply the larger of the two numbers by 100, add 50 times the smaller number to that, round the total to the nearest whole number and thats the answer.
1 solutions

Answer 54150 by checkley75(3666) About Me  on 2007-03-22 15:50:30 (Show Source):
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X-Y=12, X=Y+12
XY=17
(Y+12)Y=17
Y^2+12Y-17=0
USING THE QUADRATIC EQUATION WE GET:
X=(-12+-SQRT[-12^2-4*1*-17])/2*1
X=(-12+-SQRT[144+68])/2
X=(-12+-SQRT212)/2
X=(-12+-14.56)/2
X=(-12+14.56)/2
X=2.56/2
X=1.28 ANSWER.
X=(-12-14.56)/2
X=-26.56/2
X=-13.28 ANSWER.
1.28*100+(-13.28*50)
128-662.5
-535 FINAL ANSWER.


Problems-with-consecutive-odd-even-integers/75463: A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30 ft by 40 ft. The total area, garden plus walkway, is to be 1800 ft2. What must be the width of the walkway to the nearest thousandth?

please show work
1 solutions

Answer 54149 by checkley75(3666) About Me  on 2007-03-22 15:39:19 (Show Source):
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(30+2x)(40+2x)=1800
1200+80x+60x+4x^2=1800
4x^2+140x+1200-1800=0
4x^2+140x-600=0
x^2+35x-150=0
using the quadratic equation we get:
X=(-35+-SQRT[35^2-4*1*-150])/2*1
X=(-35+-SQRT[1225+600])/2
X=(-35+-SQRT1825)/2
X=(-35+-42.72)/2
X=(-35+42.72)/2
X=-7.72/2
X=3.86 ANSWER.
X=(-35-42.72)/2
X=-77.72/2
X=-38.86 ANSWER.


Problems-with-consecutive-odd-even-integers/75464: The length of a rectangle is 3 cm more than 5 times its width. If the area of the rectangle is 62 cm2, find the dimensions of the rectangle to the nearest thousandth.
show work please
1 solutions

Answer 54148 by checkley75(3666) About Me  on 2007-03-22 15:20:33 (Show Source):
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L=5W+3
W+(5W+3)=62
W+5W+3=62
6W=62-3
6W=59
W=59/6
W=9.833 CM LENGTH OF THE WIDTH.
L=5*9.8333+3
L=52.167 CM. IS THE LENGTH.


Square-cubic-other-roots/75410: Is it possible to find the square root of a number that is not a perfect square without a calculator? Such as 80? 195? etc...
1 solutions

Answer 54093 by checkley75(3666) About Me  on 2007-03-21 22:11:59 (Show Source):
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YES BUT IT IS MESSY:
&&&&&&&&&8.944 IS THE SQRT OF 80
&&&&&&&&&--------------
&&&&&&8)80.000000
&&&&&&&)64 DOUBLE THE 8 & ADD THE 9
------------------------
xxxx169)1600
XXXXXXXX1521
--------------------------
&&&&&1784)7900 DOUBLE THE 89 & ADD THE 4
&&&&&&&&&&7136
-----------------------
&&&&&17884)76400 DOUBLE THE 894 & ADD THE 4
&&&&&&&&&&&71536
----------------------
&&&&&&&&&&&&4864


Equations/75330: I am not sure if I am doing this problem right?
x-24
_______ =13
4

1 solutions

Answer 54085 by checkley75(3666) About Me  on 2007-03-21 21:46:00 (Show Source):
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(x-24)/4=13 now cross multiply
x-24=4*13
x-24=52
x=52+24
x=76 answer.
proof
(76-24)/4=13
52/4=13
13=13


Word_Problems_With_Coins/75365: A coffee merchant has coffee beens that sell for $9 p/lb & $12 p/lb. the two types are mixed to to create 100 lb of a mixture to sell for $11.25 p/lb. How much of each type of bean should be used in the mixture?
1 solutions

Answer 54083 by checkley75(3666) About Me  on 2007-03-21 21:41:27 (Show Source):
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100*11.25=x*12+(100-x)9
1125=12x+900-9x
12x-9x=1125-900
3x=225
x=225/3
x=75 pounds of $12 coffee.
100-75=25 pounds of $9 coffee.
proof
100*11.25=75*12+25*9
1125=900+225
1125=1125


Circles/75366: a rotating lawn sprinkler shoots water a distance of 10 meters. what is the area of the region where it waters
1 solutions

Answer 54080 by checkley75(3666) About Me  on 2007-03-21 21:35:07 (Show Source):
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area of a circle=pi*r^2
3.14*10^2
3.14*100=314 square meters


Travel_Word_Problems/75402: A baseball dimond is a square whose side measue 90ft. For a home run a player must run around the square. If a player hits 35 home runs, what is the least number of feet he or she must run?
1 solutions

Answer 54078 by checkley75(3666) About Me  on 2007-03-21 21:32:26 (Show Source):
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4*90=360 feet for one round tripper (home run).
then for 35 home runs he/she covers
360*35=12,600 feet in all.


Graphs/75403: Find the slope of the line passing through the points (1, 1) and (3, 3).
1 solutions

Answer 54075 by checkley75(3666) About Me  on 2007-03-21 21:29:25 (Show Source):
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slope=(y2-y1)/(x2-x1)
(3-1)/(3-1)
2/2=1 is the slope.


Surface-area/75406: A rectangle has sides of 3x – 4 and 7x + 10. Find the expression that represents its perimeter.
1 solutions

Answer 54074 by checkley75(3666) About Me  on 2007-03-21 21:27:33 (Show Source):
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2(3x-4)+2(7x+10)
6x-8+14x+20
20x+12 is the perimeter.


Miscellaneous_Word_Problems/75370: the perimeter of a rectangle is 84 cm. the length is twice the width. Find the length and width.
1 solutions

Answer 54073 by checkley75(3666) About Me  on 2007-03-21 21:25:22 (Show Source):
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2l+2w=perimeter
2*2w+2w=84
4w+2w=84
6w=84
w=84/6
w=14 solution for the width.
2*14=28 for the length.
proof
2*28+2*14=84
56+28=84
84=84


Linear-equations/75397: Solve. 3(x – 5) + 3x = 4x + 5
1 solutions

Answer 54071 by checkley75(3666) About Me  on 2007-03-21 21:20:47 (Show Source):
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3(x-5)+3x=4x+5
3x-15+3x=4x=5
3x+3x-4x=5+15
2x=20
x-20/2
x=10 answer.
proof
3(10-5)+3*10=4*10+5
3*5+30=40+5
15+30=45
45=45


Equations/75396: 17=x(x+12)
1 solutions

Answer 54070 by checkley75(3666) About Me  on 2007-03-21 21:17:54 (Show Source):
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17=X(X+12)
X^2+12X-17=0
USING THE QUADRATIC EQUATION WE GET:
X=(-12+-SQRT[12^2-4*1*-17])/2*1
X=(-12+-SQRT[144+68])/2
X=(-12+-SQRT212)/2
X=(-12+-14.56)/2
X=(-12+14.56)/2
X=2.56/2
X=1.28 SOLUTION.
X=(-12-14.56)/2
X=-26.56/2
X=-13.28 SOLUTION.


Travel_Word_Problems/75395: The school flagpole cast a shadow 15ft long. Mr. Hansen cast a shadow 4ft long. Mr. Hansen is 6ft tall. How tall is the flag pole.
1 solutions

Answer 54068 by checkley75(3666) About Me  on 2007-03-21 21:10:07 (Show Source):
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15/6=X/4 CROSS MULTIPLY.
6X=60
X=60/6
X=10 FEET FOR THE FLAGPOLE SHADOW.


Miscellaneous_Word_Problems/75393: Adult tickets for a play cost $17 and child tickets cost $2. If there were 32 people at a performance and the theater collected $364 from ticket sales, how many adults and how many children attended the play?
1 solutions

Answer 54067 by checkley75(3666) About Me  on 2007-03-21 21:07:17 (Show Source):
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17A+2C=364 & A+C=32 THEN A=32-C NOW WE REPLACE (32-C) FOR A IN THE OTHER EQUATION & SOLVE FOR C
17(32-C)+2C=364
544-17C+2C=364
-15C=364-544
-15C=-180
C=-180/-15
C=12 CHILDREN'S TICKETS.
A=32-12
A=20 ADULT TICKETS.
PROOF
17*20+2*12=364
340+24=364
364=364


Miscellaneous_Word_Problems/75371: mark and melinda collect baseball caps. mark has 7 more thn melinda. together, they have 115 caps. how many baseball caps does each of them have?
1 solutions

Answer 54063 by checkley75(3666) About Me  on 2007-03-21 21:00:16 (Show Source):
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X+(X+7)=115
X+X=7=115
2X=115-7
2X=108
X=108/2
X=54 CAPS FOR MELINDA
54+7=61 CAPS FOR MARK
PROOF
54+61=115
115=115


Linear-equations/75372: find points on graph using the equation -x+2y=11
how do you find the point for the graph
1 solutions

Answer 54060 by checkley75(3666) About Me  on 2007-03-21 20:57:20 (Show Source):
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-x+2y=11
2y=x+11
y=x/2+11/2 the y intercept is (0,11/2) or (0,5.5)
setting y=0 we solcve for x thus:
0=x/2+11/2
x/2=-11/2 now cross multiply thus:
2x=-22
x=-22/2
x=-11 or (-11,0) is a second point.
+graph%28+300%2C+300%2C+-12%2C+12%2C+-10%2C+10%2C+y+=+x%2F2+%2B11%2F2%29+ (graph 300x300 pixels, x from -12 to 12, y from -10 to 10, y = x/2 +11/2).


Linear-systems/75138: This question is from textbook Introductory Algebra
Graph each linear equation
2x+y=2
How do you find the RIGHT numbers to subsitute x and y with, how do you know what numbers to use?
1 solutions

Answer 53997 by checkley75(3666) About Me  on 2007-03-20 22:42:42 (Show Source):
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2X+Y=2
Y=-2X+2 THIS EQUATION IS A LINE WITH A SLOPE OF -2 & A Y INTERCEPT OF 2.
WE NOW HAVE ONE SET OF POINTS (0,2) THE Y INTERCEPT.
SETTING Y=0 WE CAN FIND ANOTHER SET OF POINTS.
0=-2X+2
-2X=-2
X=-2/-2
X=1 OR ANOTHER POINT IS (1,0)
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-2x+%2B2%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -2x +2).


Linear-equations/75154: Please help...Thanks!!
If a line contains the points (1,3), (2,6) and (3,9) determine and write the slope-intercept form of the equation, provide one additional point on this line in (x,y) form, and graph the function.

1 solutions

Answer 53996 by checkley75(3666) About Me  on 2007-03-20 22:37:31 (Show Source):
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FIRST WE FIND THE SLOPE (Y2-Y1)/(X2-X1)
(6-3)/(2-1)
3/3=3 IS THE SLOPE.
NOW USING THE LINE FORMULA AND ONE SET OF POINTS WE CAN FIND THE Y INTERCEPT.
3=3*1+b
3=3+b
b=3-3
b=0 THUS THE EQUATION IS
Y=3X
SETTING Y=12 WE SOLVE FOR X
12=3*X
3X=12
X=12/3
X=4 OR (4,12) FOR THE ADDITIONAL POINT ON THIS LINE
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+3x%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 3x).


Equations/75155: How do I find the value of of the variable in the problem: 2r+10=22? Please help.
1 solutions

Answer 53995 by checkley75(3666) About Me  on 2007-03-20 22:30:51 (Show Source):
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2R+10=22
2R=22-10
2R=12
R=12/2
R=6 ANSWER.


Graphs/75161: How do you identify horizontal and vertical asymptotes of graph functions?
1 solutions

Answer 53994 by checkley75(3666) About Me  on 2007-03-20 22:28:09 (Show Source):
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THE HORIZONTAL LINE IS THE X AXIS & THE VERTICLE LINE IS THE Y AXIS.


Proportions/75162: This question is from textbook
Two computer programs used 230 megabytes of disks space. If all programs required an equal amount of space,how many megabytes of disk space would be required for 5 programs?
1 solutions

Answer 53993 by checkley75(3666) About Me  on 2007-03-20 22:26:28 (Show Source):
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230/2=115 MEGABYTES PER PROGRAM.
115*5=575 MEGABYTES ARE REQUIRED FOR ALL 5 PROGRAMS.


Inequalities/75164: Two trucks start from the same point traveling in different directions, One truck travels at a speed of 54 mi/h , the other at 48 mi/h. How long must they travel to be at least 408 mi apart?
1 solutions

Answer 53992 by checkley75(3666) About Me  on 2007-03-20 22:24:12 (Show Source):
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54X+48X=408
102X=408
X=408/102
X=4 HOURS IS THE ANSWER.