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# Recent problems solved by 'checkley75'

checkley75 answered: 3664 problems
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 Equations/80498: 1 solutions Answer 57745 by checkley75(3666)   on 2007-05-02 20:40:59 (Show Source): You can put this solution on YOUR website!(x^2+6x+5)=y (x+5)(x+1)=y
 Exponential-and-logarithmic-functions/80500: I can't understand how exactly to solve this. the problem is:(2xy)^2(4x^2y^3)^2. I don't know if I was on the right track or not but I started off by squaring everything and then didn't know what to do after that. 1 solutions Answer 57744 by checkley75(3666)   on 2007-05-02 20:38:39 (Show Source): You can put this solution on YOUR website!(2xy)^2(4x^2y^3)^2 (4x^2y^2)(16x^4y^6) 64x^6y^8
 Quadratic_Equations/80501: help me someone please!! The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?1 solutions Answer 57743 by checkley75(3666)   on 2007-05-02 20:35:19 (Show Source): You can put this solution on YOUR website!X^2+(X+1)^2=4^2 X=WIDTH + (X+1)=LENGTH. X^2+X^2+2X+1=16 2X^2+2X+1-16=0 2X^2+2X-15=0 using the quadratic equation we get: x=(-2+-sqrt[2^2-4*2*-15])/2*2 x=(-2+-sqrt[4+120])/4 x=(-2+-sqrt124)/4 x=(-2+-11.1355)/4 x=(-2+11.1355)/4 x=9.1355/4 x=2.284 answer. x=(-2-11.1355)/4 x=-13.1355/4 x=-3.2839 answer.
 Radicals/80451: Please simplify and multiply the square root. Thanks! (√18+√8)(√18-√8)1 solutions Answer 57742 by checkley75(3666)   on 2007-05-02 20:20:20 (Show Source): You can put this solution on YOUR website!(SQRT18+SQRT8)(SQRT18-SRT8) 18+SQRT144-SQRT144-8 18-8=10 ANSWER
 Geometry_Word_Problems/80461: 87+92+K(all divided by 3)=91 Thanks1 solutions Answer 57741 by checkley75(3666)   on 2007-05-02 20:10:38 (Show Source): You can put this solution on YOUR website!(87+92+K)/3=91 (179+K)/3=91 NOW CROSS MULTIPLY & WE GET: 179+K=273 K=273-179 K=94 ANSWER.
 Equations/80473: This question is from textbook beginners algebra (0,5), m = -3/5 rewrite in standard form1 solutions Answer 57740 by checkley75(3666)   on 2007-05-02 20:06:42 (Show Source): You can put this solution on YOUR website!WITH A SLOPE (m) OF -3/5 THROUGH THE POINT (1,5) WE FIND THE Y INTERCEPT (b) THUS: 5=-3/5*0+b 5=b SO WE HAVE A Y INTERCEPT OF 5. THUS HE EQUATION IS Y=-3X/5+5
 Equations/80476: Subtract. Express your answer in simplest form. 5x-3/6 – x+3/6 1 solutions Answer 57739 by checkley75(3666)   on 2007-05-02 20:03:20 (Show Source): You can put this solution on YOUR website!5X-3/6-X+3/6 THE -3/6 & THE 3/6 CANCEL OUT EACH OTHER. THUS WE ARE LEFT WITH 5X-X=4X
 Quadratic_Equations/80489: rewrite this equation as a function of x -3x+4y=111 solutions Answer 57738 by checkley75(3666)   on 2007-05-02 19:52:16 (Show Source): You can put this solution on YOUR website!-3x+4y=11 -3x=-4y+11 x=-4y/-3+11/-3 x=4y/3-11/3
 Quadratic_Equations/80487: you have at least \$30 in change in your drawer, consisting of dimes and quarters. write and inequality that shows the different number of coins in yur drawer. Can some one please help me with this?1 solutions Answer 57737 by checkley75(3666)   on 2007-05-02 19:49:15 (Show Source): You can put this solution on YOUR website!25q+10d>=3000 (q=the number of quarters & d=the number of dimes.)
 Equations/80479: Solve the equation. (y-3) (y+7)=01 solutions Answer 57733 by checkley75(3666)   on 2007-05-02 19:29:02 (Show Source): You can put this solution on YOUR website!(y-3)(y+7)=0 y^2-3y+7y-21=0 y^2+4y-21=0 -------------------------------------- one way to check his is to use the quadratic equation ay^2+by+c: then you'll see that: y-3=0 y=3 & y+7=0 y=-7
 Linear-equations/80482: how i do this: x+2y=81 solutions Answer 57732 by checkley75(3666)   on 2007-05-02 19:25:41 (Show Source): You can put this solution on YOUR website!IF THIS IS A LINE EQUATON [Y=mX+b] THEN: X+2Y=8 2Y=-X+8 Y=-X/2+8/2 Y=-X/2+4 THIS IS A LINE WITH A SLOPE (m) OF (-1/2) & A Y INTERCEPT (b) OF (4) (graph 300x200 pixels, x from -10 to 10, y from -10 to 10, y = -x/2 +4).
 Quadratic_Equations/80484: I hope you can help with this word problem. I don't know where to begin and I cannot find an example in the book to go by. Thank you Problem Time to swing The speed T (time in seconds for one complete cycle) of a pendulum is related to the length L(in feet) of the pendulum by the formula 8T^2 = pi^2L. If a child is on a swing with a 10-foot chain, then how long does it take to complete one cycle of the swing. Hope someone can help please.1 solutions Answer 57731 by checkley75(3666)   on 2007-05-02 19:17:09 (Show Source): You can put this solution on YOUR website!8T^2=pi^2L WHEN L=10 FEET THE THE TIME IS: 8T^2=3.14^2*10 8T^2=9.8596*10 8T^2=98.596 T^2=98.596/8 T^2=12.3245 T=SQRT12.3245 T=3.51 SECONDS TO COMPLETE ONE CYCLE (SWING)
 Surface-area/80401: To restore medieval castle in Eorope, the conical roof of one of its round towers had to be painted with a special protective silver paint. If the diameter of the conical roof base 5.84 m and its altitude is 9.76 m, what is the cost of gilding the roof if the rate of painting the roof is equivalent to \$27.50/m squared?1 solutions Answer 57679 by checkley75(3666)   on 2007-05-02 08:49:40 (Show Source): You can put this solution on YOUR website!FIRST WE FIND THE SLOPE OF THE TOWER SURFACE USING THE TRIANGLE WITH SIDES OF 9.76 & 5.84/2=2.92 TO FIND THE SLOPE (HYPOTENUSE) A^2+B^2=C^2 9.76^2+2.92^2=S^2 95.2576+8.5264=S^2 S^2=103.784 S=10.187 FOR THE SLOPE. FORMULA FOR THE TOTAL SURFACE AREA OF A CONE IS TSA=1/2piDS+piR^2 WHERE pi=3.14, D=DIAMETER, R=RADIUS TSA=.5*3.14*5.84*10.187+3.14*2.92^2 TSA=93.4+26.77 TSA=120.17 IS THE TOTAL SURFACE AREA OF THE TOWER. NOW WE MULTIPLY BY \$27.50 120.17*27.50=\$3,304.68 TO PAINT THE TOWER.
 Polynomials-and-rational-expressions/80342: what is the answer to 9a+a+42a-491 solutions Answer 57650 by checkley75(3666)   on 2007-05-01 21:33:30 (Show Source): You can put this solution on YOUR website!9A+A+42A-49 52A-49 IS THE ANSWER.
 Graphs/80343: slope: -3/4;y intercept:(0,8)...How in the world do I figure this out?Help me PLEEEASE...Thank You1 solutions Answer 57648 by checkley75(3666)   on 2007-05-01 21:30:38 (Show Source): You can put this solution on YOUR website!Y=mX+b WHERE (m)=SLOPE & (b)=Y INTERCEPT. Y=-3/4X+8 IS THE EQUATION FOR THIS LINE.
 Quadratic_Equations/80349: The sum of two numbers is -15. Their product is -100. Find the two numbers.1 solutions Answer 57646 by checkley75(3666)   on 2007-05-01 21:28:12 (Show Source): You can put this solution on YOUR website!X+Y=-15 X=-Y-15 X*Y=-100 NOW REPLACE X BY (-Y-15) (-Y-15)*Y=-100 -Y^2-15Y+100=0 Y^2+15Y-100=0 (Y+20)(Y-5)=0 Y+20=-0 Y=-20 ANSWER. Y-5=0 Y=5 ANSWER. SAME ANSWERS FOR X.
 Quadratic_Equations/80352: The length of a rectangle is four less than three times the width. The area is 20 square centimeters. Find the dimensions of the rectangle.1 solutions Answer 57643 by checkley75(3666)   on 2007-05-01 21:12:14 (Show Source): You can put this solution on YOUR website!L=3W-4 W(3W-4)=20 3W^2-4W-20=0 (3W-10)(W+2)=0 3W-10=0 3W=10 W=10/3 OR 3.333 ANSWER L=3*3.333-4 L=10-4 L=6 ANSWER. PROOF 3.333*6=20 20=20
 Radicals/80346: Oh boy! tough one for me : ( One fourth of a herd of camels was seen in the forest, twice the square root of that herd had gone to the mountain slopes and 3 times 5 camels remained on the riverbank. What is the numerical measure of the herd of camels? Ugg! Please help! Thank you1 solutions Answer 57642 by checkley75(3666)   on 2007-05-01 21:04:59 (Show Source): You can put this solution on YOUR website!c/4+2sqrtc+3*5=c c/4+sqrtc+15=c c/4+15+2sqrtc=c 2sqrtc=c-c/4-15 2sqrtc=3c/4-15 2sqrtc=(3c-60)/4 sqrtc=(3c-60)/8 c=[(3c-60)/8]^2 c=(9c^2-360c+3600)/64 64c=9c^2-360c+3600 9c^2-360c-64c+3600=0 9c^2-424c+3600=0 using the quadratic equation we get: c=(424+-sqrt[-424^2-4*9*3600])/2*9 c=(424+-sqrt[179,776-129,600])/18 c=(424+-sqrt50,176)/18 c=(424+-224)/18 c=(424+224)/18 c=648/18 c=36 size of the herd. proof 36/4+2*sqrt36+15=36 9+2*6+15=36 9+12+15=36 36=36 this was not an easy one :) :)
 Graphs/80344: Write the equation of the line passing through (-2,5) and (1,3). Answer must be written in slope intercept form. HELP ME!!! ;0(1 solutions Answer 57637 by checkley75(3666)   on 2007-05-01 20:26:03 (Show Source): You can put this solution on YOUR website!FIRST WE NEED TO FIND THE SLOPE (m) THUS: (Y2-Y1)/(X2-X1)=(3-5)/(1+2)=-2/3 WHICH IS THE SLOPE (m). NOW WE REPLACE X & Y IN THE EQUATION Y=mX+b & SOLVE FOR THE Y INTERCEPT (b) 5=-2/3*-2+b 5=4/3+b b=5-4/3 b=(15-4/3) b=11/3 THUIS IS THE Y INTERCEPT. THUS THE LINE EQUATION IS Y=-2/3X+11/3 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -2x/3 +11/3).
 Rational-functions/80314: Two cars leave at noon from the same point, one traveling east at 50 mph, the other traveling due north at 60 mph. (a) How far apart are they at 1 PM? at 1:30 PM? (b) If t is the number of hours after noon, find an equation expressing the distance between the cars as a function of t.1 solutions Answer 57635 by checkley75(3666)   on 2007-05-01 20:06:05 (Show Source): You can put this solution on YOUR website!(50T)^2+(60T)^2=DISTANCE ^2 @ 1:00 THEY ARE (50*1)^2+(60*1)^2=D^2 5062=60^2=D62 2500+3600=D^2 D^2=5100 D=SQRT5100 D=71.414 MILES APART @ 1:00. ------------------------------------ @ 1:30 THEY WILL BE: (50*1.5)^2+(60*1.5)^2=D^2 75^2+90^2=D^2 D^2=5625+8100 D^2=13725 D=117.154 MILES APART @ 1:30. ------------------------------------------------------------ FORMULA IN TERMS OF T IS: (S1T)^2+(S2T)^2=D^2 T^2(S1^2+S2^2)=D^2 T^2=D^2/(S1^2+S2^2) T=(D/SQRT(S1^2+S2^2)
 Polynomials-and-rational-expressions/80341: what is the answer to 2x+x+x+x-8x+x1 solutions Answer 57633 by checkley75(3666)   on 2007-05-01 19:53:17 (Show Source): You can put this solution on YOUR website!2X^4-8X^2 2X^2(X^2-4) 2X^2(X+2)(X-2) -------------------------------------------------- 2X+X+X+X-8X+X=-2X ANSWER.
 Quadratic_Equations/80328: Hello, I am trying to solve this problem and need help. Directions are to solve, apparently there will be 6 answers. Thank you!!!1 solutions Answer 57630 by checkley75(3666)   on 2007-05-01 19:51:05 (Show Source): You can put this solution on YOUR website!y^6+9y^3+8=0 (y^3+8)(y^3+1)=0 y^3+8=0 y^3=-8 y=-2 answer. y^3+1=0 y^3=-1 y=-1 answer.
 Rate-of-work-word-problems/80330: Mike can paint a wall in three hours. Angelo can paint the same wall in two hours. How long will it take if they work together?1 solutions Answer 57629 by checkley75(3666)   on 2007-05-01 19:45:44 (Show Source): You can put this solution on YOUR website!THE ANSWER TO ALL THESE TYPE OF PROBLEMS ARE PRODUCT OVER SUM OR X*Y/(X+Y) WHETHER IT IS PEOPLE WORKING, TWO WATER PIPES FILLING, RESISTERS IN PARALLEL, ETC. YOUR CASE IS THE PRODUCT OF THE TWO TIMES 3*2=6 DIVIDED BY THE SUM (3+2)=5 3*2/(3+2)=6/5=1.2 hours when they work together.
 Radicals/80331: Multiply and then simplify the product. All variables represent positive real numbers. √5(√125-6)1 solutions Answer 57628 by checkley75(3666)   on 2007-05-01 19:44:19 (Show Source): You can put this solution on YOUR website!sqrt5[sqrt(125-6)]=2.236*sqrt119=2.236*10.9087=24.39 answer.
 Inequalities/80307: My question is off a worksheet that if called Solving problems involving inequalities. It is "Find the largest pair of consectutive integers whos sum is less than 85." My work is: x+x+2<85 2x<831 solutions Answer 57611 by checkley75(3666)   on 2007-05-01 17:43:27 (Show Source): You can put this solution on YOUR website!X+X+2<85 2X<85-2 2X<83 X<83/2 X<41.5 PROOF SET X=41 & X+2=41+2=43 41+43<86 85<86 STATEMENT IS TRUE.
 Geometry_Word_Problems/80304: The area of a circle is 64Pi. The area of a square is 256. Which is larger? the diameter of the circle or the side of the square?1 solutions Answer 57610 by checkley75(3666)   on 2007-05-01 17:38:42 (Show Source): You can put this solution on YOUR website!AREA=piR^2 OR AREA=64pi OR AREA=8pi WHERE THRE RADIUS ID 8 THUS THE DIAMETER IS 2*8=16 AREA OF A SQUARE IS X^2 X^2=256 X=16 WHICH THE LENGTH OF THE SIDE. THEREFORE THE SIDE OF THE SQUARE (16) IS EQUAL TO THE DIAMETER (16) OF THE CIRCLE.
 Geometry_Word_Problems/80300: The circumference of a circle is 20Pi. What is the area of the circle? Leave your answer in terms of Pi1 solutions Answer 57607 by checkley75(3666)   on 2007-05-01 17:32:57 (Show Source): You can put this solution on YOUR website!C=2piR 20pi=2piR DIVIDE BOTH SIDES BY pi 20=2R R=20/2 R=10 THUS THE AREA OF THIS CIRCLE IS A=piR^2 A=pi10^2 A=100pi
 Graphs/80286: Driving down a mountain, Tom finds that he has descended 1800 ft in elevation by the time he is 3.25 mi horizontally away from the of the mountain. Find the slope of his descent to the nearest hundreth. And is it possible to explain to me how to solve this, for future refrence.1 solutions Answer 57605 by checkley75(3666)   on 2007-05-01 17:28:01 (Show Source): You can put this solution on YOUR website!THE BEST WAY TO SOLVE THIS IS TO SET UP A GRAPH. ASSIGN THE POINT (0,1800)FOT YHR TOP OF THE MOUNTAIN. NOW SET A SECOND POINT (5280*3.25,0) FOR THE END OF THE DESCENT DOWN THE MOUNTAIN. THESE 2 POINTS ARE (0,1800) & (17,160,0). TO FIND THE SLOPE BETWEEN THESE TWO POINTS WE USE (Y2-Y1)/X2-X1) OR (0-1800)/(17,160-0) -1800/17,160=.104895 OR -.1 IS THE SLOPE OF THIS DESCENT.
 Linear-systems/80287: This question is from textbook Algebra I Use substitution to solve each system of equations. If the system does not have exactly one solution, state whether it has no solution or infinitely many solutions. 2x-y=-4 -3x+y=-91 solutions Answer 57604 by checkley75(3666)   on 2007-05-01 17:13:36 (Show Source): You can put this solution on YOUR website!2X-Y=-4 -Y=-2X-4 Y=2X+4 NOW SUBSTITUTE (2X+4) FOR Y & SOLVE FOR X IN THE OTHER EQUATION. -3X+(2X+4)=-9 -3X+2X+4=-9 -X=-9-4 -X=-13 X=13 ANSWER. Y=2*13+4 Y=26+4 Y=30 ANSWER.
 percentage/80142: Find the slope and y-intercept of the line represented by the following equation. 2x-3y=61 solutions Answer 57603 by checkley75(3666)   on 2007-05-01 17:07:05 (Show Source): You can put this solution on YOUR website!2X-3Y=6 -3Y=-2X+6 Y=-2X/-3+6/-3 Y=2X/3-2 (2/3=SLOPE) & (-2=Y INTERCEPT).
 Quadratic_Equations/80195: This question is from textbook what are the steps to do a quadratic equation1 solutions Answer 57602 by checkley75(3666)   on 2007-05-01 17:03:12 (Show Source): You can put this solution on YOUR website!THE FORMULA OF THE FORM aX^2+bX+c=0 IS USED TO SOLVE QUADRATIC EQUATIONS