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Recent problems solved by 'checkley75'
checkley75 answered: 3664 problems
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Equations/87141: For function y=1/x-2
Give the y values for x =-1,0,1,2,3,4.
Show work
Using these points, draw a curve. Show Graph 1 solutions
Answer 63146 by checkley75(3666) on 2007-07-03 19:26:25 (Show Source):
You can put this solution on YOUR website!X=-1 THEN Y=1/-1-2, Y=-1-2, Y=-3
X=0, THEN Y=1/0-2, Y=-2
Y=1, THEN Y=1/1-2, Y=-1
Y=2, THEN Y=1/2-2, Y=-1.5
X=3, THEN Y=1/3-2, Y=5/3
X=4, THEN Y=1/4-2, Y=-1.75
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = (1/x) -2).
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Radicals/87142: Okay, the following question has me stumped, Geometry: If the roof of a home is 7m from peak to eave and the attic space is 3m high at the peak, how long does each of the pieces of insulation need to be? (Insulation is 40cm wide rolls that are cut to fit between the rafters in the attic) Round the answer to the nearest tenth. 1 solutions
Answer 63145 by checkley75(3666) on 2007-07-03 19:17:07 (Show Source):
You can put this solution on YOUR website!WHAT YOU HAVE IS A RIGHT TRIANGLE WITH THE RIGHT SIDE=3M & THE HYPOTENUS IS 7M.
NOW WWE NEED TO FIND THE OTHER SIDE (BASE) USING THE PYTHAGOREAN THERUM A^2+B^2=C^2 WHERE A & B ARE THE 2 SIDES & C IS THE HYPOTENUSE.
3^2+B^2=7^2
9+X^2=49
X^2=49-9
X^2=40
X=SQRT40
X=6.3M IS THE BASE MEASUREMENT.
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Miscellaneous_Word_Problems/87191: I would appreciate if a tutor would teach me how to solve the following word problems step by step.
1) Solve the problem.
The height of a box is 8 inches. The length is three inches more than the width. Find the width if the volume is 560.
Question 3 answers
8 in.
10 in.
70 in.
7 in.
2) Solve the problem.
A square lawn has an area of 1568 square feet. A sprinkler placed at the center of the lawn sprays a water in a circular pattern that just covers the lawn. What is the radius of the circle?
Question 4 answers
39.6 feet
28 feet
56 feet
19.8 feet
3) Answer the question.
If a rectangle is x feet long and y feet wide, which one of the following expressions is the length of its diagonal in terms of x and y?
Question 5 answers
x2 + y2
x + y
square root x+y
square root x^2 + y^2
4) Solve the problem.
The area of a square is numerically 117 more than the perimeter. Find the length of the side.
Question 6 answers
85 units
52 units
13 units
338 units
1 solutions
Answer 63130 by checkley75(3666) on 2007-07-03 17:03:13 (Show Source):
You can put this solution on YOUR website!1) HEIGHT=8 INCHES, LENGTH=W+3 INCHES, WIDTH=W.
VOLUME =L*W*H
560=(W+3)*W*8
560=(W^2+3W)*8
560/8=W^2+3W
70=W^2+3W
W^2+3W-70=0
(W+10)(W-7)=0
W+10=0
W=-10 NOT AN ANSWER.
W-7=0
W=7 ANSWER.
PROOF
560=(7+3)*7*8
560=10*7*8
560=560
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2) 1568=S^2
S=SQRT1568
S=39.597979 IS THE LENGTH OF THE SIDES.
THUS THE RADIUS IS S/2
39.597979/2=19.798989 FEET.
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3) SQRT(X^2+Y^2)
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4)AREA=S^2 & PERIMETER=4S. THUS:
S^2=4S+117
S^2-4S-117=0
(S-13)(S+9)=0
S-13=0
S=13 ANSWER.
PROOF
13^2=4*13+117
169=52+117
169=169
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Expressions-with-variables/87133: The sum of three consective even integers is 114
a. Define variables for the smalles integer (36)?
b. Define variables to represent the 2nd and 3rd integers (38, 40)?
c. Write an equation for the sum of the tree consecutive even integers.
d. Solve the equation to find the three even integers.
1 solutions
Answer 63123 by checkley75(3666) on 2007-07-03 16:28:04 (Show Source):
You can put this solution on YOUR website!X+(X+2)+(X+4)=114
3X+6=114
3X=114-6
3X=108
X=108/3
X=36 ANSWER FOR THE FIRST/SMALLEST EVEN NUMBER
36=2=38 FOR THE SECOND EVEN NUMBER
36=4=40 FOR THE THIRD EVEN NUMBER
PROOF
36+38+40=114
114=114
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Trigonometry-basics/87185: Determine the area of triangle ABC given the following information:
A=12, B=13, C=5 1 solutions
Answer 63122 by checkley75(3666) on 2007-07-03 16:21:05 (Show Source):
You can put this solution on YOUR website!KNOWING THAT THIS IS A RIGHT TRIANGLE: WE USE THE QUADRATIC PATHOGOREAN THEROM
PROOF A^2+B^2=C^2, 12^2+5^2=13^2, 144+25-169, 169=169.
NOW WE USE THE AREA FORMULA FOR A RIGHT TRIANGLE A=B/2*H (B IS THE BASE=12), HIS THE HEIGHT=5)
A=12/2*5
A=6*5
A=30
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Quadratic_Equations/87001: This isnt a quadratic formula problem, I dont know what type of problem it is, I just really need help in it. The problem is: Simplify d^2-2d-3
d^2-10d+24
d+1
d-4
They are like that because the problem is in fraction form 1 solutions
Answer 62989 by checkley75(3666) on 2007-07-01 17:09:14 (Show Source):
You can put this solution on YOUR website!IF THIS IS THE FRACTION?
(D^2-2D-3)/(D^2-10D+24)
(D-3)(D+1)/(D-4)(D-6)
YOUR ANSWER IS (D+1)/(D-4).
QUESTION -- HOW DID YOU GET RID OF THE OTHER 2 TERMS (D-3)/(D-6)??????????
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Points-lines-and-rays/87003: Please help me solve my assignment. Thank you.
Points N, R and T lie in a straight line. R lies between N and T. If RT = 4/3 NT
and RT = 100, find NT. 1 solutions
Answer 62987 by checkley75(3666) on 2007-07-01 17:01:00 (Show Source):
You can put this solution on YOUR website!RT CANNOT BE GREATER [4/3=1.333] THAN NT IF R IS BETWEEN N&T
PROOF:
RT=100 & RT=(4/3)NT THEN
100=(4/3)NT
NT=100/(4/3)
NT=100(3/4)
NT=300/4
NT=75
THE ENTIRE LENGTH OF THE LINE (NT=75) CANNOT BE LONGER THAN THE PART (RT=100)
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Permutations/87027: If someone has 6 different pairs of pants, 10 different shirts, and 5 different pair of shoes, how many different pant, shirt, and shoe outfits are possible? 1 solutions
Answer 62985 by checkley75(3666) on 2007-07-01 16:45:03 (Show Source):
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Radicals/86830: Find the perimeter of a triangle if the three sides are:
square root 5 - square root 3
square root 5 + square root 3
4
thanks, 1 solutions
Answer 62930 by checkley75(3666) on 2007-06-30 16:31:46 (Show Source):
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Money_Word_Problems/86933: The perimeter of a rectangle is 34 feet and its area is 60 square feet. Find the length and width of the rectangle. 1 solutions
Answer 62880 by checkley75(3666) on 2007-06-29 21:13:30 (Show Source):
You can put this solution on YOUR website!xy=60
x=60/y
2x+2y=34
2(60/y)+2y=34
120/y+2y=34
(120+2y^2)/y=34
120+2y^2=34y
2y^2-34y+120=0
2(y^2-17y+60)=0
2(y-12)(y-5)=0
y-12=0
y=12 answer. the x=60/12=5
y-5=0
y=5 answer. the y=60/5=12
proof
5*12=60
60=60
2*5+2*12=34
10+24=34
34=34
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