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Points-lines-and-rays/199139: y=7/5x-3
solve for x
find x and y intercept and slope 1 solutions
Answer 149625 by checkley75(3666) on 2009-06-06 17:44:46 (Show Source):
You can put this solution on YOUR website!Y=mX+b m=slope & b=y intercept.
y=7/5x-3
y=7x/5-3
7x/5=y+3
7x=5(y+3)
7x=5y+15
x=(5y+15)/7
slope=7/5
y intercept=-3
setting y=0 we solve for the x intercept.
0=7x/5-3
7x/5=3
7x=3*5
7x=15
x=15/7 the x intercept.
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 7x/5 -3).
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Problems-with-consecutive-odd-even-integers/199148: Find three consecutive positive even integers such that the product of the first and second is two less than five times the third.(Only an algebraic solution will be accepted.): Find three consecutive positive even integers such that the product of the first and second is two less than five times the third.(Only an algebraic solution will be accepted.)
1 solutions
Answer 149624 by checkley75(3666) on 2009-06-06 17:37:32 (Show Source):
You can put this solution on YOUR website!Let x, x+2 & x+4 be the 3 even integers.
x(x+2)=5(x+4)-2
x^2+2x=5x+20-2
x^2+2x-5x-18=0
x^2-3x-18=0
(x-6)(x+3)=0
x-6=0
x=6 ans. for the first even integer.
6+2=8 for the second even integer.
6+4=10 for the third even integer.
Proof:
6*8=5*10-2
48=50-2
48=48
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Linear_Equations_And_Systems_Word_Problems/199108: The cost of 12 gallons of regular gasoline and 18 gallons of premium gasoline is $44.46. Premium costs $.22 more per gallon than regular. What is the cost per gallon of each type of gasoline? 1 solutions
Answer 149582 by checkley75(3666) on 2009-06-05 20:21:43 (Show Source):
You can put this solution on YOUR website!12x+18(x+.22)=44.46
12x+18x+3.96=44.46
30x=44.46-3.96
30x=40.50
x=40.50/30
x=1.35 is the price of regular gas per gallon.
1.35+.22=1.57 is the price of premium gas per gallon.
Proof:
12*1.35+18*1.57=44.46
16.20+28.26=44.47
44.46=44.46
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Graphs/198879: This question is from textbook Algebra Structure and Method Book 1
How do I write an equation in standard form of the line that contains (1,1) and (6,-1)? thanks 1 solutions
Answer 149416 by checkley75(3666) on 2009-06-04 08:27:21 (Show Source):
You can put this solution on YOUR website!(1,1) and (6,-1)
Y=mX+b
m=slope
b=y intercept
slope=(y2-y1)/(x2-x1)
slope=(-1-1)/(6-1)
slope=-2/5
1=-2/5*1+b
1=-2/5+b
b=1+2/5
b=(1*5+2)/5
b=(5+2)/7
b=7/5 y intercept.
y=-2x/5+7/5 is the line equation.
 (graph 300x200 pixels, x from -6 to 5, y from -6 to 5, -2x/5 +7/5x).
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Linear-equations/198739: You have 2 solutions of liquid. One contains 10% water and the other contains 30% water. How many quarts of each should you mix in order to obtain 30 quarts of mixture that is 25% water? 1 solutions
Answer 149251 by checkley75(3666) on 2009-06-02 20:14:15 (Show Source):
You can put this solution on YOUR website!.3x+.1(30-x)=.25*30
.3x+3-.1x=7.5
.2x=7.5-3
.2x=4.5
x=4.5/.2
x=22.5 qts. of 30% water.
30-22.5=7.5 qts of 10% water.
Proof:
.3*22.5+.1*7.5=7.5
6.75+.75=7.5
7.5=7.5
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Quadratic_Equations/198740: You have a total of $5,000 and decide to invest part in a bank paying 5% simple interest and in a CD that pays 8%. If you receive a total of $300 from your investments, how much was put in each account? 1 solutions
Answer 149249 by checkley75(3666) on 2009-06-02 20:09:38 (Show Source):
You can put this solution on YOUR website!.08x+.05(5,000-x)=300
.08x+250-.05x=300
.03x=300-250
.03x=50
x=50/.03
x=1,666.67 invested @ 8%
5,000-1,666.67=3,333.33 invested @ 5%
Proof:
.08*1,666.67+.05*3,333.33=300
133.33+166.67=300
300=300
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Linear-systems/198745: One year ago Walt invested $12000. He invested part of the money at 7% and the rest at 9%. He made a total of $970 in interest. How much was invested at 7%?
I do not know where to place what number in the formula equation
ax2 + bx + c = 0 1 solutions
Answer 149246 by checkley75(3666) on 2009-06-02 20:03:40 (Show Source):
You can put this solution on YOUR website!ax2 + bx + c = 0
This is not the correct formula for this type of problem.
.09x+.07(12,000-x)=970 is the correct formula.
.09x+840-.07x=970
.02x=970-840
.02x=130
x=130/.02
x=6,500 amount invested @ 9%.
12,000-6,500=5,500 amount invested @ 7%.
Proof:
.09*6,500+.07*5,500=970
585+385=970
970=970
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Linear_Equations_And_Systems_Word_Problems/198555: Investing her bonus. Donna invested her $33,000 bonus and received a total of $970 in interest after one year. If part of the money returned 4% and the remainder 2.25% then how much did she invest at each rate? 1 solutions
Answer 149102 by checkley75(3666) on 2009-06-01 16:03:22 (Show Source):
You can put this solution on YOUR website!.04x+.0225(33,000-x)=970
.04x+742.5-.0225x=970
.0175x=970-742.5
.0175x=227.5
x=227.5/.0175
x=13,000 amount invested @ 4%.
33,000-13,000=20,000 amount invested @ 2.25%.
Proof:
.04*13,000+.0225*2450=970
520+450=970
970=970
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