Tutor:

New! Get regular updates about newly solved problems via algebra.com's RSS system.

---

Recent problems solved by 'checkley71'

checkley71 answered: 8399 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399, >>Next

Volume/37601: is the volume between a 5m sphere and a 9m sphere 2530.0292405333? 1 solutions Answer 23294 by checkley71(8403)   on 2006-05-14 13:14:12 (Show Source): You can put this solution on YOUR website! WHAT'S THE QUESTION??????????????

Quadratic_Equations/37606: I am having a problem with solving for real or imaginary solutions. I need clear and direct steps so I can understand this problem. x-1/x+2=2x-3/x+4 What I have so far(not so sure it is right),is: LCD=(x+2)(x+4) I performed FOIL and got x^2+6x+8 Then I tried to multiply it to each numerator, but got a number with x^3 and so on, which does not seem to work with this type of problem. Thank you! 1 solutions Answer 23293 by checkley71(8403)   on 2006-05-14 13:12:46 (Show Source): You can put this solution on YOUR website! WHAT YOU SHOULD BE DOING IS CROSS MULTIPLYING THE TWO FRACTIONS THUS (X-1)(X+4)=(X+2)(2X-3) NOW WE HAVE X~2+3X-4=2X~2+X-6 OR X~2-2X+2

Linear-equations/37730: When solving a linear inequality, do you always need to solve for y? 1 solutions Answer 23291 by checkley71(8403)   on 2006-05-14 13:04:27 (Show Source): You can put this solution on YOUR website! IT DEBENDS IF THAT IS THE ONLY VARIABLE YES. BUT IF THERE ARE MORE THAN ONE VARIABLE YOU HAVE TO SOLVE FOR ALL OF THEM.

Linear_Equations_And_Systems_Word_Problems/37656: This question is from textbook Four oranges and five apples cost $2.00. Three oranges and four apples cost $1.56. Find the cost of an orange and the cost of an apple. 1 solutions Answer 23290 by checkley71(8403)   on 2006-05-14 13:02:53 (Show Source): You can put this solution on YOUR website! 4OR+5A=200 & 3OR+4A=156 IF WE MULTIPLY THE FIRST EAUATION BY 3 AND THE SECOND BY 4 WE GET 12OR+15A=600 & 12OR+16A=624 AND SUBTRACT THESE TWO WE GET ------------------ 0OR-1A=-24 OR A=24 THEN 4OR+5*24=200 OR 4OR+120=200 OR 4OR=80 OR OR=80/4 OR OR=20 PROOF 4*20+5*24=200 OR 80+120=200 OR 200=200 & 3*20+4*24=156 OR 60+96=156 OR 156=156

Miscellaneous_Word_Problems/37692: Each of three colleges sent one male and one female student to a conference. How many ways can the 6 students be seated in a row of 6 chairs if the students can sit in any order? How do I do this problem? 1 solutions Answer 23289 by checkley71(8403)   on 2006-05-14 12:50:57 (Show Source): You can put this solution on YOUR website! FIRST CHAIR HAS 6 POSIBILITIES THE SECOND CHAIR HAS 5 THE NEXT 4 THE NEXT 3 THE NEXT 2 AND THE LAST ONLY ONE THEREFORE THE POSIBILITIES ARE 6*5*4*3*2*1 OR 720

Linear-systems/37694: Determine the intercepts for the linear rule, 4y - 7x= 28 1 solutions Answer 23287 by checkley71(8403)   on 2006-05-14 12:37:24 (Show Source): You can put this solution on YOUR website! 4Y-7X=28 OR IN THE FORM OF Y=mX+b WE HAVE 4Y=7X+28 OR Y=7/4*X+7 THUS THE Y INTERCEPT IS 7 AND SETTING Y=0 WE GWT 0=7/4*X+7 OR 7/4*X=-7 OR X=-7(4/7) OR X=-4 IS THE X INTERCEP

Polynomials-and-rational-expressions/37699: can someone please the factor the differences of two squares 2 question, thanks b^2-144 x^-81 1 solutions Answer 23286 by checkley71(8403)   on 2006-05-14 12:30:06 (Show Source): You can put this solution on YOUR website! B~2-144=0 THEN SQRT B=SQRT144 OR B=12 X~2-81=0 THEN SQRT X=SQRT 81 OR X=9 IF X~2 IS THE RIGHT TERM & THE DIFFERENCE OF THESE TWO SQUARES IS 12-9 OR 3 OR 9-12 OR -3

Expressions-with-variables/37702: Must solve using substitution 2x+y=4 y=4x+1 1 solutions Answer 23285 by checkley71(8403)   on 2006-05-14 12:26:31 (Show Source): You can put this solution on YOUR website! IF Y=4X+1 THE SUBSTITUTING (4X+1) FOR Y IN EQUATION 1 WE GET 2X+(4X+1)=4 OR 2X+4X+1=4 OR 6X=3 OR X=3/6 OR X=1/2 THEN Y=4*1/2+1 OR Y=2+1 OR Y=3 PROOF 3=4*1/2+1 OR 3=2+1 OR 3-3 & 2*1/2+3=4 OR 1+3=4 OR 4=4

Expressions-with-variables/37703: x+y=38 x=2y-25 must solve using substitution 1 solutions Answer 23284 by checkley71(8403)   on 2006-05-14 12:21:46 (Show Source): You can put this solution on YOUR website! IF X=2Y-25 THEN SUBSTITUTING (2Y-25) FOR X IN EQUATION 1 WE GET (2Y-25)+Y=38 OR 3Y=63 OR Y=63/3 OR Y=21 THE X=2*21-25 OR X=42-25 OR X=17 PROOF 1+21=38 & 17=2*21-25OR 17=42-25 OR 17=17

Surface-area/37728: what is the volume and surface area of a cylinder whose dimensions are height 3cm and radius 4cm 1 solutions Answer 23283 by checkley71(8403)   on 2006-05-14 12:10:57 (Show Source): You can put this solution on YOUR website! VOLUME = PI*R~2*H OR 3.14*4~2*3 OR 150.72 CM~3 SURFACE AREA = PI*2*R*H OR 3.14*2*3*4 OR 75.36 CM~2

Equations/37707: Solve the following simultaneous equation: 2a + 9 = b; 7a = 1 - 3b Please show any working out, and thank you in advance for your help 1 solutions Answer 23282 by checkley71(8403)   on 2006-05-14 12:06:23 (Show Source): You can put this solution on YOUR website! IF B=2A+9 THEN 7A=1-3(2A+9) OR 7A=1-6A-27 OR 13A=-26 OR A=-26/13 OR A=-2 THEN 7*-2=1-3B OR -14=1-3B OR -15=-3B OR B=-15/3 OR B=5

Equations/37708: Solve the following simultaneous equation: r^2 + s - 7 = 0; r - s = 5 Please show any working out and thank you in advance for your help 1 solutions Answer 23274 by checkley71(8403)   on 2006-05-14 11:34:22 (Show Source): You can put this solution on YOUR website! R=S-5 NOW SUBSTITUTING S-5 FOR R WE GET (S-5)~2+S=7 OR S~2-10S+25+S=7 OR S~2-9S+18=0 OR (S-6)(S-3)=0 OR S=6 & S=3 THEN R=6-5 OR R=1 & R=3-5 OR R=-2

Polynomials-and-rational-expressions/37711: rewrite the middle term as the sum of two terms and then factor by grouping x^2+9x+20 1 solutions Answer 23272 by checkley71(8403)   on 2006-05-14 11:26:22 (Show Source): You can put this solution on YOUR website! X~2+5X+4X+20 OR X(X+5)+4(X+5) OR (X+4)(X+5)

Graphs/37714: Solve the system by addition. –3x + 5y = 8 x + 2y = 1 1 solutions Answer 23270 by checkley71(8403)   on 2006-05-14 11:22:56 (Show Source): You can put this solution on YOUR website! -3X+5Y=8 X+2Y=1 MULTIPLYING THE SECOND EQUATION BY 3 WE GET 3X+6Y=3NOW WE ADD EQUATION ONE TO THIS EQUATION -3X+5Y=8 -------- 0+11Y=11 OR Y=1 SUBSTIRUTING 1 FOR Y WE NOW GET -3X+5*1=8 OR -3X=3 OR X=-1 PROOF -1=2*1=1 OR -1+2=1 OR 1=1

Graphs/37716: The sum of two numbers is 30. Their difference is 6. What are the two numbers? 1 solutions Answer 23268 by checkley71(8403)   on 2006-05-14 11:10:13 (Show Source): You can put this solution on YOUR website! X+Y=30 & X-Y=6 THEN X=6+Y OR (6+Y)+Y=30 OR 6+2Y=30 OR 2Y=24 OR Y=12 THEN X+12=30 OR X=30-12 OR X=18 PROOF 18+12=30 & 18-12=6

Systems-of-equations/37719: How do you do y= 2x + 3 using substitution? y= 3x + 1 1 solutions Answer 23267 by checkley71(8403)   on 2006-05-14 11:02:30 (Show Source): You can put this solution on YOUR website! y=2x+3 now we substitute 2x+3 for y in equation #2 we get 2x+3=3x+1 or -x=-2 or x=2 then y=2*2+3 or y=7 & y=2*3+1 or y=7

Equations/37450: This question is from textbook MIDDLE SCHOOL MATHEMATICS w+7/8=3/4 1 solutions Answer 23090 by checkley71(8403)   on 2006-05-11 20:52:24 (Show Source): You can put this solution on YOUR website! W+7/8=3/4 OR W=3/4-7/8 OR W=6/8-7/8 OR W=-1/8 PROOF -1/8+7/8=3/4 OR 6/8=3/4 OR 3/4=3/4

Probability-and-statistics/37424: (a) If we roll two fair dice, what is the probability that a total of nine shows? (b) if we toss four fair coins, what is the probability that we get exactly two heads? 1 solutions Answer 23089 by checkley71(8403)   on 2006-05-11 20:50:03 (Show Source): You can put this solution on YOUR website! TOTAL OUTCOMES=36 (6*6) WAYS TO GET NINE ARE 3&6 4&5 5&4 6&3 OR 4 WAYS TO GET NINE TOTAL THEREFOIRE 4/36 = 1/8 OR 12.5% OF GETTING A 9 TOTAL OUTCOMES=16 AND 6 WILL HAVE 2 HEADS THUS HHTT, HTHT, HTTH, THHT, TTHH, THTH OR 6/16 OR 37.5%

Expressions-with-variables/37309: This question is from textbook Elementary and intermediate Algebra help me with the substitution method word problems. ---------------------------------------------------- Mrs. brighton invested $30,000 and received $2300.00 in interest. If she invested part of the money at 10% and the remainder at 5%, then how much did she invest at each rate ? --------------------------------------------------------------------------- tickets for a concert we're sold to adults for $3.00 and to students at $2.00. If the total receipts we're $824.00 and twice as many adult tickets as student tickets we're sold, then how many of each we're sold ? 1 solutions Answer 23088 by checkley71(8403)   on 2006-05-11 20:35:01 (Show Source): You can put this solution on YOUR website! .1X+.05(30000-X)=2300 OR .1X+1500-.05X=2300 OR .05X=2300-1500 OR .05X=800 OR X=800/.05 OR X=16000 OR $16000 INVESTED @ 10% & 30000-16000=$14000NVESTED @5% 2A*3+A*2=824 OR 6A+2A=824 THEN 8A=824 OR A=103 STUDENT TICKETS@2=$206 AND 2*103*3=$618 AND $206+$618=$824

Proportions/37315: This question is from textbook Laura invested $2000. Some at 8% per year and the rest at 10% giving her a total income of $176 per year. How much money did she invest at 8%. I know that I need to create a table. I'm stuck as to what to do next. I appreciate your help and thanks so much! Amount invested x Rate = Interest Investment A 2000 7% .07(2000) Investment B Total Investment 176 1 solutions Answer 23086 by checkley71(8403)   on 2006-05-11 20:25:18 (Show Source): You can put this solution on YOUR website! .08X+.1(2000-X)=176 OR .08X+200-.1X=176 OR -.02X=-24 OR X=24/.02 OR X=1200 THUS 1200 WAS INVESTED @ 8% WHILE 2000-1200=800 INVESTED @ 10% PROOF.08*1200+.1*800=176 OR 96+80=176 OR 176=176 INVESTMENT A 1200@8%=$96 INVESTMENT B 800*10%=$80 TOTAL INVESTMENT $176

Money_Word_Problems/37448: Vern has investments totaling $11,000 in two accounts. Once account is a savings account paying 6% interest and the other is a bond paying 9%. If the annual interest from the two investments was $855: a. How much did he have invested at the 6% rate? A) $4,500 B) $6,500 C) $6,600 D) $9,900 b. How much did he have invested at the 9% rate? A) $4,500 B) $6,500 C) $6,600 D) $9,900 c. How much interest did the 6% account earn? A) $270 B) $585 C) $660 D) $990 d. How much interest did the 9% account earn? A) $270 B) $585 C) $660 D) $990 1 solutions Answer 23084 by checkley71(8403)   on 2006-05-11 20:17:18 (Show Source): You can put this solution on YOUR website! .06X+.09(11000-X)=855 OR .06X+990-.09X=855 OR -.03X=855-990 OR .03X=135 OR X=135/.03 OR X=4500 & 11000-4500=6500. 4500 INVESTED @ 6% & 6500 INVESTED @9% .06*4500=270 INTEREST FOR THE 6% INVESTMENT .09*6500=585 FOR THE 9% INVESTMENT

Polynomials-and-rational-expressions/37260: This question is from textbook Elementary Algebra 1 solutions Answer 23083 by checkley71(8403)   on 2006-05-11 20:06:54 (Show Source): You can put this solution on YOUR website! 10X~3-25X~2+2X-5 OR 5X~2(2X-5)+(2X-5) OR (5X~2+1)(2X-5)

Linear-equations/37302: This question is from textbook Elementary and intermediate Algebra please help me with the substitution method. 3(y-1)=2(x-3) 3y-2x=-3 ------------ y=3x y=3x+1 ------------- 1 solutions Answer 23080 by checkley71(8403)   on 2006-05-11 18:51:33 (Show Source): You can put this solution on YOUR website! 3(Y-1)=2(X-3) OR 3Y=2X-6 OR Y=(2X-6)/2 SUB (2X-6)/2 FOR Y IN EQUATION #2 WE GET 3(2X-6)/2-2X=-3 OR (6X-18)/2-2X=-3 OR 3X-9-2X=-3 OR X=6 THWN Y=(2*6-6)/2 OR Y=(12-6)/2 OR Y=6/2 OR Y=3 Y=3X SUB IN EQUATION #2 WE GET 3X=3X+1 3X-3X=1 0=1 NO SOLUTIONS

Signed-numbers/37305: Translate the English sentence into an equation using the variables indicated: The ratio of brick houses to wooden houses in a particular city is 5 to 11. Let b = the number of brick houses and w = the number of wooden houses. 1 solutions Answer 23079 by checkley71(8403)   on 2006-05-11 18:43:22 (Show Source): You can put this solution on YOUR website! THE RATIO OR BRICK TO WOODEN HOUSES IS 5 TO 11 OR 5:11 OR 5/11

Polynomials-and-rational-expressions/37334: Simplify 4 sqrt 16x^3y^2 - 5y sqrt 4x^3. Not sure how to handle this. Any help is greatly appreciated. 1 solutions Answer 23078 by checkley71(8403)   on 2006-05-11 18:40:55 (Show Source): You can put this solution on YOUR website! IF YOU MEAN 4SQRT[16X~3Y~2]-5SQRT[4X~3] THEN 4*4X*YSQRT[X]-5*2XSQRT[X] OR 16XYSQRT[X]-10SQRT[X]

Expressions-with-variables/37342: Lisa Chen invested $24,000, part of it at 8% and the rest at 7.2%. How much did she invest at each rate if her income from the 8% investment is 2/3 that of the 7% investment? This is a multiple choice question so by inserting different answers I was able to figure out that the answers are $15,000 at 7.2% and $9,000 at 8%. I still don't know how to do the problem though. Please help me with this one. Thanks!! 1 solutions Answer 23077 by checkley71(8403)   on 2006-05-11 18:33:29 (Show Source): You can put this solution on YOUR website! X*.08=2/3*.072(2400-X) OR .08X=.048(2400-X) OR .08X=115.2-.048X OR .08X+.048X=115.2 OR .128=115.2 OR X=900 THEN Y=2400-900 OR Y=1500 PROOF 900*.08=2/3*.072*1500 OR 72=2/3*108 OR 72=216/3 OR 72=72

Percentage-and-ratio-word-problems/37356: Amanda has 400ft of lumber to frame a rectangular patio the perimeter of a rectangle is 2 times length plus 2 times width.She wants to maximize the area of her patio.What sould the dimensions of the patio be? and show the maximum area of the patio is calculated from the algebraic equation? 1 solutions Answer 23076 by checkley71(8403)   on 2006-05-11 18:23:02 (Show Source): You can put this solution on YOUR website! THE MAXIMUM AREA FOR A RECTANGLEIS IN THE FORM OF A SQUARE THUS 4S=400 OR S=100 WHERE S=ONE SIDE

Miscellaneous_Word_Problems/37382: In construction, floor space must be given for staircases. If the second floor is 3.6 meters above the first floor and a contractor is using the standard step pattern of 28 cm of tread for 18 cm of rise then how many steps are needed to get from the first to the second floor and how much linear distance will need to be used for the staircase? 1 solutions Answer 23075 by checkley71(8403)   on 2006-05-11 18:17:49 (Show Source): You can put this solution on YOUR website! 3.6 METERS =360 CM SO THE NUMBER OF RISERS NEEDED ARE 360/18=20 RISERS OR 19 STEPS. ALSO 19*28=252 CM NEEDED FOR THE STAIRS.

Expressions-with-variables/37396: Is there a formula that could be used to explain how you add consecutive numbers to make multiples of 100.eg.18+19=19=20=21=22=100 38+39+40+41+42=200 that would be suitable for a twelve year old to be able to solve such problems? 1 solutions Answer 23072 by checkley71(8403)   on 2006-05-11 18:10:09 (Show Source): You can put this solution on YOUR website! IF YOU DIVIDE 100 BY ANY ODD NUMBER (3,5,7,9,11,13,15,ETC) THAT GIVES YOU A WHOLE NUMBER (IE 100/5=20) THIS TELLS YOU THAT 5 SEQUENTIAL NUMBERS WITH 20 BEING THE MIDDLE NUMBER IS A SOLUTION: THUS 18+19+20+21+22=100 OR IF YOU DIVIDE 2600 BY 900/15=60 THUS 15 CONSECUTIVE NUMBERS WITH 60 AS THE MIDDLE NUMBER WILL ADD UP TO 900 THUS 53+54+55+56+57+58+59+60+61+62+63+64+65+66+67=900 HOPE THIS HELPS. IT'S NOT VERY SIMPLE BUT IT DOES WORK. TRY IT WITH 400/25=16 OR 25 NUMBERS WITH 16 AS THE MIDDLE NUMBER TRY IT WITH 2200/11=200 OR 11 NUMBERS WIT 200 AS THE MIDDLE NUMBER

Expressions-with-variables/37412: a=b+3(4-c) if b equals 5 and c equals 2, what is the value of a? please show me the work so i can understand how to do it myself 1 solutions Answer 23063 by checkley71(8403)   on 2006-05-11 17:35:06 (Show Source): You can put this solution on YOUR website! A=B+3(4-C) OR A=5+3(4-2) OR A=5+12-3*2 OR A=17-6 OR A=11

Expressions-with-variables/37403: x-2y=2 2x+3y=11 use substitution method to solve system if dependant or inconsistant so indicate 1 solutions Answer 23061 by checkley71(8403)   on 2006-05-11 17:32:15 (Show Source): You can put this solution on YOUR website! X=2Y+2 SUB (2Y+2) FOR X IN EQUATION #2 WE GET 2(2Y+2)+3Y=11 OR 4Y+4+3Y=11 OR 7Y=7 OR Y=7/7 OR Y=1 THEN X=2Y+2 OR X=2*1+2 OR X=4 PROOF 2*4+3*1=11 OR 8+3=11 OR 11=11 & 4-2*1=2 OR 4-2=2 OR 2=2