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# Recent problems solved by 'checkley71'

checkley71 answered: 8399 problems
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 Reduction-of-unit-multipliers/51283: This question is from textbook algebra 1/2 Use one unit multiplier to convert: 120 in. to ft. and 42 ft. to in.1 solutions Answer 34215 by checkley71(8403)   on 2006-09-08 19:59:51 (Show Source): You can put this solution on YOUR website!120/12=10 ft. 42*12=504 inches.
 absolute-value/51173: 4 + x = 2x 1 solutions Answer 34156 by checkley71(8403)   on 2006-09-07 22:52:16 (Show Source): You can put this solution on YOUR website!4+X=2X OR 4=2X-X OR 4=X
 Exponents/51172: John has 4 times as many stamps as Mary. Mary has 4 times as many stamps at Sue. Sue has 4 stamps. How many stamps does John have?1 solutions Answer 34154 by checkley71(8403)   on 2006-09-07 22:49:33 (Show Source): You can put this solution on YOUR website!SUE HAS 4 STAMPS MARY HAS 4TIMES AS MANY OR 4*4=16 STAMPS JOHN HAS 4 TIMES AS MANY STAMPS AS MARY 4*16=54 IS THE NUMBER OF JOHN'S STAMPS.
 Quadratic_Equations/51210: This question is from textbook Beginning Algebra The length of a rectangle is 1 cm more than 4 times its width. If the area of the rectangle is 74 cm^2, find the dimensions of the rectangle to the nearest thousandth.1 solutions Answer 34153 by checkley71(8403)   on 2006-09-07 22:45:17 (Show Source): You can put this solution on YOUR website!L*W=74 & L=4W+1 OR (4W+1)W=74 OR 4W^2+W-74=0 OR USING THE QUADRATIC FORMULA WE GET W=4.178 & -4.428 SO THE WIDTH IS 4.178 & THE LENGTH IS 4*4.178+1 OR 17.712 PROOF 4.178*17.712=74 OR 74=74
 Linear-equations/51216: i would really like someone to help me with this problem i have tried to do it but im not having much luck... NAme the slope of the line and the y intercept 2x+3y+32=0 i tried to subtract 2x from everything but i came out with 1xy+32=0 and that didnt make sense then i tried to change the signs and i got something else funny looking but i really need someone to explain it to me better than my teacher she is a good teacher but i dont understand her.... thanks1 solutions Answer 34150 by checkley71(8403)   on 2006-09-07 22:36:39 (Show Source): You can put this solution on YOUR website!THE EQUATION FOR THE SLOPE INTERCEPT IS Y=mX+b OR IN THIS CASE WE HAVE 2X+3Y+32=0 OR 3Y=-2X-32 OR Y=-2X/3-32/3 THUS THE SLOPE (m)IS -2/3 &NTHE Y INTERCEPT (b) IS -32/3.
 Linear-equations/51218: i would also like help with this please Write an equation in slope-intercept form that satisfies each condition. slope -1/2,passes through (2,-3) i did it like -3=-1/2(2)-b but i dont think thats right please help1 solutions Answer 34149 by checkley71(8403)   on 2006-09-07 22:32:19 (Show Source): You can put this solution on YOUR website!Y=mX+B OR IN THIS CASE WE HAVE Y=-X/2+b & -3=-2/2+b OR -3=-1+b OR b=-2 THUS WE HAVE Y=-X/2-2 YOU WERE ON THE RIGHT TRACK.
 Linear-equations/51215: i really need someones help with this problem Find the slope of the line that passes through... (-6,-5)and(4,1) thanks a bunch1 solutions Answer 34148 by checkley71(8403)   on 2006-09-07 22:22:01 (Show Source): You can put this solution on YOUR website!YOU HAVE (X1,Y1) & (X2,Y2) OR (-6,-5) & (4,1) SO ALL WE NEED TO DO IS FIND Y2-Y1 & X2-X1 SO WE HAVE FOR THE Y VALUES (1-[-5]) OR 1+5=6 FOR THE Y VALUE FOR THE X VALUE WE HAVE (4-[-6]) OR 4+6=10 NOW WE DIVIDE THE Y VALUE BY THE X VALUE THUS 6/10 OR .6 FOR THE SLOPE OF A LINE PASSING THROUGH THE POINTS (-6,-5) & (4,1)
 Miscellaneous_Word_Problems/51211: The main road in Belleville is 7 3/10 miles long. So far, 2 3/4 miles have been repaved. How many miles have not been repaved?1 solutions Answer 34146 by checkley71(8403)   on 2006-09-07 22:15:23 (Show Source): You can put this solution on YOUR website!7 3/10-2 3/4 OR 7.3-2.75=4.55 MILES TO BE PAVED. DECIMAL SOLUTION FRACTION SOLUTION 7 3/10=73/10 & 2 3/4=11/4 SO 73/10-11/4 REQUIRES FINDING A COMMON DENOMINATOR THAT 4 & 10 is evenly divisable by. finding the factors or 4 & 10 helps find the lowest commmon denominator thus 2*2=4 & 2*5=10 both denominators have a common factor of 2 therefotre we only need one of the 2s but we need the other 2 & the 5 thus 2*2*5=20 which is the lowest common denominator. you could have just multiplied 4*10=40 but this would not be the lowest common denominator but a common denominator that works. now change each fraction into a fraction with a denominator of 20 by multiplying the 73/10 by 2/2 we get 146/20 & multiplying 11/4 by 5/5 we get 55/20. note that 2/2 & 5/5 is just another way of expressing the number 1 thus any number multiplied by 1 is the same number just in a different form. now we can subtract 55/20 from 146/20 thus (146-55)/20 or 91/20 or 4 11/20 & 11/20=.55 so we still have an answer of 4.55
 Quadratic_Equations/51209: This question is from textbook Beginning Algebra Find the x-intercepts. y=x^2-2X-151 solutions Answer 34144 by checkley71(8403)   on 2006-09-07 22:01:10 (Show Source): You can put this solution on YOUR website!Y=X^2-2X-15 OR Y=(X-5)(X+3) OR X=5 & X=-3
 Numeric_Fractions/51204: Simplify 3^5 divided by 3^-21 solutions Answer 34141 by checkley71(8403)   on 2006-09-07 21:54:45 (Show Source): You can put this solution on YOUR website!3^5/3^2 OR 3*3*3*3*3/3*3 OR 3*3*3 OR 3^3 OR 27 ALSO 3^(5-2)=3^3
 Quadratic_Equations/51200: This question is from textbook Beginning Algebra Can I get some help with this problem? 2x^2-4x-11=01 solutions Answer 34139 by checkley71(8403)   on 2006-09-07 21:51:15 (Show Source): You can put this solution on YOUR website!2X^2-4X-11=0 OR USING THE QUADRATIC EQUATION WE GET X=3.5495 & X=-1.5495
 Inequalities/51178: I cannot figure out this answer: 3x-5(3x-7)=2(x+9)+45 1 solutions Answer 34138 by checkley71(8403)   on 2006-09-07 21:44:41 (Show Source): You can put this solution on YOUR website!3X-5(3X-7)=2(X+9)+45 OR 3X-15X+35=2X+18+45 OR -12X+35=2X+63 OR -14X=28 OR 14X=-28 OR X=-28/14 OR X=-2
 Number-Line/51194: Three times one number added to five times another number is 54. The second number is two less than the first. Find the numbers.1 solutions Answer 34136 by checkley71(8403)   on 2006-09-07 21:36:49 (Show Source): You can put this solution on YOUR website!3X+5Y=54 & 5Y=3X-2 THUS 3X=54-5Y THUS 5Y=(54-5Y)-2 OR 5Y=54-5Y-2 OR 10Y=52 OR Y=52/10 OR Y=5.2 THEN 5*5.2=3X-2 OR 26=3X-2 OR 3X=28 OR X=28/3
 Rectangles/51193: If you have a rectangle thats 30 inches high and 40 inches wide. What is the diagonal measurement1 solutions Answer 34135 by checkley71(8403)   on 2006-09-07 21:25:56 (Show Source): You can put this solution on YOUR website!THE DIAGONAL OF A RECTANGLE FORMS A RIGHT TRIANGLE THUS WE HAVE A WAY TO FIND THE DIAGONAL OR THE HYPOTENUSE (LONG SIDE) OF THE TRIANGLE. IT'S CALLED THE PYTHAGORIAN THEROM A^2+B^2=C^2. WE HAVE THE A & B VALUES (30 & 40) NOW WE SOLVE FOR C THE LONG SIDE. 30^2+40^2=C^2 OR 900+1600=C^2 OR C^2=2500 OR C=SQRT2500 OR C=50 INCHES FOR THE DIAGONAL.
 Exponents/51179: 7.8+78+0.781 solutions Answer 34134 by checkley71(8403)   on 2006-09-07 21:20:31 (Show Source): You can put this solution on YOUR website!07.80 78.00 00.78 ---- 86.58 SECRET IS TO LINE UP ALL THE DECIMALS, FILL IN THE MISSING ZEROS AND JUST ADD.
 Quadratic_Equations/51189: I am having a hard time understanding how to solve this problem. John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation. Show clearly the algebraic steps which prove your dimensions are the maximum area which can be obtained. Use the vertex form to find the maximum area. 1 solutions Answer 34133 by checkley71(8403)   on 2006-09-07 21:15:22 (Show Source): You can put this solution on YOUR website!2L+2W=300 OR 2(L+W)=300 OR (L+W)=300/2 OR L+W=150 THUS TO MAXIMIZE THE AREA L SHOULD = W SO L&W ARE 75 FEET. THE MAXIMUM AREA WITH THE MINIMUM PERIMETER IS A SQUARE (ALL SIDES ARE EQUAL).
 Numeric_Fractions/51162: a nuber n plus 81 solutions Answer 34119 by checkley71(8403)   on 2006-09-07 19:57:55 (Show Source): You can put this solution on YOUR website!N+8
 Rational-functions/51159: This question is from textbook algebra 1, applications, graphs, and equations how would i graph this linear system, step by step, i dont know how to graph or how to get the coordinates, to graph the system? the system is 2x+y=13 5x-2y=1 how would i put 2x+y=13 on a graph and 5x-2y=1 on a graph?? please if you could explain step by step for me??!! thanks!1 solutions Answer 34117 by checkley71(8403)   on 2006-09-07 19:55:39 (Show Source): You can put this solution on YOUR website!FIRST GET SOME GRAPH PAPER. NOW DRAW A HORIZONTAL LINE ACROSS THE MIDDLE OF THE PAGE. THIS IS THE X AXIS. NOW DRAW A VERTICLE LINE DOWN THE MIDDLE OF THE PAGE. THIS IS THE Y AXIS. WHERE THESE TWO LINES INTERSECT (CROSS) IS THE (X,Y) POINTS (0,0). NOW MARK EACH SQUARE TO THE RIGHT OF THE (0,0) INTERSECTION ON THE X AXIS 1,2,3,4,5,6,7,8,9 & 10. NOW MARK THE LEFT SIDE OF THIS X LINE STARTING AT (0,0) -1,-2,-3,-4,-5,-6,-7,-8,-9 & -10. NOW MARK THE SQUARES ABOVE THE INTERSECTION OF 0,0 ON THE Y AXIS 1,2,3,4,5,6,7,8,9,10,11,12,13 & 14. NOW MARK ALL THE SQUARES BELOW THE (0,0) INTERSECTION ON THE Y AXIS -1,-2,-3,-4, -5,-6,-7,-8,-9, & -10. YOU NOW HAVE A GRAPH FOR PLOTTING THE LINES REPRESENTED BY THE EQUATIONS YOUR TRYING TO GRAPH IN THE FORM Y=mX+b WHERE m=THE SLOPE & b=THE Y INTERCEPT. 2X+Y=13 MUST NOW BE TRANFORMED TO THE STANDARD LINE FORMULA THUS Y=-2X+13. THIS EQUATION HAS A SLOPE (m) OF -2 & a y intercept of 13 (0,13). NOW TO FIND THE X INTERCEPT TO HAVE TWO POINTS TO DRAW A THE LINE THROUGH WE SET Y=0 THUS 0=-2X+13 OR -2X=-13 OR 2X=13 OR X=13/2 OR X=6.5 (6.5,0). TO PLOT THE POINT (0,13) START AT THE INTRSECTION (0,0) COUNT UP 13 SQUARES AND MARK THIS POINT(0,13). NOW STARTING AGAIN AT THE INTERSECTION (0,0) AND COUNT 6 AND 1/2 SQUARES TO THE RIGHT OF THIS POINT AND MARK THIS POINT (6.5,0). NOW DRAW A LINE THROUGH THESE 2 POINTS. YOU NOW HAVE A LINE REPRESENTED BY THE EQUATION 2X+Y=13 WITH A SLOPE OF -2 AND A Y INTERCEPT OF 13. NOW YOU TRY THE NEXT EQUATION USING THE SAME GRAPH. 5X-2Y=1 OR -2Y=-5X+1 OR 2Y=5X-1 OR Y=5/2X-1/2 WHICH HAS A SLOPE OF 5/2 OR 2.5 AND A Y INTERCEPT OF -1/2 OR .5 (0,-.5) NOW SET Y=0 WE GET 5X-2*0=1 OR 5X=1 OR X=1/5 OR .2 (.2,0)
 Miscellaneous_Word_Problems/51157: Please help me on a problem that I am stuck on. The problems states: collect exactly 4-cups of water. There are only 2 pitchers, which are a 3-cup, and a 5-cup.The pitchers are not graduated, for instance,they can not acurately measure 1/2 cup. How can 4 cups exactly be collected. Thank you. 1 solutions Answer 34112 by checkley71(8403)   on 2006-09-07 19:27:29 (Show Source): You can put this solution on YOUR website!FILL THE 5 QUART PITCHER THEN FILL THE 3 QUART PITCHER. YOU NOW HAVE 2 QUARTS LEFT IN THE 5 QUART PITCHER. EMPTY THE 3 QUART PITCHER & POUR THE 2 QUARTS LEFT IN THE 5 QUART PIRCHER INTO THE 3 QUART PITCHER. NOW REFILL THE 5 QUART PITCHER. NOW FILL THE 3 QUART PITCHER WITH 1 QUART FROM THE 5 QUART PITCHER. YOU NOW HAVE EXACTLY 4 QUARTS IN THE 5 QUART PITCHER.
 Expressions-with-variables/51153: This question is from textbook write an expression for 8 minus the quanity 9 minus t Please explain how to do this. I have until this year been in a special ed math class my skills have advanced but I don't understand this one1 solutions Answer 34111 by checkley71(8403)   on 2006-09-07 19:20:25 (Show Source): You can put this solution on YOUR website!8-9-T
 Equations/51155: how can i find the number of yoga classes the person took using this information a fitness center offers yoga classes for \$10 per class and sells yoga mats for \$19.95.A person paid a total of \$139.95 to the fitness center for yoga classes and a mat. find the number of yoga classes the person took1 solutions Answer 34110 by checkley71(8403)   on 2006-09-07 19:13:42 (Show Source): You can put this solution on YOUR website!12 CLASSES @ 10.00=120.00 PLUS 1 MAT FOR 19.95 FOR A TOTAL OF 120.00+19.95=139.95 THUS WE HAVE 12 CLASSES + 1 MAT
 Polynomials-and-rational-expressions/51142: i have two probelms. (numbers in bold are exponents ) 1) x2-24=2x 2) 2x2+x=31 solutions Answer 34109 by checkley71(8403)   on 2006-09-07 18:52:05 (Show Source): You can put this solution on YOUR website!X^2-24=2X OR X^2+2X-24=0 OR (X-6)(X+4)=0 OR X=6 & X=-4 2X^2+X=3 OR 2X^2+X-3=0 OR (2X+3)(X-1)=0 OR 2X+3=0 OR 2X=-3 OR X=-3/2 & X-1=0 OR X=1
 test/51009: Find two numbers..... 1. Whose sum is 2 and whose product is -63__________ 2. Whose sum is -2 and whose product is -80__________ 3. Whose sum is 4 and whose product is -60__________ 4. Whose sum is -11 and whose product is 28__________1 solutions Answer 34108 by checkley71(8403)   on 2006-09-07 18:35:09 (Show Source): You can put this solution on YOUR website!X+Y=2 & X*Y=-63 OR X=2-Y THEN (2-Y)Y=-63 OR 2Y-Y^2=-63 OR Y^2-2Y-63 OR (Y-9)(Y+7)=0 THEN Y=9 & Y=-7 THEN X=-7 & X=9 X+Y=-2 & X*Y=-80 OR X=-2-Y THEN (-2-Y)Y=-80 OR -2Y-Y^2=-80 OR Y^2+2Y-80=0 OR (Y+10)(Y-8)=0 OR Y=-10 & Y=8 THEN X=8 & X=-10 X+Y=4 & X*Y=-60 OR X=4-Y THEN (4-Y)Y=-60 OR 4Y-Y^2=-60 OR Y^2-4Y-60=0 OR (Y-10)(Y+6)=0 OR Y=10 & Y=-6 THEN X=-6 & X=10 X+Y=11 & X*Y=28 OR X=11-Y THEN (11-Y)Y=28 OR 11Y-Y^2=28 OR Y^2-11+28=0 OR (Y-7)(Y-4)=0 OR Y=7 & Y=4 THEN X=4 & X=7
 Rational-functions/51097: I have 14, 8ft railroad ties. I cannot cut these ties. I need to know the maximum area and dimensions of a rectangle using the uncut ties. So far I have: 2L+2W=112 L+W=56 W=56-L A=L(56-L) A=-L^2+56L L=-b/2a=-56/2(-1)=28 I came up with max area =784'^2 and dimensions 28' x 28'. Then I realize that can't be right because I would have to cut the rr ties. How do I figure in the uncut ties?1 solutions Answer 34105 by checkley71(8403)   on 2006-09-07 18:15:08 (Show Source): You can put this solution on YOUR website!14 8 FOOT TIES CAN MAKE A RECTANGLE OF L+W=14/2 OR L+W=7 OR MAX VALUES OF X&Y ARE 3 & 4 THUS A 3 BY 4 TIE RECTANGLE IS THE MAX SIZE OR (3*8)(4*8)=24*32=768 SQFT. PROOF DRAW RECTANGLE USING 8 FOOT LINES FOR EACH TIE AND YOU'LL FIND A 3 BY 4 RECTANGLE IS THE LARGEST AREA.
 expressions/51135: This question is from textbook Pre-Algebra (x+5)+41 solutions Answer 34104 by checkley71(8403)   on 2006-09-07 18:06:36 (Show Source): You can put this solution on YOUR website!(X+5)+4 OR X+5+4 OR X+9
 Triangles/51088: ISBN-0618372628 If both the length and the width of a rectangle are doubled, how many times is the area of the resulting rectangle?1 solutions Answer 34103 by checkley71(8403)   on 2006-09-07 18:05:12 (Show Source): You can put this solution on YOUR website!X*Y=AREA OF ORIGINAL RECTANGLE SO IF WE DOUBLE BOTH DIMENTIONS WE HAVE 2X*2Y= NEW AREA OR 4X*Y THUS THE ORIGINAL AREA IS INCREASED BY A FACTOR OF 4
 Word_Problems_With_Coins/51133: Homers change jar contains 40 coins consisting of dimes and quarters. If the total value is \$4.90, how many dimes and quaters are there?1 solutions Answer 34102 by checkley71(8403)   on 2006-09-07 18:01:11 (Show Source): You can put this solution on YOUR website!D+Q=40 & 10D+25Q=490 THEN D=40-Q THUS 10(40-Q)+25Q=490 OR 400-10Q+25Q=490 OR 15Q=90 OR Q=90/15 OR Q=6 THEN D+6=40 OR D=40-6 OR D=34 PROOF 10*34+25*6=340+150=490 THUS THERE ARE 6 QUARTERS & 34 DIMES IN HIS JAR.
 Linear-equations/51131: Aqueducts were once used to carry water from rivers using gravity. Water flowing too quickly might damage an aqueduct, but water flowing too slowly might not keep the aquiducts clear. One of the best and most common designs for an aqueduct was to raise it 3 meters for every kilometer in length. What is the slope of an aqueduct built with this design? I need help in understanding how to find the slope from this word problem because I don't understand anything about word problems. So if you could please help me to solve this problem step by step it would be helpful. 1 solutions Answer 34100 by checkley71(8403)   on 2006-09-07 17:55:49 (Show Source): You can put this solution on YOUR website!PICTURE A GRAPH WITH AN X AXIS OF 1000 METERS AND A Y AXIS OF AT LEAST 3 METERS. THE FIRST POINT ON THE LINE FOR THE AQUEDUCT IS (0,0) AND THE SECOND POINT IS (1000,3) THUS YOU HAVE A SLOPE OF (0-3)/(0-1000) OR -3/-1000 OR .003 FOR THE SLOPE OF THE AQUADUCT.
 Numeric_Fractions/51129: x/4=-1 h1 solutions Answer 34097 by checkley71(8403)   on 2006-09-07 17:48:54 (Show Source): You can put this solution on YOUR website!X/4=-1 OR X=-4
 Money_Word_Problems/51124: This question is from textbook ALGEBRA 1 ok IN 5 seconds a athlete runs 40 feet what was his speed.1 solutions Answer 34095 by checkley71(8403)   on 2006-09-07 17:47:19 (Show Source): You can put this solution on YOUR website!40/5=8 FEET PER SECOND OR 8*3600=28,800 FEET PER HOUR OR 28,800/5,280=5.4545 MPH.
 Graphs/51119: Solving by elimination.. 3x+2y=9 -x+3y=81 solutions Answer 34094 by checkley71(8403)   on 2006-09-07 17:35:46 (Show Source): You can put this solution on YOUR website!3X+2Y=9 NOW MULTIPLY THE SECOND EQUATION BY 3 TO GET -3X+9Y=24 NOW ADD THESE TWO EQUATIONS -------------- +11Y=33 OR Y=33/11 OR Y=3 THEN 3X+2*3=9 OR 3X+6=9 OR 3X=3 OR X=1 PROOF -1*1+3*3=8 OR -1+9=8 OR 8=8