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checkley71 answered: 8399 problems
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Answer 36687 by checkley71(8403) on 2006-10-03 07:07:36 (Show Source):
You can put this solution on YOUR website!X*Y=86 & 2X+2Y=40 THUS 2X=40-2Y OR X=20-Y THEN SUBSTITUTE (20-Y) FOR X IN THE FIRST EQUATION WE GET (20-Y)Y=86 OR 20Y-Y^2-86=0 OR -Y^2+20Y-86=0 OR
Y^2-20Y+86=0 USING THE QUADRATIC EQUATION (-B+/-SQRT(B^2-4AC))/2A WE GET ANSWERS OF:
-10+/-SQRT14 OR 13.7442 & 6.258
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Surface-area/54406: This question is from textbook
Susan needs to find out the surface area of a deck that has one side that is 5.75 feet and another that is 8 feet and another that is 3 feet by 5.75 feet. 1 solutions
Answer 36663 by checkley71(8403) on 2006-10-02 21:47:17 (Show Source):
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Geometry_proofs/54370: The sum of the areas of two squares is 225. If one square is 3 units larger per side then the other, find the sizes of the squares. 1 solutions
Answer 36659 by checkley71(8403) on 2006-10-02 21:43:40 (Show Source):
You can put this solution on YOUR website!X^2+(X+3)^2=225 OR X^2+X^2+6X+9=225 OR 2X^2+6X+9-225=0 OR 2X^2+6X-216 OR
X^2+3X-108=0 OR (X-9)(X+12)=0 OR X-9=0 OR X=9 & X+12=0 OR X=-12
THUS THE SMALLER SQUARE IS 9 ON A SIDE & THE LARGER IS 9+3=12 AND THE SUM OF THE AREAS ARE 9^2+12^2=225 OR 81+144=225 OR 225=225
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Geometry_proofs/54372: Find three consecutive integers whose squares add to 110. 1 solutions
Answer 36654 by checkley71(8403) on 2006-10-02 21:35:06 (Show Source):
You can put this solution on YOUR website!X^2+(X+1)^2+(X+2)^2=110 OR X^2+X^2+2X+1+X^2+4X+4=110 OR 3X^2+6X+5=110 OR
3X^2+6X-105 OR X^2+2X-35=0 OR (X+7)(X-5)=0 OR X+7=0 OR X=-7 & X-5=0 OR X=5 THEN
X+1=6 & X+2=7 THUS 5, 6 & 7 ARE THE THREE CONSECUTIVE INTERGERS WHEN SQUARED EQUAL 110
PROOF 5^2+662+7^2=110 OR 25+36=49=110 OR 110=110
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Square-cubic-other-roots/54404: I am stuck on correct answer for:
square root of 48 - sq. root of 12 =
I am not using a specific book. I am just practicing...
1 solutions
Answer 36648 by checkley71(8403) on 2006-10-02 21:25:13 (Show Source):
You can put this solution on YOUR website!SQRT48=SQRT16*3 & THE SQRT16*3=4SQRT3 REMOVING THE SQRT OF 16=4 OUTSIDE THE SQRT.
THEN THE SQRT12=SQRT4*3 OR 2SQRT3 REMOVING THE SQRT OF 4=2 OUTSIDE THE SQRT.
SUBTRACTING 2SQRT3 FROM 4SQRT3 WE GET 2SQRT3
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Equations/54389: The length of a rectangle is 3 times the width. The perimeter is 96 cm. Find the width and length. 1 solutions
Answer 36643 by checkley71(8403) on 2006-10-02 21:17:00 (Show Source):
You can put this solution on YOUR website!PERIMETER IS EQUAL TO 2 TIMES THE LENGTH PLUS 2 TIMES THE WIDTH
THUS P=2L+2W OR 96=2*3W+2*W OR 96=6W+2W OR 96=8W OR W=96/8 OR W=12 THUS
86=2*L+2*12 OR 96=2*L+24 OR 96-24=2L OR 72=2L OR 72/2=L OR L=36
PROOF 86=2*36+2*12 OR 86=72+24 OR 86=86 WHEN THE LENGTH (36) IS 3 TIMES THE WIDTH (12) 3*12=36.
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Surface-area/54342: This question is from textbook Elementary and Intermediate Algebra
A boxing ring is in the shape of a square with 20 ft. on each side. How far apart are the fighters when they are in opposite corners of the ring? 1 solutions
Answer 36612 by checkley71(8403) on 2006-10-02 16:29:03 (Show Source):
You can put this solution on YOUR website!THIS PROBLEM IS A RIGHT TRIANGLE WITH 2 SIDES = TO 20 FEET AND THE HYPOTENUSE THE DISTANCE BETWEEN THE OPPOSITE CORNERS. THUS THE FORMULA A^2+B^2=C^2 THUS
20^2+20^2=C^2 OR 400+400=C^2 OR 800=C^2 OR C=28.28 FEET FOR THE DIAGONAL OF THE 20 FOOT SQUARE RING.
c^2 is the same as c*c or (c squared). 800 IS THE SAME AS 28.28*28.28 or 28.28 is the square root of 800 or 800=28.28*28.28 (or 28.28^2 or 28.28 squared=800)
another example: x^2=25 or x^2=x*x & 25=5*5 thus the sqare root of x^2=x & the square root of 25=5 then x=5.
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Linear-equations/54345: 1. Find the slope of the line containing the points (3,1) and (-4, -1).
2. Determine the equation of the line that passes through the points (-4, -3) and (2,2) 1 solutions
Answer 36611 by checkley71(8403) on 2006-10-02 16:24:32 (Show Source):
You can put this solution on YOUR website!THE SLOPE THROUGH THESE TWO POINTS IS (-1-1)/-4-3) OR -2/-7 OR 2/7 FOR THE SLOPE.
NOW SUBSTITUTING ONE OF THE SET OF POINTS INTO THE EQUATION Y=mX+b WE GET 1=(2/7)*3+b OR 1=6/7+b OR b=1-6/7 OR b=1/7. THUS THE EQUATION OF THIS LINE IS Y=6/7X+1/7
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Linear_Equations_And_Systems_Word_Problems/54349: A chemist has two salt solutions. One solution is 20% salt and the other if 50% salt. How many liters of each must be used to produce 600 liters of a solution that is 10% salt? 1 solutions
Answer 36607 by checkley71(8403) on 2006-10-02 16:13:18 (Show Source):
You can put this solution on YOUR website!YOU CAN'T MIX A 20% SOLUTION WITH A 50% SOLUTION AND GET A 10% SOLUTION WITHOUT ADDING WATER OR SOME OTHER NON-SALT SOLUTION. THE HIGH & LOW SOLUTIONS ARE 599*.2+1*.5=600X OR 119.8+.5=600X OR 120.3=600X OR 120.3/600=X OR X=20.09% SOLUTION AND A MAX SOLUTION OF 599*.5+1*.2=600X OR 299.5+.2=600X OR 299.7/600=X OR X=49.95%.
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Money_Word_Problems/54273: If I invest $18,750 in two different accounts and one account earns 12% interest and the other earns 10% interest, and at the end of the year have a total $20,867 (original amount + interest), how much did I invest in each account? 1 solutions
Answer 36593 by checkley71(8403) on 2006-10-02 11:29:07 (Show Source):
You can put this solution on YOUR website!INVESTING $ 18,750 AND OBTAINING $ 20,867 TOTAL FOR INTEREST FOR THE 10% & 12% INVESTMENTS.
WE HAVE $20,867-$18,750=$2,117. THUS THERE ARE TWO PARTS OF THE $18,750 BEING INVESTED X & ($18,750-X).
THUS THE INVESTMENTS ARE .12X+.10(18,750-X)=2,117 OR .12X+1,875-.10X=2,117 OR
.12X-.10X=2,117-1,875 OR .02X=242 OR X=242/.02 OR X=12,100 INVESTED @ 12% &
18,750-12,100=6,650 INVESTED @ 10%
PROOF .12*12,100+.10*6,650=2,117 OR 1,452+665=2,117 OR 2,117=2,117
& 18,750+2,117=20,867 OR 20,867=20,867
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Money_Word_Problems/54240: I have $69,000.00 to invest for one year. If B rate bonds pay 4 percent per year and CD's pay 13 percent per year, how much money in each fund do I have to invest to obtain $5730.00 after one year. 1 solutions
Answer 36509 by checkley71(8403) on 2006-10-01 17:35:29 (Show Source):
You can put this solution on YOUR website!5,730=.13x+.04(69,000-x) or 5,730=.13x+2,760-.04x or 5,730-2,760=.13x-.04x or 2,970=.09x or x=2,970/.09 or x=33,000 invested @ 13% & 69,000-33,000=36,000 invested @ 4%
proof 33,000*.13+36,000*.04=5,730 or 4,290+1,440=5,730 or 5,730=5,730
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Quadratic_Equations/54225: This question is from textbook Algebra for College Students
In order to find the domain for the below example, do you need to multiply by the denominator? What follows? Seems that the X-1 would remain? Just looking for the steps/logic. Thank you!

1 solutions
Answer 36505 by checkley71(8403) on 2006-10-01 16:29:06 (Show Source):
You can put this solution on YOUR website!ASSUME (X+4)=7 AND (X-1)=2 THEN ASSUME YOU HAVE 7/7*2 YOU WOULD HAVE 7/14 OR 2 WHICH IS (X-1).
WHATEVER (X+4) EQUALS IT CAN BE CANCELLED OUT FROM THE NUMERATOR & THE DENOMINATOR.
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Exponential-and-logarithmic-functions/53609: This question is from textbook algebra 2
consider this equation 4x-6y=12
a)what do you suppose the graph of this eqation looks like? justify your answer.
b)solve the equation for y and graph the equation.
c)explain how to find the x- and y-intercept. be complete so that you can give your explanation to someone who is still having trouble with intercepts and he or she will be able to follow and understand your explanation.
d)which form of the equation is the best for finding intercepts quickly?why?
e)use the intercepts you found inpart (c) to graph the line. did you get the same line you got in part (b)? should you? explain 1 solutions
Answer 36504 by checkley71(8403) on 2006-10-01 16:24:14 (Show Source):
You can put this solution on YOUR website!YOU'VE ASKED FOR A COMPLETE GEOMETRY LESSON USING GRAPHS. NOT WHAT WE'RE HERE FOR. BUT HERE'S SOME HELP.
THE EQUATION 4X-6Y=12 IN SLOPE INTERCEPT FORM IS -6Y=-4X+12 MULTIPLYING BOTH SIDES BY -I WE GET 6Y=4X-12 OR Y=4/6X-12/6 OR Y=2/3X-2
NOW WE HAVE A LINE DEFINED BY A SLOPE OR 2/3 AND A Y INTERCEPT OF -2 (0,-2) WHICH SAYS WHEN THE X VALUE IS 0 THE Y VALUE IS -2.
SETTING THE Y VALUE TO ZERO WE FIND THE X INTERCEPR THUS 0=2/3X-2 OR 2/3X=2 OR CROSS MULTIPLYING WE GET 2X=6 OR X=6/2 OR X=3 WHEN Y=0 OR (3,0) IS A SECOND POINT ON THE LINE Y=2/3X-2.
TO FIND ANY OTHER POINT ON THIS LINE JUST IDENTIFY AN X OR A Y POINT SUBSTITUTE THIS VALUE IN THIS EQUATION Y=2/3X-2 AND SOLVE FOR THE OTHER UNKNOWN.
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Quadratic_Equations/54224: To be perfectly honest to you...I suck at word problems.
Here is the problem; Find two numbers such that their sum 10 and their product is 22. 1 solutions
Answer 36503 by checkley71(8403) on 2006-10-01 16:12:18 (Show Source):
You can put this solution on YOUR website!IF YOU EXPAND 5+/-SQRT3 YOU GET 5+1.73=6.73 & 5-SQRT3=3.27. WE JUST USED TWO DIFFERENT WAYS OF EXPRESSING THE ANSWER.
X+Y=10 THE X=10-Y & X*Y=22 THEN SUBSTITUTING 10-Y FOR X WE GET (10-Y)Y=22 OR
10Y-Y^2=22 OR Y^2-10Y+22=0 OR (Y-6.73)(Y-3.27)=0 OR Y=6.73 & Y=3.27
PROOF 6.73+3.27=10 OR 10=10 & 6.73*3.27=22 OR 22=22
I BELIEVE YOU MIGHT HAVE COPIED DOWN THE WRONG FIGURES. AS THESE NUMBERS DON'T LOOK LIKE A VALID SOLUTION.
PRODUCT=21 MAKES MORE SENSE THEN THE NUMBERS WOULD BE 3 & 7.
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percentage/53790: Can someone help me on this problem?
I need to identify the rate, base, and amount in the following application. You do not need to solve the applications at this point.
A chemist has 300 milliliters (mL) of solution that is 18% acid. How many milliliters of acid are in the solution?
Thanks, Ashley 1 solutions
Answer 36502 by checkley71(8403) on 2006-10-01 16:02:30 (Show Source):
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Graphs/54186: What is the equation for the line represented by this graph? (I don't know how to put a graph on here to show, so I will describe it. It is a straight line with arrows at each end going up from left to right, it passes through 2 on the x-axis and -1 on the y-axis)
My thought was that I would count so you go over 2 to the left, which would give me -2x and down 1 so that is -1. My answer would be y= -2x -1, but I am not sure I am doing it right. Can anyone help without seeing the graph? 1 solutions
Answer 36500 by checkley71(8403) on 2006-10-01 15:56:28 (Show Source):
You can put this solution on YOUR website!YOU ARE PRESENTING TWO POINTS (2,0) (0,-1). NOW YOU CAN FIND THE SLOPE THUS
(-1-0)/0-2) OR -1/-2 OR 1/2 IS THE SLOPE NOW YOU HAVE THE EQUATION Y=1/2*X-1
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Exponents/54222: x^-1.5=27 . . . . . . I know that the answer is 1/9, but I have no idea how to get there. 1 solutions
Answer 36498 by checkley71(8403) on 2006-10-01 15:38:00 (Show Source):
You can put this solution on YOUR website!X^-1.5=27 OR 1/X^1.5=27 OR SQUARING BOTH SIDES WE GET 1/X^3=27*27 INVERTING BOTH SIDES OF THEEQUATION WE GET X^3=1/27*27 OR X*X*X=1/9*9*9 THEN TAKING THE CUBE ROOT OF BOTH SIDES WE GET X=1/9
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Graphs/54219: Given the equation y=6x-2 what should the graph look like? I am not sure where to start in order to graph this to show what the graph should look like. Could someone please help? 1 solutions
Answer 36496 by checkley71(8403) on 2006-10-01 15:27:15 (Show Source):
You can put this solution on YOUR website!THE LINE REPRESENTED BY Y=6X-2 IS A LINE WITH A SLOPE OF 6 AND A Y INTERCEPT OF -2. SETTING Y=0 WE GET ANOTHER POINT 0=6X-2 OR 6X=2 OR X=2/6 OR X=1/3 THUS WE NOW HAVE TWO POINTS (0,-2)(1/3,0) AND A SLOPE OF 6.
PLOT THE TWO POINTS AND DRAW A LINE THROUGH THEM.
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Equations/54206: This question is from textbook
the spedometer in a car is only correct when the car has new tires. Explain,using appropiate math, what happens as the tire wears down. It may be helpful to get some information on tire tickness of the tread and find out how speed is measured in a car. For example, a 75R14 tire has a diameter of 14 inches. From this you could figure out how far a car travels in one revolution of the wheel, What happens when the tire is worn down,say 1 inch? Illustrate your explanations with diagrams,grapsh and formulas.
It may be helpful to know that 1 mile equals 5280 feet.
hey i need help with this problem..i dont have idea how to begin..
pleaseeee!! help me... ^_^
thank you..
Frankcely Robles 1 solutions
Answer 36494 by checkley71(8403) on 2006-10-01 15:22:04 (Show Source):
You can put this solution on YOUR website!A CIRCLE WITH A DIAMETER OF 14 INCHES HAS A CIRCUMFERANCE OF 2*PI*R OR
2*3.14*7=43.98 INCHES THEREFORE IT TAKES 5280*12/43.98=63,360/43.98=1440.6548 REVOLUTIONS TO COVER 1 MILE.
ASSUMING THE CIRCUMFERANCE IS WOEN DOWN 1 INCH THEN WE HAVE 43.98-1=42.98 INCH CIRCUMFERANCE THUS 63,360/42.98=1474.174 REVOLTIONS TO COVER 1 MILE.
THUS THE LOSS OF 1 INCH REQUIRES THE WHEEL TO MAKE AN ADDITIONAL 1474.174-1440.5448=33.6292 REVOLUTIONS TO COVER 1 MILE.
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Numeric_Fractions/54161: I am a beginner.
I am stuck on correct answer for:
4 6
____ =
4 3
I can't show as needed in this email. The 6 and 3 are supposed to be visually smaller in size.
I am not using a specific book. I am just practicing...
1 solutions
Answer 36441 by checkley71(8403) on 2006-09-30 18:16:31 (Show Source):
You can put this solution on YOUR website!4^6/4^3 OR 4*4*4*4*4*4/4*4*4 OR 4*4*4=64 OR 4^3=64
YES THERE ARE 2 SYMBOLS USED TO REPRESENT SQUARED THEY ARE (~) & (^). ALSO
SOME USE SQRT.
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Equations/54158: Hi, I need help on the following problem.
Your department sends its copying to the photocopy service down the street. The service bills your department $0.09 per page. Your department is considering purchasing a copier for $2750. The expense per page with the copier would be $0.04. If the expected life of the copier is 4 years, how many copies must the department make in the 4-year period to justify the expenditure for the copier? 1 solutions
Answer 36440 by checkley71(8403) on 2006-09-30 18:12:37 (Show Source):
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