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Recent problems solved by 'checkley71'
checkley71 answered: 8399 problems
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1 solutions
Answer 37415 by checkley71(8403)   on 2006-10-08 16:43:05 (Show Source):
You can put this solution on YOUR website!DISTANCE=RATE TIMES TIME
380=50T+60T
380=110T
T=380/110
T=3 5/11 HOURS LATER THEY MEET
PROOF
380=50(3 5/11)+60(3 5/11)
380=50*38/11+60*38/11
380=1900/11+2280/11
380=4180/11
380=380
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Graphs/55152: 28x – 2(10x – 0.365) = 7x + 0.035
1 solutions
Answer 37414 by checkley71(8403) on 2006-10-08 16:34:57 (Show Source):
You can put this solution on YOUR website!28X-2(10X-.365)=7X+.035
28X-20X+.73=7X+.035
8X-7X=.035-.73
X=-.695
PROOF
28*-.695-2(10*-.695-.365)=7*-.695+.035
-19.46-2(-6.95-.365)=-4.865+.035
-19.46-2(-7.315)=-4.83
-19.46+14.63=-4.83
-4.83=-4.83
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Linear-equations/54902: The newspaper said that only 42% of the registered voters in the school board election. If 11.960 people voted, how many registered voters are there? Write an equation.
1 solutions
Answer 37072 by checkley71(8403) on 2006-10-05 20:36:57 (Show Source):
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Equations/54901: I need help on the following problem:
The difference when 7 less than a number is subtracted from twice the number is 12. What is the number?
I have no clue as to how to set up this equation. Please help!
thanks!
1 solutions
Answer 37070 by checkley71(8403) on 2006-10-05 20:33:03 (Show Source):
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Linear_Equations_And_Systems_Word_Problems/54900: This question is from textbook mathematical reasoning
a new football field under construction will have a total length (including end zones) that is 40 feet more than twice its width. the area of the football field must be calculated in order to determine the amount of grass seed is necessary to seed the field. Find the area of the field if its perimeter will be 1040 feet.
1 solutions
Answer 37069 by checkley71(8403) on 2006-10-05 20:30:34 (Show Source):
You can put this solution on YOUR website!LENGTH=40+2*WIDTH
1040=2*LENGTH+2*WIDTH
1040=2(40*2W)+2*W
1040=80+4W+2W
1040-80=6W
960=6W
W=160 THEN
L=40+2*160
L=40+320
L=360
PROOF
1040=2*360+2*160
1040=720+320
1040=1040
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Linear-systems/54827: Paul works for $6 an hour on weekdays, and makes $7 on weekends. Last week he made $250 for 40 hours. Determine how many hours he worked during the week and how many during the weekend.
1 solutions
Answer 37041 by checkley71(8403) on 2006-10-05 17:22:31 (Show Source):
You can put this solution on YOUR website!6X+7(40-X)=250
6X+280-7X=250
-X=250-280
-X=-30
X=30 HOURS WOEKED DURING THE WEEK FOR $6 PER HOUR
40-30=10 HOURS WORKED ON THE WEEKEND FOR $7 PER HOUR
PROOF 6*30+7*10=250
180+70=250
250=250
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expressions/54834: Can someone help me on this?
The length of a rectangular garden is 2 ft. less than 3 times its width. If the perimeter of the garden is 44 ft, find the dimensions of the garden.
Thanks, Lyn
1 solutions
Answer 37040 by checkley71(8403) on 2006-10-05 17:17:26 (Show Source):
You can put this solution on YOUR website!LENGTH=3W-2
WIDTH=W
PERIMETER=2*LENGTH+2*WIDTH
44=2(3W-2)+2W
44=6W-4+2W
44+4=8W
48=8W
W=48/8
W=6 & L=3*6-2 OR L=18-2 L=16
PROOF
44=2*16+2*6
44=32+12
44=44
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Equations/54839: Can someone help me on this?
I need to translate the following statement into an algebraic equation. Let x represent the number:
7 more than a number is 19
Thanks, Lyn
1 solutions
Answer 37039 by checkley71(8403) on 2006-10-05 17:09:48 (Show Source):
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Complex_Numbers/54843: WORD PROBLEM:
How much water should be added to 8 ML of 6% Saline solution to reduce the concentration to 4%?
Please Help?
1 solutions
Answer 37037 by checkley71(8403) on 2006-10-05 17:07:58 (Show Source):
You can put this solution on YOUR website!8*.06=(8+X).04
.48=.32+.04X
.04X=.48-.32
.04X=.16
X=.16/.04
X=4 ADDITIONAL L OF WATER NEEDED TO CHANGE THE MIX FROM 6% TO 4%.
PROOF
8*.06=(8+4).04
.48=12*.04
.48=.48
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Linear-equations/54854: 1. Which of the ordered pairs
(3, 1), (0, –4), (–4, 0), (–3, –7)
are solutions for the equation x – y = 4?
A) (0, –4), (–4, 0), and (–3, –7)
B) (–4, 0) and (–3, –7)
C) (0, –4) and (–3, –7)
D) (3, 1) and (–4, 0)
No book. Thank you so much for your help!!!!
1 solutions
Answer 37032 by checkley71(8403) on 2006-10-05 16:48:47 (Show Source):
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Inverses/54770: why is algebra so hard
1 solutions
Answer 36994 by checkley71(8403) on 2006-10-05 11:26:34 (Show Source):
You can put this solution on YOUR website!TRUST ME IT ISN'T!!!!!!!!!!!!!!!!!
AN EXAMPLE THAT SAYS YOU'VE BEEN DOING ALGEBRA IN YOUR HEAD FOR YEARS BUT DON'T RECOGNIZE IT AS ALGEBRA.
EXAMPLE: YOU BUY A DOZEN (12) EGGS FOR $ 1.20. QUESTION (WITHOUT PENCIL & PAPER) TELL ME HOW MUCH EACH INDIVIDUAL EGG COSTS?
IF YOUR ANSWE IS $.10 OR 10 CENTS. YOU JUST SOLVED AN ALGEBRA PROBLEM EXPRESSED BY THE FORMULA
12E=1.20
DIVIDING BOTH SIDES BY 12 WE GET
12E/12=1.20/12
1E=.10 OR 1(EACH) EGG COSTS $.10
ALGEBRA IS NOT A MYSTERY BUT SIMPLY PUT A SET OF RULES, WHEN MASTERED OPENS UP A WHOLE NEW WORD OF KNOWLEDGE AND POTENTIAL BUSINESS OPPORTUNITIES.
TRY TO NAME A JOB THAT DOES NOT REQUIRESOME LEVEL OF MATHEMATICS.
CARPENTERS NEED TO KNOW FRACTIONS. CASHIERS NEED TO KNOW HOW TO MAKE CHANGE (REGISTERS HAVE BEEN KNOWN TO FAIL).
ALL BUSINESS PEOPLE NEED TO KNOW HOW TO MANAGE A LEDGER (INCOME, PAYMENTS, ASSETS, TAXES).
HOMEOWNERS NEED TO BALANCE A CHECK BOOK, RESOLVE CREDIT CARD BILLS, MKE MORTGAGE PAYMENTS, ETC.
'NUF SAID.
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Mixture_Word_Problems/54769: A 25% SOLUTION OF ALCOHOL IS TO BE MIXED WITH A 40% SOLUTION TO GET 50L OF A FINAL MIXTURE THAT IS 30% alcohol. How much of each of the original solution should be used?
1 solutions
Answer 36993 by checkley71(8403) on 2006-10-05 11:03:52 (Show Source):
You can put this solution on YOUR website!.25X+.40(50-X)=50*.30
.25X+20-.40X=15
-.15X=15-20
-.15X=-5
X=-5/-.15 [CORRECTION I USED .25 INSTEAD OF .15 - SORRY]
X=33.33 L OF 25% ALCOHOL &
50-33.33=16.67 L OF 40% ALCOHOL ARE USED TO CREATE A MIX OF 50 L WITH 30% ALCOHOL.
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Money_Word_Problems/54709: Adult tickets for a play cost $11 and child tickets cost $10. If there were 23 people at a performance and the theater collected $246 from ticket sales, how many children attended the play?
1 solutions
Answer 36991 by checkley71(8403) on 2006-10-05 10:56:29 (Show Source):
You can put this solution on YOUR website!A+C=23
11A+10C=246
A=23-C
11(23-C)+10C=246
253-11C+10C=246
-C=246-253
-C=-7
C=7
THEN A+7=23
A=23-7
A=16
PROOF
11*16+10*7=246
176+70=246
246=246
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Mixture_Word_Problems/54735: This question is from textbook technical mathematics
i need to see how you work this problem with all steps shown:
How many metric tons of chromium must be added to 2.50 metric tons of stainless steel to raise the percent chromium from 11% to 18%?
1 solutions
Answer 36989 by checkley71(8403) on 2006-10-05 10:46:07 (Show Source):
You can put this solution on YOUR website!(2.5+X).18=2.5*.11+X
.45+.18X=.275+X
.45-.275=-.18+X
.175=.82X
X=.175/.82
X=.2134 METRIC TONS OF CHROMIUM NEEDS TO BE ADDED TO 2.5 TONS OF 11% TO RAISE THE % OF CHROMIUM TO 18%
PROOF
(2.5+.2134).18=2.5*.11+.2134
2.7134*.18=.275+.2134
.488=.488 THE TOTAL AMOUNT OF CHROMIUM
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decimal-numbers/54732: 6780.50568 rounded to .01, .1, 1, 10, 100
1 solutions
Answer 36967 by checkley71(8403) on 2006-10-05 08:50:00 (Show Source):
You can put this solution on YOUR website!IF THE .01,.1,1,10,100 INDICATE THE POSITION TO BE ROUNDED THEN
6780.50568
R TO THE .O1 POSITION IS 6780.51
R TO THE .1 POSITION IS 6780.5
R TO THE 1 POSITION IS 6781.
R TO THE 10 POSITION IS 6780.
R TO THE 100 POSITION IS 6800.
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Square-cubic-other-roots/54744: I am stuck on correct answer for:
if the width of a rectangle is one-third of its length and its length is 12, what is the area of the rectangle?
I am not using any specific book. I am just practicing..
1 solutions
Answer 36963 by checkley71(8403) on 2006-10-05 08:35:11 (Show Source):
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Miscellaneous_Word_Problems/54702: I need to know how many cats and witches are out in this problem. I know that the number of legs was 3.5 times the number of heads and the total number of heads and legs are 72.
1 solutions
Answer 36933 by checkley71(8403) on 2006-10-04 20:08:45 (Show Source):
You can put this solution on YOUR website!WHERE DO YOU GET THAT LEGS IS 3.5 TIMES THE NUMBER OF HEADS.
I GET 2 HEADS WITH A TOTAL OF 6 LEGS WHICH IS 3 TO 1 NOT 3.5 TO 1.
72=X(3)+Y(5)
72=3X+5Y
THIS HAS A FEW SOLUTIONS
6 CATS 14 WITCHES 0R 6*5+14*3=72 OR 30+42=72 OR 72=72
9 CATS 9 WITCHES OR 9*5+9*3=72 OR 45=27=72 OR 72=72
12 CATS 4 WITCHERS OR 12*5+4*3=72 OR 60+12=72 OR 72=72
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Graphs/54682: Statistics. Sam must have an average of 70 or more in his summer course to
obtain a grade of C. His first three test grades were 75, 63, and 68. Write an inequality
representing the score that Sam must get on the last test to get a C grade.
1 solutions
Answer 36918 by checkley71(8403) on 2006-10-04 19:05:16 (Show Source):
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