New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'checkley71'
checkley71 answered: 8399 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399, >>Next
Equations/58025: 44. One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number.
A) 5
B) 7
C) 17
D) 34
I really appreciate your help!!!! 1 solutions
Answer 39672 by checkley71(8403) on 2006-10-25 09:02:24 (Show Source):
You can put this solution on YOUR website!THE NUMBERS ARE X & (X+12)
X+2(X+12)=39
X+2X+24=39
3X+24=39
3X=39-24
3X=15
X=15/3
X=5 THUS
X+12=5+12=17 C) 17 IS THE CORRECT ANSWER.
|
Equations/58016: 29. Which of the ordered pairs is a solution for the equation 2x – 5y = 10?
A) (0, 2)
B) (–5, 0)
C) (–5, –2)
D) (0, –2)
Thanks for your help!!! 1 solutions
Answer 39666 by checkley71(8403) on 2006-10-25 08:53:39 (Show Source):
You can put this solution on YOUR website!2X-5Y=10
2*0-5*2=10
0-10=10
-10=10 NOT A SOLUTION
2*-5-5*0=10
-10-0=10
-10=10 NOT A SOLUTION
2*-5-5*-2=10
-10+10=10
0=10 NOT A SOLUTION
2*0-5*-2=10
0+10=10
10=10 THIS IS A SOLUTION D)(0,-2)
|
Quadratic_Equations/57961: Table of values question. Please help me someone.
what are the table of values for
4=-x^2+6x-2? I have to come up with 5 values each acceptable for x and y.
Thanks in advance 1 solutions
Answer 39661 by checkley71(8403) on 2006-10-25 08:33:00 (Show Source):
|
Quadratic_Equations/58014: in which quadrant are the following points located? 3,-1
and can you explain so i can do the rest of them?
Thanks
Heather 1 solutions
Answer 39659 by checkley71(8403) on 2006-10-25 08:29:45 (Show Source):
You can put this solution on YOUR website!THERE ARE 4 QUADRANTS IN THE GRAPHING SYSTEM.
THE UPPER RIGHT (+,+), THE UPPER LEFT (-,+), THE LOWER RIGHT (+,-), & THE LOWER LEFT (-,-).
THUS THE POINTS (3,-1) IS IN THE LOWER RIGHT QUADRANT.
|
Geometry_Word_Problems/57941: This question is from textbook Elementary and Intermediate Algebra
To Whomever can assist, Thank You!
If the total surface area of a right circular cylinder is 104PIE square meters and a radius of the base is 4 meters long, find the height of the cylinder. 1 solutions
Answer 39630 by checkley71(8403) on 2006-10-24 21:57:33 (Show Source):
You can put this solution on YOUR website!CIRCUMFERANCE OF THE BASE=2PIR THUS
C=2PI4
C=2*PI*4
C=8PI
THE AREA OF THE TOP IS A=PIR^2
A=PI*4^2
A=PI*16 OR A=16PI AND THERE ARE 2 CIRCULAR AREAS (TOP & BOTTOM) THUS
2*PI*16=32PI
THE CYLINDER SIDE AREA IS 8P1*HEIGHT
THUS THE TOTAL SURFACE AREA BEING 104PI=32PI+8PI*H
104PI-32PI=8PI*H
72PI=8PI*H
H=72PI/8PI
H=9 METERS
|
Systems-of-equations/57932: This question is from textbook geometry reasoning
decide whether lines p1 and p2 are perpendicular:
line p1: x + 8y= -4
line p2: 4x - 2y = 10 1 solutions
Answer 39626 by checkley71(8403) on 2006-10-24 21:31:35 (Show Source):
You can put this solution on YOUR website!X+8Y=-4
8Y=-X-4
Y=-X/8-4 THIS LINE HAS A SLOPE OF -1/8
4X-2Y=10
-2Y=-4X+10
Y=2X-5 THIS LINE HAS A SLOPE OF 2
THE LINES ARE NOT PERPENDICULAR
TO BE PERPENDICULAR TO LINE 1 THE SLOPE HAS TO BE +8
TO BE PERPENDICULAR TO LINE 2 THE SLOPE HAS TO BE -1/2
|
Points-lines-and-rays/57856: This question is from textbook
For the points (0,3,) and 10,0) find
a. Distance between the two points
b. Midpoint of segment connecting points
c. Equation of line containing points
Determine if the following are functions
a. F= (1,2), (3,4), (1,6)
b. G= (-1,7). (4,3), (6,10, (2,3)
1 solutions
Answer 39586 by checkley71(8403) on 2006-10-24 17:43:39 (Show Source):
You can put this solution on YOUR website!(0,3)(10,0)
3^2+10^2=X^2
9+100=X^2
109=X^2
X=10.44 IS TH DISTANCE BETWEEN (0,2)(10,0)
MID POINT IS (10/0)/2=5 FOR THE X COORDINATE
(3/0)/2=1.5 FOR THE Y COORDINATE OR (5,1.5) IS THE MID POINT.
SLOPE=(0-3)/(10-0)=-3/10=-.3
Y=mX+b
3=-.3*0+b
3=b
THUS Y=-.3X+3
|
Linear_Equations_And_Systems_Word_Problems/57751: The charge for admission to the zoo is $3.25 for each adult and $1.50 for each child. On a day when 500 people paid to visit the zoo, the receipts totaled $1,275. Find the number of adult and children tickets purchased that day ?
what I have so far....
X= adult tickets purchased
y= child's tickets purchased
3.25x + 1.50y = 1275
x+y=500
I am not sure if this is correct. Please help!!!!!
Rodney 1 solutions
Answer 39433 by checkley71(8403) on 2006-10-23 20:40:16 (Show Source):
You can put this solution on YOUR website!3.25X+1.50Y=1275
X+Y=500 NOW SOLVE FOR X
X=500-Y NOW REPLACE X BY (500-Y) IN THE FIRST EQUATION
3.25(500-Y)+1.50Y=1275
1625-3.25Y+1.50Y=1275
-1.75Y=1275-1625
1.75Y=350
Y=350/1.75
Y=200 CHILDREN TICKETS
THUS X+200=500
X=500-200
X=300 ADULT TICKETS
PROOF
3.25*300+1.50*200=1275
975+300=1275
1275=1275
|
Linear-systems/57741: system of linear wquations. solve in substitution or addition method there is no book if possible express in ordered pair
3x-5y=1
10y=6x-1
thanks,
dnn 1 solutions
Answer 39431 by checkley71(8403) on 2006-10-23 20:32:33 (Show Source):
|
Inequalities/57540: Not sure if I have this in the right category. Thanks for your help.
P(4,0), Q(6,-8)
use point-slope form to write the equation of the line passing through the two given points. Write each equation in slope-intercept form. Thanks!
1 solutions
Answer 39404 by checkley71(8403) on 2006-10-23 17:34:26 (Show Source):
You can put this solution on YOUR website!Y=mX+b
m=(-8-0)/6-4)
m=-8/2
m=-4
Y=-4X+b
SUBSTITUTING ONE OF THE POINTS IN THIS EQUATION WE FIND THE INTERCEPT (b)
0=4*-4+b
0=-16+b
b=16
THUS THE EQUATION IS
Y=-4X-16
|
Linear-equations/57687: I am supposed to graph this and I have tried to research to understand, there are not any like this that I can find.
The line with a slope of 5 and a y intercept of 2, can you explain how to solve this please 1 solutions
Answer 39399 by checkley71(8403) on 2006-10-23 17:03:59 (Show Source):
You can put this solution on YOUR website!THE SLOPE/INTERCEPT FORMULA IS Y=mX+b
Y=5X+2
SETTING Y=0 WE GET
0=5X+2
5X=-2
X=-2/5
THUS TWO POINTS ON THIS LINE ARE
(0,2)(-2/5,0)
PLOT THESE TWO POINTS AND DRAW A LINE THROUGH THEM WITH A SLOPE OF 5
|
|