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checkley71 answered: 8399 problems
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X+2 length height x diagonal is sqrt 6 m
1 solutions
Answer 41115 by checkley71(8403) on 2006-11-05 17:34:47 (Show Source):
You can put this solution on YOUR website!6^2=X^2+(X+2)^2
36=X^2+X^2+4X+4
2X^2+4X+4-36=0
2X^2+4X-32=0
X^2+2X-16=0USING THE QUADRATIC EQUATION WE GET
X=(-B+-SQRT[B^2-4AC])/2A
X=(-2+-SQRT[4-4*1*-16)/2*1
X=(-2+-SQRT[4+64])/2
X=(-2+-SQRT68)/2
X=(-2+-8.246)/2
X=(-2+8.246)/2
X=6.246/2
X=3.123 SOLUTION
X=(-2-8.246)/2
X=-10.246/2
X=-5.123 SOLUTION
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Expressions-with-variables/59897: A garden supply store sells two types of lawn mowers. Total sales of mowers for the year were $8379.70. The total number of mowers sold was 30. The small mower cost $249.99. The large mower costs $329.99. Find the number sold of each type of mower. 1 solutions
Answer 41114 by checkley71(8403) on 2006-11-05 17:23:47 (Show Source):
You can put this solution on YOUR website!249.99S+329.99L=8379.70
S+L=30 THEN
S=30-L SO
249.99(30-L)+329.99L=8379.70
7499.7-249.99L+329.99L=8379.70
80L=8379.70-7499.70
80L=880
L=880/80
L=11 LARGE HAWN MOWERS SOLD THEN
30-11=19 SMALL MOWERS SOLD
PROOF
249.99*19+329.99*11=8379.70
4749.81+3629.89=8279.70
8379.70=8379.70
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Percentage-and-ratio-word-problems/59895: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color? 1 solutions
Answer 41113 by checkley71(8403) on 2006-11-05 17:14:41 (Show Source):
You can put this solution on YOUR website!TO GUARANTEE SHE GETS ONE OF EACH COLOR SHE HAS TO TAKE 4 FOR GREEN + 4 FOR BLUE & 1 MORE TO GUARANTEE SHE GETS A RED ONETHUS SHE HAS TO PICK 9.
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Miscellaneous_Word_Problems/59888: This question is from textbook Elementry and Intermediate algebra
Thomas is going to make an open-top box by cutting equal squares from the four corners of an 11 inch by 14 inch sheet of cardboard and folding up the sides. If the area of the base is to be 80 square inches, then what size square should be cut from each corner? 1 solutions
Answer 41112 by checkley71(8403) on 2006-11-05 16:54:42 (Show Source):
You can put this solution on YOUR website!THE BASE OF THIS 11 BY 14 IN PIECE OF CARDBOARD AFTER SQUARES ARE REMOVED FROM ALL FOUR CORNERS IS
(11-2X)(14-2X)=80
154-28X-22X+4X^2=80
4X^2-50X+154-80=0
4X^2-50X+74=0
2X^2-25X+37=0 USING THE QUADRATIC EQUATION TOSOLVE THIS EQUATION WE GET
X=(-B+-SQRT[B^2-4AC])/2A
X=(25+-SQRT[625-4*2*37])/2*2
X=(25+-SQRT[625-296])/4
X=(25+-SQRT329)/4
X=(25+-18.138)/4
X=(25+18.138)/4
X=43.138/4
X=10.78 SOLUTION
X=(25-18.138)/4
X=6.862/4
X=1.716 SOLUTION
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Radicals/59881: This question is from textbook College Algebra
Use square root procedure to solve the following quadratic equation. I was able to get down to the last part of problem but have been stumped since.
2x^2=48
1) 2x^2/2=48/2
2) x^2=24
3) x=+-sq root 24
4) ???? 1 solutions
Answer 41103 by checkley71(8403) on 2006-11-05 15:39:11 (Show Source):
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Equations/59858: Solve by any method
-4x + 3y = 2
5x - 2y = -3 1 solutions
Answer 41101 by checkley71(8403) on 2006-11-05 15:33:03 (Show Source):
You can put this solution on YOUR website!-4X+3Y=2 MULTIPLY THIS EQUATION BY 5 WE GET -20X+15Y=10
5X-2Y=-3 MULTIPLY THIS EQUATION BY 4 WE GET 20X-8Y=-12
NOW ADD THESE TWO EQUATIONS THUS
-20X+15Y=10
20X-8Y=-12
-------------------------------------
7Y=-2
Y=-2/7 THEN
-4X+3*-2/7=2
-4X-6/7=2
-4X=2+6/7
-4X=20/7
X=(20/7)/-4
X=(20/7)(-1/4)
X=-5/7
PROOF
5(-5/7)-2(-2/7)=-3
-25/7+4/7=-3
(-25+4)/7=-3
-21/7=-3
-3=-3
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Rational-functions/59842: AT THE NCNB SAVINGS BANK IT TAKES A COMPUTER 4 HOURS TO PROCESS AND PRINT PAYROLL CHECKS. WHEN A SECOND COMPUTER IS USED AND THE TWO COMPUTERS WORK TOGETHER, THE CHECKS CAN BE PROCESSED AND PRINTED IN 3 HOURS. HOW LONG WOULD IT TAKE THE SECOND COMPUTER BY ITSELF TO PROCESS AND PRINT THE PAYROLL CHECKS? 1 solutions
Answer 41100 by checkley71(8403) on 2006-11-05 15:22:30 (Show Source):
You can put this solution on YOUR website!(4*X)/(4+X)=3 THIS FORMULA IS THE PRODUCT DIVIDEDBY THE SUM OF THE TWO MACHINES EQUALS THE COMBINED TIME FOR BOTH MACHINES.
4X=3(4+X)
4X=12+3X
4X-3X=12
X=12HOURS FOR THE SECOND MACHING TO PROCESS THE CHECKS.
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Linear-equations/59869: This question is from textbook
Solve
33x – 6(4x – 0.305) = 8x + 0.105 1 solutions
Answer 41094 by checkley71(8403) on 2006-11-05 15:09:54 (Show Source):
You can put this solution on YOUR website!33X-6(4X-0.305)=8X+.105
33X-24X+1.83=8X+.105
9X-8X=.105-1.83
X=-1.725
PROOF
33*-1.725-6(4*-1.725-.305)=8*-1.725+.105
-56.925-6(-6.9-.305)=-13.8+.105
-56.925-6(-7.205)=-13.695
-56.925+43.23=-13.695
-13.625=-13.695
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Equations/59878: How to solve these problems? 4w-3w+2w=24
4(x+3)=20
-8+t/3=7
4y+3
____=9
7
1 solutions
Answer 41092 by checkley71(8403) on 2006-11-05 14:54:20 (Show Source):
You can put this solution on YOUR website!4W-3W+2W=24
3W=24
W=24/3
W=8 PROOF 4*8-3*8+2*8=24
32-24+16=24
48-24=24
24=24
----------------------------------------------------
4(X+3)=20
4X+12=20
4X=20-12
4X=8
X=8/4
X=2
-----------------------------------------------------
-8+T/3=7
T/3=7+8
T/3=15
T=15*3
T=45
-------------------------------------------------------
(4Y+3)/7=9
4Y+3=9*7
4Y+3=63
4Y=63-3
4Y=60
Y=60/4
Y=15
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Quadratic_Equations/59821: i can never figure out word problems can you please help. thank you in advance
108. Boxing match. A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring? 1 solutions
Answer 41069 by checkley71(8403) on 2006-11-05 10:37:24 (Show Source):
You can put this solution on YOUR website!THE DIAGONAL OF A SQUARE 20 FOOT RING IS SOLVED BY THE FORMULA A^2+B^2=C^2 WHERE THE A & B SIDES ARE 20 FEET. THUS THE DIAGONAL (C) IS
20^2+20^2=C^2
400+400=C^2
800=C^2
C=SQRT800
C=28.28 FEET IS THE DIAGONAL ACROSS THE RING
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Miscellaneous_Word_Problems/59822: can you please help me with this word problem. thank you very much
112. Swimming pool design. An architect has a designed a motel pool with in a rectangular area the is fenced on three sides. If she uses 60 yards of fencing to enclose as area of 352 square yards, then what are the dimensions for L and W? Assume L is greater than W 1 solutions
Answer 41067 by checkley71(8403) on 2006-11-05 10:24:01 (Show Source):
You can put this solution on YOUR website!L*W=352
2L+W=60
W=60-2L
L(60-2L)=352
60L-2L^2-352=0
-2L^2+60L-352=0
L^2-30L+176=0
(L-22)(L-8)=0
L-22=0
L=22 SOLUTION
L-8=0
L=8 SOLUTION
22*W=352
W=352/22
W=16 SOLUTION
PROOF
2*22+16=60
44+16=60
60=60
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Linear-equations/59711: a. Write in scientific notation:
(1) 5, 876, 000, 000
(2) 0.00203
b. Write without exponents:
(1) 7.5 x 105 (to the fifth)
(2) 7.8 x 10 -4 (to the negative 4th pwr) 1 solutions
Answer 41024 by checkley71(8403) on 2006-11-04 17:24:00 (Show Source):
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Money_Word_Problems/59758: PLEASE HELP ME WITH THIS. THE QUESTION IS "A PERSON HAS 20 COINS IN NICKELS AND DIMES WITH A COMBINED VALUE OF $1.60. DETERMINE THE NUMBER OF COINS AND WHAT TYPE." WHAT FORMULA DO I USE TO SOLVE? 1 solutions
Answer 41021 by checkley71(8403) on 2006-11-04 17:13:58 (Show Source):
You can put this solution on YOUR website!LET N= THE NUMBER OF NUICLES & D = THE NUMBER OF DIMES THEN
YOU NEED TWO FORMULAS AS YOU HAVE TWO UNKNOWNS.
N+D=20 OR N=20-D
SEEING AS A NICKEL IS WORTH 5 CENTS AND THE DIMES ARE WORTH 10 CENTS THEN
5N+10D=160
SUBSTITUTING (20-D)FOR N IN EQUATION #2 WE GET
5(20-D)+10D=160
100-5D+10D=160
5D=60
D=60/5
D=12 NUMBER OF DIMES THEN
N+12=20
N=20-12
N=8 NUMBER OF NICKELS
PROOF
5*8+12*10=160
40+120=160
160=160
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Expressions-with-variables/59719: This question is from textbook
The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. 1 solutions
Answer 41015 by checkley71(8403) on 2006-11-04 16:59:28 (Show Source):
You can put this solution on YOUR website!L=2W+2
2L+2W=52
2(2W+2)+2W=52
4W+4+2W=52
6W=52-4
6W=48
W=48/6
W=8 THE WIDTH IS 8 CM. THEN
L=2*8+2
L=16+2
L=18 THE LENGTH IS 18 CM.
PROOF
2*18+2*8=52
36+16=52
52=52
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testmodule/59729: how do u graph x+y=3
5x-2y=10
y=1/2x-3
y=x/4+1
x=2
y=-7/2 1 solutions
Answer 41010 by checkley71(8403) on 2006-11-04 16:40:55 (Show Source):
You can put this solution on YOUR website!I'LL HELP YOU WITH THE FIRST 3 THEN YOU'RE ON YOUR OWN.
X+Y=3
Y=-X+3 THIS LINE HAS A SLOPE (m) OF -1 & THE Y INTERCEPT IS 3.
SETTING Y=0 WE GET THE X INTERCEPT IN THE EQUATION Y=mX+b
0=-X+3
-X=-3
X=3 NOW WE HAVE 2 POINTS (0,3) & (-3,0) AND THE SLOPE OF -1.
PLOT THESE 2 POINTS (0,3)(-3,0)AND YOPU HAVE A LINE WITH A SLOPE OF -1.
-------------------------------------------------------------------------
5X-2Y=10
-2Y=-5X+10
Y=-5X/-2+10/-2
Y=2.5X-5 NOW WE HAVE SLOPE OF 2.5 AND THE Y INTERCEPT OF -5 (0,-5)
SETTING Y=0 WE SOLVE FOR THE X VALUE
0=2.5X-5
2.5X=5
X=5/2.5
X=2 OR THE POINT (2,0) ALONG WITH THE POINT(0,-5) & A SLOPE OF 2.5 WE PLOT THESE 2 POINTS & DRAW A LINE THROUGH THEM WITH A SLOPE OF 2.5.
-------------------------------------------------------------------------
Y=1/2X-3 THIS LINE HAS A SLOPE OF 1/5 OR 0.5 & A Y INTERCEPT OF -3 (0,-3)
NOW WE SET Y=O & SOLVE FOR X
0=1/2X-3
1/2X=3
X=3/(1/2)
X=3*2
X=6 NOW WE HAVE 2 POINTS (0,-3)(6,0) & A SLOPE OF 0.5.
PLOT THESE 2 POINTS (0,-3)(6,0) & DRAW LINE THROUGH THEM WITH A SLOPE OF 0.5.
-----------------------------------------------------------------------------
HAPPY CALCULATING :)
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Coordinate-system/59741: Can someone help me graph this problem?
In my class I have to graph this problem. I need to graph it on the computer and is as follows:
Graph the inequality
x <-2
I am really lost on this equation
Can someone help me graph this one?
Thanks,
Lyn 1 solutions
Answer 41004 by checkley71(8403) on 2006-11-04 16:13:39 (Show Source):
You can put this solution on YOUR website!ON YOUR GRAPH PAPER DRAW A VERTICLE LINE THROUGH THE POINT (-2,0)THAT IS
X=-2, Y=0
YOU ARE LOOKING FOR ALL VALUES LESS THAN <-2 SO YOU FILL-IN THE AREA TO THE LEFT OF THE X=-2 LINE WHICH COVERS ALL POINTS LESS THAN -2.
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Inequalities/59655: This question is from textbook Pre-Algebra
Please solve the equation. 6(5g+2)+30g.
Thanks for all your help! 1 solutions
Answer 40969 by checkley71(8403) on 2006-11-04 09:56:35 (Show Source):
You can put this solution on YOUR website!what you have given is not an equation.
for an equation you need an = sign.
should you have added =0 after the 30g?
if yes then
6(5g+2)+30g=0
30g+12+30g=0
60g+12=0
60g=-12
g=-12/60
g=-1/5 or -0.2
proof
6(5*-0.2+2)+30*-0.2=0
6(-1+2)-6=0
6*1-6=0
6-6=0
0=0
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