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# Recent problems solved by 'checkley71'

checkley71 answered: 8399 problems
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 Miscellaneous_Word_Problems/59844: 80. Diagonal brace. The width of the rectangular gate id 2 meters (m) longer than its heights. The diagonal brace measures sqrt 6 m. find the width and height. X+2 length height x diagonal is sqrt 6 m 1 solutions Answer 41115 by checkley71(8403)   on 2006-11-05 17:34:47 (Show Source): You can put this solution on YOUR website!6^2=X^2+(X+2)^2 36=X^2+X^2+4X+4 2X^2+4X+4-36=0 2X^2+4X-32=0 X^2+2X-16=0USING THE QUADRATIC EQUATION WE GET X=(-B+-SQRT[B^2-4AC])/2A X=(-2+-SQRT[4-4*1*-16)/2*1 X=(-2+-SQRT[4+64])/2 X=(-2+-SQRT68)/2 X=(-2+-8.246)/2 X=(-2+8.246)/2 X=6.246/2 X=3.123 SOLUTION X=(-2-8.246)/2 X=-10.246/2 X=-5.123 SOLUTION
 Expressions-with-variables/59897: A garden supply store sells two types of lawn mowers. Total sales of mowers for the year were \$8379.70. The total number of mowers sold was 30. The small mower cost \$249.99. The large mower costs \$329.99. Find the number sold of each type of mower.1 solutions Answer 41114 by checkley71(8403)   on 2006-11-05 17:23:47 (Show Source): You can put this solution on YOUR website!249.99S+329.99L=8379.70 S+L=30 THEN S=30-L SO 249.99(30-L)+329.99L=8379.70 7499.7-249.99L+329.99L=8379.70 80L=8379.70-7499.70 80L=880 L=880/80 L=11 LARGE HAWN MOWERS SOLD THEN 30-11=19 SMALL MOWERS SOLD PROOF 249.99*19+329.99*11=8379.70 4749.81+3629.89=8279.70 8379.70=8379.70
 Percentage-and-ratio-word-problems/59895: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color? 1 solutions Answer 41113 by checkley71(8403)   on 2006-11-05 17:14:41 (Show Source): You can put this solution on YOUR website!TO GUARANTEE SHE GETS ONE OF EACH COLOR SHE HAS TO TAKE 4 FOR GREEN + 4 FOR BLUE & 1 MORE TO GUARANTEE SHE GETS A RED ONETHUS SHE HAS TO PICK 9.
 Miscellaneous_Word_Problems/59888: This question is from textbook Elementry and Intermediate algebra Thomas is going to make an open-top box by cutting equal squares from the four corners of an 11 inch by 14 inch sheet of cardboard and folding up the sides. If the area of the base is to be 80 square inches, then what size square should be cut from each corner?1 solutions Answer 41112 by checkley71(8403)   on 2006-11-05 16:54:42 (Show Source): You can put this solution on YOUR website!THE BASE OF THIS 11 BY 14 IN PIECE OF CARDBOARD AFTER SQUARES ARE REMOVED FROM ALL FOUR CORNERS IS (11-2X)(14-2X)=80 154-28X-22X+4X^2=80 4X^2-50X+154-80=0 4X^2-50X+74=0 2X^2-25X+37=0 USING THE QUADRATIC EQUATION TOSOLVE THIS EQUATION WE GET X=(-B+-SQRT[B^2-4AC])/2A X=(25+-SQRT[625-4*2*37])/2*2 X=(25+-SQRT[625-296])/4 X=(25+-SQRT329)/4 X=(25+-18.138)/4 X=(25+18.138)/4 X=43.138/4 X=10.78 SOLUTION X=(25-18.138)/4 X=6.862/4 X=1.716 SOLUTION
 Inverses/59893: 3x-(7x-5)=151 solutions Answer 41111 by checkley71(8403)   on 2006-11-05 16:38:59 (Show Source): You can put this solution on YOUR website!3X-(7X-5)=15 3X-7X+5=15 -4X=15-5 -4X=10 X=10/-4 X=-2.5 PROOF 3*-2.5-(7*-2.5-5)=15 -7.5-(-17.5-5)=15 -7.5-(-22.5)=15 -7.5+22.5=15 15=15
 Linear_Algebra/59883: Please help w/ the following: Solve: 4x^2+x=3 Thank you.1 solutions Answer 41109 by checkley71(8403)   on 2006-11-05 16:06:53 (Show Source): You can put this solution on YOUR website!4X^2+X=3 4X^2+X-3=0 (4X-3)(X+1)=0 4X-3=0 4X=3 X=3/4 SOLUTION X+1=0 X=-1 SOLUTION
 Length-and-distance/59831: how do u graph y=x/4+1 x=2 y=-7/2 what coordinates do u use 2 gragh it1 solutions Answer 41108 by checkley71(8403)   on 2006-11-05 16:03:08 (Show Source): You can put this solution on YOUR website!Y=X/4+1 THIS EQUATION IS FOR A LINE WITH A SLOPE OF 1/4 & A Y INTERCEPT OF 1 IF X=2 THEN Y=2/4+1 Y=1.5 IF Y=-7/2 THEN -7/2=X/4+1 X/4=-7/2-1 X/4=-9/2 2X=-36 X=-36/2 X=-18 SO TWO POINTS ARE (2,1.5)(-18,-7/2)
 Rational-functions/59848: Solve the following system. Find the sum of the x and y solutions. x - y = 7 4x - 5y = 25 a) 15 b) 13 c) 11 d) 9 e) none of the above1 solutions Answer 41104 by checkley71(8403)   on 2006-11-05 15:44:50 (Show Source): You can put this solution on YOUR website!X-Y=7 OR X=7+Y 4X-5Y=25 SO 4(7+Y)-5Y=25 28+4Y-5Y=25 -Y=-3 Y=3 THEN X-3=7 X=7+3 X=10 PROOF 4*10-5*-3=25 40-15=25 25=25
 Radicals/59881: This question is from textbook College Algebra Use square root procedure to solve the following quadratic equation. I was able to get down to the last part of problem but have been stumped since. 2x^2=48 1) 2x^2/2=48/2 2) x^2=24 3) x=+-sq root 24 4) ????1 solutions Answer 41103 by checkley71(8403)   on 2006-11-05 15:39:11 (Show Source): You can put this solution on YOUR website!2X^2=48 X^2=48/2 X^2=24 X=+-SQRT24 X=+-2SQRT6 OR X=+-2*2.4494897 OR X=+-4.8989794
 Equations/59858: Solve by any method -4x + 3y = 2 5x - 2y = -31 solutions Answer 41101 by checkley71(8403)   on 2006-11-05 15:33:03 (Show Source): You can put this solution on YOUR website!-4X+3Y=2 MULTIPLY THIS EQUATION BY 5 WE GET -20X+15Y=10 5X-2Y=-3 MULTIPLY THIS EQUATION BY 4 WE GET 20X-8Y=-12 NOW ADD THESE TWO EQUATIONS THUS -20X+15Y=10 20X-8Y=-12 ------------------------------------- 7Y=-2 Y=-2/7 THEN -4X+3*-2/7=2 -4X-6/7=2 -4X=2+6/7 -4X=20/7 X=(20/7)/-4 X=(20/7)(-1/4) X=-5/7 PROOF 5(-5/7)-2(-2/7)=-3 -25/7+4/7=-3 (-25+4)/7=-3 -21/7=-3 -3=-3
 Rational-functions/59842: AT THE NCNB SAVINGS BANK IT TAKES A COMPUTER 4 HOURS TO PROCESS AND PRINT PAYROLL CHECKS. WHEN A SECOND COMPUTER IS USED AND THE TWO COMPUTERS WORK TOGETHER, THE CHECKS CAN BE PROCESSED AND PRINTED IN 3 HOURS. HOW LONG WOULD IT TAKE THE SECOND COMPUTER BY ITSELF TO PROCESS AND PRINT THE PAYROLL CHECKS?1 solutions Answer 41100 by checkley71(8403)   on 2006-11-05 15:22:30 (Show Source): You can put this solution on YOUR website!(4*X)/(4+X)=3 THIS FORMULA IS THE PRODUCT DIVIDEDBY THE SUM OF THE TWO MACHINES EQUALS THE COMBINED TIME FOR BOTH MACHINES. 4X=3(4+X) 4X=12+3X 4X-3X=12 X=12HOURS FOR THE SECOND MACHING TO PROCESS THE CHECKS.
 Linear-equations/59869: This question is from textbook Solve 33x – 6(4x – 0.305) = 8x + 0.1051 solutions Answer 41094 by checkley71(8403)   on 2006-11-05 15:09:54 (Show Source): You can put this solution on YOUR website!33X-6(4X-0.305)=8X+.105 33X-24X+1.83=8X+.105 9X-8X=.105-1.83 X=-1.725 PROOF 33*-1.725-6(4*-1.725-.305)=8*-1.725+.105 -56.925-6(-6.9-.305)=-13.8+.105 -56.925-6(-7.205)=-13.695 -56.925+43.23=-13.695 -13.625=-13.695
 Equations/59878: How to solve these problems? 4w-3w+2w=24 4(x+3)=20 -8+t/3=7 4y+3 ____=9 7 1 solutions Answer 41092 by checkley71(8403)   on 2006-11-05 14:54:20 (Show Source): You can put this solution on YOUR website!4W-3W+2W=24 3W=24 W=24/3 W=8 PROOF 4*8-3*8+2*8=24 32-24+16=24 48-24=24 24=24 ---------------------------------------------------- 4(X+3)=20 4X+12=20 4X=20-12 4X=8 X=8/4 X=2 ----------------------------------------------------- -8+T/3=7 T/3=7+8 T/3=15 T=15*3 T=45 ------------------------------------------------------- (4Y+3)/7=9 4Y+3=9*7 4Y+3=63 4Y=63-3 4Y=60 Y=60/4 Y=15
 Numbers_Word_Problems/59873: The sum of two munbers is 21. Three times the smaller number is two less than twice the larger number. Find the two numbers.1 solutions Answer 41091 by checkley71(8403)   on 2006-11-05 14:46:58 (Show Source): You can put this solution on YOUR website!X+Y=21 SO X=21-Y AND 3X=2Y-2 3(21-Y)=2Y-2 63-3Y=2Y-2 -3Y-2Y=-2-63 -5Y=-65 Y=-65/-5 Y=13 THEN X+13=21 X=21-13 X=8 PROOF 3*8=2*13-2 24=26-2 24=24
 Signed-numbers/59874: -4-(-3)(-2)1 solutions Answer 41089 by checkley71(8403)   on 2006-11-05 14:37:19 (Show Source): You can put this solution on YOUR website!-4-(-3)(-2) -4-(6) -4-6=-10
 Quadratic_Equations/59821: i can never figure out word problems can you please help. thank you in advance 108. Boxing match. A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring?1 solutions Answer 41069 by checkley71(8403)   on 2006-11-05 10:37:24 (Show Source): You can put this solution on YOUR website!THE DIAGONAL OF A SQUARE 20 FOOT RING IS SOLVED BY THE FORMULA A^2+B^2=C^2 WHERE THE A & B SIDES ARE 20 FEET. THUS THE DIAGONAL (C) IS 20^2+20^2=C^2 400+400=C^2 800=C^2 C=SQRT800 C=28.28 FEET IS THE DIAGONAL ACROSS THE RING
 Systems-of-equations/59825: What is the equation of a line graphed through (-2,0)(0,-2)1 solutions Answer 41068 by checkley71(8403)   on 2006-11-05 10:30:58 (Show Source): You can put this solution on YOUR website!(-2-0)/(0-2) -2/2=-1 Y=-X+b SUBSTITUTING ONE SET OFPOINTS WE FIND THE Y INTERCEPT 0=-1*-2+b 0=2+b b=-2THUS THE EQUATION IS Y=-X-2
 Miscellaneous_Word_Problems/59822: can you please help me with this word problem. thank you very much 112. Swimming pool design. An architect has a designed a motel pool with in a rectangular area the is fenced on three sides. If she uses 60 yards of fencing to enclose as area of 352 square yards, then what are the dimensions for L and W? Assume L is greater than W1 solutions Answer 41067 by checkley71(8403)   on 2006-11-05 10:24:01 (Show Source): You can put this solution on YOUR website!L*W=352 2L+W=60 W=60-2L L(60-2L)=352 60L-2L^2-352=0 -2L^2+60L-352=0 L^2-30L+176=0 (L-22)(L-8)=0 L-22=0 L=22 SOLUTION L-8=0 L=8 SOLUTION 22*W=352 W=352/22 W=16 SOLUTION PROOF 2*22+16=60 44+16=60 60=60
 Inequalities/59776: This question is from textbook Pre-Algebra Solve the equation. 6x-21=33+9x. Thanks for all the help!1 solutions Answer 41046 by checkley71(8403)   on 2006-11-04 21:42:34 (Show Source): You can put this solution on YOUR website!6x-21=33+9x 6x-9x=33+21 -3x=54 x=54/-3 x=-18 proof 6*-18-21=33+9*-18 -108-21=33-162 -129=129
 Linear-equations/59711: a. Write in scientific notation: (1) 5, 876, 000, 000 (2) 0.00203 b. Write without exponents: (1) 7.5 x 105 (to the fifth) (2) 7.8 x 10 -4 (to the negative 4th pwr)1 solutions Answer 41024 by checkley71(8403)   on 2006-11-04 17:24:00 (Show Source): You can put this solution on YOUR website!5,876,000,000=5.876*10^8 0.00203=2.03*10(^-3) 7.5*105^5=910,529,667.5 7.8*10(^-4)=7.8*.0001=.00078
 Money_Word_Problems/59758: PLEASE HELP ME WITH THIS. THE QUESTION IS "A PERSON HAS 20 COINS IN NICKELS AND DIMES WITH A COMBINED VALUE OF \$1.60. DETERMINE THE NUMBER OF COINS AND WHAT TYPE." WHAT FORMULA DO I USE TO SOLVE?1 solutions Answer 41021 by checkley71(8403)   on 2006-11-04 17:13:58 (Show Source): You can put this solution on YOUR website!LET N= THE NUMBER OF NUICLES & D = THE NUMBER OF DIMES THEN YOU NEED TWO FORMULAS AS YOU HAVE TWO UNKNOWNS. N+D=20 OR N=20-D SEEING AS A NICKEL IS WORTH 5 CENTS AND THE DIMES ARE WORTH 10 CENTS THEN 5N+10D=160 SUBSTITUTING (20-D)FOR N IN EQUATION #2 WE GET 5(20-D)+10D=160 100-5D+10D=160 5D=60 D=60/5 D=12 NUMBER OF DIMES THEN N+12=20 N=20-12 N=8 NUMBER OF NICKELS PROOF 5*8+12*10=160 40+120=160 160=160
 Expressions-with-variables/59718: This question is from textbook Identify the rate in the statement " 72 is 24% of 300."1 solutions Answer 41019 by checkley71(8403)   on 2006-11-04 17:07:36 (Show Source): You can put this solution on YOUR website!24% OF 300=72 .24*300=72 72=72 OR 72/300=.24 .24=.24 OR 24%
 Expressions-with-variables/59716: This question is from textbook Solve. –4(2x + 1) + 2(4x – 3) = x – 101 solutions Answer 41018 by checkley71(8403)   on 2006-11-04 17:04:37 (Show Source): You can put this solution on YOUR website!-4(2X+1)+2(4X-3)=X-10 -8X-4+8X-6=X-10 -8X+8X-X=-10+4+6 -X=0 X=0 PROOF -4(2*0+1)+2(4*0-3)=0-10 -4(1)+2(-3)=-10 -4-6=-10 -10=-10
 Expressions-with-variables/59719: This question is from textbook The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.1 solutions Answer 41015 by checkley71(8403)   on 2006-11-04 16:59:28 (Show Source): You can put this solution on YOUR website!L=2W+2 2L+2W=52 2(2W+2)+2W=52 4W+4+2W=52 6W=52-4 6W=48 W=48/6 W=8 THE WIDTH IS 8 CM. THEN L=2*8+2 L=16+2 L=18 THE LENGTH IS 18 CM. PROOF 2*18+2*8=52 36+16=52 52=52
 Complex_Numbers/59757: Simplify the Complex Fraction. x - 8 _______ 5 ___ x+6 1 solutions Answer 41014 by checkley71(8403)   on 2006-11-04 16:53:46 (Show Source): You can put this solution on YOUR website!(X/8)/(5/(X+6) (X/8)(X+6)/5 (X^2+6X)/40
 Polynomials-and-rational-expressions/59754: solve: (x+2)/(x-3)=(x-5)/(x+3)1 solutions Answer 41012 by checkley71(8403)   on 2006-11-04 16:50:38 (Show Source): You can put this solution on YOUR website!(X+2)/(X-3)=(X-5)/X+3) (X-3)(X-5)=(X+2)(X+3) X^2-8X+15=X^2+5X+6 X^2-X^2-8X-5X=6-15 -13X=-9 X=9/13 PROOF (9/13+2)/(9/13-3)=(9/13-5)/(9/13+3) (35/13)/(-30/13)=(-56/13)/(48/13) (-30/13)(-56/13)=(35/13)(48/13) 1680/13=1680/13
 testmodule/59729: how do u graph x+y=3 5x-2y=10 y=1/2x-3 y=x/4+1 x=2 y=-7/21 solutions Answer 41010 by checkley71(8403)   on 2006-11-04 16:40:55 (Show Source): You can put this solution on YOUR website!I'LL HELP YOU WITH THE FIRST 3 THEN YOU'RE ON YOUR OWN. X+Y=3 Y=-X+3 THIS LINE HAS A SLOPE (m) OF -1 & THE Y INTERCEPT IS 3. SETTING Y=0 WE GET THE X INTERCEPT IN THE EQUATION Y=mX+b 0=-X+3 -X=-3 X=3 NOW WE HAVE 2 POINTS (0,3) & (-3,0) AND THE SLOPE OF -1. PLOT THESE 2 POINTS (0,3)(-3,0)AND YOPU HAVE A LINE WITH A SLOPE OF -1. ------------------------------------------------------------------------- 5X-2Y=10 -2Y=-5X+10 Y=-5X/-2+10/-2 Y=2.5X-5 NOW WE HAVE SLOPE OF 2.5 AND THE Y INTERCEPT OF -5 (0,-5) SETTING Y=0 WE SOLVE FOR THE X VALUE 0=2.5X-5 2.5X=5 X=5/2.5 X=2 OR THE POINT (2,0) ALONG WITH THE POINT(0,-5) & A SLOPE OF 2.5 WE PLOT THESE 2 POINTS & DRAW A LINE THROUGH THEM WITH A SLOPE OF 2.5. ------------------------------------------------------------------------- Y=1/2X-3 THIS LINE HAS A SLOPE OF 1/5 OR 0.5 & A Y INTERCEPT OF -3 (0,-3) NOW WE SET Y=O & SOLVE FOR X 0=1/2X-3 1/2X=3 X=3/(1/2) X=3*2 X=6 NOW WE HAVE 2 POINTS (0,-3)(6,0) & A SLOPE OF 0.5. PLOT THESE 2 POINTS (0,-3)(6,0) & DRAW LINE THROUGH THEM WITH A SLOPE OF 0.5. ----------------------------------------------------------------------------- HAPPY CALCULATING :)
 Length-and-distance/59733: which equation of the line has a slope of 5 and passes through point (2,1)?1 solutions Answer 41008 by checkley71(8403)   on 2006-11-04 16:21:27 (Show Source): You can put this solution on YOUR website!Y=mX+b m=5 THE SLOPE Y=5X+b NOW SUBSTITUTE THE GIVEN POINTS FOR Y & X WE GET 1=5*2+b b=1-10 b=-9 THEN THE EQUATION FOR THIS LINE IS Y=5X-9
 Systems-of-equations/59734: Simplify (3x^3y)^21 solutions Answer 41006 by checkley71(8403)   on 2006-11-04 16:18:32 (Show Source): You can put this solution on YOUR website!(3X^3Y)^2 9X^6Y^2
 Coordinate-system/59741: Can someone help me graph this problem? In my class I have to graph this problem. I need to graph it on the computer and is as follows: Graph the inequality x <-2 I am really lost on this equation Can someone help me graph this one? Thanks, Lyn1 solutions Answer 41004 by checkley71(8403)   on 2006-11-04 16:13:39 (Show Source): You can put this solution on YOUR website!ON YOUR GRAPH PAPER DRAW A VERTICLE LINE THROUGH THE POINT (-2,0)THAT IS X=-2, Y=0 YOU ARE LOOKING FOR ALL VALUES LESS THAN <-2 SO YOU FILL-IN THE AREA TO THE LEFT OF THE X=-2 LINE WHICH COVERS ALL POINTS LESS THAN -2.
 Inequalities/59655: This question is from textbook Pre-Algebra Please solve the equation. 6(5g+2)+30g. Thanks for all your help!1 solutions Answer 40969 by checkley71(8403)   on 2006-11-04 09:56:35 (Show Source): You can put this solution on YOUR website!what you have given is not an equation. for an equation you need an = sign. should you have added =0 after the 30g? if yes then 6(5g+2)+30g=0 30g+12+30g=0 60g+12=0 60g=-12 g=-12/60 g=-1/5 or -0.2 proof 6(5*-0.2+2)+30*-0.2=0 6(-1+2)-6=0 6*1-6=0 6-6=0 0=0