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Polynomials-and-rational-expressions/60661: How do I reduce the following fraction to its lowest terms?
6u^2-60u+144/u^2-5u+4 1 solutions
Answer 41645 by checkley71(8403) on 2006-11-09 16:29:43 (Show Source):
You can put this solution on YOUR website!(6u^2-60u+144)/(u^2-5u+4) now factor both equations
6u^2-60u+144
6(u^2-10u+24)
6(u-6)(u-4) now factor the denominator
u^2-5u+4
(u-4)(u-1) now reconstruct the fraction thus
6(u-6)(u-4)/(u-4)(u-1) we have a common factor in both the numerator & denominator and can be factored out of both thus
6(u-6)/(u-1)
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Numbers_Word_Problems/60675: I am having trouble converting this to an equation. I know the answer but can't come up with the equation that will give me the correct answer.
There is a group of boys and dogs. There are 22 heads and 68 feet. How many boys are there and how many dogs are there.
The answer is 10 boys and 12 dogs,but I need an equation.
Thank You 1 solutions
Answer 41637 by checkley71(8403) on 2006-11-09 16:06:40 (Show Source):
You can put this solution on YOUR website!HEADS=B+D
22=B+D
B=22-D
FEET=2B+4D
68=2B+4D SUBSTITUTE (22-D) FOR B IN THE FEET EQUATION WE GET
68=2(22-D)+4D
68=44-2D+4D
68-44=2D
24=2D
D=24/2
D=12 ANSWER
22=B+12
B=22-12
B=10 ANSWER
PROOF
68=2*10+4*12
68=20+48
68=68
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Geometry_Word_Problems/60673: The floor of a shed has an area of 54 square feet. Find the length and width if the length is 3 feet less than twice its width. 1 solutions
Answer 41633 by checkley71(8403) on 2006-11-09 15:48:58 (Show Source):
You can put this solution on YOUR website!AREA=LENGTH*WIDTH
54=(2W-3)W
54=2W^2-3W
2W^2-3W-54=0
(2W+9)(W-6)=0
2W+9=0
2W=-9
W=9/-2
W=-4.5 NON SOLUTION
W-6=0
W=6 SOLUTION
L=2*6-3
L=12-3
L=9 SOLUTION
PROOF
54=6*9
54=54
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Rectangles/60671: This question is from textbook Essential Algebra
Hi, I am a distance education student and new to geometry. I do not get it. Every other math sight I have found only tell you the answer but not how they got it. Thanks, Lee Ann
Problem: The Width of a rectangle is three feet less than its length. Find the length of the rectangle if its perimeter is 78 feet. 1 solutions
Answer 41632 by checkley71(8403) on 2006-11-09 15:41:28 (Show Source):
You can put this solution on YOUR website!PERIMETER=2*LENGTH+2WIDTH
78=2*L+2(L-3)
78=2L+2L-6
78=4L-6
4L=78+6
4L=84
L=84/4
L=21 THEN THE WIDTH=21-3=18
PROOF
78=2*21+2*18
78=42+36
78=78
SUGGESTION: WHEN YOU WORK WORD PROBLEMS, IF POSSIBLE, DRAW A PICTURE, SKETCH OR DIAGRAM AND LABEL ALL RELEVENT FACTS, MEASUREMENTS, ANGLES, ETC.
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Expressions-with-variables/60385: my question is about word problems:
Vince is a professional football player. He has already made 75 touchdowns. each year, he makes 5 more touchdowns. Write a equation to show how many touchdowns he has made after x years
p.s
please help me as soon as possible!
thank you! 1 solutions
Answer 41467 by checkley71(8403) on 2006-11-07 21:30:21 (Show Source):
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Equations/60364: ok i no how to do algibra BUT!
i dont no when to add or subtract the varibles!
example 3x+6=8x-9 so..... do i add or subtract the 3x and 8x
please help me!!!!
from
hockey girl 1 solutions
Answer 41465 by checkley71(8403) on 2006-11-07 21:20:57 (Show Source):
You can put this solution on YOUR website!3X+6=8X-9 CONSIDER A VARIABLE A BANANA OR ANY OTHER OBJECT
8X-3X=6+9 YOU NOW HAVE 8(BANANAS) AND YOU SUBTRACT (TAKE AWAY) 3 BANANAS WHICH LEAVES YOU WITH 5 BANANAS OR 8X-3X=5X CONTINUING BY ADDING THE 6+9=15 WE GET
5X=15
NOW DIVIDE BOTH SIDESBY 5 AND YOU GET
5X/5=15/5 OR
X=3
PROOF
3*3+6=8*3-9
9+6=24-9
15=15
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Linear-systems/60370: Geometry.
The length of a rectangle is 2 in. more than twice its width. If the
perimeter of the rectangle is 34 in., find the dimensions of the rectangle. 1 solutions
Answer 41464 by checkley71(8403) on 2006-11-07 21:14:20 (Show Source):
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Equations/60377: I'm having difficulty with this problem.
-6(5X+2)=198 I was wondering if you could solve this for me and show your work so that I can learn how to do it. I am working with my 8th grade daughter and I wish I could show her how to do this. Maybe if I see how it is done I will be able to explain it to her. I've been working on this with her for an hour. Please Help! Thanks!
Karen 1 solutions
Answer 41460 by checkley71(8403) on 2006-11-07 20:59:06 (Show Source):
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