# See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

# Recent problems solved by 'checkley71'

checkley71 answered: 8399 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399, >>Next

 Equations/61214: Can someone help me with this problem? Find the x- and y- intercepts and graph the equation. y=2x+61 solutions Answer 42159 by checkley71(8403)   on 2006-11-13 22:29:00 (Show Source): You can put this solution on YOUR website!THE Y INTERCEPT IS=6 (0,6) TO FIND THE X INTERCEPT YOU SET Y=O AND SOLVE THE EQUATION 0=2X+6 2X=-6 X=-6/2 X=-3 (-3,0) IS THE X INTERCEPT
 expressions/61197: 4+2m-m 1 solutions Answer 42157 by checkley71(8403)   on 2006-11-13 22:26:12 (Show Source): You can put this solution on YOUR website!4+2M-M=4+M
 Equations/61216: Could ssomeone please explain how to work this problem? Find the slope and y intercept by writing the equation in slope intercept form then graph the equation. 3x+y=-21 solutions Answer 42156 by checkley71(8403)   on 2006-11-13 22:24:24 (Show Source): You can put this solution on YOUR website!3X+Y=-2 Y=-3X-2 THIS IS A LINE WITH A SLOPE OF -3 & A Y INTERCEPT OF (0,-2) SETTING Y=0 WE CAN THEN FIND THE X INTERCEPT FOR A SECOND POINT TO PLOT THE LINE 0=-3X-2 -3X=2 X=2/-3 X=-2/3 OR (-2/3,0) IS A SECOND POINT ON THE LINE.
 Equations/61219: Could someone help me answer this problem? Find the slope of the line that passes through the points (-3,5) and (0,-2) Thanks to all!1 solutions Answer 42155 by checkley71(8403)   on 2006-11-13 22:20:39 (Show Source): You can put this solution on YOUR website!SLOPE=(Y2-Y1)/(X2-X1) SLOPE=(-2-5)/(0+3) SLOPE=-7/3
 Geometric_formulas/61237: What is the distance formula, please?1 solutions Answer 42154 by checkley71(8403)   on 2006-11-13 22:17:57 (Show Source): You can put this solution on YOUR website!DISTANCE(MILES)=RATE(MPH)*TIME(HOURS) EXAMPLE YOU TRAVEL @ 50 MPH FOR 6 HOURS THEN THE DISTANCE TRAVELED IS D=50*6=300 MILES
 Travel_Word_Problems/61278: A northbound train left at noon. Two hours later, a southbound train left the same station. At 6:00 p.m., the two trains were 490 miles apart. Find the rate of each train if the northbound train traveled 15 miles per hour faster than the southbound train.1 solutions Answer 42153 by checkley71(8403)   on 2006-11-13 22:14:45 (Show Source): You can put this solution on YOUR website!490=(R-15)*6+R*4 490=6R-90+4R 490=10R-90 10R=490+90 10R=580 R=580/10 R=58 MPH FOR 4 HOURS FOR THE SOUTH BOUND TRAIN THUS THE NORTH BOUND TRAIN WAS TRAVELING 58-15=43 MPH FOR 6 HOURS PROOF 490=43*6+58*4 490=258+232 490=490
 Numeric_Fractions/61246: add 5+1/2=1 solutions Answer 42152 by checkley71(8403)   on 2006-11-13 22:08:54 (Show Source): You can put this solution on YOUR website!5+1/2=5+.5=5.5 OR 5+1/2=10/2+1/2=11/2=5 1/2=5.5
 Equations/61273: 4.2 # 8- The sum of three consecutive odd integers is 81. Find the integers.1 solutions Answer 42151 by checkley71(8403)   on 2006-11-13 22:02:36 (Show Source): You can put this solution on YOUR website!X+(X+2)+(X+4)=81 3X+6=81 3X=81-6 3X=75 X=75/3 X=25 FIRST ODD NUMBER X+2=25=2=27 SECOND ODD NUMBER X+4=25=4=29 LAST ODD NUMBER PROOF 25+27+29=81 81=81
 Expressions-with-variables/61276: -y+5(y+6)=541 solutions Answer 42149 by checkley71(8403)   on 2006-11-13 21:59:38 (Show Source): You can put this solution on YOUR website!-Y+5(Y+6)=54 -Y+5Y+30=54 4Y=54-30 4Y=24 Y=24/4 Y=6 PROOF -6+5(6+6)=54 -6+5*12=54 -6+60=54 54=54
 Travel_Word_Problems/61272: At noon a horse and buggyheaded north traveling 10 miles per hour. Two hours later, a roadster headed south from the same location driving 50 miles per hour. At which time will the horse and buggy be 140 miles from the roadster?1 solutions Answer 42148 by checkley71(8403)   on 2006-11-13 21:52:48 (Show Source): You can put this solution on YOUR website!140=10T+50(T-2) 140=10T+50T-100 60T=140+100 60T=240 T=240/60 T=4 HOURS PROOF 140=10*4+50(4-2) 140=40+50*2 140=40+100 140=140
 Miscellaneous_Word_Problems/61271: This question is from textbook Area of a window. A window is in the shape of a square of side s, with a semicircle of a diameter s above it. Write a function that expresses the total area of a window s a function of s. Gracias1 solutions Answer 42146 by checkley71(8403)   on 2006-11-13 21:49:43 (Show Source): You can put this solution on YOUR website!AREA OF THE WINDOW IS S^2 THE AREA OF THE SEMI CIRCLE ABOVE IT HAS AN AREA OF PI*R^2/2 WHERE THE R=S/2 THUS WE HAVE S^2+(PI*S/2)/2 FOR THE ENTIRE AREA
 Volume/61254: Please help! Question: Lauren wants to buy an aquarium that has a volume of 18 cubic units. how many different aquariums with the same volume could she buy? write the measurements for each one.1 solutions Answer 42145 by checkley71(8403)   on 2006-11-13 21:44:50 (Show Source): You can put this solution on YOUR website!THE NUMBER OF DIFFERENT AQUARIUMS WITH A VOLUME OF 18 CUBIC UNITS IS INFINITE (WITHOUT NUMBER). DON'T THINK YOU WANT THEM ALL!!!!!!
 Linear-equations/61257: Help which graph best represents the equation y=3x+7?1 solutions Answer 42144 by checkley71(8403)   on 2006-11-13 21:40:39 (Show Source): You can put this solution on YOUR website!A LINE THAT PASSES THROUGH THE POINT(0,7) WITH A SLOPE OF 3 REPRESENTS THIS LINE. SETTING Y=0 WE CAN FIND ANOTHER POINT ON THE X AXIS THUS 0=3X+7 3X=7 X=7/3 THUS A SECOND POINT IS(7/3,0)
 Numbers_Word_Problems/61168: the sum of two integers, a and b (a>b). the smaller minus the larger is -746. find the value of the integers a and b.1 solutions Answer 42130 by checkley71(8403)   on 2006-11-13 18:12:37 (Show Source): You can put this solution on YOUR website!IF YOU'VE DEFINED THE PROBLEM CORRECTLY. THERE ARE MANY SOLUTIONS THUS: A>B THEN B IS THE SMALLER NUMBER & B-A=-746 THEN IF B=1 THEN 1-A=-746 -A=-746-1 A=747 SETTING B=242 WE GET 242-A=-746 -A=-746-242 A=988
 Graphs/61185: please show me how to get this equation. write the equation of the line which passes through the point(2,1) and is parallelto the line with equation y=5/2x+6 Thank you.1 solutions Answer 42128 by checkley71(8403)   on 2006-11-13 18:04:15 (Show Source): You can put this solution on YOUR website!Y=5/2X+6 HAS A SLOPE OF 5/2 AND PASSES THROUGH POINTS(2,1) THEN 1=5/2*2+b 1=5+b B=1-5 b=-4 THUS THE EQUATION FOR THIS LINE IS Y=5/2X-4
 Equations/61221: Could someone please explain how to work out this problem? Write the equation of the line with slope -2 and passes through the point (-1,5) Then write the equation in standard form. Thanks1 solutions Answer 42127 by checkley71(8403)   on 2006-11-13 17:58:28 (Show Source): You can put this solution on YOUR website!Y=mX+b 5=(-2*-1)+b 5=2+b b=5-2 b=3 THEN THE EQUATION IS Y=-2X+3
 Linear-systems/61213: 1.2=3w + 1.8 We understand that 1.8 is subtracted from both sides, but confused about whether we should cancel out the 3 and how. Thanks in advance1 solutions Answer 42125 by checkley71(8403)   on 2006-11-13 17:55:47 (Show Source): You can put this solution on YOUR website!1.2=3W+1.8 3W=1.2-1.8 3W=-.6 W=-.6/3 W=-.2 PROOF 1.2=3*-.2+1.8 1.2=-.6+1.8 1.2=1.2
 Linear-systems/61215: -4/6z + 2=30, I need to help my son write this out and be able to explain the steps to him. thanks in advance for the help1 solutions Answer 42124 by checkley71(8403)   on 2006-11-13 17:52:34 (Show Source): You can put this solution on YOUR website!-4/6Z+2=30 -4/6Z=30-2 -4/6Z=28 CROSS MULTIPLYING WE GET -4Z=28*6 -4Z=168 Z=168/-4 Z=-42 PROOF (-4/6)-42+2=30 (-4*-42)/6+2=30 168/6+2=30 28+2=30 30=30
 Linear-equations/61212: Could someone help me figure out this problem? Find the x and y intercepts and graph the equation. x-4y=-81 solutions Answer 42123 by checkley71(8403)   on 2006-11-13 17:48:11 (Show Source): You can put this solution on YOUR website!Y=mX+b IS THE LINE FORMULA -4Y=-X-8 OR Y=X+8 THUS THE Y INTERCEPT (b) IS=8 AND THE SLOPE IS (+1). NOW SUBSTITUTING 0 FOR Y WE GET THE X INTERCEPT THUS 0=X+8 X=-8 THUS WE HAVE 2 POINTS (-8,0)(0,8) AND A SLOPE OF +1
 logarithm/61211: I dont know what 2=2 is 1 solutions Answer 42122 by checkley71(8403)   on 2006-11-13 17:44:02 (Show Source): You can put this solution on YOUR website!2=2 IS A STATEMENT OF EQUALITY THAT STATES 2 IS EQUAL TO 2.
 Polynomials-and-rational-expressions/61209: Can you help me subtract this rational equation, and put it in simplest form? y-2 over y+3 minus y over 2y+6 Thanks in advance! ac1 solutions Answer 42121 by checkley71(8403)   on 2006-11-13 17:42:17 (Show Source): You can put this solution on YOUR website!(Y-2)/(Y+3)-Y/(2Y+6) FINDING THE COMMON DENOMINATOR WE GET [(Y-2)(2Y+6)-Y(Y+3)]/(Y+3)(2Y+6) NOW MULTIPLY (2Y^2-4Y+6Y-12-Y^2-3Y)/(2Y^2+6Y+6Y+18) (Y^2-Y-12)/(2Y^2+12Y+18) (Y-4)(Y+3)/(2Y+6)(Y+3) NOW CANCEL OUT THE (Y+3) COMMON FACTORS & WE ARE LEFT WITH (Y-4)/(2Y+6) OR (Y-4)/2(Y+3)
 Coordinate-system/61194: Please help. Write the equation of a line, in standard form with the integer coefficiants, that passes through the points (6,7) and (-2,15) PLEASE SHOW ME THE WORK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! and how to solve. -Thanks 1 solutions Answer 42120 by checkley71(8403)   on 2006-11-13 17:31:34 (Show Source): You can put this solution on YOUR website!FIRST WE FIND THE SLOPE USING THE TWO POINTAS GIVEN (Y2-Y1)/(X2-X1) (15-7)/(-2-6) 8/-8=-1 FOR THE SLOPE NOW REPLACING Y+X IN THE LINE FORMULA (Y=mX+b) WITH -1 FOR (m) & WITH ONE SET OF THE COORDINATES WE GET 6=-7+b AND SOLVE FOR b (THE Y INTERCEPT) 6+7=b b=13 THIS GIVE US THE EQUATION Y=-X+13 FOR THIS LINE WITH A SLOPE OF (-1)& A Y INTERCEPTOF (13) ----------------------------------------------------------------------------- WHAT YOU MAY NEED IS TO GRAPH THESE TYPEOFPROBLEMS USING GRAPH PAPER. IF YOU DON'T HAVE ANY JUST GO TO ANY STAPLES OR STORE THAT SELLS PAPER PRODUCTS AND GET A PAD OF GRAPH PAPER. DRAW THE X (VERTICLE LINE) & Y (HORIZONTAL) LINE IN THE MIDDLE OF THE PAGE. THEN LABEL THE MANY UNITS TO THE RIGHT OF THE LINE INTERSECTION PLUS X (+X) VALUES, UNITS TO THE LEFT AS MINUS X (-X) VALUES, THEN LABEL THE UNITS ABOVE THE INTERSECTION PLUS Y (+Y)VALUES AND THE UNITS BELOW THE INTERSECTION MINUS Y (-Y)VALUES. IF YOU NEED MORE HELP GET A GEOMETRY TEXT BOOK FROM THE LOCAL LIBRARY.
 Inequalities/61207: In the formula V= lwh, find l when w=4in., h=6in., and V =144 cu. in.1 solutions Answer 42119 by checkley71(8403)   on 2006-11-13 17:22:43 (Show Source): You can put this solution on YOUR website!144=L*4*6 144=24L L=144/24 L=6 IN. ------------------------------------------ TYHE * SIGN MEANS MULTIPLY EXAMPLE: 2*3*4=24
 Travel_Word_Problems/61204: A small aircraft flies a 2160-mi round trip in a 45 mi/h wind. Find the average rate of speed for the trip if the aircraft can fly 225 mi/h with no wind. I was just confused because, to me, this problem doesnt seem like it has enough information to put in a R | T | D box. Thanks for your help.1 solutions Answer 42118 by checkley71(8403)   on 2006-11-13 17:20:52 (Show Source): You can put this solution on YOUR website!BECAUSE IT IS A ROUND TRIP THE AVERAGE FLIGHT TIME WITH THE WIND IS (225+45) & against the wind the speed is (225-45). now the first 1/2 of the trip is 1080 miles we get (225+45)t=1080 270T=1080 T=1080/270 T=4 HOURS FOR THE FIRST 1/2 OF THE TRIP (225-45)T=1080 180T=1080 T=1080/180 T=6 HOURS FOR THE SECOND 1/2 OF THE TRIP. TOTALTIME IS 4+6=10HOURS TOTAL DISTANCE IS 2160 AND THE TIME IS 10 HOURS THEN 2160=10R R=2160/10 R=216 MPH IS THE AVERAGE SPEED FOR THE ENTIRE TRIP.
 Linear-equations/61198: Can someone please explain the System of linear equation by substitution. Thank you 5X + 2Y = -1 2X - y = -131 solutions Answer 42117 by checkley71(8403)   on 2006-11-13 17:09:55 (Show Source): You can put this solution on YOUR website!2X-Y=-13 -Y=-2X-13 Y=2X+13 NOW SUBSTITUTE (2X+13) FOR X IN THE OTHER ERQUATION WE GET 5X+2(2X+13)=-1 5X+4X+26=-1 9X=-26-1 9X=-27 X=-27/9 X=-3 SOLUTION NOW SUBSTITUTE 3 FOR X IN THE OTHER EQUATION 2*-3-Y=-13 -6-Y=-13 -Y=6-13 -Y=-7 Y=7