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5X-8-3X-X-5-6X-3
-5X-16

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12X-6-11X
X-6

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(13*3+1)/52 the 13*3 is all suits except clubs & the 1 is for the ace of clubs
(39+1)/52=.7692307 or 76.92307% probability of success.

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5,000/600,000=X/900,000
600,000X=5,000*900,000
600,000X=4,500,000,000
X=4,500,000,000/600,000
X=7,500
LOOKS GOOD TO ME.

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33/120=AVERAGE
.275 IS THE DECIMAL AVERAGE.

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P=(4X+1)+(7X-2)+(7X+1)
P=4X+1+7X-2+7X+1
P=18X

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O=S+12
N=2S
S+O+N=132
S+(S+12)+2S=132
S+S+12+2S=132
4S=132-12
4S=120
S=120/4]
S=30 SOLUTION
O=30+12
S=42 SOLUTION
N=2*30
N=60 SOLUTION
PROOF
30+42+60=132
132=132

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FIRST ARRANGE THESE VALUES SMALLEST TO LARGEST THUS:
25,75,156,215,318 NOW ADD ALL THESE VALUES AND DIVIDE BY 5 TO GET THE MEAN
(25+75+156+215+318)/5=789/5=$157.80 IS THE MEAN OR AVERAGE.
THE MEDIAN IS THE MIDDLE NUMBER WHICH IS $156.00.

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AREA=(S1+S2)/2*16
224=[(20+S2)/2]*16
224=[20+S2)*8
224=160+8*S2
224-160=8*S2
8*S2=64
S2=64/8
S2=8m THE LENGTH OF THE SECOND SIDE.
PROOF
224=[(20+8)2]*16
224=[(28/2]*16
224=14*16
224=224

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-3X-27
3X+27
3(X+9)

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ARE YOU SURE THE PROBLEM IS -3A^(B?) OR SHOULD IT BE -3A^(?)B?
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(-3a^2b*14a^3b^2)/(35a^5*-9b^4)
(-42*a^5b^3)/(-315a^5b^4)
(2)/(15b)
2/15b

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9X-7-5X-3
4X-10
2(2X-5)

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Y=4^2+16X+23 USING THE QUADRATIC EQUATION WE GET
Y=(-16+-SQRT[-16^2-4*4*23])/2*4
Y=(-16+-SQRT[256-368])/8
Y=(-16+-SQRT[-112])/8
Y=(-16+-10.583i)/8
Y=(-2+-1.323i)

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PUT THE EQUATION IN THE LINE FORM THUS
4X+Y>=4
Y>=-4X+4 THIS LINE PASSES THROUGH THE Y INTERCEPT (0,4) WITH A SLOPE OF -4
THE X INTERCEPT CAN BE FOUND BY SETTING Y=-0 THUS
0>=-4X+4
-4>=-4X
X=>-4/-4
X=>1 OR THE OTHER POINT IS (1,0)
NOW DRAW A LINE THROUGH THESE TWO POINTS (1,0)&(0,4) AND SHADE THE AREA BELOW THIS LINE TO ELIMINATE ALL VALUES OF X & Y THAT DO NOT SATISFY THIS EQUATIION.

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I don't have graphing capability but will try to help.
for q<5 you need to draw a verticle doted line through the points (5,0) & shade the area to the left of the line (all points q<55).
for q>16 draw another verticle doted line through the points (16,0) and shade the area to the right of the line (all points q>16) .
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for x>-2 draw another verticle doted line throught the point(-2,0) and shade the areato the right of this line.
for x<-5 draw a verticle doted line through the points(-5,0) and shade the area to the left of the line.
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hope this helps.

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Geometry is a vast subject.
Need a little more information like:
What is your specific needs TRIANGLES (area,perimeter, angles, patagorian theorem [a^2+b^2=c^2], etc.)
RECTANGLES (area, perimeters, diagonals, etc.)
CIRCLES (circumferance, area, chords, angles, etc.)
GRAPHING lines using the line formula (Y=mX+b), finding the slope of a line, finding the line formula when you have two points or a point & a slope.
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Present a speciofic area & I'm sure we'll be able to asist you master whatever!!!!!!!!
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The key to solving angles within triangles is: the sum of all three angles is 180 degrees.
The most common triangles is the 45/45/90 & 30/60/90.
If your given two fo the angles say 40 & 50 then assign the unknown angles x then 180=35+40+x
180=75+x
180-75=x
x=105
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Another example would be one angles is 15 more than the second and the third is 45 less than the first. Let x be the first angle then the second is (x+15) and the third is (x-45). Now just add these three angles and set the sum = to 180 thus:
x+(x+15)+(x-45)=180
x+x+x+15-45=180
3x=180-15+45
3x=210
x=210/3
x=70
proof
70+(70+15)+(70-45)=180
70+85+25=180
180=180

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3X-2Y+1 AND
2X+3Y-8 ARE BOTH APPROPRIATE EQUATIONS FOR THE SOLUTION (1,2)
---------------------------------------------------------------
PROOFS
3*1-2*2+1=0
3-4+1=0
0=0
------------------------------
2*2+3*2-8=0
4+6-8=0
0=0

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-5-3^2-3(x-2)=3[(x-2)3-4]
-5+9-3x+6=3[(x-2)-1]
10-3x=3[-x+2]
10-3x=-3x-3
10=-3
--------------------------
are you sure you coppied the problem correctly??????

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(x-3)^2-(x+3)^2
(x^2-6x+9)-(x^2+6x+9)
x^2-6x+9-x^2-6x-9
-12x

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1.2/5.4=22.22%
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(3/5)/20
3/5*1/20
3/100=3%
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25/125=.2=20%
-------------------------------------------
6/125=.048=4.8%

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L=3W+5
92=W(3W+5)
92=3W^2+5W
3W^2+5W-92 USING THE QUADRATIC EQUATION WE GET
W=(-5+-SQRT[25-4*3*-92])/2*3
W=(-5+-SQRT(25+1104])/6
W=(-5+-SQRT1129)/6
W=(-5+-33.6)/6
W=(-5+33.6)/6
W=28.6/6
W=4.767 SOLUTION
L=3*4.767+5
L=19.301 SOLUTION
PROOF
4.767*19.301=92
92=92

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20-SQRT-8
20-2SQRT-2

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X MIDPOINT IS (8-4)/24/2=2
Y MIDPOINT IS (-1+2)/2=1/2=.5
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X+7Y=4
X----Y
-2..(6/7)
-1..(5/7)
0...(4/7)
1...(3/7)
2...(2/7)
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X=-13 IS A VERTICLE LINE PASSING THROUGH THE POINTS (-13,0)

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(x^4/x^5)(x^-2/x)
(x^[4-2])/(x^5*x)
x^2/x^6
1/x^4

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Y=4X^2+16X+23 USING THE QUADRATIC EQUATION WE GHET
Y=(-16+-SQRT[16*16-4*4*23])/2*4
Y=(-16+-SQRT[256-368])/8
Y=(-16+-SQRT-112])/8
Y=(-16+-10.583i)/8
Y=(-16+10.583i)/8
Y=-2+1.323i
Y=-2-1.323i

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400*.25=.10X+.35(400-X)
100=.10X+140-.35X
.25X=40
X=40/.25
X=160 GALLONS OF 10 % GASOHOL
400-160=240 GALLONS OF 35 % ALCOHOL
PROOF
400*.25=.10*160+.35*240
100=16+84
100=100

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10^(-4)/10^5
10^(-4)*10^(-5)
10^(-9)

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CAN'T HELP YOU WITH THE GRAPHING BUT I'LL GIVE YOU ALL THE POINTS AND THE EQUATION
Y=mX+b
3.8Y=-4.2X+1.9
Y=(-4.2/3.8)X+1.9/3.8
Y=(-2.1/1.9)X+.5
Y=-1.1X+.5 NOW YOU HAVE THE SLOPE OF THIS LINE (-1.1) & THE Y INTERCEPT OF.5
SETTING Y=0 YOU CAN GET THE X INTERCEPT THUS
0=-1.1X+.5
1.1X=.5
X=.5/1.1
X=.4545 WHICH IS THE X INTERCEPT (.4545,-1.1)(0,.5) ARE TWO POINTS ON THE LINE.

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6z^3-27z^2+12z factoring out 3z we get
3z(2z^2-9z+4)
3z(2z-1)(z-4)

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DISTANCE=RATE*TIME SO
D=10T FOR THE FIRST RIDER
FOR THE SECOND RIDER WE HAVE
D=18(T-3) SEEING AS THE DISTANCES ARE EQUAL WE HAVE
10T=18(T-3)
10T=18T-54
10T-18T=-54
-8T=-54
T=-54/-8
T=6.75 HOURS AFTER 6:00 AM WHICH MAKES IT 6+6.75 OR 12:45 P.M.

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3X+Y=-8
5X-Y=-16 NOW JUST ADD THESE TWO EQUATIONS
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8X=-24
X=-24/8
X=-3 NOW SUBSTITUTE (-3) FOR X IN EITHER EQUATION & SOLVE FOR Y
3(-3)+Y=-8
-9+Y=-8
Y=-8+9
Y=1
PROOF
5(-3)-1=--16
-15-1=-16
-16=-16