New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'checkley71'
checkley71 answered: 8399 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399, >>NextGraphs/64698: This question is from textbook An Incremental Development
Find the equation of the line that passes through (3,-5) and is perpendicular to the line that passes through (7,-5) and (-2,-4) 1 solutions
Answer 45255 by checkley71(8403) on 2006-12-11 18:14:39 (Show Source):
You can put this solution on YOUR website!FIRST WE FIND THE SLOPE OF THE LINE THROUGH THE 2 POINTS THUS
(Y2-Y1)/(X2-X1)
(-4+5)/(-2-7)
1/-9 IS THE SLOPE OF THE LINE THROUGH ((7,-5)(-2,-4)
NOW TO IDENTIFY A LINE PERPENDICULAR TO THIS LINE IT HAS TO HAVE A SLOPE OF A NEGATIVE RECIPRICAL OF THIS SLOPE. THUS THE SL;OPE OF A LINE PERPENDICULAR TO THIS LINE THROUGH (3,-5) HAS A SLOPE OF 9. NOW WE SUBSTITUTE THESE X&Y POINTS IN THE FORMULA USING THE NEW SLOPE WE GET
-5=9*3+b
-5=27+b
b=-5-27
b=-32 THUS THUIS EQUATION IS
Y=9X-32
|
Travel_Word_Problems/64718: This question is from textbook algebra 1
An airline starts off on a trip with all engines running. It is going at a rate of 900 km per hour, after x hours it shuts down one engine and reduces its speed to 700 km per hour. The trip is a total of 3 hours long
How lonng should the pilot fly before shutting down one engine in order to go a total distance of 2352 in 3 hours. 1 solutions
Answer 45246 by checkley71(8403) on 2006-12-11 17:29:12 (Show Source):
You can put this solution on YOUR website!900T+700(3-T)=2352
900T+2100-700T=2352
200T=2352-2100
200T=252
T=252/200
T=1.26 HOURS @ 900 MPH BEFORE SHUTTING DOWN THE ENGINE
PROOF
900*1.26+700(3-1.26)=2352
1134+700*1.74=2352
1134+1218=2352
2352=2352
|
Linear_Algebra/64546: (5a-2)^2-a=0 1 solutions
Answer 45171 by checkley71(8403) on 2006-12-10 19:47:53 (Show Source):
You can put this solution on YOUR website!(5A-2)^2-A=0
25A^2-20A+4-A=0
25A^2-21A+4=0
USING THE QUADRATIC EQUATION WE GET
X=(-B+-SQRT[B^2-4AC])/2A
X=(21+-SQRT[441-4*25*4])/2*25
X=(21+-SQRT[441-400])/50
X=(21+-SQRT41])/50
X=(21+-6.4)/50
X=(21+6.4)/50
X=27.4/50
X=.548 SOLUTION
X=(21-6.4)/50
X=14.6/50
X=.292 SOLUTION
|
Linear-equations/64554: Find the equation of the line through (-1,2) that is perpendicular to 3x-y=4 1 solutions
Answer 45167 by checkley71(8403) on 2006-12-10 19:35:59 (Show Source):
You can put this solution on YOUR website!3x-y=4
-y=-3x+4
y=3x-4 thus the slope of this line is 3. A line perpendicular to this one has a slope of -1/3. Using this slope & the two points we have the line formula of--
y=mx+b where m=slope & b=y intercept.
2=(-1/3)*-1+b
2=1/3+b
b=2-1/3
b=1 2/3 or 5/3
Thus this line is y=-1/3x+5/3
|
percentage/64557: This question is from textbook Algebra 1
Hiriko invested $11,700,part at 5% interest and the balance at 7% interest.If her annaul earnings from both investments is $733,how much is invested at each rate? 1 solutions
Answer 45165 by checkley71(8403) on 2006-12-10 19:26:30 (Show Source):
You can put this solution on YOUR website!.07x+.05(11700-x)=733
.07x+585-.05x=733
.02x=733-585
.02x=148
x=148/.02
x=7400 amount invested @ 7%.
then the remainder is (11700-7400=4300) or 4300 is invested @ 5%
proof
.07*7400+.05*4300=733
518+215=733
733=733
|
Functions/64478: will you help with a word problem?
My Phone Co, Inc. uses the following price schedule: x < 200 minutes, $.25 per minute; between 201 and 500 minutes, $.15 per minute; Over 501 minutes, $.10 per minute.
How much does 480 minutes cost?
1 solutions
Answer 45139 by checkley71(8403) on 2006-12-10 15:20:33 (Show Source):
|
Functions/64479: I really need help on this
Find the equation of the line in slope intercept form given the following:
19.) m = 5 and point (3, -10)
20.) The line runs through (2, 3) and (-3, 7)
1 solutions
Answer 45138 by checkley71(8403) on 2006-12-10 15:17:40 (Show Source):
You can put this solution on YOUR website!Y=mX+b
-10=5*3+b
-10=15+b
b=-1)-15
b=-25 THEN THE EQUATION IS
Y=5X-25
-----------------------------------------------------
TO FIND THE SLOPE(m) WE MAKE A FRACTION (Y2-Y1/(X20-X1)
SLOPE=(7-3)/(-3-2)
SLOPE=4/-5
SLOPE=-4/5 NOW WE FIND THE Y INTERCEPT(b) BY USING ONE SET OF POINTS FOR X & Y
3=-4/5*2+b
b=3+4/5
b=19/5 THUS WE HAVE
Y=-4/5X+19/5 FOR THE LINE PASSING THROUGH THESE TWO POINTS.
|
Expressions-with-variables/64524: REAL WORLD PROBLEM!!!
Source: http://verizonmath.blogspot.com/
Verizon Wireless charges for data use. Their rate for this data use is .002 cents per kilobyte. If George uses 35,893 kilobytes, What does he owe in dollars? 1 solutions
Answer 45134 by checkley71(8403) on 2006-12-10 14:59:40 (Show Source):
|
Linear-equations/64453: write an equation that contains the points (2,-1) and (-5,-1)? 1 solutions
Answer 45075 by checkley71(8403) on 2006-12-09 17:46:01 (Show Source):
You can put this solution on YOUR website!FIRST WE FIND THE SLOPE OF THIS LINE WHICH IS (Y2-Y1)/(X2-X1)
(-1+1)/-5-7)=0/-12=0 THEREFORE THIS A HORIZONTAL LINE WITH SLOPE OF 0 & PASSES THROUGH Y=-1.
THEREFORE THE LINE EQUATION Y=mX+b (m=SLOPE, b=Y INERCEPT)
BECOMES Y=-1
|
Linear-systems/64402: This question is from textbook McDougal Littell
2876question #42 says you are selling tickets for a high school play students tickets cost 4$ and general admission cost$6. you sell 525 tickets and collect $2876 how many of each type of ticket did you sell? so far the only thing i get is that one of the equatons is i think 4x+6y=525 but i don't know how to get the other one,? help? 1 solutions
Answer 45052 by checkley71(8403) on 2006-12-09 11:11:49 (Show Source):
You can put this solution on YOUR website!S+G=525 STUDENT + GENERAL ADMISSION TICKETS SOLD
4S+6G=2876 AMOUNT OF MONEY COLLECTED FOR SELLING STUDENT TICKETS FOR $4 & GENERAL ADMISSION FOR $6.
THEN S=525-G NOW SUBSTITUTE (525-G) FOR S IN THE OTHER EQUATION WE GET
4(525-G)+6G=2876
2100-4G+6G=2876
2G=2876-2100
2G=776
G=776/2
G=388 THE NUMBER OF GENERAL ADMISSION TICKETS SOLD. THEN
525-388=137 NUMBER OF STUDENT TICKETS SOLD.
PROOF
4*137+6*388=2876
548+2328=2876
2876=2876
|
|