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# Recent problems solved by 'checkley71'

checkley71 answered: 8399 problems
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 Linear-equations/64883: Someone please help me with this problem: Find the slope of the line passing through the points (-2,4) and (-3,5).1 solutions Answer 45375 by checkley71(8403)   on 2006-12-12 21:21:31 (Show Source): You can put this solution on YOUR website!THE SLOPE IS FOUND BY (Y2-Y1)/(X2-X1) (5-4)/(-3+2) 1/-1 -1 IS THE SLOPE
 Exponential-and-logarithmic-functions/64900: Having a difficult time solving the following problem (3rs)^5 thanks1 solutions Answer 45374 by checkley71(8403)   on 2006-12-12 21:19:16 (Show Source): You can put this solution on YOUR website!(3RS)^5 EACH ELEMENT IS RAISED TO THE 5th POWER 243R^5S^5
 Inequalities/64891: This question is from textbook Pre-Algebra Find the sum or difference. -3/4 - (-5/18) Thanks sooooooo much! Happy Holidays!1 solutions Answer 45372 by checkley71(8403)   on 2006-12-12 21:16:11 (Show Source): You can put this solution on YOUR website!FIRST WE FIND A COMMON DENOMINATOR FOR 4 & 18 WHICH IS 36 (2*2)(2*9) SINCE A 2 IS COMMON TO BOTH DENOMINATORS WE ONLY NEED TO USE IT ONCE. ALL OTHER NUMBERS ARE MULTIPLIED TO GET THE NEW DENOMINATOR - THUS 2*2*9=36 -3/4=X/36 4X=-108 X=-108/4 X=-27 THUS WE HAVE -3/4=-27/36 ----------- 5/18=X/36 18X=180 X=-180/18 X=-10 THUS WE HAVE -5/18=-10/36 ------------------------- -27/36-(-10/36) -27/36+10/36 -17/36
 Rectangles/64884: Please help: The length of a rectangle is 4 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 136 feet, find the length of the rectangle.1 solutions Answer 45369 by checkley71(8403)   on 2006-12-12 21:07:56 (Show Source): You can put this solution on YOUR website!LENGTH=2W-4 SO THE PERIMETER IS 2W+2(2W-4)=136 2W+4W-8=136 6W=136=8 6W=144 W=144/6 W=24 SOLUTION THEN THE LENGTH IS 2*24-4=48-4=44 PROOF 2*24+2*44=136 48+88=136 136=136
 Equations/64893: what is the answer to using addition on #1 and #2 and on #3 using substituion #1)x + 2y =5 #2)5x -4y =1 #3) 7x + y = 1 3x +4y =1 -10x + 8y = -3 3x + 2y= -9 1 solutions Answer 45368 by checkley71(8403)   on 2006-12-12 21:02:01 (Show Source): You can put this solution on YOUR website!X+2Y=5 3X+4Y=1 ----------------- 4X+6Y=6 ANSWER #1 ###################################### 5X-4Y=1 -10X+8Y=-3 ----------------- -5X+4Y=-2 ANSWER #2 ##################################### 7X+Y=1 -(3X+2Y=-9) ----------------- 4X-Y=10 ANSWER #3
 Expressions-with-variables/64897: Evaluate b2 – 2bc + c2 if b = 3 and c = –21 solutions Answer 45367 by checkley71(8403)   on 2006-12-12 20:57:00 (Show Source): You can put this solution on YOUR website!B^2-2BC+C^2 3^2-2*3*-2+(-2)^2 9+12+4=25
 Miscellaneous_Word_Problems/64898: Any help on this would be great, I can't seem to figure it out. A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108in2. What are the dimensions of the photo?1 solutions Answer 45366 by checkley71(8403)   on 2006-12-12 20:54:52 (Show Source): You can put this solution on YOUR website!(X+4)(X+7)=108 (X+4)IS THE WIDTH (X)+ TWO 2 INCH BORDERS (X+7)IS THE LENGTH (X+3)+ TWO 2 INCH BORBERS (X+4)(X+7)=108 X^2+11X+28=108 X^2+11X-80=0 (X+16)(X-5)=0 X+16=0 X=-16 (NON SOLUTION) X-5=0 X=5 SOLUTION. INCHES FOR THE WIDTH OF THE PICTURE X+3=8 INCHES FOR THE LENGTH OF THE PICTURE.
 Triangles/64887: How do I find the base of a triangle? The area of the triangle is 200 ft. squared, and the height is 12ft.1 solutions Answer 45365 by checkley71(8403)   on 2006-12-12 20:45:38 (Show Source): You can put this solution on YOUR website!AREA=B*H/2 200=B*12/2 200=6B B=200/6 B=33 1/3 IS THE BASE PROOF 200=(33 1/3)12/2 200=(33*12+12/3)/2 200=(396+4)/2 200=400/2 200=200
 Inequalities/64889: This question is from textbook Pre-Algebra Find the sum or difference. -4/17 + 3/5 Thanks soooooooooo much! Happy Holidays!1 solutions Answer 45363 by checkley71(8403)   on 2006-12-12 20:40:14 (Show Source): You can put this solution on YOUR website!-4/17+3/5 WE NEED TO FIND A COMMON DENOMINATOR FOR THESE 2 FRACTIONS THUS 17*5=105 WHICH IS COMMON. NOW WE CONVERT BOTH FRACTIONS TO FRACTION WITH A DENOMINATOR OF 85 -4/7=X/105 7X=-4*105 7X=-420 X=-420/7 X=-60 SO -4/7 BECOMES -60/105 ------------------------------------ 3/5=X/105 5X=315 X=315/5 X=63 SO 3/5 BECOMES 63/105 ------------------------------------ NOW WE CAN SUBTRACT THESE FRACTIONS 63/105-60/105=3/105=1/35
 Rate-of-work-word-problems/64886: This was on a test not in book. If a potato grows 3cm in 2 weeks, how much will it grow in 52 weeks? 1 solutions Answer 45362 by checkley71(8403)   on 2006-12-12 20:30:57 (Show Source): You can put this solution on YOUR website!3CM/2WEEKS=XCM/52WEEKS 2X=3*52 2X=156 X=156/2 X=78 CM IS THE GROWTH IF THE GROWTH OVER THE NEXT 50 WEEKS IS CONSTANT.
 Functions/64857: For the floor plans given in exercise 27, determine whether the side through the points (2, 3) and (11, 6) is perpendicular to the side through the points (2, 3) and (-3, 18).1 solutions Answer 45360 by checkley71(8403)   on 2006-12-12 20:28:16 (Show Source): You can put this solution on YOUR website!(6-3)/(11-2)=3/9=1/3 SLOPE (18-3)/(-3-2)=15/-5=-3 SLOPE THAT IS PERPENDICULAR TO THE FIRST SLOPE BECAUSE IT IS THE NEGATIVE RECIPRICAL OF 1/3
 Functions/64860: Write the equation of the line passing through each of the given pairs of points. Write your result in slope-intercept form, where possible. (2, -3) and (2, 4)1 solutions Answer 45359 by checkley71(8403)   on 2006-12-12 20:24:37 (Show Source): You can put this solution on YOUR website!SLOPE=(4+3)/(2-2) 7/0 SLOPE IS UNDEFINED AND IS A VERTICLE LINE THROUGH X=2 THUS THE LINE EQUATION Y=mX+b BECOMES X=2
 Expressions-with-variables/64867: This question is from textbook algebra 1 solve for x and y 3x+1=-7y 6x+7y=01 solutions Answer 45356 by checkley71(8403)   on 2006-12-12 20:21:05 (Show Source): You can put this solution on YOUR website!3X+1=-7Y 3X+7Y=-1 -(6X+7Y=0) NOW SUBTRACT THESE 2 EQUATIONS. ---------------------------- -3X=-1 X=-1/-3 X=1/3 SOLUTION. SUBSTITUTING 1/3 FOR X IN EITHER EQUATION WE SOLVE FOR Y 3*1/3+1=-7Y 1+1=-7Y 7Y=-2 Y=-2/7 SOLUTION PROOF 6*1/3+7(-2/7)=0 2-14/7=0 2-2=0 0=0
 Expressions-with-variables/64873: This question is from textbook algebra 1 Determine the best method to solve the system .Then solve for x and y. 2x+y=3x-15 x+5=4y+2x1 solutions Answer 45354 by checkley71(8403)   on 2006-12-12 20:07:58 (Show Source): You can put this solution on YOUR website!2X+Y=3X-15 2X-3X+Y=-15 -X+Y=-15 ----------------------- X+5=4Y+2X X-2X-4Y=-5 -X-4Y=-5 ----------------------- NOW WE CAN SUBTRACT THESE 2 EQUATIONS AND SOLVE OFOR X & Y. -X+Y=-15 -(-X-4Y=-5) ----------------------- 5Y=-10 Y=-10/5 Y=-2 SOLUTION NOW SUBSTITUTE (-2) FOR Y IN ONE OF THESE EQUATIONS 2X+(-2)=3X-15 2X-2=3X-15 -X=-15+2 -X=-13 X=13 SOLUTION PROOF 13+5=4(-2)+2*13 18=-8+26 18=18
 Equations/64882: 3x divided by 4 equals -81 solutions Answer 45352 by checkley71(8403)   on 2006-12-12 19:51:12 (Show Source): You can put this solution on YOUR website!3x/4=-8 3x=-32 x=-32/3 x=-10 2/3 solution proof 3(-10 2/3)/4=-8 3(-32/3)/4=-8 (-96/3)/4=-8 (-96/3*1/4)=-8 -96/12=-8 -8=-8
 Money_Word_Problems/64816: An experienced accountant can prepare a tax return in 10 hours. A novice accountant can do the job in 16 hours. How long will it take them to do the job working together?1 solutions Answer 45330 by checkley71(8403)   on 2006-12-12 14:46:36 (Show Source): You can put this solution on YOUR website!THIS IS A SIMPLE SOLUTION. MAKE A FRACTION OF THE PRODUCT OF THE TIMES DIVIDED BY THE SUM OF THE TIMES THUS: (16*10)/(16+10) 160/26=6.1538 HOURS TO DO THE JOB JOINTLY.
 Travel_Word_Problems/64818: Roberto invested some money at 7%, and then investes \$5000 more than twice this amount at 11%. His total annual income from the two investments was \$3450. How much was invested at 11%?1 solutions Answer 45329 by checkley71(8403)   on 2006-12-12 14:42:00 (Show Source): You can put this solution on YOUR website!.07x+.11(2x+5000)=3450 .07x+.22x+550=3450 .29x=3450-550 .29x=2900 x=2900/.29 x=10000 amount invested @ 7% 2*10000+5000=20000+5000=25000 amount invested @ 11% proof .07*10000+.11*25000=3450 700+2750=3450 3450=3450
 Graphs/64755: Find the slope of any line perpendicular to the line through points (0, 5) and (-3, -4).1 solutions Answer 45315 by checkley71(8403)   on 2006-12-12 10:29:10 (Show Source): You can put this solution on YOUR website!(0,5)(-3,-4) developes the slope of (y2-y1)/(x2-x1) (-4-5)/(-3-0) -9/-3=3 is the slope of a line through these 2 points. for a perpendicular line it has to have a slope of -1/3 (this is a negative reciprical of the line with the slope of 3).
 Equations/64786: Express each number in standard form -9.102040x10(to the 2 power)1 solutions Answer 45314 by checkley71(8403)   on 2006-12-12 10:23:58 (Show Source): You can put this solution on YOUR website!-9.102040x10^2 -910.2040
 Equations/64785: Express each number in standard form -9.5x10-3 This is 10 to the -3 power1 solutions Answer 45313 by checkley71(8403)   on 2006-12-12 10:20:35 (Show Source): You can put this solution on YOUR website!-9.5x10^(-3) -.0095 [move the decimal point 3 places to the left 10^-3]
 Equations/64784: Express each number in scientific notation -0.0000032 I would appreciate your help1 solutions Answer 45312 by checkley71(8403)   on 2006-12-12 10:16:56 (Show Source): You can put this solution on YOUR website!-3.2*10^(-6) [Move the decimal point 6 places to the right = 10^-6]
 Inequalities/64719: ok i need help with this problem: 1x+2y=2 -4x+3y=25 using the elimination process1 solutions Answer 45277 by checkley71(8403)   on 2006-12-11 20:08:56 (Show Source): You can put this solution on YOUR website!-4X+3Y=25 NOW MULTIPLY THE OTHER EQUATION BY 4 WE GET 4X+8Y=8 NOW ADD -------------------------------------- 11Y=33 Y=33/11 Y=3 SOLUTION SUBSTITUTING 3 FOR Y WE GET 4X+8*3=8 4X+24=8 4X=-24+8 4X=-16 X=-16/4 X=-4 SOLUTION PROOF -4*-4+3*3=25 16+9=25 25=25
 Coordinate-system/64743: 6n2+17n+71 solutions Answer 45276 by checkley71(8403)   on 2006-12-11 19:59:35 (Show Source): You can put this solution on YOUR website!6N^2+17N+7=0 (2N+1)(3N+7)=0 2N+1=0 2N=-1 N=-1/2 SOLUTION 3N+7=0 3M=-7 N-7/3 N=-2 1/3 SOLUTION
 Equations/64737: I need help with this... Write the slope-intercept form of an equation of the line that passes through thr given point and is perpendicular to the graph of each equation. (-2,-2), y= -1/3x+9 I got really confused in class today and my teacher explained how to do these problems in examples. Is there a formula i can use for it?1 solutions Answer 45273 by checkley71(8403)   on 2006-12-11 19:39:38 (Show Source): You can put this solution on YOUR website!Y=-1/X+9 IS A LINE WITH A SLOPE OF (-1/3) & A Y INTERCEPT OF (0,9). FOR A LINE TO BE PERPENDICULAR IT MUST HAVE A SLOPE THAT IS THE NEGATIVE RECIPRICAL OF THE LINE IT IS PERPENDICULAT TO. THUS THE SLOPE IS 3 FOR THE PERPENDICULAR LINE THROUGH (-2,-2). NOW SUBSTITUTE THESE POINTS X=-2, Y=-2 AND THE SLOPE IN THE LINE FORMULA Y=mX+b WE GET -2=3(-2)+b -2=-6+b B=-2+6 b=4 SOLUTION FOR THE Y INTERCEPT (0,4) THUS THE EQUATION FOR THIS LINE IS Y=3X+4
 Expressions-with-variables/64734: The sum of two numbers is 82. Their difference is 24. Write a system of equations that describes this situation. Solve by elimination to find the two numbers.1 solutions Answer 45271 by checkley71(8403)   on 2006-12-11 19:33:45 (Show Source): You can put this solution on YOUR website!X+Y=82 X-Y=24 NOW ADD THESE 2 EQUATIONS -------------------------------------------- 2X=106 X=106/2 X=53 SOLUTION 53+Y=82 Y=82-53 Y=29 SOLUTION PROOF 53-29=24 24=24
 expressions/64696: This question is from textbook can you explain to me step by step if I need to change the whole number into an improper fraction to work the problem 1 solutions Answer 45263 by checkley71(8403)   on 2006-12-11 18:42:09 (Show Source): You can put this solution on YOUR website!7 -4 2/3 CHANGE THE 7 TO 6 3/3 THEN SUBTRACT THE FRACTIONS AND THE WHOLE NUMBERS THUS 6 3/3 -4 2/3 ------------ 2 1/3 ------------------------------------------------------------------- 7=6 3/3 because 3/3=1 & 6+1=7 ------------------------------------------------ 7 also = 6 7/7 if you were working with fractions with 7 in the denominator again 6+7/7=6+1=7 -------------------------------------------------------------------- 7 also = 6 35/35 if you were working with fractions with 35 in the denominator again 7=6+35/35=6+1=7
 Expressions-with-variables/64669: use elimination to solve the system 4x+7y=-14 and 8x+5y=8 for x1 solutions Answer 45262 by checkley71(8403)   on 2006-12-11 18:38:27 (Show Source): You can put this solution on YOUR website!4X+7Y=-14 MULTIPY THIS EQUATION BY -5 WE GET -20X-35Y=70 8X+5Y=8 NOW MULTIPLY THIS EQUATION BY 7 WE GET 56X+35Y=56 NOW ADD -20X-35Y=70 56X+35Y=56 ----------------------------------------- 36X=126 X=126/36 X=3.5 SOLUTION
 Square-cubic-other-roots/64693: This question is from textbook An Incremental Development Please help to simplify : square root of 8 times the square root of 81 solutions Answer 45259 by checkley71(8403)   on 2006-12-11 18:28:10 (Show Source): You can put this solution on YOUR website!SQRT8*SQRT8 2SQRT4*2SQRT4 4SQRT4 4*2=8
 real-numbers/64728: WRITE THE DECIMAL AS A FRACTION IN SIMPLEST FORM. 2.3051 solutions Answer 45258 by checkley71(8403)   on 2006-12-11 18:24:04 (Show Source): You can put this solution on YOUR website!2.305=2 305/1000=2 61/200=461/200
 Linear-equations/64727: This question is from textbook algebra 1 6-4/7x=13+3/7x1 solutions Answer 45257 by checkley71(8403)   on 2006-12-11 18:19:36 (Show Source): You can put this solution on YOUR website!6-4/7X=13+3/7X -4/7X-3/7X=13-6 -7/7X=7 -X=7 X=-7 SOLUTION PROOF 6-(4/7)(-7)=13+(3/7)(-7) 6+4=13-3 10=10
 Graphs/64698: This question is from textbook An Incremental Development Find the equation of the line that passes through (3,-5) and is perpendicular to the line that passes through (7,-5) and (-2,-4)1 solutions Answer 45255 by checkley71(8403)   on 2006-12-11 18:14:39 (Show Source): You can put this solution on YOUR website!FIRST WE FIND THE SLOPE OF THE LINE THROUGH THE 2 POINTS THUS (Y2-Y1)/(X2-X1) (-4+5)/(-2-7) 1/-9 IS THE SLOPE OF THE LINE THROUGH ((7,-5)(-2,-4) NOW TO IDENTIFY A LINE PERPENDICULAR TO THIS LINE IT HAS TO HAVE A SLOPE OF A NEGATIVE RECIPRICAL OF THIS SLOPE. THUS THE SL;OPE OF A LINE PERPENDICULAR TO THIS LINE THROUGH (3,-5) HAS A SLOPE OF 9. NOW WE SUBSTITUTE THESE X&Y POINTS IN THE FORMULA USING THE NEW SLOPE WE GET -5=9*3+b -5=27+b b=-5-27 b=-32 THUS THUIS EQUATION IS Y=9X-32