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Quadratic_Equations/130455: Can someone assist me. Thank You
f(x)=x^2-2x-6 1 solutions
Answer 95282 by checkley71(8403) on 2008-03-04 19:25:19 (Show Source):
You can put this solution on YOUR website!F(X)=X^2-2X-6
IF YOU NEED TO SOLVE THIS EQUATION YOU NEED TO USES THE QUADRATIC EQUATION:
ANSWERS=3.6 & -1.6
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NORMALLY THERE ARE VALUES OF X GIVEN AND YOU'RE ASKED TO SOLVE THIS EQUATION.
GIVEN A VALUE FOR X JUST REPLACE X BY THE NUMBER AND SOLVE THE EQUATION.
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Equations/130449: This question is from textbook
(3,2) Y=3X+4
1 solutions
Answer 95280 by checkley71(8403) on 2008-03-04 19:19:47 (Show Source):
You can put this solution on YOUR website!Y=3X+4 (RED LINE)
IF THESE POINTS (3,2) ARE ON A PARALLEL LINE THEN:
2=3*3+b
2=9+b
b=2-9
b=-7 Y INTERCEPT.
Y=3X-7 (GREEN LINE)
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10,of TWO functions 3x +4 and 3x -7).
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Percentage-and-ratio-word-problems/130450: Five eighths of the 4960 voters supported Mayor Rios. answer:3100
a.) How many voters did not support Mayor Rios? answer: 1860
b.) What was the ratio of voters who supported the mayor to those who did not support the mayor? answer: I keep getting 155/93, but it's incorrect. Can you tell me what I am doing wrong? Thank you! Megan 1 solutions
Answer 95276 by checkley71(8403) on 2008-03-04 19:11:51 (Show Source):
You can put this solution on YOUR website!REDUCING YOUR FRACTION BY DIVIDING EACH TERM BY 31 YOU GET 5/3.
5/8:3/8=40/24=5/3 IS THE RATION OF VOTERS FOR MAYOR RIOS TO THOSE WHO DID NOT VOTE FOR HIM.
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Probability-and-statistics/130429: This question is from textbook Statistics
A 35 year old woman purchases a $100,000 term life insurance policy for an annual payment of $360. Based on a period life toable for the U.S. government, the probablity that she will survive the year is is 0.999057. Find the expected value of the policy for the insurance company. 1 solutions
Answer 95265 by checkley71(8403) on 2008-03-04 18:07:23 (Show Source):
You can put this solution on YOUR website!1-.999057=.000943*100,000=$94.3 DOLLARS IS THE EXPECTED PAYOUT FOR EACH OF THE INSURED IN A GIVEN YEAR.
THUS THEIR PROFIT IS $360-$94.3=$265.7 FOR THE FIRST YEAR.
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Miscellaneous_Word_Problems/130436: The owner of a go cart track was counting the money from one days ticket sales
He knew that a total of 168 tickets were sold. Adult tickets cost 7.50 each and
childrens tickets cost 4.75 each. The total receipts for the day was 996.00 how many of each type of ticket was sold. 1 solutions
Answer 95264 by checkley71(8403) on 2008-03-04 17:54:57 (Show Source):
You can put this solution on YOUR website!A+C=168 OR A=168-C
7.50A+4.75C=996
7.50(168-C)+4.75C=996
1260-7.5C+4.75C=996
-2.75C=996-1260
-2.75C=-264
C=-264/-2.75
C=96 THE NUMBER OF CHILDREN'S TICKETS SOLD.
168-96=72 ADULT TICKETS SOLD.
PROOF:
7.50*72+4.75*96=996
540+456=996
996=996
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Probability-and-statistics/130388: The daily double at most race tracks consists of selecting the winning horse in both the first and second races. If the first race has 8 entries and the second race has 9 entries, how many daily double tickets must be purchased to guarantee a win? 1 solutions
Answer 95263 by checkley71(8403) on 2008-03-04 17:47:42 (Show Source):
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Percentage-and-ratio-word-problems/130431:
The school production of "Our town" was a big success. For opening night, 323
tickets were sold. Students paid $2.50 each while non students paid $4.50 each. If a total of $1009.50 was collected, how many students and how many non students attended?
1 solutions
Answer 95262 by checkley71(8403) on 2008-03-04 17:43:56 (Show Source):
You can put this solution on YOUR website!S+NS=323 OR S=323-NS
2.50S+4.50NS=1009.50
2.50(323-NS)+4.50NS=1009.50
807.5-2.50NS+4.50NS=1009.50
2NS=1009.50-807.50
2NS=202
NS=202/2
NS=101 NUMBER OF NON STUDENT TICKETS SOLD.
323-101=222 STUDENT TICKETS SOLD.
PROOF:
2.50*222+4.50*101=1009.50
555+454.5=1009.5
1009.5=1009.5
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Mixture_Word_Problems/130391: I have a world problem, not sure if I came up with the right answer. Could I have some help on this, thanks. The good seed flower shop sells its own brand of fertilizer. It mixes one brand of fertilizer that contains 7% nitrogen with another that contains 8% nitrogen. The resulting mixture contains 7.7% nitrogen. How many pounds of the 8% fertilizer must be used to make 200 pounds of the 7.7% mixture? I have 98.6 Could you let me know if it is correct. Thank you, I appreciate the help. 1 solutions
Answer 95257 by checkley71(8403) on 2008-03-04 17:09:12 (Show Source):
You can put this solution on YOUR website!.08X+.07(200-X)=.077*200
.08X+14-.07X=15.4
.01X=15.4-14
.01X=1.4
X=1.4/.01
X=140 POUNDS OF 8% FERTILIZER IS NEEDED.
200-140=60 POUNDS OF 7% IS NEEDED.
PROOF:
.08*140+.07*60=.077*200
11.2+4.2=15.4
15.4=15.4
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percentage/130395: Last month a factory produced 800 television sets. This month, The same factory produced 1,064 television sets. The increase in production from last month to this month is? 1 solutions
Answer 95256 by checkley71(8403) on 2008-03-04 17:02:54 (Show Source):
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Linear_Algebra/130416: I am stumped with the following problem:
A function gives the value of "c" as 2 x (22/7) x r. Find "c" when r=14 cm and r=70 cm. Please help if able. 1 solutions
Answer 95242 by checkley71(8403) on 2008-03-04 16:21:01 (Show Source):
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Mixture_Word_Problems/130412: four pencils and 2 pens cost $2.26. six pencils and five pens cost $5.17. find the cost of the pencil. find the cost of the pen 1 solutions
Answer 95239 by checkley71(8403) on 2008-03-04 16:04:09 (Show Source):
You can put this solution on YOUR website!4X+2Y=2.26
6X+5Y=5.17
NOW MULTIPLY THE FIRST EQUATON BY -3 & THE SECOND EQUATIOB BY 2 & ADD.
-12X-6Y=-6.78
12X+10Y=10.34
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4Y=3.56
Y=3.56/4
Y=.89 COST OF 1 PEN.
4X+2*.89=2.26
4X+1.78=2.26
4X=2.26-1.78
4X=.48
X=.48/4
X=.12 COST OF 1 PENCIL.
PROOF:
6*.12 +5*.89=5.17
.72+4.45=5.17
5.17=5.17
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Coordinate-system/130378: This question is from textbook algebra
Hi! How are you all Today?
So I am having a bit of trouble with this question.
The problem is: Find the slope of a line between the points (5,3) and (-2,-3).
pLease and Thank You=) 1 solutions
Answer 95213 by checkley71(8403) on 2008-03-04 11:03:56 (Show Source):
You can put this solution on YOUR website!slope=(y2-y1)/(x2-x1)=(-3-3)/(-2-5)=-6/-7=6/7 is the slope.
3=5*6/7+b
3=30/7+b
b=3-30/7
b=(21-30)/7
b=-9/7 the y intercept.
thus this line equation is:
Y=6X/7-9/7
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, 6x/7 -9/7).
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Miscellaneous_Word_Problems/130342: Roberto invested some money at 7%, and then invested $2,000 more than twice his amount at 11%. His total annual income from the two investemnts was $3,990. How much was invested at 11%. 1 solutions
Answer 95209 by checkley71(8403) on 2008-03-04 10:55:22 (Show Source):
You can put this solution on YOUR website!.07X+.11(2X+2000)=3990
.07X+.22X+220=3990
.29X=3990-220
.29X=3770
X=3770/.29
X=13,000 INVESTED @ 7%.
2*13000+2000=26000+2000=28,000 IS THE AMOUNT INVESTED @ 11%.
PROOF:
.07*13000+.11*28000=3990
910+3080=3990
3990=3990
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Rectangles/130363: This question is not in a book.
The width of a rectangle is 14 feet less than twice the length. What is the length if the perimeter is 62 feet? 1 solutions
Answer 95208 by checkley71(8403) on 2008-03-04 10:48:14 (Show Source):
You can put this solution on YOUR website!W=2L-14
2(2L-14)+2L=62
4L-28+2L=62
6L=62+28
6L=90
L=90/6
L=15 IS THE LENGTH
W=2*15-14
W=30-14
W=16 IS THE WIDTH.
PROOF:
2*15+2*16=62
30+32=62
62=62
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Polynomials-and-rational-expressions/130294: Please help me with this problem I am not sure how to solve it. I tried it and can't get it. Please help me.
Solve the following problem involving applications of polynomials.
Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
1 solutions
Answer 95171 by checkley71(8403) on 2008-03-03 20:18:57 (Show Source):
You can put this solution on YOUR website!X, X+2, X+4 ARE THE 3 CONSECUTIVE EVEN INTEGERS.
(X+4)^2=(X+2)^2+76
X^2+8X+16=X^2+4X+4+76
8X-4X=80-16
4X=64
X=64/4
X=16 ANSWER FOR THE SMALLER INTEGER.
16+2=18 THE MIDDLE INTEGER.
16+4=20 THE LARGEST INTEGER.
20^2=18^2+76
400=324+76
400=400
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