# See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

# Recent problems solved by 'checkley71'

checkley71 answered: 8399 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399, >>Next

 Linear-equations/68354: how do i work this out?? A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?1 solutions Answer 48632 by checkley71(8403)   on 2007-01-28 17:35:00 (Show Source): You can put this solution on YOUR website!44*X+48(X-1)=274 44X+48X-48=274 92X=274+48 92X=322 X=322/92 X=3.5 HOURS AFTER 1 PM = 4:30 PM THE 2 BUSES WILL BE 274 MILES APART.
 Linear-equations/68356: how can i work this out? The length of a rectangular playing field is 5 ft less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the field.1 solutions Answer 48631 by checkley71(8403)   on 2007-01-28 17:29:59 (Show Source): You can put this solution on YOUR website!LENGTH=2W-5 & W=WIDTH. THUS 2(2W-5)+2W=230 4W-10+2W=230 6W=230+10 6W=240 W=240/6 W=40 ANSWER FOR THE WIDTH LENGTH=2*24-5 LENGTH=48-5 LENGTH=43 PROOF 2(2*40-5)+2*40=230 2(80-5)+80=230 2*75+80=230 150+80=230 230=230
 Polynomials-and-rational-expressions/68361: This question is from textbook An Incremental Development please help to solve by factoring -5x - 6 = -6x^2 1 solutions Answer 48630 by checkley71(8403)   on 2007-01-28 17:22:33 (Show Source): You can put this solution on YOUR website!-5X-6=-6X^2 6X^2-5X-6=0 (3X+2)(2X-3)=0 3X+2=0 3X=-2 X=-2/3 ANSWER 2X-3=0 2X=3 X=2/3 ANSWER
 Geometry_Word_Problems/68362: please help me with this Two angles are complementary if their sum of their measures is 90 degrees. 1 solutions Answer 48629 by checkley71(8403)   on 2007-01-28 17:14:31 (Show Source): You can put this solution on YOUR website!ANY TWO ANGLES THAT ADD UP TO 90 DEGREES ARE COMPLEMENTARY & FORM A RIGHT ANGLE THUS: 30 DEGREES + 60 DEGREES = 90 DEGREES ( A RIGHT ANGLE) 42 DEGREES + 48 DEGREES = 90 DEGREES 6 DEGREES + 84 DEGREES =90 DEGREES 24 DEGREES + 66 DEGREES = 90 DEGREES
 Quadratic_Equations/68371: This question is from textbook An Incremental Development Please help to solve using the quadratic formula : -3x^2 - 4 = 2x1 solutions Answer 48628 by checkley71(8403)   on 2007-01-28 17:10:35 (Show Source): You can put this solution on YOUR website!-3X^2-2X-4=0 X=(-B+-SQRT[B^2-4AC])/2A X=(2+-SQRT[4-4*-3*-4])/2*-3 x=(2+-sqrt[4-48])/6 x=(2+-sqrt-44)/6 x=(2+-6.63325i)/6 x=2/6+6.63325i/6 x=.33333+1.10554i answer x=2/6-6.63325i/6 x=.3333-1.10554i answer ---------------------------------- happy manipulating :)
 Length-and-distance/68374: This question is from textbook An Incremental Development use the distance formula to find the distance between (5,-2) and (-3,3)1 solutions Answer 48627 by checkley71(8403)   on 2007-01-28 17:01:50 (Show Source): You can put this solution on YOUR website!DISTANCE^2=(5-[-3])^2+(3-[-2])^2 D^2=(5+3)^2+(3+2)^2 D^2=8^2+5^2 D^2=64+25 D^2=89 D=SQRT89 D=9.434 IS THE DISTANCE BETWEEN THESE POINTS (HYPOTENUSE OF A RIGHT TRIANGLE)
 Quadratic_Equations/68373: This question is from textbook An Incremental Development Find the equation of the line that passes through (4,2) and is perpendicular to the line 3y - 2x = 51 solutions Answer 48626 by checkley71(8403)   on 2007-01-28 16:55:56 (Show Source): You can put this solution on YOUR website!3Y-2X=5 3Y=2X+5 Y=2X/3+5/3 THUS THIS LINE HAS A SLOPE OF (2/3) & A LINE PERPENDICULAR TO THIS LINE THEN HAS A SLOPE OF THE NEGATIVE RECIPRICAL OF THIS SLOPE. THUS THE NEW SLOPE IS(-3/2). NOW SUBSTITUTE THE POINTS THROUGH WHICH THIS NEW LINE PASES (4,2) FOR THE X & Y VALUES IN THE EQUATION ---- Y=mX+b WHERE (m=SLOPE) & SOLVE FOR THE Y INTERCEPT (b) THUS: 2=-3/2*4+b 2=-12/2+b 2=-6+b 2+6=b 8=b WHICH IS THE Y INTERCEPT OF THE NEW LINE. THUS THE EQUATION OF THIS LINE IS Y=-3/2X+8
 Equations/68363: This question is from textbook An Incremental Development please help to multiply (2x + 4)(3x^2 - 2x - 10)1 solutions Answer 48625 by checkley71(8403)   on 2007-01-28 16:48:32 (Show Source): You can put this solution on YOUR website!3X^2-2X-10 2X+4 -------------------------------- 6X^3-4X^2-20X+12X^2-8X-40 NO COMBINE LIKE TERMS THUS: 6X^3+8X^2-28X-40 NOW FACTOR OUT 2 2(3X^3+4X^2-14X-20)
 Quadratic_Equations/68364: This question is from textbook An Incremental Development PLease help to evaluate : x^2 - x^3y - xy if x = -1/2 and y = -1/41 solutions Answer 48624 by checkley71(8403)   on 2007-01-28 16:44:50 (Show Source): You can put this solution on YOUR website!X^2-X^3Y-XY (-1/2)^2-(-1/2^3*-1/4)-(-1/2*-1/4) 1/4-(-1/8*-1/4)-(1/8) 1/4-(1/32)-1/8 1/4-1/32-1/8 TO ADD THESE FRACTION YOU NEED TO FIND A COMMON DENOMINATOR (32 WORKS BECAUSE 4 & 8 ARE FACTORS OF 32) (1*8-1*1-1*4)/32 (8-1-4)/32 3/32
 Polynomials-and-rational-expressions/68230: multiply (x + 2y)^41 solutions Answer 48588 by checkley71(8403)   on 2007-01-28 08:26:33 (Show Source): You can put this solution on YOUR website!X+2Y X+2Y ------------- X^2+4XY+4Y^2 X+2Y -------------- X^3+4X^2Y+4XY^2+2X^2Y+8XY^2+8Y^3 X+2Y ------------------------------------ X^4+4X^3Y+4X^2Y^2+2X^3Y+8X^2Y^2+8XY^3+2X^3Y+8X^2Y^2+8XY^3+4X^2Y^2+16XY^3+16Y^4 X^4+(4X^3Y+2X^3Y+2X^3Y)+(4X^2Y^2+8X^2Y^2+8X^2Y^2+4X^2Y^2)+(8XY^3+8XY^3+16XY^3) +16Y^4 X^4+8X^3Y+24X^2Y^2+32XY^3+16Y^4 --------------------------------------------------------------------------- HOPE YOU CAN FOLLOW THIS PROCESS!!!!!! HAPPY MATHING : )
 Graphs/68295: Find the slope of the line passing through the points (–9, –4) and (0, –4). Thanks!1 solutions Answer 48584 by checkley71(8403)   on 2007-01-28 08:03:22 (Show Source): You can put this solution on YOUR website!SLOPE=(Y2-Y1)/X2-X1) (-4+4)/(0+9) 0/9 REPRESENTS A VERTICLE LINE PASSING THROUGH Y=-4 Y=-4 IS THE FORMULA FOR THIS LINE. (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -4).
 Graphs/68291: Which of the ordered pairs (3, 1), (0, –4), (–4, 0), (–3, –7) are solutions for the equation x – y = 4? Thanks! 1 solutions Answer 48583 by checkley71(8403)   on 2007-01-28 07:58:48 (Show Source): You can put this solution on YOUR website!(0,-4) & (-3,-7) ARE SOLUTIONS 0-(-4)=4 0+4=4 4=4 -------------- -3-(-7)=4 -3+7=4 4=4
 Graphs/68290: I could really use some help. Thanks! Angela Find the slope of the line passing through the points (–8, –3) and (–2, 2).1 solutions Answer 48581 by checkley71(8403)   on 2007-01-28 07:56:11 (Show Source): You can put this solution on YOUR website!SLOPE=(Y2-Y1)/(X2-X1) (2+3)/(-2+8) 5/6 IS THE SLOPE OF A LINE THROUGH THESE TWO POINTS.
 Miscellaneous_Word_Problems/68272: This question is from textbook An Incremental Development How many different ways can the letters, M, A, T and H be arranged in order if no repeition is permitted?1 solutions Answer 48556 by checkley71(8403)   on 2007-01-27 20:25:07 (Show Source): You can put this solution on YOUR website!4*3*2*1=24 different arrangements without repeititions.
 Graphs/68273: This question is from textbook An Incremental Development Please help to graph on a rectangular coordinate system x + 3y + 6 = 01 solutions Answer 48555 by checkley71(8403)   on 2007-01-27 20:23:28 (Show Source): You can put this solution on YOUR website!x=3y+6=0 3y=-x-6 y=-x/3-6/3 y=-x/3-2 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -x/3 -2).
 Graphs/68022: Given a line containing the points (1,4), (2,7), and (3,10) determine the slope-intercept form of the equation, provide one additional point on this line, and graph the function. 1 solutions Answer 48550 by checkley71(8403)   on 2007-01-27 18:13:16 (Show Source): You can put this solution on YOUR website!(1,4)(2,7),(3/100 IS A LINE WITH A SLOPE OF --- (10-4)/3-1) 6/2=3 FOR THE SLOPE. NOW REPLACE THE X & Y UNKNOWNS & THE SLOPE (m)IN THE FORMULA Y=mX+b & FIND THE Y INTERCEPT. 4=3*1+b 4=3+b b=4-3 Y=1 THEREFORE THE FORMULA IS Y=3X+1 (graph 300x200 pixels, x from -3 to 4, y from -5 to 5, Y = 3X +1).
 Linear-systems/68023: how to find 5(2x-6)+2=2x+x1 solutions Answer 48546 by checkley71(8403)   on 2007-01-27 18:04:57 (Show Source): You can put this solution on YOUR website!5(2X-6)+2=2X+X 10X-30+2=3X 10X-3X=30-2 7X=28 X=28/7 X=4 ANSWER PROOF 5(2*4-6)+2=2*4+4 5(8-6)+2=8+4 5*2+2=12 10=2=12 12=12
 absolute-value/68042: Solve. 6(2-x)=4x1 solutions Answer 48544 by checkley71(8403)   on 2007-01-27 18:00:32 (Show Source): You can put this solution on YOUR website!6(2-X)=4X 12-6X=4X -6X-4X=-12 -10X=-12 X=-12/-10 X=6/5
 Proportions/68066: a - 3 3 ------ = - 8 41 solutions Answer 48542 by checkley71(8403)   on 2007-01-27 17:54:13 (Show Source): You can put this solution on YOUR website!(A-3)/8=3/4 CROSS MULTIPLY 4(A-3)=8*3 4A-12=24 4A=24+12 4A=36 A=36/4 A=9 ANSWER PROOF (9-3)/8=3/4 6/8=3/4 CROSS MULTIPLY 24=24
 Linear-equations/68088: X raised to the third plus 641 solutions Answer 48541 by checkley71(8403)   on 2007-01-27 17:49:52 (Show Source): You can put this solution on YOUR website!x^3+64=0 if this is what you mean then: x^3=-64 x=-4
 Polynomials-and-rational-expressions/68237: factor: 6x^2+11x+151 solutions Answer 48539 by checkley71(8403)   on 2007-01-27 17:45:07 (Show Source): You can put this solution on YOUR website!6x^2+11x+15using the quadratic equation we get x=(-b+-sqrt[b^2-4ac])/2a x=(-11+-sqrt[11^2-4*6*15])/2*6 x=(-11+-sqrt[121-360])/12 x=(-11+-sqrt-239)/12 x=(-11+-[-15.4596i])/12 x=(-11-15.4596i)/12 x=(-11/12)-15.4596i/12 x=-.916666-1.2883i x=-.916666+1.2883i
 Polynomials-and-rational-expressions/68234: Find the following product. (3x - 4) (x^2 - 2x + 3)1 solutions Answer 48538 by checkley71(8403)   on 2007-01-27 17:36:52 (Show Source): You can put this solution on YOUR website!(3x-4)(x^2-2x+3) 3x^3-6x^2+9x-4x^2+8x-12 3x^3-10x^2+17x-12
 Graphs/68236: I don't know how to graph two equations to find the breaking point. C=25+x*0.24 and C=31+x*0.19 I have to graph these points to find the breaking point and I am stuck..How do I do this? Thanks Brandi 1 solutions Answer 48537 by checkley71(8403)   on 2007-01-27 17:32:20 (Show Source): You can put this solution on YOUR website!CREATE LINE FORMUILAS FOR EACH EQUATION THUS Y=25+.24X & Y=31+.19X Y=.24X+25 & Y=.19X+31 NOW GRAPH THEM (graph 600x400 pixels, x from -6 to 5, y from -10 to 35, of TWO functions y = .24x +25, y = .19x + 31).
 absolute-value/68199: Solve: 5x/7 – 6x/5 = 3/35 1 solutions Answer 48535 by checkley71(8403)   on 2007-01-27 17:09:35 (Show Source): You can put this solution on YOUR website!5X/7-6X/5=3/35 FIND A COMMON DENOMINATOR FOR THE LEFT SIDE FRACTIONS THUS (7*5=35) (5X*5-6X*7)/35=3/35 (25X-42X)/35=3/35 -7X/35=3/35 -7X=3 X=3/-7 X=-3/7
 Expressions-with-variables/68201: Which expression describes the sequence below, when 'n' is the position in the sequence? 3, 8, 13, 18, .... a) 5n + 3 b) 5n - 2 c) 2n + 1 d) n + 21 solutions Answer 48533 by checkley71(8403)   on 2007-01-27 17:05:16 (Show Source): You can put this solution on YOUR website!THE ANSWER IS B) 5*1-2=3 5*2-2=8 5*3-2=13 5*4-2=18
 Inverses/68208: This question is from textbook I need help with problem 43 in chapter 2 section 3. The problem is x+7/6=2x-7/61 solutions Answer 48532 by checkley71(8403)   on 2007-01-27 17:02:32 (Show Source): You can put this solution on YOUR website!X+7/6=2X-7/6 X-2X=-7/6-7/6 -X=-14/6 X=14/6 X=2 2/6
 Polynomials-and-rational-expressions/68228: The cost, y, of growing special oranges in dollar as a function of the number of oranges, n, is given by y = 0.7n + 20.34 Make a plot of the above equation. What is the cost of growing 50 special oranges?1 solutions Answer 48530 by checkley71(8403)   on 2007-01-27 17:00:30 (Show Source): You can put this solution on YOUR website!Y=.7N+20.34 FOR 50 SPECIAL ORANGES WE SUBSTITUTE 50 FOR N THUS Y=.7*50+20.34 Y=35+20.34 Y=55.34
 Polynomials-and-rational-expressions/68229: The speed of light in vacuum is one hundred eighty six thousand miles per second. Write the speed of light in scientific notation.1 solutions Answer 48528 by checkley71(8403)   on 2007-01-27 16:56:33 (Show Source): You can put this solution on YOUR website!186,000 MPS 1.86*10^5
 Polynomials-and-rational-expressions/68235: Find the following product. (0.3x + 0.2) (0.3x - 0.2)1 solutions Answer 48527 by checkley71(8403)   on 2007-01-27 16:54:45 (Show Source): You can put this solution on YOUR website!(.3X+.2)(.3X-.2) USE THE "FOIL" PROCESS .09X^2+.06X-.06X-.04 .09X^2-.04
 Polynomials-and-rational-expressions/68213: Please help me solve this equation: 1 solutions Answer 48517 by checkley71(8403)   on 2007-01-27 13:52:23 (Show Source): You can put this solution on YOUR website![(2/9)-(2/5)]/(3+3/5) [(2*5-2*9)/45]/(18/5) (10-18/45)/(18/5) (-8/45)/18/5 (-8*5)/(45*18) -40/810 -4/81
 Linear-equations/68218: This question is from textbook x/5-x/4=11 solutions Answer 48516 by checkley71(8403)   on 2007-01-27 13:43:51 (Show Source): You can put this solution on YOUR website!x/5-x/4=1 NOW FIND THE COMMON DENOMINATOR (4*5=20) (4x-5x)/20=1 4x-5x=20 -x=20 x=-20 answer proof -20/5-(-20)/4=1 -4+5=1 1=1