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Linear-equations/68354: how do i work this out??
A bus leaves a station at 1 P.M., traveling west at an average
rate of 44 mi/h. One hour later a second bus leaves the same station, traveling
east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
1 solutions

Answer 48632 by checkley71(8403) About Me  on 2007-01-28 17:35:00 (Show Source):
You can put this solution on YOUR website!
44*X+48(X-1)=274
44X+48X-48=274
92X=274+48
92X=322
X=322/92
X=3.5 HOURS AFTER 1 PM = 4:30 PM THE 2 BUSES WILL BE 274 MILES APART.


Linear-equations/68356: how can i work this out?
The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field.
1 solutions

Answer 48631 by checkley71(8403) About Me  on 2007-01-28 17:29:59 (Show Source):
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LENGTH=2W-5 & W=WIDTH. THUS
2(2W-5)+2W=230
4W-10+2W=230
6W=230+10
6W=240
W=240/6
W=40 ANSWER FOR THE WIDTH
LENGTH=2*24-5
LENGTH=48-5
LENGTH=43
PROOF
2(2*40-5)+2*40=230
2(80-5)+80=230
2*75+80=230
150+80=230
230=230


Polynomials-and-rational-expressions/68361: This question is from textbook An Incremental Development
please help to solve by factoring
-5x - 6 = -6x^2
1 solutions

Answer 48630 by checkley71(8403) About Me  on 2007-01-28 17:22:33 (Show Source):
You can put this solution on YOUR website!
-5X-6=-6X^2
6X^2-5X-6=0
(3X+2)(2X-3)=0
3X+2=0
3X=-2
X=-2/3 ANSWER
2X-3=0
2X=3
X=2/3 ANSWER


Geometry_Word_Problems/68362: please help me with this
Two angles are complementary if their sum of their measures is 90 degrees.

1 solutions


Answer 48629 by checkley71(8403) About Me  on 2007-01-28 17:14:31 (Show Source):
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ANY TWO ANGLES THAT ADD UP TO 90 DEGREES ARE COMPLEMENTARY & FORM A RIGHT ANGLE THUS:
30 DEGREES + 60 DEGREES = 90 DEGREES ( A RIGHT ANGLE)
42 DEGREES + 48 DEGREES = 90 DEGREES
6 DEGREES + 84 DEGREES =90 DEGREES
24 DEGREES + 66 DEGREES = 90 DEGREES


Quadratic_Equations/68371: This question is from textbook An Incremental Development
Please help to solve using the quadratic formula :
-3x^2 - 4 = 2x
1 solutions

Answer 48628 by checkley71(8403) About Me  on 2007-01-28 17:10:35 (Show Source):
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-3X^2-2X-4=0
X=(-B+-SQRT[B^2-4AC])/2A
X=(2+-SQRT[4-4*-3*-4])/2*-3
x=(2+-sqrt[4-48])/6
x=(2+-sqrt-44)/6
x=(2+-6.63325i)/6
x=2/6+6.63325i/6
x=.33333+1.10554i answer
x=2/6-6.63325i/6
x=.3333-1.10554i answer
----------------------------------
happy manipulating :)


Length-and-distance/68374: This question is from textbook An Incremental Development
use the distance formula to find the distance between (5,-2) and (-3,3)
1 solutions

Answer 48627 by checkley71(8403) About Me  on 2007-01-28 17:01:50 (Show Source):
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DISTANCE^2=(5-[-3])^2+(3-[-2])^2
D^2=(5+3)^2+(3+2)^2
D^2=8^2+5^2
D^2=64+25
D^2=89
D=SQRT89
D=9.434 IS THE DISTANCE BETWEEN THESE POINTS (HYPOTENUSE OF A RIGHT TRIANGLE)


Quadratic_Equations/68373: This question is from textbook An Incremental Development
Find the equation of the line that passes through (4,2) and is perpendicular to the line 3y - 2x = 5
1 solutions

Answer 48626 by checkley71(8403) About Me  on 2007-01-28 16:55:56 (Show Source):
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3Y-2X=5
3Y=2X+5
Y=2X/3+5/3 THUS THIS LINE HAS A SLOPE OF (2/3) & A LINE PERPENDICULAR TO THIS LINE THEN HAS A SLOPE OF THE NEGATIVE RECIPRICAL OF THIS SLOPE. THUS THE NEW SLOPE IS(-3/2). NOW SUBSTITUTE THE POINTS THROUGH WHICH THIS NEW LINE PASES (4,2) FOR THE X & Y VALUES IN THE EQUATION ----
Y=mX+b WHERE (m=SLOPE) & SOLVE FOR THE Y INTERCEPT (b) THUS:
2=-3/2*4+b
2=-12/2+b
2=-6+b
2+6=b
8=b WHICH IS THE Y INTERCEPT OF THE NEW LINE. THUS THE EQUATION OF THIS LINE IS
Y=-3/2X+8


Equations/68363: This question is from textbook An Incremental Development
please help to multiply
(2x + 4)(3x^2 - 2x - 10)
1 solutions

Answer 48625 by checkley71(8403) About Me  on 2007-01-28 16:48:32 (Show Source):
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3X^2-2X-10
2X+4
--------------------------------
6X^3-4X^2-20X+12X^2-8X-40 NO COMBINE LIKE TERMS THUS:
6X^3+8X^2-28X-40 NOW FACTOR OUT 2
2(3X^3+4X^2-14X-20)


Quadratic_Equations/68364: This question is from textbook An Incremental Development
PLease help to evaluate :
x^2 - x^3y - xy if x = -1/2 and y = -1/4
1 solutions

Answer 48624 by checkley71(8403) About Me  on 2007-01-28 16:44:50 (Show Source):
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X^2-X^3Y-XY
(-1/2)^2-(-1/2^3*-1/4)-(-1/2*-1/4)
1/4-(-1/8*-1/4)-(1/8)
1/4-(1/32)-1/8
1/4-1/32-1/8 TO ADD THESE FRACTION YOU NEED TO FIND A COMMON DENOMINATOR
(32 WORKS BECAUSE 4 & 8 ARE FACTORS OF 32)
(1*8-1*1-1*4)/32
(8-1-4)/32
3/32


Polynomials-and-rational-expressions/68230: multiply (x + 2y)^4
1 solutions

Answer 48588 by checkley71(8403) About Me  on 2007-01-28 08:26:33 (Show Source):
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X+2Y
X+2Y
-------------
X^2+4XY+4Y^2
X+2Y
--------------
X^3+4X^2Y+4XY^2+2X^2Y+8XY^2+8Y^3
X+2Y
------------------------------------
X^4+4X^3Y+4X^2Y^2+2X^3Y+8X^2Y^2+8XY^3+2X^3Y+8X^2Y^2+8XY^3+4X^2Y^2+16XY^3+16Y^4
X^4+(4X^3Y+2X^3Y+2X^3Y)+(4X^2Y^2+8X^2Y^2+8X^2Y^2+4X^2Y^2)+(8XY^3+8XY^3+16XY^3)
+16Y^4
X^4+8X^3Y+24X^2Y^2+32XY^3+16Y^4
---------------------------------------------------------------------------
HOPE YOU CAN FOLLOW THIS PROCESS!!!!!!
HAPPY MATHING : )


Graphs/68295: Find the slope of the line passing through the points (–9, –4) and (0, –4).
Thanks!
1 solutions

Answer 48584 by checkley71(8403) About Me  on 2007-01-28 08:03:22 (Show Source):
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SLOPE=(Y2-Y1)/X2-X1)
(-4+4)/(0+9)
0/9 REPRESENTS A VERTICLE LINE PASSING THROUGH Y=-4
Y=-4 IS THE FORMULA FOR THIS LINE.
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-4%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -4).


Graphs/68291: Which of the ordered pairs
(3, 1), (0, –4), (–4, 0), (–3, –7)
are solutions for the equation x – y = 4?

Thanks!

1 solutions

Answer 48583 by checkley71(8403) About Me  on 2007-01-28 07:58:48 (Show Source):
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(0,-4) & (-3,-7) ARE SOLUTIONS
0-(-4)=4
0+4=4
4=4
--------------
-3-(-7)=4
-3+7=4
4=4


Graphs/68290: I could really use some help. Thanks!
Angela

Find the slope of the line passing through the points (–8, –3) and (–2, 2).
1 solutions

Answer 48581 by checkley71(8403) About Me  on 2007-01-28 07:56:11 (Show Source):
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SLOPE=(Y2-Y1)/(X2-X1)
(2+3)/(-2+8)
5/6 IS THE SLOPE OF A LINE THROUGH THESE TWO POINTS.


Miscellaneous_Word_Problems/68272: This question is from textbook An Incremental Development
How many different ways can the letters, M, A, T and H be arranged in order if no repeition is permitted?
1 solutions

Answer 48556 by checkley71(8403) About Me  on 2007-01-27 20:25:07 (Show Source):
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4*3*2*1=24 different arrangements without repeititions.


Graphs/68273: This question is from textbook An Incremental Development
Please help to graph on a rectangular coordinate system
x + 3y + 6 = 0
1 solutions

Answer 48555 by checkley71(8403) About Me  on 2007-01-27 20:23:28 (Show Source):
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x=3y+6=0
3y=-x-6
y=-x/3-6/3
y=-x/3-2
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-x%2F3+-2%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -x/3 -2).


Graphs/68022: Given a line containing the points (1,4), (2,7), and (3,10) determine the slope-intercept form of the equation, provide one additional point on this line, and graph the function.
1 solutions

Answer 48550 by checkley71(8403) About Me  on 2007-01-27 18:13:16 (Show Source):
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(1,4)(2,7),(3/100 IS A LINE WITH A SLOPE OF ---
(10-4)/3-1)
6/2=3 FOR THE SLOPE.
NOW REPLACE THE X & Y UNKNOWNS & THE SLOPE (m)IN THE FORMULA Y=mX+b & FIND THE Y INTERCEPT.
4=3*1+b
4=3+b
b=4-3
Y=1
THEREFORE THE FORMULA IS
Y=3X+1
+graph%28+300%2C+200%2C+-3%2C+4%2C+-5%2C+5%2C+y+=+3x+%2B1%29+ (graph 300x200 pixels, x from -3 to 4, y from -5 to 5, Y = 3X +1).


Linear-systems/68023: how to find 5(2x-6)+2=2x+x
1 solutions

Answer 48546 by checkley71(8403) About Me  on 2007-01-27 18:04:57 (Show Source):
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5(2X-6)+2=2X+X
10X-30+2=3X
10X-3X=30-2
7X=28
X=28/7
X=4 ANSWER
PROOF
5(2*4-6)+2=2*4+4
5(8-6)+2=8+4
5*2+2=12
10=2=12
12=12


absolute-value/68042: Solve.
6(2-x)=4x
1 solutions

Answer 48544 by checkley71(8403) About Me  on 2007-01-27 18:00:32 (Show Source):
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6(2-X)=4X
12-6X=4X
-6X-4X=-12
-10X=-12
X=-12/-10
X=6/5


Proportions/68066: a - 3 3
------ = -
8 4
1 solutions

Answer 48542 by checkley71(8403) About Me  on 2007-01-27 17:54:13 (Show Source):
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(A-3)/8=3/4 CROSS MULTIPLY
4(A-3)=8*3
4A-12=24
4A=24+12
4A=36
A=36/4
A=9 ANSWER
PROOF
(9-3)/8=3/4
6/8=3/4 CROSS MULTIPLY
24=24


Linear-equations/68088: X raised to the third plus 64
1 solutions

Answer 48541 by checkley71(8403) About Me  on 2007-01-27 17:49:52 (Show Source):
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x^3+64=0 if this is what you mean then:
x^3=-64
x=-4


Polynomials-and-rational-expressions/68237: factor: 6x^2+11x+15
1 solutions

Answer 48539 by checkley71(8403) About Me  on 2007-01-27 17:45:07 (Show Source):
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6x^2+11x+15using the quadratic equation we get
x=(-b+-sqrt[b^2-4ac])/2a
x=(-11+-sqrt[11^2-4*6*15])/2*6
x=(-11+-sqrt[121-360])/12
x=(-11+-sqrt-239)/12
x=(-11+-[-15.4596i])/12
x=(-11-15.4596i)/12
x=(-11/12)-15.4596i/12
x=-.916666-1.2883i
x=-.916666+1.2883i


Polynomials-and-rational-expressions/68234: Find the following product.
(3x - 4) (x^2 - 2x + 3)
1 solutions

Answer 48538 by checkley71(8403) About Me  on 2007-01-27 17:36:52 (Show Source):
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(3x-4)(x^2-2x+3)
3x^3-6x^2+9x-4x^2+8x-12
3x^3-10x^2+17x-12


Graphs/68236: I don't know how to graph two equations to find the breaking point.
C=25+x*0.24 and C=31+x*0.19
I have to graph these points to find the breaking point and I am stuck..How do I do this?
Thanks Brandi

1 solutions

Answer 48537 by checkley71(8403) About Me  on 2007-01-27 17:32:20 (Show Source):
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CREATE LINE FORMUILAS FOR EACH EQUATION THUS
Y=25+.24X & Y=31+.19X
Y=.24X+25 & Y=.19X+31
NOW GRAPH THEM
+graph%28+600%2C+400%2C+-6%2C+5%2C+-10%2C+35%2C+y+=+.24x+%2B25%2C+y+=+.19x+%2B31%29+ (graph 600x400 pixels, x from -6 to 5, y from -10 to 35, of TWO functions y = .24x +25, y = .19x + 31).


absolute-value/68199: Solve:
5x/7 – 6x/5 = 3/35
1 solutions

Answer 48535 by checkley71(8403) About Me  on 2007-01-27 17:09:35 (Show Source):
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5X/7-6X/5=3/35 FIND A COMMON DENOMINATOR FOR THE LEFT SIDE FRACTIONS THUS (7*5=35)
(5X*5-6X*7)/35=3/35
(25X-42X)/35=3/35
-7X/35=3/35
-7X=3
X=3/-7
X=-3/7


Expressions-with-variables/68201: Which expression describes the sequence below, when 'n' is the position in the sequence?
3, 8, 13, 18, ....
a) 5n + 3
b) 5n - 2
c) 2n + 1
d) n + 2
1 solutions

Answer 48533 by checkley71(8403) About Me  on 2007-01-27 17:05:16 (Show Source):
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THE ANSWER IS B)
5*1-2=3
5*2-2=8
5*3-2=13
5*4-2=18


Inverses/68208: This question is from textbook
I need help with problem 43 in chapter 2 section 3.
The problem is x+7/6=2x-7/6
1 solutions

Answer 48532 by checkley71(8403) About Me  on 2007-01-27 17:02:32 (Show Source):
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X+7/6=2X-7/6
X-2X=-7/6-7/6
-X=-14/6
X=14/6
X=2 2/6


Polynomials-and-rational-expressions/68228: The cost, y, of growing special oranges in dollar as a function of the number of oranges, n, is given by
y = 0.7n + 20.34
Make a plot of the above equation. What is the cost of growing 50 special oranges?
1 solutions

Answer 48530 by checkley71(8403) About Me  on 2007-01-27 17:00:30 (Show Source):
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Y=.7N+20.34 FOR 50 SPECIAL ORANGES WE SUBSTITUTE 50 FOR N THUS
Y=.7*50+20.34
Y=35+20.34
Y=55.34


Polynomials-and-rational-expressions/68229: The speed of light in vacuum is one hundred eighty six thousand miles per second. Write the speed of light in scientific notation.
1 solutions

Answer 48528 by checkley71(8403) About Me  on 2007-01-27 16:56:33 (Show Source):
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186,000 MPS
1.86*10^5


Polynomials-and-rational-expressions/68235: Find the following product.
(0.3x + 0.2) (0.3x - 0.2)
1 solutions

Answer 48527 by checkley71(8403) About Me  on 2007-01-27 16:54:45 (Show Source):
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(.3X+.2)(.3X-.2) USE THE "FOIL" PROCESS
.09X^2+.06X-.06X-.04
.09X^2-.04


Polynomials-and-rational-expressions/68213: Please help me solve this equation: +%282%2F9-2%2F5%29%2F%283%2B3%2F5%29

1 solutions

Answer 48517 by checkley71(8403) About Me  on 2007-01-27 13:52:23 (Show Source):
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[(2/9)-(2/5)]/(3+3/5)
[(2*5-2*9)/45]/(18/5)
(10-18/45)/(18/5)
(-8/45)/18/5
(-8*5)/(45*18)
-40/810
-4/81


Linear-equations/68218: This question is from textbook
x/5-x/4=1
1 solutions

Answer 48516 by checkley71(8403) About Me  on 2007-01-27 13:43:51 (Show Source):
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x/5-x/4=1 NOW FIND THE COMMON DENOMINATOR (4*5=20)
(4x-5x)/20=1
4x-5x=20
-x=20
x=-20 answer
proof
-20/5-(-20)/4=1
-4+5=1
1=1