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# Recent problems solved by 'checkley71'

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 Parallelograms/95687: OK. I am given a parallelogram on a graph with no points and I am asked to find the perimeter of this parallelogram. How do I find the perimeter of this graphed parallelogram?1 solutions Answer 69709 by checkley71(8403)   on 2007-09-02 16:25:32 (Show Source): You can put this solution on YOUR website!FIRST YOU NEED TO IDENTIFY ALL THE CORNER POINTS. THEN FIND THE DISTANCE BETWEEN THEM USING THE PYTHAGOREON THEORUM (A^2+B^2=C^2) AS EACH SET OF POINTS FORM A RIGHT TRIANGLE. THE DISTANCE IS THE HYPOTENUSE OF THESE TRIANGLES (C). ONCE YOU'VE FOUND THE LENGTH OF THE TWO PARALLEL SIDES JUST ADD THEM FOR THE PERIMETER.
 Equations/95691: Please help. Solve 2/5x=-101 solutions Answer 69708 by checkley71(8403)   on 2007-09-02 16:21:47 (Show Source): You can put this solution on YOUR website!IF YOU MEAN (2/5)X=-10 THEN: 2X/5=-10 NOW CROSS MULTIPLY 2X=-50 X=-50/2 X=-25 ANSWER. PROOF (2/5)-25=-10 -50/5=-10 -10=-10
 Graphs/95639: Please help. Add 3 1/5+2 1/4= Thank you.1 solutions Answer 69707 by checkley71(8403)   on 2007-09-02 16:19:39 (Show Source): You can put this solution on YOUR website!THERE'S AN EASY WAY & A TOUGH WAY TO SOLVE THESE TYPE OF PROBLEM. THE EASY WAY IS TO CONVERT THE MIXED NUMBERS TO DECIMALS.THUS: 3.2+2.25=5.45 OR YOU CAN GO THE FRACTIONAL ROUTE. THUS; 16/5+9/4 NOW FIND A COMMON DENOMINATOR. HERE WE HAVE 20. (16*4+9*5)/20=(64+45)/20=109/20=5 9/20. TAKE YOUR PICK!!!!!!!!!!
 Mixture_Word_Problems/95688: dear algebra tutors, this baby has stumped me - the 23% confuses me. one thousand quarts of milk testing 4% butterfat are to be reduced to 3%. how many quarts of cream testing 23% must be separated from the milk to produce the required? all percents are by volume. thank you!1 solutions Answer 69706 by checkley71(8403)   on 2007-09-02 16:14:29 (Show Source): You can put this solution on YOUR website!1000*.04-.23x=.03(1000-x) 40-.23x=30-.03x 40-30=.23x-.03x 10=.2x x=10/.2 x=50 quarts of 23% must be removed. proof 1000*.04-.23*50=.03(1000-50) 40-11.5=30-1.5 28.5=28.5
 Exponents/95690: 1.how do i write the exponets of x*x*y*y*y? is it x2 y3? 2.how do i write the exponets of a/b*a/b*c/d*c/d*c/d?1 solutions Answer 69704 by checkley71(8403)   on 2007-09-02 16:09:23 (Show Source): You can put this solution on YOUR website!x*x*y*y*y=x^2y^3 Correct! a/b*a/b*c/d*c/d*c/d=(a/b)^2(c/d)^3 This is exactly the same problem as the x*y problem only with fractions. Don't let fractions confuse you. Treat them like any other term or number.
 Graphs/95689: How do I write an equation of a line with a slope of -2 and y interecept (0,0). Thanks1 solutions Answer 69703 by checkley71(8403)   on 2007-09-02 16:03:46 (Show Source): You can put this solution on YOUR website!Y=mX+b WHERE (m)=SLOPE & (b)=THE Y INTERCEPT Y=-2X HERE THE SLOPE (m)=-2 & THE Y INTERCEPT(b)=0 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -2x).
 Human-and-algebraic-language/95685: Please Help! The question is: The Sum of two numbers is 25. Tweleve less than four times one of the numbers is 16 more than twice the other number. Find both numbers. I tried figuring it out, but I got that 12&39=25, which is not possible. Please help!1 solutions Answer 69702 by checkley71(8403)   on 2007-09-02 16:00:40 (Show Source): You can put this solution on YOUR website!X+Y=25 OR X=25-Y 4X-12=2Y+16 NOW SUBSTITUTE (25-Y) FOR X IN THE SECOND EQUATION & SOLVE FOR Y: 4(25-Y)-12=2Y+16 100-4Y-12=2Y+16 100-16-12=2Y+4Y 6Y=72 Y=72/6 Y=12 FOR ONE NUMBER. X+12=25 X=25-12 X=13 FOR THE SECOND NUMBER PROOF 4*13-12=2*12+16 52-12=24+16 40=40
 Average/95683: explain why there is no value of x for which the expressions x + 3 and x + 4 are equal? My 7th grade son has this question on one of his worksheets and sadly I am unable to help him. Thanks so much in advance for your help1 solutions Answer 69700 by checkley71(8403)   on 2007-09-02 15:45:04 (Show Source): You can put this solution on YOUR website!X+3=X+4 X-X=4-3 0=-1 SAYS THAT THERE IS NO SOLUTION TO THIS PROBLEM. ALSO: NO NUMBER INCREASED BY 3 CAN BE EQUAL TO THE SAME NUMBER INCREASED BY 4!
 Linear-equations/95643: Susan purchased municipal bonds which yield 7% annually and certificates of deposit which yield 8% annually. If Susan's initial investment amounts to \$18,000 and the annual income is \$1380, how much money is invested in bonds and how much is invested in certificates of deposit?1 solutions Answer 69699 by checkley71(8403)   on 2007-09-02 15:41:46 (Show Source): You can put this solution on YOUR website!.08*X+.07(18000-X)=1380 .08X+1260-.07X=1380 .01X=1380-1260 .01X=120 X=120/.01 X=12000 INVESTED IN CERTIFICATES. 18000-12000=6000 INMVESTED IN BONDS. PROOF 12000*.08+6000*.07=1380 960+420=1380 1380=1380
 Finance/95665: Mr.Smith had \$3000 invested at 5% per year. How much must he invest at 6% in order to make his total annual income \$300?1 solutions Answer 69696 by checkley71(8403)   on 2007-09-02 15:33:39 (Show Source): You can put this solution on YOUR website!3000*.05+X*.06=300 150+.06X=300 .06X=300-150 .06X=150 X-150/.06 X=\$2500 MUST BE ADDED @ 6% TO GET \$300 INTEREST PER YEAR. PROOF 3000*.05+2500*.06=300 150+150=300 300=300
 Radicals/95682: Simplify the radical expression. ^3RT(x^8) (cube root of X to the eighth power) sorry my question wasn't clear the first time. thanks!!1 solutions Answer 69694 by checkley71(8403)   on 2007-09-02 15:29:20 (Show Source): You can put this solution on YOUR website!CUBERTX^8=CUBERT(X^3)(X^3)(X^2)=X*XCUBERTX^2=X^2CUBERTX^2
 Equations/95680: I am stuck with this problem. Please help. The length of one of the equal legs of an isosceles triangle is 8cm less than 4 times the length of the base. If the perimeter is 29cm, find the lengths of the equal legs. 1 solutions Answer 69692 by checkley71(8403)   on 2007-09-02 15:26:17 (Show Source): You can put this solution on YOUR website!2(4X-8)+X=29 8X-16+X=29 9X=29+16 9X=45 X=45/9 X=5 ANSWER FOR THE BASE. 4*5-8=20-8=12 FOR THE EQUAL SIDES. PROOF 2(4*5-8)+5=29 2(20-8)+5=29 2*12+5=29 24+5=29 29=29
 Polynomials-and-rational-expressions/95669: Determine the solutions for the following polynomial. 9x^5 - 21x^4 = 0 1 solutions Answer 69690 by checkley71(8403)   on 2007-09-02 15:18:03 (Show Source): You can put this solution on YOUR website!9X^5-21X^4=0 X^4(9X-21)=0 3X^4(3X-7)=0 3X^4=0 X=0 ANSWER. 3X-7=0 3X=7 X=7/3 ANSWER.
 Polynomials-and-rational-expressions/95672: The square of a number added to the original number is 72. Determine all possible values of the number.1 solutions Answer 69689 by checkley71(8403)   on 2007-09-02 15:14:15 (Show Source): You can put this solution on YOUR website!X+X^2=72 X^2+X-72=0 (X+9)(X-8)=0 X-8=0 X=8 ANSWER. PROOF 8+8*8=72 8+64=72 72=72
 Radicals/95674: Simplify the radical expression. 3√x81 solutions Answer 69688 by checkley71(8403)   on 2007-09-02 15:11:03 (Show Source): You can put this solution on YOUR website!IF THE PROBLEM IS- 3SQRTX^8 THEN: 3*X^4=3X^4
 Linear-systems/95580: y=2x-11 solutions Answer 69619 by checkley71(8403)   on 2007-09-01 19:09:25 (Show Source): You can put this solution on YOUR website!IF THIS IS A LINE EQUATION . THEN: (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 2x -1). IT HAS A SLOPE(m) OF 2 & A Y INTERCEPT (b) OF -1
 Equations/95582: This question is from textbook A man left an estate of \$64,000 to three children. the eldest child recieved three times as much as the youngest. the middle child received \$14,000 more than the youngest. how much did each child recieve. we know that e=3y m=y + 14000 m + y + e= 64000 and now i'm not sure how to set up the problem...please help1 solutions Answer 69618 by checkley71(8403)   on 2007-09-01 19:06:18 (Show Source): You can put this solution on YOUR website!E=3Y M+Y+3Y=64000 M+4Y=64000 (Y+14000)+4Y=64000 Y+14000+4Y=64000 5Y=64000-14000 5Y=50000 Y=50000/5 Y=10000 AMOUNT GIVEN TO THE YOUNGEST. E=3*10000=30000 FOR THE ELDEST M+4*10000=64000 M+40000=64000 M=64000-40000 M=24000 AMOUNT GIVEN TO THE MIDDLE CHILD. PROOF 10,000+30000+24000=64000 64000=64000
 Equations/95581: This question is from textbook this is probably a simple problem but i'm making it to hard. Directions: write an expression in terms of the given variable that represents the indicated quantity Problem: the sum of 3 consecutive odd natural numbers if the least is x.1 solutions Answer 69617 by checkley71(8403)   on 2007-09-01 18:59:14 (Show Source): You can put this solution on YOUR website!X+(X+2)+(X+4)
 Polynomials-and-rational-expressions/95456: Simplify the rational expression 21-7x/18-6x1 solutions Answer 69616 by checkley71(8403)   on 2007-09-01 18:57:29 (Show Source): You can put this solution on YOUR website!(21-7X)/(18-6X) 7(3X-1)/6(3X-1) CANCEL OUT THE (3X-1) TERM 7/6 ANSWER.
 Equations/95579: 2/3+1/4t=1/31 solutions Answer 69614 by checkley71(8403)   on 2007-09-01 18:53:10 (Show Source): You can put this solution on YOUR website!2/3+T/4=1/3 T/4=1/3-2/3 T/4=-1/3 CROSS MULTIPLY: 3T=-4 NOW DIVIDE BOTH SIDES BY 3: T=-4/3 ANSWER. PROOF 2/3+(-4/3)/4=1/3 2/3-4/3*1/4=1/3 2/3-1/3=1/3 1/3=1/3
 Expressions-with-variables/95563: Each student is given 20 problems. Five points are awarded for each correct answer, and two points are deducted for each incorrect answer. Ellen's score was 72. How many correct answers did she have? Is this the correct way: 20(5x-2y)=721 solutions Answer 69613 by checkley71(8403)   on 2007-09-01 18:48:38 (Show Source): You can put this solution on YOUR website!NO! 5X-2(20-X)=72 5X-40+2X=72 7X=72+40 7X=112 X=112/7 X=16 CORRECT ANSWERS. 20-16=4 INCORRECT ANSWERS. PROOF 16*5-4*2=72 80-8=72 72=72.
 Distributive-associative-commutative-properties/95572: If I have 2(N sq. + 1)-3(2N sq. - 3) and I need to solve for N, how do I work the squared N? 1 solutions Answer 69612 by checkley71(8403)   on 2007-09-01 18:40:40 (Show Source): You can put this solution on YOUR website!2(n^2+1)-3(2n^2-3) 2n^2+2-6n^2+9 -4n^2+11 answer. Unless you set this equation=0. then: -4n^2+11=0 -4n^2=-11 n^2=-11/-4 n^2=11/4 n=sqrt11/4 n=sqrt2.75 n=1.683 answer.
 Polynomials-and-rational-expressions/95578: Can you please help me by showing me how to simplify this. ((3x^a y^b)^3/ (-3x^a y^b)^2 )^2 I am not sure if I am writing this properly. The problem is written as a fraction and the entire problem is squared.1 solutions Answer 69611 by checkley71(8403)   on 2007-09-01 18:34:23 (Show Source): You can put this solution on YOUR website![(3^ay^b)^3]=27(x^3a)(y^3b) [(-3x^ay^b)^2]=9(x^2a)(y^2b) [27(x^3a)(y^3b)/9(x^2a)(y^2b)]^2 [3(x^a)(y^b)]^2 9(x^2a)(y^2b) answer.
 Points-lines-and-rays/95297: This question is from textbook Two angles are complimentary. the measure of one angle is 21 more than twice the measure of the other angle. find the measures.1 solutions Answer 69610 by checkley71(8403)   on 2007-09-01 15:27:14 (Show Source): You can put this solution on YOUR website!X=FIRST ANGLE (2X+21)=THE SECOND ANGLE ANGLE1+ANGLE2=90 X+2X+21=90 3X=90-21 3X=69 X=69/3 X=23 FOR THE SMALLER ANGLE 2*23+21=46+21=67 PROOF 23+67=90 90=90