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test/100637: Decide which of the two methods for graphing lines------the intercept method or the splope intercept method-----is more appropricate for graphing the equation
4x-9=39 1 solutions
Answer 73281 by checkley71(8403) on 2007-09-26 19:28:18 (Show Source):
You can put this solution on YOUR website!4X-9=39
4X=39+9
4X=48
X=48/4
X=12 ANSWER.
FOR THIS EXAMPLE THE INTERCEPT IS BETTER AS THIS LINE IS A VERTICLE LINE THROUGH THE POINT (12,0)
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test/100640: Write the equation of the line passing through (7,4) and (14,12) 1 solutions
Answer 73279 by checkley71(8403) on 2007-09-26 19:25:17 (Show Source):
You can put this solution on YOUR website!FIRST WE FIND THE SLOPE
(Y2-Y1)/(X2-X1)=(12-4)/(14-7)=8/7 IS THE SLOPE (m).
NOW WE USE ONE SET OF (X,Y) VALUES AND THE SLOPE (m) 8/7 IN THE LINE EQUATION[Y=mX+b] & SOLVE FOR THE Y INTERCEPT (b).
4=9/8*7+b
4=63/8+b
b=4-63/8
b=(32-68)/8
b=-36/8
b=-4.5
THUS THE LINE BEQUATION IS:
Y=9X/8-4.5
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Rate-of-work-word-problems/100647: Two boats leave a ramp traveling in opposite directions. The second boat is 10 miles per hour faster than the first. After 3 hours they sre 150 miles apart. Find the speeds of the boats. 1 solutions
Answer 73275 by checkley71(8403) on 2007-09-26 19:18:46 (Show Source):
You can put this solution on YOUR website!3X+3(X+10)=150
3X+3X+30=150
6X=150-30
6X=120
X=120/6
X=20 MPH FOR THE SLOWER BOAT
20+10=30 MPH FOR THE FASTER BOAT.
PROOF
3*20+3(30)=150
60+90=150
150=150
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Rate-of-work-word-problems/100658: A triangle has a perimeter of 165 cm. The first side is 65 cm less than twice the second side. The third side is 10 cm less than the second side. Write and solve an equation to find the length of each side of the triangle. 1 solutions
Answer 73273 by checkley71(8403) on 2007-09-26 19:12:47 (Show Source):
You can put this solution on YOUR website!X=SECOND SIDE
2X-65=FIRST SIDE
X-10=THIRD SIDE
X+(2X-65)+(X-10)=165
4X-65-10=165
4X=165+75
4X=240
X=240/4
X=60 CM FOR THE SECOND SIDE.
2*60-65=120-65=55 FOR THE FIRST SIDE.
60-10=50 FOR TH E THIRD SIDE.
PROOF
60+55+50=165
165=165
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Geometry_Word_Problems/100653: How long must a guywire be to run from the top of an 18-ft pole to a point on level ground 16 ft away from the base of the pole? 1 solutions
Answer 73248 by checkley71(8403) on 2007-09-26 18:25:49 (Show Source):
You can put this solution on YOUR website!HERE YOU HAVE A RIGHT TRIANGLE WITH SIDES OF 18 7 16 FEET. THE GUYWIRE IS THE HYPOTENUSE.
USING THE PYTHAGOREON FORMULA WE GET:
18^2+16^2=H^2
324+256=H^2
580=H^2
H=SQRT580
H=24.08 FEET FOR THE GUYWIRE.
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Equations/100650: I don't understand this one: (-23)(-3) do I multiply the 2 negative numbers? 1 solutions
Answer 73244 by checkley71(8403) on 2007-09-26 18:18:19 (Show Source):
You can put this solution on YOUR website!THE RULES ARE: (+*+=+), (+*-=-), (-*-=+) & (-*+=-). OR: LIKE SIGNS WHEN MULTIPLIED=(+). UNLIKE SIGNS WHEN MULTIPLIED=(-).
THEREFORE THIS PROBLEM (-23)(-3)=+69 ANSWER.
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Rate-of-work-word-problems/100645: Two airplanes depart from an airport traveling opposite directions. The second airplane is 200 miles per hour faster than the first. After 2 hours they are 1100 miles apart. Find the speeds of the airplanes. 1 solutions
Answer 73242 by checkley71(8403) on 2007-09-26 18:12:39 (Show Source):
You can put this solution on YOUR website!2X+2(X+200)=1100
2X+2X+400=1100
4X=1100-400
4X=700
X=700/4
X=175 MPH. FOR THE SLOWER PLANE.
175+200=375 MPH FOR THE FASTER PLANE.
PROOF
2(175+375)=1100
2*550=1100
1100=1100
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Graphs/100643: This question is from textbook texas algebra 2
The problem is that i have to find the slope of each line it gives me a x and y on each side like -3x+2y=7 and i can do that one but what do i do whenever there is no x only a y the problem is y=7 and i have to find the slope what do i do ? 1 solutions
Answer 73240 by checkley71(8403) on 2007-09-26 18:06:55 (Show Source):
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test/100638: Are lines L1 through points (-3,2) and (0,4) and L2 through points (2,3) and (5,1) perpendicular? 1 solutions
Answer 73238 by checkley71(8403) on 2007-09-26 18:01:44 (Show Source):
You can put this solution on YOUR website!L1 HAS A SLOPE=(4-2)/(0+3)=2/3
L2 HAS A SLOPE=(1-3)/(5-2)=-2/3
THESE SLOPES ARE NOT NEGATIVE RECIPRICALS OF EACH OTHER. THEREFORE THE L1 & L2 LINES ARE NOT PERPENDICULAR.
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Mixture_Word_Problems/100632: this is a list of ingredients to make 16 brownies. use this list to answer both questions:
2/3 cup butter
5 squares (1 ounce ea) unsweetened chocolate
1 1/2 cups of sugar
2 teaspoons vanilla
2 eggs
1 cup flour
1. How much sugar is needed to make 8 brownies?
2. What is the greatest # of brownies that can be made if baker only has 1 cup of butter
1 solutions
Answer 73236 by checkley71(8403) on 2007-09-26 17:52:53 (Show Source):
You can put this solution on YOUR website!8/16=1.5/X CROSS MULTIPLY
8X-1.5*16
8X=24
X=3 CUPS OF SUGAR ARE REQUIRED.
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(2/3)/1=16/X
2X/3=16
2X=3*16
2X=48
X=48/2
X=24 COOKIES CAN BE MADE WITH I CUP OF BUTTER.
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Geometry_Word_Problems/100616: You are going to make a box out of cardboard. The box needs to measure 10 cm. by 5 cm. by 5 cm. 10% of the final product will be wasted in the cutting process. How much cardboard do you need???
Thanks!! 1 solutions
Answer 73234 by checkley71(8403) on 2007-09-26 17:46:55 (Show Source):
You can put this solution on YOUR website!IF THE FINAL PRODUCT IS 10X5X5.
10*15=150
2*5*5=50
THIS TOTAL SURFACE AREA IS 100+50=200.
THE 10% WASTE IS 200*.1=20 SQUARE CM. THUS THE TOTAL AREA OF THE CARDBOARD WAS:
200+20=220 SQ CM.
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Graphs/100619: Solve by graphing.Indicate wheter it is independent,inconsistent,or dependent.: y = 3x - 4
y = -2x + 1
1 solutions
Answer 73230 by checkley71(8403) on 2007-09-26 17:14:06 (Show Source):
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expressions/100614: This question is from textbook Algebra:Structure and Method
A discount store bought 12 dozen radios,each to be sold at $15 above cost. The store sold x of the radios at that price. Each of the remaining radios wassold at $4 below cost. If the store paid $11 for each radio, what was the total income from the sale? (hint: income=sales-cost) 1 solutions
Answer 73229 by checkley71(8403) on 2007-09-26 17:09:35 (Show Source):
You can put this solution on YOUR website!144*11=$1584 the price paid for all the radios
income=(11+15)x+7(144-x)-1584
income=26x+1008-7x-1584
income=19x-576 [x being the number of radios sold for $15 above cost].
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Volume/100554: I need to find out how many gumballs are in a gumball machine. If the diameter of the sphere is 4cm and if a square of 9 gumballs is 1/2cm. I am clueless. Please help. 1 solutions
Answer 73202 by checkley71(8403) on 2007-09-26 11:02:37 (Show Source):
You can put this solution on YOUR website!V=4/3PIR^3
V=4/3*3.14*2^3
V=9.42/3*8
V=25.12 ANSWER FOR THE MACHINE VOLUME.
9/0.5=X/25.12 NOW CROSS MULTIPLY.
.5X=226.08
X=226.08/.5
X=452.16 ANSWER FOR THE NUMBER OF BALLS.
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THIS ANSWER ASSUMES THE BALLS ALL STACK UP IN A SQUARE. HOWEVER: THAT ISN'T THE WAY THEY LIE IN THE MACHINE SO THE ACTUAL TOTAL NUMBER MAY BE SLIGHTLY LARGER.
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