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Travel_Word_Problems/108101: A BICYCLIST RODE INTO THE COUNTRY FOR 5 HRS. IN RETURNING, HER SPEED WAS 5 M/H FASTER AND THE TRIP TOOK 4 HOURS.
WHAT WAS HER SPEED EACH WAY?
Thanks
JMS
1 solutions
Answer 78737 by checkley71(8403)   on 2007-11-04 21:50:48 (Show Source):
You can put this solution on YOUR website!DISTANCE=RATE*TIME
SEEING AS THE DISTANCES ARE THE SAME WE HAVE THE EQUATION
5*R=4(R+5)
5R=4R+20
5R-4R=20
R=20 MPH HER SPEED GOING
PROOF
5*20=4(25)
100=100
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Matrices-and-determiminant/108090: i need to solve this system using an augmented matrix and i don't know how colud someone please help me.
5x+2y=2
3x-y=-12
1 solutions
Answer 78736 by checkley71(8403) on 2007-11-04 21:47:27 (Show Source):
You can put this solution on YOUR website!AN AUGMENTED MATRIX IS A STANDARD MATRIX WITH THE NUMERIC VALUES ADDED THUS
5,2
3-1
BECOMES:
5,2,2
3,-1,-12 NOW MULTIPLY THE SECOND ENTRY BY 2 & ADD THE 2 ROWS
5,2,2
6,-2,-24
----------------
11,0,-22 OR
11X=-22
X=-22/11
X=-2 ANSWER.
5*-2+2Y=2
-10+2Y=2
2Y=2+10
2Y=12
Y=12/2
Y=6 ANSWER.
PROOF
3*-2-6=-12
-6-6=-12
-12=-12
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Trigonometry-basics/108087: 17 11/12 diveded by 6 1/10 =
HELP PLEASE
1 solutions
Answer 78734 by checkley71(8403) on 2007-11-04 21:28:01 (Show Source):
You can put this solution on YOUR website!FIRST WE NEED TO CHANGE THE MIXED FRACTION TO AN IMPROPER FRACTION.
(17 11/12=(12*17+11)/12=215/12
NOW CHANGE THE OTHER FRACTION ALSO
6 1/10=(10*6+1)/10=61/10
NOW WE CAN DIVIDE THESE 2 FRACTIONS THUS:
(215/12)/(61/10) NOW WE NEED TO INVERT THE DENOMINATOR & MULTIPLY
215/12*10/61
2150/732
2.937 ANSWER.
----------------------------------------------------------------
OR WE COULD CHANGE THESE FRACTIONS TO DECIMALS AND DIVIDE.
17 11/12=17.9167
6 1/10=6.1
NOW DIVIDE:
17.9167/6.1
2.937 ANSWER.
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Trigonometry-basics/108080: The interest rate on an auto loan in May was 12 3/8%. By
September the rate was up to 14 1/4 %. How many percentage points did the interest rate increase over the period?
Please can someone help me with this percentage and fraction problem??
1 solutions
Answer 78732 by checkley71(8403) on 2007-11-04 21:15:04 (Show Source):
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Trigonometry-basics/108082: Julio works as a quality control expert in a beverage factory. The assembly line that he monitors produces about 20,000 bottles in a
24-hour period. Julio samples about 120 bottles an hour and rejects the line if
he finds more than 1/50 of the sample to be defective. About how many defective
bottles should Julio allow before rejecting the entire line?
Can someone please help me with this problem? I do not even no where or how to begin?
1 solutions
Answer 78730 by checkley71(8403) on 2007-11-04 21:08:57 (Show Source):
You can put this solution on YOUR website!1/50*24*120=2880/50=57.6 DEFECTS IN THE 24 HOUR SAMPLE IS THE TARGET FOR SHUTTING DOWN THE LINE.
HE SHOULD SHUT DOWN THE LINE IF 58 OF THE 2880 SAMPLES ARE DEFECTIVE.
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Trigonometry-basics/108078: Robin ran 5 1/3 mi on Sunday, 2 1/4 mi on Tuesday, and 3 1/2 mi on Friday.
How far did she run during the week?
HELP please i hate word problems and fractions here there are both.
1 solutions
Answer 78729 by checkley71(8403) on 2007-11-04 21:01:33 (Show Source):
You can put this solution on YOUR website!5 1/3=16/3
2 1/4=9/4
3 1/2=7/2 NOW ADD
16/3+9/4+7/2 NEED TO FIND A COMMON DENOMINATOR THAT ALL DENOMINATORS DIVIDE EVENLY INTO.
4*3 LOOKS LIKE AN OPTION
16/3+9/4+7/2
(4*16+3*9+6*7)/12
(64+27+42)/12
133/12=11 1/11 MILES ANSWER.
YOU COULD CONVERT THESE FRACTIONS TO DECIMALS & ADD THEM THUS:
5.333+2.25+3.5=11.083 WHICH EQUALS 11 1/11
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Linear-systems/108022: Write an equation of a line that is perpendicular to y= -3/4x + 2 and passes through (-4,1)
1 solutions
Answer 78727 by checkley71(8403) on 2007-11-04 20:53:40 (Show Source):
You can put this solution on YOUR website!THIS LINE HAS A SLOPE OF -3/4.
THEREFORE A PERPENDICULAR LINE HAS A SLOPE OF 4/3.
NOW REOPLACE THE X & Y VALUES IN THE LINE EQUATION [Y=mX+b] WITH (-4,1) & SOLVE FOR THE Y INTERCEPT (b).
1=4/3*-4+b
1=-16/3+b
b=1+16/3
b=(3+16)/3
b=19/3 FOR THE Y INTERCEPT.
Y=4X/3+19/3 ANSWER.
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Equations/108028: Oats 'n' Barely bulk food store sells cashews at $18/kg and peanuts at $6/kg. If the store wants to make a mixture of 50kg of cashews and peanuts to sell for $9/kg, how many kilograms of cashews and how many kilograms of peanuts must be in the mixture?
1 solutions
Answer 78725 by checkley71(8403) on 2007-11-04 20:45:05 (Show Source):
You can put this solution on YOUR website!18X+6(50-X)=9*50
18X+300-6X=450
12X=450-300
12X=150
X=150/12
X=12.5 KG OF CASHEWS.
50-12.5=37.5 KG OF PEANUTS.
PROOF
18*12.5+6*37.5=9*45
225+225=450
450=450
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Equations/108030: Write the equations in standard form of the horizontal and vertical lines that pass through the point.
1. (-5,-7)
2. (6,-10)
1 solutions
Answer 78723 by checkley71(8403) on 2007-11-04 20:38:19 (Show Source):
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Graphs/108032: Translate the following statement into an algebraic equaion. Let x represent the number.
10 less than 17 times a number is 3 times that same number.
1 solutions
Answer 78722 by checkley71(8403) on 2007-11-04 20:34:11 (Show Source):
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Graphs/108034: Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second.
1 solutions
Answer 78720 by checkley71(8403) on 2007-11-04 20:29:24 (Show Source):
You can put this solution on YOUR website!LET X & X+2 BE THE 2 ODD INTEGERS.
5X=12+3(X+2)
5X=12+3X+6
5X-3X=18
2X=18
X=18/2
X=9 ANSWER FOR THE SMALLER ODD INTEGER.
9+2=11 FOR THE LARGER ODD INTEGER.
PROOF
5*9=12+3*11
45=12+33
45=45
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Equations/108035: An open cylindrical garbage container has a surface are of 1500cm^2(squared) and a radius of 12cm. What is its height to the nearest tenth of a centimetre?
1 solutions
Answer 78719 by checkley71(8403) on 2007-11-04 20:25:56 (Show Source):
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Graphs/108037: Solve the following systems by graphing.
3x-6y=9
x-2y=3
-1(3x-6y)=9(-1)
-3(x-2y)=3(-3)
then
-3x+6y=-9
-3x+6y=-9
Am I doing this wrong because this does not look right?
1 solutions
Answer 78718 by checkley71(8403) on 2007-11-04 20:19:30 (Show Source):
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Systems-of-equations/108039: Write in slope-intercept form.
(-2/3,4) (6,-1/3)
1 solutions
Answer 78717 by checkley71(8403) on 2007-11-04 20:15:51 (Show Source):
You can put this solution on YOUR website!SLOPE=(Y2-Y1)/(X2-X1)
SLOPE=(1/3-4)/(6+2/3)
SLOPE=(-3 3/4)/(6 2/3)
SLOPE=(-15/4)/(20/3)
SLOPE=-15/4*3/20
SLOPE=-45/80
SLOPE=-9/16 THE (m) TERM IN THE STARND LINE FORMULA.
NOW SUBSTITUTE ONE SET OF POINTS FOR THE X & Y VALUES & SOLVE FOR THE Y INTERCEPT(b) IN THE LINE FORMULA
Y=mX+b.
4=-9/15*-2/3+b
4=18/45+b
b=4-18/45
b=(4*45-18)/45
b=(180-18)/45
b=162/45=18/5 FOR THE Y INTERCEPT.
THUS THE EQUATION IS
Y=-9X/16+18/5
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Pythagorean-theorem/108056: This question is from textbook Introductoru & Intermediate Algebra
The length of a rectangle exceeds twice its width by 3 inces. If the area is 10 square inches, find the rectangles dimensions. Round to the nearest tenth of an inch.
1 solutions
Answer 78715 by checkley71(8403) on 2007-11-04 20:05:20 (Show Source):
You can put this solution on YOUR website!L=2W+3
L*W=10
(2W+3)*W=10
2W*2+3W-10=0
USING THE QUADRATIC EQUATON WE GET
X=(-3+-SQRT[3^2-4*2*-10])/2*2
X=(-3+-SQRT[9+80])/4
X=(-3+-SQRT89)/4
X=(-3+-9.43)/4
X=(-3+9.43)/4
X=6.43/4
X=1.6 ANSWER FOR THE WIDTH.
L=2*1.6
L=3.2+3
L=6.2 FOR THE LENGTH.
PROOF
1.6*6.2=10
10=10
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Length-and-distance/108052: Could someone please help me on this...I am clueless.
On Saturday morning, Lynn walked
for 2 hours and then ran for 30 minutes. If she ran twice
as fast as she walked and covered 12 miles altogether,
then how fast did she walk?
1 solutions
Answer 78710 by checkley71(8403) on 2007-11-04 19:50:48 (Show Source):
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Linear-equations/108049: Alice Gleeson invested a portion of $32,000.00 at 9% interest and the balance at 11% interest, how much did she invest at each rate if her total income from both investments was $3,200.00?
1 solutions
Answer 78708 by checkley71(8403) on 2007-11-04 19:42:42 (Show Source):
You can put this solution on YOUR website!.11X+.09(32,000-X)=3,200
11X+2880-.09X=3,200
.02X=3,200-2,880
.02X=320
X=320/.02
X=16,000 AMOUNT INVESTED @ 11%
32,000-16,000=16,000 AMOUNT INVESTED @ 9%
PROOF
.11*16,000+.09*16,000=3,200
1,760+1,440=3,200
3,200=3,200
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Travel_Word_Problems/108043:
A BUS LEAVES A STATION AT 1 P.M., TRAVELING WEST AT AN AVERAGE RATE OF 44 MI/H.
ONE HOUR LATER A SECOND BUS LEAVES THE SAME STATION TRAVELING EAST AT A RATE OF 48 MI/H.
AT WHAT TIME WILL THE TWO BUSES BE 274 MILES APART?
a
1 solutions
Answer 78707 by checkley71(8403) on 2007-11-04 19:37:08 (Show Source):
You can put this solution on YOUR website!274=44T+48(T-1)
274=44T+48T-48
274=92T-48
92T=274+48
92T=322
T=322/92
T=3.5 HOURS
PROOF
274=44*3.5+48(3.5-1)
274=154+48*2.5
274=154+120
274=274
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Linear-equations/107870: Are the following lines parrallel, perpendicular, or neither. L1 2x+4y=5 L2 x+2y=4
thanks for any help it is greatly appreciated
Heather
1 solutions
Answer 78632 by checkley71(8403) on 2007-11-03 22:48:03 (Show Source):
You can put this solution on YOUR website!TO ANSWER THIS PROBLEM WE NEED TO FIND THE SLOPES OF THESE TWO LINES.
2X+4Y=15
4Y=-2X+15
Y=-2X/4+15/4
Y=-X/2+15/4 THIS LINE HAS A SLOPE IS -1/2.
X+2Y=4
2Y=-X+4
Y=-X/2+4/2
Y=-X/2+2 THIS LINE HAS A SLOPE OF -1/2.
THEREFORE THEY ARE PARALLEL LINES.
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Parallelograms/107866: A parallelogram is a quadrilateral with two pairs of parallel sides. Show that ABCD is a parallelogram if the coordinates of the vertices are A(-2,3), B(2,7), C(8,5), and D(4,1).
1 solutions
Answer 78625 by checkley71(8403) on 2007-11-03 22:32:59 (Show Source):
You can put this solution on YOUR website!TO PROVE THIS IS A PARALLELOGRAM WE NEED TO PROVE THAT THE SLOPESOF THE OPOSITE SIDES ARE EQUAL.
(7-3)/2+2)=4/4=1 & (1-5)/(4-8)=-4/-4=1 THESE 2 LINES ARE PARALLEL.
(1-3)/(4+2)=-2/6=-3 & (5-7)/(8-2)=-2/6=-3 THESE 2 LINES ARE PARALLEL.
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Human-and-algebraic-language/107763: At $11.25 per foot for the curved portion and $1.75 per foot for the straight portion. How much will it cost to put molding around a window. Use 3.14
1 solutions
Answer 78623 by checkley71(8403) on 2007-11-03 22:23:04 (Show Source):
You can put this solution on YOUR website!4 FEET 6 INCHES=4.5 FEET.
2 FEET 3 INCHES=2.25 FEET.
4.5*2=9 FEET FOR THE STRAIGHT PORTION.
9*1.75=$15.75 IS THE COST FOR THE STRAIGHT MOLDING.
RADIUS OF THE TOP SECTION IS 2.25 FEET.
1/2 THE CIRCUMFERANCE IS THE LENGTH OF THE CURVED SECTION FOR MOLDING.
C=2*PI*R
C=2*3.14*2.25
C=14.13 IS THE CIRCUMFERANCE.
1/2*14.13=7.065 FEET IS HALF THE CIRCUMFERANCE.
7.065*11.25=79.48 COST OF THE CURVED SECTION.
15.75+79.48=$95.23 FOR THE TOTAL COST.
DON'T KNOW HOW THEY GOT $103.11?
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Polynomials-and-rational-expressions/107864: This question is from textbook
Can you help me with this problem and show me the steps to solve it?
-2a^2-5ab-2b^2
Thanks!
1 solutions
Answer 78621 by checkley71(8403) on 2007-11-03 22:17:00 (Show Source):
You can put this solution on YOUR website!-2A^2-5AB-2B^2
TO MAKE THESE TERMS MORE MANAGEABLE. MULTIPLY ALL THESE TERMS BY -1
2A^2+5AB+2B^2 NOW FACTOR: ARRANGE THE FACTORS OF 2 (1 & 2) SO THAT THE 2 PRODUCTS ARE = 2 AND THE SUM IS 5. [2*2+1*1=4+1=5] & [1*2=2 & 1*2=2]
(2A+B)(A+2B)
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