New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'checkley71'
checkley71 answered: 8399 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399, >>NextEquations/121436: Of all possible quotients of the numbers 10, -1/2, -5, and 1/5 which tow produce the largest quotient? Which two produce the smallest? 1 solutions
Answer 89108 by checkley71(8403) on 2008-01-20 20:52:00 (Show Source):
|
absolute-value/121432: These data represent the population of a certain city.
Year Population (in thousands)
1950 18
1960 23
1970 29
1980 32
1990 38
2000 42
(a) Draw a line graph for the data.
(b) Use the line graph to predict the population in the year 2010
1 solutions
Answer 89106 by checkley71(8403) on 2008-01-20 20:47:39 (Show Source):
You can put this solution on YOUR website!Y=mX+b
USING THE POINTS (5,18)(10,42) WE HAVE A SLOPE OF:
(42-18)/(10-5)=24/5=4.8.
NOW USING ONE SET OF POINTS WE FIND THE Y INERCEPT.
18=4.8*5+b
b=18-24
b=-6
NOW WE HAVE THE LINE EQUATION:
Y=4.8X-6
WHEN X=11 THE Y=4.8*11-6 OR Y=46.8
this says that the population in 2010 will be 46.8 thousand.
 (graph 300x300 pixels, x from -6 to 12, y from -10 to 50, y = 4.8x -6).
|
Quadratic_Equations/121354: Solve by completeing the square.
x squared - 6x -3 = 0
2x squared + 10x + 11 = 0
1 solutions
Answer 89102 by checkley71(8403) on 2008-01-20 20:25:34 (Show Source):
You can put this solution on YOUR website!X^2-6X-3=0
X^2-6X+9=3+9
(X-3)^2=12
X-3=SQRT12
X=3+3.464
X=6.464 ANSWER.
----------------------------------
2X^2+10X+11=0
2X^2+10X=11
2(X^2+5X+6.26)=11+2*6.25
2(X+5/2)^2=11+12.5
(X+5/2)^2=23.5/2
(X+5/2)^2=11.75
X+2.5=SQRT11.75
X=-2.5+3.4278
X=.92378 ANSWER.
|
Expressions-with-variables/121375: Find the solution to system of equations by substitution.
Problem: Y=2X+7 and Y=-X-5. I am confused on which equation do i insert and when. For this problem I tried Y=-X(2X+7)-5, Then I'm stumped, I think the -x multiplied by the 2x is messing me up. Plus both of these start with Y=. The other examples problems show x+2y=6 and 4y=12-2x ? Totally different. Can you help me sort out how to do substition? How to start. I have went thru example after example in book and I keep getting the wrong answers I am missing a step or concept i think. 1 solutions
Answer 89097 by checkley71(8403) on 2008-01-20 19:51:20 (Show Source):
You can put this solution on YOUR website!Y=2X+7 NOW REPLACE THE Y IN THE OTHER EQUATION WITH(2X+7) & SOLVE FOR X.
2X+7=-X-5
2X+X=-5-7
3X=-12
X=-12/3
X=-4 ANSWER.
Y=2*-4+7
Y=-8+7
Y=-1 ANSWER.
PROOF
-1=-(-4)-5
-1=4-5
-1=-1
---------------------------------------------------
X+2Y=6 OR X=6-2Y
NOW REPLACE X IN THE OTHER EQUATION WITH(6-2Y) & SOLVE FOR Y.
4Y=12-2(6-2Y)
4Y=12-12-2Y
4Y+2Y=0
2Y=0
Y=0 ANSWER.
X+2*0=6
X=6 ANSWER.
PROOF
4*0=12-2*6
0=12-12
0=0
|
Equations/121379:
how do you remove brackets? e.g. 2(x+5) or a(a-4)
multiply out of brackets and simplify? e.g. (x+3)(+2) or (2c-3)(3c+4)
1 solutions
Answer 89096 by checkley71(8403) on 2008-01-20 19:42:56 (Show Source):
|
Linear-systems/121371: Find an equation of the line containing the given pair of points (-2, -9) and (-6, -7). Please show your steps. Thank you 1 solutions
Answer 89093 by checkley71(8403) on 2008-01-20 19:24:38 (Show Source):
You can put this solution on YOUR website!FIRST WE FIND THE SLOPE (m)
M=(Y2-Y1)/(X2-X1)=(-7+9)/(-6+2)=2/-4=-1/2 IS THE SLOPE
NOW REPLACE THE X & Y TERMS IN THE LINE EQUATION[Y=mX+b] & SOLVE FOR b.
-9=-1/2*-2+b
-9=1+b
b=-9-1
b=-10 THE Y INTERCEPT.
THUS THE LINE EQUATION IS:
Y=-X/2-10
|
Miscellaneous_Word_Problems/121377: Mark wants to have a semester average of 85 in his math class. The three 6-week grades and the semester exam grade count equally in figuring the semester average in his school. The first six weeks Mark scored 92, the second six weeks he scored 75, and the third sixweeks Mark scored 83. What does Mark score on the semester exam to have exactly an 85 average for the semester?
It is a multiple choice question, but instead of going through all of the answers and wasting time, I would rather if you could explain to me how to do this problem faster[if there is one]. 1 solutions
Answer 89090 by checkley71(8403) on 2008-01-20 19:14:01 (Show Source):
You can put this solution on YOUR website!(92+75+83+x)/4=85
(250+x)/4=85 now cross multiply.
250+x=4*85
250+x=340
x=340-250
x=90 is the score required for the last test.
proof
(92+75+83+90)/4=85
340/4=85
85=85
|
Permutations/121408: a certain car averages 28 miles per gallon. gasoline cost 1.11 per gallon. to the number of miles the car would be expected to go on 250 worth of gasoline?
1 solutions
Answer 89089 by checkley71(8403) on 2008-01-20 19:04:58 (Show Source):
|
Numeric_Fractions/121414: Please help me solve the following question:
In the problem 4/n plus 5/m, if m is the Lowest Common Denominator for the problem, what do you know about the relationship between n and m?
Thank you so much,
Brigid 1 solutions
Answer 89088 by checkley71(8403) on 2008-01-20 19:01:08 (Show Source):
|
Equations/121416: I need help with this problem so that I can help my daughter understand her homework. The problem is : 8x + 4y = 12 1 solutions
Answer 89087 by checkley71(8403) on 2008-01-20 18:58:42 (Show Source):
You can put this solution on YOUR website!Thank you very much for your help. One more question... if the problem had been a minus ((8x-4y=12)) would it still be an addition on the right of the equal sign... or would the sign have changed?
if you change all the signs by a negative sign you get the same equation.
-(8x+4y=12) or -8x-4y=-12 or -4y=8x-12 or y=8x-4-12/-4 or y=-2x+3
---------------------------------------------------------------------
IF THIS IS A LINE EQUATION THEN:
8X+4Y=12
4Y=-8X+12
Y=-8X/4+12/4
Y=-2X+3 THIS LINE HAS A SLOPE=-2 & A Y INTERCEPT=3 (0,3).
GRAPH FOLLOWS.
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -2x +3).
|
Proportions/121348: A man who is 75 inches tall is 15 inches on a TV monitor. The image of his friend is 13 inches tall on monitor. How tall is his friend. 1 solutions
Answer 89084 by checkley71(8403) on 2008-01-20 18:51:49 (Show Source):
|
Average/121409:
Write the equation of the line which has y-intercept (0, 5) and is perpendicular to the line with equation y = –3x + 1. 1 solutions
Answer 89083 by checkley71(8403) on 2008-01-20 18:43:32 (Show Source):
You can put this solution on YOUR website!Y=-3X+1 THIS LINE HAS A SLOPE OF -3.
A PERPENDICULAR LINE HAS SLOPE IS 1/3.
IF THIS LINE PASSES (0,5) HAS A LINE EQUATION OF
5=1/3*+b
b=5-1/3
b=(15-1)/3
b=14/3
Y=X/3+14/3 ANSWER.
|
Exponents/121376: This question is from textbook pre-algebra
i really need help on my math i have an F on my math so ill give my first answer!
8 to the power of 13 over 8 to the power of 10 1 solutions
Answer 89081 by checkley71(8403) on 2008-01-20 18:35:07 (Show Source):
|
real-numbers/121401: Calculate the first 10 powers of i. Observe the pattern. Explain how to quickly calculate any whole number power of i.( ex. What is i^312?)
I know how to calculate the first ten powers and I see the pattern but I am awful at explaining to other people. Can you help? 1 solutions
Answer 89075 by checkley71(8403) on 2008-01-20 18:11:17 (Show Source):
You can put this solution on YOUR website!i^1=sqrt-1
i^2=-1
i^3=1sqrt-1
i^4=1
i^5=1sqrt-1
i^6=-1
i^7=-1sqrt-1
i^8=1
i^9=1sqrt-1
i^10=-1
---------------------------------------
i^312=i^(78*4) or i^4=1
IF THE POWER IS DIVISABLE BY 4 THEN THE ANSWER IS (1)
IF DIVIDING THE POWER BY 4 GIVES A REMAINDER OF 1 THEN THE ANSWER IS (SQRT-1)
IF DIVIDING THE POWER BY 4 GIVES A REMAINDER OF 2 THEN THE ANSWER IS (-1)
IF DIVIDING THE POWER BY 4 GIVES A REMAINDER OF 3 THEN THE ANSWER IS (1SQRT-1)
|
Rate-of-work-word-problems/121396: This question is from textbook algebra and trigonometry with analiytic geometry
A consulting engineer's time is billed at $100 per hour, and her assistant's is billed at $20 per hour. A customer received a bill for $1200 for a certain job. If the assistant worked 3 hours less than the engineer, how much time did each bill on the job? 1 solutions
Answer 89072 by checkley71(8403) on 2008-01-20 17:57:36 (Show Source):
You can put this solution on YOUR website!100X+20(X-3)=1200
100X+20X-60=1200
120X=1200+60
120X=1260
X=1260/120
X=10.5 HOURS WAS BILLED FOR THE ENGINEER OR:
100*10.5=$1050 WAS THE ENGINEER'S BILL.
20(10.5-3)=20*7.5=$150 WAS THE ASSISTANT'S BILL.
PROOF
100*10.5+20*7.5=1200
1050+150=1200
1200=1200
|
Travel_Word_Problems/121398: a plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for second part of the trip? 1 solutions
Answer 89070 by checkley71(8403) on 2008-01-20 17:52:01 (Show Source):
You can put this solution on YOUR website!560/(X+1)=480/X
560X=480(X+1)
560X=480X+480
560X-480X=480
80X=480
X=480/80
X=6 HOURS FOR THE SECOND 480 MILE TRIP.
6+1=7 HOURS FOR THE FIRST 560 MILE TRIP.
PROOF
560/7=480/6
80=80
|
|