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checkley71 answered: 8399 problems
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Quadratic_Equations/132848: Sam is a guest on the TV show Math Jeopardy, and has just chosen the $300 question in the category "Quadratic Equations." The answer is "The solutions are x=3 and x=-2." What question could Sam ask that would win the $300? Is there more than one possible correct question? Explain. 1 solutions Answer 97202 by checkley71(8403)   on 2008-03-20 17:31:39 (Show Source): You can put this solution on YOUR website! ONE QUESTION WOULD BE: WHAT IS THE VALUE OF X IN THE EQUATION X^2-X-6=0 SOLUTION: (X-3)(X+2)=0 X-3=0 X=3 ANSWER. X+2=0 X=-2 ANSWER.

Quadratic_Equations/132849: Robin is mowing a rectangular field that measures 24 yards by 32 yards, by pushing the mower around and around the outside of the plot. This creates a widening border that surrounds the unmowed grass in the center. During a brief rest, Robin wonders whether the job is half done yet. How wide is the uniform mowed border when Robin is half done? 1 solutions Answer 97200 by checkley71(8403)   on 2008-03-20 17:26:06 (Show Source): You can put this solution on YOUR website! 24*32=768 FT^2 IS THE TOTAL LAWN AREA. (24-2X)(32-2X)=768/2 768-64X-48X+4X^2=384 4X^2-112X+768-384=0 4X^2-112X+384=0 4(X^2-28X+96)=0 4(X-24)(X-4)=0 X-4=0 X=4 ANSWER FOR THE WIDTH OF THE MOWED AREA. (24-8)(32-8)=384 16*24=384 384=384

Linear_Equations_And_Systems_Word_Problems/132872: Please help! I cannot figure out how to set this problem up. I have to include the cost function as well. Thank you! Here it is: An appliance repair service charges $50 to come out for a service call which is applied toward the first 30 minutes of service should a repair be needed. If a repair is needed, the charge of $37 per 30 minutes (after the initial half hour included in the service call charge) for labor and the cost of parts. Write a cost function to determine the amount a customer needing a repair that takes 1.5 hours and requires a $103 part. 1 solutions Answer 97199 by checkley71(8403)   on 2008-03-20 17:11:57 (Show Source): You can put this solution on YOUR website! 50+(2*37)+103=50+74+103=$227 FOR THE TOTAL SERVICE BILL.

Quadratic_Equations/132877: In 1990, Michael's college tuition was $1500. In 1995, tuition at the same college cost $3200. Assuming that an exponential model applies, how much will tuition cost in 2009?? I think the answer is $6837 ???????? 1 solutions Answer 97198 by checkley71(8403)   on 2008-03-20 17:06:41 (Show Source): You can put this solution on YOUR website! (1905-1990)/(3,000-1500) 5/1500=(2009-1990)/X-1500) 5/1500=19/(X-1500) 5(X-1500)=19*1500 5X-7500=28500 5X=28500+7500 5X=36000 X=36000/5 X=$7200 IS THE PROJECTED TUITION IN 2009 PROOF: 5/1500=19/(7200-1500) 5/1500=19/5700 19*1500=5*5700 28500=28500

Polynomials-and-rational-expressions/132898: Can someone show me hoe to sovle foe C? 1 solutions Answer 97195 by checkley71(8403)   on 2008-03-20 16:57:28 (Show Source): You can put this solution on YOUR website! IF YOU SET THIS ITEM=0 THEN: B-6C=0 -6C=-B C=-B/-6 C=B/6

Quadratic_Equations/132899: A group of people want to share equally the cost of a $200,000 airplane. They want to find 5 more people to join their club so that the cost per person decreases by $2000. How many people are currently in the club? 1 solutions Answer 97194 by checkley71(8403)   on 2008-03-20 16:54:29 (Show Source): You can put this solution on YOUR website! 200,000/X=200,000/(X+5)+2000 200,000/X-200,000/(X+5)=2,000 COMBINE THE X FRACTIONS USING A COMMON DENOMINATOR. [200,000(X+5)-200,000X)/X(X+5)=2,000 (200,000X+1,000,000-200,000X)/(X^2+5X)=2,000 NOW CROSS MULTIPLY 2,000(X^2+5X)=1,000,000 2,000(X^2+5X)-1,000,000=0 2,000(X^2+5X-500)=0 2,000(X+25)(X-20)=0 X-20=0 X=20 IS THE NUMBER OF ORIGINAL CLUB MEMBERS. PROOF: 200,000/20=200,000/25+2,000 10,000=8,000+2,000 10,000=10,000

Linear_Equations_And_Systems_Word_Problems/132933: The creekside Theater is putting on a play.The hanson Family bought 5 adult ticketsand 2 child tickets for 129.00. The Rivera family bought 2 adult tickets and 6 cgild Tickets for 107.50. Write a system of equations to represent the situation. Then solve the system.How much Does a Adult ticket cost and how much does a child ticket cost. 1 solutions Answer 97187 by checkley71(8403)   on 2008-03-20 16:17:10 (Show Source): You can put this solution on YOUR website! 5A+2C=129 2A+6C=107.50 NOW MULTIPLY THE FIRST EQUATION BY -3 & ADD THEM. -15A-6C=-387 -------------------------------- -13A=-279.5 A=-279.5/-13 A=$21.50 COST OF THE ADULT TICKET. 5*21.5+2C=129 107.5+2C=129 2C=129-107.5 2C=21.5 C=21.5/2 C=$10.75 COST OF THE CHILDREN'S TICKET. PROOF: 2*21.50+6*10.75=107.5 43+64.5=107.50 107.50=107.50

Equations/132937: Please help me solve this formula for the specified variable: 1/a+1/b=c for b 1 solutions Answer 97178 by checkley71(8403)   on 2008-03-20 15:58:32 (Show Source): You can put this solution on YOUR website! 1/A+1/B=C SUBTRACT 1/A FROM BOTH SIDES. 1/B=C-1/A CROSS MULTIPLY. B(C-1/A)=1 DIVIDE BY (C-1/A) B=1/(C-1/A) ANSWER.

Miscellaneous_Word_Problems/132945: A basketball player completed 42.5% of his field goals in the most recent season. He made 281 field goals. How many did he attempt? (type an integer or a decimal. round to the nearest integer as needed) Please help. i know i keep coming up with the wrong answer. I got 6.7 lol 1 solutions Answer 97176 by checkley71(8403)   on 2008-03-20 15:55:20 (Show Source): You can put this solution on YOUR website! 281/.425=661 SHOTS ATTEMPTED.

Travel_Word_Problems/132949: A cyclist traveled at a rate of 24mph to visit a nearby town. The cyclist averaged 18mph on the return trip. If the round trip took 4.9 hours find the distance to the nearby town. 1 solutions Answer 97174 by checkley71(8403)   on 2008-03-20 15:51:32 (Show Source): You can put this solution on YOUR website! D/24+D/18=4.9 (18D+24D)/24*18=4.9 42D/432=4.9 42D=432*4.9 42D=2116.8 D=2116.8/42 D=50.4 MILES IS THE DISTANCE TO THE NEARBY TOWN. PROOF: 50.4/24+50.4/18=4.9 2.1+2.8=4.9 4.9=4.9

Travel_Word_Problems/132950: This question is from textbook Applied College Algebra A ballet performance brought in $61,800 on the sale of 3000 tickets. If the tickets sold for $14 and $25, how many of each type of tickets were sold? 1 solutions Answer 97171 by checkley71(8403)   on 2008-03-20 15:46:36 (Show Source): You can put this solution on YOUR website! 14X+25(3000-X)=61,800 14X+75,000-25X=61,800 -11X=61,800-75,000 -11X=-13,200 X=-13,200/-11 X=1,200 TICKETS FOR $14 WERE SOLD. 3,000-1,200=1,800 TICKETS FOR $25 WERE SOLD. PROOF: 14*1,200+25*1,800=61,800 16,800+45,000=61,800 61,800=61,800

Equations/132958: 1/2N + 11 = 2N please show me the correct steps 1 solutions Answer 97169 by checkley71(8403)   on 2008-03-20 15:40:45 (Show Source): You can put this solution on YOUR website! n/2+11=2n n/2-2n=-11 -n/2=-11 -n=-22 -n=-22/-1 n=22 answer. proof: 22/2+=11=2*22 11+11=22 22=22

Equations/132959: Which best describes the effect on the graph of f(x)=4x+8 if the y-intercept is changed to-3? 1 solutions Answer 97168 by checkley71(8403)   on 2008-03-20 15:37:30 (Show Source): You can put this solution on YOUR website! f(x)=4x+8 this line has a slope (m) of 3 & a y intercept (b) of 8 f(x)=4x-3 this line is a parallel line with slope of 4 & a y intercept (b) of -3.

Quadratic_Equations/132828: Some students planned for a get-together. The budget for food was $500. Five of the students failed to come because of the distance and therefore the cost of food for each member increased by $5. How many students attended the get-together? 1 solutions Answer 97068 by checkley71(8403)   on 2008-03-19 18:36:20 (Show Source): You can put this solution on YOUR website! 500/X=500/(X-5)-5 500/X-500/(X-5)=-5 (500(X-5)+X)/X(X-5)=-5 (500X-2500-500X)/(X^2+5X)=-5 CROSS MULTIPLY. -5(X^2+5X)=-2500 -5X^2+25X+2500=0 -5(X^2-5X-500=0 -5(X-25)(X+20)=0 X-25=0 X=25 NUMBER OF STUDENTS ORIGINALLY PLANNED TO ATTEND. PROOF: 500/25=500/(25-5)-5 20=(500/20)-5 25=25-5 20=20

Quadratic_Equations/132831: Rita rows 12 km upstream and 12 km downstream in 3 hours. The speed of her boat in still water is 9 km/hr. Find the speed of the stream 1 solutions Answer 97063 by checkley71(8403)   on 2008-03-19 18:23:32 (Show Source): You can put this solution on YOUR website! 12/(9-X)+12/(9+X)=3 [12(9+X)+12(9-X)]/(9+X)(9-X)=3 [108(12X+108-12X]/(81-X^2)=3 216/(81-X^2)=3 NOW CROSS MULTIPLY 3(81-X^2)=216 243-3X^2-216=0 -3X^2+27=0 -3(X^2-9)=0 -3(X+3)(X-3)=0 X-3=0 X=3 KMH IS THE SPEED OF THE CURRENT. PROOF: 12/(9-3)+12/(9+3)=3 12/6+12/12=3 2+1=3 3=3

Complex_Numbers/132732: please help me i do not understand ((3y+15)/y) / ((y+5)/y) 1 solutions Answer 97061 by checkley71(8403)   on 2008-03-19 18:07:28 (Show Source): You can put this solution on YOUR website! [(3Y+15)/Y]/(Y+5)/Y NOW INVERT THE DIVISOR AND MULTIPLY THE FRACTIONS: [(3Y+15)/Y]

Proportions/132743: Can you please help me solve for x 500/(x+5)+5=500/x 1 solutions Answer 97059 by checkley71(8403)   on 2008-03-19 18:02:57 (Show Source): You can put this solution on YOUR website! 500/(X+5)+5=500/X 500/(X+5)-500/X=-5 [500*X-500(X+5)]/X(X+5)=-5 (500X-500X-2500)/(X^2+5X)=-5 CROSS MULTIPLY -5(X^2+5X)=-2500 -5X^2-25X+2500=0 -5(X^2+5X-500)=0 -5(X+25)(X-20)=0 X+25=0 X=-25 ANSWER. X-20=0 X=20 ANSWER.

Quadratic_Equations/132748: A motor boat travels 300km downstream and returns 300km upstream in a total of 12 hours. The speed of the current is 6km/h. Write the equation that could be used to determine the speed of the motorboat in still water? I think it is (300/x )+(300/x+6)=12 Can someone please confirm this for me ???? 1 solutions Answer 97055 by checkley71(8403)   on 2008-03-19 17:53:42 (Show Source): You can put this solution on YOUR website! 300/(X-6)+300/(X+6)=12 THE FIRST FRACTION IS THE SPEED UP STREAM AGAINST THE TIDE & THE SECOND FRACTION IS THE SPEED WITH THE CURRENT. [300(X+6)+300(X-6)]/(X+6)(X-6)=12 (300X+1800+300X-1800)/(X^2-36)=12 600X/(X^2-36)=12 NOW CROSS MULTIPLY. 12(X^2-36)=600X 12X^2-432-600X=0 12X^2-600X-432=0 12(X^2-50X-36)=0 USING THE QUADRATIC EQUATUION: WE GET: X=(50+-SQRT[-50^2-4*1*-36])/2*1 X=(5)=-SQRT[2500+144])/2 X=(50+-SQRT2644)/2 X=(50+-51.42)/2 X=(50+51.42)/2 X=101.42/2 X=50.71 ANSWER FOR THE SPEED OF THE MOTOR BOAT. PROOF: 300/(50.71+6)+300/(50.71-6)=12 300/56.71+300/44.71=12 5.29+6.71=12 12=12

Square-cubic-other-roots/132754: How do you solve a question like: 4 (square-root-of) 3 + 6 (square-root-of) 2 - 5 (square-root-of) 4 I add it and I just don't understand it. It was on my placement test. Not homework. I just want to know how to solve it 1 solutions Answer 97048 by checkley71(8403)   on 2008-03-19 17:31:11 (Show Source): You can put this solution on YOUR website! 4SQRT3+6SQRT2-5SQRT4 4SQRT3+6SQRT2-5*2 4SQRT3+6SQRT2-10 ANSWER. SQRT WITH DIFFERENT VALUES (3 & 2) CANNOT BE COMBINED.

Linear-equations/132758: express the following equation in the form Y= mx+b a. 2y= 6x+8 1 solutions Answer 97047 by checkley71(8403)   on 2008-03-19 17:27:02 (Show Source): You can put this solution on YOUR website! 2y=6x+8 y=6x/2+8/2 Y=3X+4 ANSWER. m=3 & b=4.

Miscellaneous_Word_Problems/132790: A stamp collection consists of 5, 13, and 18 cent stamps. The number of 13 cent stamps is one less than twice the number of 5 cent stamps. The number of 18 cent stamps is five more than the number of 13 cent stamps. The total value of all the stamps is $2.60. Find the number of 13 cent stamps. 1 solutions Answer 97044 by checkley71(8403)   on 2008-03-19 17:24:08 (Show Source): You can put this solution on YOUR website! X=NUMBER OF .05 STAMPS 2X-1=NUMBER OF .13 STAMPS (2X-1)+5=NUMBER OF .18 STAMPS .05X+.13(2X-1)+.18[(2X-1)+5]=2.60 .05X+.26X-.13+.36X+.18(2X+4)=2.60 .05X+.26X-.13+.36X+.18X+.72=2.60 .67X=2.60+.13-.72 .67X=201 X=2.01/.67 X=3 IS THE NUMBEER OF 5 CENT STAMPS 2*3-1=6-1=5 IS THE NUMBER OF 13 CENT STAMPS. 5+5=10 IS THE NUMBER OF 18 CENT STAMPS PROOF: .05*3+.13*5+.18*10=2.60 .15+.65+1.80=2.60 2.60=2.60

Signed-numbers/132791: Given f(x)=2x^2-3x+5, Find f(1). 1 solutions Answer 97042 by checkley71(8403)   on 2008-03-19 17:07:36 (Show Source): You can put this solution on YOUR website! F(X)=2X^2-3X+5 F(1)=2*1^2-3*1+5 F(1)=2*1-3*1+5 F(1)=2-3+5 F(1)=4 ANSWER.

Reduction-of-unit-multipliers/132802: 3L=?mL 1 solutions Answer 97040 by checkley71(8403)   on 2008-03-19 17:04:51 (Show Source): You can put this solution on YOUR website! 3L=.003ml

Quadratic_Equations/132804: Factor 7p + 5x = Help me factor this please. Not good at all with these problems. 1 solutions Answer 97039 by checkley71(8403)   on 2008-03-19 17:00:21 (Show Source): You can put this solution on YOUR website! 7P+5X NO FACTORING POSSIBLE HERE BECAUSE YOU HAVE 2 UNKNOWN FACTORS AND NO COMMON FACTORS WITHIN THE INTEGERS.

Quadratic_Equations/132801: 9x-8=5x Help me please. 1 solutions Answer 97038 by checkley71(8403)   on 2008-03-19 16:57:43 (Show Source): You can put this solution on YOUR website! 9X-8=5X 9X-5X=8 4X=8 X=8/4 X=2 ANSWER. PROOF: 9*2-8=5*2 18-8=10 10=10

Square-cubic-other-roots/132778: solve: square 4x-13=1 1 solutions Answer 97037 by checkley71(8403)   on 2008-03-19 16:53:16 (Show Source): You can put this solution on YOUR website! 4X-13=1 4X=1+13 4X=14 X=14/4 X=7/2 OR 3.5 ANSWER.

Finance/132798: Jane has $10 000 to invest. She invested part of it in a term deposit that pays 4% per year and the rest of her money was invested in bonds paying 5% per year. If Jane earned $440 in interest for one year, how much money did she invest at each rate? 1 solutions Answer 97035 by checkley71(8403)   on 2008-03-19 16:47:12 (Show Source): You can put this solution on YOUR website! .05X+.04(10,000-X)=440 .05X+400-.04X=440 .01X=440-400 .01X=40 X=40/.01 X=4,000 AMOUNT INVESTED @ 5%. 10,000-4,000=6,000 AMOUNT INVESTED @ 4%. PROOF: .05*4,000+.04*6000=440 200+240=440 440=440

Quadratic_Equations/132621: A square lawn is surrounded by a walk one metre wide. If the area of the walk is equal to half the area of the lawn,what are the dimensions of the lawn??? 1 solutions Answer 96990 by checkley71(8403)   on 2008-03-18 21:22:57 (Show Source): You can put this solution on YOUR website! LET X BE THE LAWN SIDE MEASUREMENT. X^2=THE LAWN AREA. (X+2)^2-X^2=X^2/2 TOTAL AREA [(X+2)^2] MINUS THE LAWN AREA [X^2] = 1/2 THE LAWN AREA [X^2/2]. X^2+4X+4-X^2=X^2/2 4X+4=X^2/2 X^2=2(4X+4) X^2=8X+8 X^2-8X-8=0 USING THE QUADRATIC EQUATION: WE GET: X=(8+-SQRT[-8^2-4*1*-8])/2*1 X=(8+-SQRT64+32])/2 X=(8+-SQRT96)/2 X=(8+-9.7979)/2 X=(8+9.7979)/2 X=17.7979/2 X=8.899 METERS FOR THE DIMENSION OF THE SQUARE. PROOF: (8.899+2)^2-8.899^2=8.899^2/2 10.899^2-79.192=79.192/2 118.788-79.192=39.596 39.596=39.596

Quadratic_Equations/132623: In 1990,Joshua's university tuition was $1500. In 1995, tuition at the same university cost $3200. Assuming that an exponential model applies, how much will tuition cost in 2009? 1 solutions Answer 96987 by checkley71(8403)   on 2008-03-18 21:04:30 (Show Source): You can put this solution on YOUR website! (1995-1990)/(3200-1500)=(2009-1990)/(X-1500) 5/1700=19/(X-1500 5(X-1500)=19*1700 5X-7500=32300 5X=32300+7500 5X=39800 X=39800/5 X=$7,960 IS THE PROJECTED TUITION FOR 2009.

percentage/132663: An instrument store gives a 10% discount to all students off the original cost of an instrument. During a back to school sale an additional 15% is taken off the discounted price. a student purchases a flute for $306. I need to find the original price,but i don't know where to start, please help me thanks. 1 solutions Answer 96985 by checkley71(8403)   on 2008-03-18 20:57:07 (Show Source): You can put this solution on YOUR website! (.9*.85)X=306 .765X=306 X=306/.765 X=400 WAS THE ORIGINAL PRICE. PROOF 400(1-.10)(1-.15)=306 400*.9*.85=306 400*.765=306 306=306

Proportions/132665: Solve Proportions: 9/-15 = -27/P My question is: If just the demonitor or just the numerator is a negative number does this make the entire fraction negative? Thank you for your help, Brooke 1 solutions Answer 96983 by checkley71(8403)   on 2008-03-18 20:53:10 (Show Source): You can put this solution on YOUR website! 9/-15=-9/15=-(9/15) -9/15=-27/P NOW CROSS MULTIPLY. -9P=15*-27 -9P=-405 P=-405/-9 P=45 ANSWER.