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checkley71 answered: 8399 problems
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Any help with this equation would be Greatly appreciated:} 1 solutions
Answer 91773 by checkley71(8403) on 2008-02-06 09:09:12 (Show Source):
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Quadratic_Equations/125220:
looked like a rectangle is 300 cm^2. the difference between length and width is 13 cm. find the lenght of the diagonal 1 solutions
Answer 91771 by checkley71(8403) on 2008-02-06 08:50:47 (Show Source):
You can put this solution on YOUR website!L=W+13
300=W(W+13)
300=W^2+13W
W^2+13W-300=0
(W-12)(W+25)
W-12=0
W=12cmNSWER FOR THE WIDTH.
L=12+13=25cm R THE LENGTH.
THE DIAGONAL IS C
A^2+B^2=C^2
12^2+25^2C^2
144+625=C^2
769=C^2
C=SQRT769
C=27.73cm IS THE LENGTH OF THE DIAGONAL.
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Radicals/125107:
PLEASE HELP ME!!!
Simplify. write in lowest term
1)sqrt 45/125
Simplify. Assume the variable x represents a positive real number
2)sqrt 16x^14
Rewrite the following in simplified radical form.
3)sqrt 27
Rewrite the following in simplified radical form. Assume all variables represent positive real numbers.
4)Sqrt 50y^12
Solve for z. Where z is a real number
5)sqrt z-9=2
THANK YOU IN ADVANCE!!!
1 solutions
Answer 91725 by checkley71(8403) on 2008-02-05 18:59:17 (Show Source):
You can put this solution on YOUR website!1) SQRT45/125=SQRT.36=.6 ANSWER.
2) SQRT16X^14=4X^7 ANSWER.
3) SQRT27=3SQRT3 ANSWER.
4) SQRT50Y^12=5Y^6SQRT2 ANSWER.
5) SQRTZ-9=2 OR SQRTZ=2+9 OR SQRTZ=11 OR Z=11^2 OR Z=121 ANSWER.
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expressions/125110: PLEASE HELP
The lenght of a rectangle is 1ft more then twice its width, and the area of the rectangle is 45ft^2. I am trying to find the diensions of the rectangle.
Length _____ft
Width _____ft
THANK YOU IN ADVANCE 1 solutions
Answer 91724 by checkley71(8403) on 2008-02-05 18:50:45 (Show Source):
You can put this solution on YOUR website!L=2W+1
AREA=L*W
45=(2W+1)W
45=2W^2+W
2W^2+W-45=0
(2W-9)(W+5)+0
2W-9=0
2W=9
W=9/2
W=4.5 FEET ANSWER FOR THE WIDTH.
L=2*4.5+1
L=9+1
L=10 FEET ANSWER FOR THE LENGTH.
PROOF
4.5*10=45
45=45
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Expressions-with-variables/125113: How do you know if an expression has infinitely many solutions? 1 solutions
Answer 91721 by checkley71(8403) on 2008-02-05 18:40:40 (Show Source):
You can put this solution on YOUR website!AN EXPRESSION THAT HAS MORE UNKNOWNS THAN EQUATIONS FITS THIS CRITERIA.
EXAMPLE:
2X+3Y=8
X COULD BE=1 THEN Y=2. 2*1+3*2=8 OR 2+6=8 OR 8=8.
OR X COULD BE=2 THEN Y=4/3. 2*2+3*4/3=8 OR 4+4=8 OR 8=8.
OR X COULD BE=10 THEN Y=-4. 2*10+3*-4=8 OR 20-12=8 OR 8=8.
YOU CAN SEE HOW AN INFINITE NUMBER OF SOLUTIONS ARE POSSIBLE.
EVERY DIFFERENT X VALUE CREATES A CORRESPONDING DIFFERENT VALUE FOR Y.
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Quadratic_Equations/125099:
1.) 2x^2 - 5x – 10 = 0
2.) 3x^2 - 8x + 5 = 0 1 solutions
Answer 91716 by checkley71(8403) on 2008-02-05 17:41:03 (Show Source):
You can put this solution on YOUR website!1) 2x^2-5x-10=0 using the quadratic equation we get:
x=(5+-sqrt[-5^2-4*2*-10])/2*2
x=(5+-sqrt[25+80])/4
x=(5+-sqrt105)/4
x=(5+-10.25)/4
x=(5+10.25)/4
x=15.25/4
x=3.81 answer.
x=(5-10.25)/4
x=-5.25/4
x=-1.31 answer.
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2) 3x^2-8x+5=0
(3x-5)(x-1)=0
3x-5=0
3x=5
x=5/3 answer.
x-1=0
x=1 answer.
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Money_Word_Problems/125079: Cofee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture? 1 solutions
Answer 91712 by checkley71(8403) on 2008-02-05 17:23:45 (Show Source):
You can put this solution on YOUR website!12X+9(100-X)=11.25*100
12X+900-9X=1125
3X=1125-900
3X=225
X=225/3
X=75 POUNDS OF $12 COFFEE BEANS.
100-75=25 POUNDS OF $9 COFFEE.
PROOF.
12*75+9*25=1125
900+225=1125
1125=1125
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Miscellaneous_Word_Problems/125094: In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many voted did each candidate receive. 1 solutions
Answer 91711 by checkley71(8403) on 2008-02-05 17:14:59 (Show Source):
You can put this solution on YOUR website!X+(X+220)=810
2X+220=810
2X=810-220
2X=590
X=590/2
X=295 ANSWER. FOR THE LOSSER'S NUMBER OF VOTES.
295+220=515 ANSWER FOR THE WINNER'S NUMBER OF VOTES.
PROOF
295+515=810
810=810
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Systems-of-equations/125089: There were 166 paid admissions to a game. The price was $2.00 for aduls and $0.75 for children. The amount taken in was $293.25. How many adults and how many children attended? 1 solutions
Answer 91706 by checkley71(8403) on 2008-02-05 16:58:19 (Show Source):
You can put this solution on YOUR website!A+C=166 OR A=166-C
2A+.75C=293.25 NOW REPLACE A WITH (166-C) & SOLVE FOR C.
2(166-C)+.75C=293.25
332-2C+.75C=293.25
-1.25C=293.25-332
-1.25C=-38.75
C=-38.75/-1.25
C=31 THE NUMBER OF CHILDREN.
166-31=135 THE NUMBER OF ADULTS.
PROOF
2*135+.75*31=293.25
270+23.25=293.25
293.25=293.25
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Linear-equations/125070: Please help me to solve this problem.
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M (2,4 ) is the midpoint of RS. If S has coordinates (5,0 ) find the distance from R to S. 1 solutions
Answer 91696 by checkley71(8403) on 2008-02-05 16:14:14 (Show Source):
You can put this solution on YOUR website!THE DISTANCE BETWEEN X=5 & X=2 IS 5-2=3.
SO THE DISTANCE BETWEEN M & R IS ALSO 3 OR 2-3=-1 THE X COORDINATE FOR THE R POINT.
THE DISTANCE BETWEEN Y=0 & Y=4 IS 4-0=4.
SO THE DISTANCE BETWEEN M & R IS ALSO 4 0R 4+4=8 THE Y COORDINATE FOR THE R POINT.
THUS WE HAVE R=(-1,8)
THE DISTANCE BETWEEN (-1,8) & (5,0) IS
5+1=6 FOR THE X AXIS.
8-0=8 FOR THE Y AXIS.
SO WE HAVE A RIGHT TRIANGLE WITH SIDES EQUAL TO 6 & 8.
NOW WE FIND THE HYPOTENUSE (DISTANCE BETWEEN R&S).
6*2+8*2=RS^2
36+64=RS^2
100=RS^2
RS=SQRT100
RS=10 ANSWER FOR THE DISTANCE BETWEEN R & S.
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Rectangles/125064: 17.
Write an equation for a line perpendicular to Y=2/3x-5which contains point (2,4)
(Points: 1)
y = 2/3x + 4
y = -3/2x + 4
y = -3/2x + 7
y = 2x + 6
is the answer C
1 solutions
Answer 91680 by checkley71(8403) on 2008-02-05 15:28:06 (Show Source):
You can put this solution on YOUR website!Y=2X/3-5 (RED LINE).
THIS LINE HAS A SLOPE OF 2/3. THUS A PERPENDICULAR LINE HAS A SLOPE OF -3/2.
4=-3/2*2+b
4=-3+b
b=4+3
b=7 IS THE Y INTERCEPT.
THUS THE EQUATION FOR THIS LINE IS:
Y=-3X/2+7 (GREEN LINE).
YES THE ANSWER IS (C).
 (graph 200x200 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = 2x/3 -5 and y = -3x/2 +7).
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