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checkley71 answered: 8399 problems
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Equations/125224: Each year, your school organizes a carnival to raise money for a class trip. This year, a total of 1026 people attended the carnival.Last year,a total of 950 people attended the carnival.By what percent did the attendance increase from last year to this year.

Any help with this equation would be Greatly appreciated:}
1 solutions

Answer 91773 by checkley71(8403) About Me  on 2008-02-06 09:09:12 (Show Source):
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1026/950=1.08 OR AN 8% INCREASE IN ATTENDANCE.


Quadratic_Equations/125219: a number increased by twice the square root is 48. what is this number
1 solutions

Answer 91772 by checkley71(8403) About Me  on 2008-02-06 09:07:19 (Show Source):
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X+2SQRTX=48
2SQRTX=48-X
NOW SQUARE BOTH SIDES OF THE EQUATION.
4X=2304-96X+X^2
X^2-96X-4X+2304=0
X^2-100X+2304=0
(X-36)(X-64)=0
X-36=0
X=36 ANSWER.
PROOF
36+2SQRT36=48
36+2*6=48
36+12=48
48=48


Quadratic_Equations/125220:
looked like a rectangle is 300 cm^2. the difference between length and width is 13 cm. find the lenght of the diagonal
1 solutions

Answer 91771 by checkley71(8403) About Me  on 2008-02-06 08:50:47 (Show Source):
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L=W+13
300=W(W+13)
300=W^2+13W
W^2+13W-300=0
(W-12)(W+25)
W-12=0
W=12cmNSWER FOR THE WIDTH.
L=12+13=25cm R THE LENGTH.
THE DIAGONAL IS C
A^2+B^2=C^2
12^2+25^2C^2
144+625=C^2
769=C^2
C=SQRT769
C=27.73cm IS THE LENGTH OF THE DIAGONAL.


Graphs/125119:
Please Help Me With this Equation y-20=5%2F8%284%29%2Bb
1 solutions

Answer 91728 by checkley71(8403) About Me  on 2008-02-05 19:11:54 (Show Source):
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Y-20=5/(8*4)+b
Y-20=5/32+b
Y=5/32+20+b
Y=(5+20*32)/32+b
y=(5+640)/32+b
Y=645/32+b
Y=645/32+b ANSWER.


Radicals/125107:
PLEASE HELP ME!!!
Simplify. write in lowest term
1)sqrt 45/125
Simplify. Assume the variable x represents a positive real number
2)sqrt 16x^14
Rewrite the following in simplified radical form.
3)sqrt 27
Rewrite the following in simplified radical form. Assume all variables represent positive real numbers.
4)Sqrt 50y^12
Solve for z. Where z is a real number
5)sqrt z-9=2
THANK YOU IN ADVANCE!!!

1 solutions

Answer 91725 by checkley71(8403) About Me  on 2008-02-05 18:59:17 (Show Source):
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1) SQRT45/125=SQRT.36=.6 ANSWER.
2) SQRT16X^14=4X^7 ANSWER.
3) SQRT27=3SQRT3 ANSWER.
4) SQRT50Y^12=5Y^6SQRT2 ANSWER.
5) SQRTZ-9=2 OR SQRTZ=2+9 OR SQRTZ=11 OR Z=11^2 OR Z=121 ANSWER.


expressions/125110: PLEASE HELP

The lenght of a rectangle is 1ft more then twice its width, and the area of the rectangle is 45ft^2. I am trying to find the diensions of the rectangle.
Length _____ft
Width _____ft
THANK YOU IN ADVANCE
1 solutions

Answer 91724 by checkley71(8403) About Me  on 2008-02-05 18:50:45 (Show Source):
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L=2W+1
AREA=L*W
45=(2W+1)W
45=2W^2+W
2W^2+W-45=0
(2W-9)(W+5)+0
2W-9=0
2W=9
W=9/2
W=4.5 FEET ANSWER FOR THE WIDTH.
L=2*4.5+1
L=9+1
L=10 FEET ANSWER FOR THE LENGTH.
PROOF
4.5*10=45
45=45


Expressions-with-variables/125113: How do you know if an expression has infinitely many solutions?
1 solutions

Answer 91721 by checkley71(8403) About Me  on 2008-02-05 18:40:40 (Show Source):
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AN EXPRESSION THAT HAS MORE UNKNOWNS THAN EQUATIONS FITS THIS CRITERIA.
EXAMPLE:
2X+3Y=8
X COULD BE=1 THEN Y=2. 2*1+3*2=8 OR 2+6=8 OR 8=8.
OR X COULD BE=2 THEN Y=4/3. 2*2+3*4/3=8 OR 4+4=8 OR 8=8.
OR X COULD BE=10 THEN Y=-4. 2*10+3*-4=8 OR 20-12=8 OR 8=8.
YOU CAN SEE HOW AN INFINITE NUMBER OF SOLUTIONS ARE POSSIBLE.
EVERY DIFFERENT X VALUE CREATES A CORRESPONDING DIFFERENT VALUE FOR Y.


Distributive-associative-commutative-properties/125112: factor:

x^2-10x+24
1 solutions

Answer 91718 by checkley71(8403) About Me  on 2008-02-05 18:32:17 (Show Source):
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X^2-10X+24=0
(X-12)(X+2)=0
X-12=0
X=12 ANSWER.
X+2=0
X=-2 ANSWER.


Distributive-associative-commutative-properties/125111: factor:
a^2+11a+18
1 solutions

Answer 91717 by checkley71(8403) About Me  on 2008-02-05 18:30:10 (Show Source):
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A^2+11A+18=0
(A+9)(A+2)=0
A+9=0
A=-9 ANSWER.
A+2=0
A=-2 ANSWER.


Quadratic_Equations/125099:
1.) 2x^2 - 5x – 10 = 0
2.) 3x^2 - 8x + 5 = 0
1 solutions

Answer 91716 by checkley71(8403) About Me  on 2008-02-05 17:41:03 (Show Source):
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1) 2x^2-5x-10=0 using the quadratic equation we get:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(5+-sqrt[-5^2-4*2*-10])/2*2
x=(5+-sqrt[25+80])/4
x=(5+-sqrt105)/4
x=(5+-10.25)/4
x=(5+10.25)/4
x=15.25/4
x=3.81 answer.
x=(5-10.25)/4
x=-5.25/4
x=-1.31 answer.
-------------------------------------------
2) 3x^2-8x+5=0
(3x-5)(x-1)=0
3x-5=0
3x=5
x=5/3 answer.
x-1=0
x=1 answer.


Linear-equations/125096: Find the slope of the line 3y+8=0
1 solutions

Answer 91715 by checkley71(8403) About Me  on 2008-02-05 17:31:11 (Show Source):
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3y+8=0
3y=8
y=8/3 The slope of this line is 0. Or an horizontal line through the point (0,8/3)
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+8%2F3%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = 8/3).


Linear-equations/125097: Graph y equals three-fifths x
1 solutions

Answer 91714 by checkley71(8403) About Me  on 2008-02-05 17:27:48 (Show Source):
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Y=3X/5
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+3x%2F5%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y =3x/5).


Linear-equations/125095:
Find the slope of the line through the points (10, -7) and (-3, -2)
1 solutions

Answer 91713 by checkley71(8403) About Me  on 2008-02-05 17:25:45 (Show Source):
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SLOPE=(-2+7)/(-3-10)=5/-13 OR -5/13 ANSWER.


Money_Word_Problems/125079: Cofee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture?
1 solutions

Answer 91712 by checkley71(8403) About Me  on 2008-02-05 17:23:45 (Show Source):
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12X+9(100-X)=11.25*100
12X+900-9X=1125
3X=1125-900
3X=225
X=225/3
X=75 POUNDS OF $12 COFFEE BEANS.
100-75=25 POUNDS OF $9 COFFEE.
PROOF.
12*75+9*25=1125
900+225=1125
1125=1125


Miscellaneous_Word_Problems/125094: In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many voted did each candidate receive.
1 solutions

Answer 91711 by checkley71(8403) About Me  on 2008-02-05 17:14:59 (Show Source):
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X+(X+220)=810
2X+220=810
2X=810-220
2X=590
X=590/2
X=295 ANSWER. FOR THE LOSSER'S NUMBER OF VOTES.
295+220=515 ANSWER FOR THE WINNER'S NUMBER OF VOTES.
PROOF
295+515=810
810=810


Polynomials-and-rational-expressions/125084: Please help me solve this equation
Solve by removing factors of 2
36y^12/40y^9
1 solutions

Answer 91710 by checkley71(8403) About Me  on 2008-02-05 17:10:19 (Show Source):
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36Y^12/40Y^9 REDUCE BY DIVIDING THE INTEGERS BY 4 & THE Y TERMS BY Y^9
9Y^3/10 ANSWER.


Linear-systems/125088: This question is from textbook intermediate algebra


4x-2y=42 5x+3y=25
1 solutions

Answer 91708 by checkley71(8403) About Me  on 2008-02-05 17:05:44 (Show Source):
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MULTIPLY THE FIRST EQUATION BY 3 & THE SECOND EQUATION BY 2 & THEN ADD.
12X-6Y=126
10X+6Y=50
-------------------------------
22X=176
X=176/22
X=8 ANSWER.
4*8-2Y=42
32-2Y=42
-2Y=42-32
-2Y=10
Y=10/-2
Y=-5 ANSWER.
PROOF:
5*8+3*-5=25
40-15=25
25=25


Systems-of-equations/125089: There were 166 paid admissions to a game. The price was $2.00 for aduls and $0.75 for children. The amount taken in was $293.25. How many adults and how many children attended?
1 solutions

Answer 91706 by checkley71(8403) About Me  on 2008-02-05 16:58:19 (Show Source):
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A+C=166 OR A=166-C
2A+.75C=293.25 NOW REPLACE A WITH (166-C) & SOLVE FOR C.
2(166-C)+.75C=293.25
332-2C+.75C=293.25
-1.25C=293.25-332
-1.25C=-38.75
C=-38.75/-1.25
C=31 THE NUMBER OF CHILDREN.
166-31=135 THE NUMBER OF ADULTS.
PROOF
2*135+.75*31=293.25
270+23.25=293.25
293.25=293.25


Numeric_Fractions/125080: Please help me solve this equation
Add, first finding the LCD
4/25+1/30+2/625
1 solutions

Answer 91705 by checkley71(8403) About Me  on 2008-02-05 16:51:47 (Show Source):
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4/25+1/30+2/625 THE LCD IS 3750.
(4*150+1*125+2*6)/3750
(600+25+12)/3750
637/3750 ANSWER.


Polynomials-and-rational-expressions/125078: Please help me solve this equation"
Multiply and simplify
7y^4/2y * 3/y
1 solutions

Answer 91704 by checkley71(8403) About Me  on 2008-02-05 16:28:11 (Show Source):
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(7Y^4/2Y)(3/Y)
(7Y^3/2)(3/Y)
21Y^3/2Y
21Y^2/2 ANSWER.


Systems-of-equations/125067: Calvin paid his $1.35 skate rental with dimes and nickels only. There were 19 coins in all. How many of each coin were there?
1 solutions

Answer 91702 by checkley71(8403) About Me  on 2008-02-05 16:25:07 (Show Source):
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N+D=19 N=19-D
.10D+.05(19-D)=1.35
.10D+.95-.05D=1.35
.05D=1.35-.95
.05D=.40
D=.40/.05
D=8 DIMES.
19-8=11 NICKELS.
PROOF
.10*8+.05*11=1.35
.80+.55=1.35
1.35=1.35


Mixture_Word_Problems/125072: This question is from textbook algebra 1
33 1/3% of a number is 3 2/3. Find the number.
1 solutions

Answer 91699 by checkley71(8403) About Me  on 2008-02-05 16:17:05 (Show Source):
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1/3*X=3 2/3
X/3=11/3 CROSS MULTIPLY
3X=3*11
3X=33
X=33/3
X=11 ANSWER FOR THE NUMBER.


Linear-equations/125070: Please help me to solve this problem.
__
M (2,4 ) is the midpoint of RS. If S has coordinates (5,0 ) find the distance from R to S.
1 solutions

Answer 91696 by checkley71(8403) About Me  on 2008-02-05 16:14:14 (Show Source):
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THE DISTANCE BETWEEN X=5 & X=2 IS 5-2=3.
SO THE DISTANCE BETWEEN M & R IS ALSO 3 OR 2-3=-1 THE X COORDINATE FOR THE R POINT.
THE DISTANCE BETWEEN Y=0 & Y=4 IS 4-0=4.
SO THE DISTANCE BETWEEN M & R IS ALSO 4 0R 4+4=8 THE Y COORDINATE FOR THE R POINT.
THUS WE HAVE R=(-1,8)
THE DISTANCE BETWEEN (-1,8) & (5,0) IS
5+1=6 FOR THE X AXIS.
8-0=8 FOR THE Y AXIS.
SO WE HAVE A RIGHT TRIANGLE WITH SIDES EQUAL TO 6 & 8.
NOW WE FIND THE HYPOTENUSE (DISTANCE BETWEEN R&S).
6*2+8*2=RS^2
36+64=RS^2
100=RS^2
RS=SQRT100
RS=10 ANSWER FOR THE DISTANCE BETWEEN R & S.


Graphs/125044:

Evaluate 2m-5n/n+3p if m = –2, n = 4, and p = –1.

1 solutions

Answer 91691 by checkley71(8403) About Me  on 2008-02-05 16:01:43 (Show Source):
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2M-5N/N+3P
(2*-2)-(5*4/4)+(3*-1)
-4-5-3=-12 ANSWER.


Graphs/125038: This question is from textbook Structure and Method Book 1
3x+y=5
1 solutions

Answer 91684 by checkley71(8403) About Me  on 2008-02-05 15:36:16 (Show Source):
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3X+Y=5
Y=-3X+5 ANSWER. IF THIS IS A LINE EQUATION.


Expressions-with-variables/125041: This question is from textbook Structure and Method Book 1
2x+y=28
1 solutions

Answer 91683 by checkley71(8403) About Me  on 2008-02-05 15:35:08 (Show Source):
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2X=Y=28
Y=-2X+28 IF THIS IS A LINE EQUATION THEN THIS IS THE ANSWER.


Linear_Equations_And_Systems_Word_Problems/125045:
Use the associative property of addition to write an expression
that is equivalent to the following expression.
(9 + 20) + 19

1 solutions

Answer 91682 by checkley71(8403) About Me  on 2008-02-05 15:33:18 (Show Source):
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(9+20)+19
9+(20+19)


Equations/125051: 4 2nd power + 2 x 7 – (5 x 4 – 15)
1 solutions

Answer 91681 by checkley71(8403) About Me  on 2008-02-05 15:31:22 (Show Source):
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4^2+2*7-(5*4-15)
16+14-(20-15)
30-5=25 ANSWER.


Rectangles/125064: 17.

Write an equation for a line perpendicular to Y=2/3x-5which contains point (2,4)

(Points: 1)
y = 2/3x + 4
y = -3/2x + 4
y = -3/2x + 7
y = 2x + 6
is the answer C

1 solutions

Answer 91680 by checkley71(8403) About Me  on 2008-02-05 15:28:06 (Show Source):
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Y=2X/3-5 (RED LINE).
THIS LINE HAS A SLOPE OF 2/3. THUS A PERPENDICULAR LINE HAS A SLOPE OF -3/2.
4=-3/2*2+b
4=-3+b
b=4+3
b=7 IS THE Y INTERCEPT.
THUS THE EQUATION FOR THIS LINE IS:
Y=-3X/2+7 (GREEN LINE).
YES THE ANSWER IS (C).
+graph%28+200%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+2x%2F3+-5%2C+y+=+-3x%2F2+%2B7%29+ (graph 200x200 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = 2x/3 -5 and y = -3x/2 +7).


expressions/125065: I am trying to simplify the following
v%5E6u%5E2%2Fvu%5E4
1 solutions

Answer 91677 by checkley71(8403) About Me  on 2008-02-05 15:18:27 (Show Source):
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V^6U^2/VU^4=V^5/U^2


expressions/125062: I am trying to write this without parentheses




%28u%5E2%2F-3v%29%5E2 %28%28-3%29y%5E2%2Fz%5E3%29%5E2

1 solutions

Answer 91675 by checkley71(8403) About Me  on 2008-02-05 15:16:32 (Show Source):
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[U^2/-3V]^2=U^2/9V^2 ANSWER.
[((-3)Y^2/Z^3)^2=9Y^4/Z^6 ANSWER.