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15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629, >>NextAge_Word_Problems/259510: Mike and Jay are brothers. Mike is 33. This is 3 times as old as Jay was when Mike was the age that Jay is today.
How old is Jay?
1 solutions
Answer 191045 by ankor@dixie-net.com(15628) on 2010-01-21 21:26:31 (Show Source):
You can put this solution on YOUR website!Mike and Jay are brothers. Mike is 33. This is 3 times as old as Jay was when Mike was the age that Jay is today.
How old is Jay?
:
let j = Jay's present age
33-j = the difference in their ages
:
"This is 3 times as old as Jay was when Mike was the age that Jay is today.
33 = 3(j - (33-j))
:
33 = 3(j - 33 + j)
:
33 = 3(2j - 33)
:
33 = 6j - 99
:
33 + 99 = 6j
:
132 = 6j
j = 
j = 22 yrs is Jay's present age
|
Trigonometry-basics/259535: How many revolutions will a car wheel of diameter 28 inches make over a period of half an hour if the car is traveling at 60 miles per hour? round your answer to the nearest tenth. 1 solutions
Answer 191042 by ankor@dixie-net.com(15628) on 2010-01-21 21:15:19 (Show Source):
You can put this solution on YOUR website!How many revolutions will a car wheel of diameter 28 inches make over a period of half an hour
if the car is traveling at 60 miles per hour? round your answer to the nearest tenth.
:
No. of inches traveled in 30 min at 60 mph/wheel circumference
:
 = 21,608.7 revolutions
|
Average/259537: Adam tried to compute the average of his 7 test scores. He mistakenly divided the
correct sum of all of his test scores by 6, which yielded 84. What is Adam’s correct
average test score? 1 solutions
Answer 191026 by ankor@dixie-net.com(15628) on 2010-01-21 20:30:55 (Show Source):
You can put this solution on YOUR website!Adam tried to compute the average of his 7 test scores.
He mistakenly divided the correct sum of all of his test scores by 6, which yielded 84.
What is Adam’s correct average test score?
:
His total must have been: 6 * 84 = 504
 = 72 is his correct score, (a big disappointment no doubt)
|
Radicals/259287: Please help with an algebra application with carburetor open mm's and rpm's. I need to reverse this formula with the existing p=4480 and D=84 for the following, and instead of p=4480 as the result, need D=84 as the result.
Thank you very much!
D(p)=0.75√2.8p
D(p)=(3/4)(√14/5)p
D*2=(9/16)(14/5)p
p=(16/9)(5/14)D^2
p=(16/9)(5/14)(84)^2
p=4480 1 solutions
Answer 191023 by ankor@dixie-net.com(15628) on 2010-01-21 20:24:55 (Show Source):
You can put this solution on YOUR website!Please help with an algebra application with carburetor open mm's and rpm's.
I need to reverse this formula with the existing p=4480 and D=84 for the following, and instead of p=4480 as the result, need D=84 as the result.
:
I assume you want to solve for p when you know d
:
The original formula
 = d
:
divide both sides by .75
 =
 = 1.33d
:
Square both sides
2.8p = (1.33d)^2
2.8p = 1.778d^2
:
Divide both sides by 2.8
p = 
:
You can check this: substitute 84 for d and confirm that p = 4480
|
Equations/259520: You have a rectangular swimming pool 20 ft. by 10 ft, and a uniform depth of 8 ft. You want to fill the pool to the top. You calculate that it will take 4 hours to fill the pool. It actually takes you 4.5 hours to fill the pool. You suspect the pool is leaking. How much water has leaked from the pool during the 4.5 hours? Assuming a uniform filling rate, and neglecting evaporation, what is the leakage rate (to the nearest gal. per minute)? (1 cu. ft. =7.5 gal.) 1 solutions
Answer 191013 by ankor@dixie-net.com(15628) on 2010-01-21 20:01:20 (Show Source):
You can put this solution on YOUR website!You have a rectangular swimming pool 20 ft. by 10 ft, and a uniform depth of 8 ft.
You want to fill the pool to the top.
You calculate that it will take 4 hours to fill the pool.
It actually takes you 4.5 hours to fill the pool.
You suspect the pool is leaking. How much water has leaked from the pool during the 4.5 hours?
Assuming a uniform filling rate, and neglecting evaporation, what is the leakage rate (to the nearest gal. per minute)? (1 cu. ft. =7.5 gal.)
:
Find out the total gallons in the pool
:
20 * 10 * 8 * 7.5 = 12,000 gallons
:
Find the gallons/min pumped to pump 12000 gallons
 = 50 gal.min
:
Find the number of gal pumped in the extra 30 min time
30 * 50 = 1500 gal
that amt in a 4.5 hr period:
 = 5.556 ~ 6 gal/min leak
:
:
Check it this way on a calc:
4.5*60*(50-5.556) = 11999.88 ~ 12000
|
Miscellaneous_Word_Problems/259462: a charter company will provide for a fare of $60 each for 20 or fewer passengers. for each passenger in excess of 20, the fare is decreased $2 per person for everyone what number of passengers will produce the greatest revenue for the company
OHH I REALLY NEED HELP WITH THIS!PLEASE! 1 solutions
Answer 191006 by ankor@dixie-net.com(15628) on 2010-01-21 19:39:57 (Show Source):
You can put this solution on YOUR website!a charter company will provide for a fare of $60 each for 20 or fewer passengers.
for each passenger in excess of 20, the fare is decreased $2 per person for everyone what number of passengers will produce the greatest revenue for the company
:
Let x = no. of passengers greater than 20
:
Revenue = no. of passengers * price per passenger
r = (20+x)*(60-2x)
FOIL
r = 1200 - 40x + 60x - 2x^2
A quadratic equation
-2x^2 + 20x + 1200 = 0
:
We can find x that gives the max revenue by finding the axis of symmetry; x = -b/(2a)
In this equation a = -2; b = 20
x = 
x = 
x = +5
;
We can say 25 passengers will give max revenue
|
Numbers_Word_Problems/259482: I am stuck on my Algebra question and i need help this is it... 'Find four consecutive integers such that the sum of the two greatest is 17 less than twice the sum of the two smallest.' 1 solutions
Answer 191003 by ankor@dixie-net.com(15628) on 2010-01-21 19:19:39 (Show Source):
You can put this solution on YOUR website!'Find four consecutive integers
x, (x+1), (x+2), (x+3
:
such that the sum of the two greatest is 17 less than twice the sum of the two smallest.'
x+2 + x+3 = 2(x + x+1) - 17
:
2x + 5 = 2(2x + 1) - 17
;
2x + 5 = 4x + 2 - 17
:
2x + 5 = 4x - 15
:
5 + 15 = 4x - 2x
:
20 = 2x
x = 
x = 10, 11, 12, 13 are the 4 consecutive numbers
;
:
Check solution:
13 + 12 = 2(11+10) - 17
25 = 2(21) - 17
25 = 42 - 17
|
Trigonometry-basics/259102: To the nearest three decimal places:
(a) Find the length of the arc that subtends the given central angle 3.5 on a circle of diameter 177 cm.
(b) Find the area of the sector defined by the above information. 1 solutions
Answer 191000 by ankor@dixie-net.com(15628) on 2010-01-21 19:04:39 (Show Source):
You can put this solution on YOUR website!(a) Find the length of the arc that subtends the given central angle 3.5 on a circle of diameter 177 cm.
:
 = .108 cm
:
(b) Find the area of the sector defined by the above information.
:
 = .096 sq/cm
|
Money_Word_Problems/258806: A charter bus company has determined that the cost of providing x people a tour is
C(x) = 180.00 + 2.50 x.
A full tour is 60 people. The cost of a ticket is $15.00 plus $0.25 for each unsold ticket. Determine (a) the revenue function, (b) the profit function, (c) the company’s maximum profit, and (d) the number of ticket sales that yields the maximum profit.
1 solutions
Answer 190926 by ankor@dixie-net.com(15628) on 2010-01-21 14:39:18 (Show Source):
You can put this solution on YOUR website!A charter bus company has determined that the cost of providing x people a tour is
C(x) = 180.00 + 2.50x.
A full tour is 60 people. The cost of a ticket is $15.00 plus $0.25 for each unsold ticket.
Determine
(a) the revenue function,
r = x(.25(60-x)+15)
r = x(15 -.25x + 15)
r = x(30-.25x)
r = -.25x^2 + 30x
:
(b) the profit function,
p = r - c
p = -.25x^2 + 30x - (180+2.5x)
p = -.25x^2 + 30x - 180 - 2.5x
p = -.25x^2 + 27.5x - 180
:
(c) the company’s maximum profit,
Find the axis of symmetry on the above equation, x = -b/(2a); a=-.25, b=27.5
x = 
x = 55 passengers for max profit
Find actual profit, replace x with 55
p = -.25(55^2) + 27.5(55) - 180
p = -.25(3025) + 1512.5 - 180
p = -756.25 + 1512.5 - 180
p = $576.25 profit at 55 passengers
:
(d) the number of ticket sales that yields the maximum profit.
We did that when we determined the profit; x = 55 passengers
:
It may be interesting to see this graphically

where
x = no. of passengers
y = $$
Profit is green, revenue is purple. the difference between them represents the cost
:
Note that graph is not valid past x=60
|
Evaluation_Word_Problems/259068: The OfficeJet Printer can copy Maria's document in 8 minutes. The LaserJet printer can copy the same document in 12 minutes. If the two machines work together, how long would it take to copy the document? 1 solutions
Answer 190913 by ankor@dixie-net.com(15628) on 2010-01-21 13:55:51 (Show Source):
You can put this solution on YOUR website!The OfficeJet Printer can copy Maria's document in 8 minutes.
The LaserJet printer can copy the same document in 12 minutes.
If the two machines work together, how long would it take to copy the document?
:
Let t = time required when both machines work together
Let the complete job = 1; (copying the document)
:
A typical shared work equation:
 +  = 1
Clear the denominators, multiply by 24, results:
3t + 2t = 24(1)
5t = 24
t = 
t = 4.8 min or 4 min + .8(60) = 48 seconds
;
:
Check solution
4.8/8 + 4.8/12 =
.6 + .4 = 1
|
Linear-equations/259155: Hi please help me and explain thorouly on how to find the equation of the line that contains: Point (0,5), M=2.(PLEASE SHOW ME STEP BY STEP CAUSE IM STUCK ON THIS) And one more problem; Is the line x= -2 perpendicular to the line y= 3? Please expalin!
Thanks I really appreciate it. 1 solutions
Answer 190907 by ankor@dixie-net.com(15628) on 2010-01-21 13:15:54 (Show Source):
You can put this solution on YOUR website! find the equation of the line that contains: Point (0,5), M=2.
:
When you are given the point and the slope use the "point/slope formula", which is:
y - y1 = m(x - x1)
:
in your problem: x1=0, y1=5, m=2, substituting in the above equation:
y - 5 = 2(x - 0)
y - 5 = 2x - 0; multiply what's inside the brackets by 2
or just
y - 5 = 2x
add 5 to both sides
y = 2x + 5; the equation of the given line
:
And one more problem; Is the line x= -2 perpendicular to the line y= 3? Please explain
when x is given a single value, it is a vertical line going thru -2
when y is given a single value, it is a horizontal line going thru +3
A vertical line is perpendicular to a horizontal line, right??
:
Did this shed some light on this stuff for you?
|
Mixture_Word_Problems/259238: If you want to mix 50lb of nuts worth $2.00 per lb with some nuts worth $6.00 per lb to make a mixture worth $5.00 per lb. How many pounds of $6.00 nuts must you use?
That is the question. How do I turn this into an equation or whatever I need to do? 1 solutions
Answer 190901 by ankor@dixie-net.com(15628) on 2010-01-21 12:55:21 (Show Source):
You can put this solution on YOUR website!If you want to mix 50lb of nuts worth $2.00 per lb with some nuts worth $6.00 per lb to make a mixture worth $5.00 per lb.
How many pounds of $6.00 nuts must you use?
:
A typical mixture equation, learn this method and you can do most of these in the future
:
Let x = no. of lb of $6 nut required
then you know the resulting mixture = (x + 50)
:
2(50) + 6x = 5(x + 50)
100 + 6x = 5x + 250
6x - 5x = 250 - 100
x = 150 lb of $6 nuts
:
:
Check your solution in the original equation
2(50) + 6(150) = 5(150 + 50)
100 + 900 = 5(200); confirms the solution
:
:
That's not so hard, is it?
|
Geometry_Word_Problems/259071: A square's side is increased by 10 yards, which corresponds to an increase in the area by 400 square yards. How many yards is the side of the initial square? 1 solutions
Answer 190774 by ankor@dixie-net.com(15628) on 2010-01-20 21:51:28 (Show Source):
You can put this solution on YOUR website!A square's side is increased by 10 yards, which corresponds to an increase in the area by 400 square yards.
How many yards is the side of the initial square?
:
Let x = side of the original square
then
(x+10) = side of the larger square
:
Large area - small area = 400 sq/yd
(x+10)^2 - x^2 = 400
FOIL
x^2 + 20x + 100 - x^2 = 400
20x = 400 - 100
20x = 300
x = 
x = 15 yds is the original square
;
:
Check it:
25^2 - 15^2 =
625 - 225 = 400
|
Circles/258990: The area of a right triangle is 6. The sum of the lengths of the two sides adjacent to the right angle of the triangle is 12. What is the length of the hypotenuse of the triangle? 1 solutions
Answer 190764 by ankor@dixie-net.com(15628) on 2010-01-20 21:29:21 (Show Source):
You can put this solution on YOUR website!The area of a right triangle is 6.
The sum of the lengths of the two sides adjacent to the right angle of the triangle is 12.
What is the length of the hypotenuse of the triangle?
:
Let x = 1 leg of the right triangle (let it be the base)
then
(12-x) = the other leg (let it be the height)
:
Area: .5*b*h = 6
.5x*(12-x) = 6
6x - .5x^2 = 6
-.5x^2 + 6x - 6 = 0
Multiply by -2
x^2 - 12x + 12 = 0
Using the quadratic formula: x=1.1 and x=10.9, the two sides of the triangle
:
Find the hypotenuse
h = 
h = 
h = 
h = 10.96 is the hypotenuse
:
:
Check by finding the area using the values: .5 * 1.1 * 10.9 = 5.995 ~ 6
|
Travel_Word_Problems/258710: Wilma drove at an average speed of 35 mph from her home in City A to visit her sister in City B.
She stayed in City B 20 hours, and on the trip back averaged 55 mph. She returned home 50 hours after leaving.
We have to determine how many miles x is it from City A to City B. 1 solutions
Answer 190752 by ankor@dixie-net.com(15628) on 2010-01-20 21:03:44 (Show Source):
You can put this solution on YOUR website!Wilma drove at an average speed of 35 mph from her home in City A to visit her sister in City B.
She stayed in City B 20 hours, and on the trip back averaged 55 mph. She returned home 50 hours after leaving.
We have to determine how many miles x is it from City A to City B
:
Obviously, we are only interested in her actual travel time
50 - 20 = 30 hrs total travel time
:
x = the miles between city A and B
:
Write a time equation; time = dist/speed
Time there + time back = 30 hrs
 +  = 30
:
Multiply by a common denominator, 385 with do the job
385*  + 385*  = 385(30)
;
Cancel the denominators and you have:
11x + 7x = 11550
;
18x = 11550
x = 
x = 641  miles between cities
;
:
Check this on calc; find the total time
641.67/35 + 641.67/55
18.33 + 11.67 = 30 hrs, confirms our solution
|
Mixture_Word_Problems/258985: HElP! I cant figure this out. what equation do i use?
Jim can fill a pool carrying buckets of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together? 1 solutions
Answer 190719 by ankor@dixie-net.com(15628) on 2010-01-20 20:01:44 (Show Source):
You can put this solution on YOUR website!Jim can fill a pool carrying buckets of water in 30 minutes.
Sue can do the same job in 45 minutes.
Tony can do the same job in 1 ½ hours.
How quickly can all three fill the pool together?
:
Let t = time required all working together
:
Change 1.5 hrs to 90 min
:
Let the completed job = 1 (full pool)
:
Each will do a fraction of the job, the three fractions add up to 1
:
 +  +  = 1
Multiply equation by 90 to get rid of the denominators. results:
3t + 2t + t = 90
6t = 90
t = 
t = 15 min all working together
:
:
Check solution on a calc
15/30 + 15/45 + 15/90
.5 + .333 + .167 = 1
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Travel_Word_Problems/259011: A high school student in Seattle, Washington, attends the University of Central Florida. On the way to UCF he took a southern route. After graduation he returned to Seattle via a northern trip. On both trips he had the same average speed. If the southern trek took 48 hours, the northern trek took 53 hours, the northern trek was 285 miles longer, how long was each trip? 1 solutions
Answer 190715 by ankor@dixie-net.com(15628) on 2010-01-20 19:54:08 (Show Source):
You can put this solution on YOUR website!A high school student in Seattle, Washington, attends the University of Central Florida. On the way to UCF he took a southern route.
After graduation he returned to Seattle via a northern trip.
On both trips he had the same average speed.
If the southern trek took 48 hours, the northern trek took 53 hours, the northern trek was 285 miles longer, how long was each trip?
:
Let d = distance of the southern trip
then
(d+285) = distance of the northern trip
:
Write a speed equation, speed = dist/time, (speed same on both trips)
:
 = 
cross multiply
53d = 48(d+285)
:
53d = 48d + 13680
:
53d - 48d = 13680
d = 
d = 2736 mi is the southern route
and
2736 + 285 = 3021 mi is the northern route
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Trigonometry-basics/258995: a truck is moving at a rate of 90 kilometers per hour, and the diameter of its wheels is 1 meter. find the angular speed of the wheels in radians per minute.
I'm confused on how to get the answer. does this question involve the conversion of degrees and radians? please help me solve it. 1 solutions
Answer 190708 by ankor@dixie-net.com(15628) on 2010-01-20 19:38:49 (Show Source):
You can put this solution on YOUR website!a truck is moving at a rate of 90 kilometers per hour, and the diameter of its wheels is 1 meter. find the angular speed of the wheels in radians per minute.
:
Circumference of the wheel
C = 
:
 = 1500 meters/minute
:
Find rpm
 = 3000 radians/minute
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Exponents/258925: Please help me understand this problem: The variable q stand for a prime number. Make a factor tree. Then write the prime factorization without exponents for each expression: 8qtothe2nd 1 solutions
Answer 190681 by ankor@dixie-net.com(15628) on 2010-01-20 18:58:06 (Show Source):
You can put this solution on YOUR website!The variable q stand for a prime number. Make a factor tree. Then write the prime factorization without exponents for each expression: 8qtothe2nd
 prime factors to: 2 * 2 * 2 * q * q
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Polynomials-and-rational-expressions/258805: Hi I need help with this problem.
Simplify the complex expression by multiplying.
i to the 7th power and then in ( ) is 56 over 7i to the 4th. (It's 7i to the 4th power on the bottom of the fraction in parentheses)
Thanks
1 solutions
Answer 190675 by ankor@dixie-net.com(15628) on 2010-01-20 18:41:53 (Show Source):
You can put this solution on YOUR website!Simplify the complex expression by multiplying.
i to the 7th power and then in ( ) is 56 over 7i to the 4th.
(It's 7i to the 4th power on the bottom of the fraction in parentheses
:
Assume this is the problem:

Successive powers of i can be simplified
we know that

and

so we have

-8i
:
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Human-and-algebraic-language/258835: In order for a company to realize a profit in the manufacture and sale of a certain item, the revenue, R, for selling X items must be greater than the cost, C, of producing x items. If R=79.99x and C=61x+1050, for what values of x will this product return profit? 1 solutions
Answer 190601 by ankor@dixie-net.com(15628) on 2010-01-20 16:12:09 (Show Source):
You can put this solution on YOUR website!In order for a company to realize a profit in the manufacture and sale of a certain item, the revenue, R, for selling X items must be greater than the cost, C, of producing x items.
If R=79.99x and C=61x+1050, for what values of x will this product return profit?
:
Profit occurs when Revenue is greater than Cost; R > C
79.99x > 61x + 1050
:
79.99 - 61x > 1050
:
18.99x > 1050
x > 
x > 55.3
We can say it returns a profit when 56 or more items are sold
;
:
Check this when x = 56
79.99(56) = 4,479.44
61(56) + 1050 = 4,466.00
----------------------------
a profit of $13.44
however,
when x = 55 items sold
79.99(55) = 4399.45
61(55) + 1050 = 4405
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a loss of $5.55
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Travel_Word_Problems/258807: Two ships leave the same harbor at the same time. The first ship heads north at 20 miles per hour and the second ship heads west at 15 miles per hour. Write an expression that gives the distance d between ships after t hours. 1 solutions
Answer 190594 by ankor@dixie-net.com(15628) on 2010-01-20 15:53:18 (Show Source):
You can put this solution on YOUR website!Two ships leave the same harbor at the same time.
The first ship heads north at 20 miles per hour and the second ship heads west at 15 miles per hour.
Write an expression that gives the distance d between ships after t hours.
:
This is a pythag problem: c^2 = a^2 + b^2 or
c = 
a = dist traveled in t hrs of the 1st ship
b = dist traveled in t hrs by 2nd ship
c = dist between the two ships after t hrs (d)
;
Dist = speed * time (t)
:
d = 
d = 
d = 
d = 25t is the distance between the ships after t hrs
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Quadratic_Equations/258646: Write a quadratic quation having the given numbers as solutions.
-5 and -1
The quadratic equation is ? = 0
(Type your answer in standard form. Type an expression using x as a variable.)
Thank very much for your help with this problem. 1 solutions
Answer 190589 by ankor@dixie-net.com(15628) on 2010-01-20 15:40:01 (Show Source):
You can put this solution on YOUR website!Write a quadratic equation having the given numbers as solutions.
-5 and -1
These solutions would be derived from factors;
(x+5)(x+1) = 0
FOIL
x^2 + x + 5x + 5 = 0
:
x^2 + 6x + 5 = 0
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Rate-of-work-word-problems/258585: Christopher can paint the interior of his house in 21 hours. If he hires Cynthia to help him they can do the same job together in 15 hours. If he lets Cynthia work alone, how long will it take her to paint the interior of his house?
Enter the exact answer.
Cynthia can paint the house alone in hours.
1 solutions
Answer 190521 by ankor@dixie-net.com(15628) on 2010-01-20 12:37:23 (Show Source):
You can put this solution on YOUR website!Christopher can paint the interior of his house in 21 hours.
If he hires Cynthia to help him they can do the same job together in 15 hours.
If he lets Cynthia work alone, how long will it take her to paint the interior of his house?
:
Let x = time required by Cynthia, alone
:
Let the completed job = 1
Each painter will do a fraction of the job, the two fractions add up to 1
:
A typical shared work equation
 +  = 1
Multiply by 21x, to get rid of the denominators, results
15x + 21(15) = 21x
:
15x + 315 = 21x
:
315 = 21x - 15x
:
315 = 6x
x = 
x = 52.5 hrs by herself
;
:
Check this on a calc
15/21 + 15(52.5) =
.714 + .286 = 1
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Travel_Word_Problems/258762: tina hiked 15 km up a mountain trail. Her return trip along the same trail took 30 minutes less because she was able to increase her speed by 1km/hour . how long did it take her to climb up and down the mountain ?
1 solutions
Answer 190467 by ankor@dixie-net.com(15628) on 2010-01-20 09:40:10 (Show Source):
You can put this solution on YOUR website!tina hiked 15 km up a mountain trail.
Her return trip along the same trail took 30 minutes less because she was able to increase her speed by 1km/hour.
how long did it take her to climb up and down the mountain?
:
Change 30 min to .5 hrs
:
Find the hiking rate first, then find the time:
:
Let r = T's rate up the mt
then
(r+1) = time down the mt
:
Write a time equation; time = dist/speed
:
Time up the mt - time down the mt = .5 hrs
 -  = .5
multiply equation by r(r+1), results
15(r+1) - 15r = .5r(r+1)
:
15r + 15 - 15r = .5r^2 + .5r
Arrange as a quadratic equation
.5r^2 + .5r - 15 = 0
Multiply by 2, get rid of the decimals
r^2 + r - 30 = 0
Factor
(r+6)(r-5) = 0
the positive solution is what we want here
r = 5 km/hr hiking rate up the mt
:
Find the time up:
15/5 = 3 hrs
find the time down
15/6 = 2.5 hrs, (a difference of 30 min)
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Geometry_Word_Problems/258630: i have no type of idea how to find out to solve nothing i appreciate n thank you
a stake is to be driven into the ground away from the base of a 50foot pole,a wire from the stake on the ground to the top of the pole is to be installed at an angle of elevation of 52degrees.

This is like the triangle on the paper being that b is 5o foot pole,A is 52 degress and C is the wire
how far away from the base of the pole should the stake be driven in,to the NEAREST foot? what will be the length of the wire from the stake to the top of the pole, to the NEAREST foot? 1 solutions
Answer 190413 by ankor@dixie-net.com(15628) on 2010-01-19 20:50:48 (Show Source):
You can put this solution on YOUR website!a stake is to be driven into the ground away from the base of a 50foot pole,a wire from the stake on the ground to the top of the pole is to be installed at an angle of elevation of 52degrees.
Photobucket
This is like the triangle on the paper being that b is 5o foot pole,A is 52 degress and C is the wire
how far away from the base of the pole should the stake be driven in,to the NEAREST foot? what will be the length of the wire from the stake to the top of the pole, to the NEAREST foot?
:
Use the tangent of 52 degrees, side adjacent = x; (dist from the stake to the pole)
tan(52) = 
1.27994 = 
x = 
x = 39 ft from the stake to the pole
and
use the sine of 52 degrees, hypotenuse = h (length of the wire)
sin(52) = 
h = 
h = 63 ft is the wire
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Quadratic_Equations/258241: a 16 inch wire cut into two pieces bent into squares find the length if the sum of the areas is 10 in squared 1 solutions
Answer 190199 by ankor@dixie-net.com(15628) on 2010-01-19 09:39:50 (Show Source):
You can put this solution on YOUR website!Let x = side of one square
Let y = side of the other square
;
Write an equation for each phrase
:
a 16 inch wire cut into two pieces bent into squares
4x + 4y = 16
simplify, divide by 4
x + y = 4
x = (4-y)
:
find the length if the sum of the areas is 10 in squared
x^2 + y^2 = 10
Replace x with (4-y)
(4-y)^2 + y^2 = 10
FOIL
16 - 8y + y^2 + y^2 = 10
Arrange as a quadratic equation
2y^2 - 8y + 16 - 10 = 0
2y^2 - 8y - 6 = 0
Simplify divide by 2
y^2 - 4y + 3 = 0
Factor
(y - 1)(y - 3) = 0
Two solutions
y = 1, then x = 3
y = 3, then x = 1
;
;
Check:
4(1) + 4(3) = 16
3^2 + 1^2 = 10
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