Tutor:

New! Get regular updates about newly solved problems via algebra.com's RSS system.

---

Recent problems solved by 'ankor@dixie-net.com'

ankor@dixie-net.com answered: 15609 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629, >>Next

Quadratic_Equations/259988: solve by completing the square: x^2+7/2x=7 1 solutions Answer 191502 by ankor@dixie-net.com(15624)   on 2010-01-23 16:09:38 (Show Source): You can put this solution on YOUR website! Find the value that completes the square = Add to both sides Add the values on the right : which is = find the square root of both sides = +/- Subtract 7/4 from both sides, Extract the square root of 1/16 x = +/- You could write the two solutions; x = and x =

Numeric_Fractions/260067: A shopkeeper is making a triangular sign for his store front, but he must keep the sign under 20 square feet to adhere to zoning laws. If the base of the sign is 20 feet, what is the maximum height of the triangular sign? 1 solutions Answer 191499 by ankor@dixie-net.com(15624)   on 2010-01-23 15:42:37 (Show Source): You can put this solution on YOUR website! keep the sign under 20 square feet to adhere to zoning laws. If the base of the sign is 20 feet, what is the maximum height of the triangular sign? : .5*b*h = A : .5*20*h < 20 : 10h < 20 h < h < 2 ft, height of the sign

Travel_Word_Problems/259998: Suppose Charlie O'Brian of the Braves hits a baseball straight upward at 150ft/sec from a height of 5 ft. How long does it take for the ball to return to earth? 1 solutions Answer 191492 by ankor@dixie-net.com(15624)   on 2010-01-23 15:21:15 (Show Source): You can put this solution on YOUR website! Suppose Charlie O'Brian of the Braves hits a baseball straight upward at 150ft/sec from a height of 5 ft. How long does it take for the ball to return to earth? : Using the equation: h = -16t^2 + 150t + 5, where h = height after t seconds -16t^2 = downward pull of gravity 150t = upward rate of the ball 5 = initial height (where ball was hit) : -16t^2 + 150t + 5 = 0 : Using the quadratic formula: a=-16, b=150; c=5 the positive solution: t ~ 9.41 seconds

Travel_Word_Problems/260051: If car A is traveling at 75 miles per hour for 100 hours and car B is traveling 65 miles per hour for 75 miles which car will arrive at their destination first and how long did each car travel? 1 solutions Answer 191482 by ankor@dixie-net.com(15624)   on 2010-01-23 14:44:38 (Show Source): You can put this solution on YOUR website! If car A is traveling at 75 miles per hour for 100 hours and car B is traveling 65 miles per hour for 75 miles which car will arrive at their destination first and how long did each car travel? : Are you sure this is written out correctly? It does not make sense.

test/259912: 17 Mickey and Minnie both drive the same distance. By driving 25 mph faster, Mickey gets there in 3 hours, while it takes Minnie 5 hours. How fast does each drive? 1 solutions Answer 191479 by ankor@dixie-net.com(15624)   on 2010-01-23 14:34:47 (Show Source): You can put this solution on YOUR website! Mickey and Minnie both drive the same distance. By driving 25 mph faster, Mickey gets there in 3 hours, while it takes Minnie 5 hours. How fast does each drive? : Let s = Minnie's speed then (s+25) = Mickey's speed : They are driving the same dist, write a distance equation: dist = time * speed : Min's dist = Mic's dist 5s = 3(s+25) 5s = 3s + 75 5s - 3s = 75 s = s = 37.5 mph is Minnie's speed then 37.5 + 25 = 62.5 mph is Mickey's speed : ; Prove this by finding the distance of each 3*62.5 = 187.5 mi 5*37.5 = 187.5 mi

Vectors/259557: the area of a square, expressed in square inches, is 165 in inches greater than its perimeter, expressed in inches. what is the length of a side of the square? 1 solutions Answer 191472 by ankor@dixie-net.com(15624)   on 2010-01-23 13:11:08 (Show Source): You can put this solution on YOUR website! the area of a square, expressed in square inches, is 165 in inches greater than its perimeter, expressed in inches. what is the length of a side of the square? : Area = x^2 Perimeter = 4x : x^2 - 4x = 165 : x^2 - 4x - 165 = 0; our old friend, the quadratic equation! Factor (x - 15)(x + 11) = 0 Positive solution is what we want here x = 15 is the length of the square : : Is this true? 15^2 - 4(15) = 225 - 60 = 165

Travel_Word_Problems/259924: Jan rollerskated to Cindy’s house against a strong headwind. She got there in 20 minutes. When she went back home, the tail wind strength was the same as before. That trip took only 8 minutes. How long would it take Jan to ride to her Cindy’s house if there was no wind? 1 solutions Answer 191471 by ankor@dixie-net.com(15624)   on 2010-01-23 13:02:13 (Show Source): You can put this solution on YOUR website! Jan rollerskated to Cindy’s house against a strong headwind. She got there in 20 minutes. When she went back home, the tail wind strength was the same as before. That trip took only 8 minutes. How long would it take Jan to ride to her Cindy’s house if there was no wind? : Let s = her speed with no wind Let w = the force of the wind then (s-w) = her speed against the wind and (s+w) = her speed with the wind : Choose a convenient number for the distance, 40 units : write two distance equations, time * speed = distance 20(s-w) = 40 8(s+w) = 40 Simplify, divide the 1st equation by 20, the 2nd equation by 8 s - w = 2 s + w = 5 ----------addition eliminates w 2s = 7 s = 7/2 s = 3.5 : Find the time at this speed: = 11.43 min with no wind ; : Prove this find the times of each situation When her speed is 3.5 the wind = 1.5 : against: 40/(3.5-1.5) = 20 min with: 40/(3.5+1.5) = 8 min

Percentage-and-ratio-word-problems/259959: A class consisting of 30 girls and 40 boys sponsored a Halloween dance. If 60 percent of the girls and 25 percent of the boys went to the dance, what percent of the entire class went to the dance? a)30 % b) 40 % c) 45 % d) 70 % e) 85 % 1 solutions Answer 191429 by ankor@dixie-net.com(15624)   on 2010-01-23 09:23:14 (Show Source): You can put this solution on YOUR website! A class consisting of 30 girls and 40 boys sponsored a Halloween dance. If 60 percent of the girls and 25 percent of the boys went to the dance, what percent of the entire class went to the dance? : Let x = per cent of entire class (as a decimal) : 70x = .60(30) + .25(40) 70x = 18 + 10 70x = 28 x = 28/70 x = .4 = 40% of the entire class

Quadratic_Equations/259971: Solve using quadratic formula. My book says the answer is 4x^2-2x-7=0 x= x= x= I need help at this point. Thank you 1 solutions Answer 191427 by ankor@dixie-net.com(15624)   on 2010-01-23 09:05:51 (Show Source): You can put this solution on YOUR website! Solve using quadratic formula. My book says the answer is 4x^2-2x-7=0 x= x= x= Note that we can factor to reveal a perfect square inside the radical x= extract the perfect square x= You can cancel both 2's into the 8 x=

Quadratic_Equations/259972: My book says the answer is -5 and -3, where am I missing it? x= x= x= x= x= 1 solutions Answer 191423 by ankor@dixie-net.com(15624)   on 2010-01-23 08:55:21 (Show Source): You can put this solution on YOUR website! My book says the answer is -5 and -3, where am I missing it? , assume the equation should be x^2 - 8x + 15 x= x= x= : Th book is wrong, this would factor to: (x-5)(x-3) = 0 which is: x=5,x=3

Numbers_Word_Problems/259748: a number is less than the sum of twice its opposite and five. find the number 1 solutions Answer 191382 by ankor@dixie-net.com(15624)   on 2010-01-22 22:00:09 (Show Source): You can put this solution on YOUR website! a number is less than the sum of twice its opposite and five. x < -2x + 5) : find the number x + 2x < 5 3x < 5 x < x < 1.67 we can say x = 1

Polynomials-and-rational-expressions/259862: three times a number minus the sum of the number and seven 1 solutions Answer 191381 by ankor@dixie-net.com(15624)   on 2010-01-22 21:52:47 (Show Source): You can put this solution on YOUR website! Equals what? This is incomplete

Expressions-with-variables/259897: solution for: x+2y=7 x+6y=1 (ordered pairs!) 1 solutions Answer 191380 by ankor@dixie-net.com(15624)   on 2010-01-22 21:48:49 (Show Source): You can put this solution on YOUR website! x + 2y = 7 x + 6y = 1 ------------ subtraction eliminates x 0 - 4y = 6 -4y = 6 y = y = -1.5 : Find x using x + 6y = 1 x + 6(-1.5) = 1 x - 9 = 1 x = 1 + 9 x = 10 : The ordered pair 10, -1.5 : : Check solution in the 1st equation x + 2y = 7 10 + 2(-1.5) = 7 10 - 3 = 7, confirms our solution

Numeric_Fractions/259875: Open-top box. Thomas is going to make an open-top box by cutting equal squares from the four corners of an 11 inch by 14 inch sheet of cardboard and folding up the sides. If the area of the base is to be 80 square inches, then what size square should be cut from each corner? 1 solutions Answer 191379 by ankor@dixie-net.com(15624)   on 2010-01-22 21:35:21 (Show Source): You can put this solution on YOUR website! make an open-top box by cutting equal squares from the four corners of an 11 inch by 14 inch sheet of cardboard and folding up the sides. If the area of the base is to be 80 square inches, then what size square should be cut from each corner? : Let x = the side of the 4 squares to be cut from each corner then the dimensions of the base will be: (11-2x) by (14-2x) : Given the area, we have: (11-2x)*(14-2x) = 80 FOIL 154 - 22x - 28x + 4x^2 = 80 : 4x^2 - 50x + 154 - 80 = 0 : A quadratic equation 4x^2 - 50x + 74 = 0 ; simplify divide by 2 2x^2 - 25x + 37 = 0 ; Solve this using the quadratic formula; a=2; b=-25, c=37 you should get the reasonable answer of x = 1.715 inches is the side of the removed squares : : Check this on a calc: enter (11-2(1.715)) * (14-2(1.715)) = 80.015 ~ 80

logarithm/259892: use natural log to solve: 9*2^z=19*11^z solve for z 1 solutions Answer 191364 by ankor@dixie-net.com(15624)   on 2010-01-22 21:10:24 (Show Source): You can put this solution on YOUR website! 9*2^z = 19 * 11^z solve for z : ln(9) + ln(2^z) = ln(19) + ln(11^z) : 2.197 + z*ln(2) = 2.944 + z*ln(11) : 2.197 + .693z = 2.944 + 2.398z : 2.197 - 2.944 = 2.398z - .693z : -.747 = 1.705z z = z = -.438 ; ; Check on a calc: enter: 9 * 2^-.438 = 6.643 and 19 * 11^-.438 = 6.646, close enough

Equations/259889: I am a parent that didn't get to finish in high school and my son has this problem and i don't know to write the equation out. thank you for your time. Here is the problem. Air Travel: A jet leaves the Chalotte, Noth Carolina, airport traveling at an aveage rate of 564 km/h. Another plane leaves the airport one half hour later traveling at 744 km/h in the same direction. Use an equation to find how long the second jet will take to overtake the first. 1 solutions Answer 191353 by ankor@dixie-net.com(15624)   on 2010-01-22 20:15:51 (Show Source): You can put this solution on YOUR website! A jet leaves the Charlotte, North Carolina, airport traveling at an average rate of 564 km/h. Another plane leaves the airport one half hour later traveling at 744 km/h in the same direction. Use an equation to find how long the second jet will take to overtake the first. : : Change 30 min to .5 hrs : Let t = time required for the faster jet catch up with the 1st jet then (t+.5) = travel time of the slower plane : When this happens, the two planes will have traveled the same distance. : Write a dist equation: dist = speed * time Fast jet dist = slow jet dist 744t = 564(t+.5) 744t = 564t + 282 744t - 564t = 282 180t = 282 t = t = 1.567 hrs or 1 + .567(60) = 1 hr 34 min

Numeric_Fractions/259869: Gone fishing. Debbie traveled by boat 5 miles upstream to fish in her favorite spot. Because of the 4-mph current, it took her 20 minutes longer to get there than to return. How fast will her boat go in still water? 1 solutions Answer 191339 by ankor@dixie-net.com(15624)   on 2010-01-22 19:17:52 (Show Source): You can put this solution on YOUR website! Debbie traveled by boat 5 miles upstream to fish in her favorite spot. Because of the 4 mph current, it took her 20 minutes longer to get there than to return. How fast will her boat go in still water? : Let s = boat speed in still water then (s-4) = speed upstream and (s+4) = speed down stream : Convert 20 min to hrs: 20/60 = hr : Write a time equation: time = Upstream time = downstream time + 20 minutes (1/3 hr) = + : To clear out these denominators, multiply equation by 3(s+4)(s-4) 3(s+4)(s-4)* = 3(s+4)(s-4)* + *3(s+4)(s-4) Results in : 15(s+4) = 15(s-4) + (s+4)(s-4) : 15s + 60 = 15s - 60 + s^2 - 16 : 0 = 15s - 15s - 60 - 60 + s^2 - 16 : 0 = s^2 - 136 : s^2 = 136 s = s = 11.66 mph speed in still water : : Check solution on calc: (speed up = 7.66 and speed down = 15.66) 5/7.66 - 5/15.66 = .3333 which is 1/3 of an hr

Travel_Word_Problems/259861: Towns A and B are 300km apart. A man travels from A to B at a speed of 120km/h and a woman travels from B to A at a speed of 80km/h. The woman begins her journey 15 minutes after the man does. How far away from B will they meet? : Let d = distance traveled by the woman (from town B) Then (300-d) = distance traveled by the man (from town A) : Change 15 min to .25 hrs : Write a time equation: Time = dist/speed Man's travel time = woman's travel time + 15 min (.25 hr) 300-d/120 = d/80 + 1/4 -5d=-540 thereore d=108. They will meet 108km away from B Is that correct? 1 solutions Answer 191334 by ankor@dixie-net.com(15624)   on 2010-01-22 18:34:39 (Show Source): You can put this solution on YOUR website! That is correct, way to go!

Geometry_Word_Problems/259812: The length of a rectangle is 3 times the width. If the length is decreased by 4 m and the width is increased by 1 m. te perimeter will be 66 m. What are the dimensions of the original rectangle? 1 solutions Answer 191313 by ankor@dixie-net.com(15624)   on 2010-01-22 17:15:32 (Show Source): You can put this solution on YOUR website! Write an equation for each statement: : The length of a rectangle is 3 times the width. L = 3W : If the length is decreased by 4 m and the width is increased by 1 m the perimeter will be 66 m. : 2(L-4) + 2(W+1) = 66 2L - 8 + 2W + 2 = 66 2L + 2W - 6 = 66 2L + 2W = 66 + 6 2L + 2W = 72 Simplify, divide by 2 L + W = 36 : What are the dimensions of the original rectangle? Replace L with 3W 3W + W = 36 4W = 36 W = W = 9 m, original width then 3(9) = 27 m original length ; : Check this 2(23) + 2(10) = 46 + 20 = 66

Travel_Word_Problems/259810: Towns A and B are 300km apart. A man travels from A to B at a speed of 120km/h and a woman travels from B to A at a speed of 80km/h. The woman begins her journey 15 minutes after the man does. How far away from B will they meet? Can I have the eguations of this problem? 1 solutions Answer 191290 by ankor@dixie-net.com(15624)   on 2010-01-22 15:57:19 (Show Source): You can put this solution on YOUR website! Towns A and B are 300km apart. A man travels from A to B at a speed of 120km/h and a woman travels from B to A at a speed of 80km/h. The woman begins her journey 15 minutes after the man does. How far away from B will they meet? : Let d = distance traveled by the woman (from town B) Then (300-d) = distance traveled by the man (from town A) : Change 15 min to .25 hrs : Write a time equation: Time = dist/speed Man's travel time = woman's travel time + 15 min (.25 hr) = + .25 : That's the equation, if you need further help, let me know via student comment I'll edit this and include the solution

Travel_Word_Problems/259807: A man rides a bike a straight distance at a speed of 10 miles per hour. He came back the same way, traveling the same distance at a speed of 20 miles per hours. What was the man's total number of miles for the trip back and forth if his total traveling time was one hour?? Thank you!!! 1 solutions Answer 191279 by ankor@dixie-net.com(15624)   on 2010-01-22 15:38:16 (Show Source): You can put this solution on YOUR website! A man rides a bike a straight distance at a speed of 10 miles per hour. He came back the same way, traveling the same distance at a speed of 20 miles per hours. What was the man's total number of miles for the trip back and forth if his total traveling time was one hour?? : Let d = no. of miles one-way : Write a time equation: Time = dist/speed : Time there + time back = 1 hr + = 1 Multiply equation by 20, get rid of the denominators, results: 2d + d = 20 3d = 20 d = d = 6 (miles one way) Therefore 2(6) = 13 total miles : : Check on a calc; 6.67/10 + 6.67/20 = .667 + .333 = 1

Exponents-negative-and-fractional/259802: V=s2+1/2sh for h 1 solutions Answer 191278 by ankor@dixie-net.com(15624)   on 2010-01-22 15:30:08 (Show Source): You can put this solution on YOUR website! V=s2+1/2sh for h Write it: s^2 + .5sh = V Subtract s^2 from both sides .5sh = V - s^2 Divide both side by .5s h =

percentage/259803: I need to figure out an original salary: Joe got an 11% raise which will bring his yearly salary to $26,085, What is Joe earning now? I tried to take 89% of 26085, and got $23,215.65. So did I do this right? Would the original salary be $23,215.65. Thanks, Sam 1 solutions Answer 191277 by ankor@dixie-net.com(15624)   on 2010-01-22 15:26:03 (Show Source): You can put this solution on YOUR website! I need to figure out an original salary: Joe got an 11% raise which will bring his yearly salary to $26,085, What is Joe earning now? ; The problems says he is earning 26085 now : To find the original salary : Let x = original salary with a 11% raise: 1.11x = 26085 x = x = $23,500 : : Check this .11(23500) = 2585; 23500 + 2585 = 26085

Travel_Word_Problems/259567: Ryan left the science museum going south. Gabriel left 3 hours later riding 42 km per hour faster than ryan. After 2 hours Gabriel caught up to Ryan. Find Ryan's average speed. 1 solutions Answer 191097 by ankor@dixie-net.com(15624)   on 2010-01-22 07:51:37 (Show Source): You can put this solution on YOUR website! Ryan left the science museum going south. Gabriel left 3 hours later riding 42 km per hour faster than Ryan. After 2 hours Gabriel caught up to Ryan. Find Ryan's average speed. : Let s = Ryan's average speed then (s+42) = Gabriel's speed : A couple useful facts R's travel time = 5 hrs G's travel time = 2 hrs When G catch R, they will have traveled he same distance : Write a distance equation; dist = speed * time : R's dist = G's dist 5s = 2(s+42) 5s = 2s + 84 5s - 2s = 84 3s = 84 s = s = 28 km/hr is Ryan's speed : : Check solution by ensuring that they did travel the same dist 5(28) = 140 km 2(28+42) = 140 km

Travel_Word_Problems/259295: Susan completes a journey in two stages. In stage 1 of her journey she drives at an average speed of 80 km/h and takes 1 hour and 45 minutes. How far does Susan travel in stage 1 of her journey? 1 solutions Answer 191049 by ankor@dixie-net.com(15624)   on 2010-01-21 21:40:35 (Show Source): You can put this solution on YOUR website! Susan completes a journey in two stages. In stage 1 of her journey she drives at an average speed of 80 km/h and takes 1 hour and 45 minutes. How far does Susan travel in stage 1 of her journey? : All they are asking is,"How far can you drive in 1.75 hrs at 80 km/hr?" : 1.75 * 80 = 140 km

Percentage-and-ratio-word-problems/259190: In ‘F’ Troop, 2/3 of the men are married and 2/3 of these married men do not have children. What fraction of the men in ‘F’ Troop are married with children? a) 1/9 b) 2/9 c) 1/3 d) 2/3 e) 8/9 1 solutions Answer 191048 by ankor@dixie-net.com(15624)   on 2010-01-21 21:35:30 (Show Source): You can put this solution on YOUR website! In ‘F’ Troop, 2/3 of the men are married and 2/3 of these married men do not have children. What fraction of the men in ‘F’ Troop are married with children? : Since 2/3 of 2/3 have no children then 1/3 of 2/3 do have children 1/3 * 2/3 = 2/9

Age_Word_Problems/259510: Mike and Jay are brothers. Mike is 33. This is 3 times as old as Jay was when Mike was the age that Jay is today. How old is Jay? 1 solutions Answer 191045 by ankor@dixie-net.com(15624)   on 2010-01-21 21:26:31 (Show Source): You can put this solution on YOUR website! Mike and Jay are brothers. Mike is 33. This is 3 times as old as Jay was when Mike was the age that Jay is today. How old is Jay? : let j = Jay's present age 33-j = the difference in their ages : "This is 3 times as old as Jay was when Mike was the age that Jay is today. 33 = 3(j - (33-j)) : 33 = 3(j - 33 + j) : 33 = 3(2j - 33) : 33 = 6j - 99 : 33 + 99 = 6j : 132 = 6j j = j = 22 yrs is Jay's present age

Trigonometry-basics/259535: How many revolutions will a car wheel of diameter 28 inches make over a period of half an hour if the car is traveling at 60 miles per hour? round your answer to the nearest tenth. 1 solutions Answer 191042 by ankor@dixie-net.com(15624)   on 2010-01-21 21:15:19 (Show Source): You can put this solution on YOUR website! How many revolutions will a car wheel of diameter 28 inches make over a period of half an hour if the car is traveling at 60 miles per hour? round your answer to the nearest tenth. : No. of inches traveled in 30 min at 60 mph/wheel circumference : = 21,608.7 revolutions

Average/259537: Adam tried to compute the average of his 7 test scores. He mistakenly divided the correct sum of all of his test scores by 6, which yielded 84. What is Adam’s correct average test score? 1 solutions Answer 191026 by ankor@dixie-net.com(15624)   on 2010-01-21 20:30:55 (Show Source): You can put this solution on YOUR website! Adam tried to compute the average of his 7 test scores. He mistakenly divided the correct sum of all of his test scores by 6, which yielded 84. What is Adam’s correct average test score? : His total must have been: 6 * 84 = 504 = 72 is his correct score, (a big disappointment no doubt)

Radicals/259287: Please help with an algebra application with carburetor open mm's and rpm's. I need to reverse this formula with the existing p=4480 and D=84 for the following, and instead of p=4480 as the result, need D=84 as the result. Thank you very much! D(p)=0.75√2.8p D(p)=(3/4)(√14/5)p D*2=(9/16)(14/5)p p=(16/9)(5/14)D^2 p=(16/9)(5/14)(84)^2 p=4480 1 solutions Answer 191023 by ankor@dixie-net.com(15624)   on 2010-01-21 20:24:55 (Show Source): You can put this solution on YOUR website! Please help with an algebra application with carburetor open mm's and rpm's. I need to reverse this formula with the existing p=4480 and D=84 for the following, and instead of p=4480 as the result, need D=84 as the result. : I assume you want to solve for p when you know d : The original formula = d : divide both sides by .75 = = 1.33d : Square both sides 2.8p = (1.33d)^2 2.8p = 1.778d^2 : Divide both sides by 2.8 p = : You can check this: substitute 84 for d and confirm that p = 4480

Equations/259520: You have a rectangular swimming pool 20 ft. by 10 ft, and a uniform depth of 8 ft. You want to fill the pool to the top. You calculate that it will take 4 hours to fill the pool. It actually takes you 4.5 hours to fill the pool. You suspect the pool is leaking. How much water has leaked from the pool during the 4.5 hours? Assuming a uniform filling rate, and neglecting evaporation, what is the leakage rate (to the nearest gal. per minute)? (1 cu. ft. =7.5 gal.) 1 solutions Answer 191013 by ankor@dixie-net.com(15624)   on 2010-01-21 20:01:20 (Show Source): You can put this solution on YOUR website! You have a rectangular swimming pool 20 ft. by 10 ft, and a uniform depth of 8 ft. You want to fill the pool to the top. You calculate that it will take 4 hours to fill the pool. It actually takes you 4.5 hours to fill the pool. You suspect the pool is leaking. How much water has leaked from the pool during the 4.5 hours? Assuming a uniform filling rate, and neglecting evaporation, what is the leakage rate (to the nearest gal. per minute)? (1 cu. ft. =7.5 gal.) : Find out the total gallons in the pool : 20 * 10 * 8 * 7.5 = 12,000 gallons : Find the gallons/min pumped to pump 12000 gallons = 50 gal.min : Find the number of gal pumped in the extra 30 min time 30 * 50 = 1500 gal that amt in a 4.5 hr period: = 5.556 ~ 6 gal/min leak : : Check it this way on a calc: 4.5*60*(50-5.556) = 11999.88 ~ 12000