Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

# Recent problems solved by 'ankor@dixie-net.com'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659, >>Next

 Travel_Word_Problems/269229: A Boat goes upstream 40 miles and downstream 86 miles in 8 Hours. If it goes upstream 24 miles and down the same distance in 5 hrs, what is the boat speed?1 solutions Answer 197510 by ankor@dixie-net.com(15652)   on 2010-02-14 14:18:20 (Show Source): You can put this solution on YOUR website!A Boat goes upstream 40 miles and downstream 86 miles in 8 Hours. If it goes upstream 24 miles and down the same distance in 5 hrs, what is the boat speed? : Let x = boat speed in still water Let y = speed of the current Then (x+y) = speed downstream (x-y) = speed upstream : Write a time equation for each statement : "A Boat goes upstream 40 miles and downstream 86 miles in 8 Hours." + = 8 Multiply by (x-y)(x+y) to get rid of the denominators : 40(x+y) + 86(x-y) = 8(x+y)(x-y) 40x + 40y + 86x - 86y = 8(x^2 - y^2) 126x - 46y = 8x^2 - 8y^2 Simplify, divide by 2 63x - 23y = 4x^2 - 4y^2 4x^2 - 63x + 23y - 4y^2 = 0 : " If it goes upstream 24 miles and down the same distance in 5 hrs," + = 5 Multiply by (x-y)(x+y) to get rid of the denominators : 24(x+y) + 24(x-y) = 5(x+y)(x-y) 24x + 24y + 24x - 24y = 5(x^2 - y^2) 48x = 5x^2 - 5y^2 5x^2 - 48x - 5y^2 = 0 : Try to eliminate some of this, mult the 1st by 5, the above by 4 20x^2 - 315x + 115y - 20y^2 = 0 20x^2 - 192x + 0y - 20y^2 = 0 -------------------------------------subtraction eliminates x^2 and y^2 -123x + 115y = 0 115y = 123x : I don't think this is possible, the current exceeds the boat speed
 Travel_Word_Problems/268803: a boat can travel 42 miles upstream and 42 miles downstream in 10 hours. if the speed of the boat in still water is 10mph, what is the speed of the current. I'm not sure how to re-arrange the formula for these variables, here's what I tried: 42+42/10=8.4 (presumably the average speed) 10mph-8.4mph=1.6(presumably the speed of the current)1 solutions Answer 197507 by ankor@dixie-net.com(15652)   on 2010-02-14 14:06:50 (Show Source): You can put this solution on YOUR website!a boat can travel 42 miles upstream and 42 miles downstream in 10 hours. if the speed of the boat in still water is 10mph, what is the speed of the current. : Although there is a certain logic in what you are doing, it's not right Here is what they want I think : Let x = rate of the current then (10+x) = speed downstream (10-x) = speed upstream : Write time equation; time = dist/speed : downstr time + upstr time = 10 hrs + = 10 : multiply by (10+x)(10-x) to eliminate the denominators 42(10-x) + 42(10+x) = 10(10+x)(10-x) : 420 - 42x + 420 + 42x = 10(100 - x^2) : 840 = 1000 - 10x^2 : 10x^2 = 1000 - 840 10x^2 = 160 Simplify, divide by 10 x^2 = 16 x = x = 4 mph is the current : : Check solution by finding the time (14 mph down, 6 mph up) 42/14 = 3 42/6 = 7 ---------- total = 10 hrs
 Money_Word_Problems/269030: I have \$1500 in a savings account drawing 6% interest and would like to make a payment once year for three years to have an ending balance of \$10,000 at the end of the three years. I need for these payments to be the same amount to make it easier for me to remember. Can you please help me by giving the formula for this?1 solutions Answer 197405 by ankor@dixie-net.com(15652)   on 2010-02-13 21:56:06 (Show Source): You can put this solution on YOUR website! I have \$1500 in a savings account drawing 6% interest and would like to make a payment once year for three years to have an ending balance of \$10,000 at the end of the three years : I used the financial feature on my TI83 with your figures and came up with \$2579.93, just make it \$2580 deposited every year (compounded once a year) If compounded quarterly you only need 2574
 Square-cubic-other-roots/268734: Maximum sail area. According to the new International America’s Cup Class Rules, the maximum sail area in square meters for a yacht in the America’s Cup race is given by the formula S =(13.0368 + 7.84D1/3 - 0.8L)^2 where D is the displacement in cubic meters (m3), and L is the length in meters (m). (www.sailing.com). Find the maximum sail area for a boat that has a displacement of 18.42 m3 and a length of 21.45 m. S (m2) D (m3) L (m) 1 solutions Answer 197401 by ankor@dixie-net.com(15652)   on 2010-02-13 21:40:45 (Show Source): You can put this solution on YOUR website!Maximum sail area. According to the new International America’s Cup Class Rules, the maximum sail area in square meters for a yacht in the America’s Cup race is given by the formula S =(13.0368 + 7.84D1/3 - 0.8L)^2 where D is the displacement in cubic meters (m3), and L is the length in meters (m). (www.sailing.com). Find the maximum sail area for a boat that has a displacement of 18.42 m3 and a length of 21.45 m. S (m2) D (m3) L (m) : The think the formula should be the cube root of the displacement S =(13.0368 + 7.84(D^(1/3)) - 0.8L)^2 : S =(13.0368 + 7.84(18.42^(1/3)) - 0.8(21.45))^2 : S =(13.0368 + 7.84(2.641)) - 17.16)^2 : S =(13.0368 + 20.705 - 17.16)^2 : S = 16.582^2 : S = 274.962 sq/meters of sail
 test/268697: Diane canned 18 quarts of peaches, 15 quarts of apricots, and 12 quarts of plums. she would like to place the quarts into the greatest number of boxes so that each box has the same number of each kind of fruit. how many boxes does she need?1 solutions Answer 197395 by ankor@dixie-net.com(15652)   on 2010-02-13 21:03:47 (Show Source): You can put this solution on YOUR website!Diane canned 18 quarts of peaches, 15 quarts of apricots, and 12 quarts of plums. she would like to place the quarts into the greatest number of boxes so that each box has the same number of each kind of fruit. how many boxes does she need? : I think 3 boxes. 3 is the only number that will divide evenly into 18, 15, 12 6 peaches 5 apricots 4 plums
 Linear-equations/268695: write the slope-intercept form of the equation of the line through the given points: through: (3,1) and (0,3)1 solutions Answer 197383 by ankor@dixie-net.com(15652)   on 2010-02-13 19:22:41 (Show Source): You can put this solution on YOUR website!write the slope-intercept form of the equation of the line through the given points: through: (3,1) and (0,3) : Find the slope: = = Y intercept occurs when x = 0, therefore y = x + 3; the slope intercept form ; Check solution, replace x with 3: y = (3) + 3 y = -2 + 3 y = 1
 Polygons/269206: I have been working on this math problem and don't know how to get the second part of it and I was wondering if someone could help me? Please and Thank you! I would deeply appreciate it! A team's best hitter has a lifetime batting average of .320. He has been at bat 325 times. He has made 104 hits. b. The same player goes into a slump and doesn't get any hits at all in his next ten times at bat. What is his current batting average to the nearest thousandth?1 solutions Answer 197311 by ankor@dixie-net.com(15652)   on 2010-02-13 15:32:53 (Show Source): You can put this solution on YOUR website!Not hard, just add 10 to the times at bat and 0 to no. of hits = .310 batting average now
 Numbers_Word_Problems/269156: When the digits of a two-digit number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?1 solutions Answer 197298 by ankor@dixie-net.com(15652)   on 2010-02-13 13:47:38 (Show Source): You can put this solution on YOUR website!I think this problem should read: ; "When the digits of a two-digit number are reversed, the number is 9 more than the original number, and the sum of the digits of the original number is 11. What is the original number?" : Let x = the 10's digit Let y = the units the 10x + y = "the original two digit number : "When the digits of a two-digit number are reversed, the number is 9 more than the original number," 10y + x = 10x + y + 9 10y - y = 10x - x + 9 9y = 9x + 9 Simplify divide by 9 y = x + 1 : "the sum of the digits of the original number is 11. x + y = 11 Replace y with (x+1) x + x + 1 = 11 2x = 11-1 x = 5 then y = 5 + 1 = 6 : 56 is the original number ; : Check solution in the statement: "the digits of a two-digit number are reversed, the number is 9 more than the original number," 65 = 56 + 9
 Rate-of-work-word-problems/269152: It takes 8 painters 6 hours to paint the walls of a gymnasium. a. How many person-hours does this job require? b. How many hours will 12 painters take to paint the gymnasium?1 solutions Answer 197294 by ankor@dixie-net.com(15652)   on 2010-02-13 13:28:30 (Show Source): You can put this solution on YOUR website!It takes 8 painters 6 hours to paint the walls of a gymnasium. : a. How many person-hours does this job require? Person-hours??? Who comes up with these dumb terms?? : 8 * 6 = 48 MAN-hours, to do the job : b. How many hours will 12 painters take to paint the gymnasium? : Let x = no. of hours, when 12 men do the job 12x = 48 x = 48/12 x = 4 hrs to do the job
 Linear-equations/269175: how do i put find the slope of linear equations by putting them in to slope-intercept form? i.e) 2x-4y=3 or probably y-3=2(x-2)please and thank you for your help 1 solutions Answer 197288 by ankor@dixie-net.com(15652)   on 2010-02-13 12:52:14 (Show Source): You can put this solution on YOUR website!how do i put find the slope of linear equations by putting them in to slope-intercept form? i.e) 2x-4y=3 : The slope/intercept form: y = mx + b; where m is the slope : 2x - 4y = 3 Subtract 2x from both sides -4y = -2x + 3 Divide both sides by 4 -y = x + y has to be positive, multiply both sides by -1 y = x - reduce the fraction y = x - ; this is the slope/intercept form, therefore slope (m) =
 Miscellaneous_Word_Problems/269162: Three friends jog regularly in a park: Anna jogs every 10 days, Barbara jogs every 15 days, and Jo jogs every 14 days. One Sunday they happen to jog together. After how many days will the three friends jog together again? (A)150 (B) 210 (C) 350 (D) 420 (E) Never 1 solutions Answer 197287 by ankor@dixie-net.com(15652)   on 2010-02-13 12:45:24 (Show Source): You can put this solution on YOUR website!Three friends jog regularly in a park: Anna jogs every 10 days, Barbara jogs every 15 days, and Jo jogs every 14 days. One Sunday they happen to jog together. After how many days will the three friends jog together again? : Find a number that is a multiple of all three numbers 15 * 14 = 210, we know 10 is also a factor since it ends in 0 : 210 days is ans
 Miscellaneous_Word_Problems/269169: What power of 16 is equal to 8 ? express your answer as a common fraction 1 solutions Answer 197279 by ankor@dixie-net.com(15652)   on 2010-02-13 11:31:28 (Show Source): You can put this solution on YOUR website!Find the 4th root of 16, (2) and cube that : 16^(3/4) = 8
 Linear_Equations_And_Systems_Word_Problems/268817: Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. Find the actual voltage of each battery.1 solutions Answer 197278 by ankor@dixie-net.com(15652)   on 2010-02-13 11:25:29 (Show Source): You can put this solution on YOUR website!Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. Find the actual voltage of each battery. : Let x = voltage of the 1st battery : " The voltage of the first battery is twice the voltage of the second", then: .5x = voltage of the 2nd battery : "and 1/3 the voltage of the third battery."which means: 3x = voltage of the third battery : Find the actual voltage of each battery. : x + .5x + 3x = 54 4.5x = 54 x = x = 12v is the 1st battery and .5(12) = 6v is the 2nd battery and 3(12) = 36v is the 3rd battery : : Check solution: 12 + 6 + 36 = 54
 Quadratic_Equations/268745: victor threw a baseball into the air that modeled the equation h=-16t+36t+1,where h is the height in feet and t is the time in seconds.How long was the ball in the air if casey caught the ball 9 feet above the ground on its way down?1 solutions Answer 197203 by ankor@dixie-net.com(15652)   on 2010-02-12 21:54:51 (Show Source): You can put this solution on YOUR website!victor threw a baseball into the air that modeled the equation h=-16t+36t+1,where h is the height in feet and t is the time in seconds.How long was the ball in the air if casey caught the ball 9 feet above the ground on its way down? : -16t^2 + 36t + 1 = 9 : -16t^2 + 36t + 1 - 9 = 0 : -16t^2 + 36t - 8 = 0 Simplify, change the signs, divide by -4 4t^2 - 9t + 2 = 0 Factors to (4t - 1)(t - 2) = 0 Two solutions 4t = 1 t = sec ; ball just off the bat and t = 2 sec; ball is caught at 9 ft
 Travel_Word_Problems/268891: On Saturday morning, Lynn walked for 2 hours and then ran for 30 minutes. If she ran twice as fast as she walked and she covered 12 miles altogether,then how fast did she walk?1 solutions Answer 197198 by ankor@dixie-net.com(15652)   on 2010-02-12 21:47:33 (Show Source): You can put this solution on YOUR website!On Saturday morning, Lynn walked for 2 hours and then ran for 30 minutes. If she ran twice as fast as she walked and she covered 12 miles altogether,then how fast did she walk? : Let s = L's walking speed then 2s = L's running speed : Write a dist equation: dist = time * speed : Walk dist + run dist = 12 mi 2s + .5(2s) = 12 2s + 1s = 12 3s = 12 s = s = 4 mph is L's walking speed ; ; Check solution in dist equation 2(4) + .5(8) = 12
 Polynomials-and-rational-expressions/268894: A red ball and a green ball are simultaneously tossed into the air. The red ball is given an initial velocity of 96 feet per second, and its height t seconds after it is tossed is -16t^ 2 +96t feet. The green ball is given an initial velocity of 80 feet per second, and its height t seconds after it is tossed is-16t^2+ 80t feet. a) Find a polynomial D(t) that represents the difference in the heights of the two balls. b) How much higher is the red ball 2 seconds after the balls are tossed? c) In reality, when does the difference in the heights stop increasing? 1 solutions Answer 197194 by ankor@dixie-net.com(15652)   on 2010-02-12 21:40:27 (Show Source): You can put this solution on YOUR website!A red ball and a green ball are tossed into the air. The red ball is given an initial velocity of 96 feet per second and its height "t" seconds after it is tossed is -16t^2 + 96t feet. The green ball is given an initial velocity of 80 feet per second and its height "t" seconds after being tossed is -16t^2 +80t feet. : Find a polynomial D(t) that represents the difference in the heights of the two balls. D(t) = (-16t^2 + 96t) - (-16t^2 +80t) : Remove brackets D(t) = -16t^2 + 96t + 16t^2 - 80t : combine like terms: D(t) = 16t : How much higher is the red ball 2 seconds after the balls are tossed? D(t) = 16(2) D(t) = 32 ft difference after 2 seconds : When does the difference in the heights stop increasing? : Obviously, when one of the balls hits the ground : Find when the lowest ball hits the ground (h=0) -16t^2 + 80t = 0 Factor out -16t -16t(t - 5) = 0 t = 5 seconds when the difference stops increasing; : A graph illustrates this well
 Travel_Word_Problems/268766: sherie rides her bike at 5 miles per hour. her sister leaves 15 minutes later cycling 8 miles per hour. long will it take her sister to catch up to sherie?1 solutions Answer 197163 by ankor@dixie-net.com(15652)   on 2010-02-12 20:07:20 (Show Source): You can put this solution on YOUR website!sherie rides her bike at 5 miles per hour. her sister leaves 15 minutes later cycling 8 miles per hour. long will it take her sister to catch up to sherie? : Change 15 min to 15/60 = .25 hrs Let t = sister's travel time (in hrs) then (t+.25) = S's travel time : When sister catches S, they will have ridden the same distance. Write a distance equation: Dist = speed * time : sister's dist = S's dist 8t = 5(t+.25) 8t = 5t + 1.25 8t - 5t = 1.25 3t = 1.25 t = t = .4167 hrs or .4167 * 60 = 25 minutes to catch her : : Check solution by finding the dist of each, should be the same 8(.4167) = 3.33 mi 5(.4167+.25) = 3.33 mi
 Square-cubic-other-roots/269028: Please help me solve this problem: Simplify by taking roots of the numerator and the denominator. Assume that all expressions under radicals represent positive numbers. 3 I dont know if I wrote the problem correctly but the 3 is the degree of the square root. thanks1 solutions Answer 197160 by ankor@dixie-net.com(15652)   on 2010-02-12 19:54:12 (Show Source): You can put this solution on YOUR website!Simplify by taking roots of the numerator and the denominator. Assume that all expressions under radicals represent positive numbers. : 3 : Factor to reveal the perfect cubes inside the radical 3 : Extract those perfect cubes 3