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15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659, >>NextTravel_Word_Problems/700832: Summer drove at an average speed of 35 mi/h from her home in Dallas to visit her sister in Minneapolis. She stayed in Minneapolis 20 hours, and on the trip back averaged 45 mi/h. She returned home 50 hours after leaving. How many miles is Dallas from Minneapolis?
1 solutions
Answer 432164 by ankor@dixie-net.com(15652)   on 2013-01-11 17:02:47 (Show Source):
You can put this solution on YOUR website! Summer drove at an average speed of 35 mi/h from her home in Dallas to visit her sister in Minneapolis.
She stayed in Minneapolis 20 hours, and on the trip back averaged 45 mi/h.
She returned home 50 hours after leaving.
How many miles is Dallas from Minneapolis?
:
Actual travel time: 50-20 = 30 hrs
:
Let d = one way dist
:
Write a time equation, time = dist/speed
 +  = 30
multiply by 315 to clear the denominators
9d + 7d = 315(30)
16d = 9450
d = 9450/16
d = 590.6 mi one way (Actually it's almost twice that)
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absolute-value/700886: Clara was (2x+3) years old last year. her brother is 4 years younger than her. What would be their combined age 5 years from now?
1 solutions
Answer 432158 by ankor@dixie-net.com(15652) on 2013-01-11 16:46:06 (Show Source):
You can put this solution on YOUR website!Clara was (2x+3) years old last year. her brother is 4 years younger than her. What would be their combined age 5 years from now?
:
If C was (2x+3) yrs old one year ago, now C is (2x+4)
Brother 4 yrs younger
b = (2x+4) - 4
b = 2x
:
Combined age 5 yrs from now
A = (2x+4) + 5 + 2x + 5
A = 4x + 14
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Graphs/700926: Hi, I'm new here and hope this is the right topic for my question(s)...
I have some problems with my math project. I have problems with c. d. and e. i'll add a. and b. too though so you know what i've done here already :
1. Pick two animals to be in a race and answer the following questions.
a.) Suppose two animals are in a race. Choose the two animals and calculate the speed of each animal in yards per second.
I chose a fox with 20.53 yards per second and a coyote with 21.02 yards per second.
b. Decide how much of a head start (in yards) the faster animal offers the slower animal. For each animal, write an equation relating distance from the starting line to time.
I also got this.
The fox gets 10yd head start.
fox: x = 20.53y + 10 (because of the 10yd head start he got)
coyote: x = 21.02y
now here comes where I don't know what to/ how to do it.
c. Graph the two equations on the same coordinate plane. ( Now this is my problem)
I don't know how to graph and where they would go/etc.
d. How long will it take the faster animal to overtake the slower animal? How
many yards from the starting line are the animals when the faster animal
overtakes the slower animal?
now e. is the last part i added a screenshot for it : http://i49.tinypic.com/350rk.jpg
Now there's also a second part of this, but I don't want to ask too much of you.
I hope that you can help me and that I did not confuse you with my writing, I'm not native english. I would really appreciate it if you could help me out here and also explain so I can understand how you got to the answer and so i'll know what to do next time when i will have a problem like this.
1 solutions
Answer 432134 by ankor@dixie-net.com(15652) on 2013-01-11 15:06:37 (Show Source):
You can put this solution on YOUR website!I would do it this way:
let x = travel time of the two animals
then write a distance equation for each
Fox
d = 20.53x+10
Coyote
d = 21.02x
:
Plot these two equations, vert is distance in yds
As you can see, because the speeds of the animals are so close it is hard to get a definitive graph, the lines are almost parallel
:
If you can, choose an animal with large speed difference say a coyote and rabbit
The speed of rabbit is about 17.1 yds/sec, give it a 20 yd head start, then you would have an equation of 17.1x + 20
Coyote catches the rabbit in about 5 sec a little over 100 yds
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Rectangles/700674: how do you find the length of a diagonal of a rectangle if all you have is an equation: 7x-2 for one diagonal and 4x+3 for the other diagonal?
1 solutions
Answer 432114 by ankor@dixie-net.com(15652) on 2013-01-11 13:33:14 (Show Source):
You can put this solution on YOUR website!: how do you find the length of a diagonal of a rectangle if all you have is an equation: 7x-2 for one diagonal and 4x+3 for the other diagonal?
:
We know that the two diagonals in rectangle are equal, therefore
7x - 2 = 4x + 3
Solve for x
7x - 4x = 3 + 2
3x = 5
x = 5/3
:
Find the length of the diagonal by replacing x with 5/3 in 7x - 2
d = 7(5/3) - 2
d = (35/3) - 2
d = 11  - 2
d = 9 is the length of the diagonal
:
Check this by doing the same in 4x + 3
d = 4(5/3) + 3
d = (20/3} + 3
d = 6 + 3
d = 9
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Travel_Word_Problems/700936: vehicle a and vehicle b are 10 mi apart.vehicle a travels 20 mph. vehicle b travels 30 mph. veh a travels perpindicular to a line between veh a and veh b. both vehs start at same time. veh b must intercept veh a in shortest distance. what is the distance?
1 solutions
Answer 432083 by ankor@dixie-net.com(15652) on 2013-01-11 10:19:47 (Show Source):
You can put this solution on YOUR website! vehicle a and vehicle b are 10 mi apart.vehicle a travels 20 mph.
vehicle b travels 30 mph.
veh a travels perpendicular to a line between veh a and veh b.
both vehs start at same time. veh b must intercept veh a in shortest distance.
what is the distance?
:
The perpendicular paths to intercept form a right triangle, with a hypotenuse of 10 mi
:
Find the travel time, then we can find the distance that b travels to intercept
Let t = travel time
:
Using pythag: a^2 + b^2 = c^2
(20t)^2 + (30t)^2 = 10^2
400t^2 + 900t^2 = 100
simplify, divide by 100
4t^2 + 9t^2 = 1
13t^2 = 1
t = 
t = .27735 hrs to intercept
distance traveled by veh b
.27735(30) = 8.32 mi
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Circles/700877: A chord of length 16 sqrt3 is the perpendicular bisector of the radius in a circle. Determine the area of the circle.Please show me the steps
1 solutions
Answer 432050 by ankor@dixie-net.com(15652) on 2013-01-11 08:26:25 (Show Source):
You can put this solution on YOUR website!A chord of length 16 sqrt3 is the perpendicular bisector of the radius in a circle.
Determine the area of the circle.Please show me the steps
:
We want to find the radius first.
A right triangle is formed by half the chord and half the radius and the radius
The radius is the hypotenuse, therefore using pythag; a^2 + b^2 = c^2
 +  = 
64(3) + .25r^2 = r^2
192 = r^2 - .25r^2
192 = .75r^2
r^2 = 192/.75
r^2 = 156
r = 
r = 16
:
A = 
A = 804.2477 sq units
|
Travel_Word_Problems/700776: Dustin drives 5 mph faster than Kelly. If he leaves town one hour after Kelly and they travel in opposite directions, they will have driven equal distances after Dustin has traveled seven hours. How far apart are they?
1 solutions
Answer 432013 by ankor@dixie-net.com(15652) on 2013-01-10 21:55:20 (Show Source):
You can put this solution on YOUR website! Dustin drives 5 mph faster than Kelly.
If he leaves town one hour after Kelly and they travel in opposite directions, they will have driven equal distances after Dustin has traveled seven hours.
How far apart are they?
:
Let s = K's speed
then
(s+5) = D's speed
:
K travels 8 hrs
:
Write a distance equation; dist = speed * time
8s = 7(s+5)
8s = 7s + 35
8s - 7s = 35
s = 35 mph is K's speed
:
Find the distance he traveled in 8 hrs
8 * 35 = 280 mi
Find D's distance, they should be the same
7 * 40 = 280 mi
:
They would be 2(280) 560 mi apart
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Numbers_Word_Problems/700828: Lupe is thinking of two 3 digit numbers. The sum of the numbers is 619. Their difference is 33. Whatare the numbers?
1 solutions
Answer 432010 by ankor@dixie-net.com(15652) on 2013-01-10 21:44:05 (Show Source):
You can put this solution on YOUR website!Lupe is thinking of two 3 digit numbers. The sum of the numbers is 619.
Their difference is 33. What are the numbers?
:
Write an equation for each statement, the two number are a & b
a + b = 619
a - b = 33
-------------adding eliminates b, find a
2a = 652
a = 326
then
326 - b = 33
b = 326 - 33
b = 293
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Graphs/700783: How do I find y for this equation? 2x-y=1 I don't understand how to solve it and then graph it along with y=-3.
1 solutions
Answer 432007 by ankor@dixie-net.com(15652) on 2013-01-10 21:37:51 (Show Source):
You can put this solution on YOUR website!find y for this equation?
2x - y = 1
subtract 2x from both sides
-y = -2x + 1
y has to be positive, multiply both sides by-1
y = 2x - 1
:
"graph it along with y=-3."
find x when y = -3
2x -1 = -3
2x = -3 + 1
2x = -2
x = 2/-2
x = -1
:
Make a table to plot a graph using above coordinates and x = -3, 0 and +2
x | y
------
-3 |-7; replace x with -3, find y to be -7
-1 |-3
0 |-1
+2 |+3
:
Plot these points, your graph should look like this
|
real-numbers/700462: Can you please help me out with this?
2/x+3/3x / 1/3x-1/2x
Thank you so much!
1 solutions
Answer 431998 by ankor@dixie-net.com(15652) on 2013-01-10 20:54:45 (Show Source):
You can put this solution on YOUR website!Not quite sure what you mean here, assume this is problem
 + 
------------
 - 
we want to get each pair of fractions over a single denominator
The top one is easy, cancel the 3's
+ 
------------
-
which is
------------
-
which is
------------
-
the bottom pair has a common denominator of 6x, so we have:
--------
which is
---------
invert the dividing fraction and multiply, cancel out the x
*  = 3*-6 = -18
|
Distributive-associative-commutative-properties/700732: 2h+2(2h+4)=26 i have tried so hard to understand algebra using distributive property and my teacher doesn't will not sit and explain it to me and if i could get any help it would be appreciated. Thank you very much Jordan.
1 solutions
Answer 431971 by ankor@dixie-net.com(15652) on 2013-01-10 19:53:11 (Show Source):
You can put this solution on YOUR website!2h + 2(2h+4) = 26
The distributive property says multiply each term inside the bracket by the term outside the brackets, then remove the brackets
2h + 4h + 8 = 26
Combine like terms
6h + 8 = 26
Subtract 8 from both sides
6h = 26 - 8
6h = 18
divide both sides by 6
h = 18/6
h = 3
:
:
Prove to yourself that this is true in the original problem
2h + 2(2h+4) = 26
replace h with 3
2(3) + 2(2(3) + 4) = 26
6 + 2(6+4) = 26
6 + 2(10) = 26
6 + 20 = 26; confirms the solution of h = 3
:
:
Have we shed some light on this for you now? C
|
Systems-of-equations/700426: a number of two digits is 9 more than 5 times the sum of its digits. its ten's digit is one more that its unit's digit. find the number.
1 solutions
Answer 431968 by ankor@dixie-net.com(15652) on 2013-01-10 19:37:33 (Show Source):
You can put this solution on YOUR website!let a = the 10's digit
let b = the units
Then
10a+b = the two digit number
:
a number of two digits is 9 more than 5 times the sum of its digits.
10a + b = 5(a + b) + 9
10a + b = 5a + 5b + 9
10a - 5a = 5b - b + 9
5a = 4b + 9
:
its ten's digit is one more that its unit's digit.
a = b + 1
:
Replace a with (b+1) in the the eq: 5a = 4b + 9
5(b+1) = 4b + 9
5b + 5 = 4b + 9
5b - 4b = 9 - 5
b = 4
:
I'll let you find a, check the obtained number in the 1st statement so see if it is true
find the number.
|
�t�e�s�t/700721: A ladder is 3m long it is leaning against the wall. The foot of a ladder makes an angle of 76 degrees with the ground. How far up the wall is the top of the ladder? Give the length to the nearest tenth.
Can you please help me? Thanks so much in advance:)
1 solutions
Answer 431963 by ankor@dixie-net.com(15652) on 2013-01-10 19:17:45 (Show Source):
You can put this solution on YOUR website!A ladder is 3m long it is leaning against the wall.
The foot of a ladder makes an angle of 76 degrees with the ground.
How far up the wall is the top of the ladder?
Give the length to the nearest tenth.
:
picture the ladder forming a right triangle with the wall and the ground
The ladder is the hypotenuse, The side opposite (w) the angle of 76 degrees is the wall.
Sine = 
So we have:
sin(76) = 
.97 =
w = .97*3
w = 2.9, meters up the wall
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Linear_Equations_And_Systems_Word_Problems/700407: Hi! I need help solving this math word problem please? 55 boxes are packed in 5 hours, if each hour the packer packs 2 more boxes than the previous hour, how many boxes were packed in the final hour? How do I know what equation etc I should use to solve this?
Thank you!
1 solutions
Answer 431960 by ankor@dixie-net.com(15652) on 2013-01-10 18:59:13 (Show Source):
You can put this solution on YOUR website! 55 boxes are packed in 5 hours, if each hour the packer packs 2 more boxes than the previous hour, how many boxes were packed in the final hour?
:
let n = number of boxes packed the 1st hr, and the next 4 hrs are:
n + (n+2) + (n+4) + (n+6) + (n+8) = 55
Combine like terms
5n + 20 = 55
5n = 55 - 20
n = 35/5
n = 7 boxes in the 1st hr
then
7 + 8 = 15 boxes in the final hr
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Proofs/700425: HE TRAVELLED 300KM TO ATTEND A CONFERANCE .IF THE AVARAGE SPEED OF HIS TRIP HAS BEEN INCREASED BY 10 KM PER HOUR,HE WOULD HAVE REACHED THE CONFERANCE HALL ONE HOUR EARLIER. WHAT WAS THE AVARAGE SPEED OF HIS TRIP
1 solutions
Answer 431935 by ankor@dixie-net.com(15652) on 2013-01-10 18:03:40 (Show Source):
You can put this solution on YOUR website!Let s = the av speed of the trip
then
(x+10) = the faster speed
:
Write a time equation, time = dist/speed
:
Actual speed time - faster speed time = 1 hr
 -  = 1
multiply by s(s+10), clear the denominators, results:
300(s+10) - 300s = s(s+10)
300s + 3000 - 300s = s^2 + 10s\
A quadratic equation
0 = s^2 + 10s - 3000
Factors to
(s+60)(s-50) = 0
The positive solution
s = 50 km/h is the av speed of the trip
:
:
Check this; find the time at each speed:
300/50 = 6 hr
300/60 = 5 hr
----------------
differs: 1 hr
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Radicals/700479: if only radicls can be added or subtracted then why 5 square root of 3 + 2 square root of 12 can be simplified
1 solutions
Answer 431909 by ankor@dixie-net.com(15652) on 2013-01-10 16:55:42 (Show Source):
You can put this solution on YOUR website!if only LIKE radicals can be added or subtracted; then why 5 square root of 3 + 2 square root of 12 can be simplified
:
Factor inside the second radical to reveal a perfect square (4)
Extract the square root of that perfect square (2)
Now we have like radicals that can be added, resulting in:
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Mixture_Word_Problems/700547: Julia mixes 10 liters of 6% acidic solution with a specific amount of a 12% acidic solution, which results in an 8% acidic solution. Find the number of liters of 12% acid solution in the new mixture.
1 solutions
Answer 431903 by ankor@dixie-net.com(15652) on 2013-01-10 16:38:23 (Show Source):
You can put this solution on YOUR website!Julia mixes 10 liters of 6% acidic solution with a specific amount of a 12% acidic solution, which results in an 8% acidic solution.
Find the number of liters of 12% acid solution in the new mixture.
:
Let x = the specific amt of 12% solution
:
A typical mixture equation
.06(10) + .12x = .08(x+10)
.6 + .12x = .08x + .8
.12x - .08x = .8 - .6
.04x = .2
x = .2/.04
x = 5 liters of 12% solution required
:
:
Check this
.06(10) + .12(5) = .08(5+10)
.6 + .6 = .08(15)
1.2 = 1.2; confirms our solution of 5 liters
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Human-and-algebraic-language/700403: 12 men can complete a work in 4 days. how many men will be required in order to complete 8 times work in half times?
1 solutions
Answer 431897 by ankor@dixie-net.com(15652) on 2013-01-10 16:24:42 (Show Source):
You can put this solution on YOUR website!12 men can complete a work in 4 days.
Find how many man-days
12 * 4 = 48 man-days to complete one job
:
Assume this means
how many men will be required in order to complete 8 times the work, in half the time?
Half the time = 2 days, let m the no. of men to do this
2m = 8*48
2m = 384
m = 384/2
m = 192 men to do 8 times the work in 2 days
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Equations/700388: the weekly wages of John and Stephanie are in the ratio 5:3. their weekly expenditures are in the ration 9:5. each saves $30 dollars a week, find their weekly wages.
1 solutions
Answer 431886 by ankor@dixie-net.com(15652) on 2013-01-10 16:03:17 (Show Source):
You can put this solution on YOUR website!the weekly wages of John and Stephanie are in the ratio 5:3.
their weekly expenditures are in the ration 9:5. each saves $30 dollars a week, find their weekly wages.
:
Let x = the multiplier for their wages, then:
5x = J's wages
3x = S's wages
;
Let y = the multiplier for their expenditures, then
9y = J's expend
5y = S's expend
:
Write an equation for each
5x - 9y = 30
3x - 5y = 30
:
Use elimination here multiply the 1st equation by 3, the 2nd by 5
15x - 27y = 90
15x - 25y = 150
------------------subtraction eliminates x, find y
-2y = -60
y = +30 is the multiplier for expenses
Find x
5x - 9(30) = 30
5x - 270 = 30
5x = 30 + 270
5x = 300
x = 300/5
x = 60 is the multiplier for wages
Then
5(60) = $300 is J's wages
3(60) = $180 is S's wages
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Travel_Word_Problems/700341: At 2:45pm you are 112 miles from Dallas. You want to be in Dallas at 4:30pm. What is the average speed you must travel to be on time?
1 solutions
Answer 431876 by ankor@dixie-net.com(15652) on 2013-01-10 15:27:05 (Show Source):
You can put this solution on YOUR website!At 2:45pm you are 112 miles from Dallas.
You want to be in Dallas at 4:30pm.
What is the average speed you must travel to be on time?
:
Find the travel time
4:30 - 2:45 = 1 hr 45 min, which is 1.75 hrs
:
Speed = 
S = 64 mph av to be on time
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Age_Word_Problems/700439: what if we assume son is as old as his father is today then there ages total will be 126 and if father is as old as his son is today then there ages total will be 38. find there present ages
1 solutions
Answer 431863 by ankor@dixie-net.com(15652) on 2013-01-10 14:14:31 (Show Source):
You can put this solution on YOUR website!what if we assume son is as old as his father is today then there ages total will be 126
s + 2f = 126
if s = f, then
f + 2f = 126
f = 126/3
f = 42 is father's present age
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and if father is as old as his son is today then there ages total will be 38. find there present ages
2s = 38
s = 19 is son's present age
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Age_Word_Problems/699976: Please help me to solve this problem....
Angel is twice as old as Gavin.In three years,Angels will be13years less than twice as old as Gavin.
Find their ages
1 solutions
Answer 431798 by ankor@dixie-net.com(15652) on 2013-01-09 21:37:40 (Show Source):
You can put this solution on YOUR website!let a = A's present age
let g = G's present age
;
Write an equation for each statement:
:
Angel is twice as old as Gavin.
a = 2g
:
In three years, Angels will be 13 years less than twice as old as Gavin.
a + 3 = 2(g+3) - 13
a + 3 = 2g + 6 - 13
a + 3 = 2g - 7
a = 2g - 7 - 3
a = 2g - 10
Replace a with 2g
2g = 2g - 10
Obviously this is not possible, an undo-able problem
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Travel_Word_Problems/700292: a man rows his boat up a river at a constant speed
when opposite a cabin on the shore, he drops a bottle in the water,
he continues rowing upstream for 15 minutes then he turns around and rows downstream until he catches up with the bottle, at which point he is 1 mile downstream from the cabin
how fast is the river flowing?
1 solutions
Answer 431797 by ankor@dixie-net.com(15652) on 2013-01-09 21:24:17 (Show Source):
You can put this solution on YOUR website!a man rows his boat up a river at a constant speed when opposite a cabin on the shore, he drops a bottle in the water,
he continues rowing upstream for 15 minutes then he turns around and rows downstream until he catches up with the bottle, at which point he is 1 mile downstream from the cabin
how fast is the river flowing?
:
Since they are both in the water, the current has no affect on their relationship
If he rowed 15 min away from the bottle, it would take him 15 min to return to it
The round trip would be 1/2 hr
During this half hour the current carried the bottle 1 mi, therefore
rate of the current = 2 mph
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Travel_Word_Problems/700208: Two planes leave BWI at the same time and fly in the same directions. Their speeds
are 520 miles per hour and 630 miles per hour. How far apart will the planes be after 1.5 hours?I just need the equation to set it up
1 solutions
Answer 431793 by ankor@dixie-net.com(15652) on 2013-01-09 21:13:48 (Show Source):
You can put this solution on YOUR website!Two planes leave BWI at the same time and fly in the same directions.
Their speeds are 520 miles per hour and 630 miles per hour.
How far apart will the planes be after 1.5 hours?
:
Let d = distance apart after 1.5 hrs
:
d = 1.5(630) - 1.5(520)
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Mixture_Word_Problems/700121: I am in College algebra and working on "Solving systems of equations by the Addition Method". I have the answers in front of me but I don't know how to work the problem.
The Word problems is as follow's...
A chemist needs 90 milliliters of a 72% solution but has only 68% and 77% solutions available. Find how many milliliter of each that should be mixed to get the desired solution.
I have tried using X+Y=72% over 68%X+77%Y=90 and adding the two together to single out the x and y values,but this just brings up some wierd number that are way to high. The answer in the book is 50 ml of 68% and 40ml of 77%. I cant see how they get this answer. Please help
1 solutions
Answer 431653 by ankor@dixie-net.com(15652) on 2013-01-09 14:49:44 (Show Source):
You can put this solution on YOUR website!A chemist needs 90 milliliters of a 72% solution but has only 68% and 77% solutions available.
Find how many milliliter of each that should be mixed to get the desired solution.
:
Let x = amt of 77% solution required
Let y = amt of 68% solution required
:
"A chemist needs 90 milliliters of a 72% solution"
x + y = 90
y = (90-x); use this form for substitution
:
" but has only 68% and 77% solutions available."
Use the decimal equiv here
.77x + .68y = .72(90)
.77x + .68y = 64.8
Replace y with (90-x)
.77x + .68(90-x) = 64.8
.77x + 61.2 - .68x = 64.8
.77x - .68x = 64.8 - 61.2
.09x = 3.6
x = 3.6/.09
x = 40 ml of 77% solution
:
You can find the amt of 68% solution, check it in the original mixture equation
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Quadratic_Equations/700057: A rock is thrown downwards at a rate of 144 feet per second from an initial height of 352. Write the quadratic function that represents this vertical motion. Graph the quadratic equation on the coordinate plane provided. Show all work. Help! I've tried everything!
1 solutions
Answer 431652 by ankor@dixie-net.com(15652) on 2013-01-09 14:37:52 (Show Source):
You can put this solution on YOUR website!A rock is thrown downwards at a rate of 144 feet per second from an initial height of 352.
Write the quadratic function that represents this vertical motion. Graph the quadratic equation on the coordinate plane provided.
:
y = -16t^2 - 144t + 352
y = height in ft
t = time in sec
:
Plot this equation from 0 to 2 seconds
x | y
-------
0 |352; initial height
.5 |276
1.0|192
1.5|100
2.0| 0; strikes the ground
:
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Linear-equations/700035: On a school picnic, a group of boys agree to pay equally for the use of a boat and each pays
$ 40. If there had been 5 more boys in the group, each would have to pay $ 10 less. How
many boys were in the group?
1 solutions
Answer 431619 by ankor@dixie-net.com(15652) on 2013-01-09 12:28:21 (Show Source):
You can put this solution on YOUR website!On a school picnic, a group of boys agree to pay equally for the use of a boat and each pays $ 40.
If there had been 5 more boys in the group, each would have to pay $ 10 less.
How many boys were in the group?
:
let b = no. of boys in the group
then
40b = total amt paid for the use of the boat
:
40 -  = 10
:
- = 10 -40
:
- = -30
multiply both sides by -1
= 30
multiply both sides by (b+5)
40b = 30(b+5)
40b = 30b + 150
40b - 30b = 150
10b = 150
b = 15 boys
:
:
Check this. total cost 40*15 = $600
600/20 = 30, $10 less
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