Tutor:

New! Get regular updates about newly solved problems via algebra.com's RSS system.

---

Recent problems solved by 'ankor@dixie-net.com'

ankor@dixie-net.com answered: 15646 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659, >>Next

Triangles/398748: i have a triangle whos first side is 84 degrees and the other is 63 degrees,what is the third side? 1 solutions Answer 282516 by ankor@dixie-net.com(15661)   on 2011-01-24 08:35:10 (Show Source): You can put this solution on YOUR website! You mean angles, you know that a triangle has a total of 180 degrees; What's 180 - 84 - 63

Travel_Word_Problems/398819: Ms. Driva Reck drove from her home to a service station at 48 km/h. She returned home by bicycle at 16 km/h. The entire trip took 4 hours. How far was the service station from Ms. Reck's home? 1 solutions Answer 282513 by ankor@dixie-net.com(15661)   on 2011-01-24 08:22:57 (Show Source): You can put this solution on YOUR website! Ms. Driva Reck drove from her home to a service station at 48 km/h. She returned home by bicycle at 16 km/h. The entire trip took 4 hours. How far was the service station from Ms. Reck's home? : Let d = distance to the service station : Write a time equation: time = dist/time : to time + return time = 4 hrs + = 4 Multiply by 48, to clear the denominators: 48* + 48* = 4(48) d + 3d = 48(4) 4d = 192 d = 192/4 d = 48 km : : Check this 48/48 + 48/3 = 1 + 3 = 4

Polynomials-and-rational-expressions/398648: Is there currently anyone online that can help me by answering a few of my questions? 1 solutions Answer 282509 by ankor@dixie-net.com(15661)   on 2011-01-24 08:01:39 (Show Source): You can put this solution on YOUR website! Questions pertaining to basic algebra? Yes. ankor@att.net

Rate-of-work-word-problems/398521: It takes pump A 2 hours less time than pump B to empty a certain swimming pool. Pump A is started at 8:00 A.M., and pump B is started at 11:00 A.M. If the pool is still half full at 5:00 P.M., then how long would it take pump A working alone? 1 solutions Answer 282451 by ankor@dixie-net.com(15661)   on 2011-01-23 22:10:21 (Show Source): You can put this solution on YOUR website! It takes pump A 2 hours less time than pump B to empty a certain swimming pool. Pump A is started at 8:00 A.M., and pump B is started at 11:00 A.M. If the pool is still half full at 5:00 P.M., then how long would it take pump A working alone? : Let t = time required by pump A working alone then (t+2) = time required by pump B working alone : Pump A: 8 AM to 5 PM: 9 hrs, Pump B: 11Am to 5 PM: 6 hrs : Let the empty pool = 1, then a half full pool = : + = Multiply by 2t(t+2), results: 9(2(t+2)) + 6(2t) = t(t+2) 18(t+2) + 12t = t^2 + 2t 18t + 36 + 12t = t^2 + 2t 30t + 36 = t^2 + 2t A quadratic equation t^2 + 2t - 30t - 36 = 0 t^2 - 28t - 36 = 0 Use the quadratic formula to find t In this equation: x=t; a=1; b=-28; c=-36 Do the math here, should get a positive solution of: t = 29.23 hrs, Pump A will empty the pool alone : : Check solution + = .308 + .192 = .500 (a half full pool)

Rate-of-work-word-problems/398361: if four people can repair a vehicle in 5 1/2 hours, how many people working the same rate will it take to finish the job in 3 hours 1 solutions Answer 282306 by ankor@dixie-net.com(15661)   on 2011-01-23 10:33:44 (Show Source): You can put this solution on YOUR website! if four people can repair a vehicle in 5 1/2 hours, how many people working the same rate will it take to finish the job in 3 hours : Use man-hrs here 4 * 5.5 = 22 man-hrs to complete the job : let m = no. of men to complete the job in 3 hrs 3m = 22 m = m = 7 men, maybe 6 men and boy

Age_Word_Problems/398363: If 2 years ago, the ages of seven children totalled 30, what would their ages total in 3 years time?? 1 solutions Answer 282305 by ankor@dixie-net.com(15661)   on 2011-01-23 10:25:55 (Show Source): You can put this solution on YOUR website! If 2 years ago, the ages of seven children totalled 30, what would their ages total in 3 years time? : since each will add five years to their age, 30 + (5*7) = 65

Rectangles/398282: The area of a rectangle is five times the area of a square. If the rectangle is 50 inches long, and the width of the rectangle is the same as the length of a side of the square, find the dimensions of both the rectangle and the square. inches (length of rectangle) inches (width of rectangle) inches (side length of square) 1 solutions Answer 282299 by ankor@dixie-net.com(15661)   on 2011-01-23 09:30:41 (Show Source): You can put this solution on YOUR website! The area of a rectangle is five times the area of a square. If the rectangle is 50 inches long, and the width of the rectangle is the same as the length of a side of the square, find the dimensions of both the rectangle and the square. : Let s = side of the square, and width of the rectangle then s^2 = area of the square and 50s = area of the rectangle : It says,"The area of a rectangle is five times the area of a square." therefore: 50s = 5s^2 divide both sides by 5s, results 10 = s width of rect and side of square = 10 inches : 10^2 = 100 sq/inches the area of the square and 50*10 = 500 sq/inches the area of the rectangle (5 times the square)

Linear-equations/398262: this is a hard question to put in words, but i have a math equation that looks like this -2y=2-x i set it up like this y=mx+b so -2y=2-x and i divide the whole thing by two i then get y=1 but i dont know how to divide the x and to graph it after i divide by two i use x as zero and y as what my assingment calls for two points of each and im not sure if i drop the run over rise and use the next number and just add or subtract what ever the equation asks for. i need to get a slope on the graph please help me 1 solutions Answer 282223 by ankor@dixie-net.com(15661)   on 2011-01-22 21:36:44 (Show Source): You can put this solution on YOUR website! -2y = 2 - x y has to be positive, multiply both sides by -1 and you have 2y = x - 2 divide both sides by 2, (x is understood to be 1x) y = x - 1 or we could just write it y = .5x - 1; this is the y=mx+b form, the slope is 1/2, or .5 : Choose two values for x and find y, to get your points x=4 y = .5(4) - 1 y = 2 - 1 y = 1 First point: 4, 1 and x = -4 y = .5(-4) - 1 y = -2 - 1 y = -3 Second point: -4, -3 ; : plot these two points, join with a straight line, should look like this: : If we do this correctly, the slope will take care of itself you can see it rises 1 unit for each 2 units of run

Numbers_Word_Problems/398107: A two digit number is 4 times the sum of its digits and twice the product of its digit.FIND THE NUMBER 1 solutions Answer 282196 by ankor@dixie-net.com(15661)   on 2011-01-22 19:20:22 (Show Source): You can put this solution on YOUR website! two digits, x & y 10x + y = the number : A two digit number is 4 times the sum of its digits 10x + y = 4(x+y) 10x + y = 4x + 4y 10x - 4x = 4y - y 6x = 3y divide both sides by 3 2x = y " and twice the product of its digit." 10x + y = 2xy Replace y with 2x 10x + 2x = 2*x*2x 12x = 4x^2 Divide both sides by 4x 3 = x then y = 2(3) y = 6 : the number = 36 : You can confirm this in both statement: 36 = 4(3+6) and 36 = 2(3*6)

Travel_Word_Problems/398166: Two bicyclists, 42 miles apart, begin riding toward each other on a long straight avenue. One cyclist travels 15 miles per hour and the other 20 miles per hour. At the same time, Spot (a greyhound), starting at one cyclist, runs back and forth between the two cyclists as they approach each other. If Spot runs 38 miles per hour and turns around instantly at each cyclist, how far has he run when the cyclists meet? 1 solutions Answer 282171 by ankor@dixie-net.com(15661)   on 2011-01-22 17:57:23 (Show Source): You can put this solution on YOUR website! Two bicyclists, 42 miles apart, begin riding toward each other on a long straight avenue. One cyclist travels 15 miles per hour and the other 20 miles per hour. : Find their travel time (t) when they meet 20t + 15t = 42 t = 42/35 t = 1.2 hrs : At the same time, Spot (a greyhound), starting at one cyclist, runs back and forth between the two cyclists as they approach each other. If Spot runs 38 miles per hour and turns around instantly at each cyclist, how far has he run when the cyclists meet? : Dog travels 38 mph for 1.2 hrs: 1.2*38 = 45.6 mi

Travel_Word_Problems/398162: A boat travels 27 miles downstream in 3 hours, and when traveling upstream it takes twice as much time to travel 2/3 of that distance. Find the rate of the boat in still water and the rate of the current. 1 solutions Answer 282169 by ankor@dixie-net.com(15661)   on 2011-01-22 17:49:24 (Show Source): You can put this solution on YOUR website! A boat travels 27 miles downstream in 3 hours, and when traveling upstream it takes twice as much time to travel 2/3 of that distance. Find the rate of the boat in still water and the rate of the current. : Find the upstream distance: *27 = 18 miles : Let s = boat speed in still water Let c = current speed then (s-c) = effective speed upstream and (s+c) = effective speed downstream : Write a distance equation for each way : 3(s+c) = 27 6(s-c) = 18 Simplify both equations, divide the 1st by 3, and the 2nd by 6, results: s + c = 9 s - c = 3 ------------addition eliminates c, find s 2s = 12 s = 6 mph is the boat speed in still water and 6 + c = 9 c = 3 mph is the current speed : : Check solutions by finding the distance 3(6+3) = 27 6(6-3) = 18

Quadratic_Equations/398138: word problem associated with quadratic equation chapter:: a motorboat maintained a constant speed of 12 mph relative to the water going 23 miles upstream then returning. Total time for the trip was 24 hours. Using this information provided, what is the speed of the current in mph? 1 solutions Answer 282133 by ankor@dixie-net.com(15661)   on 2011-01-22 15:24:04 (Show Source): You can put this solution on YOUR website! a motorboat maintained a constant speed of 12 mph relative to the water going 23 miles upstream then returning. Total time for the trip was 24 hours. Using this information provided, what is the speed of the current in mph? : Let x = speed of the current then (12-x) = effective speed upstream and (12+x) = effective speed downstream : Write a time equation; time = dist/speed : time upstr + time downstr = 24 hrs + = 24 : Multiply equation by (12-x)(12+x) to get rid of the denominators, results: 23(12+x) + 23(12-x) = 24(12-x)(12+x) : 276 + 23x + 276 - 23x = 24(144 - x^2) : 552 = 3456 - 24x^2 : 24x^2 = 3456 - 552 : 24x^2 = 2904 divide both sides by 24 x^2 = 121 x = x = 11 mph is the speed of the current ; : That seems high, but let's check the time each way 23/(12+11) = 1.0 hr 23/(12-11) = 23 hrs -------------------------- round trip time: 24 hrs, which confirms our solution of x = 11 mph current

Quadratic-relations-and-conic-sections/398076: Hi! Im studying for an exam, im having a problem with this problem, i tried to input the values in the formula(x^2=4py) but cant get the answer. The problem is: the distance between two towers is 150m, the points of support of the cable on the towers are 22m above the roadway, and the lowest point on the cable is 7m above the roadway. Find the vertical distance to the cable from a point in the roadway 15m from the foot of a tower. Can you show me how to get the ordinate of the focal parameter being asked? I tried for almost an hour but still cant get the correct answer. the answer stated in the book is 16.6m THAN YOU VERY MUCH!!! 1 solutions Answer 282098 by ankor@dixie-net.com(15661)   on 2011-01-22 09:34:17 (Show Source): You can put this solution on YOUR website! the distance between two towers is 150m, the points of support of the cable on the towers are 22m above the roadway, and the lowest point on the cable is 7m above the roadway. Find the vertical distance to the cable from a point in the roadway 15m from the foot of a tower. : The cable is a parabola; calculate a quadratic equation from the given dimensions Using the form: ax^2 + bx + c = y x=0, y = 22, therefore c = 22 : x=75, y=7; (the midpoint) 75^2a + 75b + 22 = 7 5625a + 75b = 7 - 22 5625a + 75b = -15 and x=150, y=22 (far end) 150^2a + 150b + 22 = 22 22500a + 150b = 22 - 22 22500a + 150b = 0 : Use elimination on these two equations, multiply the 1s equation by 2 subtract from the above equation 22500a + 150b = 0 11250a + 150b = -30 -----------------------subtraction eliminates b, find a 11250a = 30 a = a = .002667 : Find b 22500(.002667) + 150b = 0 60 + 150b = 0 150b = -60 b = b = -.4 : The quadratic equation: y = .00267x^2 -.4x + 22 : Plotting this equation will help understand this: You can see the cable is about 7 meters above 0, crossing the vert at 22 : Find the vertical dist (y) at 15 m from the base of the tower (x) Substitute 15 for x in the equation y = .00267(15^2) -.4(15) + 22 y = .00267(225) - 6 + 22 y = .6 - 6 + 22 y = 16.6 is the vertical height, 15 m from the tower : How about this? Did it make sense to you? Carl

Rate-of-work-word-problems/397946: it takes mang kaloy 3 hrs to plow his ricefield with his new tractor. using the old tractor it takes him 5 hrs. if his son helped him plow the ricefield how long will it take them to plow the ricefield using both tractors 1 solutions Answer 282032 by ankor@dixie-net.com(15661)   on 2011-01-21 21:40:36 (Show Source): You can put this solution on YOUR website! it takes mang kaloy 3 hrs to plow his ricefield with his new tractor. using the old tractor it takes him 5 hrs. if his son helped him plow the ricefield how long will it take them to plow the ricefield using both tractors : Let t = time required working together Let the completed job = 1 (a plowed rice field) : + = 1 multiply thru by 15, results 3t + 5t = 15 8t = 15 t = t = 1.875 hrs, or 1 + .875(60) = 1 hr 52.5 min

Miscellaneous_Word_Problems/397945: The amount of an investment of P dollars for t years at simple interest rate r is given by A = P + Prt. a) Rewrite this formula by factoring out the greatest common factor on the right-hand side. b) Find A if $8300 is invested for 3 years at a simple interest rate of 15%. 1 solutions Answer 282029 by ankor@dixie-net.com(15661)   on 2011-01-21 21:33:46 (Show Source): You can put this solution on YOUR website! The amount of an investment of P dollars for t years at simple interest rate r is given by A = P + Prt. : a) Rewrite this formula by factoring out the greatest common factor on the right-hand side. A = P(1 + rt) ; b) Find A if $8300 is invested for 3 years at a simple interest rate of 15%. A = 8300(1 + (.15*3)) A = 8300 * 1.45 A = $12,035

Miscellaneous_Word_Problems/398023: A college student has finished 48 credit hours with a GPA of 2.875. To get into the program she wishes to enter, she must have a GPA of 3.0. How many additional credit hours of 4.0 work will raise her GPA to 3.0? 1 solutions Answer 282025 by ankor@dixie-net.com(15661)   on 2011-01-21 21:26:18 (Show Source): You can put this solution on YOUR website! A college student has finished 48 credit hours with a GPA of 2.875. To get into the program she wishes to enter, she must have a GPA of 3.0. How many additional credit hours of 4.0 work will raise her GPA to 3.0? : Let c = no. of 4.0 credit hours required to have a 3.0 : = 3.0 Multiply both sides by(c+48), results: 48(2.875) + 4c = 3(c+48) : 138 + 4c = 3c + 144 : 4c - 3c = 144 - 138 : c = 6 credit hrs at 4.0 : : Check this = = 3

Travel_Word_Problems/397878: A man can run 3 kilometers faster than he walks. It takes him 4 hours to run 30 kilometers. How long would it take him to walk the same distance? 1 solutions Answer 281987 by ankor@dixie-net.com(15661)   on 2011-01-21 18:02:26 (Show Source): You can put this solution on YOUR website! : A man can run 3 kilometers faster than he walks. It takes him 4 hours to run 30 kilometers. How long would it take him to walk the same distance? : Let w = his walking speed then (w+3) = his running speed : Therefore: (s+3) = 4(w+3) = 30 4w + 12 = 30 4w = 30 - 12 w = w = 4.5 km/hr is his walking speed therefore: = 6 hrs to walk it

Metalworking/397899: Please help me solve this equation : the square root of 5z multiplied by the square root of 5 minus the squareroot of z 1 solutions Answer 281981 by ankor@dixie-net.com(15661)   on 2011-01-21 17:46:16 (Show Source): You can put this solution on YOUR website! the square root of 5z multiplied by the square root of 5 minus the squareroot of z : I don't see an equal sign here so it is not an equation, we can try to simplify it. which is like terms,

Linear_Equations_And_Systems_Word_Problems/397901: If in 5 days a clerk can copy 125 pages, 36 lines/page, 11 words/line, how many pages of 30 lines each and 12 words per line can he copy in 6 days? -- The answer is 165, but how do I get there? Thank you! 1 solutions Answer 281978 by ankor@dixie-net.com(15661)   on 2011-01-21 17:38:12 (Show Source): You can put this solution on YOUR website! If in 5 days a clerk can copy 125 pages, 36 lines/page, 11 words/line, how many pages of 30 lines each and 12 words per line can he copy in 6 days? : Find how many words per day he can copy = 9900 words per day : In six days: 6 * 9900 = 59400 words : Find the no. of 12 word lines: = 4950 lines : Find no. of 30 line pages: = 165 pages

Mixture_Word_Problems/397861: A guy has five rings, each weighing 11 g, made of an alloy of 15% silver and 85% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 55%. How much silver should he add? 1 solutions Answer 281951 by ankor@dixie-net.com(15661)   on 2011-01-21 16:40:37 (Show Source): You can put this solution on YOUR website! A guy has five rings, each weighing 11 g, made of an alloy of 15% silver and 85% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 55%. How much silver should he add? : Total weight: 5 * 11 = 55 grams : Let s = amt of silver required When 55% gold is obtained, silver content will be 45% : Write a percent silver equation .15(55) + s = .45(s+55) 8.25 + s = .45s + 24.75 s - .45s = 24.75 - 8.25 .55s = 16.5 s = s = 30 grams of silver to be added : : Check .15(55) + 30 = .45(30 + 55) 8.25 + 30 = .45(85) 38.25 = 38.5, confirms our solution of 30 grams of silver

test/397937: This is my algebra 2 question. It says to find the value of x. Area of rectangle=36cm2. Xcm and (x+5) how do u get the answer 4. 1 solutions Answer 281947 by ankor@dixie-net.com(15661)   on 2011-01-21 16:27:33 (Show Source): You can put this solution on YOUR website! his is my algebra 2 question. It says to find the value of x. Area of rectangle=36cm2. Xcm and (x+5) how do u get the answer 4. : Assume you mean the rectangle is x by (x+5), so you have x*(x+5) = 36 x^2 + 5x - 36 = 0 Factors to (x+9)(x-4) = 0 the positive solution x = 4

Systems-of-equations/397758: Write a system of equations to solve the following problem. Let c be the number of child tickets and a be the number of adult tickets. Each child ticket for a ride costs $3, while each adult ticket costs $5. If the ride collected a total of $150, and 40 tickets were sold, how many of each type of ticket was sold? 1 solutions Answer 281929 by ankor@dixie-net.com(15661)   on 2011-01-21 15:43:55 (Show Source): You can put this solution on YOUR website! Write a system of equations to solve the following problem. Let c be the number of child tickets and a be the number of adult tickets. Each child ticket for a ride costs $3, while each adult ticket costs $5. If the ride collected a total of $150, and 40 tickets were sold, how many of each type of ticket was sold? : Two equations: c + a = 40 a = (40-c); use this for substitution and 3c + 5a = $150

Length-and-distance/397681: Rachel and Josie live in the cities 500 miles apart. They leave their home at the same time and travel toward each other at the rate of 40mph and 45mph. If they leave at 9 A.M. at what time will they still be 75 miles apart? 1 solutions Answer 281927 by ankor@dixie-net.com(15661)   on 2011-01-21 15:39:09 (Show Source): You can put this solution on YOUR website! Rachel and Josie live in the cities 500 miles apart. They leave their home at the same time and travel toward each other at the rate of 40mph and 45mph. If they leave at 9 A.M. at what time will they still be 75 miles apart? : Let t = time they will be 75 mi apart : Write a distance equation: dist = speed * time 40t + 45t = (500 - 75) 85t = 425 t = t = 5 hrs: 9 Am + 5 hrs = 2:00 PM, they will be 75 mi apart : : Check this by finding each travel distance 5*40 = 200 mi 5*45 = 225 mi -------------- total: 425 mi; still have 75 mi to cover the total of 500 mi

Surface-area/397920: If 2 square feet of a fence can be painted in 10 minutes, how long will it take to paint 150 feet (squared) of fence? NOTE: The base of the fence is 25 ft long and the height is 6 ft. This is my work: (2 sq ft=10 minutes) 150 ft=750 minutes 750 min/10 minutes=75 minutes= 1hr15min*2=2hrs30min 1 solutions Answer 281926 by ankor@dixie-net.com(15661)   on 2011-01-21 15:28:57 (Show Source): You can put this solution on YOUR website! If 2 square feet of a fence can be painted in 10 minutes, how long will it take to paint 150 feet (squared) of fence? NOTE: The base of the fence is 25 ft long and the height is 6 ft. : If 2 sq/ft require 10 min, then 1 sq/ft required 5 min therefore 150*5 = 750 min, right?

test/397803: What is the most important part of elementary algebra 1 solutions Answer 281921 by ankor@dixie-net.com(15661)   on 2011-01-21 15:17:50 (Show Source): You can put this solution on YOUR website! Doing it!

Polynomials-and-rational-expressions/397800: Multiply. 1 solutions Answer 281919 by ankor@dixie-net.com(15661)   on 2011-01-21 15:16:19 (Show Source): You can put this solution on YOUR website! Square stuff, then: (16x^2)(4x^6) = 64x^8

Linear-equations/397753: Hello! I have a few questions here which all relate to one another and I am having equal difficulty in completing. I will appreciate any and all answers. Problem: Given A(1, 5); B(6, 2); C(-6, -4); and D(-3, 1) answer the following. 1)Find the slope of line AB. 2)Find the length of line CD. (Round to nearest tenth's place.) 3)Find the midpoint of line BD. (Express in terms of fractions.) 4)Find (a) the slope and (b) the y-intercept of the line with the equation 4x+2y=6. Thank you so much!!!! I eagerly await your solution. Thanks in advance for all of your help! :D 1 solutions Answer 281912 by ankor@dixie-net.com(15661)   on 2011-01-21 14:47:12 (Show Source): You can put this solution on YOUR website! Problem: Given A(1, 5); B(6, 2); C(-6, -4); and D(-3, 1) answer the following. : 1)Find the slope of line AB. Find the slope using the slope formula: m = Assign the given points for A & B as follows x1=1; y1=5 x2=6; y2=2 m = = = is the slope of line AB : 2)Find the length of line CD. (Round to nearest tenth's place.) Use the dist equation: d = Assign the given points for C & D as follows x1=-6; y1=-4 x2=-3; y2=1 d = Which is d = = d = = = = 5.8 is the length of CD : 3)Find the midpoint of line BD. (Express in terms of fractions.) Use the mid=point formula: mp = , Assign the BD values as follows x1=6; y1=2 x2=-3; y2=1 mp = , = , is the mid-point : ; 4)Find (a) the slope and (b) the y-intercept of the line with the equation 4x+2y=6. Convert to the slope intercept form y = mx-b 4x + 2y = 6 2y = -4x + 6 divide both sides by 2 y = -2x + 3 (a) slope: -2 (b) y intercept + 3 : : These are the methods for each of these questions, however, there is a lot of chances for math errors here. Follow this with your own calculations to help you learn and make sure I did not make a mistake here somewhere. CArl

Square-cubic-other-roots/397792: Multiply. Simplify your answer. 1 solutions Answer 281895 by ankor@dixie-net.com(15661)   on 2011-01-21 13:31:48 (Show Source): You can put this solution on YOUR website! FOIL The radical cancel out 18 - 120 = -102 -

Graphs/397789: A. Solve -What are the solutions? x=____ B. Find the x-intercepts of -What are the x-intercepts? The x-intercepts are ____. 1 solutions Answer 281894 by ankor@dixie-net.com(15661)   on 2011-01-21 13:24:48 (Show Source): You can put this solution on YOUR website! A. Solve Divide both sides by 4 Find the square root of both sides x = +/- : B. Find the x-intercepts of -What are the x-intercepts? The x-intercepts are + and - .

Linear_Equations_And_Systems_Word_Problems/397884: Four men working together can dig a ditch in 42 days. They begin, but one man works only half-days. How long will it take to complete the job? -- The answer is 48 days, but how do I get there? Been a 10+ years since I've done a problem like this. Thank you! 1 solutions Answer 281892 by ankor@dixie-net.com(15661)   on 2011-01-21 13:16:31 (Show Source): You can put this solution on YOUR website! Four men working together can dig a ditch in 42 days. Find the number of man-days to complete the job 4*42 = 168 man-days : They begin, but one man works only half-days. How long will it take to complete the job? Let d = no. days to complete the job d(3 + .5) = 168 3.5d = 168 d = d = 48 days

Travel_Word_Problems/397718: A sprinter runs the 100-yd dash in 9.3 secs. At the same rate, a. how long would it take the sprinter to run 100.0m? b. What is the sprinters speed in meter per second? c. How long would it take the sprinter to run a distance of 1.45km? 1 solutions Answer 281890 by ankor@dixie-net.com(15661)   on 2011-01-21 13:11:29 (Show Source): You can put this solution on YOUR website! A sprinter runs the 100-yd dash in 9.3 secs. At the same rate, : a. how long would it take the sprinter to run 100.0m? : Find his speed in meters/sec Convert 100 yds to meters: 100 * .9144 = 91.44 meter in 9.3 sec = 9.832 meters/sec then = 10.17 sec to run 100 meters ; : b. What is the sprinters speed in meter per second? 9.832 m/sec (from above) : c. How long would it take the sprinter to run a distance of 1.45km? : If he could maintain this speed (which is doubtful): = 147.47 sec or 2 min 27.47 sec