Tutor:

New! Get regular updates about newly solved problems via algebra.com's RSS system.

---

Recent problems solved by 'ankor@dixie-net.com'

ankor@dixie-net.com answered: 15609 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629, >>Next

Quadratic_Equations/443312: What is the quadratic equation? 1 solutions Answer 305784 by ankor@dixie-net.com(15624)   on 2011-05-01 15:21:05 (Show Source): You can put this solution on YOUR website! A quadratic equation is an equation involving the 2nd power, but no higher power, of an unknown. The general form a^2 + bx + c = 0 (a, b, and c are known; x is unknown) (a does not = 0). There are three ways to solve this kind of equation for x. One way is to factor the left hand side, one is completing the square, and the third is using the quadratic formula:

Trigonometry-basics/443124: If one root of a quadratic equation is 1/2-2i, what is the equation? 1 solutions Answer 305782 by ankor@dixie-net.com(15624)   on 2011-05-01 15:12:15 (Show Source): You can put this solution on YOUR website! If one root of a quadratic equation is 1/2-2i, what is the equation? x = - 2i We can write it x = .5 - 2i x - .5 = -2i Square both sides, FOIL the left side x^2 - 1x + .25 = 4i^2 we know i^2 = -1, therefore x^2 - x + .25 = 4(-1) x^2 - x + .25 = -4 x^2 - x + .25 + 4 = 0 x^2 - x + 4.25 = 0; the equation

Linear-equations/443184: Find x and y intercepts and graph the equation plotting the intercepts, show me how you do this step by step please. Create graph. 5x -6y = -45 1 solutions Answer 305777 by ankor@dixie-net.com(15624)   on 2011-05-01 14:42:06 (Show Source): You can put this solution on YOUR website! Find x and y intercepts and graph the equation plotting the intercepts, show me how you do this step by step please. Create graph. : 5x -6y = -45 : The x intercept occurs when y = 0, replace y with 0 in the above equation 5x - 6(0) = -45 5x = -45 x = x = -9 is the x intercept : The y intercept occurs when x = 0, replace x with 0 in the same equation 5(0) -6y = -45 -6y = -45 y has to be positive, multiply both sides by -1 6y = 45 y = reduces to , therefore: y = 7.5 is the y intercept : we can confirm this with a graph, put equation in to slope/intercept form y = mx + b 5x - 6y = -45 subtract 5x from both sides -6y = -5x - 45 get rid of the negative y, multiply both sides by -1 6y = 5x + 45 divide by 6 y = x - reduce fraction y = x - y = x + 7.5 : Plot this using x=-3 and x=+3 When x= -3 y = (-3) + 7.5 y = + 7.5 y = -2.5 + 7.5 y = 5 Ordered pair -3, 5 : when x = +3 y = (3) + 7.5 y = + 7.5 y = +2.5 + 7.5 y = 10 ordered pair 3, 10 : Plot a straight line thru these to points should look like this You can see the intercepts are what we calculated them to be

Age_Word_Problems/443266: Beth is two years older than Julio. Gerald is twice as old as Beth. Debra is twice as old as Gerald. The sum of their ages is 38. How old is Beth? 1 solutions Answer 305771 by ankor@dixie-net.com(15624)   on 2011-05-01 14:16:59 (Show Source): You can put this solution on YOUR website! Beth is two years older than Julio. Gerald is twice as old as Beth. Debra is twice as old as Gerald. The sum of their ages is 38. How old is Beth? : write an equation for each statement, get everything in terms of b: : Beth is two years older than Julio. b = j+2 or j = (b-2) : Gerald is twice as old as Beth. g = 2b : Debra is twice as old as Gerald. d = 2g Replace g with 2b d = 2(2b) d = 4b : The sum of their ages is 38. b + j + g + d = 38 Replace j, g, d b +(b-2) + 2b + 4b = 38 8b = 38 + 2 b = b = 5 yrs is Beth's age : : Check solution by finding the total 5 + 3 + 10 + 20 = 38, confirms our solution of b=5 :

Travel_Word_Problems/443214: The Smith family and the Jones family are next-door neighbors and are driving to Las Vegas in separate cars for vacation. They are traveling on the same road in the same direction. The Smith family leaves at 8:00am and drives 70mph. Because of a luggage malfunction, the Jones family leaves at 10:00 am and drives 20% faster than the Smith family in an attempt to catch them. A. How long will it take the Jones family to catch the Smith family? 12 hrs B.At what time of day will this occur? 8 pm C. How far from the starting point will they be when the Jones family catches the Smith Family? 840 miles I cannot figure out how to write the equation I figured out the answers on a bar graph 1 solutions Answer 305744 by ankor@dixie-net.com(15624)   on 2011-05-01 12:53:08 (Show Source): You can put this solution on YOUR website! The Smith family and the Jones family are next-door neighbors and are driving to Las Vegas in separate cars for vacation. They are traveling on the same road in the same direction. The Smith family leaves at 8:00am and drives 70mph. Because of a luggage malfunction, the Jones family leaves at 10:00 am and drives 20% faster than the Smith family in an attempt to catch them. ; A. How long will it take the Jones family to catch the Smith family? Let t = travel time of Jones then (t+2) = travel time of Smith : Find Jones' speed: 1.2(70) = 84 mph : When J catches S, they will have traveled the same distance write a distance equation Dist = speed * time : 84t = 70(t+2) 84t = 70t + 140 84t - 70t = 140 14t = 140 t = t = 10 hrs is Jones travel time : B.At what time of day will this occur? 10 Am + 10 hrs = 8 Pm : C. How far from the starting point will they be when the Jones family catches the Smith Family? 84 * 10 = 840 mi : Confirm this by finding the dist of the Smiths 70 * 12 = 840 mi

Rectangles/443128: a rectangle has its length increased by a factor of three and its width increased by a factor of two. what is the ratio of the area of the original rectangle to the area of the larger rectangle? 1:6, 1:5, 1:3, 2:3... can you please explain the equation of how to work this out? 1 solutions Answer 305739 by ankor@dixie-net.com(15624)   on 2011-05-01 12:25:45 (Show Source): You can put this solution on YOUR website! a rectangle has its length increased by a factor of three and its width increased by a factor of two. what is the ratio of the area of the original rectangle to the area of the larger rectangle? : Let L = original Length then 3L = increased length : Let W = original width then 2W = increased width : LW = original area then 3L*2W = 6LW increased area : Areas, Ratio Cancel LW or 1:6 is the ratio of the areas

Quadratic_Equations/443135: Please help me with this problem I am having a diffcult time with it, Than you so much. The population P in 1999 for a state given along with r, its annual percentage rate of continuous growth P= 21 millions, r= 1.9% (a) Write the formula f(x) = P e^yx, where r is in the decimal notation, that models the population in millions x years after 1999. (b) Estimate the population in 2020 F(x) = ? The population in 2020 will be approximately how many million? (round to the nearest tenth as needed) Any help is greatly appreciated!!! 1 solutions Answer 305709 by ankor@dixie-net.com(15624)   on 2011-05-01 10:48:48 (Show Source): You can put this solution on YOUR website! The population P in 1999 for a state given along with r, its annual percentage rate of continuous growth P = 21 millions, r= 1.9% (a) Write the formula f(x) = P e^rx, where r is in the decimal notation, that models the population in millions x years after 1999. f(x) = 21*e^.019x : (b) Estimate the population in 2020, (that's 21 yrs after 1999) F(x) = 21*e^(.019*21) f(x) = 21*e^.399 Find e^.399 on a calc f(x) = 21 *1.4903 f(x) = 31.3 million in 2020

Divisibility_and_Prime_Numbers/442923: Formula x2 - x + 41 substitute the x in the formula with 0, then two even numbers, then two odd numbers and see if a prime number occurs. Try to find a number for x that when substituted in the formula yields a composite number 1 solutions Answer 305599 by ankor@dixie-net.com(15624)   on 2011-04-30 21:48:38 (Show Source): You can put this solution on YOUR website! Formula x^2 - x + 41 substitute the x in the formula with 0, then two even numbers, then two odd numbers and see if a prime number occurs. : This is an equation used to generate prime numbers. : Try to find a number for x that when substituted in the formula yields a composite number. Obviously, when x = 41, we have 41^2 = 1681 has to be a composite number

Miscellaneous_Word_Problems/442880: One more I am stuck on, I feel like there is something missing. A person who must meet the requirements of a nutritional program is considering a combination of two foods which are in tubes. Each tube of A contains 4 units of protein, 2 units of carbs, and 2 units of fat and weighs 3 pounds. The requirement is 42 units of protein, 30 units of carbs, and 18 units of fat. How many tubes of each should be used? 1 solutions Answer 305589 by ankor@dixie-net.com(15624)   on 2011-04-30 21:36:51 (Show Source): You can put this solution on YOUR website! There is something missing, only tube A is given here, there probably should be tube B and tube C

Quadratic_Equations/442639: Solve the following equation by using the quadratic formula. (Enter solutions from smallest to largest. If there is one solution with a multiplicity of two, enter it in both answer boxes.) 3x^2=-4x+2 x = ? x = ? Please show me the steps to get the answer. Thanks 1 solutions Answer 305584 by ankor@dixie-net.com(15624)   on 2011-04-30 21:27:48 (Show Source): You can put this solution on YOUR website! 3x^2 = -4x + 2 put equation into the standard form 3x^2 + 4x - 2 = 0 The quadratic equation In this equation: a=3, b=4, c=-2 : Minus a minus is a plus : : Find the square root. Two solutions x = x = .387 and x = x = -1.721

Miscellaneous_Word_Problems/442797: Please help me solve this equation: If the surface area of a cube is increased by a factor of 64, what is the change in the length if the sides of the cube? 1 solutions Answer 305576 by ankor@dixie-net.com(15624)   on 2011-04-30 21:14:03 (Show Source): You can put this solution on YOUR website! If the surface area of a cube is increased by a factor of 64, what is the change in the length if the sides of the cube? : Let 6x^2 = surface area of original cube Let 6y^2 = surface area of larger cube : 6y^2 = 64(6x^2) divide both sides by 6 y^2 = 64x^2 Find the square root of both sides y = 8x : We can say the new cube side is 8 times the original cube side

Quadratic_Equations/442559: solving by elimination method. 5x+5y=-11 7x-3y=13 1 solutions Answer 305549 by ankor@dixie-net.com(15624)   on 2011-04-30 19:39:00 (Show Source): You can put this solution on YOUR website! solving by elimination method. 5x+5y=-11 7x-3y=13 : Multiply the 1st equation by 3, multiply the 2nd equation by 5, results: 15x + 15y = -33 35x - 15y = 65 -----------------addition eliminates y, find x 50x = 32 x = simplify, divide by 2 x = or x = .64 : Find y using the 1st equation: 5() + 5y = -11 + 5y = -11 same as 3.2 + 5y = -11 5y = -11 - 3.2 5y = -14.2 y = y = -2.84 : : Check solutions in the 2nd original equation: 7x - 3y = 13 7(.64) - 3(-2.84) = 13 4.48 + 8.52 = 13 13 = 13; confirms our solutions

Average/442917: A teacher told Melinda that she has a course average of 78 based on her six math tests. When she got home, she found 5 of her tests with scores of 87, 63, 79, 71, and 96. She couldn't find the sixth test. What score did she obtain on that test? 1 solutions Answer 305538 by ankor@dixie-net.com(15624)   on 2011-04-30 18:49:53 (Show Source): You can put this solution on YOUR website! A teacher told Melinda that she has a course average of 78 based on her six math tests. When she got home, she found 5 of her tests with scores of 87, 63, 79, 71, and 96. She couldn't find the sixth test. What score did she obtain on that test? ; Let x = score on the lost test : = 78 : = 78 Multiply both sides by 6 x + 396 = 6(78) x + 396 = 468 x = 468 - 396 x = 72 is the score of the lost test

Linear-systems/442756: A labourer is engaged for 20 days on the condition that he will receive for Rs. 60 for each day he works and will be fined Rs. 5 for each day he is absent. If he receives Rs. 745 in all, for how many days did he remain absent 1 solutions Answer 305535 by ankor@dixie-net.com(15624)   on 2011-04-30 18:39:56 (Show Source): You can put this solution on YOUR website! A labourer is engaged for 20 days on the condition that he will receive for Rs. 60 for each day he works and will be fined Rs. 5 for each day he is absent. If he receives Rs. 745 in all, for how many days did he remain absent. : Let a = number of days absent then (20-a) = number of days worked : Pay amt - fine amt = 745 60(20-a) - 5a = 745 1200 - 60a - 5a = 745 -65a = 745 - 1200 -65a = -455 a = a = 7 days absent : : Check this, he worked 13 days so we have: 13(60) - 7(5) = 780 - 35 = 745; confirms our solution

Proportions/442768: a) A locomotive is 10 m long and weighs 72 tonnes. A similar model, made of the same material, is 40 cm long, find the mass of the model. b) Suppose the tank of the model locomotive contains 0.85 liters of water when full, find the capacity of the tank of the locomotive. 1 solutions Answer 305521 by ankor@dixie-net.com(15624)   on 2011-04-30 16:49:20 (Show Source): You can put this solution on YOUR website! a) A locomotive is 10 m long and weighs 72 tonnes. A similar model, made of the same material, is 40 cm long, find the mass of the model. : Convert 40 cm to .4 m : Use a volume proportion equation, let x = mass of the 40 cm engine = = Cross multiply: 1000x = 72 * .064 1000x = 4.608 x = x = .004608 tonnes change to kilograms .004608*1000 = 4.61 kg : : b) Suppose the tank of the model locomotive contains 0.85 liters of water when full, find the capacity of the tank of the locomotive. = .064x = 1000*.85 .064x = 850 x = x = 13,281.25 liters of water

Polynomials-and-rational-expressions/442414: Please use the laws of exponents to simplify: 3.7^(7/4)/ 3.7^(4/7) **Please note that the squared portion is a fraction** 1 solutions Answer 305315 by ankor@dixie-net.com(15624)   on 2011-04-29 20:50:47 (Show Source): You can put this solution on YOUR website! Please use the laws of exponents to simplify: = Use a common denominator : , numerators are 49 and 16 : ; numerator is 33

real-numbers/442155: Simplify . I don't know if this is written right. on the problem in front of me the 3 is tiny 1 solutions Answer 305307 by ankor@dixie-net.com(15624)   on 2011-04-29 20:39:19 (Show Source): You can put this solution on YOUR website! Factor inside the radical to reveal the cubes, extract the cube roots: =

test/442574: hey,6ths grade is starting this Augst and im all for the learning but i got a problem as good as i do on average (strait A's 7 years(including kindergarten)but when it comes to those tests im a complete failer!!:( :( i dont know what happend in all subjects i was a great student but when i when into 4th and 5th grade tests just were hard and i would study and study but nothing and after a bit the words would bler and make no sence even if i prononced it right i tried to get a tuder but my parents would get letters saying that i was in gifted classes and they wouldnt lisen i asked my teachers for help nothing(sigh) i even ask my worst nightmare and well.... what do you think!!!!!!! :( whats the matter am i just a rere or is it somthing els??? please help before its too late!!! 1 solutions Answer 305304 by ankor@dixie-net.com(15624)   on 2011-04-29 20:30:57 (Show Source): You can put this solution on YOUR website! It sounds like the teachers have let you down in the early grades. You should not have that much trouble understanding. Ask to go to normal, rather than gifted classes in August, insist on it. See how you do. Those gifted classes, teachers often think, "these kids are smart, I won't have to explain things to them" and they get lazy. Have your parents pick some work books designed for summer at your grade level, insist that your parents help you with them. You will feel much better if you go into the 6th grade knowing what to expect.

Travel_Word_Problems/442273: Two houses on the same road are 10 miles apart. The angles formed between the road and the lines of sight from the houses to a cell phone tower are 51 degrees and 39 degrees. Find the distances between each house and the cell phone tower (round to nearest tenth) 1 solutions Answer 305295 by ankor@dixie-net.com(15624)   on 2011-04-29 20:07:15 (Show Source): You can put this solution on YOUR website! Two houses on the same road are 10 miles apart. The angles formed between the road and the lines of sight from the houses to a cell phone tower are 51 degrees and 39 degrees. Find the distances between each house and the cell phone tower (round to nearest tenth) : Find the third angle: 180 - 51 - 39 = 90 degrees, so it is a right triangle Therefore sin(51) = .777*10 = a a = 7.8 mi, one house dist to tower and cos(51) = .629*10 = b 6.3 mi, the other house to the tower

Quadratic_Equations/442106: Solve the following equation by using the quadratic formula. (Enter solutions from smallest to largest. If there is one solution with a multiplicity of two, enter it in both answer boxes.) 9x^2+18x+2=0 x = ? x = ? Please show me the steps to get the answer. Thanks 1 solutions Answer 305023 by ankor@dixie-net.com(15624)   on 2011-04-28 22:05:09 (Show Source): You can put this solution on YOUR website! Solve the following equation by using the quadratic formula. 9x^2 + 18x + 2 = 0 the quadratic formula: In this problem a=9, b=18, c=2 : : Two solutions x = x = -.1181 and x = x = -1.882

Quadratic_Equations/441579: Ms. Theodorou wants to hang a portrait of Mr Fucheck in the hallway. The length of the picture is (x+2) and the width of the picture is (x+1). Ms Cavazzi will build a frame out of wood. The Frame will have a 2 inch border. The area of that entire Portrait will cover is 272 inches square. Find the dimensions of the picture. 1 solutions Answer 304974 by ankor@dixie-net.com(15624)   on 2011-04-28 19:22:08 (Show Source): You can put this solution on YOUR website! Ms. Theodorou wants to hang a portrait of Mr Fucheck in the hallway. The length of the picture is (x+2) and the width of the picture is (x+1). Ms Cavazzi will build a frame out of wood. The Frame will have a 2 inch border. The area of that entire Portrait will cover is 272 inches square. Find the dimensions of the picture. : A 2" border will add 4" to each picture dimension therefore (x+2) + 4 = (x+6); overall length (x+1) + 4 = (x+5); overall width : Entire area (x+6)*(x+5) = 272 FOIL x^2 + 6x + 5x + 30 = 272 x^2 + 11x + 30 - 272 = 0 x^2 + 11x - 242 = 0 You can solve this using the quadratic formula: a=1; b=11; c=-242 But it will factor to (x+22)(x-11) = 0 the positive solution x = 11 therefore 11 + 2 = 13" is the length of the picture 11 + 1 = 12" is the width : : Check this by finding the overall area with these values (13+4)*(12+4) = 272

Numbers_Word_Problems/441564: eight less than the product of three and a number is one. what is the number? 1 solutions Answer 304792 by ankor@dixie-net.com(15624)   on 2011-04-27 21:50:51 (Show Source): You can put this solution on YOUR website! Just write an equation for what it says: : eight less than the product of three and a number is one. what is the number? 3x - 8 = 1 I'm sure you can solve this

Polynomials-and-rational-expressions/441667: Wendy can type 12 pages in 4 hours. How long does it take Anita to type 5 pages if she and wendy can type 28 pages in 8 hours when they work together 1 solutions Answer 304789 by ankor@dixie-net.com(15624)   on 2011-04-27 21:42:59 (Show Source): You can put this solution on YOUR website! Wendy can type 12 pages in 4 hours. How long does it take Anita to type 5 pages if she and Wendy can type 28 pages in 8 hours when they work together : Find Wendy's typing rate: 12/4 = 3 pages/hr Let a = Anita's typing rate : Find Anita's typing rate 8a + 8(3) = 28 8a + 24 = 28 8a = 28 - 24 8a = 4 a = a = .5 pages/hr, Anita's typing rate : Find how long to type 5 pages at this rate t = 5/.5 t = 10 hrs for Anita to type 5 pages

Travel_Word_Problems/441562: An Object falling from rest covers distance of d=9800t²mm in t seconds. Solve this equation for t and determine how many seconds it takes for an object to fall 22,050 mm. 1 solutions Answer 304786 by ankor@dixie-net.com(15624)   on 2011-04-27 21:32:54 (Show Source): You can put this solution on YOUR website! An Object falling from rest covers distance of d = 9800t²mm in t seconds. Solve this equation for t and determine how many seconds it takes for an object to fall 22,050 mm. : Replace d with 22,050 : 9800t^2 = 22050 t^2 = t^2 = 2.25 t = t = 1.5 seconds to fall 22,050 mm : : Check solution 9800(1.5^2) = 9800(2.25) = 22050

Travel_Word_Problems/441538: Write the equation of this problem: Suppose an airplane can travel 160 miles in the same time a second airplane can travel 200 miles. If the speed of the second airplane is 20 miles per hour faster than the first airplane, what was the speed of the first airplane? 1 solutions Answer 304783 by ankor@dixie-net.com(15624)   on 2011-04-27 21:26:49 (Show Source): You can put this solution on YOUR website! Write the equation of this problem: Suppose an airplane can travel 160 miles in the same time a second airplane can travel 200 miles. If the speed of the second airplane is 20 miles per hour faster than the first airplane, what was the speed of the first airplane? : Let s = speed of the 1st airplane it says,"the speed of the second airplane is 20 miles per hour faster than the first" therefore: (s+20) = speed of the 2nd airplane : Write time equation; time = dist/speed : 2nd plane travel time = 1st plane travel time = : Cross multiply 200s = 160(s+20) 200s = 160s + 3200 200s - 160s = 3200 40s = 3200 s = s = 80 mph speed of 1st plane then 80 + 20 = 100 mph speed of the the 2nd plane ; : Confirm this, find the actual times, they should be equal 200/100 = 2 hrs 160/80 = 2 hrs

Geometry_Word_Problems/441176: A rancher with 750 ft of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle. a.) Find a function that models the total area of the four pens. b.) Find the largest possible total area of four pens. 1 solutions Answer 304760 by ankor@dixie-net.com(15624)   on 2011-04-27 20:17:15 (Show Source): You can put this solution on YOUR website! A rancher with 750 ft of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to one side of the rectangle. ; a.) Find a function that models the total area of the four pens. The perimeter for this 2L + 5W = 750 2L = (750-5W) L = The Area equation A = L * W Replace L A = *W A = : b.) Find the largest possible total area of four pens. Max area will occur at axis of symmetry, formula for that x = -b/(2a) W = W = 75 ft for max area : Find the area : A = +14,062.5 sq/ft max area

Exponents-negative-and-fractional/441289: I can't figure out how to simplify this problem: Please help me. 1 solutions Answer 304712 by ankor@dixie-net.com(15624)   on 2011-04-27 17:01:38 (Show Source): You can put this solution on YOUR website! divide 3 into 12 we want to combine exponents of like terms, so they are positive using common denominators : ; the top exponents should be 7/6

Age_Word_Problems/441229: if bob is one third the age of his dad. in 12 years he will be half his age how old are they now? 1 solutions Answer 304704 by ankor@dixie-net.com(15624)   on 2011-04-27 16:24:05 (Show Source): You can put this solution on YOUR website! Let b = Bob's present age Let d = dad's present age : Write an equation for each statement: : "bob is one third the age of his dad." b = d Multiply by 3 to get rid of the fraction, results 3b = d : "in 12 years he will be half his age" b + 12 = (d+12) multiply by 2, to get rid of the fraction, results 2(b+12) = d + 12 2b + 24 = d + 12 2b = d + 12 - 24 2b = d - 12 Replace d with 3b, from the 1st statement: 2b = 3b - 12 12 = 3b - 2b b = 12 yrs is bob's present age : I'll let you find dad's age, check the solution in the 2nd statement

logarithm/441348: I have no idea how to do this my teacher never taught this type to us. I tried to look in the book but am just so confused with story problems and how to even go about doing this problem. The amount remaining of a certain radioactive substance after t days is A(t)=A e^(-0.0025t) where A is the begining amount. How much do we need to 0 0 begin with if we want 80 grams after 10 days? 1 solutions Answer 304651 by ankor@dixie-net.com(15624)   on 2011-04-27 13:58:42 (Show Source): You can put this solution on YOUR website! The amount remaining of a certain radioactive substance after t days is A(t) = A*e^(-0.0025t) where A is the beginning amount. How much do we need to begin with if we want 80 grams after 10 days? : write the equation: A*e^(-0.0025t) = A(t) Given values: A(t) = 80 t = 10 Replace A(t) and t and we have: A*e^(-0.0025*10) = 80 : A*e^(-0.025) = 80 Find e^-.025 on a calc, then we have: .97531A = 80 A = A = 82.025 grams will decay to 80 grams in 10 days ; : Check this on a calc: enter: 82.025*e^(-.0025*10): results: 79.9998 ~ 80 : How about this? Did we shed some light on this stuff for you?

Equations/441095: Hello, i have to solve these equations by rearranging. 1.3x=7 2.12(x+5)=3(7+4x) 3.5(x-3)=2x-3(x+1) Thank you for all your help :) much appreciated 1 solutions Answer 304562 by ankor@dixie-net.com(15624)   on 2011-04-27 07:41:46 (Show Source): You can put this solution on YOUR website! 1.3x=7 divide both sides by 3 x = : 2.12(x+5)=3(7+4x) multiply whats inside the brackets 12x + 60 = 21 + 12x Combine like terms 12x - 12x = 21 - 60 0 = -39, obviously not a valid equation : 3. 5(x-3)=2x-3(x+1) 5x - 15 = 2x - 3x - 3; neg outside the brackets, changes the sign inside 5x - 15 = -x - 3 5x + x = -3 + 15 6x = 12 divide both sides by 6 x = x = 2 Check solution in original equation 5(2-3)=2(2)-3(2+1) 5(-1) = 4 -3(3) -5 = 4 -9

Radicals/441085: For this problem I got this far... x^2(x^2-43)+450=0 How would you factor this? Help me! 1 solutions Answer 304526 by ankor@dixie-net.com(15624)   on 2011-04-26 21:58:36 (Show Source): You can put this solution on YOUR website! For this problem I got this far... x^2(x^2-43)+450=0 How would you factor this? Write it: x^4 - 43x^2 + 450 = 0 This will factor to (x^2 - 18)(x^2 - 25) = 0 Four solutions x^2 = 18 x = +/- x = +/- and x^2 = 25 x = +/- x = +/- 5 : Check all solutions in the original equation