New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'ankor@dixie-net.com'
ankor@dixie-net.com answered: 15730 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749, >>NextEquations/523114: given that velocity can be described in terms of the acceleration rate and the time period . . . v=at and given that the time period can be described can be described in terms of the distance covered and the acceleration rate . . . t=square root of 2d/a, how would I convert the equation to describe the velocity in terms of distance and acceleration? 1 solutions
Answer 347221 by ankor@dixie-net.com(15745) on 2011-10-29 21:51:25 (Show Source):
You can put this solution on YOUR website!given that velocity can be described in terms of the acceleration rate and the time period . . . v=at
and given that the time period can be described can be described in terms of the distance covered and the acceleration rate . . . t=square root of 2d/a,
how would I convert the equation to describe the velocity in terms of distance and acceleration?
:
v = a*t
replace t with 
v = 
we can also write it
v = 
cancel a
v =
|
Polynomials-and-rational-expressions/523083: I am having trouble understanding how to do this problem. (3a-5)cubed
I have the answer but don't know how they got it. Can you please help me?????
Thanks,
Jill 1 solutions
Answer 347217 by ankor@dixie-net.com(15745) on 2011-10-29 21:31:26 (Show Source):
You can put this solution on YOUR website!
which is
(3a-5)*(3a-5)*(3a-5)
First FOIL (3a-5)(3a-5)
9a^2 - 5a - 5a + 25
9a^2 - 10a + 25
Multiply this by (3a-5), using the old method of multiplying you learned in grade school.
9a^2 - 10a + 25
. . X . . 3a - 5
----------------
you should get
27a^3 - 75a^2 + 125a - 125
|
Travel_Word_Problems/523129: Trais made a business trip of 234 miles. He averaged 54 mph for the first part of the trip and 60 mph for the second part. If the trip took 4 hours, how long did he travel at each rate? 1 solutions
Answer 347196 by ankor@dixie-net.com(15745) on 2011-10-29 20:10:24 (Show Source):
You can put this solution on YOUR website!a business trip of 234 miles. He averaged 54 mph for the first part of the trip and 60 mph for the second part.
If the trip took 4 hours, how long did he travel at each rate?
:
Let t = travel time at 60
then
(4-t) = travel time at 54
:
Write a distance equation: dist = speed * time
:
dist at 60 + dist at 54 = 234 mi
60t + 54(4-t) = 234
60t + 216 - 54t = 234
60t - 54t = 234 - 216
6t = 18
t = 18/6
t = 3 hrs at 60 mph
then
4 - 3 = 1 hr at 54 mph
:
:
Check by finding the distance at each speed
3*60 = 180
1*54 = 54
-----------
total: 234 mi
|
Circles/523096: A bicycle tire has a diameter of 14 in. How many feet does the bicycle travel when the wheel makes 20 revolutions? Round to the nearest hundredth of a foot. 1 solutions
Answer 347182 by ankor@dixie-net.com(15745) on 2011-10-29 15:30:38 (Show Source):
You can put this solution on YOUR website!A bicycle tire has a diameter of 14 in.
How many feet does the bicycle travel when the wheel makes 20 revolutions? Round to the nearest hundredth of a foot.
:
d = 
d = 879.65 ft
|
Linear-equations/523082: please could you let me know: determine the equqtion of the line through the given point with the given slope
(2,-5) m=1
thank you 1 solutions
Answer 347181 by ankor@dixie-net.com(15745) on 2011-10-29 15:27:13 (Show Source):
You can put this solution on YOUR website!(2,-5) m=1
Use the point slope format: y - y1 = m(x-x1)
In this problem: x1=2, y1=-5, m=1
:
y - (-5) = 1(x - 2)
y + 5 = 1x - 2
y = x - 2 - 5
y = x - 7
:
:
Check this, replace x with 2
y = 2 - 7
y = -5
|
Travel_Word_Problems/522807: A trip between two cites 175 miles apart take 1.5 hrs less than by bus. The average speed of the bus is 15 miles per hour less than the train.
Find the average speeds of the train and the bus. 1 solutions
Answer 347167 by ankor@dixie-net.com(15745) on 2011-10-29 10:46:48 (Show Source):
You can put this solution on YOUR website!A trip between two cites 175 miles apart take 1.5 hrs less than by bus.
The average speed of the bus is 15 miles per hour less than the train.
Find the average speeds of the train and the bus.
:
Let s = speed of the bus
then
(s+15) = speed of the train
:
Write a time equation, time = dist/speed
:
Train time - Bus time = 1.5 hrs
 -  = 1.5
;
multiply by s(s+15)
s(s+15)*  - s(s+15)*  = 1.5s(s+15)
:
Cancel out the denominators, results:
175(s+15) - 175s = 1.5s^2 + 22.5s
175s + 2625 - 175s = 1.5s^2 + 22.5s
:
a quadratic equation
0 = 1.5s^2 + 22.5s - 2625
get rid of the decimals, multiply by 2
3s^2 + 45s - 5250 = 0
You can use the quadratic formula here, but this will factor to:
(3s-105)(s+50) = 0
positive solution
3s = 105
s = 105/3
s = 35 mph is the speed of the bus,
then
35+15 = 50 mph is the speed of the train
:
:
Check this by finding the actual time of each
175/35 = 5.0 hrs
175/50 = 3.5 hrs
-----------------
differs: 1.5 hrs
|
Numbers_Word_Problems/522973: the difference of digits of two digit number is 1.five times the sum of the number plus one is equal to the number. find the number 1 solutions
Answer 347160 by ankor@dixie-net.com(15745) on 2011-10-29 10:19:55 (Show Source):
You can put this solution on YOUR website!the difference of digits of two digit number is 1.
five times the sum of the number plus one is equal to the number.
find the number
:
Two digits, a, b
then
10a + b = the number
:
"the difference of digits of two digit number is 1."
a - b = 1
:
"five times the sum of the number plus one is equal to the number."
5(a+b) + 1 = 10a + b
5a + 5b + 1 = 10a + b
5a - 10a + 5b - b = -1
-5a + 4b = -1
:
Use substitution here, multiply the 1st equation by 4, add to the 2nd eq
+4a - 4b = 4
-5a + 4b = -1
--------------addition eliminates b, find a
-a = 3
a = -3
find b
-3 - b = 1
-b = 1 + 3
-b = 4
b = -4
:
The number
-3(10) + (-4) = -34 is the number
:
:
Usually not a neg answer in these problems, see if this works in the statement:
"five times the sum of the number plus one is equal to the number."
5(-3 + (-4)) + 1 = -34
5(-7) + 1 = -34
-35 + 1 = -34; confirms our solution of -34
|
Travel_Word_Problems/523006: David and Frank cycle from Islamabad to Lahore, a distance of 210 km, at the speeds of 20 km/hr and 15 km/hr. David reaches Lahore and starts back for Islamabad. How far Lahore will he meet Frank? 1 solutions
Answer 347159 by ankor@dixie-net.com(15745) on 2011-10-29 09:52:07 (Show Source):
You can put this solution on YOUR website!David and Frank cycle from Islamabad to Lahore, a distance of 210 km, at the speeds of 20 km/hr and 15 km/hr.
David reaches Lahore and starts back for Islamabad.
How far Lahore will he meet Frank?
:
Find the time for the faster cyclist to arrive at Lahore
t = 
t = 10.5 hr
:
Find how far Frank is from Lahore in 10.5 hrs
d = 210 -(15*10.5)
d = 52.5 km from Lahore when David arrives at Lahore
:
Find the travel time (m) for them to meet from this point
write a distance equation, dist = speed * time
15m + 20m = 52.5
35m = 52.5
m = 
m = 1.5 hrs for them to meet
:
Find how far from Lahore in 1.5 hrs
1.5*20 = 30 km from Lahore when they meet
|
Travel_Word_Problems/523010: A driver on a highway journey of 50 km travels the first 30 km in exactly 20 mnts and completes the rest of the journey at a constant speed of 100 kmph.find the average speed os the driver in first 30 km 1 solutions
Answer 347157 by ankor@dixie-net.com(15745) on 2011-10-29 09:23:43 (Show Source):
You can put this solution on YOUR website!A driver on a highway journey of 50 km travels the first 30 km in exactly 20 minutes and completes the rest of the journey at a constant speed of 100 kmph.
find the average speed of the driver in first 30 km.
:
Speed = dist/time
change 20 min to  hr
s = 
s = 30 * 3
s = 90 km/h
|
Expressions-with-variables/522607: Subtract. Simplify if possible.
(4-y/y-6)-(4y-9)/6-y
Please show work so I understand how you arrived at your answer.
Thank you. 1 solutions
Answer 347108 by ankor@dixie-net.com(15745) on 2011-10-28 21:53:53 (Show Source):
You can put this solution on YOUR website!Subtract. Simplify if possible.
 - 
:
on the 2nd denominator we can factor out -1, to make the denominators the same
 - 
:
this changes the sign so we have:
 + 
:
the denominators are the same so we can write it, then combine like terms:
 =  =
|
Points-lines-and-rays/522909: which equations that satisfy this fact?
A is the midpoint of SM.
.S------.A------.M <---- this is supposed to represent a line lol
SA = AM
SA + AM = SM
SM + AM = SA
AM + SM = SA
Thank you for taking the time to help me out! :)
1 solutions
Answer 347105 by ankor@dixie-net.com(15745) on 2011-10-28 21:41:45 (Show Source):
You can put this solution on YOUR website!A is the midpoint of SM.
.S------.A------.M <---- this is supposed to represent a line lol
SA = AM
SA + AM = SM
the others don't
|
Rate-of-work-word-problems/522803: if it takes 7 people 15 days to do a job, how long will it take 3 people to do the same job. 1 solutions
Answer 347101 by ankor@dixie-net.com(15745) on 2011-10-28 21:34:57 (Show Source):
You can put this solution on YOUR website!If it takes 7 people 15 days to do a job, how long will it take 3 people to do the same job.
:
Find the number of man-days to do the job: 7 * 15 = 105 man-days to do the job
:
Let d = number of days required for 3 men to do the job
3d = 105
d = 105/3
d = 35 days for 3 men to do it.
|
Money_Word_Problems/522735: Pete gets paid $35 per hour to fix the blinking lights at the top of the radio transmission towers, and this week, since there ate no thunderstorms in the forecast, he plans to work 5 hours overtime. By week's end, the government will have taken out $462 in taxes from his check, leaving him a total of $1,463. How many hours does pete normally work per week?
HELP PLEASSSE! 1 solutions
Answer 347097 by ankor@dixie-net.com(15745) on 2011-10-28 21:15:23 (Show Source):
You can put this solution on YOUR website!Pete gets paid $35 per hour to fix the blinking lights at the top of the radio transmission towers, and this week, since there ate no thunderstorms in the forecast, he plans to work 5 hours overtime.
By week's end, the government will have taken out $462 in taxes from his check, leaving him a total of $1,463.
How many hours does pete normally work per week?
:
Find his gross, (total made for the week) 1463 + 462 = $1925
:
Assume he gets time & a half for overtime: 1.5*5*35 = $262.50 for the 5 hrs OT
:
Let x = normal number of hours worked per week (no overtime)
:
normal pay = gross - overtime pay
35x = 1925 - 262.50
35x = 1662.50
x = 
x = 47.5 hrs
|
Age_Word_Problems/522324: Use an algebraic approach to solve the problem. (Objective 2)
Aura took three biology exams and has an average score of 87. Her second exam score was 7 points better than her first, and her third exam score was 4 points better than her second exam. What were her three exam scores?
(lowest score)
(highest score)
1 solutions
Answer 347093 by ankor@dixie-net.com(15745) on 2011-10-28 20:54:59 (Show Source):
You can put this solution on YOUR website!Aura took three biology exams and has an average score of 87.
 = 87
a + b + c = 3(87)
a + b + c = 261
:
Her second exam score was 7 points better than her first,
b = a+7
or
a = b-7
:
and her third exam score was 4 points better than her second exam.
c = b+4
:
a + b + c = 261
Replace a and c
(b-7) + b + (b+4) = 261
3b - 3 = 261
3b = 261 + 3
3b = 264
b = 264/3
b = 88
:
You should be able to find a and c now
What were her three exam scores?
(lowest score)
|
Age_Word_Problems/522747: Dear Tutor,
I am having a hard time trying to work out this problem. Would you please be so kind as to try and help me.
This is the question:
John is 3 times younger than his dad's age. The sum of their ages is 79. Find Johns age as a fraction.
I tied by saying 79 divide by 3 and got 26 and a third but I would like to know for sure.
Thank you for taking the time to help me
kind regards
Tracey 1 solutions
Answer 347091 by ankor@dixie-net.com(15745) on 2011-10-28 20:24:29 (Show Source):
You can put this solution on YOUR website!I would do it this way
:
John is 3 times younger than his dad's age.
d = 3j
but they want John's age as a fraction, divide both sides by 3
j =  d
:
The sum of their ages is 79.
d + j = 79
:
replace j with  d
1d +  d = 79
:
1 1/3 = 4/3, so write it
 d = 79
:
multiply both sides by 3, to get rid of the denominators
4d = 3(79)
4d = 237
d = 237/4
d = 59.25 is Dad's age
then
j =  59.25
j = 19.75 or 19  yr is John's age
:
:
Check this by finding the sum of their ages
59.25
19.75
-----
79.00
|
Travel_Word_Problems/522755: A train when moves at an average speed of 40 kmph reaches it's destination on time. if the average speed becomes 35 kmph, then it reaches the destination 15 minutes late. Find the length of the journey?
1 solutions
Answer 347084 by ankor@dixie-net.com(15745) on 2011-10-28 20:00:25 (Show Source):
You can put this solution on YOUR website!A train when moves at an average speed of 40 kmph reaches it's destination on time.
if the average speed becomes 35 kmph, then it reaches the destination 15 minutes late.
Find the length of the journey?
:
Let d = the length of the journey
:
Change 15 min to .25 hr
:
Write a time equation; time = dist/speed
:
Slow time - required time = .25 hrs
 -  = .25
multiply by 280,
280*  - 280*  = 280(.25)
cancel the denominators:
8d - 7d = 70
d = 70 km is the length of the journey
:
:
Check this, find the time at each speed
70/35 = 2.00 hr
70/40 = 1.75 hr
----------------
time dif: .25 hrs which is 15 min
|
Travel_Word_Problems/522570: A person travels by car from one city to another with different constant speeds between the cities. She drives 30 min at 80 km/hr, 12 min at 100 km/hr and 45 min at 40 km/hr. Determine the average speed for the trip and determine the distance between the initial and final cities along the trip. 1 solutions
Answer 347072 by ankor@dixie-net.com(15745) on 2011-10-28 18:42:36 (Show Source):
You can put this solution on YOUR website!A person travels by car from one city to another with different constant speeds between the cities. She drives 30 min at 80 km/hr, 12 min at 100 km/hr and 45 min at 40 km/hr.
Determine the average speed for the trip and determine the distance between the initial and final cities along the trip.
:
Change minutes to hrs, divide by 60:
30 min = .50 hrs
45 min = .75 hrs
12 min = .20 hrs
----------------
total + 1.45 hrs, total travel time
:
let a = average speed for the trip
:
Write a dist equation, dist = speed * time
:
80(.5) + 100(.20) + 40(.75) = 1.45a
40 + 20 + 30 = 1.45a
90 = 1.45a
a = 
a = 62.069 km/h, for the entire trip
and
90 km is the total distance
|
Travel_Word_Problems/522714: two cars are leaving a city, one traveling east and the other traveling west. the car going east is traveling at 66 mph and the cargoing west is traveling at 60 mph. how long before they are 441 miles apart?
write an algebraic expression for the distance traveled by the car going east
write an algebraic expression for the distance traveled by the car going west
write an algebraic expression for the total distance traveled by the two cars
write an equation to answer the question
1 solutions
Answer 347027 by ankor@dixie-net.com(15745) on 2011-10-28 15:30:30 (Show Source):
You can put this solution on YOUR website!two cars are leaving a city, one traveling east and the other traveling west.
the car going east is traveling at 66 mph and the car going west is traveling at 60 mph.
how long before they are 441 miles apart?
:
write an algebraic expression for the distance traveled by the car going east
66t
:
write an algebraic expression for the distance traveled by the car going west
60t
;
write an algebraic expression for the total distance traveled by the two cars
66t + 60t
:
write an equation to answer the question
66t + 60t = 441
126t = 441
t = 
t = 3.5 hrs
|
Travel_Word_Problems/522686: If a train travels at the speed of 45 km/hr, it is late by 48 minutes. If it travels 50 km/hr it arrives exactly on time. What is distance the train is traveling (in km)? 1 solutions
Answer 347018 by ankor@dixie-net.com(15745) on 2011-10-28 15:05:37 (Show Source):
You can put this solution on YOUR website!If a train travels at the speed of 45 km/hr, it is late by 48 minutes.
If it travels 50 km/hr it arrives exactly on time.
What is distance the train is traveling (in km)?
:
let d = the distance traveled
then
 = the time to arrive on time
and
 = the time to be 48 min late
:
Convert 48 min:  = .8hrs
:
slower time - ideal time = .8 hrs
 -  = .8
multiply by 450
450*  - 450*  = 450(.8)
cancel the denominators, results:
10d - 9d = 360
d = 360 miles is the distance
;
:
:
Check this by finding the times
360/45 = 8.0 hrs, late
360/50 = 7.2 hrs. on time
-----------------
differs: .8 hrs which is 48 min
|
Linear_Equations_And_Systems_Word_Problems/522670: Doreen and Irena plan to leave their houses at the same time, roller blade towards each other, and meet fo rlunch after 4 hours on the road. Doreen can maintain a speed of 7 mph, which is 70% of Irena's speed. If they meet exactly as planned, what is the distance between their houses.
1 solutions
Answer 347014 by ankor@dixie-net.com(15745) on 2011-10-28 14:24:59 (Show Source):
You can put this solution on YOUR website!meet for lunch after 4 hours on the road.
Doreen can maintain a speed of 7 mph, which is 70% of Irena's speed.
If they meet exactly as planned, what is the distance between their houses.
:
let s = Irene's speed
Find d's speed
.7s = 7
s = 7/.7
s = 10 mph is Irene's speed
:
Write a distance equation; dist = speed * time
4(10) + 4(7) = 68 miles
|
Rate-of-work-word-problems/522778: A certain tank can be filled by pipe A in 12 minutes. Pipe B can empty the tank in 18 minutes. If both pipes are open, how long will it take to fill or empty the tank? 1 solutions
Answer 347013 by ankor@dixie-net.com(15745) on 2011-10-28 14:10:13 (Show Source):
You can put this solution on YOUR website!A certain tank can be filled by pipe A in 12 minutes. Pipe B can empty the tank in 18 minutes.
If both pipes are open, how long will it take to fill or empty the tank?
:
It takes less time to fill it than to empty it, therefore with both valves open the tank will be filled eventually
:
Let t = time to fill the tank with both valves open
Let a full tank = 1
 -  = 1
multiply by 36
36*  - 36*  = 36(1)
Cancel the denominators, results
3t - 2t = 36
t = 36 hrs to fill the tank with both valves left open
|
Travel_Word_Problems/522681: A truck driver began driving at 8 am,drove 570 miles,and arrived at his destination at 6 pm. His stops along the route added up to exactly 1 hour. While he was driving, he averaged 65 mph for the first part of the trip and 60 mph for the rest of the trip. How long did he travel at each rate? 1 solutions
Answer 347011 by ankor@dixie-net.com(15745) on 2011-10-28 13:58:00 (Show Source):
You can put this solution on YOUR website!A truck driver began driving at 8 am,drove 570 miles,and arrived at his destination at 6 pm.
His stops along the route added up to exactly 1 hour.
While he was driving, he averaged 65 mph for the first part of the trip and 60 mph for the rest of the trip.
How long did he travel at each rate?
:
From the information given, we know the trip took 10 hrs
Stops added up to 1 hr, so travel time = 9 hrs
:
Let t = travel time at 65 mph
then
(9-t) = travel time at 60 mph
:
Write a distance equation, dist = speed * time
65t + 60(9-t) = 570
65t + 540 - 60t = 570
65t - 60t = 570 - 540
5t = 30
t = 30/5
t = 6 hrs at 65 mph
then
9-6 = 3 hrs at 60 mph
:
:
Check this by finding the dist at each speed
65(6) = 390
60(3) = 180
-----------
total = 570
|
Age_Word_Problems/522751: Dear Tutor,
My question is this:
Jason started reading a book with 450 pages. He finished reading 300 pages. In its simplest form, what fraction of the book is left unread.
my answer is 1.5 but I would like to know if it is right and if not, if you could help me solve it please.
Thank you so much for taking the time to do this for me
Tracey 1 solutions
Answer 347004 by ankor@dixie-net.com(15745) on 2011-10-28 13:23:26 (Show Source):
You can put this solution on YOUR website!Jason started reading a book with 450 pages.
He finished reading 300 pages.
In its simplest form, what fraction of the book is left unread.
:
Find how many pages left for him to read;
450-300 = 150 pages unread
then
 , we can reduce this fraction, divide numerator and denominator by 150, results:
 of the book unread
|
Rate-of-work-word-problems/522592: If 15 workers can complete a job in 20 days, how long should it take 25 workers to complete the same job? 1 solutions
Answer 347002 by ankor@dixie-net.com(15745) on 2011-10-28 13:15:04 (Show Source):
You can put this solution on YOUR website!If 15 workers can complete a job in 20 days, how long should it take 25 workers to complete the same job?
:
Let's use man-days to do this problem
:
15*20 = 300 man-days required to do this job
:
Let d = no. of days using 25 workers
:
25d = 300
d = 
d = 12 days to complete the job with 25 men
|
Travel_Word_Problems/522652: Over thanksgiving break, drew decides to fly home from Arcata airport. The pilot announces that they have a tailwind and thus will make the 300 mile flight to San Fransisco airport in 45 minutes. Unfortunately, coming home, the pilot announces over the intercom that there is a headwind and they will be taking an hour and a half to get to Arcata Airport. How fast is the tailwind/headwind and how fast is Drew's airplane? 1 solutions
Answer 347001 by ankor@dixie-net.com(15745) on 2011-10-28 13:07:22 (Show Source):
You can put this solution on YOUR website!Over thanksgiving break, drew decides to fly home from Arcata airport.
The pilot announces that they have a tailwind and thus will make the 300 mile flight to San Fransisco airport in 45 minutes.
Unfortunately, coming home, the pilot announces over the intercom that there is a headwind and they will be taking an hour and a half to get to Arcata Airport.
How fast is the tailwind/headwind and how fast is Drew's airplane?
:
Let s = plane speed in still air
Let w = wind speed
:
Change 45 min to .75 hrs
:
Write a distance equation for each way. (dist = speed * time)
:
.75(s + w) = 300
1.5(s - w) = 300
Simplify both equations, divide the 1st by .75 and the 2nd by 1.5, results
s + w = 400
s - w = 200
-------------Adding eliminates w, find s
2s + 0 = 600
s = 
s = 300 mph is the speed of the plane
:
Find the wind speed
300 + w = 400
w = 400 - 300
w = 100 mph is the speed of the wind
:
:
Check solution in the 2nd equation
1.5(300 - 100) =
1.5(200) = 300
|
Geometry_Word_Problems/522662: I just submitted a question concerning spreading gravel in my driveway. I inadvertently asked how many "square yards" of gravel it would take instead of asking how many "CUBIC yards" it would take!! I am spreading gravel 3 inches deep, 12 feet wide and 900 feet long. I MAY decide to spread it 4 inches deep instead. I need to know how many CUBIC yards of material would be required in either scenario. What formula would I employ? 1 solutions
Answer 346977 by ankor@dixie-net.com(15745) on 2011-10-28 11:27:51 (Show Source):
You can put this solution on YOUR website!I am spreading gravel 3 inches deep, 12 feet wide and 900 feet long. I MAY decide to spread it 4 inches deep instead.
I need to know how many CUBIC yards of material would be required in either scenario.
:
Change 3 in to .25 ft
Find the vol in cu/ft; .25*12*900 = 2700 cu/ft
Change 2700 cu/ft to cu yds: 2700.27 = 100 cu yds for 3" thickness
:
Change 4 in to  ft
Find the vol: (1/3)*12*900 = 3600 cu/ft
Change 3600 cu/ft to cu yds: 3600/27 = 133  cu yds for 4" thickness
|
Travel_Word_Problems/522689: David is traveling to the airport to catch a flight, if he travels at the speed of 30 mph, he is late by 13 minutes. If he travels at the speed of 40 mph, he will arrive 7 minutes earlier than the scheduled departure time of the flight. What is the distance to the airport (in miles)? 1 solutions
Answer 346973 by ankor@dixie-net.com(15745) on 2011-10-28 10:58:20 (Show Source):
You can put this solution on YOUR website!David is traveling to the airport to catch a flight, if he travels at the speed of 30 mph, he is late by 13 minutes.
If he travels at the speed of 40 mph, he will arrive 7 minutes earlier than the scheduled departure time of the flight.
What is the distance to the airport (in miles)?
:
Let d = distance to airport
Let s = speed required to arrive on time
then
 = the ideal time to the airport
:
Write a time equation for each scenario
:
 -  =  ; late
-  +  =  ; early
--------------------------------------- addition, eliminates d/s
 -  + 0 = 
Clear denominators, multiply by 120, results:
4d - 3d = 2(20)
d = 40 mi to the airport
:
:
See if this works; find s
 -  =  ;
mult by 60s, results
2s(40) - 60(40) = 13s
80s - 2400 = 13s
80s - 13s = 240
67s = 2400
s = 
s = 35.82 mph the ideal speed
:
Check solution in the late equation
 -  =
1.3333 - 1.1167 = .2166 hr which is 13 min
|
Travel_Word_Problems/522669: Please can you help me with the workings for this word problem as I am unable to do so: A man is rowing a boat up a river and his hat falls in the water. He doesn't notice and keeps rowing for ten minutes before he realises his hat is gone. He turns his boat and rows after it. He rows and retieves his hat which has floated three kilometres downstream from the where it fell in the water. How fast was the river flowing? 1 solutions
Answer 346968 by ankor@dixie-net.com(15745) on 2011-10-28 10:00:53 (Show Source):
You can put this solution on YOUR website!A man is rowing a boat up a river and his hat falls in the water.
He doesn't notice and keeps rowing for ten minutes before he realises his hat is gone.
He turns his boat and rows after it. He rows and retieves his hat which has floated three kilometres downstream from the where it fell in the water.
How fast was the river flowing?
:
The boat and the hat are moving with the current at the same rate, therefore
if he rowed 10 min away from the hat he would take 10 min to get back to the hat.
A total of 20 min. The hat traveled 3 km in 20 min, 1/3 of an hr, therefore:
3 * 3 = 9 km/hr is the flow rate of the river
|
|