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Miscellaneous_Word_Problems/536954: In ΔABC, the measure of ∠A is 36°. The measure of ∠B is three times the measure of ∠C. Find m∠B & m∠C.
Please help me. I only need this one last problem before I finish my homework! Thanks!
1 solutions

Answer 352669 by ankor@dixie-net.com(15624) About Me  on 2011-11-26 22:03:38 (Show Source):
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In ΔABC, the measure of ∠A is 36°.
The measure of ∠B is three times the measure of ∠C.
Find m∠B & m∠C.
:
A = 36
B = 3C
:
A + B + C = 180
36 + B + C = 180
B + C = 180 - 36
B + C = 144
Replace B with 3C
3C + C = 144
4C = 144
C = 144/4
C = 36 degrees
:
B = 3(36)
B = 108 degrees


Square-cubic-other-roots/536683: x^6-28x^3+27=0
1 solutions

Answer 352661 by ankor@dixie-net.com(15624) About Me  on 2011-11-26 20:55:07 (Show Source):
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x^6 - 28x^3 + 27 = 0
Factors to
(x^3 - 1)(x^3 - 27)
Two solutions
x^3 = 1
find the cube root of both sides
x = 1
and
x^3 = 27
Find the cube root of both sides
x = 3
:
:
You can check both solutions in the original equation


Miscellaneous_Word_Problems/536681: A caterer in quoting the charge for producing a dinner proposes the following terms. For a group of 60 people, he will charge $30 per person. For every extra 10 people, he will lower the price for $1.50 per person for the whole group. What size group does the caterer want to maximize his income?
Thanks!
1 solutions

Answer 352659 by ankor@dixie-net.com(15624) About Me  on 2011-11-26 20:47:55 (Show Source):
You can put this solution on YOUR website!
A caterer in quoting the charge for producing a dinner proposes the following terms.
For a group of 60 people, he will charge $30 per person.
For every extra 10 people, he will lower the price for $1.50 per person for the whole group.
What size group does the caterer want to maximize his income?
:
Let x = no. of groups of 10, that will maximize income
Let x = no. of $1.50 reductions in price
Let R = his income
;
R = (60+10x)(30 - 1.50x)
FOIL
R(x) = 1800 - 90x + 300x - 15x^2
R(x) = -15x^2 + 210x + 1800
Find the axis of symmetry
x = %28-210%29%2F%282%2A-15%29
x = %28-210%29%2F%28-30%29
x = +7 groups of 10, 70 more people which would be 130 total
:
Cost per person then, 30 - 7(1.50) = $19.50
:
Total income: 19.50 * 130 = $2,535


Travel_Word_Problems/536797: If the horsepower p required to drive a speedboat through water is directly proportional to the cube of the speed v of the boat, what change is horsepower would be required to double the speed of the boat?
1 solutions

Answer 352627 by ankor@dixie-net.com(15624) About Me  on 2011-11-26 19:04:11 (Show Source):
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If the horsepower p required to drive a speedboat through water is directly proportional to the cube of the speed v of the boat,
what change is horsepower would be required to double the speed of the boat?
:
P = v^3
"what change is horsepower would be required to double the speed of the boat?"
P = (2v)^3
P = 8v^3
:
Power has to be increased by a factor of 8


Quadratic_Equations/536711: If a bus traveled 10km/h faster, it would take 2 hours less time to make a 315km trip. What is its speed?
Thanks for any help:)
1 solutions

Answer 352619 by ankor@dixie-net.com(15624) About Me  on 2011-11-26 18:43:32 (Show Source):
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If a bus traveled 10km/h faster, it would take 2 hours less time to make a 315km trip.
What is its speed?
:
Let s = the speed of the bus
then
(s+10) = the faster speed
:
Write time equation, time = dist/speed
:
Actual time - faster time = 2 hrs
315%2Fs - 315%2F%28%28s%2B10%29%29 = 2
multiply by s(s+10)
s(s+10)*315%2Fs - s(s+5)*315%2F%28%28s%2B10%29%29 = 2s(s+10)
Cancel the denominators and you have
315(s+10) - 315s = 2s^2 + 20s
315s + 3150 - 315s = 2s^2 + 20s
0 = 2s^2 + 20s - 3150
Simplify, divide by 2
s^2 + 10s - 1575 = 0
Factors to
(s+45)(s-35) = 0
The positive solution
s = 35 mph is the actual bus speed
:
:
Check this by finding the times at each speed
315/35 = 9 hrs
315/45 = 7 hrs


Expressions-with-variables/536737: A farmer keeps some animals on a strict diet. Each animal is to recieve 12 grams of protein and 6.5 grams of carbohydrates. The farmer uses two food mixes with nutrients as shown in the table. How many grams of each mix should be used to provide the correct nutrients for each animal.

Protiens Carbohydrates
Mix A 12% 9%
Mix B 15% 5%
Please for the gentleman or lady that solves my
problem please, give an explanation as to why you did what
you did in each step. Thank you and have a blessed day-Tray Tillmon
1 solutions

Answer 352593 by ankor@dixie-net.com(15624) About Me  on 2011-11-26 15:34:47 (Show Source):
You can put this solution on YOUR website!
A farmer keeps some animals on a strict diet.
Each animal is to receive 12 grams of protein and 6.5 grams of carbohydrates.
The farmer uses two food mixes with nutrients as shown in the table.
How many grams of each mix should be used to provide the correct nutrients for each animal.
:
Proteins | Carbohydrates
Mix A: 12%| 9%
Mix B: 15%| 5%
:
Write an equation for each
Prot eq: .12A + .15B = 12
Carb eq: .09A + .05B = 6.5
:
We can use elimination here, multiply the 2nd equation by -3, add to the 1st eq
.12A + .15B = 12
-.27A - .15B = -19.5
----------------------add eliminates B, find A
-.15A = -7.5
A = %28-7.5%29%2F%28-.15%29
A = 50 grams of Mix A
:
Find B using the 1st equation
.12(50) + .15B = 12
6 + .15B = 12
.15B = 12 - 6
.15B = 6
B = 6%2F.15
B = 40 grams of mix B
:
:
Check these solutions in the 2nd original equation
.09A + .05B = 6.5
.09(50) + .05(40) =
4.5 + 2.0 = 6.5; confirms our solution of A=50, B=40
:
:


Rate-of-work-word-problems/535888: If computer a can process 10 pictures in 180 sec, and working toghether with computer b, processes them in 100 sec, how long does it take for b to process the same amount of pictures
1 solutions

Answer 352035 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 21:48:03 (Show Source):
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If computer a can process 10 pictures in 180 sec, and working together with computer b, processes them in 100 sec,
how long does it take for b to process the same amount of pictures
:
let b = time required by b alone
let the completed job = 1 (10 pics processed)
:
A typical shared work equation
100%2F180 + 100%2Fb = 1
mult by 180b
180b*100%2F180 + 180b*100%2Fb = 180b
Cancel the denominators and you have
100b + 180(100) = 180b
18000 = 180b - 100b
18000 = 80b
b = 18000%2F80
b = 225 sec alone


percentage/535897: I am now taking algebra 2 we are studying percent word problems,,,my teacher asked us to round the answer to a 10th of a percent I dont understand ?for example a check of 150 united airline flights last month idetified that 113 of them arrived on time,what on time percent does that represent ? my answer is 113/150= 75.3% NOW SHE SAYS ROUND TO THE 10TH % HOW DO i DO THAT
1 solutions

Answer 352031 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 21:29:09 (Show Source):
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You have rounded it to the nearest 10th. Seventy-five and 3 tenths percent
:


Money_Word_Problems/535909: The state owes me interest on a claim which is $90,000 and they owe the interest over 3 years, if they give me 4% interest how much do they owe me in total?
1 solutions

Answer 352029 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 21:17:21 (Show Source):
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The state owes me interest on a claim which is $90,000 and they owe the interest over 3 years, if they give me 4% interest how much do they owe me
:
If it is compounded annually,
A = 90000*(1.04)^3
A = $101,237.76


Travel_Word_Problems/535914: If Kyle drove the first 40 miles and I droved the last leg of the drive. Taking the same route home Kyle drove the first leg and I drove the last 50 miles.
Who drove the most and by how much?
I have tried putting this into a trigonometry distance formula as well as an algerbraic formula (40x=50x) then dividing them both by 50 which will become: x=40x/50, I configured it to x=.8x. I am lost on where to go from there if I am even on the correct track. Thank you for your time and help.
1 solutions

Answer 352027 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 21:12:23 (Show Source):
You can put this solution on YOUR website!
If Kyle drove the first 40 miles and I droved the last leg of the drive.
Taking the same route home Kyle drove the first leg and I drove the last 50 miles.
Who drove the most and by how much?
:
Let h = dist of the last leg of the outbound trip (which he drove)
then
(h+40) = total one-way distance
:
"Taking the same route home Kyle drove the first leg and I drove the last 50 miles."
Find the dist Kyle drove (k)
K = (h+40) - 50
k = h - 10
Therefore h drove 10 more miles than k (Kyle)


Systems-of-equations/535686: Write an equation of the line that passes through the point (3,0) and has the slope, m = -2. Thanks for your help :]

1 solutions

Answer 352020 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 19:27:14 (Show Source):
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Write an equation of the line that passes through the point (3,0) and has the slope, m = -2.
:
Use the point/slope formula: y - y1 = m(x - x1)
in this problem
m = -2
x1 = 3
y1 = 0
:
y - 0 = -2(x - 3)
y = -2x + 6; is the equation


Equations/535794: I have an exam in just a little more than an hour. I am going over my review for the exam and there are 2 problems that I have the answers for, because they have given us that but I need to know how to go about solving the probelems. Anyone's help is greatly appreciated!!!
_x+4_ = _x+10___
x-3 x+2
Not sure if this makes any sense... I am not sure how to type this up.. It is fractions. x+4 is over x-3 and then it is = in the middle with x+10 above x+2.
The other one that I am struggling with is this
__5__ + _3__ = 1
3x x
This is the same it is a fraction but instead of it being a fraction at the end it is an equals sign with a 1. Thanks so much!
1 solutions

Answer 352004 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 15:57:03 (Show Source):
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%28%28x%2B4%29%29%2F%28%28x-3%29%29 = %28%28x%2B10%29%29%2F%28%28x%2B2%29%29
Cross multiply
(x+4)(x+2) = (x-3)(x+10)
FOIL
x^2 + 2x + 4x + 8 = x^2 + 10x - 3x - 30
x^2 + 6x + 8 = x^2 + 7x - 30
Combine the x's on the left, combine the numbers on the right
x^2 - x^2 + 6x - 7x = -30 - 8
-x = -38
which is
x = 38
Check this in the original problem
:
5%2F%283x%29 + 3%2Fx = 1
Multiply by 3x
3x*5%2F%283x%29 + 3x*3%2Fx = 3x(1)
Cancel the denominators, and you have:
5 + 3(3) = 3x
14 = 3x
x = 14/3
x = 42%2F3
:
:
Check this in the original, you can use 4.67 to do this on a calc, it should be very close to 1


Linear-systems/535652: I honestly have no idea what toopic this question would fall under... Solve this system of equations using substitution. Put your answer in ordered pair form, (x, y). x + 2y = 7 and 2x + y = 8 I can't figure out how to do it. I've tried to many times, but I can't figure it out. Can you please help me?
1 solutions

Answer 351998 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 15:19:48 (Show Source):
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Solve this system of equations using substitution. Put your answer in ordered pair form, (x, y).
x + 2y = 7
2x + y = 8
we can use the 2nd equation for substitution
2x + y = 8
Subtract 2x from both sides
y = -2x + 8
:
Now we can substitute (-2x+8) for y in the 1st equation
x + 2y = 7
x + 2(-2x+8) = 7
x - 4x + 16 = 7
subtract 16 from both sides
x - 4x = 7 - 16
do the math
-3x = -9
x has to be positive, multiply both sides by -1, this changes the signs
3x = 9
divide both sides by 3
x = 9/3
x = 3
:
We can use the equation y =-2x+8, to find y, replace x with 3
y = -2(3) + 8
y = -6 + 8
y = 2
:
the x,y form (3,2)
:
:
Check our solutions in the 1st equation
x + 2y = 7
replace x and y with our solutions
3 + 2(2) = 7
3 + 4 = 7, confirms our solution
;
Are you understanding this better now, any questions?


Average/535651: I am learning division of fractions, and I have an application problem that I do not understand.
A 5/8 karat diamond was purchased for $1200. What would a similar diamond weighing 1 karat cost?
thank you for your help,
Kristie
1 solutions

Answer 351997 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 15:06:29 (Show Source):
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A 5/8 karat diamond was purchased for $1200.
What would a similar diamond weighing 1 karat cost?
:
Let x = cost of a 1 carat diamond
then
5%2F8x = 1200
multiply both sides by 8
5x = 8(1200)
5x = 9600
Divide both sides by 5
x = 9600%2F5
x = $1920 for a 1 carat


Travel_Word_Problems/535638: If one has already has already driven one mile at 30 mph, how fast must one drive the second mile so that the average speed for the trip equals 60 mph
1 solutions

Answer 351994 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 14:52:43 (Show Source):
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If one has already has already driven one mile at 30 mph, how fast must one drive the second mile so that the average speed for the trip equals 60 mph
:
this is not possible, the time used for the 1st mile, would be the time required to run 2 mi,
:
The equation for this: time = dist/speed, x = speed required to accomplish this
1%2F30 + 1%2Fx = 2%2F60
multiply by 60x, results
2x + 60 = 2x; obviously, not possible


Percentage-and-ratio-word-problems/535592: It takes Mr. Soriano 4 days longer to prepare an order of pies than it takes Mrs. Pascual. Together they baked some pies for 2 days and then Mrs. Pascual left. Mr. Soriano took 7 additional days to complete the order of pies. Working alone, how long would it have taken Mrs. Pascual to prepare the pies?
1 solutions

Answer 351962 by ankor@dixie-net.com(15624) About Me  on 2011-11-22 09:44:55 (Show Source):
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It takes Mr. Soriano 4 days longer to prepare an order of pies than it takes Mrs. Pascual.
Together they baked some pies for 2 days and then Mrs. Pascual left.
Mr. Soriano took 7 additional days to complete the order of pies.
Working alone, how long would it have taken Mrs. Pascual to prepare the pies?
:
Let p = Mrs. time to make the pies alone
then
(p+4) = Mr. time to do it
Let the completed job = 1, (an order of pies)
:
A shared work equation, Mr. worked to total of 9 days
:
9%2F%28%28p%2B4%29%29 + 2%2Fp = 1
multiply by p(p+4)
9p + 2(p+4) = p(p+4)
9p + 2p + 8 = p^2 + 4p
11p + 8 = p^2 + 4p
combine like terms on the right
0 = p^2 + 4p - 11p - 8
A quadratic equation
p^2 - 7p - 8 = 0
Factors to
(p-8)(p+1) = 0
the positive solution is all we want here
p = 8 days for Mrs. working alone


Travel_Word_Problems/535236: A car traveled 462 km in 7 h. for the last 3 h of the trip its average speed was 20 km/h less than twice its average speed for the first 4 h. find the two speeds at which the car traveled. (using uniform motion)
1 solutions

Answer 351895 by ankor@dixie-net.com(15624) About Me  on 2011-11-21 21:01:54 (Show Source):
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A car traveled 462 km in 7 h. for the last 3 h of the trip its average speed was 20 km/h less than twice its average speed for the first 4 h.
find the two speeds at which the car traveled. (using uniform motion)
:
Let s = car speed the 1st 4 hrs
then
(2s-20) = speed the last 3 hrs"
:
Write a distance equation; dist = speed * time
:
4s + 3(2s-20) = 462
4s + 6s - 60 = 462
10s = 462 + 60
10s = 522
s = 522/10
s = 52.2 km/hr the 1st 4 hrs
then
2(52.2) - 20 = 84.4 km/hr the last 3 hrs
:
:
You can check these solutions, find the distance at each speed, should equal 462 km


Travel_Word_Problems/534921: How long does it take to travel 12 miles traveling at 10 miles per hour?
1 solutions

Answer 351795 by ankor@dixie-net.com(15624) About Me  on 2011-11-21 15:42:36 (Show Source):
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How long does it take to travel 12 miles traveling at 10 miles per hour?
time = dist/speed
12%2F10 = 1.2 hrs


test/535043: Kayla and judy start walking the track at the same time.. But it takes Kayla 6 min to walk a track and it takes Judy 8min. How many times will they meet at the starting point?
1 solutions

Answer 351740 by ankor@dixie-net.com(15624) About Me  on 2011-11-21 09:52:21 (Show Source):
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Kayla and judy start walking the track at the same time.. But it takes Kayla 6 min to walk a track and it takes Judy 8min. How many times will they meet at the starting point?
:
This is a Least Common multiple problem: the LCM of 6 and 8 is 24
In find how many times each will walk the track in 24 min


Rate-of-work-word-problems/535024: there were 4 workers that built A WALL IN 5 DAYS AND THERE 10 WORKERS HOW MANY DAYS DID IT TAKE THEME TO BUILT A WALL
1 solutions

Answer 351737 by ankor@dixie-net.com(15624) About Me  on 2011-11-21 09:22:26 (Show Source):
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there were 4 workers that built A WALL IN 5 DAYS
Find how many man-days to complete wall:
4 * 5 = 20 man-days
:
"THERE 10 WORKERS HOW MANY DAYS DID IT TAKE THEM TO BUILd A WALL?
let d = no. of days for 10 guys to do it
10d = 20
d = 2 days for 10 guys to do it
:
:
This is in theory only, usually when you get that many together, at least two of them are goof-offs. If they are city workers, the no. of goof-offs will quadruple.
:
However, your teacher probably is not interested in the social aspect of the situation, have a Blessed Thanksgiving! C


Linear-systems/535025: Please Solve by Elimination
-3x-5y+3z=-2
4x+4y+2z=6
x-2y-3z=-5
Please help me to figure out this problem, I dont even know where to begin.
1 solutions

Answer 351736 by ankor@dixie-net.com(15624) About Me  on 2011-11-21 09:03:15 (Show Source):
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Solve by Elimination
-3x - 5y + 3z =-2
4x + 4y + 2z = 6
x - 2y - 3z =-5
:
Multiply the 3rd equations and add
-3x - 5y + 3z =-2
4x + 4y + 2z = 6
-x + 2y + 3z = 5
---------------------adding eliminates x
0 + y + 8z = 9
y = (9-8z)
:
Multiply the 3rd equation by 3 add to the first equation
-3x - 5y + 3z =-2
3x - 6y - 9z =-15
---------------------adding eliminates x
0 - 11y - 6z = -17
replace y with (9-8z)
-11(9-8z) - 6z = -17
-99 + 88z - 6z = -17
82z = -17 + 99
82z = 82
z = 1
:
find y:
y = (9-8z)
y = 9 - 8(1)
y = 1
:
I'll let you find x, check the solutions in the original equations
(Don't be surprised if x=0)


test/534999: If there 5/8 of girls in a choir plus 12 more boys, how many kids are there?
1 solutions

Answer 351733 by ankor@dixie-net.com(15624) About Me  on 2011-11-21 08:27:26 (Show Source):
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let x = total n. of kids
:
x = 5%2F8x + 12
multiply by 8 to get rid of the denominators
8x = 5x + 96
8x - 5x = 96
3x = 96
x = 32 kids
;
;
Check this:
5%2F8*32 + 12 =
5(4) + 12 = 32


Expressions-with-variables/534977: Substitution Problem: 2x + 3y= 1 and -x + 1/3y= 5
The answer in the book says (-4,3) but i didn't get that when i did it! Please explain.
1 solutions

Answer 351732 by ankor@dixie-net.com(15624) About Me  on 2011-11-21 08:21:03 (Show Source):
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Problem:
2x + 3y = 1
-x + 1/3y= 5
:
Multiply the 2nd equation by -9, then you have
2x + 3y = 1
9x - 3y = -45
---------------- addition eliminates y, find x
11x = -44
x = %28-44%29%2F11
x = -4
:
Find x using the 1st equation
2x + 3y = 1
2(-4) + 3y = 1
-8 + 3y = 1
3y = 1 + 8
3y = 9
y = 3


Miscellaneous_Word_Problems/534302: Find 2 positive real numbers whose product is the maximum given that the sum is twice the first and three times the second is 48
1 solutions

Answer 351672 by ankor@dixie-net.com(15624) About Me  on 2011-11-20 22:12:53 (Show Source):
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Find 2 positive real numbers whose product is the maximum given that the sum is twice the first and three times the second is 48
:
Two numbers, x & y
:
2x + 3y = 48
3y = -2x + 48
y = -2%2F3x + 16
:
x*y
replace y with (-2%2F3x+16)
write an equation
f(x) = x(-2%2F3x+16)
f(x) = (-2%2F3x^2+16x)
find the axis of symmetry, x = -b/(2a)
x = %28-16%29%2F%282%2A%28-2%2F3%29%29
x = %28-16%29%2F%28-4%2F3%29
x = -16 * -3%2F4
x = +12 gives max on the above equation
:
Find y
2(12) + 3y = 48
3y = 48-24
y = 24/3
y = 8
:
The two real numbers for max xy: 12,8


Age_Word_Problems/534499: The age of the father is 3 years more than 3 times the age of his son. After there years the age of the father will be 10 years more than twice the age of the son. Find their present ages?
Solution?
1 solutions

Answer 351597 by ankor@dixie-net.com(15624) About Me  on 2011-11-20 13:48:52 (Show Source):
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The age of the father is 3 years more than 3 times the age of his son.
After three years the age of the father will be 10 years more than twice the age of the son.
Find their present ages?
:
let f = the father's age
let s = the son's age
:
write an equation for each statement;
:
"The age of the father is 3 years more than 3 times the age of his son."
f = 3s + 3
:
"After three years the age of the father will be 10 years more than twice the age of the son."
f + 3 = 2(s+3) + 10
f + 3 = 2s + 6 + 10
f = 2s + 16 - 3
f = 2s + 13
:
from the 1st statement, replace f with (3s+3)
3s + 3 = 2s + 13
3s - 2s = 13 - 3
s = 10 yrs is the son's age
find Dad's age
f = 3(10) + 3
f = 33 yrs is Dad's age
:
:
Check this in the statement:
"After there years the age of the father will be 10 years more than twice the age of the son. "
33 + 3 = 2(10+3) = 10
36 = 26 + 10



Travel_Word_Problems/534356: a runner starts jogging at her house. She jogs 6 miles and then turns around and jogs back to her house. The first part of her job is mostly uphill, so her speed averages 3 miles per hour less than her returning spped. If the total time she spends jogging is 1 3/4 hours, find her speed going and her speed returning
1 solutions

Answer 351490 by ankor@dixie-net.com(15624) About Me  on 2011-11-19 21:18:07 (Show Source):
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a runner starts jogging at her house. She jogs 6 miles and then turns around and jogs back to her house. The first part of her job is mostly uphill, so her speed averages 3 miles per hour less than her returning speed. If the total time she spends jogging is 1 3/4 hours, find her speed going and her speed returning
:
let s = the uphill speed
then
(s+3) = the downhill speed
:
Change time to 1.75 hrs
:
Write a time equation, time = dist/speed
:
Up time + down time = total time
6%2Fs + 6%2F%28%28s%2B3%29%29 = 1.75
multiply by s(s+3) to clear the denominators, results:
6(s+3) + 6s = 1.75s(s+3)
6s + 18 + 6s = 1.75s^2 + 5.25s
Combine like terms
0 = 1.75s + 5.25s - 12s - 18
1.75s - 6.75s - 18 = 0
Use the quadratic formula to find s
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x = s; a=1.75, b=-6.75, c=-18
s+=+%28-%286.67%29+%2B-+sqrt%28-6.75%5E2-4%2A1.75%2A-18+%29%29%2F%282%2A-1.75%29+
You can do the rather tedious math here, you should get a positive solution
s = 5.67 mph, the speed uphill, and obviously, 8.67 mph down


Proportions/534007: A metal smith wishes to create an alloy of 20%,silverand12% gold. She has three raw materials to work with. One is 10%,silverand10% gold the second is 25%,silverand10% gold, and the final metal is 30%,silverand15% gold. In what proportions should she combine the three to produce the desired alloy?
1 solutions

Answer 351476 by ankor@dixie-net.com(15624) About Me  on 2011-11-19 20:24:56 (Show Source):
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A metal smith wishes to create an alloy of 20% silver and 12% gold.
One is 10% silver and 10% gold the second is 25% silver and 10% gold, and the final metal is 30% silver and 15% gold.
In what proportions should he combine the three to produce the desired alloy?
:
Let a = amt of 1st alloy
let b = amt of 2nd
let c = amt of 3rd
:
Let's assign a value to the resulting amt. 120 units is good value
Obviously besides gold and silver, a percentage of filler is in each alloy
The remaining amt when you subtract the silver and gold.
:
Write an equation for each substance
Silver:
.10a + .25b + .30c = .20(120)
.10a + .25b + .30c = 24
Gold:
.10a + .10b + .15c = .12(120)
.10a + .10b + .15c = 14.4
Filler:
.80a + .65b + .55c = .68(120)
.80a + .65b + .55c = 81.6
:
Subtract the 2nd equation from the 1st
.10a + .25b + .30c = 24
.10a + .10b + .15c = 14.4
----------------------------subtraction eliminates a
.15b + .15c = 9.6
:
Multiply the 2nd equation by 8, subtract the 3rd equation
.80a + .80b + 1.2c = 115.2
.80a + .65b + .55c = 81.6
-----------------------------subtraction eliminates a
.15b + .65c = 33.6
.15b + .15c = 9.6
------------------Subtraction eliminates b, find c
.50c = 24
c = 48 units of the 3rd alloy
Find b
.15b + .15(48) = 9.6
.15b = 9.6 - 7.2
.15b = 2.4
b = 2.4/.15.10a + .25b + .30c = 24
b = 16 units of the 2nd alloy
:
Find a
.10a + .25b + .30c = 24
.10a + .25(16) + .30(48) = 24
.10a + 4 + 14.4 = 24
.10a = 24 - 18.4
.10a = 5.6
a = 56 units of the 1st alloy
:
a:b:c
56:16:48
reduce using 8 as a divisor
7:2:6 is the proportion of the 3 alloys
:
I'll let you confirm that the math is correct here


Average/533982: what is the score for missing 40 question out of 68

1 solutions

Answer 351323 by ankor@dixie-net.com(15624) About Me  on 2011-11-19 07:29:04 (Show Source):
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what is the score for missing 40 question out of 68?
:
%28%2868-40%29%29%2F68 * 100 = 41.2 %


Polynomials-and-rational-expressions/534072: Factor completely. Remember to look first for a common factor and to check by multiplying. If a polynomial is prime, state this.
-36a^2 -96ab - 64b^2
1 solutions

Answer 351263 by ankor@dixie-net.com(15624) About Me  on 2011-11-18 21:52:52 (Show Source):
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-36a^2 -96ab - 64b^2
:
Factor out -4,
-4(9a^2 + 24ab + 16b^2)
:
-4 times a perfect square
-4(3a+4b)(3a+4b)


Geometry_Word_Problems/534021: The water depth d, in feet, at which a wave breaks varies directly with the height h, in feet, of the wave. A 6.5 foot wave breaks at a water depth of 8.45 feet.
a. Write a linear model that gives d as a function of h.
b. If a wave breaks at a depth of 5.2 feet, what is its height?

1 solutions

Answer 351262 by ankor@dixie-net.com(15624) About Me  on 2011-11-18 21:47:51 (Show Source):
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The water depth d, in feet, at which a wave breaks varies directly with the height h, in feet, of the wave.
A 6.5 foot wave breaks at a water depth of 8.45 feet.
:
a. Write a linear model that gives d as a function of h.
let k = the constant of variation
d = kh
8.45 = 6.5k
k = 8.45%2F6.5
k = 1.3
d = 1.3h
:
b. If a wave breaks at a depth of 5.2 feet, what is its height?
1.3h = 5.2
h = 5.2%2F1.3
h = 4 ft is the height of the wave, if the depth is 5.2 ft


Travel_Word_Problems/533970: If a car is traveling 40 mi/hour. What is the car's speed in feet per second?
1 solutions

Answer 351254 by ankor@dixie-net.com(15624) About Me  on 2011-11-18 21:26:32 (Show Source):
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If a car is traveling 40 mi/hour. What is the car's speed in feet per second?
:
Multiply by 5280 ft then divide by 3600 to get per second
%28%2840%2A5280%29%29%2F3600 = 58.67 ft/sec