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15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659, >>NextMiscellaneous_Word_Problems/560621: I am trying to simplify this. I don't actually have to solve, just set up in an algebraic expression. Below the problem is the work I did, but it's wrong. I can't figure out why.
1.In a certain triangle the measure of one angle is double the measure of a second angle but is 10 degrees less than the measure of the third angle. [The sum of the measures of three interior angles of a triangle is always 180 degrees.] What is the measure of each angle?
180 = 2x + x + 2x + 10 = 5x + 10 = 180 5x = 170
1 solutions
Answer 363980 by ankor@dixie-net.com(15656)   on 2012-01-22 10:59:07 (Show Source):
You can put this solution on YOUR website!1.In a certain triangle the measure of one angle is double the measure of a second angle but is 10 degrees less than the measure of the third angle.
:
Let x = "second angle"
:
"In a certain triangle the measure of one angle is double the measure of a second angle
2x = "one angle
:
"but is 10 degrees less than the measure of the third angle. "
2x + 10 = "a third angle
:
The sum of the 3 angles = 180; your equation seems right to me:
2x + x + (2x+10) = 180;
5x = 180 - 10
5x = 170
x = 
x = 34 degrees is the 2nd angle
the
2(34) = 68 is the "one angle
and
76 + 10 = 86 is the third angle
:
:
Check: 68 + 34 + 86 = 180
|
Angles/560524: An Angle is 12 degrees less than one half of its supplement. Find the supplement? i need help setting this up. Would it be x + 12 = 1/2(180-x) because i keep getting a decimal on that.
1 solutions
Answer 363979 by ankor@dixie-net.com(15656) on 2012-01-22 10:36:19 (Show Source):
You can put this solution on YOUR website!An Angle is 12 degrees less than one half of its supplement.
:
Your equation: x + 12 = 1/2(180-x) is correct to find the angle x
x + 12 = 90 - .5x
x + .5x = 90 - 12
1.5x = 78
x = 
x = 52 degrees is the angle
:
Find the supplement? 180 - 52 = 128 degrees
:
:
We can confirm this
52 + 12 = .5(128)
64 = 64
|
Travel_Word_Problems/560442: A cyclist leaves Las Vegas riding at the rate of 18 mph. One hour later, a car leaves Las Vegas going 45 mph in the same direction. How long will it take the car to overtake the cyclist?
1 solutions
Answer 363931 by ankor@dixie-net.com(15656) on 2012-01-21 21:56:18 (Show Source):
You can put this solution on YOUR website!A cyclist leaves Las Vegas riding at the rate of 18 mph.
One hour later, a car leaves Las Vegas going 45 mph in the same direction.
How long will it take the car to overtake the cyclist?
:
Let t = travel time of the car
then
(t+1) = travel time of the bike
:
When car catches bike they will have traveled the same distance
A simple distance equation
:
45t = 18(t+1)
|
Linear-equations/560349: I dont understand this word problem please help me
You have been assigned a task of estimating the cost of a tree removal. The cost is $25 per foot, up to 50 feet; above that, the cost increases to $50 per foot. You drop the kids off at the swimming pool and see some of your friends basking in the sun and wish you could stay. You get to the job site only to find that the basket truck that was supposed to meet you broke down on the highway 16 miles away. Explain how you can estimate the height of the tree.
1 solutions
Answer 363928 by ankor@dixie-net.com(15656) on 2012-01-21 21:31:24 (Show Source):
You can put this solution on YOUR website!You have been assigned a task of estimating the cost of a tree removal. The cost is $25 per foot, up to 50 feet; above that, the cost increases to $50 per foot. You drop the kids off at the swimming pool and see some of your friends basking in the sun and wish you could stay. You get to the job site only to find that the basket truck that was supposed to meet you broke down on the highway 16 miles away. Explain how you can estimate the height of the tree.
:
From the information given, we know the sun is shining, in the morning, so the tree should cast a pretty good shadow.
Measure the shadow from the base of the tree.
Measure the shadow that you have from your body.
The relationship of your height to your shadow will be that same as:
the relationship of the tree height to it's shadow
:
For example, say that you are 5 ft high, your shadow is 10 ft: ratio of 1:2
Or we can say, you are half as long as your shadow
Remember similar triangles
Say the tree shadow is 80 ft, it's half as high as it's shadow also, 40 ft
|
�t�e�s�t/560361: Fred cycled from home to his friends house and back again.
The distance from Fred's home to his friends house is 20km
on his way from home to his friends house fred cycled at Xkm per hour
on his way back freds speed had decreased by 2 km per hour
it took fred 4 hours altogether to cycle to his friends house and back.
Write down an equation for x.
THEN SHow that the equation can be written as :
x^2 - 12x + 10 = 0
and solve it.
All i know is that it needs to be factorised somewhere? But im really unsure.
1 solutions
Answer 363916 by ankor@dixie-net.com(15656) on 2012-01-21 20:44:27 (Show Source):
You can put this solution on YOUR website!Fred cycled from home to his friends house and back again.
The distance from Fred's home to his friends house is 20km
on his way from home to his friends house fred cycled at Xkm per hour
on his way back freds speed had decreased by 2 km per hour
it took fred 4 hours altogether to cycle to his friends house and back.
Write down an equation for x.
:
Let x = from home speed
then
(x-2) = return home speed
:
Write a time equation, time = dist/speed
:
from time + return time = 4 hrs
 +  = 4
multiply by x(x-2) to clear the denominators, results:
20(x-2) + 20x = 4x(x-2)
20x - 40 + 20x = 4x^2 - 8x
combine like terms on the right
0 = 4x^2 - 8x - 40x + 40
A quadratic equation
4x^2 - 48x + 40 = 0
simplify, divide by 4 and you have
x^2 - 12x + 10 = 0
and solve it.
Use the quadratic formula: a=1, b=-12; c=10
Only one solution will make sense, check it in the original time equation
|
Travel_Word_Problems/560195: The local train is 25 miles down the track from central station when the express leaves the station. The local train travels at a rate of 50 mi/hr and the express travels at a rate of 80 mi/hr. Let N represent the number of hours since the express train left Central Station.
Question 1.) Write at expression that represents the express train's distance from Central Station in N hours.
Question 2.) When will the express train catch up with the local train?
1 solutions
Answer 363849 by ankor@dixie-net.com(15656) on 2012-01-21 13:09:55 (Show Source):
You can put this solution on YOUR website!The local train is 25 miles down the track from central station when the express leaves the station.
The local train travels at a rate of 50 mi/hr and the express travels at a rate of 80 mi/hr.
Let N represent the number of hours since the express train left Central Station.
:
Question 1.) Write at expression that represents the express train's distance from Central Station in N hours.
80n
:
Question 2.) When will the express train catch up with the local train?
:
When the express catches up with the local, they will have traveled the same distance
write a distance equation: dist = = speed * time
:
80n = 50(n +  )
80n = 50(n+.5)
80n = 50n + 25
80n - 50n = 25
30n = 25
n = 
n =  hr or 50 minutes to catch up with the local
:
:
Confirm this by finding the actual distances, they should be the same:
Local took half hr longer; 8/6 hrs
*80 = 66.67 mi
 *50 = 66,67 mi
|
Human-and-algebraic-language/559996: a motorboat has a constant speed of 14 miles per hour relative to the water going upstream for 33 miles and then returning. the total trip time was 7 hours. use this information to find the speed of the current.
1 solutions
Answer 363769 by ankor@dixie-net.com(15656) on 2012-01-20 21:39:23 (Show Source):
You can put this solution on YOUR website!a motorboat has a constant speed of 14 miles per hour relative to the water going upstream for 33 miles and then returning.
the total trip time was 7 hours. use this information to find the speed of the current.
:
Let c = the rate of the current
then
(14-c) = effective speed upstream (in relation to the land)
and
(14+c) = effective speed downstream
:
Write a time equation; time = dist/speed
:
Time upstr + time downstr = 7 hrs
 +  = 7
;
Multiply by (14-c)(14+c), results:
33(14+c) + 33(14-c) = 7(14-c)(14+c)
:
462 + 33c + 462 - 33c = 7(196-c^2)
:
924 = 1372 - 7c^2
:
7c^2 = 1372 - 924
:
7c^2 = 448
:
c^2 = 
c^2 = 64
c = 
c = 8 mph is the speed of the current
:
:
See if this checks out. Find the actual time of each trip.
33/(14-8) = 5.5 hrs
33/(14+8) = 1.5 hrs
------------------
total time: 7.0 hrs
|
Average/560178: Say I have an 87.5 the first quarter and a 76.3 the second quarter and I got a 68 on my final exam which is worth 1/9th of my final grade, what would my final grade be?
1 solutions
Answer 363757 by ankor@dixie-net.com(15656) on 2012-01-20 20:31:10 (Show Source):
You can put this solution on YOUR website!Say I have an 87.5 the first quarter and a 76.3 the second quarter and I got a 68 on my final exam which is worth 1/9th of my final grade, what would my final grade be?
:
 =  =  = 80.4
|
Quadratic_Equations/560125: During the first part of a trip, a canoeist travels 34 miles at a certain speed. The canoeist travels 9 miles on the second part of the trip at a speed 5mph slower. The total time for the trip is 5hrs. What was the speed on each part of the trip? Type an integer or decimal and round to the nearest hundredth.
1 solutions
Answer 363717 by ankor@dixie-net.com(15656) on 2012-01-20 18:16:01 (Show Source):
You can put this solution on YOUR website!During the first part of a trip, a canoeist travels 34 miles at a certain speed.
The canoeist travels 9 miles on the second part of the trip at a speed 5mph slower.
The total time for the trip is 5hrs. What was the speed on each part of the trip?
:
Let s = the speed on the 1st 34 mi
then
(s-5) = speed on the last 9 mi
:
Write a time equation, time = dist/speed
:
fast time + slow time = 5 hrs
 +  = 5
multiply by s(s-5), results:
34(s-5) + 9s = 5s(s-5)
34s - 170 + 9s = 5s^2 - 25s
43s - 170 = 5s^2 - 25s
0 = 5s^2 - 25s - 43s + 170
A quadratic equation\
5s^2 - 68s + 170 = 0
use the quadratic formula to find s:
In this problem x=s; a=5; b=-68; c=170
:
:
I'll let you do the rest of the math here
you will get two positive solutions, but only one will make sense
Check it in the original time equation
|
Money_Word_Problems/560131: I have story problems I have to get an equation for and solve. I try to draw out tables to help me figure out the equations but I have a rough time finding the right spot to put everything in. Can you help me?
Here is the problem:
A certain sum of money is invested at 6.35%, and $4000 more than that amount is invested at 7.28%. If the annual interest from the two investments is $972.70, how much was invested at 6.35%?
My table I made using the formula I=P*R*T
I = P * R * T
INVEST 1 635X X 635 1
INVEST 2 728(4000-X) 4000-X 1
TOTAL 972.70 4000
Can you please explain what I did wrong and how to do it right and show me what the equation is?
Thanks!! :)
1 solutions
Answer 363703 by ankor@dixie-net.com(15656) on 2012-01-20 17:09:02 (Show Source):
You can put this solution on YOUR website!A certain sum of money is invested at 6.35%, and $4000 more than that amount is invested at 7.28%.
If the annual interest from the two investments is $972.70, how much was invested at 6.35%?
:
Let's do it this way
Let x = amt invested at 6.35%
then it says,"$4000 more than that amount, is invested at 7.28%." therefore
(x+4000) = amt invested at 7.28%
;
.0635x + .0728(x+4000) = 972.70; this is the equation you want
.0635x + .0728x + 291.20 = 972.70
.0635x + .0728x = 972.70 - 291.20
.1363x = 681.50
x = 
x = $5000 invested at 6.35%
;
:
Check the solution by finding the amt invested on each one
.0635*5000 = 317.50
.0728*9000 = 655.20
===================
total int: = 972.70
|
Geometry_Word_Problems/560080: A circular pool has a radius of 15 feet. It needs fencing that is 5 feet away at all points. What is the circumference of the fencing that will be need?
1 solutions
Answer 363696 by ankor@dixie-net.com(15656) on 2012-01-20 16:42:57 (Show Source):
You can put this solution on YOUR website!A circular pool has a radius of 15 feet.
It needs fencing that is 5 feet away at all points.
What is the circumference of the fencing that will be need?
:
This will increase the radius by 5ft and the diameter by 10 ft
C = 
C = 78.54 ft
|
logarithm/560081: The half-life of 234U, uranium-234, is 2.52 multiplied by 105 yr. If 97.9% of the uranium in the original sample is present, what length of time (to the nearest thousand years) has elapsed?
1 solutions
Answer 363680 by ankor@dixie-net.com(15656) on 2012-01-20 15:45:33 (Show Source):
You can put this solution on YOUR website!The half-life of 234U, uranium-234, is 2.52 multiplied by 105 yr.
If 97.9% of the uranium in the original sample is present, what length of time (to the nearest thousand years) has elapsed?
:
Assume you mean the half-life uranium 234 is 2.52(10^5) yrs
:
The radioactive decay formula: A = Ao*2^(-t/h), where
A = resulting amt after t yrs
Ao = initial amt, t=0
h = half-life of substance
t = time
:
Assuming initial amt = 1
2^(-t/2.52(10^5) = .979
we will use nat logs
 *ln(2) = ln(.979)
;
= 
;
= -.03062
:
t = 
:
t = 7,716 ~ 8,000 yrs
|
Geometry_Word_Problems/559882: Two runners are to race one lap on a circular track.The radius to the inside lane is 40m. the radius to the outside lane is 41m. How much of a head start should the outside runner be given.
1 solutions
Answer 363672 by ankor@dixie-net.com(15656) on 2012-01-20 15:18:56 (Show Source):
You can put this solution on YOUR website!Two runners are to race one lap on a circular track.The radius to the inside lane is 40m. the radius to the outside lane is 41m.
How much of a head start should the outside runner be given.
:
Find the circumference of each
:
 = 257.6
 = 251.3
-------------------
difference of: 6.3 head start
|
Angles/559791: two angels are complementary. The sum measures of the first angel and half of the second angel is 64 degrees. find the measurments of angels.
1 solutions
Answer 363666 by ankor@dixie-net.com(15656) on 2012-01-20 14:59:12 (Show Source):
You can put this solution on YOUR website!two angels are complementary.
A + B = 90
The sum measures of the first angel and half of the second angel is 64 degrees.
A + .5B = 64
:
Subtract the 2nd eq from the 1st eq:
A + B = 90
A +.5B =64
------------subtraction eliminates A, find B
.5B = 26
B = 2*26
B = 52 degrees
then
A = 90 - 52
A = 38 degrees
:
:
Check this
38 + .5(52) = 64
|
Complex_Numbers/560058: Corrosion in the metal surface of an airplane can be difficult to detect visually. One test used to locate it involves passing an alternating current through a small area on the plane’s surface. If the current varies from one region to another, it may indicate that corrosion is occurring. The impedance Z (or opposition to the flow of electricity) of the metal is related to the voltage V and current I by the equation, where Z, V, and I are complex numbers.
Calculate Z for the given values of V and I.
V=10+20i I=3+7i
1 solutions
Answer 363648 by ankor@dixie-net.com(15656) on 2012-01-20 13:32:41 (Show Source):
You can put this solution on YOUR website! The impedance Z (or opposition to the flow of electricity) of the metal is related to the voltage V and current I by the equation, where Z, V, and I are complex numbers.
Calculate Z for the given values of V and I.
V=10+20i I=3+7i
:
Z = V/I
:
Z = 
:
multiply by the conjugate of the denominator over itself
Z = *  =  =  =  = 
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Travel_Word_Problems/560048: The distance from the Earth to the Moon is approximately 240,000 miles. If a rocket travels at a speed of 7.50 km/sec, it will take __________ days to travel between the Earth and Moon.
1 solutions
Answer 363646 by ankor@dixie-net.com(15656) on 2012-01-20 13:06:22 (Show Source):
You can put this solution on YOUR website!The distance from the Earth to the Moon is approximately 240,000 miles.
If a rocket travels at a speed of 7.50 km/sec, it will take __________ days to travel between the Earth and Moon.
:
Change 240,000 mi to km: 1.609 * 240000 = 386,160 km
:
Find the no. of sec in one day: 3600 * 24 = 86,400 sec in one day
:
 = .596 days (14.3 hrs)
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Travel_Word_Problems/560030: An alien rocketship is traveling at a speed of 0.029 miles per second. At this speed, how many feet will it travel in 1 hour? Round to the nearest thousandth.
1 solutions
Answer 363645 by ankor@dixie-net.com(15656) on 2012-01-20 12:56:14 (Show Source):
You can put this solution on YOUR website!An alien rocketship is traveling at a speed of 0.029 miles per second.
At this speed, how many feet will it travel in 1 hour?
Round to the nearest thousandth.
:
There are 3600 sec in 1 hr, 5280 ft in 1 mile, therefore:
:
3600 * .029 * 5280 = 551,232 ft in 1 hr
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Travel_Word_Problems/559895: A slow goods train starts from each city at 12.25 pm. One train travels at a constant speed of 60 km per hour and the other at 40 kilometres an hour. At what time (after passing one another) will they be 40 kilometres apart?
1 solutions
Answer 363643 by ankor@dixie-net.com(15656) on 2012-01-20 12:51:05 (Show Source):
You can put this solution on YOUR website!A slow goods train starts from each city at 12.25 pm.
One train travels at a constant speed of 60 km per hour and the other at 40 kilometres an hour.
At what time (after passing one another) will they be 40 kilometres apart?
:
I think we have to know how far apart the cities are.
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Radicals/559939: This radical has me stumped. I have gotten two different answers.
3-2radicand symbol 3 + 5 radicand symbol 3. These are my answers.1)3*radicand symbol 3+3 2)3 + 3 radicand symbol 3. Please show steps.
1 solutions
Answer 363637 by ankor@dixie-net.com(15656) on 2012-01-20 12:46:45 (Show Source):
You can put this solution on YOUR website!3-2radicand symbol 3 + 5 radicand symbol 3. These are my answers.1)3*radicand symbol 3+3 2)3 + 3 radicand symbol 3.
:
 are like terms, -2 + 5 = +3,therefore
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percentage/559956: Attendance at a cinema decreased by 12 %. How many percent should the price of
the movie ticket be raised so that the revenue would only decrease by 5 %?
1 solutions
Answer 363601 by ankor@dixie-net.com(15656) on 2012-01-20 08:43:28 (Show Source):
You can put this solution on YOUR website!Attendance at a cinema decreased by 12 %.
How many percent should the price of the movie ticket be raised so that the revenue would only decrease by 5 %?
:
Assume there are 100 at $1 each in attendance originally
A 12% decrease means only $88 in revenue
A 5% decrease mean $95 in revenue
95 - 88 = 7% increase in price to have 95% revenue
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logarithm/559328: A constant tone is being applied to a speaker. The voltage across the speaker is 5 volts. The voltage across the speaker is increased to 15 volts in order to increase the sound level. What is the decibel gain, rounded to the nearest decibel?
1 solutions
Answer 363545 by ankor@dixie-net.com(15656) on 2012-01-19 21:46:13 (Show Source):
You can put this solution on YOUR website!A constant tone is being applied to a speaker. The voltage across the speaker is 5 volts. The voltage across the speaker is increased to 15 volts in order to increase the sound level. What is the decibel gain, rounded to the nearest decibel?
:
db = 20*log 
db = 20*log(3)
db = 20*.477
db = 9.54 ~ 10 db gain
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Length-and-distance/559312: The distance around (perimeter) a certain rectangular playing field is 310 meters. The length is 65 meters more than the width. What are the dimensions (length and width) of the field? I need help solving this problem please....step by step. Thank you.
1 solutions
Answer 363538 by ankor@dixie-net.com(15656) on 2012-01-19 21:24:03 (Show Source):
You can put this solution on YOUR website!This is not hard, write an equation for each statement
The distance around (perimeter) a certain rectangular playing field is 310 meters.
2L + 2W = 310
We can simplify this, divide by 2
L + W = 155
:
The length is 65 meters more than the width.
L = W + 65
now
Using the 1st simplified equation, we can replace L with (W+65), find W
(W+65) + W = 155
2W = 155 - 65; subtracted 65 from both sides
2W = 90
W = 90/2; divided both sides by 2
W = 45 meters is the width
then
L = W + 65
L = 45 + 65
L = 110 meters is the length
:
:
Confirm this by finding the perimeter using these dimensions
2(110) + 2(45) =
220 + 90 = 310
:
Was this step-by-step enough?
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test/559386: two telephone poles, 22 feet and 29 feet high respectively, are 70 feet apart. How long is the wire from the top of one pole to the top of the second pole. Assume the wire is tight and that the wire is attached at the edge of each pole.
1 solutions
Answer 363535 by ankor@dixie-net.com(15656) on 2012-01-19 21:13:50 (Show Source):
You can put this solution on YOUR website!two telephone poles, 22 feet and 29 feet high respectively, are 70 feet apart.
How long is the wire from the top of one pole to the top of the second pole.
Assume the wire is tight and that the wire is attached at the edge of each pole.
:
Draw this out and it will be apparent that a right triangle is formed
one leg is the difference in the height of the poles 7'
the other leg is 70 ft
the distance between the tops of the poles is the hypotenuse
:
h = 
h = 70.35 ft
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Travel_Word_Problems/559581: At 1:00 p.m. a car leaves St. Louis for Chicago, traveling at a constant speed of 65 miles per hour. At 2:00 p.m. a truck leaves Chicago for St. Louis, traveling at a constant speed of 55 miles per hour. If it is a 305-mile drive between St. Louis and Chicago, at what time will the car and truck pass each other?
I'm having trouble with this because of the different times that the vehicles left. Thanks!
1 solutions
Answer 363533 by ankor@dixie-net.com(15656) on 2012-01-19 21:02:57 (Show Source):
You can put this solution on YOUR website!At 1:00 p.m. a car leaves St. Louis for Chicago, traveling at a constant speed of 65 miles per hour.
At 2:00 p.m. a truck leaves Chicago for St. Louis, traveling at a constant speed of 55 miles per hour.
If it is a 305-mile drive between St. Louis and Chicago, at what time will the car and truck pass each other?
:
Let t = travel time of the truck that leaves at 2 PM
then
(t+1) = travel time of the car which left at 1 PM
:
When the two meet, the distance each traveled will add up to 305 mi
:
Write a distance equation, dist = speed * time
car dist + truck dist = 305 mile
65(t+1) + 55t = 305
65t + 65 + 55t = 305
65t + 55t = 305 - 65
120t = 240
t = 240/120
t = 2 hrs, is the travel time of the truck which left at 2 PM
therefore
2 PM + 2 hrs = 4 PM they will meet
:
:
We can prove this
Car travel time = 3 hrs
3*65 = 195
2*55 = 110
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total: 305
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Quadratic_Equations/559574: Is this even considered to be a quadratic equation?? I do not understand by what they mean to solve this.. Do they mean distribute and then solve? But how? Please help! I am very frustrated! Thanks!
(x-3)(5x+2)= -13(x-3)
1 solutions
Answer 363530 by ankor@dixie-net.com(15656) on 2012-01-19 20:46:20 (Show Source):
You can put this solution on YOUR website!(x-3)(5x+2) = -13(x-3)
Hey! we don't have to do a lot here, divide both sides by (x-3), results
5x + 2 = -13
5x = -13 -2
5x = -15
x = 
x = -3
;
:
Check it:
(-3-3)(5(-3)+2) = -13(-3-3)
-6 * -13 = -13 * -6
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Graphs/559616: What is the x and y intercepts of this equation 9x-6=-72
1 solutions
Answer 363521 by ankor@dixie-net.com(15656) on 2012-01-19 20:10:31 (Show Source):
You can put this solution on YOUR website!What is the x and y intercepts of this equation 9x-6=-72
But where is y in this equation?
assume you mean
9x - 6y = -72
Put equation into the slope/intercept form y = mx + b
-6y = -9x - 72
Multiply by -1
6y = 9x + 72
Divide by 6
y =  x + 
y = 1.5x + 12
:
The x intercept occurs when y = 0
1.5x + 12 = 0
1.5x = -12
x = 
x = -8 is the x intercept
:
The y intercept occurs when x = 0
y = 1.5(0) + 12
y = 12 is y intercept
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Numbers_Word_Problems/559404: Amber is thinking of a number. Twice the number increased by 1 is less than 3 times
the number. What is the number?
1 solutions
Answer 363516 by ankor@dixie-net.com(15656) on 2012-01-19 19:58:34 (Show Source):
You can put this solution on YOUR website!Twice the number increased by 1 is less than 3 times the number.
2n + 1 < 3n
2n - 3n < -1
-n < -1
Multiply both sides by -1, this reverses the inequality sign
n > 1
:
The number is greater than 1
;
Check it out with n=2, in the original equation:
2(2) + 1 < 3(2)
5 < 6, which is true
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