New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'ankor@dixie-net.com'
ankor@dixie-net.com answered: 15608 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629, >>NextAverage/569356: Ok, my son is has a problem in Algebra, he is in the 9th grade. I can get the answer for him but he need to write it in algebra terms. I never took algebra in school, so if I can tell you the question. can you please tell me how to write it in algebra terms.
Mike just got a phone bill for $27.60. he is charge $.07 per minute for local calls and $.20 for long distance calls. he talked for a total of 320 minutes. How many long distance minutes did he use?
It sounds just like a typical story problem and easy to solve but feel bad that I can't put it in Algebra form
Thanks so much,
Until Next time,
Sue 1 solutions
Answer 367314 by ankor@dixie-net.com(15623) on 2012-02-07 21:36:30 (Show Source):
You can put this solution on YOUR website!Mike just got a phone bill for $27.60. he is charged $.07 per minute for local calls and $.20 for long distance calls. he talked for a total of 320 minutes.
How many long distance minutes did he use?
:
We need two equation to solve two unknowns, we are going to use substitution to solve this
Let x = no. of local minutes
Let y = no. of L.D minutes
;
x + y = 320; (total minutes equation
x = (320-y); this form for substitution
:
.07x + .20y = 27.60; (total cost equation)
Replace x with (320-y)
.07(320-y) + .20y = 27.60
22.4 - .07y + .20y = 27.60; (multiplied what's inside the brackets)
-.07y +.20y = 27.60 - 22.4
.13y = 5.20
y = 
y = 40 minutes of L.D calls which is answer they want
:
then in order to check our solution
using x + y = 320
x + 40 = 320
x = 320 - 40
x = 280 minutes of Local calls
:
:
Confirm this in the equation; .07x + .20y = 27.60
.07(280) + .20(40) =
19.60 + 8.00 = 27.60;
|
Travel_Word_Problems/569139: Jose left the airport and traveled toward the mountains. Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him. After 1.2 hours, Kayla finally caught up. Find Jose's average speed. 1 solutions
Answer 367307 by ankor@dixie-net.com(15623) on 2012-02-07 21:13:34 (Show Source):
You can put this solution on YOUR website! Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him.
After 1.2 hours, Kayla finally caught up. Find Jose's average speed.
:
From the information given:
1.2 hrs is K's travel time (sorry about that)
and
2.1 + 1.2 = 3.3 hrs is J's travel time
:
When K catches, J, they will have traveled the same distance.
Let j = J's speed
then
(j+35) = K's speed
:
Write a distance equation: Dist = speed * time
:
3.3j = 1.2(j+35)
3.3j = 1.2j + 42
3.3j - 1.2j = 42
2.1j = 42
j = 42/2.1
j = 20 mph is J's average speed
:
:
Check this by finding the distance each traveled, they should be equal
3.3(20) = 66 mi
1.2(55) = 66 mi
|
test/567517: 2• radicand of 48y^5 power - 3y•radicand of 12y^3 power 1 solutions
Answer 366721 by ankor@dixie-net.com(15623) on 2012-02-04 21:40:38 (Show Source):
You can put this solution on YOUR website!2• radicand of 48y^5 power - 3y•radicand of 12y^3 power
Assume the problem is:
;

Factor inside the radicals to reveal some perfect squares

Extract the square root of those squares

which are now like terms
 =
|
Linear-systems/567653: I need help with this (solving systems).
The Science Club needs to rent a bus for a field tripe. M.S. Buses charges a $40 rental fee, plus $2 per mile. C.B. Buses charges a $20 rental fee, plus $3 per mile. For what number of miles will the total be the same? What will the charge be?
How would I solve this problem? Thank you for the help. 1 solutions
Answer 366712 by ankor@dixie-net.com(15623) on 2012-02-04 21:16:47 (Show Source):
You can put this solution on YOUR website!The Science Club needs to rent a bus for a field tripe. M.S. Buses charges a $40 rental fee, plus $2 per mile. C.B. Buses charges a $20 rental fee, plus $3 per mile. For what number of miles will the total be the same? What will the charge be?
How would I solve this problem?
Write a cost equation for each statement and make them equal to each other
:
Let m = no, of miles for this to be true
:
" M.S. Buses charges a $40 rental fee, plus $2 per mile.
C = 2m + 40
:
"C.B. Buses charges a $20 rental fee, plus $3 per mile."
C = 3m + 20
:
3m + 20 = 2m + 40
now just solve for m, then find the cost by replacing m with that value in both equations.
If you did it right, they should be equal.
;
Let me know if you have difficulty with this.
|
�t�e�s�t/567792: A student did a word-processing job for $42. It took him 8 hours longer than he expected, and therefore he earned $4 per hour less than he anticipated. How long did he expect that it would take to do the job? 1 solutions
Answer 366710 by ankor@dixie-net.com(15623) on 2012-02-04 21:07:49 (Show Source):
You can put this solution on YOUR website!A student did a word-processing job for $42.
It took him 8 hours longer than he expected, and therefore he earned $4 per hour less than he anticipated.
How long did he expect that it would take to do the job?
:
Let t = time he expected to do the job
then
 = his expected hourly pay
:
Let (t+8) = his actual time to do the job
then
 = his actual hourly pay
:
The equation
expect hrly pay - actual hrly pay = $4
 -  = 4
multiply by t(t+8), resulting in:
42(t+8) - 42t = 4t(t+8)
:
42t + 336 - 42t = 4t^2 + 32t
Arrange as a quadratic equation
4t^2 + 32t - 336 = 0
Simplify, divide by 4
t^2 + 8t - 84 = 0
Factors to
(t+14)(t-6) = 0
the positive solution
t = 6 hrs was his anticipated time for the job
:
:
Check this by finding the actual hourly pay
42/6 = $7 an hr
42/14= $3 an hr
-----------------
differ: $4
|
Linear_Equations_And_Systems_Word_Problems/567631: In a chemistry class, 4 liters of a 4% silve iodide solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed? 1 solutions
Answer 366703 by ankor@dixie-net.com(15623) on 2012-02-04 20:47:05 (Show Source):
You can put this solution on YOUR website!In a chemistry class, 4 liters of a 4% silver iodide solution must be mixed with a 10% solution to get a 6% solution.
How many liters of the 10% solution are needed?
:
Let x = amt of 10% solution required
:
.04(4) + .10x = .06(x+4)
.16 + .10x = .06x + .24
.10x - .06x = .24 - .16
.04x = .08
x = .08/.04
x = 2 liters of 10% solution needed
;
:
Check this
.04(4) + .10(2) = .06(2 + 4)
.16 + .20 = .06(6)
.36 = .36; confirms our solution
|
Money_Word_Problems/567632: how to find the balance when you have $20,000 deposit earning 3.5% compound quarterly, after 10 years
can you give me the steps please i understand how to do principal earning but i don't get deposit earning 1 solutions
Answer 366661 by ankor@dixie-net.com(15623) on 2012-02-04 12:21:29 (Show Source):
You can put this solution on YOUR website!how to find the balance when you have $20,000 deposit earning 3.5% compound quarterly, after 10 years
:
The compound interest formula: 
Where:
A = amt after t yrs
P = initial amt (principal)
r = interest rate in decimal form
n = no. of compounding periods per year
t = no. of yrs
:
In this problem

find the value of 1.00875^40 on a calc
A = 20000*1.41691
A = $28,338.18 after 10 yrs
|
Travel_Word_Problems/567590: train 1 is travelling from a - b at a speed of 105 miles per hour. time duration = 30 minutes
Train 2 is travelling from b - a at 85 miles per second . What is the current distance of both trains? 1 solutions
Answer 366659 by ankor@dixie-net.com(15623) on 2012-02-04 11:58:18 (Show Source):
You can put this solution on YOUR website!train 1 is traveling from a - b at a speed of 105 miles per hour.
time duration = 30 minutes
Train 2 is traveling from b - a at 85 miles per second .
What is the current distance of both trains?
:
Change 30 min to .5 hrs
:
Train 1: .5 * 105 = 52.5 mi from a
Train 2: .5 * 85 = 42.5 mi from b
|
Travel_Word_Problems/567434: A is moving 17 feet per second slower than B. How long will it take B to catch A if B starts out 672 feet behind A? How far will A have traveled before B catches up?
thanks
1 solutions
Answer 366600 by ankor@dixie-net.com(15623) on 2012-02-03 21:57:58 (Show Source):
You can put this solution on YOUR website!A is moving 17 feet per second slower than B.
How long will it take B to catch A if B starts out 672 feet behind A?
:
B's relative speed to A is 17 ft/sec, therefore
 = 39.53 seconds for B to catch A
:
How far will A have traveled before B catches up?
I don't think you can know this with the information given, all we can say is
A will travel 672 ft less than B travels
|
Points-lines-and-rays/567286: the measure of two supplementary angles are in the ratio 5:7. what is the measure of the larger angle?
1 solutions
Answer 366589 by ankor@dixie-net.com(15623) on 2012-02-03 21:09:05 (Show Source):
You can put this solution on YOUR website!the measure of two supplementary angles are in the ratio 5:7.
what is the measure of the larger angle?
:
Let x = the multiplier
then
one angle = 5x
other angle = 7x
Supplementary, therefore
5x + 7x = 180
12x = 180
x = 180/12
x = 15 is the multiplier
:
therefore, the angle are:
15*5 = 75 degrees
15*7 = 105 degrees is the larger angle
|
Quadratic_Equations/567351: A box with an open top is constructed from a rectangular piece of cardboard which is initially 30 inches long and 23 inches wide. The box will be formed by removing squares of length x inches from each corner and then folding up the sides (as shown below). Express the volume (V) of the box as a function of x.
I've been trying to figure out this problem for a while, any help is greatly appreciated!!! Thanks! 1 solutions
Answer 366578 by ankor@dixie-net.com(15623) on 2012-02-03 20:42:20 (Show Source):
You can put this solution on YOUR website!A box with an open top is constructed from a rectangular piece of cardboard which is initially 30 inches long and 23 inches wide.
The box will be formed by removing squares of length x inches from each corner and then folding up the sides (as shown below).
Express the volume (V) of the box as a function of x.
:
From the information, the box dimensions will be:
(30-2x) by (23-2x) by x (Height)
:
therefore the volume:
V(x) = x*(30-2x)*(23-2x)
FOIL
V(x) = x(690 - 60x - 46x + 4x^2)
;
which is usually written
V(x) = x(4x^2 - 106x + 690)
;
multiply by the height
V(x) = 4x^3 - 106x^2 + 690x
|
Travel_Word_Problems/567226: How far can Phelps swim upstream at 8 km/hr and still return downstream at 12 km/hr in a total time of 4 hours? 1 solutions
Answer 366576 by ankor@dixie-net.com(15623) on 2012-02-03 20:27:26 (Show Source):
You can put this solution on YOUR website!How far can Phelps swim upstream at 8 km/hr and still return downstream at 12 km/hr in a total time of 4 hours?
:
Let d = one-way distance
write a time equation, time = dist/speed
:
time up = time down = 4 hrs
 +  = 4
multiply by 24 to clear the denominators, resutls
3d + 2d = 24(4)
5d = 96
d = 
d = 19.2 km,
:
:
Check this by finding the actual time each way
19.2/8 = 2.4 hrs
19.2/12= 1.6
--------------
total; 4 hrs
|
Travel_Word_Problems/567238: Two skiers are 105 kilometers apart and head towards each other. They meet in 3.5 hours. If the second skier is 8 kilometers per hour faster the the other, find the speed of each skier? 1 solutions
Answer 366574 by ankor@dixie-net.com(15623) on 2012-02-03 20:20:09 (Show Source):
You can put this solution on YOUR website!Two skiers are 105 kilometers apart and head towards each other.
They meet in 3.5 hours.
If the second skier is 8 kilometers per hour faster the the other, find the speed of each skier?
:
When they do meet, their travel distances total 105 km
:
Let s = the speed of one skier
then
(s+8) = speed of the other skier
;
Write a distance equation, dist = speed * time
3.5s + 3.5(s+8) = 105
3.5s + 3.5s + 28 = 105
7s = 105 - 28
7s = 77
s = 77/7
s = 11 km/hr is the speed of one skier
and
11 + 8 = 19 km/hr speed of the other skier
;
:
Check this by finding the distance each traveled
3.5*11 = 38.5 km
3.5*19 = 66.5
---------------
total d: 105
|
Travel_Word_Problems/567323: Distance Traveled At noon a bicyclist is 50 miles from home, riding toward home at 10 miles per hour.(a) Make a table that shows the bicyclist’s distance D from home after 1, 2, 3, 4, and 5 hours. (b) Write a formula that calculates the distance D from home after x hours.(c) Use your formula to determine D when hours. Does your answer agree with the value
shown in your table? (d) For what times was the bicyclist at least 20 miles
from home? Assume that 0 # x #
1 solutions
Answer 366568 by ankor@dixie-net.com(15623) on 2012-02-03 20:07:48 (Show Source):
You can put this solution on YOUR website!At noon a bicyclist is 50 miles from home, riding toward home at 10 miles per hour.
:
It's easier if you write the equation first:
D = 50 - 10x
:
(a) Make a table that shows the bicyclist’s distance D from home after 1, 2, 3, 4, and 5 hours.
Use the equation to make the table
x | d
-------
1 | 40
2 | 30
3 | 20
4 | 10
5 | 0, he's home
;
(b) Write a formula that calculates the distance D from home after x hours.
we did
;
(c) Use your formula to determine D when ?? hours. Does your answer agree with the value shown in your table?
:
(d) For what times was the bicyclist at least 20 miles
from home?
x =< 3 hrs
|
Linear_Equations_And_Systems_Word_Problems/567231: A pot contains 2 L of brine at a concentration of 100 g/L. How much of the water should be boiled off to increase the concentration to 200 g/L? 1 solutions
Answer 366565 by ankor@dixie-net.com(15623) on 2012-02-03 19:55:44 (Show Source):
You can put this solution on YOUR website!A pot contains 2 L of brine at a concentration of 100 g/L.
How much of the water should be boiled off to increase the concentration to 200 g/L?
:
Convert 100g/L to 10% brine, which is .10
.10(2) = .20(2-w)
.2 = .4 - .2w
.2w = .4 - .2
.2w = .2
w = 1 liter should be boiled off
:
:
Check this
.10(2) = .20(2 - 1)
.2 = .2(1)
|
Radicals/567489: square root of y+8 minus square root of y-6 equals -3, Help!
I have tried isolating one of the radicals and raising both sides to the power of the index, then isolating the radical again, but webassign isnt taking my answer! I come up with 6 25/36. 1 solutions
Answer 366560 by ankor@dixie-net.com(15623) on 2012-02-03 19:35:50 (Show Source):
You can put this solution on YOUR website!square root of y+8 minus square root of y-6 equals -3,
:
 = -3
:
 - 3
square both sides
y + 8 = [  - 3]^2
FOIL the right side
y + 8 = 
:
y + 8 = y + 3 - 
:
y + 8 = y + 3 - 
y - y + 8 - 3 = 
5 = 
square both side again
25 = 36(y-6)
25 = 36y - 216
25 + 216 = 36y
241 = 36y
y = 
y = 6.7 which about what you got, but the trouble is if we substitute this in the original problem we get a +3 not -3, therefore there is no solution
|
Rate-of-work-word-problems/567310: A can finish the work in 6 days less than the time taken by B to finish the work.If both of them together can finish it in 4 days, then find the time taken by B alone to finish the workA can finish the work in 6 days less than the time taken by B to finish the work.If both of them together can finish it in 4 days, then find the time taken by B alone to finish the work 1 solutions
Answer 366544 by ankor@dixie-net.com(15623) on 2012-02-03 18:44:33 (Show Source):
You can put this solution on YOUR website!A can finish the work in 6 days less than the time taken by B to finish the work.
If both of them together can finish it in 4 days, then find the time taken by B alone to finish the work.
:
Let t = time required by B to do the work
then
(t-6) = time required by A to do it
:
Let the completed job = 1
:
A shared work equation
:
 +  = 1
multiply by t(t-6)
t(t-6)*  + t(t-6)*  = t(t-6)
cancel the denominators, resulting in
4t + 4(t-6) = t^2 - 6t
4t + 4t - 24 = t^2 - 6t
combine like terms on the right to form a quadratic equation
0 = t^2 - 6t - 8t + 24
t^2 - 14t + 24 = 0
Factors to
(t-12)(t-2) = 0
Two solutions, but only one will make sense
t = 12 hrs for B to do the job alone.
:
:
Check this
 +  =
 +  = 1
|
Age_Word_Problems/567227: Rose is 29 Years old. Her mother is 50. How many years ago was the mother twice as old as Rose? 1 solutions
Answer 366533 by ankor@dixie-net.com(15623) on 2012-02-03 17:05:39 (Show Source):
You can put this solution on YOUR website!Rose is 29 Years old. Her mother is 50.
How many years ago was the mother twice as old as Rose?
:
Let y = no. of years for this to be true
:
50-y = 2(29-y)
50 - y = 58 - 2y
- y + 2y = 58 - 50
y = 8 yrs ago
;
:
See if that is true, 8 yrs ago:
Mom will be 42
Rose will be 21
|
Travel_Word_Problems/567370: A train travels at a speed of 88 mi/hr.
A.) How many hours does it take to travel 1100 feet?
B.) How many yards can it travel in thirty minutes?
Thank you! 1 solutions
Answer 366531 by ankor@dixie-net.com(15623) on 2012-02-03 16:55:05 (Show Source):
You can put this solution on YOUR website!A train travels at a speed of 88 mi/hr.
:
A.) How many hours does it take to travel 1100 feet?
 = .002367 hrs
:
B.) How many yards can it travel in thirty minutes?
we know there are 1760 yds in mile
 * (88*1760) = 77,440 yds
|
Quadratic_Equations/567353: A flag is raised while an onlooker watches from a distance of 21 feet away from the base of the flag pole (see the figure below). The flag rises vertically at a rate of 8 inches per second. Let t denote the time (in seconds) after the flag begins to rise (For simplicity, assume that when the flag begins to rise it is 0 inches above the ground). Express the distance d (in feet) between the flag and the onlooker as a function of t.
All of the answers I come up with are incorrect! Any help is greatly appreciated!!! Thanks! 1 solutions
Answer 366529 by ankor@dixie-net.com(15623) on 2012-02-03 16:32:47 (Show Source):
You can put this solution on YOUR website!A flag is raised while an onlooker watches from a distance of 21 feet away from the base of the flag pole (see the figure below).
The flag rises vertically at a rate of 8 inches per second.
Let t denote the time (in seconds) after the flag begins to rise (For simplicity, assume that when the flag begins to rise it is 0 inches above the ground).
Express the distance d (in feet) between the flag and the onlooker as a function of t.
:
They want this in feet; convert 8" to  ft
:
The distance from the onlooker to the flag is the hypotenuse, formed by the 21' from the base of the pole and height of the flag which would be  t
:
d(t) =
d(t) =
|
Numeric_Fractions/567391: I need to divide 38 3/4 inches by 4 to make a skirt. I would appreciate not just an answer but if you can help me understand it! I would like to understand how this strange system works in division. I actually don't understand why sometimes a number is called an 1/8 & sometimes 2/16th. Can you help me? Many thanks. 1 solutions
Answer 366523 by ankor@dixie-net.com(15623) on 2012-02-03 15:25:29 (Show Source):
You can put this solution on YOUR website!I need to divide 38 3/4 inches by 4 to make a skirt.
:
First convert 38 3/4 inches to an improper fraction (find how many 4th are in 38 3/4)
4(38) + 3
which is:
152 + 3 = 
:
You can effectively divide this by four, my multiplying it by 1/4
multiply the numerators and the denominators
 *  = 
convert that by using long division where you have a remainder
. . ____
16| 155
You should get 9 with a remainder of 11, therefore it's 9 11/16 inches
:
:
I actually don't understand why sometimes a number is called an 1/8 & sometimes 2/16th.
Think of it as if you cut a pizza into 16 equal pie-shaped pieces
then
8 pieces would be one half the pizza (1/2), which is 8/16 of the pizza
Similarly:
4 pieces would be one fourth of a pizza (1/4), which is 4/16 of the pizza
and
2 pieces would be one eighth of a pizza (1/8), which is 2/16 of the pizze
:
Did this help? I will endeavor to explain further if you want me to. Anyone who has the skill to actually sew their own skirt, should have no trouble with fractions.
|
Triangles/567400: please help me solve this problem: one side of an equilateral triangle increased by 11 is 33 less than three times another side. if the sides are measured in inches, what are the measures of the three sides of the triangle?
I have tried a bunch of different ways and just can not figure it out. I tried doing things back words (ex:increased by 11/decreased by 11) and nothing is working your help would be much apreciated. 1 solutions
Answer 366522 by ankor@dixie-net.com(15623) on 2012-02-03 15:02:50 (Show Source):
You can put this solution on YOUR website!one side of an equilateral triangle increased by 11 is 33 less than three times another side. if the sides are measured in inches, what are the measures of the three sides of the triangle?
:
x = the length of the 3 sides of the equilateral triangle
:
"one side of an equilateral triangle increased by 11 is 33 less than three times another side."
x + 11 = 3x - 33
11 + 33 = 3x - x
44 = 2x
x = 22 inches
|
Miscellaneous_Word_Problems/566914: John, Paul, George, and Stuart were four school friends. After one particularly hard day's night, they went to see a movie together. After the first time, they began going regularly but on different schedules. (They even went on weekends.) John went every fourth day, Paul went every fifth day, George went every seventh day, and Stuart went every ninth day. How many days was it before all four went to the movies together again?
Thanks 1 solutions
Answer 366437 by ankor@dixie-net.com(15623) on 2012-02-02 21:03:21 (Show Source):
You can put this solution on YOUR website!John went every fourth day,
Paul went every fifth day,
George went every seventh day, and
Stuart went every ninth day.
How many days was it before all four went to the movies together again?
:
What we want here is the Least common multile of 4, 5, 7, 9
The numbers do not have any common prime factors, therefore
4*5*7*9 = 1260 days before they all went to the movies together again
|
Travel_Word_Problems/566835: The clarke family went sailing on a lake. Their boat averaged 6 kilometers per hour. The rourke family took their outboard runabout for a trip on the lake for the same amount of time. Their boat averaged 14 kilometers per hour. The rourke family traveled 20 kilometers farther thanthe clarke family. How many hours did each family spend on the their boat trip? 1 solutions
Answer 366434 by ankor@dixie-net.com(15623) on 2012-02-02 20:42:06 (Show Source):
You can put this solution on YOUR website!The clarke family went sailing on a lake.
Their boat averaged 6 kilometers per hour.
The rourke family took their outboard runabout for a trip on the lake for the same amount of time.
Their boat averaged 14 kilometers per hour.
The rourke family traveled 20 kilometers farther thanthe clarke family.
How many hours did each family spend on the their boat trip?
:
Let t = no. of hrs of each boat trip
:
Write a distance equation, dist = speed * time
;
14t = 6t + 20
14t - 6t = 20
8t = 20
t = 20/8
t = 2.5 hrs on the lake for each family
:
:
Check this by finding the distance each traveled
14(2.5) = 35 km
6(2.5) = 15
----------------
differs = 20 km
|
Volume/566576: A grain silo has a cylindrical shape. Its diameter is 16 ft, and its height is 46ft. What is the volume of grain that can be stored in the silo?
(Use the value for , and round your answer to the nearest cubic foot. Be sure to include the correct unit in your answer.)
1 solutions
Answer 366386 by ankor@dixie-net.com(15623) on 2012-02-02 15:46:37 (Show Source):
You can put this solution on YOUR website!A grain silo has a cylindrical shape.
Its diameter is 16 ft, and its height is 46ft.
What is the volume of grain that can be stored in the silo?
;
radius of silo will be 8 ft
Vol of cylinder: 
therefore:

V = 9248.85 ~ 9,249 cu/ft
|
test/566483: Penny is 39 years old and has lived in Pennsylvania for 16 years. How old will penny be when she has lived in Pennsylvania for half of her life? 1 solutions
Answer 366373 by ankor@dixie-net.com(15623) on 2012-02-02 14:36:39 (Show Source):
You can put this solution on YOUR website!Penny is 39 years old and has lived in Pennsylvania for 16 years.
How old will penny be when she has lived in Pennsylvania for half of her life?
:
Let x = no. of yrs for her to have lived half her life in Pa
:
x + 16 =  (x+39)
x + 16 = .5x + 19.5
x - .5 = 19.5 - 16
.5x = 3.5
Multiply both side by 2
1x = 2(3.5)
x = 7 yrs,
therefore
39 + 7 = 46 yrs old, she will have lived half her life in PA
:
:
Check this by finding the no. yrs in PA
7 + 16 = 23 yrs, which is half of 46
|
Polygons/566580: Please help me on this, i have a test on this next class and i have no idea what im supposed to do!
The ratio of the weight of an object on Mars to its weight on Earth is 9 to 25. If a person weighs 120 pounds on Earth, how much would the person weigh on Mars?
A flagpole casts a shadow of 8.5 meters long. If an algebra student 1.6 meters tall casts a shadow of 2.0 meters long at the same time and location, how tall is the flagpole in meters?
THANKS SO MUCH!!!! :DDDDDDDDDDDDDDDDDDDDDDDDDD 1 solutions
Answer 366300 by ankor@dixie-net.com(15623) on 2012-02-02 07:08:47 (Show Source):
You can put this solution on YOUR website!The ratio of the weight of an object on Mars to its weight on Earth is 9 to 25.
If a person weighs 120 pounds on Earth, how much would the person weigh on Mars?
:
These are just ratio equations, quite easy.
let m = his weight on Mars
 = 
cross multiply
25m = 120 * 9
25m = 1080
m = 
m = 43.2 lb on Mars
:
:
A flagpole casts a shadow of 8.5 meters long.
If an algebra student 1.6 meters tall casts a shadow of 2.0 meters long at the same time and location, how tall is the flagpole in meters?
:
Similar triangles, the corresponding sides have the same ratio
let f = height of the flag pole
 = 
Cross multiply
2f = 1.6 * 8.5
:
You should be able to finish this one, just like the 1st one
|
Average/566416: A stuent received scores of 51, 79, and 57 on their first three tests for a class. There will be a total of four tests for the class and the student hopes to acheive and average score of n in the class. Express the score, S, needed on the fourth test to acheive this average, as a function of n. 1 solutions
Answer 366250 by ankor@dixie-net.com(15623) on 2012-02-01 21:56:19 (Show Source):
You can put this solution on YOUR website!A stuent received scores of 51, 79, and 57 on their first three tests for a class.
There will be a total of four tests for the class and the student hopes to acheive and average score of n in the class.
Express the score, S, needed on the fourth test to acheive this average, as a function of n.
:
 = n
s + 187 = 4n
s = 4n - 187
|
Linear_Algebra/566535: The sum of two numbers is 30. The larger number is 5 more than four times the smaller one. Find the product of the number. (Ans 125) 1 solutions
Answer 366249 by ankor@dixie-net.com(15623) on 2012-02-01 21:50:43 (Show Source):
You can put this solution on YOUR website!The sum of two numbers is 30.
a + b = 30
:
The larger number is 5 more than four times the smaller one.
a = 4b + 5
:
Replace a in the 1st equation with (4b+5), find b
(4b+5) + b = 30
5b = 30 - 5
b = 25/5
b = 5, then a = 4(5)+5 = 25
:
"Find the product of the number."
25 * 5 = 125
|
|