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Percentage-and-ratio-word-problems/652371: D= 1/5 fk (solve for f) 1 solutions Answer 407990 by ankor@dixie-net.com(15746)   on 2012-09-16 22:18:09 (Show Source): You can put this solution on YOUR website! D = 1/5 fk (solve for f) multiply both sides by 5 5D = fk Divide both sides by k = f

Numbers_Word_Problems/652352: Luke wants to travel 1,000 miles on an adult tricycle and has two spare tires. However, he wants to use all five tires equally over the course of the trip. Because he is riding a tricycle he can only ride three at a time. At the end of the trip. How many miles will each tire have been used? 1 solutions Answer 407985 by ankor@dixie-net.com(15746)   on 2012-09-16 21:56:28 (Show Source): You can put this solution on YOUR website! Luke wants to travel 1,000 miles on an adult tricycle and has two spare tires. However, he wants to use all five tires equally over the course of the trip. Because he is riding a tricycle he can only ride three at a time. At the end of the trip. How many miles will each tire have been used? : I am going to say 3/5 * 1000 = 600 mi per tire, or 3000 tire-miles divided by 5, also gives 600 mi per tire.: To rotate the tires: replace tire 1 with tire 4 after 400 mi, tire 1 has 200 mi left on it replace tire 2 with tire 5 after 400 mi, tire 2 has 200 mi left on it replace tire 3 with tire 1 after 600 mi, at 800 mi replace tire 1 with tire 2

Exponents/652291: Hi. I am an 8th grader in an honors math class. Right now I have below a 70 and have to atleast have an 80 To stay in the class. My final dates are oct, 1&2. I understand all of the material but when we take test or quizzes I either make lots of dumb mistakes or freak out and get it wrong. Any advice? 1 solutions Answer 407968 by ankor@dixie-net.com(15746)   on 2012-09-16 20:53:02 (Show Source): You can put this solution on YOUR website! One of the things that you can do with equations in algebra, is check your answer in the original problem, for instance if you get x = 4, replace x in the original problem with 4 and see if equality is preserved, (right side value = left side value.) Do this for every equation problem that you have, both homework and in the final. You will find math mistakes and other errors this way. : If the problem is not an equation, an expression that you must simplify, then assign a value (like 2) to the variables in the original expression, find the value. Do the same with your simplified expression, they should be equal : Sometimes assigning a value of 2 will cause you to have a 0 in the denominator; This of course is not allowed. Then assign another value like 3 and do the same thing

Travel_Word_Problems/652094: A stream with a velocity of 1/4 mile per hour can move coarse sand particles about 0.02 inch in diameter. Approximate the velocity required to carry particles 0.12 inch in diameter. Use the fact that the diameter of the largest particle that can be moved by a stream varies approximately directly as the square of the velocity of the stream. 1 solutions Answer 407952 by ankor@dixie-net.com(15746)   on 2012-09-16 20:02:17 (Show Source): You can put this solution on YOUR website! A stream with a velocity of 1/4 mile per hour can move coarse sand particles about 0.02 inch in diameter. Approximate the velocity required to carry particles 0.12 inch in diameter. Use the fact that the diameter of the largest particle that can be moved by a stream varies approximately directly as the square of the velocity of the stream. : let v = velocity of the stream; change 1/4 to .25 : Write a proportion equation = = 6 v = v = .612 mph

Travel_Word_Problems/651801: An aircraft carrier left the Pier 53 and traveled north. An container ship left 1 hour later traveling at 3km/h faster in an effort to catch up to the aircraft carrier. After traveling for 5 hours the container ship finally caught up. What was the aircraft carrier's average speed? 1 solutions Answer 407843 by ankor@dixie-net.com(15746)   on 2012-09-15 21:27:58 (Show Source): You can put this solution on YOUR website! An aircraft carrier left the Pier 53 and traveled north. A container ship left 1 hour later traveling at 3km/h faster in an effort to catch up to the aircraft carrier. After traveling for 5 hours the container ship finally caught up. What was the aircraft carrier's average speed? : Let s = the carrier's speed then (s+3) = container ship's speed : When the container catches the carrier, they will have traveled the same dist Write a dist equation; dist = time * speed The carrier traveled for 1 hr longer, 6 hrs 6s = 5(s+3) 6s = 5s + 15 6s - 5s = 15 s = 15 km/hr is the carrier speed : : Check this by finding the distances Carrier: 6(15) = 90 km Container: 5(18) = 90 km

Linear_Equations_And_Systems_Word_Problems/651642: The ones and hundreds digits of a three-digit number are interchanged and the new number is subtracted from the first number. The difference obtained is three-digit number 59x. Find x. How am I going to find x ?? I tried by using xyz-zyk=59x but i would get decimal number. 1 solutions Answer 407802 by ankor@dixie-net.com(15746)   on 2012-09-15 15:58:07 (Show Source): You can put this solution on YOUR website! The ones and hundreds digits of a three-digit number are interchanged and the new number is subtracted from the first number. The difference obtained is three-digit number 59x. Find x. : The equation should be: (100x + 10y + z) - (100z + 10y + x) = 590 + x Remove the brackets and combine like terms 100x - x + 10y - 10y - 100z + z = 590 + x 99x - 99z = 590 + x we know that the right side also has to be divisible by 99, (99*6=594) x = 4

Numbers_Word_Problems/651576: the digits of a three- digit number are three consecutive even integers. The middle digit is the least and the first digit is the greatest. If the number is divided by twice the sum of its digits, the quotient is 423/18. Find the number. pls really need ur help 1 solutions Answer 407791 by ankor@dixie-net.com(15746)   on 2012-09-15 14:56:16 (Show Source): You can put this solution on YOUR website! the digits of a three-digit number are three consecutive even integer : The middle digit is the least and the first digit is the greatest. Let n = the middle digit then (n+4) = the greatest and (n+2) = the next greatest : The sum of the three digits: n + (n+2) + (n+4) = (3n+6) : If the number is divided by twice the sum of its digits, the quotient is 423/18 = = = Cancel 3 = Cross multiply 423(2n+4) = 18(37n + 134) 846n + 1692 = 666n + 2412 846n - 666n = 2412 - 1692 180n = 720 n = 720/180 n = 4 is the middle digit of the number then 4 + 4 = 8 is the 1st digit and 4 + 2 = 6 is 3rd digit : 846 is the number : : Check this; (number over twice the sum of the digits) = 846/36 reduces to 423/18

Square-cubic-other-roots/651541: simplify by removing factors from radicand: square root 288, cube root 500, cube root -250, 4th root 192 1 solutions Answer 407729 by ankor@dixie-net.com(15746)   on 2012-09-14 21:47:27 (Show Source): You can put this solution on YOUR website! simplify by removing factors from radicand: : Factor to reveal a perfect square 12^2 = 144 : Factor to reveal a perfect cube, 5^3 = 125 : factor; -5^3 = -250 : factor; 2^4 = 16

Numbers_Word_Problems/651527: If the square of the larger of two consecutive integers is reduced by three times the smaller, the result is the sum of the integers. Find the integers 1 solutions Answer 407719 by ankor@dixie-net.com(15746)   on 2012-09-14 20:37:31 (Show Source): You can put this solution on YOUR website! If the square of the larger of two consecutive integers is reduced by three times the smaller, the result is the sum of the integers. Find the integers : Let x = the larger integer then (x-1) = the smaller : x^2 - 3(x-1) = x + (x-1) x^2 - 3x + 3 = 2x - 1 x^2 - 3x - 2x + 3 + 1 = 0 x^2 - 5x + 4 = 0 Factors to (x-1)(x-4) = 0 two solutions x = 1, then 0 = the smaller integer and x = 4, then 3 = the smaller integer : Both solutions seems to work, if you consider 0 an integer

Travel_Word_Problems/651552: at 6AM, a boy rides his bike due north from campus at 12 mph. Two hours later, another boy rides his bike due east from the same point, also at 12mph. When will they be 120 miles apart? 1 solutions Answer 407710 by ankor@dixie-net.com(15746)   on 2012-09-14 19:43:08 (Show Source): You can put this solution on YOUR website! at 6AM, a boy rides his bike due north from campus at 12 mph. Two hours later, another boy rides his bike due east from the same point, also at 12mph. When will they be 120 miles apart? : let t = travel time of the 1st boy then (t-2) = travel time of the 2nd (left 2 hrs later) therefore: 12t = distance traveled by the 1st boy and 12(t-2) = (12t-24) = distance traveled by the 2nd : This is a pythag problem; a^2 + b^2 = c^2, where a = 12t b = 12(t-2) c = 120 : (12t)^2 + (12t-24)^2 = 120^2 : 144t^2 + 144t^2 - 288t - 288t + 576 = 14400 : 288t^2 - 576t + 576 - 14400 = 0 : 288t^2 - 576t - 13824 = 0 Simplify, divide thru by 288, results: t^2 - 2t - 48 = 0 factors to (t-8)(t+6) = 0 The positive solution t = 8 hrs is the travel time of the 1st boy, therefore 6:00 Am + 8:00 = 2:00 pm, they will 120 mi apart : : Check this on your calc: enter

Quadratic_Equations/651454: Find the roots of the quadratic equation x2 + 2x + 3 = 3x2 + 2x - 1. (Enter the smaller root in the first box and the larger root in the second box.) 1 solutions Answer 407707 by ankor@dixie-net.com(15746)   on 2012-09-14 19:15:21 (Show Source): You can put this solution on YOUR website! Find the roots of the quadratic equation x^2 + 2x + 3 = 3x^2 + 2x - 1. Combine like terms on the right 0 = 3x^2 - x^2 + 2x - 2x - 1 - 3 0 = 2x^2 - 4 4 = 2x^2 Divide both sides by 2 2 = x^2 x = + and x = -

Numbers_Word_Problems/651498: the product of two numbers is 30. if one of the numbers i four fifths, what is the other number? 1 solutions Answer 407704 by ankor@dixie-net.com(15746)   on 2012-09-14 19:03:36 (Show Source): You can put this solution on YOUR website! the product of two numbers is 30. if one of the numbers i four fifths, what is the other number? : Let x = the other number x = 30 multiply both sides by 5 4x = 150 x = 150/4 x = 37 : : Check this using decimal values, x = 37.5 and 4/5 = .8 .8 * 37.5 = 30

Rate-of-work-word-problems/651311: It take 5 people to mow the lawn in 12 hours. How long would it take for 2 people to complete the same job? 1 solutions Answer 407683 by ankor@dixie-net.com(15746)   on 2012-09-14 17:10:58 (Show Source): You can put this solution on YOUR website! It take 5 people to mow the lawn in 12 hours. Find the number of man-hrs to do the job 5 * 12 = 60 man-hrs : How long would it take for 2 people to complete the same job? Let t = no. of hrs for 2 men to do it 2t = 60 t = 60/2 t = 30 man-hrs

Age_Word_Problems/651399: Maricar is ten times older than her son Carl. In five years, the product of her age and her son's age two years ago will be 35. Find their present age. 1 solutions Answer 407670 by ankor@dixie-net.com(15746)   on 2012-09-14 15:10:36 (Show Source): You can put this solution on YOUR website! Maricar is ten times older than her son Carl. m = 10c : In five years, the product of her age and her son's age two years ago will be 35. (m+5)(c-2) = 35 replace m with 10c (10c+5)(c-2) = 35 FOIL 10c^2 - 20c + 5c - 10 = 35 10c^2 - 15c - 10 - 35 = 0 10c^2 - 15c - 45 = 0 simplify, divide by 5 2c^2 - 3c - 9 = 0 Factors to (2c+3)(c-3) = 0 the positive solution is all we want here c = 3 yrs is Carl's present age then 10(3) = 30 yrs is M's present age

Travel_Word_Problems/651286: We drove from town A to town D. In order to get there, we hade to drive thru town B and town C. It is 10 mi farther from town A to town B then it is from town B to town C. It is 10mi farther from town B to town C then it from town C to town D. It is 330 miles from town A to town D. How far is it from town A to town B? 1 solutions Answer 407662 by ankor@dixie-net.com(15746)   on 2012-09-14 14:28:11 (Show Source): You can put this solution on YOUR website! We drove from town A to town D. In order to get there, we had to drive thru town B and town C. It is 10 mi farther from town A to town B than it is from town B to town C. It is 10mi farther from town B to town C than it from town C to town D. It is 330 miles from town A to town D. How far is it from town A to town B? : A--------------B---------C------D : "It is 10 mi farther from town A to town B than it is from town B to town C." AB = BC + 10 : "It is 10mi farther from town B to town C than it from town C to town D." BC = DC + 10 or DC = BC - 10 : "It is 330 miles from town A to town D. AD = 330 Therefore AB + BC + CD = 330 replace AB and DC (BC+10) + BC + (BC-10) = 330 Combine like terms 3BC + 10 - 10 = 330 3BC = 330 BC = 330/3 BC = 110 : "How far is it from town A to town B?" AB = BC + 10 AB = 110 + 10 AB = 120 mi

Rational-functions/651053: please help me with the following problem =http://postimage.org/image/y8wymavmx/ 1 solutions Answer 407578 by ankor@dixie-net.com(15746)   on 2012-09-13 22:01:56 (Show Source): You can put this solution on YOUR website! (a) The overall radius of the tank = (r+1) : Find the volume of the base Vb = The volume of the outer part is overall vol - inner volume Vo = - () Factor out pi*h Vo = FOIL (r+1)(r+1) Vo = : Vo = : Volume of outer plus base = 100 cu/ft + = 100 Divide by pi + = 31.831 + = 31.831 h(2r+1) = 31.831 - r^2 - 2r - 1 h = : (b) V = : (c) Max vol = 65 cu/ft; r = 2.75; h = 2.73

Travel_Word_Problems/650999: Cyclists A and B each average 30 km/h for the first hour of a 100 km race at the end of the hour , B has a a mishap and loses 12 min. Cyclist A finishes the remainder of the race at an average of 25 km/ h . if cyclist B averages 27.5 km/h after resuming, will B catch A before the finish line? 1 solutions Answer 407548 by ankor@dixie-net.com(15746)   on 2012-09-13 18:57:53 (Show Source): You can put this solution on YOUR website! Cyclists A and B each average 30 km/h for the first hour of a 100 km race. At the end of the hour, B has a a mishap and loses 12 min. Cyclist A finishes the remainder of the race at an average of 25 km/h. If cyclist B averages 27.5 km/h after resuming, will B catch A before the finish line? : From the given information, I understand that both cyclist have 70 km to go. Change 12 min to 12/60 = .2 hrs : Find A's time to finish the race = 2.8 hrs Add .2 hr to B's time to finish the race .2 + = 2.745 hrs Therefore B will finish the race before A

Bodies-in-space/650764: a cylinder with radius 2 inches and height 4 inches has its radius tripled. How many times greater is the volume of the larger cylinder than the smaller cylinder. bobhilton34@yahoo.com 1 solutions Answer 407517 by ankor@dixie-net.com(15746)   on 2012-09-13 16:35:35 (Show Source): You can put this solution on YOUR website! a cylinder with radius 2 inches and height 4 inches has its radius tripled. How many times greater is the volume of the larger cylinder than the smaller cylinder. : Since the radius is squared when you find the volume of a cylinder, tripling the radius, increases the volume by 3^2 or 9 times : You can confirm this on your calc enter: and

Travel_Word_Problems/650622: two cars travel the same route to a town that is 200 miles from where they started and then return, by the same route to where they started. Car A averages 50 miles per hour one way and 40 miles per hour on the return trip. Car B averages 45 miles per hour both ways. Do the cars travel the total distance in the same amout of time? 1 solutions Answer 407354 by ankor@dixie-net.com(15746)   on 2012-09-12 22:01:29 (Show Source): You can put this solution on YOUR website! two cars travel the same route to a town that is 200 miles from where they started and then return, by the same route to where they started. Car A averages 50 miles per hour one way and 40 miles per hour on the return trip. Car B averages 45 miles per hour both ways. Do the cars travel the total distance in the same amount of time? : Car A time A = + A = 9 hrs : Car B time B = B = 8.89 hrs

Numeric_Fractions/650564: 3/4+1/3 ---------this is straight line 2/3+1/6 what is the order of operations for this expression .order of operations says division comes before addition.you can divide 2/3+1/6 into 3/4+1/3.how do you solve this? 1 solutions Answer 407351 by ankor@dixie-net.com(15746)   on 2012-09-12 21:52:12 (Show Source): You can put this solution on YOUR website! --------- : Put the fractions over a single common denominator ------------ which is ------ invert the dividing fraction and multiply, then cancel 12 * = = 1

Mixture_Word_Problems/649910: i kneed to know what kind of ingredient and the amount needed to stabilize 75 gallons of gassoline for 1 yesr. 1 solutions Answer 407117 by ankor@dixie-net.com(15746)   on 2012-09-11 21:55:37 (Show Source): You can put this solution on YOUR website! Buy some fuel stabilizer (there are several brands), the directions on the container will tell you how many oz required for each gallon. For that many gallons you will need several containers of it.

Functions/649450: A flag is raised while an onlooker watches from a distance of 17 feet away from the base of the flag pole. The flag rises vertically at a rate of 5 inches per second. Let t denote the time (in seconds) after the flag begins to rise (For simplicity, assume that when the flag begins to rise it is 0 inches above the ground). Express the distance d (in feet) between the flag and the onlooker as a function of t. I have attempted this several times using the pythagorean theorem, but I I have not gotten the correct answer. Please help! 1 solutions Answer 407108 by ankor@dixie-net.com(15746)   on 2012-09-11 21:16:16 (Show Source): You can put this solution on YOUR website! A flag is raised while an onlooker watches from a distance of 17 feet away from the base of the flag pole. The flag rises vertically at a rate of 5 inches per second. Let t denote the time (in seconds) after the flag begins to rise (For simplicity, assume that when the flag begins to rise it is 0 inches above the ground). Express the distance d (in feet) between the flag and the onlooker as a function of t. : Change 5 inches to ft : Use the pythag: c^2 = a^2 + b^2, in this problem a = t b = 17 c = d : d^2 = (t)^2 + 17^2 d =

Travel_Word_Problems/649584: if a bullet travels at 631.0 m/s, what is its speed in miles per hour? 1 solutions Answer 407065 by ankor@dixie-net.com(15746)   on 2012-09-11 17:19:35 (Show Source): You can put this solution on YOUR website! if a bullet travels at 631.0 m/s, what is its speed in miles per hour? : Convert to km/hr, then to mph * .6214 = 1411.57 mph

Percentage-and-ratio-word-problems/649396: Riley, Benny, and Claudia share a bag of peas in the ratio 4:3:8. If claudia gives 1/4 of her share to Benny, Benny will have 14 more peas than Riley. How many peas are there altogether? 1 solutions Answer 407040 by ankor@dixie-net.com(15746)   on 2012-09-11 16:29:26 (Show Source): You can put this solution on YOUR website! Riley, Benny, and Claudia share a bag of peas in the ratio 4:3:8. If Claudia gives 1/4 of her share to Benny, Benny will have 14 more peas than Riley. How many peas are there altogether? : Let x = the multiplier then 4x = R's peas 3x = B's peas 8x = C's peas and 15x = total number of peas : "If claudia gives 1/4 of her share to Benny, Benny will have 14 more peas than Riley." 3x + *8x = 4x + 14 3x + 2x = 4x + 14 5x - 4x = 14 x = 14 is the multiplier therefore 15(14) = 210 peas altogether : : : Check this, find how many each started out with, and find the total R: 14(4) = 56 peas B: 14(3) = 42 peas C: 14(8) = 112 peas -------------------- total peas: 210

Travel_Word_Problems/649345: A person starts a journey from his home and travels in a speed of 5Km/h he arrives to the destination 1 minute late. and if he travels in a speed of 6Km/h he arrives 1 minute early . what's the distance he traveled? 1 solutions Answer 407023 by ankor@dixie-net.com(15746)   on 2012-09-11 16:13:38 (Show Source): You can put this solution on YOUR website! A person starts a journey from his home and travels in a speed of 5Km/h, he arrives to the destination 1 minute late. and if he travels in a speed of 6Km/h he arrives 1 minute early. what's the distance he traveled? : Let d = the distance traveled : The time difference between the two scenarios is 2 min: 2/60 = 1/30 hr : Write a time equation: time = dist/speed : - = multiply by 30 6d - 5d = 1 d = 1 mi is the distance he traveled

Travel_Word_Problems/649587: tom and rib walk towards each other at 5km/hr and 10 km/hr.then they double their speed at end of each hour.find after covering how much distance tom meets rib? 1 solutions Answer 406995 by ankor@dixie-net.com(15746)   on 2012-09-11 15:02:41 (Show Source): You can put this solution on YOUR website! tom and rib walk towards each other at 5km/hr and 10 km/hr. then they double their speed at end of each hour. find after covering how much distance tom meets rib? : Not enough information, how far apart initially?

Travel_Word_Problems/649364: 240 miles where travel in 7 hours 1st part of the trip was travel at 20 miles/hr then the speed was double for the second part , how many miles where travel at 20 mph 1 solutions Answer 406954 by ankor@dixie-net.com(15746)   on 2012-09-11 08:25:02 (Show Source): You can put this solution on YOUR website! 240 miles were traveled in 7 hours. 1st part of the trip was traveled at 20 miles/hr, then the speed was doubled for the second part. How many miles were traveled at 20 mph? : Let d = distance traveled at 20 mph then (240-d) = distance traveled at 40 mph : Write a time equation; time = dist/speed : 20mph time + 40mph time = 7 hrs + = 7 multiply by 40 to clear the denominators, results: 2d + 240 - d = 40(7) d = 280 - 240 d = 40 mi at 20 mph, then 240-40 = 200 mi at 40 mph : : Confirm this, find the times at each speed 40/20 = 2 hrs 200/40 = 5 hrs ----------------- total time: 7 hrs

Travel_Word_Problems/648934: sue walks at a rate of 10 feet every 5 seconds while tom walks at a rate of 15 feet every 5 seconds. If sue has a head start of 25 feet, after how many seconds will they be at the same spot? 1 solutions Answer 406888 by ankor@dixie-net.com(15746)   on 2012-09-10 20:00:14 (Show Source): You can put this solution on YOUR website! Sue walks at a rate of 10 feet every 5 seconds while tom walks at a rate of 15 feet every 5 seconds. If sue has a head start of 25 feet, after how many seconds will they be at the same spot? : Change the speeds to ft/sec Sue: 10/5 = 2 ft/sec Tom: 15/5 = 3 ft sec : Let t = time (in sec) for T to catch S : When T catches S, T will have walked 25 more ft than S Write a distance equation; dist = speed * time : 3t = 2t + 25 3t - 2t = 25 t = 25 sec for Tom to catch Sue : : Confirm this, Tom: 3(25) = 75ft Sue: 2(25) = 50ft; plus her 25 ft head start = 75 ft

Miscellaneous_Word_Problems/648464: THE SPEED OF A MOVING WALKAWAY IS TYPICALLY ABOUT 2.5 PER SECOND. WALKING ON SUCH A MOVING WALKAWAY, IT TAKES KAREN A TOTAL OF 40 SECONDS TO TRAVEL 50 FEET WITH THE MOVEMENT OF THE WALKAWAY AND THEN BACK AGAIN AGAINST THE MOVEMENT OF THE WALKAWAY. WHAT IS KAREN'S NORMAL WALKING SPEED? 1 solutions Answer 406858 by ankor@dixie-net.com(15746)   on 2012-09-10 17:18:05 (Show Source): You can put this solution on YOUR website! THE SPEED OF A MOVING WALKAWAY IS TYPICALLY ABOUT 2.5 PER SECOND. WALKING ON SUCH A MOVING WALKAWAY, IT TAKES KAREN A TOTAL OF 40 SECONDS TO TRAVEL 50 FEET WITH THE MOVEMENT OF THE WALKAWAY AND THEN BACK AGAIN AGAINST THE MOVEMENT OF THE WALKAWAY. WHAT IS KAREN'S NORMAL WALKING SPEED? : Let w = normal walking speed in ft/sec Then (w+2.5) = effective speed with the walkway and (w-2.5) = effective speed against the walkway : Write a time equation: time = dist/speed : Time with + time against = 40 sec + = 40 : Multiply by (w+2.5)(w-2.5); results: 50(w-2.5) + 50(w+2.5) = 40(w-2.5)(w+2.5) : 50w - 125 + 50w + 125 = 40(w^2-6.25) : 100w = 40(w^2-6.25) divide both sides by 20 5w = 2(w^2-6.25) 5w = 2w^2 - 12.5 A quadratic equation 2w^2 - 5w - 12.5 = 0 Use the quadratic formula to find w; a=2; b=-5; c=-12.5 : I got a positive solution ~ 4.045 ft/sec, normal walking speed, see what you get

Equations/648359: 1/4(t+3g)=-g/8 1 solutions Answer 406694 by ankor@dixie-net.com(15746)   on 2012-09-09 19:58:37 (Show Source): You can put this solution on YOUR website! Assume you want to find g : (t+3g)= multiply both side by 8, results: 2(t+3g) = -g 2t + 6g = -g 6g + g = -2t 7g = -2t g = t

Travel_Word_Problems/647921: In a race of 1000m, Jacqui finishes 110m ahead of Lisa and 180m ahead of Fran. If Lisa and Fran continue at the same rates, how far in front of Fran will Lisa finish? (The answer is not 80m). 1 solutions Answer 406502 by ankor@dixie-net.com(15746)   on 2012-09-08 22:21:18 (Show Source): You can put this solution on YOUR website! In a race of 1000m, Jacqui finishes 110m ahead of Lisa and 180m ahead of Fran. If Lisa and Fran continue at the same rates, how far in front of Fran will Lisa finish? : Assume a time for Jac to run the race, 100 seconds : In 100 sec Lisa runs (1000-110) 890 meters : Find Lisa's speed: 890/100 = 8.9 m/sec : Find how long it takes Lisa to run 1000 m, finish the race 1000/8.9 = 112.36 seconds : Find Fran's speed; 1000-180 = 820 m; 820/100 = 8.2 m/sec is Fran's speed : Find how far Fran has run when Lisa crossed the finish line in 112.36 sec 8.2*112.36 = 921.35 m therefore 1000-921.35 = 78.65 m Fran is behind, when Lisa finishes