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 Travel_Word_Problems/654675: over a distance a car traveling 40 mph, the car then drives that same distance 10 mph, what is the average mph for the whole trip? i tried working it out but i got stuck at the 2nd stage of the solution so please give me a very detailed solution 1 solutions Answer 408840 by ankor@dixie-net.com(15652)   on 2012-09-20 20:39:53 (Show Source): You can put this solution on YOUR website!over a distance a car traveling 40 mph, the car then drives that same distance 10 mph, what is the average mph for the whole trip? : let d = the distance traveled at 40 mph and the distance traveled at 10 mph let a = the average mph for the trip : Write a time equation; time = dist/speed : 40mph time + 10mph time = total time + = multiply by 40a, to clear the denominators 40a* + 40a* = 40a* Cancel the denominators ad + 4ad = 40(2d) 5ad = 80d divide both sides by d 5a = 80 a = 80/5 a = 16 mph is the average for the trip : Was this detailed enough for you? C
 Expressions-with-variables/654691: I dont understand how to do this equations with variables on both sides: -2(k-8)+7k = -2-k please help.1 solutions Answer 408839 by ankor@dixie-net.com(15652)   on 2012-09-20 20:26:49 (Show Source): You can put this solution on YOUR website!-2(k-8) + 7k = -2 - k multiply whats inside the brackets -2k + 16 + 7k = - 2 - k Combine the k's on the left -2k + 7k + k + 16 = -2 6k + 16 = -2 Subtract 16 from both sides 6k = -2 - 16 6k = -18 k = -18/6 k = -3 : : Check solution in the original equation -2(-3 - 8) + 7(-3) = -2 -(-3) -2(-11) - 21 = -2 + 3 +22 - 21 = -2 + 3 1 = 1; confirms our solution of k=-3
 Linear_Equations_And_Systems_Word_Problems/654459: One number is 5 greater than another number. If the smaller number is added to twice the larger number, the answer is 28. Find the two numbers. if you can will you give the answer in an equation. thanks so much. -ciara1 solutions Answer 408838 by ankor@dixie-net.com(15652)   on 2012-09-20 20:17:26 (Show Source): You can put this solution on YOUR website!One number is 5 greater than another number. If the smaller number is added to twice the larger number, the answer is 28. Find the two numbers. : Let a = one number let b = another number : Write an equation for each statement: "One number is 5 greater than another number." a = b+5 : "If the smaller number is added to twice the larger number, the answer is 28." b + 2a = 28 : Replace a with (b+5), from the 1st statement b + 2(b+5) = 28 b + 2b + 10 = 28 3b = 28 - 10 3b = 18 b = 18/3 b = 6 I'll let you find a : Check the solutions in the 2nd statement
 Exponents-negative-and-fractional/654328: See I'm trying to help my son who's always been in special ed in elementary and has had one on one help on his math and reading. So now that he's in jr. high it hard for him, and for me to couse I don't know how to do this kind of math myself. Here's one of the problems 3.5 divided by -4 1 solutions Answer 408830 by ankor@dixie-net.com(15652)   on 2012-09-20 18:41:21 (Show Source): You can put this solution on YOUR website! See I'm trying to help my son who's always been in special ed in elementary and has had one on one help on his math and reading. So now that he's in jr. high it hard for him, and for me to couse I don't know how to do this kind of math myself. Here's one of the problems 3.5 divided by -4 : You have to use long division here, place the decimal in the answer above the number you are dividing When a positive number is divided by a negative number the answer will always, be negative. Add some zeros to 3.5 : using periods here to keep things lined up : ..... -0.875 .......------- -4 |3.5000 .........32 ........---- 4 goes into 35, 8 times with a remainder of 3, bring down the 0 ...........30 ...........28 ...........---- 4 goes into 30, 7 times with a remainder of 2, bring down the 0 ............20 ............20 ............---- 4 goes into 20, exactly 5 times, no remainder, so we're done : : you can check this on your calc, enter -.875 * -4, results: 3.5
 test/654565: hello my name is malik im 14 years old and i need help with my algebra im taking 1a advance and need a tutor fast. thank you1 solutions Answer 408800 by ankor@dixie-net.com(15652)   on 2012-09-20 17:04:48 (Show Source): You can put this solution on YOUR website!On this site you have to submit an actual problem, as accurately as possible You can request a step-by-step solution which will give the knowledge to do other similar problems. Some tutors will give you individual help. Click on "our tutors" to see which ones will do this.
 Linear-systems/654507: i need help with problems like this. i know it says only one problem per submission but i cant figure out how to ask another question. i have tried to solve these two problems but they are extremely difficult for me and i cant find any good examples anywhere else. please help :( thanks _______________________________________________________________________________ a restaurant manager bought 80 lb of hamburger and 30 lb of steak for a total cost of 163 a second purchase at the same prices includes 150 lb of hamburger and 50 lb of steak and costs 290 find price of 1 lb of hamburger __________________________________________________________________________________ a coin bank contains only dimes and quarters the total value is 3.70. if the dimes were quarters and the quarters were dimes the total value would be 2.95 find the number of quarters _______________________________________________________________________________1 solutions Answer 408795 by ankor@dixie-net.com(15652)   on 2012-09-20 17:00:02 (Show Source): You can put this solution on YOUR website!a restaurant manager bought 80 lb of hamburger and 30 lb of steak for a total cost of 163 a second purchase at the same prices includes 150 lb of hamburger and 50 lb of steak and costs 290 find price of 1 lb of hamburger : let h = cost per pound for hamburger let s = cost per pound for steak : Write a total cost equation for each order 80h + 30s = 163 150h + 50s = 290 : We are going to us elimination; mult the 1st eq by 5, the 2nd eq by 3, results: 400h + 150s = 815 450h + 150s = 870 ------------------subtraction eliminates s, find h -50h + 0 = -55 h = -55/-50 h = \$1.10 a pound for hamburger __________________________________________________________________________ a coin bank contains only dimes and quarters the total value is 3.70. if the dimes were quarters and the quarters were dimes the total value would be 2.95 find the number of quarters : Let x = original number of dimes Let y = original number of quarters : Write an equation for each scenario .10x + .25y = 3.70 .25x + .10y = 2.95 : Using elimination again, mult the 1st equation by 5, the 2nd eq by 2 .50x + 1.25y = 18.50 .50x + .20y = 5.90 -------------------subtraction eliminates x, find y (quarters) 0 + 1.05y = 12.60 y = 12.6/1.05 y = 12 quarters : You should check both these problems by finding the other variable value. Then substitute the values in the original equations, to see if it is true.
 Linear-equations/654493: Find the value of k so that the line containing the points (-4,k) and (8,-4) is perpendicular to the line y=2/5x+4. If you could explain how I should start this problem. I thought if it is perpendicular I would use the opposite reciprocol, but considering I have an unknown variable(k) not quite sure what to do with it. Thanks for your time! 1 solutions Answer 408751 by ankor@dixie-net.com(15652)   on 2012-09-20 14:26:20 (Show Source): You can put this solution on YOUR website!Find the value of k so that the line containing the points (-4,k) and (8,-4) is perpendicular to the line y=2/5x+4. : The slope of the given equation: m1 = Find the slope (m2) of the given coordinates The slope formula m = Assign the values as follows x1=-4, y1=k x2=8, y2=-4 m2 = = : We know the slope relationship between perpendicular lines is m1*m2 = -1 * = -1 cancel 2 into 12 * = -1 = -1 multiply both sides by -30, also gets rid of all those negatives 4 + k = 30 k = 30 - 4 k = 26 : Use this value for y1, find the slope (m2) of the new equation, Find the equation using the point/slope formula, y-y1 = m(x-x1) See that it is perpendicular to y = x + 4
 Mixture_Word_Problems/654384: how many gallons of 40% cream must be added to 10 gallons of 4.5% milk to make it into a mixture containing 18% fat?1 solutions Answer 408748 by ankor@dixie-net.com(15652)   on 2012-09-20 13:31:44 (Show Source): You can put this solution on YOUR website!how many gallons of 40% cream must be added to 10 gallons of 4.5% milk to make it into a mixture containing 18% fat? : Let x = amt of 40% cream required : An amt of fat equation .40x + .045(10) = .18(x+10) .40x + .45 = .18x + 1.8 .40x - .18x = 1.8 - .45 .22x = 1.35 x = 1.35/.22 x ~ 6.136 gallons of cream
 Polynomials-and-rational-expressions/654179: whats 7 over 4y plus 3 over 4y minus 2 over 4y? reduced answers to lowest terms.1 solutions Answer 408638 by ankor@dixie-net.com(15652)   on 2012-09-19 20:52:53 (Show Source): You can put this solution on YOUR website!All fractions have the same denominator, just to the math with the numerators. Then cancel the 4 into the 8 = =
 Average/654170: How would I calculate what the pieces per hour are if I had 2097 pieces produced with 9 people working for 2 hours (120 min)1 solutions Answer 408636 by ankor@dixie-net.com(15652)   on 2012-09-19 20:28:50 (Show Source): You can put this solution on YOUR website! How would I calculate what the pieces per hour are if I had 2097 pieces produced with 9 people working for 2 hours (120 min) : If you want pieces per hr per man, you can use man-hrs 9 * 2 = 18 man-hrs to produce 2097 pieces : ~ 117 per hr per man
 Travel_Word_Problems/653988: Two trains 500 miles apart accidentally are on the same track heading toward each other. The passenger train is traveling 80mph while the frieght train is traveling 40mph. a dispatcher discover the error and warns them 1 minute before they collide. how far apart were they when they were warned?1 solutions Answer 408565 by ankor@dixie-net.com(15652)   on 2012-09-19 16:37:06 (Show Source): You can put this solution on YOUR website!Two trains 500 miles apart accidentally are on the same track heading toward each other. The passenger train is traveling 80mph while the freight train is traveling 40mph. a dispatcher discover the error and warns them 1 minute before they collide. how far apart were they when they were warned? : Objects going toward each other the effective speed is their sum 80 + 40 = 120 mph : How far will be traveled in 1 minute at 120 mph? (hr) : Dist = *120 = 2 miles
 Mixture_Word_Problems/653926: A chemist needs 160 milliliters of a 36% solution but has only 24% and 72% solutions available. Find how many milliliters of each that should be mixed to get the desired solution. A) 40 ml of 24%; 120 ml of 72% B) 123 ml of 24%; 40 ml of 72% C) 120 ml of 24%; 40 ml of 72% D) 123 ml of 24%; 37 ml of 72%1 solutions Answer 408564 by ankor@dixie-net.com(15652)   on 2012-09-19 16:28:10 (Show Source): You can put this solution on YOUR website!A chemist needs 160 milliliters of a 36% solution but has only 24% and 72% solutions available. Find how many milliliters of each that should be mixed to get the desired solution. : Let x = amt of 72% solution required The resulting amt is to be 16 ml, therefore (160-x) = amt of 24% solution : A typical mixture equation using the decimal equiv of per cent : .72x + .24(160-x) = .36(160) .72x + 38.4 - .24x = 57.6 .72x - .24x = 57.6 - 38.4 .48x = 19.2 x = 19.2/.48 x = 40 ml of 72% solution required : I'll let you find the amt of 24% required
 Numeric_Fractions/653684: how to write a negative mixed # such as: 19 3/7- 8 4/5= 1 solutions Answer 408554 by ankor@dixie-net.com(15652)   on 2012-09-19 14:59:31 (Show Source): You can put this solution on YOUR website! how to write a negative mixed # such as: 19 3/7- 8 4/5= The two fractions have to have the same denominator, change to 35th 3/7 = 15/35 4/5 = 28/35 : 19 -8 --------- : the top numerator is smaller than the bottom numerator, we have to borrow one from 19, in the form of 35/35th, add to the existing fraction, we have 18 -8 --------- easy subtraction now 10
 Miscellaneous_Word_Problems/653849: A classroom contains an equal number of boys and girls. If 8 girls leave, twice as many boys as girls remain. What was the original number of students present?1 solutions Answer 408545 by ankor@dixie-net.com(15652)   on 2012-09-19 14:29:18 (Show Source): You can put this solution on YOUR website!Write an equation for each statement: : A classroom contains an equal number of boys and girls. b = g : If 8 girls leave, twice as many boys as girls remain. b = 2(g-8) Replace g with b b = 2(b-8) b = 2b - 16 16 = 2b - b b = 16 boys, then 16 girls originally : What was the original number of students present? 32, obviously :
 Quadratic_Equations/653770: The sum of the digits of a two-digit number is 8. The number obtained by interchanging the two digits exceeds the given number by 36. Find the number.1 solutions Answer 408515 by ankor@dixie-net.com(15652)   on 2012-09-19 11:06:24 (Show Source): You can put this solution on YOUR website!Let x = the 10's digit Let y = the units then 10x+y = the two digit number : Write an equation for each statement : The sum of the digits of a two-digit number is 8 x + y = 8 : The number obtained by interchanging the two digits exceeds the given number by 36. interchanged = original + 36 10y + x = 10x + y + 36 Combine like terms on the left: 10y - y - 10x + x = 36 9y - 9x = 36 simplify, divide by 9 y - x = 4 : Use elimination with the 1st equation y - x = 4 y + x = 8 -----------adding eliminates x, find y 2y = 12 y = 6 You can finish this problem now I am sure
 Equations/653450: Please i need help doing this step by step. The question asks me to solve the following equation in terms of "y" R(x+y)=xy 1 solutions Answer 408420 by ankor@dixie-net.com(15652)   on 2012-09-18 19:34:57 (Show Source): You can put this solution on YOUR website!solve the following equation in terms of "y" R(x+y) = xy multiply what's inside the brackets Rx + Ry = xy Subtract Rx from both sides, subtract xy from both sides and you have: Ry - xy = -Rx Factor out y y(R-x) = -Rx Divide both sides by (R-x) y =
 Numeric_Fractions/653373: Can you please break down step by step the problem? I am unfamiliar with algebra and would like to learn how to do it rather than simply 'cheat' through my class. Thank you so much for your help M2+2M-24 ---------- M2-3M 1 solutions Answer 408372 by ankor@dixie-net.com(15652)   on 2012-09-18 16:50:46 (Show Source): You can put this solution on YOUR website!Assume the problem is: : You should be able to recognize you can factor M^2 + 2M - 24, See factors of 24 that have difference of +2, therefore the larger is positive Now in the denominator, you can factor out M But that is about all you can do with it
 Miscellaneous_Word_Problems/653214: i need the formula for this problem i need to fill a number of containers with a mix that is 3 cubic feet of a to 1 cubic foot b. the containers are .668 cubic feet in volume. i need to know how much of each thing i need to buy to fill 247 containers. the items only come in 2.5 cubic foot amounts for part a and 1 cubic foot of part b. i understand the total volume but how to i get from total volumes to how much of each thing?1 solutions Answer 408367 by ankor@dixie-net.com(15652)   on 2012-09-18 16:36:11 (Show Source): You can put this solution on YOUR website! i need the formula for this problem i need to fill a number of containers with a mix that is 3 cubic feet of a to 1 cubic foot b. the containers are .668 cubic feet in volume. i need to know how much of each thing i need to buy to fill 247 containers. the items only come in 2.5 cubic foot amounts for part a and 1 cubic foot of part b. i understand the total volume but how to i get from total volumes to how much of each thing? : Find the total volume required: .668 * 247 ~ 165 cu/ft : Let x = the multiplier, then 1x = amt of b 3x = amt of a : 1x + 3x = 165 4x = 165 x = 165/4 x = 41.25 is multiplier then Mixture b = 41.25 cu/ft required Mixture a = 3(41.25) = 123.75 cu/ft required : Find no. of containers of each b = 41.25 ~ 42 containers and a = 123.75/2.5 = 49.5 ~ 50 containers
 Rate-of-work-word-problems/653004: Together Bill and Fred working at the same rate rake a yard in an hour and a half. If three of their friends had joined them at the start and also worked at the rate, it would have taken them ___ minutes for the five of them to rake the yard. 1 solutions Answer 408342 by ankor@dixie-net.com(15652)   on 2012-09-18 15:20:08 (Show Source): You can put this solution on YOUR website!Together Bill and Fred working at the same rate rake a yard in an hour and a half. If three of their friends had joined them at the start and also worked at the rate, it would have taken them ___ minutes for the five of them to rake the yard. : let the completed job = 1 Find the rate (r) using Bill and Fred : + = 1 Multiply by r 1.5 + 1.5 = r r = 3 hrs for one man to do the job : Let t = time required for 5 to do it : + + + + = 1 = 1 5t = 3 t = 3/5 * 60 min = 36 min when all 5 do the job
 Mixture_Word_Problems/653234: a 3% salt solution is mixed with a 9% salt solution. how many grams of the 9% salt solution were used to make 150 g of a 4% salt solution? _________________________________________________________________________________ I don't know where to start in order to solve this. There will be 2 questions like this on my test on Thursday and I have a lot of trouble figuring out how to solve these. Do you have any tips or tricks for how to get equations out of word problems? It is very confusing for me, and my teacher isn't very good at explaining anything. :/ Thank you very much!1 solutions Answer 408315 by ankor@dixie-net.com(15652)   on 2012-09-18 13:47:04 (Show Source): You can put this solution on YOUR website!a 3% salt solution is mixed with a 9% salt solution. how many grams of the 9% salt solution were used to make 150 g of a 4% salt solution? : We convert the per cent to the decimal equiv. In this case we write a amt of salt equation, the amt of salt of the two solutions, equal amt in the resulting solution : Let x = grams of 9% solution required the result will be 150 grams, therefore (150-x) = grams of 3% solution : .09x + .03(150-x) = .04(150) .09x + 4.5 - .03x = 6 .09x - .03x = 6 - 4.5 .06x = 1.5 x = 1.5/.06 x = 25 grams of 9% solution required, which is what they asked then we would like to know 150 - 25 = 125 grams of 3% solution : : We can confirm this solution by finding the actual amt of salt in each solution, see if it adds up to the amt of salt in the resulting solution .09(25) + .03(125) = .04(150) 2.25 + 3.75 = 6; proves we have good answer : : This is a typical mixture equation, can be applied to most mixture problems. Always a good idea, when you get the answer, to check it as we did here. : Did this help you understand? C
 Complex_Numbers/652519: It takes Denis 3 hrs longer than Rolly to complete a certain job. Working together, both can complete the job in 2 hrs. How long does it take each person to complete the job working alone?1 solutions Answer 408175 by ankor@dixie-net.com(15652)   on 2012-09-17 20:53:09 (Show Source): You can put this solution on YOUR website! It takes Denis 3 hrs longer than Rolly to complete a certain job. Working together, both can complete the job in 2 hrs. How long does it take each person to complete the job working alone? : let r = time required by Rolly alone then (r+3) = time required by Denis : Let the completed job = 1 : A shared work equation : + = 1 multiply by r(r+3), results 2(r+3) + 2r = r(r+3) : 2r + 6 + 2r = r^2 + 3r Combine like terms on the right 0 = r^2 + 3r - 2r - 2r - 6 A quadratic equation r^2 - r - 6 = 0 Factors to (r-3)(r+2) = 0 the positive solution r = 3 hrs, Rolly working alone then 3 + = 6 hrs, Denis working alone : : Check this 2/3 + 2/6 = 1
 Geometry_Word_Problems/652470: an open-top box with a square base is to have a volume of 900 cubic feet.express the surface area of the box as a function of the length of one of the sides of the base?1 solutions Answer 408028 by ankor@dixie-net.com(15652)   on 2012-09-17 13:00:16 (Show Source): You can put this solution on YOUR website!an open-top box with a square base is to have a volume of 900 cubic feet. express the surface area of the box as a function of the length of one of the sides of the base? : let x = length of one side of the base let h = the height of the box : Find h in terms of x x^2 * h = 900 cu ft h = : Surface area: SA = x^2 + 4(xh) replace h with SA = x^2 + 4(x*) Cancel x SA = x^2 + 4() SA = x^2 +
 Complex_Numbers/652468: 51 = 72 – 3x1 solutions Answer 408027 by ankor@dixie-net.com(15652)   on 2012-09-17 12:44:18 (Show Source): You can put this solution on YOUR website! 51 = 72 – 3x add 3x to both sides 3x + 51 = 72 subtract 51 from both sides 3x = 72 - 51 3x = 21 divide both sides by 3 x = 21/3 x = 7 : Check solution in original problem 51 = 72 - 3(7) 51 = 72 - 21
 Graphs/652474: HOW DO I USE THE ELIMINATION METHOD TO SOLVE THE SYSTEM OF EQUATIONS a+6b=1 a+2b+-3 what is the ordered pair1 solutions Answer 408026 by ankor@dixie-net.com(15652)   on 2012-09-17 12:40:20 (Show Source): You can put this solution on YOUR website!a + 6b = 1 a + 2b = -3 --------------subtraction eliminates a, find b 4b = 4 b = 1 Find a a + 6(1) = 1 a = 1 -6 a = -5 : The ordered pair, -5, 1
 Travel_Word_Problems/652433: Please help me solve this. I first got 27 but i then tried the equation and got 44. But i have a feeling im doing it incorrectly. a driver travels 30 miles to the gym at a constant speed and travels the same distance home at a constant speed. his speed on the return trip was sixteen miles per hour faster, and the total time for both trips was two hours. find his speed on the way to the gym.1 solutions Answer 407992 by ankor@dixie-net.com(15652)   on 2012-09-16 22:37:57 (Show Source): You can put this solution on YOUR website!a driver travels 30 miles to the gym at a constant speed and travels the same distance home at a constant speed. his speed on the return trip was sixteen miles per hour faster, and the total time for both trips was two hours. find his speed on the way to the gym. : Here is the equation you want let s = his speed on the way to the gym then (s+16) = his speed returning : Write a time equation time = dist/speed : Time there + time back = 2 hrs + = 2 multiply by s(s+16) to clear the denominators, you will get a quadratic equation to solve
 Linear-systems/652418: factor by completing the square. please show how the work is done. I can get the answer but do not know how to work the problem. Thank you. x^2+3x-1=01 solutions Answer 407991 by ankor@dixie-net.com(15652)   on 2012-09-16 22:31:39 (Show Source): You can put this solution on YOUR website!x^2 + 3x - 1 = 0 add 1 to each side x^2 + 3x + ___ = 1 Fill in the blank with a value that will complete the square To find this value, divide the coefficient of x by 2 and square it = 2.25, therefore we add 2.25 to both sides x^2 + 3x + 2.25 = 1 + 2.25 x^2 + 3x + 2.25 = 3.25 : This square factors to (x + 1.5)^2 = 3.25 : Find the square root of both sides x + 1.5 = +/- : Subtract 1.5 from both sides, two solutions x = -1.5 + and x = -1.5 -
 Percentage-and-ratio-word-problems/652371: D= 1/5 fk (solve for f)1 solutions Answer 407990 by ankor@dixie-net.com(15652)   on 2012-09-16 22:18:09 (Show Source): You can put this solution on YOUR website!D = 1/5 fk (solve for f) multiply both sides by 5 5D = fk Divide both sides by k = f
 Numbers_Word_Problems/652352: Luke wants to travel 1,000 miles on an adult tricycle and has two spare tires. However, he wants to use all five tires equally over the course of the trip. Because he is riding a tricycle he can only ride three at a time. At the end of the trip. How many miles will each tire have been used?1 solutions Answer 407985 by ankor@dixie-net.com(15652)   on 2012-09-16 21:56:28 (Show Source): You can put this solution on YOUR website!Luke wants to travel 1,000 miles on an adult tricycle and has two spare tires. However, he wants to use all five tires equally over the course of the trip. Because he is riding a tricycle he can only ride three at a time. At the end of the trip. How many miles will each tire have been used? : I am going to say 3/5 * 1000 = 600 mi per tire, or 3000 tire-miles divided by 5, also gives 600 mi per tire.: To rotate the tires: replace tire 1 with tire 4 after 400 mi, tire 1 has 200 mi left on it replace tire 2 with tire 5 after 400 mi, tire 2 has 200 mi left on it replace tire 3 with tire 1 after 600 mi, at 800 mi replace tire 1 with tire 2
 Exponents/652291: Hi. I am an 8th grader in an honors math class. Right now I have below a 70 and have to atleast have an 80 To stay in the class. My final dates are oct, 1&2. I understand all of the material but when we take test or quizzes I either make lots of dumb mistakes or freak out and get it wrong. Any advice?1 solutions Answer 407968 by ankor@dixie-net.com(15652)   on 2012-09-16 20:53:02 (Show Source): You can put this solution on YOUR website!One of the things that you can do with equations in algebra, is check your answer in the original problem, for instance if you get x = 4, replace x in the original problem with 4 and see if equality is preserved, (right side value = left side value.) Do this for every equation problem that you have, both homework and in the final. You will find math mistakes and other errors this way. : If the problem is not an equation, an expression that you must simplify, then assign a value (like 2) to the variables in the original expression, find the value. Do the same with your simplified expression, they should be equal : Sometimes assigning a value of 2 will cause you to have a 0 in the denominator; This of course is not allowed. Then assign another value like 3 and do the same thing
 Travel_Word_Problems/652094: A stream with a velocity of 1/4 mile per hour can move coarse sand particles about 0.02 inch in diameter. Approximate the velocity required to carry particles 0.12 inch in diameter. Use the fact that the diameter of the largest particle that can be moved by a stream varies approximately directly as the square of the velocity of the stream. 1 solutions Answer 407952 by ankor@dixie-net.com(15652)   on 2012-09-16 20:02:17 (Show Source): You can put this solution on YOUR website!A stream with a velocity of 1/4 mile per hour can move coarse sand particles about 0.02 inch in diameter. Approximate the velocity required to carry particles 0.12 inch in diameter. Use the fact that the diameter of the largest particle that can be moved by a stream varies approximately directly as the square of the velocity of the stream. : let v = velocity of the stream; change 1/4 to .25 : Write a proportion equation = = 6 v = v = .612 mph
 Travel_Word_Problems/651801: An aircraft carrier left the Pier 53 and traveled north. An container ship left 1 hour later traveling at 3km/h faster in an effort to catch up to the aircraft carrier. After traveling for 5 hours the container ship finally caught up. What was the aircraft carrier's average speed?1 solutions Answer 407843 by ankor@dixie-net.com(15652)   on 2012-09-15 21:27:58 (Show Source): You can put this solution on YOUR website!An aircraft carrier left the Pier 53 and traveled north. A container ship left 1 hour later traveling at 3km/h faster in an effort to catch up to the aircraft carrier. After traveling for 5 hours the container ship finally caught up. What was the aircraft carrier's average speed? : Let s = the carrier's speed then (s+3) = container ship's speed : When the container catches the carrier, they will have traveled the same dist Write a dist equation; dist = time * speed The carrier traveled for 1 hr longer, 6 hrs 6s = 5(s+3) 6s = 5s + 15 6s - 5s = 15 s = 15 km/hr is the carrier speed : : Check this by finding the distances Carrier: 6(15) = 90 km Container: 5(18) = 90 km