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# Recent problems solved by 'ankor@dixie-net.com'

 Linear-equations/189767: Find an equation of the line having the given slope and containing the given point. m=-9,(2,4) 1 solutions Answer 142457 by ankor@dixie-net.com(18980)   on 2009-04-06 18:09:14 (Show Source): You can put this solution on YOUR website! Find an equation of the line having the given slope and containing the given point. m=-9,(2,4) : Using the point/slope formula: y - y1 = m(x - x1) y - 4 = -9(x - 2) y - 4 = -9x + 18 y = -9x + 18 + 4 y = -9x + 22
 Linear-equations/189768: Find an equation of the line containing the given pair of points. (1,2) and (3,3) 1 solutions Answer 142456 by ankor@dixie-net.com(18980)   on 2009-04-06 18:01:38 (Show Source): You can put this solution on YOUR website! Find an equation of the line containing the given pair of points. (1,2) and (3,3) : Assign the given coordinates as follows: x1=1; y1=2 x2=3; y2=3 : Find the slope (m) using the slope formula: m = : m = = : Use the point/slope formula: y - y1 = m(x - x1) y - 2 = (x - 1) y - 2 = x - y = x - + 2 y = x - + y = x +
 Rational-functions/189742: This question is from textbook saxon algebra 2 Identify any excluded values. Then simplify the expression. 9x^2-3x over 27(3x-1)^2 1 solutions Answer 142450 by ankor@dixie-net.com(18980)   on 2009-04-06 17:02:31 (Show Source): You can put this solution on YOUR website! 9x^2-3x over 27(3x-1)^2 : : Excluded values for x are those that cause the denominator to equal 0 27(3x-1)^2 = 0 which is 27(3x-1)(3x-1) = 0 we can ignore the 27 here 3x = +1 x = is an excluded value : to simplify: = cancel 3: Cancel(3x-1)
 Rate-of-work-word-problems/189821: The radiator in a certain make of car needs to contain 30 liters of 40% antifreeze. The radiator now contains 30 liters of 20% antifreeze. How many liters of this solution must be drained and replaced with 100% antifreeeze to get the desired strength? 1 solutions Answer 142416 by ankor@dixie-net.com(18980)   on 2009-04-06 14:05:43 (Show Source): You can put this solution on YOUR website! The radiator in a certain make of car needs to contain 30 liters of 40% antifreeze. The radiator now contains 30 liters of 20% antifreeze. How many liters of this solution must be drained and replaced with 100% antifreeze to get the desired strength? : Let x = amt of 20% solution to be drained, and also amt of 100% to be added : .2(30-x) + 1.0(x) = .4(30) 6 - .2x + 1x = 12 -.2x + 1x = 12 - 6 .8x = 6 x = x = 7.5 liters to be removed and replaced ; : Check solution in original equation .2(30-7.5) + 7.5 = .4(30) .2(22.5) + 7.5 = 12 4.5 + 7.5 = 12
 Polynomials-and-rational-expressions/189608: Can you please help me solve this? I have to solve for all roots. 1 solutions Answer 142285 by ankor@dixie-net.com(18980)   on 2009-04-05 09:51:23 (Show Source): You can put this solution on YOUR website! Factor out 2x, difference of cubes real roots x = 0 x = 2
 Quadratic_Equations/189595: This question is from textbook saxon algebra 2 Graph y is greater than or equal to -2x^2+2x+4. I got as far as: x=-b/2a-2/2(-2) I need help, please! 1 solutions Answer 142266 by ankor@dixie-net.com(18980)   on 2009-04-04 21:44:28 (Show Source): You can put this solution on YOUR website! Graph y is greater than or equal to -2x^2+2x+4. : The graph: : Area of feasibility: at or above the graph
 Geometry_Word_Problems/189577: The amount of paint needed to cover the walls of a room varies jointly as the perimeter of the room and the height of the wall. If a room with a perimeter of 45 feet and 6 foot high walls requires 3 quarts of paint, find the amount of paint needed to cover the walls of two rooms that each have a perimeter of 35 feet and 6-foot high walls. How many quarts are needed ( round up to the nearest quart). 1 solutions Answer 142265 by ankor@dixie-net.com(18980)   on 2009-04-04 21:35:35 (Show Source): You can put this solution on YOUR website! The amount of paint needed to cover the walls of a room varies jointly as the perimeter of the room and the height of the wall. If a room with a perimeter of 45 feet and 6 foot high walls requires 3 quarts of paint, : Find the area of this room: 45 * 6 = 270 sq/ft : find the amount of paint needed to cover the walls of two rooms that each have a perimeter of 35 feet and 6-foot high walls. : Find the area of these two room: 2 * 35 * 6 = 420 sq/ft : How many quarts are needed ( round up to the nearest quart). : Let x = no. of quarts needed: = cross multiply 270x = 420 * 3 x = x = 4.67 ~ 5 quarts required
 Inequalities/189576: This question is from textbook Elementary and Intermediate Algebra In 1978 Udo Beyer (East Germany) set a world record in the shot-put of 72 ft 8 in. If Beyer had projected the shot straight upward with a velocity of 30 ft/sec from a height of 5 ft, then for what values of t would the shot be under 15 ft high? 1 solutions Answer 142263 by ankor@dixie-net.com(18980)   on 2009-04-04 21:21:03 (Show Source): You can put this solution on YOUR website! In 1978 Udo Beyer (East Germany) set a world record in the shot-put of 72 ft 8 in. If Beyer had projected the shot straight upward with a velocity of 30 ft/sec from a height of 5 ft, then for what values of t would the shot be under 15 ft high? : Gravity: -16t^2, upward velocity 30t, initial height: 5'; gives us an equation of: : h = -16t^2 + 30t + 5 : " for what values of t would the shot be under 15 ft high?" -16t^2 + 30t + 5 < 15 : -16t^2 + 30t + 5 - 15 = 0 : -16t^2 + 30t - 10 = 0 Solve this using the quadratic formula: a=-16; b=30; c=-10 : You should get two solutions t ~ .43 sec t ~ 1.44 sec : We can say that shot-put was below 15 ft from 0 to .43 sec and it was below 15 ft from 1.44 sec until it hit the ground Find out when it hit the ground (h=0) using the equation -16t^2 + 30t + 5 = 0 ; Use a graph for this, green line represents 15 ft; time (t) on the x axis: It was below 15 ft from 1.44 sec to approx 2 sec when it hit the ground : : did this make sense to you?
 Proportions/189548: The difference between the prices of a coach ticket and a first class ticket is \$135. If the first class ticket is 175% of the cost of a coach ticket what is the cost of the coach ticket? 1 solutions Answer 142237 by ankor@dixie-net.com(18980)   on 2009-04-04 15:33:43 (Show Source): You can put this solution on YOUR website! The difference between the prices of a coach ticket and a first class ticket is \$135. If the first class ticket is 175% of the cost of a coach ticket what is the cost of the coach ticket? : Let x = cost of a coach ticket then (x+135) = cost of 1st class ticket : Change 175% to decimal, namely, 1.75: : 1.75x = x + 135 : 1.75x - x = 135 : .75x = 135 x = x = \$180 is the coach fare :
 Linear-equations/189472: From a base elevation of 8400ft a mountain peak in Colorado rises to a summit elevation of 14856 over a horizontal distance of 15849ft, find the grade. I am having trouble determining how to set this equation up. 1 solutions Answer 142186 by ankor@dixie-net.com(18980)   on 2009-04-03 21:18:03 (Show Source): You can put this solution on YOUR website! From a base elevation of 8400ft a mountain peak in Colorado rises to a summit elevation of 14856 over a horizontal distance of 15849ft, find the grade. I am having trouble determining how to set this equation up. : Find the height of the mountain from the base: 14856 - 8400 = 6456 ft : % grade = * 100 = 40.7% grade
 Expressions-with-variables/189485: Divide Rs 12,540 in A B and C so that A may receive 3/7 of B and C, and B receive 2/9 of A and C. 1 solutions Answer 142164 by ankor@dixie-net.com(18980)   on 2009-04-03 17:02:39 (Show Source): You can put this solution on YOUR website! Divide Rs 12,540 in A B and C so that A may receive 3/7 of B and C, and B receive 2/9 of A and C. : Write an equation for each and arrange in a standard integer form : "12,540 in A B and C" a + b + c = 12540 : "that A may receive 3/7 of B and C," a = (b + c) multiply both sides by 7 7a = 3(b + c) 7a = 3b + 3c 7a - 3b - 3c = 0 : " and B receive 2/9 of A and C." b = (a + c) multiply both sides by 9 9b = 2(a + c) 9b = 2a + 2c -2a + 9b - 2c = 0 : Multiply the 1st equation by 2 and add to the above equation -2a + 9b - 2c = 0 2a + 2b + 2c = 25080 ------------------------adding eliminates a & c, find b 11b = 25080 b = b = 2280 : Multiply the 1st equation by 3 and add to the 2nd equation: 3a + 3b + 3c = 37620 7a - 3b - 3c = 0 --------------------addition eliminates b & c, find a 10a = 37620 a = a = 3762 ; Find c: 3762 + 2280 + c = 12540 c = 12540 - 6042 c = 6498 : Check solution using a = (b + c) a = (2280 + 6498) a = (8778) a = 3762 as we got above : You can check the solutions in the other equations
 Polynomials-and-rational-expressions/189455: I need to have a couple of examples of how rational expressions are used both at home and at work. I am totally lost as to how these would be used at home, could you please offer me some help? 1 solutions Answer 142161 by ankor@dixie-net.com(18980)   on 2009-04-03 15:54:49 (Show Source): You can put this solution on YOUR website! One could involve your cell phone bill: Where the monthly fee was \$30 with the 1st 60 min free, then .25 per min. m = no. of minutes Cost = .25(m - 60) + 30 : How about a parking lot garage: where the 1st hr = \$5 and \$3 every hour after that where t = no. of hours you parked Cost = 3(t-1) + 5
 Linear_Equations_And_Systems_Word_Problems/189486: a doctor's prescription calls for the creation of pills that contain 12 units of vitamin B12 and 12 units of vitamin E. Your pharmacy stocks two powders that can be used to make these pills: one contains 20% vitamin B12 and 30% vitamin E, the other 40% vitamin B12 and 20% vitamin E. How many units of each powder should be mixed in each pill? 1 solutions Answer 142160 by ankor@dixie-net.com(18980)   on 2009-04-03 15:43:25 (Show Source): You can put this solution on YOUR website! a doctor's prescription calls for the creation of pills that contain 12 units of vitamin B12 and 12 units of vitamin E. Your pharmacy stocks two powders that can be used to make these pills: one contains 20% vitamin B12 and 30% vitamin E, the other 40% vitamin B12 and 20% vitamin E. How many units of each powder should be mixed in each pill? : Let x = amt of the 1st powder required (20% B12, 30% E) Let y = amt of the 2nd powder required (40% B12, 20% E) : Write an equation for each vitamin: .20x + .40y = 12; (Vit B12) .30x + .20y = 12: (Vit E) : Multiply the 2nd equation by 2, subtract the 1st equation from it: .60x + .40y = 24 .20x + .40y = 12 --------------------subtraction eliminates y, find x .4x = 12 x = x = 30 units of the 1st power : Find y using eq: .2x + .4y = 12 .2(30) + .4y = 12 6 + .4y = 12 .4y = 12 - 6 .4y = 6 y = y = 15 units of the 2nd powder : : Check solution in the 2nd equation .3x + .2y = 12 .3(30) + .2(15) = 9 + 3 = 12
 Polynomials-and-rational-expressions/189481: For problems 18 through 20, the height, h, of a ball t seconds after it is released for a jump shot in a basketball game can be modeled with the equation . 19. State the number of solutions to the problem and state if the ball has a chance of going into the basket. a. There are 2 solutions, meaning 2 times when the ball is 10 ft. high. The time that the ball reaches 10 feet on its way up and on its way down. One of these times will be the ball's opportunity to pass through the hoop. b. The equation does not allow two solutions to the problem. This ball will not reach ten feet. c. The ball reaches ten feet as its maximum height so there is only one solution. 1 solutions Answer 142146 by ankor@dixie-net.com(18980)   on 2009-04-03 14:55:10 (Show Source): You can put this solution on YOUR website! For problems 18 through 20, the height, h, of a ball t seconds after it is released for a jump shot in a basketball game can be modeled with the equation h = -16t^2 + 12t + 8 . : 19. State the number of solutions to the problem and state if the ball has a chance of going into the basket. : a. There are 2 solutions, meaning 2 times when the ball is 10 ft. high. The time that the ball reaches 10 feet on its way up and on its way down. One of these times will be the ball's opportunity to pass through the hoop. -16t^2 + 12t + 8 = 10 -16t^2 + 12t + 8 - 10 = 0 -16t^2 + 12t - 2 = 0 Simplify and change the signs, Divide by -2 8t^2 - 6t + 1 = 0 Factor (4t - 1)(2t - 1) = 0 Two solutions: 4t = 1 t = sec and 2t = 1 t = sec; could just barely pass thru the hoop : : Similar to this graph
 Travel_Word_Problems/189480: This is from a worksheet given by my professor, not from a textbook. Two bicyclists, one averaging 14 mph and one averaging 18 mph, start from the same point. The slower bicyclist arrives at the end of the course a half-hour after the other bicyclist. Find the distance of the ride. Round to the nearest whole mile. 1 solutions Answer 142141 by ankor@dixie-net.com(18980)   on 2009-04-03 13:43:20 (Show Source): You can put this solution on YOUR website! Two bicyclists, one averaging 14 mph and one averaging 18 mph, start from the same point. The slower bicyclist arrives at the end of the course a half-hour after the other bicyclist. Find the distance of the ride. Round to the nearest whole mile. ; Let d = distance of the ride: : Write a time equation; Time = : 14mph biker time = 18mph biker time + one-half hr : = + Multiply equation by 252; (14*18)results: 18d = 14d + 126 : 18d - 14d + 126 : 4d = 126 d = d = 31.5 ~ 32 mi : : Check solution by finding the times of each 31.5/14 = 2.25 31.5/18 = 1.75 ------------- dif = .5 hr
 Volume/189329: This question is from textbook Pre-Algebra I am trying to find the volume of a composite figure. The figure Is a cylinder that is 3 inches in height and 3 inches in length. Attached to one end of the cylinder is a cone which is 2 inches in length. The book wants me to find the volume of the composite figure. The following is what I've tried. V= pi(r)to the power of 2 x H. V= pi (3)to the power of 2 x 3 + 1/2 x 4/3 pi (2) to the power of 3. V= pi (9)(3) + 2/3 pi (8) V= 27 pi + 16.76 pi = 43.76pi. So the answer would of been 43.76 pi. My teacher tells me this is wrong. So, I guess I need a new method for working this problem, and information to help me understand this topic better. Can you help?? Thanks ~Ave 1 solutions Answer 142124 by ankor@dixie-net.com(18980)   on 2009-04-03 08:25:24 (Show Source): You can put this solution on YOUR website! I am trying to find the volume of a composite figure. The figure Is a cylinder that is 3 inches in height and 3 inches in length. Attached to one end of the cylinder is a cone which is 2 inches in length. The book wants me to find the volume of the composite figure. The following is what I've tried. V= pi(r)to the power of 2 x H. V= pi (3)to the power of 2 x 3 + 1/2 x 4/3 pi (2) to the power of 3. V= pi (9)(3) + 2/3 pi (8) V= 27 pi + 16.76 pi = 43.76pi. : Lets see what I get when I attack this problem V = cylinder vol + Cone vol V = + I have to assume that one of those 3" measurements is the diameter, therefore r = 1.5 inches V = + V = 21.20575 + 4.7124 V = 25.9 cu/in : It looks like you got the vol of a sphere instead of the vol of a cone : Did this make sense to you?
 Quadratic_Equations/189349: A farmer has 500 feet of fencing to use to make a rectangular garden. One side of the garden will be a barn, which requires no fencing. How should the pen be built in order to enclose the largest amount of area possible? Give your answer by filling in the blanks in the following sentence: The farmer should build the pen ______ feet away from the barn, and ________ feet wide, for an area of _______ square feet How do I solve this? 1 solutions Answer 142123 by ankor@dixie-net.com(18980)   on 2009-04-03 08:04:38 (Show Source): You can put this solution on YOUR website! A farmer has 500 feet of fencing to use to make a rectangular garden. One side of the garden will be a barn, which requires no fencing. How should the pen be built in order to enclose the largest amount of area possible? : Let L = the length Let x = the width : We only need 3 sides so the perimeter equation would be: L + 2x = 500 L = (500-2x) : Area = x * L Substitute (500-2x) for L A = x(500-2x) A = -2x^2 + 500x : A quadratic equation, we can use the axis of symmetry and vertex to find the maximum area; x = -500/(2*-2) x = -500/-4 x = 125 ft is the width which will give max area : The length: L = 500 - 2(125) L = 250 ft is the length for max area : Find the max area : A = 250 * 125 A = 31,250 sq/ft : I'll let you fill in the blanks "The farmer should build the pen ______ feet away from the barn, and ________ feet wide, for an area of _______ square feet
 Rate-of-work-word-problems/189389: Two pumps can fill a water tank in 45 minutes when working together. Alone, the second pump takes 3 times longer than the first to fill the tank. How long does it take the first pump alone to fill the tank 1 solutions Answer 142095 by ankor@dixie-net.com(18980)   on 2009-04-02 20:10:49 (Show Source): You can put this solution on YOUR website! Two pumps can fill a water tank in 45 minutes when working together. Alone, the second pump takes 3 times longer than the first to fill the tank. How long does it take the first pump alone to fill the tank? : Let x = time required for the first pump to fill the tank alone then 3x = time required for the 2nd pump to do it alone : Write an equation of them working together; let the full tank = 1 Each pump will do a fraction of the job and will equal 1 when added together : + = 1 Multiply equation by 3x, results 3(45) + 45 = 3x : 135 + 45 = 3x : 180 = 3x x = x = 60 min for pump 1 alone : ; Check solution; (2nd pump requires 3*60 = 180 min alone) + = .75 + .25 = 1; confirms our solution
 Exponential-and-logarithmic-functions/189330: Sound: the level of sound V in decibels with an intensity I can be modeled by V= 10log(I/10^-16) Where I is intensity in watts per centimeter. Loud music can have an intensity of 10^-5 watts per centimeter. find the level of sound of loud music 1 solutions Answer 142090 by ankor@dixie-net.com(18980)   on 2009-04-02 19:20:18 (Show Source): You can put this solution on YOUR website! Sound: the level of sound V in decibels with an intensity I can be modeled by V = 10log(I/10^-16) Where I is intensity in watts per centimeter. Loud music can have an intensity of 10^-5 watts per centimeter. find the level of sound of loud music: " V = V = V = Log of 10^11 is 11 : V = 10 * 11 : V = 110 decibels
 Travel_Word_Problems/189326: A rowing team rowing with the current travelled 24 km in 3 hours. Against the current, the team rowed 8 km in 2 hours. Find: a) The rate of the rowing team in calm water and, b) The rate of the current I tried the question and got 6km/h in calm water and 2km/h as the rate of the current. Is that right? 1 solutions Answer 142086 by ankor@dixie-net.com(18980)   on 2009-04-02 19:09:35 (Show Source): You can put this solution on YOUR website! A rowing team rowing with the current travel ed 24 km in 3 hours. Against the current, the team rowed 8 km in 2 hours. Find: Let x = boat speed in calm water Let y = rate of the current : Write two distance equations; Dist = time * speed 3(x + y) = 24; with the current 2(x - y) = 8; against the current : Simplify both equations, divide the 1st by 3 and the 2nd by 2; results x + y = 8 x - y = 4 ------------addition eliminates y 2x = 12 x = x = 6 mph is the boat speed in calm water and x + y = 8 6 + y = 8 y = 8 - 6 y = 2 mph is the speed of the current : which is what you got, way to go!
 Percentage-and-ratio-word-problems/189327: A bag of peanuts is worth #.30 less than a bag of cashews. Equal amount of peanuts and cashews are used to make 40 bags of a miture that sells for 1.05 per bag. How much is a bag of cashews worth? 1 solutions Answer 142066 by ankor@dixie-net.com(18980)   on 2009-04-02 16:49:09 (Show Source): You can put this solution on YOUR website! A bag of peanuts is worth #.30 less than a bag of cashews. Equal amount of peanuts and cashews are used to make 40 bags of a mixture that sells for 1.05 per bag. How much is a bag of cashews worth? : they said equal amts, 20 bags of peanuts and 20 bags of cashews were used to make a 40 bag mixture : Let x = cost of cashews then (x-.30) = cost of peanuts : A simple mixture equation: 20x + 20(x-.3) = 1.05(40) : 20x + 20x - 6 = 42.00 : 40x = 42 + 6 x = x = \$1.20 a bag for cashews : : Check solution (peanuts cost .90) 20(1.2) + 20(.9) = 1.05(40) 24 + 18 = 42
 Polynomials-and-rational-expressions/189277: The additive inverse of a number divided by 16 is the same as 1 less than -5 times its reciprocal. Find the number. 1 solutions Answer 142053 by ankor@dixie-net.com(18980)   on 2009-04-02 15:54:22 (Show Source): You can put this solution on YOUR website! The additive inverse of a number divided by 16 is the same as 1 less than -5 times its reciprocal. Find the number. : Let x = "a number" = -5() - 1 = - 1 multiply equation by -1, get rid of all these negatives: = + 1 Multiply equation by 16x, results: x^2 = 16(5) + 16x : x^2 = 80 + 16x : x^2 -16x - 80 = 0 Factors to: (x-20)(x+4) = 0 : x = +20 x = -4 : : Check solutions in original equation: x=20 = -5() - 1 -1.25 = -.25 - 1 and x=-4 = -5() - 1 +.25 = +1.25 - 1
 Age_Word_Problems/189303: 6 yaers ago the age of father was 6 times the age of son. After 8 years the age of father will be twice the son. What are their present ages? 1 solutions Answer 142047 by ankor@dixie-net.com(18980)   on 2009-04-02 14:26:59 (Show Source): You can put this solution on YOUR website! Let f = father's present age Let s = son's present age : Write an equation for each statement: : 6 years ago the age of father was 6 times the age of son. (f-6) = 6(s-6) f - 6 = 6s - 36 f - 6s = -36 + 6 f - 6s = -30 : After 8 years the age of father will be twice the son. (f+8) = 2(s+8) f + 8 = 2s + 16 f - 2s = 16 - 8 f - 2s = 8 : Use elimination with these two equations: f - 2s = 8 f - 6s = -30 -----------------subtraction eliminates f +4s = 38 s = s = 9.5 yrs is son's present age : Then f - 2(9.5) = 8 f - 19 = 8 f = 27 yrs is father's present age : Usually solution to these problems are integers, however, let's check it: check solution in the the statement: "6 years ago the age of father was 6 times the age of son." (27-6) = 6(9.5-6) 21 = 6(3.5) 21 = 21 and "After 8 years the age of father will be twice the son. " 27 + 8 = 2(9.5 + 8) 35 = 2(17.5) 35 = 35
 Expressions-with-variables/189338: Erum's age is 2/3 that of Zahra's .Two years ago Erum's age was 1/2 of what Zahra's age will be in 5 year's time. How old is Zahra now ? 1 solutions Answer 142045 by ankor@dixie-net.com(18980)   on 2009-04-02 13:34:06 (Show Source): You can put this solution on YOUR website! Let E = Erum's present age Lot Z = Zahra's present age : Write an equation for each statement: ; Erum's age is 2/3 that of Zahra's . E = Z : Two years ago Erum's age was 1/2 of what Zahra's age will be in 5 year's time. (E-2) = (Z+5) : Multiply both sides by 2: 2(E-2) = Z + 5 : 2E - 4 = Z + 5 : 2E = Z + 5 + 4 : 2E = Z + 9 : How old is Zahra now ? : Substitute Z for E in the above equation 2(Z) = Z + 9 Z = Z + 9 Subtract Z from both sides Z - Z = 9 Z = 9 Multiply both sides by 3 Z = 27 yrs is Zahra's age now : The (27) = 18 yrs is Erum's age now : : Check solution in the statement: "Two years ago Erum's age was 1/2 of what Zahra's age will be in 5 year's time." (18-2) = .5(27 + 5)
 Polynomials-and-rational-expressions/189240: Is the answer to 7^x-3 divided by 7^3x-1 = 1/1^2x+2 1 solutions Answer 142042 by ankor@dixie-net.com(18980)   on 2009-04-02 13:15:21 (Show Source): You can put this solution on YOUR website! Is the answer to 7^x-3 divided by 7^3x-1 = 1/1^2x+2 I think it would be
 Rational-functions/189254: This question is from textbook McDougal Littel Algebra 2 Perform the indicated operation. Simplify the result. multiplied by **Work I Tried do** multipled by Thank You... 1 solutions Answer 141980 by ankor@dixie-net.com(18980)   on 2009-04-01 20:24:14 (Show Source): You can put this solution on YOUR website! * : Factor just like you did: * But you can also do this * Cancel our (x-2) and (x+3) leaving: (x+2) * =
 Square-cubic-other-roots/189185: This question is from textbook Structure and Method Book 1 ONE EIGHTH OF THE SQUARE ROOT OF 7 LESS THAN A NUMBER IS 2. WHAT IS THE NUMBER? 1 solutions Answer 141975 by ankor@dixie-net.com(18980)   on 2009-04-01 19:42:21 (Show Source): You can put this solution on YOUR website! ONE EIGHTH OF THE SQUARE ROOT OF 7 LESS THAN A NUMBER IS 2. WHAT IS THE NUMBER? : = 2 : multiply both sides by 8 = 16 : Square both sides, 7 - x = 256 : -x = 256 - 7 : -x = 249 : Multiply both sides by -1 x = -249 : : Check solution in original problem: = 2 = 2 = 2 = 2
 Average/189175: I wrote prior that I can solve this but somehow it gets too much and confused and I am sure I made a mistake somewhere. Can you help me solving this? 9/(x+1) - 2/(x-2) = 5/(x+1) and help me to check all proposed solutions? 1 solutions Answer 141972 by ankor@dixie-net.com(18980)   on 2009-04-01 19:25:59 (Show Source): You can put this solution on YOUR website! - = : Multiply by (x+1)(x-2)* (x+1)(x-2)* - (x+1)(x-2)* = (x+1)(x-2)* Cancel out the denominators and you have; 9(x-2) - 2(x+1) = 5(x-2) : 9x - 18 - 2x - 2 = 5x - 10 : x's on the left numerals on the right 9x - 2x - 5x = -10 + 2 + 18 : 2x = 10 x = x = 5 : : Check solution in original equation - = - = - =
 Graphs/189115: The path of a falling object is given by the function S=-16t^2+v_o t+s_o where represents the initial velocity in ft/sec and represents the initial height in feet. Also, s represents the height in feet of the object at any time, t, which is measured in seconds. If a rock is thrown upward with an initial velocity of 40 feet per second from the top of a 30-foot building, write the height (s) equation using this information. 1 solutions Answer 141941 by ankor@dixie-net.com(18980)   on 2009-04-01 16:17:03 (Show Source): You can put this solution on YOUR website! The path of a falling object is given by the function S=-16t^2+v_o t+s_o where represents the initial velocity in ft/sec and represents the initial height in feet. Also, s represents the height in feet of the object at any time, t, which is measured in seconds. If a rock is thrown upward with an initial velocity of 40 feet per second from the top of a 30-foot building, write the height (s) equation using this information. : S(t) = -16t^2 + 40t + 30 :
 Quadratic-relations-and-conic-sections/189085: The cable for a suspension bridge is shaped like a parabola. The towers are 100 ft tall and 800 ft apart. It touches the roadway at the center. How long are the support cables at 50 ft, 200 ft, and 350 ft from the center? 1 solutions Answer 141920 by ankor@dixie-net.com(18980)   on 2009-04-01 14:33:17 (Show Source): You can put this solution on YOUR website! The cable for a suspension bridge is shaped like a parabola. The towers are 100 ft tall and 800 ft apart. It touches the roadway at the center. : determine the quadratic equation: y = ax^2 + bx + c : From the information given we have 3 coordinates: x=400, y=0; where it touches the roadway in the center x=0, y=100; left tower; this also the y intercept, therefore c = 100 x=800, y=100; right tower : Solve for a & b x=400, y=0 400^2a + 400b + 100 = 0 160000a + 400b = -100 : x=800, y=100 800^2a + 800b + 100 = 100 640000a + 800b = 100 - 100 640000a + 800b = 0 : Multiply the 1st equation by 2 and subtract from the above equation 640000a + 800b = 0 320000a + 800b = -200 -----------------------subtraction eliminates b 320000a = +200 a = a = .000625 : Find be substitute .000625 for a in the 1st equation: 160000(.000625) + 400b = -100 100 + 400b = -100 400b = -100 -100 b = b =-.5 : The equation: y = .000625x^2 - .5x + 100 Plot this graph, looks like what we would expect. : How long are the support cables at 50 ft from the center that means: 400 - 50 = 350; x=350. find y: y = .000625(350^2) - .5(350) + 100 y = .000625(122500) - 175 + 100 y = 1.5625 ft : How long are the support cables at 200 ft from the center that means: 400 - 200 = 200; x=200. find y: y = .000625(200^2) - .5(200) + 100 y = .000625(40000) - 100 + 100 y = 25 ft : How long are the support cables at 350 ft from the center that means: 400 - 350 = 50; x=50. find y: y = .000625(50^2) - .5(50) + 100 y = .000625(2500) - 25 + 100 y = 76.5625 ft
 Polynomials-and-rational-expressions/189087: i need you help.! can you please help me solve this equation?? the length of a rectangle is 3 inches more than its width. If the area of the rectangle is 180 square inches, write an equation for the above situation 1 solutions Answer 141906 by ankor@dixie-net.com(18980)   on 2009-04-01 10:47:43 (Show Source): You can put this solution on YOUR website! the length of a rectangle is 3 inches more than its width. If the area of the rectangle is 180 square inches, write an equation for the above situation : Let x = the width : It says,"the length of a rectangle is 3 inches more than its width." therefore: (x+3) = the length : Area = Length * Width, therefore: A = x * (x+3) A = x^2 + 3x; is the equation : It says, area = 180, therefore: x^2 + 3x = 180 : Subtract 180 from both sides, you have a quadratic equation: x^2 + 3x - 180 = 0 : This will factor to: (x + 15)(x - 12) = 0 : We want the positive solution here: x = + 12 is the width then 12 + 3 = 15 is the length : : Check by finding the area: 12 * 15 = 180