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# Recent problems solved by 'anantha'

 Numbers_Word_Problems/363728: the difference between two numbers is 3. IF the square of the smaller number is equal to 4 times the larger number. find the numbers TWO POSITIVE NUMBERS DIFFER BY 5 AND THE SQUARE OF THEIR SUM IS 169. FIND THE NUMBErs.. 1 solutions Answer 259449 by anantha(86)   on 2010-10-30 04:00:03 (Show Source): You can put this solution on YOUR website!in this problem larger numberbe x and smaller number be y difference between the numbers x-y=3 x-y=3 add y on both sides x-y+y=3+y x=3+y square of the smaller number=4 times the larger number y^2=4*x y^2=4(3+y) y^2=12+4y subtract 12 and 4y on both sides y^2-4y-12=12+4y-12-4y y^2-4y-12=0 on adding -6 and +2 we get -4 and multiplying -6and 2 we get -12 y^2 -4y-12=0 can be written as y^2-6y+2y-12=0 y(y-6)+2(y-6)=0 here 1st two terms y is common term and last two terms 2 is common term now y0--6 is common term (y-6)(y+2)=0 here equating these two terms with zero we get y value y-6=0 adding 6 on both sides y-6+6=0+6 y=6 y+2=0 subtract 2 on both sides y+2-2=0-2 y=-2 here we take only positive values y=6 only now x=3+y=3+6=9 x=9 and y=6 check this problem difference of these two numbers=9-6=3 two positive numbers differ by 5 means here positive numbers are x and y x-y=5 their sum is x+y square of their sum=(x+y)^2 (x+y)^2=169 here 169 can be written as 13^2 (x+y)^2=(13)^2 here powers equal then bases equal x+y=13 and x-y=5 solving these two equations we get x and y values x+y=13 x-y=5 ------- 2x=18 dividing both sides by 2 2x/2=18/2 x=9 x+y=13 9+y=13 subtract 9 on both sides 9+y-9=13-9 y=4 x=9 and y=4 check: x+y=13 9+4=13
 Triangles/363760: find the measure of the third side of the triangle given its 2 sides and perimeter. 1side= 7x^2 + 5x + 9 2side= 8x^2 - 6x + 12 P= 19x^2 + 12x + 35cm please help thank you!1 solutions Answer 259445 by anantha(86)   on 2010-10-30 03:27:55 (Show Source): You can put this solution on YOUR website!in a triangle perimeter= sum of the 3 sides perimeter=1st side+2nd side+3rd side 19x^2+12x+35cm=(7x^2+5x+9)+(8x^2-6x+12)+3rd side here do addition carefully add only like terms means x^2 terms and add xterms and constant terms 19x^2+12x+35=(7x^2+8x^2)+(5x-6x)+(9+12)+3rd side 19x^2+12x+35=15x^2-x+21+3rd side we subtract 15x^2 on both sides 19x^2-15x2+12x+35=(15x^2-15x^2)-x+21+3rd side 4x^2+12x+35=-x+21+3rd side add x on both sides 4x^2+12x+x+35=(-x+x)+21+3rd side 4x^2+13x+35=21+ 3rd side subtract 21 on both sides 4x^2+13x+35-21=(21-21)+ 3rd side 4x^2+13x+14=3rd side
 Percentage-and-ratio-word-problems/280317: If the ratio of 3x - 7y + 4 to 4x + 3y + 12 is 1/3 then the ratio of x to y is A –18/5 b 5/18 c 2 d 24/5 e none of these 1 solutions Answer 203868 by anantha(86)   on 2010-03-13 22:30:42 (Show Source): You can put this solution on YOUR website!sol the ratio of 3x-7y+4 to 4x+3y+12 is 1/3 means (3x-7y+4)/(4x+3y+12)=1/3 on cross multiplication 3*(3x-7y+4)=1*(4x+3y+12) 9x-21y+12=4x+3y+12 for isolating x we subtract both sides by 4x,3y,12 9x-21y+12-4x-3y-12=4x+3y+12-4x-3y-12 5x-24y=0 again add 24y on both sides 5x-24y+24y=0+24y 5x=24y dividing both sides by 5 5x/5=24y/5 x=24y/5 again dividing by y x/y=24y/5y x/y=24/5 the answer is d)
 Volume/279983: a cylindrical is 10 inches high, and the diameter of it's base is 5 inches . what is the volume.1 solutions Answer 203472 by anantha(86)   on 2010-03-11 22:30:14 (Show Source): You can put this solution on YOUR website!sol: cylinder high=10 inches diameter=5 inches radius=diameter/2=5/2=2.5 inches volume of the cylinder= pi*r^2*h v= 22/7*2.5*2.5* 10 v=3.14*2.5*2.5*10=196.43 cubic inches
 Linear-equations/279958: Please help me solve 10x=3y+15. I need the slope and y-intercept1 solutions Answer 203470 by anantha(86)   on 2010-03-11 22:22:56 (Show Source): You can put this solution on YOUR website!sol: the equation of the line is of the form ax+by+c=0 then the slope= -(x coefficient/y coefficient)= -(a/b) x-intercept= -(c/a) y-intercept= -(c/b) now convert the equation is of the form ax+by+c=0 given equation is 10x=3y+15 subtract 3y and 15 on both sides 10x-3y-15=3y+15-3y-15 10x-3y-15=0 now the equation of the form ax+by+c=0 here a=10 ,b= -3, c= -15 slope=-(a/b)= -(10/-3)=-(-10/3)=10/3 (.e;-*-=+) y-intercept=-(c/b)=-(-15/-3)= - (15/3)= -15/3 (i.e;-/-=+, -*+=-) slope=10/3,y-intercept= -15/3
 Linear-equations/279523: Find the slope of the line that passes through the pair of points. (7,-5) (-1,8) 1 solutions Answer 203233 by anantha(86)   on 2010-03-10 23:20:11 (Show Source): You can put this solution on YOUR website!sol: slope of the line passing through the points (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1) slope of the line passing through the points (7,-5) (-1,8) here x1=7,y1=-5,x2=-1,y2=8 slope=(y2-y1)/(x2-x1) slope=(8-(-5))/(-1-7) slope=(8+5)/(-8) slope=13/(-8) slope= - 13/8
 Pythagorean-theorem/279554: Using Pythagorean Theorem, calculate the measure of b, if a = 4 cm. and c = 8 cm. In this case c is the hypotenuse of the right angle triangle.1 solutions Answer 203231 by anantha(86)   on 2010-03-10 23:12:41 (Show Source): You can put this solution on YOUR website!sol: in right angle triangle (hypotenuse)^2=sum of the squares of the remaining two sides this is Pythagorean Theorem in this problem hypotenuse(c)=8cm and one side (a)=4cm then we find the other side using above formula c^2=a^2+b^2 8^2=4^2+b^2 64=16+b^2 subtract 16 on both sides 64-16=16-16+b^2 48=b^2 b= sqrt(48) b=6.9 cm
 Exponents-negative-and-fractional/279578: Please help me solve this equation: X^5/X^21 solutions Answer 203229 by anantha(86)   on 2010-03-10 22:59:01 (Show Source): You can put this solution on YOUR website!sol: in x^5 the base=x and exponent is 5 in x^2 the base =x and exponent is 2 here bases are same so we can subtract the exponents x^5/x^2= x^(5-2)=x^3 2nd method in x^5 the base=x and exponent is 5 , x^5 means we can multiply the base 5 times means x^5=x*x*x*x*x in x^2 the base=x and exponent is 2,x^2 means we can multiply the base 2 times means x^2=x*x now x^5/x^2=(x*x*x*x*x)/(x*x) after cancellation we have x*x*x x^5/x^2=x*x*x=x^3
 Money_Word_Problems/274732: Finite Math is hard how do I solve this question. Find the amount of each payment to be made into a sinking fund so that enough will be present to accumulate the following amounts. Payments are made at the end of each period. \$75,000; money earns 6% compounded semiannually for 4 1/2 years 1 solutions Answer 200494 by anantha(86)   on 2010-02-26 22:09:51 (Show Source): You can put this solution on YOUR website!using this method solve these type of problems are easy formula is used to solve these type of problems amount A= p here p= \$75,000 rate of interest per year =6%, this is very important step convert rate of interest per half year for this we divide the rate of interest by 2 now rate of interest for half year=6%/2=3% ,now r=3% now the time period=4 1/2 years=in 4 years we are having 8 half years ,in 4 1/2 years we are having 9 half years, now n=9 p=\$75,000,r=3%,n=9 amount A=p substitute p,r,n values in this formula we get amount compounded half-yearly A=\$75,000 A=\$75,000 A=\$75,000 A=\$75,000*1.03*1.03*1.03*1.03*1.03*1.03*1.03*1.03*1.03 do this using calculator
 Linear-equations/274752: find the slope of the line 5x +2y =1. 1 solutions Answer 200487 by anantha(86)   on 2010-02-26 21:25:58 (Show Source): You can put this solution on YOUR website!equation of the line= 5x+2y=1 the equation is of the form ax+by+c=0 then the slope of the line= -(x coefficient)/(y coefficient) step1:1st we convert given line in to ax+by+c=0 for this we subtract 1 on both sides 5x+2y-1=1-1 5x+2y-1=0 now the equation is of the form ax+by+c=0 slope= -(x coefficient)/(y coefficient) here x coefficient=5,y coefficient=2 slope= -(5)/2
 Linear-systems/274486: perimeter of a triangle The perimeter of the triangle shows the accompanying figure 12 meters Determine the value of x, x+1, x+2 by solving the equation x+(x+1)+(x+2)=121 solutions Answer 200318 by anantha(86)   on 2010-02-26 02:23:25 (Show Source): You can put this solution on YOUR website!perimeter=sum of the three sides of a triangle here the sides are x,x+1 and x+2 means 1st side= x 2nd side=x+1 and 3rd side=x+2 perimeter=1st side+2nd side+3rd side given perimeter=12 12=(x)+(x+1)+(x+2) 12=x+x+1+x+2 12=3x+3 isolate x subtract 3 on both sides 12-3=3x+3-3 9=3x dividing both sides by 3 9/3=3x/3 3=x 1st side=3 2nd side=x+1=3+1=4 3rd side=x+2=3+2=5 check: 1st side+2nd side +3rd side=perimeter perimeter=3+4+5=12 which is given in our problem
 Equations/274517: Soybean meal is 18% protein, cornmeal is 9% protein.How many pounds of each should be mixed in order to get 360lb of mixture that is 10% protein? a. how many pounds of cornmeal should be in the mixture? b. how many pounds of soybean meal should be in the mixture?1 solutions Answer 200313 by anantha(86)   on 2010-02-26 01:38:45 (Show Source): You can put this solution on YOUR website!let no of pounds of soybean meal be x pounds and no of pounds of cornmeal be y pounds x pounds of 18% protein and y pounds of 9% protein should be mixed we get 360lb of 10% protein x+y=360lb -------(1)equation y=360-x(i.e; for isolating y subtract x from both sides) x * (18%)+ y*(9%) =360*(10%) x*(18/100)+y*(9/100)=360*(10/100) 18x/100+9y/100=3600/100 multiplying every term by 100 (18x/100)*100+(9y/100)*100=(3600/100)*100 after removing 100 on both sides we have 18x+9y=3600------------(2) equation substitute y value in 2 equation 18x+9(360-x)=3600 18x+9*360-9*x=3600 18x+3240-9x=3600 9x+3240=3600(subtracting 9x from 18x we get 9x) isolate x on one side subtract 3240 on both sides 9x+3240-3240=3600-3240 9x=360 dividing both sides by 9 we get 9x/9 =360/9 x=40 substitute x value in y=360-x y=360-x y=360-40=320 no of pounds of soybean meal=40 pounds no of pounds of cornmeal=320 pounds
 Functions/239275: give the given function g described by g(x) = 5x, find each of the following: (a) g(-10)= (b)g(6)= (c) g(32)=1 solutions Answer 175705 by anantha(86)   on 2009-11-15 23:23:55 (Show Source): You can put this solution on YOUR website!sol: given function be g(x)=5x a) g(-10)= substitute x= -10 in the above function g(-10)=5*(-10)=-50 g(-10)=-50 b) g(6) substitute x=6 in the above function g(6)=5*6=30 g(6)=30 c) g(32) substitute x=32 in the above function g(32)=5*32=160 g(32)=160
 Functions/239276: writee an equation of the line containing the given point and parallel to the given line(4,-6);3x-7y=61 solutions Answer 175704 by anantha(86)   on 2009-11-15 23:16:25 (Show Source): You can put this solution on YOUR website!sol: equation the line parallel to the given point (4,-6) is 3x-7y=k substitute x=4 and y=-6 in 3x-7y=k 3*4-7*(-6)=k 12+42=k k=54 equation of the line parallel to the given line is 3x-7y=54
 Geometry_Word_Problems/239286: The length of a room is 5 less than twice the width. The perimeter is 80 feet.1 solutions Answer 175703 by anantha(86)   on 2009-11-15 23:08:14 (Show Source): You can put this solution on YOUR website!sol: let width be x twice the width=2x length of the room=5 less than twice the width=2x-5 perimeter of the rectangle=2*(length+width)=2*(2x-5+x)=2*(3x-5) according to the problem perimeter of the rectangle=80 feet 2*(3x-5)=80 dividing both sides by 2 2*(3x-5)/2=80/2 3x-5=40 adding both sides by 5 3x-5+5=40+5 3x=45 dividing by 3 on both sides 3x/3=45/3 x=15 width=15 feet and length=2x-5=(2*15)-5=30-5=25 feet check this problem: perimeter =2*(length+width)=2(25+15)=2*40=80 feet which is given
 Inverses/239295: the sum of a number and seven times its reciprocal is 16/3. find the number1 solutions Answer 175702 by anantha(86)   on 2009-11-15 22:58:39 (Show Source): You can put this solution on YOUR website!sol: let the number be x its reciprocal=1/x 7 times its reciprocal=7*1/x=7/x according to the problem sum of a number and 7 times its reciprocal=16/3 x+7/x=16/3 multiply both sides by x x*x+7/x*x=16/3*x x^2+7=16x/3 multiply both sides by 3 x^2*3+7*3=16x/3*3 3x^2+21=16x transpose 16x from R.H.S to L.H.S 3x^2-16x+21=0 on multiplying two numbers we get 63 and adding or subtracting two numbers we get 16 those numbers are 7 and 9 7*9=63 and 7+9=16 3x^2-16x+21=0 can be written as 3x^2-9x-7x+21=0 3x(x-3)-7(x-3)=0 (3x-7)(x-3)=0 3x-7=0 3x=7 x=7/3 x-3=0 x=3 the number is 7/3 or 3
 Linear_Equations_And_Systems_Word_Problems/239288: Find the equation through the point (2,4) with slope 41 solutions Answer 175700 by anantha(86)   on 2009-11-15 22:44:28 (Show Source): You can put this solution on YOUR website!sol: equation of the line passing through (x1,y1) and slope m is y-y1=m(x-x1) in this problem the coordinates (x1,y1)=(2,4) means x1=2 and y1=4 and slope m=4 substitute these values in the above formula y-4=4(x-2) y-4=4x-8 transpose L.H.S part to R.H.S 4x-8-y+4=0 4x-y-4=0 which is the requried equation passing through (2,4) and slope 4
 Linear-equations/238693: I need help with my home work please. I can not figure out this equation. Find the equation of the line containing the given pair of points (4,2) and (12,5)1 solutions Answer 175401 by anantha(86)   on 2009-11-14 00:06:57 (Show Source): You can put this solution on YOUR website!sol: equation of the line passing through the points (x1,y1),(x2,y2) is y-y1/y2-y1=x-x1/x2-x1 equation of the line passing through the points (4,2)and (12,5) is x1=4,y1=2,x2=12,y2=5 substitute the values in the above formula y-2/5-2=x-4/12-4 y-2/3=x-4/8 on cross multiplication 8(y-2)=3(x-4) 8y-16=3x-12 transpose L.H.S part to R.H.S 3x-12-8y+16=0 3x-8y+4=0
 Travel_Word_Problems/238660: A cruise ship travels 4 hours on a trip downstream with a 6-mph current. The return trip against the same current takes 5 hours. Find the speed of the boat in the water when the water is still. 1 solutions Answer 175400 by anantha(86)   on 2009-11-13 23:55:57 (Show Source): You can put this solution on YOUR website!sol: let speed of boat in still water =x mph speed of current=6mph speed of boat in downstream=speed of boat in still water+speed of current speed of boat in down stream=x+6 mph speed of boat in up stream=speed of boat in still water-speed of current speed of boat in up stream=x-6 time taken to travel down stream=4 hours time taken to travel up stream=5 hours distance=speed*time distance travel downstream=speed of boat downstream/time taken to travel down stream distance travel down stream=(x+6)*4 distance travel upstream=speed of boat upstream/time taken to travel up stream distance travel up stream=(x-6)*5 according to the problem distance travel downstream=distance travel up stream (x+6)*4=(x-6)*5 4x+24=5x-30 transpose 4x on R.H.S side and -30 on L.H.S 24+30=5x-4x 54=x speed of boat in still water=54 mph
 Angles/238417: How many degrees are there in an angle that measures 25 degree more than the measure of its complement? The measure of the supplement of an angle is 45 degree less than four times the measure of the angle. Find the measure of the angle and its supplement.1 solutions Answer 175180 by anantha(86)   on 2009-11-13 06:33:21 (Show Source): You can put this solution on YOUR website!sol: let the angle be x its complement angle=90-x according to the problem x=25+(90-x) 90-x transpose to L.H.S side x-(90-x)=25 x-90+x=25 2x-90=25 adding 90 on both sides 2x-90+90=25+90 2x=115 dividing by 2 on both sides 2x/2=115/2 x=57.5 sol: let the angle be x supplement of angle=180-x four times the measure of the angle=4x according to the problem supplement of angle=four times measure of angle-45 180-x=4x-45 transpose 45 on L.H.S side and x on R.H.S side 180+45=4x+x 225=5x dividing both sides by 5 225/5=5x/5 45=x supplement of angle=180-45=135
 Travel_Word_Problems/238423: the equation is d = 44t. If d = 66, whate is it 1 solutions Answer 175178 by anantha(86)   on 2009-11-13 06:09:19 (Show Source): You can put this solution on YOUR website!sol: the given equation is d=44t if d=66 substitute d value in the above equation 66=44*t dividing both sides by 44 66/44=44t/44 3/2=t t=3/2
 Angles/238432: find the angle such that its complement is fourteen times the angle1 solutions Answer 175176 by anantha(86)   on 2009-11-13 05:53:56 (Show Source): You can put this solution on YOUR website!sol: let the angle be x fourteen times the angle=14x complement of the angle=90-x according to the problem complement of the angle= 14 times the angle 90-x=14x adding x on both sides 90-x+x=14x+x 90=15x dividing both sides by 15 we get 90/15=15x/15 6=x the angle=6 degrees
 Equations/238008: can you help me solve by factoring and using the principle of zero products x^2+4x-77=01 solutions Answer 174940 by anantha(86)   on 2009-11-12 07:06:23 (Show Source): You can put this solution on YOUR website!sol: x^2+4x-77=0 product of two numbers we get 77 and adding or subtracting we get 4 those numbers are 11 and 7 their product=11*7=77 subtracting those numbers=11-7=4 above equation can be written as x^2+11x-7x-77=0 here 4 terms are there ,in 1 and 2 terms x is common and 3 and 4 terms 7 is common x(x+11)-7(x+11)=0 now x+11 is common term (x+11)(x-7)=0 x+11=0 x=-11 x-7=0 x=7 the roots are 7 and -11
 Equations/238019: Mary is twice Wang's age & Kat is 2 years younger the Wang. The sum total of their ages is 46. How old is each person?1 solutions Answer 174938 by anantha(86)   on 2009-11-12 06:51:08 (Show Source): You can put this solution on YOUR website!sol: let Wang's age be x Mary is twice Wnag's=2*x kat is 2 years younger the wang=x-2 according to the problem sum of their ages=46 x+2x+x-2=46 4x-2=46 adding 2 on both sides 4x-2+2=46+2 4x=48 dividing by 4 on both sides 4x/4=48/4 x=12 Wang's age=12 years Mary age=2*Wang's age=2*12=24 years Kat age=Wang's age-2=12-2=10 years check: sum of their ages=46 Wang's age+Mary age+Kat age=12+24+10=46 L.H.S=R.H.S
 Circles/238034: The radius of a circle whose circumference is equal to the sum of the circumferences of the two circles of diameters 36cm and 20 cm is (A) 56 cm (B) 42 cm (C) 28 cm (D) 16 cm 1 solutions Answer 174936 by anantha(86)   on 2009-11-12 06:41:28 (Show Source): You can put this solution on YOUR website!sol: in this problem 3 circles are given let the radius of the 1 st circle be r circumference of 1st circle=2*pi*r and diameter of the 2nd circle=36cm circumference of 2nd circle=pi*diameter of 2nd circle=pi*36=36pi diameter of the 3rd circle=20cm circumference of the 3rd circle=pi*20=20pi according to the problem circumference of 1st circle=circumference of 2nd circle +circumference of 3rd circle 2*pi*r=36pi+20pi 2*pi*r=56pi dividing both sides by pi 2*pi*r/pi=56pi/pi 2r=56 dividing both sides by 2 2r/2=56/2 r=28cm
 Exponents/229500: if y=3 then y3(y3-y)=1 solutions Answer 170129 by anantha(86)   on 2009-10-20 23:38:16 (Show Source): You can put this solution on YOUR website!sol: y^3(y^3-y) here y^3 can be written as y*y*y substitute y value y^3=y*y*y=3*3*3=27 y^3(y^3-y) here substitute y^3 value and y value =27(27-3) =27(24) =27*24=648
 Triangles/226913: Given that the area of an equilateral triangle is 57 cm^2, find its perimeter. 1 solutions Answer 168798 by anantha(86)   on 2009-10-14 22:54:48 (Show Source): You can put this solution on YOUR website!sol: Area of an equilateral triangle=squareroot(3)/4*a^2 inthe above formula a is side of an equilateral triangle according to the question area of an equilateral triangle=57 cm^2 squareroot(3)/4*a^2=57 multiplying both sides by 4/root(3) root(3)/4*4/root(3)*a^2=57*4/1.732 (root(3)=1.732) after cancilation a^2=228/1.732 a^2=131.63 a=root(131.63) a=11.47 now the perimeter of equilateral triangle=root(3)/2*a =1.732/2*(11.47) =0.866*11.47 =9.93cm
 Quadratic_Equations/206219: 2x^2+20=-13x1 solutions Answer 155777 by anantha(86)   on 2009-08-11 01:07:29 (Show Source): You can put this solution on YOUR website!sol: solving a Quadratic equation step1: write the given Quadratic equation in standard form,ax^2+bx+c=0 step2: factorize the trinomial ax^2+bx+c and express it as the product of two linear factors step3: put each linear factor equal to zero thus,two values of x will be obtained,these are the roots of the given quadratic equation. sol: we have 2x^2+20= -13x step1:given equation in standard form is 2x^2+20+13x=0 here -13x is transpose to L.H.S it convert into +13x step2: now we find the factors of this quadratic equation 2x^2+13x+20=0 now find two numbers with sum=13 and product=(2*20)=40 clearly,such numbers are 8 and 5,adding these numbers we get 8+5=13 and product we get 8*5=40 now 2x^2+13x+20=0 can be written as 2x^2+8x+5x+20=0 (2x^2+8x)+(5x+20)=0 2x(x+4)+5(x+4)=0 (x+4)(2x+5)=0 step3: x+4=0 or 2x+5=0 x+4=0 x=-4 ,transpose +4 from L.H.S to R.H.S we get -4 2x+5=0 2x= -5 dividing by 2 on both sides 2x/2=-5/2 x= -5/2 x= -4 or -5/2 these are the roots of the quadratic equation
 Quadratic_Equations/206088: 4. Rita rows 12 km upstream and 12 km downstream in 3 hours. The speed of her boat in still water is 9 km/hr. Find the speed of the stream.1 solutions Answer 155642 by anantha(86)   on 2009-08-10 04:28:00 (Show Source): You can put this solution on YOUR website!sol: speed=distance/time according to the question speed of upstream=distance/time=12/3=4km/hr according to the question speed of boat in still water=9 km/hr let speed of stream= x km/hr now speed of upstream=speed of boat in still water-speed of stream substitute above values in this formula ,we get 4km/hr=9 km/hr-x transposing x from R.H.S to L.H.S and 4 from L.H.S to R.H.S x=9 km/hr-4 km/hr= 5km/hr speed of stream=5 km/hr check:speed of upstream=4km/hr speed of upstream=speed of boat in still water-speed of stream =9 km/hr- 5 km/hr=4 km/hr L.H.S= R.H.S (as requried)
 Quadratic-relations-and-conic-sections/198904: what is the parabola graph of 6x^2=5y1 solutions Answer 149402 by anantha(86)   on 2009-06-04 00:51:59 (Show Source): You can put this solution on YOUR website!sol: 6x^2=5y y=6x^2/5 now put x=1 then y=6*(1^2)/5=6/5=1.2 here(x,y)=(1,1.2) now put x=2 then y=6*(2^2)/5=24/5=4.8 here (x,y)=(2,4.5) now put x=3 then y=6*(3^2)/5=54/5=10.8 here(x,y)=(3,10.8) now put x=0 then y=6*(0^2)/5=0/5=0 here (x,y)=(0,0) now put x=-1 then y-=6*(-1^2)/5=6/5=1.2 here (x,y)=(-1,1.2) now put x=-2 then y=6*(-2^2)/5=24/5=4.8 here (x,y)=(-2,4.8) now put x=-3 then y=6*(-3^2)/5=54/5=10.8 here (x,y)=(-3,10.8) the points are (1,1.2),(2,4.5),(3,10.8),(0,0),(-1,1.2),(-2,4.5),(-3,10.8) using these points draw the graph
 Quadratic-relations-and-conic-sections/198907: What is the parabola graph of y^2=10x1 solutions Answer 149400 by anantha(86)   on 2009-06-04 00:21:25 (Show Source): You can put this solution on YOUR website!sol y^2=10x dividing by 10 on both sides y^2/10=10x/10 x=y^2/10 put y=1 then x=y^2/10=1^2/10=1/10=0.1 put y=2 then x=y^2/10=2^2/10=2*2/10=4/10=0.4 put y=3 then x=y^2/10=3^2/10=9/10=0.9 put y=0 then x=y^2/10=0/10=0 put y=-1 then x=y^2/10=(-1)^2/10=1/10=0.1 put y=-2 then x=y^2/10=(-2)^2/10=4/10=0.4 put y=-3 then x=y^2/10=(-3)^2/10=9/10=0.9 the coordinates (x,y) are (0.1,1),(0.4,2),(0.9,3),(0,0),(0.1,-1),(0.4,-2),(0.9,-3) now draw the graph of the above coordinates using graph paper