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Recent problems solved by 'Niku'

Niku answered: 6 problems
Quadratic_Equations/51014: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
1 solutions

Answer 35062 by Niku(6) About Me  on 2006-09-16 22:02:10 (Show Source):
You can put this solution on YOUR website!
width=x
length= 2x+2
Perimeter=2(length + width)
52 cm= 2(2x+2+x)
52 cm=4x+4+2x
48 cm=6x
8 cm= width
18 cm= length


Average/52502: Find the slope and y-intercept.
x = –8

1 solutions

Answer 35054 by Niku(6) About Me  on 2006-09-16 21:35:46 (Show Source):
You can put this solution on YOUR website!
this makes a verticle line & thus, its slope is undefined as neither is there a y-intecept :D


Linear-equations/52334: solve and check please..
32-2(5-2^2)=45x
1 solutions

Answer 34963 by Niku(6) About Me  on 2006-09-15 23:25:19 (Show Source):
You can put this solution on YOUR website!
32-2(5-2^2)=45x
32-10+8=45x
30=45x
2/3=x


Linear-equations/52331: solve and check please..
-6x+2-2(x+1)=6x+6
1 solutions

Answer 34962 by Niku(6) About Me  on 2006-09-15 23:21:44 (Show Source):
You can put this solution on YOUR website!
-6x+2-2(x+1)=6x+6
2-2x-2=12x+6
0=14x+6
-6=14x
-3/7=x


Inverses/52378: hey sher, when u have digits inside the absolute value symbols, u take the distance those numbers are from zero....4 is 4 away & -3 is 3 away from 0. it's always gonna be postive. so u just add 4 & 3 and get 7 :D
| 4 | + |-3|
Thank you,
Sher
1 solutions

Answer 34957 by Niku(6) About Me  on 2006-09-15 23:11:10 (Show Source):


Inverses/50993: I really couldn't find a catagory for my pre- Algebra problem sorry.
Well here is my problem x-21=-2. Thank you for your time:)
x=-2+21
x=19
1 solutions

Answer 34955 by Niku(6) About Me  on 2006-09-15 23:06:22 (Show Source):