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Functions/40756: Functions: p(x)=-3x^2+4x+26 g(x)=x^3+5x-18
1. What is the range?
2. Does the function have an absolute maximum or minimum? 1 solutions
Answer 26138 by Nate(3500) on 2006-06-04 21:55:44 (Show Source):
You can put this solution on YOUR website!p(x)= -3x^2 + 4x + 26
The vertex is: ((2/3),(82/3)) and the parabola opens downward
Range: {y|  }
g(x)= x^3 + 5x - 18

Range: {y|all reals}
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Inequalities/40732: Question:
Let a < b. Show that (a+b)/2 is the midpoint between a and b on the number line. I think that you use the metric way to slove this but I am not sure as to how to do that. Thanks
Julie 1 solutions
Answer 26128 by Nate(3500) on 2006-06-04 20:29:36 (Show Source):
You can put this solution on YOUR website!The mean or average tells you to add up numbers and divide the sum by the amount of numbers to get the midpoint.  is just a limitation to the available points to pick, but the average property tells you that is the way to find the midpoint.
Example:
<-----(-1)-----(0)-----(1)----->
(a + b)/2 = M
(-1 + 1)/2 = M
(0)/2 = M = 0
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Linear-systems/40703: Line 2 is perpendicular to a line that passes through the points (4,-3) and (-2,6). How do I find the slope intercept (y=mx+b) and the general form (Ax+By=C)? 1 solutions
Answer 26093 by Nate(3500) on 2006-06-04 17:22:56 (Show Source):
You can put this solution on YOUR website!Slope = (y2 - y1)/(x2 - x1) = (6 + 3)/(-2 - 4) = 9/(-6) = 3/(-2)
Perpendicular to this slope, so it is: 
You are missing the information that tells us what point or points the new line goes through. Does it go through of the points you gave for the other line?
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Miscellaneous_Word_Problems/34252: The distance d, in feet, a bomb falls in t seconds is given by
How many seconds are required for a bomb released at 21,000 feet to reach its target? (If necessary, round your answer to two decimal places.)
A) 1167.12 seconds
B) 185.76 seconds
C) 92.88 seconds
D) 2972.19 seconds
1 solutions
Answer 26079 by Nate(3500) on 2006-06-04 16:59:49 (Show Source):
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Volume/40668: Question
A solid pyramid of height 40 cm and with a square base of sides 30 cm each is put into a cubical tank of sides 40 cm each. The tank is then filled with water. If the pyramid is removed, find the depth of water in the tank.
Please help to solve this question.
Thank you very much. 1 solutions
Answer 26069 by Nate(3500) on 2006-06-04 16:41:21 (Show Source):
You can put this solution on YOUR website!(Volume of Cube) - (Volume of Pyramid) = (Volume of Water)
(lwh) - ((w^2)h(1/3)) = V
(40*40*40) - ((30^2)40(1/3)) = V
(64000) - (12000) = V
52000 = V
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Surface-area/40669: This question is not from a text book. Therefore, I don't have anything to provide.
Please solve this in a step-by-step format:
The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs. 1 solutions
Answer 26067 by Nate(3500) on 2006-06-04 16:36:31 (Show Source):
You can put this solution on YOUR website!Base's side length: b
Leg's side length: 4b - 8
side + side + side = perimeter
b + (4b - 8) + (4b - 8) = 29
9b - 16 = 29
9b = 45
b = 5
Leg's side length:
4b - 8
4(5) - 8
20 - 8
12
Side's lengths: 5,12,12
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Exponents/40644: 56. help--
A bus leave a station at 1 p.m. , traveling west an average rate of 44 mi/h. One hour later a second bus leaves the same station,traveling each at a rate of 58 mi/h.At what time will the two buses be 274 mi apart? 1 solutions
Answer 26064 by Nate(3500) on 2006-06-04 16:31:25 (Show Source):
You can put this solution on YOUR website!First bus:
y = 44x + 44
Second bus:
q = 58x
Combine:
q - y = 274
58x - (44x + 44) = 274
58x - 44x - 44 = 274
14x = 318
x = 159/7 or about 22.7 hours
22 hours and 42 minutes; means 1 hour and 18 minutes from a whole day
11:42 a.m.
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