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A business purchses a piece of equipment for $25,000. After 5 years, the equipment will be worth only $5,000. Write a linear equation that gives the value, V, of the equipment during the five years. 1 solutions
Answer 29895 by Nate(3500) on 2006-07-07 16:26:49 (Show Source):
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Equations/45061: Please help to show the work.
(1)Compute (a) (f+g)x, (b)(f*g)x, and f(g(x)) given f(x)= x^2-1 and g(x)=x+2.
1 solutions
Answer 29892 by Nate(3500) on 2006-07-07 16:23:53 (Show Source):
You can put this solution on YOUR website!f(x) = x^2 - 1 and g(x) = x + 2
(f + g)x = x^2 - 1 + x + 2
(f + g)x = x^2 + x + 1
(f * g)x = (x^2 - 1)(x + 2)
(f * g)x = x^3 + 2x^2 - x - 2
f[g(x)] = (x + 2)^2 - 1
f[g(x)] = x^2 + 4x + 3
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Functions/45062: Help to show the work please.
Find the (a) domain and range, (b) determine the intervals over which the function is increasing, decreasing, or constant and (c) determine any maximum or minimum values. f(x)=2-x^2 1 solutions
Answer 29891 by Nate(3500) on 2006-07-07 16:20:26 (Show Source):
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Equations/45065: Please help to show the work
find f(-3) when f(x) = 3/x+5 - 4/x-2 1 solutions
Answer 29890 by Nate(3500) on 2006-07-07 16:16:37 (Show Source):
You can put this solution on YOUR website!find f(-3) when f(x) = 3/(x + 5) - 4/(x - 2)
f(x) = 3/(x + 5) - 4/(x - 2)
f(-3) = 3/(-3 + 5) - 4/(-3 - 2)
f(-3) = 3/(2) - 4/(-5)
f(-3) = 15/(10) + 8/(10)
f(-3) = 23/10 = 2.3
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Functions/45064: Please help to show work.
Find the x and y intercepts of the following function.
y =(x+5)(x-3) 1 solutions
Answer 29889 by Nate(3500) on 2006-07-07 16:14:04 (Show Source):
You can put this solution on YOUR website!y-intercept:
y = (x + 5)(x - 3)
y = (0 + 5)(0 - 3)
y = (5)(-3)
y = -15
x-intercept:
0 = (x + 5)(x - 3)
x + 5 = 0
x = -5
and
x - 3 = 0
x = 3
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Functions/45063: Determine the domain, range and reverse of these functions. Then determine if they are functions.
((-3,5),(-3,6),(4,5),(4,6)). I need help what do i do 1 solutions
Answer 29888 by Nate(3500) on 2006-07-07 16:11:55 (Show Source):
You can put this solution on YOUR website!Domain (x-values): -3, 4
Range (y-values): 5, 6
Not A Function Because There Are Same x-values
Inverse of Function:
(5,-3), (6,-3), (5,4), (6,4)
Domain (x-values): 5, 6
Range (y-values): -3, 4
Not A Function Because There Are Same x-values
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Rational-functions/45025: given f(x)=3x+4
1.is f(x) a function? why or why not?
2. find f^-1(x)
is f^-1(x)a function? why or why not. 1 solutions
Answer 29867 by Nate(3500) on 2006-07-07 15:30:30 (Show Source):
You can put this solution on YOUR website!given f(x) = 3x + 4
1.is f(x) a function? why or why not?
Yes, there are no y-values that result in the same value for 'x'.

2. find f^-1(x)
f(x) = 3x + 4
y = 3x + 4
x = 3y + 4
x - 4 = 3y
(1/3)x - (4/3) = f^-1(x)
Yes, there are no y-values that result in the same value for 'x'.
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Quadratic_Equations/45048: Craig is saving to buy a vacation home He inherits some money from a wealthy uncle, then combines this with the $ 22,000 he has already saved and doubles the total in a lucky investment. He endes up with $ 134,000, just enough to buy a cabin on the lake. How much did he inherit?? 1 solutions
Answer 29864 by Nate(3500) on 2006-07-07 15:21:58 (Show Source):
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Functions/45039: This question is from textbook
Find the horizontal asymptote of the rational function f(x)=8x-12/4x-2.
My answer is y=1/2.
Thanks. 1 solutions
Answer 29854 by Nate(3500) on 2006-07-07 14:58:21 (Show Source):
You can put this solution on YOUR website!f(x) = (8x - 12)/(4x - 2)
Vertical Asymptote:
4x - 2 = 0
4x = 2
x = 1/2
Horizontal Asymptote: (this is my theory)
(coefficient of numerator)/(coefficient of denominator)
8/4
2 = y
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Polynomials-and-rational-expressions/45040: This question is from textbook
The degree three polynomial f(x) with real coefficients and leading coefficient 1, has 4 and 3 + i among its roots. Express f(x) as a product of linear and quadratic polynomials with real coefficients.
My answer is f(x)=(x-4)(x^2-6x+9).
Thanks. 1 solutions
Answer 29852 by Nate(3500) on 2006-07-07 14:55:10 (Show Source):
You can put this solution on YOUR website!(x - (3 + i))(x - (3 - i))
((x - 3) + i)((x - 3) - i)
(x - 3)^2 + (x - 3)i - (x - 3)i - i^2
x^2 - 6x + 9 - (-1)
x^2 - 6x + 10
then:
(x^2 - 6x + 10)(x - 4) = f(x)
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