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oooopppppssssssss for the problem ...thanks Mathtut

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x-y=4.......eq 1
x-2y=10.....eq 2
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subtract all terms in eq 2 from terms in equation 1:
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x terms will be eliminated because x-x=0. We are left with -y+2y=4-10
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take y's found value and plug it back into either eq 1 or 2 . I chose eq 1
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x-(-6)=4
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x+6=4
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squared both sides
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=

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ooooooooops you forgot the problem....thanks Mathtut

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use point slope formula
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y-2=(2/3)(x-5)
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y-2=2/3x-10
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y=(2/3)x-8
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so for
x=8: y=2/3(8)-8=16/3-24/3=-8/3
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x=11: y=2/3(11)-8=22/3-24/3=-2/3
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x=12: y=2/3(12)-8=8-8=0

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let the number of adult and student tickets be a and s respectively
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a=2s..........eq 1
3a+2s=824.....eq 2
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take a's value in eq 1 and plug that into eq 2
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3(2s)+2s=824
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8s=824
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number of student tickets sold
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number of adult tickets sold

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A bicycle rider travels 18 miles in the same amount of time that it takes a jogger to travel 10 miles. If the bicyclist goes 9.6 miles per hour faster than the jogger, how fast does each person travel?
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distance = rate * time
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let r be the rate of the jogger...therefore rate of the bike rider is r+9.6
times are equal
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bike:18=(r+9.6)t...eq 1
jogger:10=rt.......eq 2
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rewrite eq 2 to t=10/r and plug that into eq 1
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18=(r+9.6)(10/r)
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18r=10(r+9.6)......multiplied both sides by r
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18r=10r+96
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8r=96
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mph-speed of jogger
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mph-speed of bike rider

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a) it would correctly be the C intercept not the n intercept
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remember the slope intercept equation y=mx+b......where m is the slope and b is
the y intercept. This is the same thing only its C instead of y.
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so the C-intercept is 30.52. We cannot really interpret it without more information which you probably didnt give us. If you want it interpreted email me the rest of the problem.
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for n=0 to 20
you just plug the values in for n and solve for C
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example: n=0, C=30.52...so (0,30.52)
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n=1, C=2.85(1)+30.52=33.37...so (1,33.37)
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you'll find for every increase in n by 1 that the C will increase by 2.85
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so n=2 is 33.37+2.85=36.22
...n=3 is 36.22+2.85
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and so it continues to 20
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here is the graph:

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f(x) = -3x2 – 4x + 5, evaluate for f(0) and f(2
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..if then V=113.04 cu inches

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let x and y be the amount of money invested at 8 and 11%, respectively
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x+y=24000.........eq 1
.08x+.11y=2340....eq 2
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rewrite eq 1 to x=24000-y and plug that value into eq 2
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.08(24000-y)+.11y=2340
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1920-08y+.11y=2340
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.03y=420
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$invested at 11%
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$invested at 8%

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C(m)=.07m+189.......m is the amount of miles driven for the week. C is the Cost of driving the car per week as a funtion of miles.

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-7+4r=-15
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4r=-8.....added 7 to both sides
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divided both sides by 4 to isolate the variable r
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-5x+13=-17
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-5x=-30.....subtracted 13 from both sides
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divided both sides by -5 to isolate the variable x

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-7+4r=-15
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4r=-8.....added 7 to both sides
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divided both sides by 4 to isolate the variable r

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write this in slope intercept form y=mx+b
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5y=bx+10
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y=(b/5)x+2
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so m=slope=( b/5)=3 is what we are looking for
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restrictions are x can be all real numbers except for -4. -4 would put a zero in the denominator and that would make this undefined, therefore it is not allowed.

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let y and x be the time crane 1 and crane 2, respectively, take to unload the ship by themselves. y=2x
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crane 1 does 1/2x of the job per hour
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crane 2 does 1/x of the job per hour
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(1/x+1/2x)(4)=1job
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((2+1)/2x)4=1
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12/2x=1
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2x=12=
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hours-time for crane 2 to do the job
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y=2xhours-time for crane 1 to do the job

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a)mph
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b)
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feet

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answer is F) it is equal to 8
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just multiply out the terms using FOIL-first terms ,outside terms, inside terms,followed by last terms
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so you would have

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remember =-1 so we have -(-1)(-1)=-1
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so A is the answer

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there are many is a parabola
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is another.
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for inputs just put in any value for x that you choose and solve for y.
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remember in a function for every value of x there is 1 and only 1 value of y.
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because for every value of y the value of x is 4.....this creates a vertical line at x=4

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S= where X is each term, M is the mean and n is the number of terms.
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mean is 28
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S=1.87
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population S
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pS==
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pS=1.67

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let n and p be the number of nickles and pennies
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n+p=52...........eq 1
.05n+.01p=1.2....eq 2
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rewrite eq 1 to n=52-p and plug that value into eq 2
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.05(52-p)+.01p=1.2
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2.6-.05p+.01p=1.2
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-.04p=-1.4
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number of pennies
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number of nickels

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(1/2x)- 15 > 11
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(1/2)x>26.....added 15 to both sides
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x>52.......multiplied both sides by 2
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(52,infinity)

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-10<3-x<-5
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-13<-x<-8
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13>x>8......reversed signs when we divided by a negative 1
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(8,13)

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mean is 28
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S=1.87S= where X is each term, M is the mean and n is the number of terms.
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mean is 28
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S=1.87
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population S
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pS==
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pS=1.67

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I think people shy away from percentiles because the math world cant get their act together on one definition:...there are really 3 ways of looking at percentiles .:
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There is no universally accepted definition of a percentile. Using the 65th percentile as an example, the 65th percentile can be defined as the lowest score that is greater than 65% of the scores. Lets call this "Definition 1". The 65th percentile can also be defined as the smallest score that is greater than or equal to 65% of the scores. This we will call "Definition 2". Unfortunately, these two definitions can lead to dramatically different results, especially when there is relatively little data. Moreover, neither of these definitions is explicit about how to handle rounding. For instance, what score is required to be higher than 65% of the scores when the total number of scores is 50? This is tricky because 65% of 50 is 32.5. How do we find the lowest number that is less than 32.5% of the scores? A third way to compute percentiles is a weighted average of the percentiles computed according to the first two definitions. This third definition handles rounding more gracefully than the other two and has the advantage that it allows the median to be defined conveniently as the 50th percentile.
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I will use the 3rd method but give answers to the other 2
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first line this up in ascending order:
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20,22,22,19,22,50,24,15,34,43,22,20,17,38,18,21,21,23,18,23
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15,17,18,18,19,20,20,21,21,22,22,22,22,23,23,24,34,38,43,50
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The first step is to compute the rank (R) of the 20th and 75th percentiles. This is done using the following formula: R=P/100(N+1) where P is the desired percentile and N is the number of terms.
In our cases P=20 and 75 and N=20
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so in our case for the 20 percentile: R=20/100(20+1)=4.2
.......................75 percentile: R=75/100(20+1)=15.75

If R were an integer, the P the percentile would be the number with rank R. When R is not an integer, we compute the Pth percentile by interpolation as follows:
Define IR as the integer portion of R (the number to the left of the decimal point). For our problems IR = 4 and 15
Define FR as the fractional portion of R. In our problems FR= .2 and .75
Find the scores with Rank IR and with Rank IR+1. For our problems this would be
the 4th and 5th terms for 20th percentile and 15 and 16th for the 75th percentile. For P=20 this would be 18 and 19. for P=75 it would be 23 and 24
Interpolate by multiplying the difference between the scores by FR and add the result to the lower score. So for P=20 you would take .2(19-18)+18=. For P=75 it would be .75(24-23)+23=
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15,17,18,18,19,20,20,21,21,22,22,22,22,23,23,24,34,38,43,50
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Therefore, the 20th percentile is 18.2 and the 75th percentile is 23.75. If we had used the first definition (the smallest score greater than 20% and 75% of the scores) the 20th percentile would have been 19(5th term) and for the 75 percentile would have been 24(16th term). If we had used the second definition ( the smallest score greater than or equal to 25% of the scores) the 20th percentile would have been 18(4th term) and the 75 percentile would have been 23(15th term).
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As you can see these definitions need to be standardized so everyone is on the same page.
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hope that helps