New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'MathLover1'
MathLover1 answered: 6609 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629, >>NextProbability-and-statistics/734489: Hello, please help with this question. I'm stuck
The lengths, in inches, of a sample of eight Brazilian Barking Treefish are given below.11, 17, 24, 26, 27, 29, 34, 42 Round the following to 2 DECIMAL PLACES if necessary.
Find the sample mean weight.
Find the sample standard deviation.
1 solutions
Answer 448989 by MathLover1(6611) on 2013-04-06 16:06:22 (Show Source):
You can put this solution on YOUR website!The sample mean is the average and is computed as the sum of all the observed outcomes from the sample divided by the total number of events.
Variance and Standard Deviation: Step by Step
Calculate the mean,  .
Write a table that subtracts the mean from each observed value.
 -------  -------
 -------  -------
 -------  -------
 -------  -------
 -------  -------
 -------  -------
 -------  -------
 -------  -------
 -------  -------
Total:
Divide  by  where  is the number of items in the sample.
 This is the  .
To get the  we take the square root of the variance.
|
�t�e�s�t/734301: In a right triangle angle B is 90 degrees and side AB is 1 cm longer than side BC. If the perimeter of the triangle is 70 cm.Find the length.
Can you please help me out? Thanks so much in advance:) 1 solutions
Answer 448867 by MathLover1(6611) on 2013-04-05 22:08:32 (Show Source):
You can put this solution on YOUR website!
length  : 
length  : 
length  :
It follows that: given perimeter  , then
 ...factor
solutions:
If  , then  , and it is not a solution for  because  must be less than  .
If  , then  .
Hence,  .
so,
length  : 
length  : 
length  :
|
Quadratic-relations-and-conic-sections/734009: Hi there!
Well I was wondering if I could please get some help finding the center and foci of this hyperbola. It would be good if I could see the work so I could understand the problem better. (y + 2) ^ 2 /4 - x ^ 2 / 12 = 1
thank you so much! 1 solutions
Answer 448689 by MathLover1(6611) on 2013-04-04 23:23:12 (Show Source):
You can put this solution on YOUR website! where  and  are the coordinates of the center
 ,  ,; so, the center is at (  ,  )
 ...=>  ....the semi-transverse axis is  unit
long
 ...=>  ...the semi-conjugate axis is  units
long
focus:
 and  .....The foci are  units right and left of the center:
(  ,  )=(  ,  )
and (  ,  )=(  ,  )
|
percentage/733890: Hi, I'm having some trouble with math work and need some help. Please show the work with it.
What is 92 percent of 175?
What is 20 percent of 115?
What percent of 115 is 69?
23 is 46 percent of what?
57 is 30 percent of what?
What is 44 percent of 25?
What percent of 84 is 63?
What percent of 350 is 77? 1 solutions
Answer 448653 by MathLover1(6611) on 2013-04-04 20:27:43 (Show Source):
You can put this solution on YOUR website!1.
What is  percent of  ?
 %=
and you have  ; so,  % of  is
2.
What is  percent of  ?
and you have  ; so,  % of  is
3.
What percent of  is  ?
you are looking for  %=  of  that is equal to
so,
 ......so,  is  % of
4.
 is  percent of what?
 .........  is  percent of
5.
 is  percent of what?
 .........  is  percent of
6.
What is  percent of  ?
 %=
and you have  ; so,  % of  is
7.
What percent of  is  ?
8.
What percent of  is  ?
 .........  is  % of
|
test/733808: I am really confused about algebra. Like problems such as: 2(x+3)=9+x..and other problems including more variables. Can someone please help me? 1 solutions
Answer 448608 by MathLover1(6611) on 2013-04-04 15:43:02 (Show Source):
You can put this solution on YOUR website!
 ....first multiply
 ....now isolate variable  ; add  to both sides
 ...cancel  and  on right side
 .....add  to both sides
 ...cancel  and  on left side
 ...solution for variable  and it is only solution that makes  true
|
Coordinate-system/733775: find the equation in standard form for the line passing through the points (-3,5)and (5,-3) 1 solutions
Answer 448594 by MathLover1(6611) on 2013-04-04 14:07:25 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-3, 5) and (x2, y2) = (5, -3).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .
y=(-1)x + (2)
Your graph:

|
|
Linear-equations/733768: Given line AB, explain how to contruct a square with sides of length AB. 1 solutions
Answer 448593 by MathLover1(6611) on 2013-04-04 14:05:59 (Show Source):
You can put this solution on YOUR website!
Use only a non-collapsible compass and a straight-edge (not a ruler), construct a square with sides AB.
1. Have the compass length as AB.
2. Draw a straight line XY with a straight edge of length much greater than AB.
3. Now mark a point P on XY.
4. With P as center cut an arc on line XY for Q. Now PQ = AB.
5. With P as center cut two arcs on either side of line XY.
6. With Q as center cut two arcs on either side of line XY, so that they make two points with the arcs drawn with P as center.
7. Mark those points as R and S.
8. Now join P, R, Q, S.
9. Now we have a parallelogram PRQS. PR = RQ = QS = SP parallelogram with all sides equal is a rhombus.
10. The Diagonals of the rhombus are perpendicular to each other
11. Now Draw a line UV with points R ans S.
12. Now mark the point at which RS cuts PQ as A.
13. With A as center cut an arc on UV to get the point C.
14. With A as center cut an arc on XY to get the point B.
15. With B as center cut an arc on one side of XY.
16. With C as center cut an arc which cuts the ac drawn with B as center to get the point D.
17. Now ABCD is the required Square with side AB.
or
use compass and ruler
1.
Draw a line from the left side of your paper to the right using a ruler. Draw and label two endpoints. End point A will be on the left and end point B on the right. The distance from point A and point B will be labeled r. Distance r will be the length of each side of your square. Extend the line further to the right from point B to help in finding a new line that will be perpendicular to Line AB.
2.
Draw a perpendicular line upwards from point B. Using distance r, mark and label a new end point C. This will be the second side of the square at an exact 90 degree angle.
3.
Draw an arc with end point A as the center and r as the distance using a compass. Draw a second arc using end point C as the center and r as the distance. Mark and label where these two arcs meet as point D. This is the final corner for your square.
4.
Connect end point A to point D with your ruler. Connect end point C to point D.
|
absolute-value/733742: Write an equation in slope-intercept form of the line through (2, -1) and (3, 4) 1 solutions
Answer 448583 by MathLover1(6611) on 2013-04-04 12:24:18 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (2, -1) and (x2, y2) = (3, 4).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .
y=(5)x + (-11)
Your graph:

|
|
|