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Recent problems solved by 'MathGrace'

MathGrace answered: 6 problems
Quadratic_Equations/16270: 2+3x < 3(x-1)
1 solutions

Answer 7958 by MathGrace(6) About Me  on 2005-10-20 10:28:27 (Show Source):
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2+3x < 3(x-1)
2+3x < 3x-3 Distribute the 3.
-2 -2 Subtract a 2 from both sides (trying to get x by itself)
3x < 3x-5
-3x -3x Subtract a 3x from both sides
0<-5 This is a false statement so there is no number that will work for this inequality. If it had been a true statement (such as 0>-5) then any real number would have worked for x.


Complex_Numbers/16313: can you please help me with {x+y=12
{x-y=2
1 solutions

Answer 7956 by MathGrace(6) About Me  on 2005-10-20 10:25:36 (Show Source):
You can put this solution on YOUR website!
There are several ways to do this problem (linear combination, substitution, graphing). The easiest is by linear combination. You are going to subtract the two equations.
x+y=12
-(x-y=2) Put the common terms over each other like a subtraction problem.
---------
x+y=12
-x+y=-2 Distribute the negative to both sides of equation
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0x+2y=10 Combine like terms.
2y=10
2y/2=10/2
y=5


Expressions-with-variables/16251: (5-y)+(6-y)-(5-y)=0 what does y equal???
1 solutions

Answer 7955 by MathGrace(6) About Me  on 2005-10-20 10:21:46 (Show Source):
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First you have to distribute any minus or pluses you have. You can re-write the equation as 5-y+6-y-5+y=0. Then you should combine like terms on the left and right. 5+6-5=6 and -y-y+y=-y. After you've combined like terms you now have 6-y=0. Subtract a 6 from both sides to get -y=-6, then multiply both sides by -1 to make y positive. (-1)(-y)=(-1)(-6) => y=6


Rational-functions/16318: Slopes and Intercepts y=2x
1 solutions

Answer 7954 by MathGrace(6) About Me  on 2005-10-20 10:17:07 (Show Source):
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This is the equation of a line. It is in the form y=mx+b. m stands for the slope of the line and b stands for the y-intercept of the line (meaning where the line crosses the y-axis...the actual point would be (0,b)). The x-intercept is the point where the line crosses the x-axis (that point would be (x1,0)). So what you really have is the equation y=2x+0. m=2, b=0, and to find the x-intercept you would plug in 0 for y and then solve for x (0=2x+0). Hope that helps!


Equations/16249: How do you do this problem? x/-3=0
1 solutions

Answer 7952 by MathGrace(6) About Me  on 2005-10-20 10:12:39 (Show Source):
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To solve this problem, you would have to multiply both sides of the equation by -3. This is because you want x all by itself so you use the opposite operation (multiplication being the opposite of division (/)).
So -3*(x/-3)=-3*0
x=0


Equations/12564: find z if 3z-19=173-wang

1 solutions

Answer 6372 by MathGrace(6) About Me  on 2005-09-25 20:04:55 (Show Source):
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To solve any equation, you can use PEMDAS (Order of Operations) backwards. First get rid of any subtraction and addition.
Add 19 to both sides. 3z-19+19=173+19 --> 3z=192
Then get rid of any multiplication and division.
Divide both sides by 3. 3z/3=192/3 --> z=64
Finally, plug your answer back in to make sure you did it right.
3(64)-19=192-19=173 We have the right answer! :-)